The diagram represents a rectangular garden of length 15 m and width 10 m. The flower bed is a triangle and the vegetable patch is a trapezium. The rest of the garden is lawn. 4 m 3 m Work out the area of the lawn. Flower | bed 8 m Lawn Vegetable ||10 m patch + 8 m 7 m.
Pls help

Answer:

x is 4/7 :)

Step-by-step explanation:

The factored forms of the expressions are: 3x + 9 = 3(x + 3), 5x + 15 = 5(x + 3), 8x - 20 = 4(2x - 5), 12x - 20 = 4(3x - 5).

To find the factored form of each expression, we need to factor out the greatest common factor (GCF) from each expression. Let's factor out the GCF for each expression:

3x + 9:

The GCF of 3x and 9 is 3.

Factored form: 3(x + 3)

5x + 15:

The GCF of 5x and 15 is 5.

Factored form: 5(x + 3)

8x - 20:

The GCF of 8x and 20 is 4.

Factored form: 4(2x - 5)

12x - 20:

The GCF of 12x and 20 is 4.

Factored form: 4(3x - 5)

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Linear pair angles are adjacent angles that add up to 180 ° ( form a straight line)

So, by looking at the image:

12. <7 and <8 NO

Because they are not adjacent angles.

13. <2 and <4 are vertical angles . YES

Vertical angles are opposite angles

14. m<9 = m<6+m<8 YES

m<6+m<8+m<9 form a straight line, and the bisctor line makes m<9 = m<6+m<8

Using the bottom rules, we can conclude that Ethan's mistakes are: shapes C and F are placed in the wrong groups.

The image showing the two groups is as shown in the brainly link attached at the end.

From the attached file in the brainly link, we see that the shapes are grouped using the following criteria:

Using the above rules, we can conclude that Ethan's mistakes are: shapes C and F are placed in the wrong groups.

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The  total mass of the deposit is 67.5 grams (g).

To find the total mass of the mineral deposit, we need to integrate the density function over the entire length of the strip:

```
M = ∫[0,8] s(x) dx
 = ∫[0,8] 0.06x (8 - x) dx
```

Using algebra and the power rule of integration, we can simplify and evaluate this integral:

```
M = 0.06 ∫[0,8] (8x - x^2) dx
 = 0.06 [(4x^2 - x^3)/3]_[0,8]
 = 0.06 [(4(8^2) - 8^3)/3]
 = 67.5 g
```

Therefore, the total mass of the deposit is 67.5 grams (g).
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The probability that Jeff has to play the game exactly 5 times i.e he keeps playing until he wins prize is (0.25)⁵.

We have, a fast-food restaurant runs a promotion which consists some food items with games pieces. 1 in 4 game pieces is a winner. This means, probability of winning game or sucess (p) = 1/4 . Since number of trials is fixed, trials are independent and probability of success is constant in each trial, we can use Binomial distribution. The Binomial distribution probability formula is

P(X= x) = ⁿCₓ(p)ˣ(1-p)⁽ⁿ⁻ˣ⁾

where,n --> number of trials

p --> probability of success

x --> number of times for a specific outcome within n trials

ⁿCₓ --> number of combinations

we have calculate the probability that he has to play the game exactly 5 times, i.e

x = 5 . Jeff keeps playing until he wins and he wins when he play exactly 5 times so,n= 5

Now, plugging all known values in above formula we get,

P(X= 5) = ⁵C₅(0.25)⁵(1-0.25)⁰

=> P(X= 5) = ⁵C₅(0.25)⁵(0.75)⁰

=> P(X= 5) = 1× (0.25)⁵× 1 = (0.25)⁵

Hence, required probability is (0.25)⁵

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Answer:

there are 10

Step-by-step explanation:

10

Answer:

iiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii, so I think a bit more than 100

Step-by-step explanation:

I counted it! ;) please give me brainiest!

Using it's concept, the domain of the function in interval notation is given by:

(-4,2).

The domain of a function is the set that contains all possible input values for the function. In a graph, it is the set that contains the values of x.

For this function, x varies between -4 and 2, with an open circle, meaning that -4 and 2 are not part of it, hence the domain is:

(-4,2).

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The sum formula for geometric sequence is Sn = a(1 - r^n) / (1 - r)

A unique kind of sequence is a geometric sequence. It is a sequence in which each term aside from the first term and is multiplied by a fixed number to obtain its subsequent term. To obtain the following term in the geometric sequence, one must multiply with a fixed term known as the common ratio, and one need only divide the term by the same common ratio to determine the previous term in the sequence.

There are infinite and finite geometric sequences. The formula for the same is Sn = a(1 - r^n) / (1 - r). Here Sn is the sum of the first n terms of the geometric sequence,  a is the first term of the sequence,  r is the common ratio between consecutive terms in the sequence and n is the number of terms in the sequence

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The cause-specific mortality rate from tuberculosis in Sample City in 2018 is approximately 1.7 per 1,000 population.

To calculate the cause-specific mortality rate from tuberculosis in Sample City in 2018, we need to divide the number of deaths caused by tuberculosis by the population size and then multiply the result by a constant factor (e.g., 1,000 or 100,000) to express it per a specific unit of population.

Given information:

Population of Sample City: 200,000

Number of deaths resulting from tuberculosis: 340

Cause-specific mortality rate from tuberculosis = (Number of deaths resulting from tuberculosis / Population) * Constant factor

Let's calculate the cause-specific mortality rate:

Cause-specific mortality rate = (340 / 200,000) * 1,000

Calculating the value:

Cause-specific mortality rate = 0.0017 * 1,000

≈ 1.7

Therefore, the cause-specific mortality rate from tuberculosis in Sample City in 2018 is approximately 1.7 per 1,000 population.

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Answer: The greatest number of students for whom 30 apples, 45 pears and 60 oranges can be distributed equally is 15.

Step-by-step explanation:

taking HCF

so

HCF of 30,45,60

30 = 2*5*3

45 = 3*3*5

60=3*2*2*5

HCF = 3*5 = 15

so

1 student will get = 30/15 = 2 apples

1 student will get = 45/15 = 3 pears

1 student will get = 60/15 = 4 oranges

Answer:

Step-by-step explanation:

To maximize the volume of the box, we need to find the height that will maximize the volume of the box.

Let's start by finding an expression for the volume of the box. The box has dimensions of 14-2x by 10-2x by x, where x is the height of the box. The volume of the box is:

V(x) = (14-2x)(10-2x)(x)

Expanding this expression, we get:

V(x) = 4x^3 - 48x^2 + 140x

To find the value of x that maximizes this expression, we can take the derivative of V(x) with respect to x and set it equal to zero:

V'(x) = 12x^2 - 96x + 140 = 0

We can solve this quadratic equation using the quadratic formula:

x = [96 ± sqrt(96^2 - 4(12)(140))]/(2(12)) = [96 ± 16sqrt(6)]/24

We can simplify this to:

x = 4 ± sqrt(6)/3

Since the dimensions of the box must be positive, we can discard the negative solution:

x = 4 + sqrt(6)/3

So the height of the box that will give a maximum volume is approximately 5.61 inches (rounded to two decimal places).

The nearest square inch, the area of triangle RST is 95 square inches.

The correct answer is D.

To find the area of triangle RST using Heron's formula, we need to calculate the semi-perimeter of the triangle first.

The perimeter of triangle RST is given as 50 inches, so the sum of its sides must be equal to 50:

22 + 13 + x = 50

Simplifying the equation, we find:

35 + x = 50

Subtracting 35 from both sides:

x = 15

Now that we know the value of the remaining side, we can calculate the semi-perimeter:

s = (22 + 13 + 15) / 2 = 50 / 2 = 25

Next, we can apply Heron's formula to find the area of the triangle:

Area = √(s(s - a)(s - b)(s - c))

where a, b, and c are the lengths of the sides of the triangle.

Area = √(25(25 - 22)(25 - 13)(25 - 15))

Area = √(25(3)(12)(10))

Area = √(9000)

Area ≈ 94.8683298

Rounding to the nearest square inch, the area of triangle RST is 95 square inches.

The correct answer is D.

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Answer:

4.07

Step-by-step explanation:

I am genius

Answer:

\(4 \sqrt{5} \)

☽------------❀-------------☾

Hi there!

~

\(4\sqrt{5}\)

⇒Using the law of radicals

\(\sqrt{a}\) × \(\sqrt{b}\) ⇔ \(\sqrt{ab}\)

⇒ \(\sqrt{80}\)

⇒ \(\sqrt{16} \times 5\)   \(= \sqrt{16}\) × \(\sqrt{5}\) \(= 4\sqrt{5}\)

❀Hope this helped you!❀

☽------------❀-------------☾

Answer:

I think it is 3x-7y=-28

Anthony's "hiring process" or "recruitment period" was 30 days.

The blank can be filled with "hiring process" or "recruitment period" to indicate the duration between placing the advertisement for a new assistant on November 1 and hiring Marquis on December 1. This period represents the time it took Anthony to evaluate applicants, conduct interviews, and make the decision to hire Marquis.

The hiring process typically involves several steps, such as advertising the job opening, reviewing applications, conducting interviews, and finalizing the selection. The duration of this process can vary depending on various factors, including the number of applicants, the complexity of the position, and the efficiency of the hiring process.

In this case, the hiring process took 30 days, indicating the length of time it took for Anthony to complete the necessary steps and choose Marquis as the new assistant. This duration provides insight into the timeframe Anthony needed to assess candidates and make a hiring decision.

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The two inequalities that define the shaded region in the diagram are:

y ≥ 4 and y < x

For the solid vertical line, the slope (m) is 0. The inequality sign we would use would be "≥"  because the shaded region is to the left and the boundary line is solid.

The y-intercept is at 4, therefore, substitute m = 0 and b = 4 into y ≥ mx + b:

y ≥ 0(x) + 4

y ≥ 4

For the dashed line:

m = change in y / change in x = 1/1 = 1

b = 0

the inequality sign to use is: "<"

Substitute m = 1 and b = 0 into y < mx + b:

y < 1(x) + 0

y < x

Thus, the two inequalities are:

y ≥ 4 and y < x

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Answer:

Task

Kipton has a digital scale. He puts a marshmallow on the scale and it reads 7.2 grams. How much would you expect 10 marshmallows to weigh? Why?

Kipton takes the marshmallows off the scale. He then puts on 10 jellybeans and then scale reads 12.0 grams. How much would you expect 1 jellybean to weigh? Why?

Kipton then takes off the jellybeans and puts on 10 brand-new pink erasers. The scale reads 312.4 grams. How much would you expect 1,000 pink erasers to weigh? Why?

IM Commentary

The purpose of this task is to help students

Recognize that in a multi-digit number, a digit in one place represents 10 times as much as it represents in the place to its right and 1/10 of what it represents in the place to its left (5.NBT.1)

By setting the task in the context of weighing objects and bundles of 10, 100, and 1,000 objects, it helps students visualize that bundling 10 units of a given place value will create 1 unit of the next highest place value. For example, taking 10 of an item that weighs 4.2 grams will result in 42 grams because it is 10 groups of 4 grams that weights 40 grams all together, and 10 groups of 0.2 grams that weigh 2 grams all together. The task allows students to explore both the structure of our place value system and how we use that to efficiently multiply and divide powers of 10.

Though this task is written as questions to be discussed or answered by students, the parts of this task are most valuable as a set of scenarios to be infused throughout a unit on place value. The teacher can actually bring in a digital scale and go through a series of explorations with students. It might be natural to start with students weighing one object and making predictions about how much 10 or 100 of these objects would weigh. From there, the teacher may want to have students start weighing sets of 10 or 100 objects and work backwards to think about the weight of 1 object.

The digital scale has several advantages: the weight will always appear in decimal form, thereby making it perfect for students to start reasoning about shifts in decimal place value from a more intuitive place. Moreover, the digital scale will not always show the expected answer. For example, something that weighs 3.5 grams alone might weigh 35.4 grams (rather than 35 grams) when taken as a group of 10. This slight difference provides an excellent opportunity to talk about rounding error. It also requires students to think beyond the rules of sliding a decimal point to the right when multiplying by powers of 10.

If students were still developing the rules for multiplying and dividing by powers of 10, this task would also incorporate MP8, Look for and express regularity in repeated reasoning. It also incorporates parts of MP6, Attend to precision, in that a higher-level discussion will push students to reason why one marshmallow might weigh 7.2 grams, but 10 marshmallows might weigh 7.19 grams. See the solution for part (a) for further elaboration.

Solution

Solution:

10 marshmallows should weigh 72 grams. Students might use repeated addition, multiplication or reason that each digit’s place value will be multiplied by a factor of 10:

10×(7+0.2)(10×7)+(10×0.2)70+272===

If students have had practice using digital scales in class, some students might respond with guesses that are close such as 73 grams or 72.4 grams because the original 7.2 grams may have been rounded to the nearest tenth. If, for example, the original actual weight were 7.24 grams, then the weight of ten marshmallows on a scale that rounds to the nearest tenth of a gram would be 72.4 grams.

1 jellybean should weigh 1.2 grams. Students may come to the solution a number of ways.

Students might notice that dividing 12 by 10 could be expressed in fraction form 1210. Students might further reason that

1210=1010+210

or 1.2.

Students might alternately reason that 12÷10 is the same as

(10÷10)+(2÷10)=1+0.2=1.2

Students might also use the rule that they are beginning to develop about sliding the decimal point one place to the left to divide by 10.

1,000 pink erasers should weigh about 31,240 grams. Students may come to the solution a number of ways:

A student might reason that first, it would be necessary to find out what 100 erasers would weigh by multiplying by a factor of 10 and then further multiplying by another factor of 10 to find out what 1,000 erasers would weigh. This is represented by

312.4×10×10

In this solution method, the student reasoned that multiplying by a factor of 10 and then another factor of 10 would be the same as multiplying by a factor of 100:

312.4×10×10312.4×100100×(300+10+2+0.4)30,000+1,000+200+4031,240====

Another student might want to find the weight of a single eraser. If 10 erasers weigh 312.4 grams, then one eraser must weigh 31.24 grams. From there the student could multiply the weight of one eraser by a factor of 1,000:

1000×(30+1+0.22+0.04)30,000+1,000+200+4031,240==

Step-by-step explanation:

You would expect 1,000 pink erasers to weigh 31,240 grams.

If 10 erasers weigh 312.4 grams, and to get 1,000 you multiply by 100, if you multiply 312.4 by 100 you get 31240.

Or if you use rates

\(\frac{312.4}{10} =\frac{31240}{1000}\)

(when you multiply by 100)

Answer:

need to see problem please

The value of Sin 2x if, Sin x = 2 / 5  and tan(x) > 0, is 4 √21 / 25 so, option B is correct.

Trigonometry is the branch of mathematics that deals with particular angles' functions and how to use those functions in calculations. There are six popular trigonometric functions for an angle. Sine, cosine, and tangents are their names and acronyms (tan).

Given:

Sinx = 2 / 5  and  tan(x) > 0,

Calculate the value of tan x as shown below,

B² = 5² - 2²  (Using Pythagoras theorem)

B² = 25 - 4

B = √21

Hence, Tan x = 2 / √21

Calculate the value of Sin 2x as shown below,

Sin2x = 2 Tan x / (1 + tan² x)

Sin2x = 2 × 2 / √21 / (1 + (2 / √21)²)

Sin2x = 4 / √21 / (1 + 4 / 21)

Sin2x = 4 / √ 21 / (25 / 21)

Sin2x = 4 √21 / 25

Thus, the value of Sin2x  is 4 √21 / 25.

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Answer:

B

Step-by-step explanation:

just took it

The vertical component of velocity can be zero at specific points in the motion of an object.

What is Velocity?

Velocity is a vector quantity that describes the rate of change of an object's position in space over time. It is defined as the displacement of an object divided by the time interval during which the displacement occurred.

The vertical component of velocity can be zero at specific points in the motion of an object. This occurs when the object reaches the highest point in its vertical motion and begins to fall back down. At this point, the vertical component of velocity changes direction from upward to downward, and its magnitude becomes zero. This moment is known as the "instant of maximum height" or "instant of maximum altitude." Beyond this point, the vertical component of velocity becomes negative, indicating that the object is moving downward.

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Answer:

4

Step-by-step explanation: 2x2 Idiot

Tomando el cociente entre la masa de la muestra y la masa de un átomo, veremos que hay 1.7*10^21 átomos de uranio en la muestra.

Para determinar el número de átomos en la muestra, simplemente debemos dividir la masa de la muestra (0.7 gramos) por la masa de un átomo de uranio (4*10^(-25) kg)

Donde la complicación viene por que tenemos distintas unidades.

Para resolver esto, podemos escribir la masa de la muestra en kilogramos.

Sabemos que: 1g = 1*10^-3 kg

Entonces podemos reescribir la masa de la muestra como:

0.7g = (0.7)*(10^-3 kg) = 7*10^-4 kg

Ahora si podemos tomar el cociente, el número de átomos esta dado por:

\(N = \frac{7*10^{-4}kg}{4*10^{-25}kg} = 1.7*10^{21}\)

Así podemos concluir que hay 1.7*10^21 átomos de uranio en la muestra.

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According to the question we have the solution of the  given differential equation initial value problem is: g(x) = (3/4)x^4 - x + 9/4 .

To solve the given initial value problem, we need to integrate both sides of the differential equation. We have:

g'(x) = 3x(x^2 - 1/3)

Integrating both sides with respect to x, we get:

g(x) = ∫[3x(x^2 - 1/3)] dx

g(x) = ∫[3x^3 - 1] dx

g(x) = (3/4)x^4 - x + C

where C is the constant of integration.

To find the value of C, we use the initial condition g(1) = 2. Substituting x = 1 and g(x) = 2 in the above equation, we get:

2 = (3/4)1^4 - 1 + C

2 = 3/4 - 1 + C

C = 9/4

Therefore, the solution of the given initial value problem is:

g(x) = (3/4)x^4 - x + 9/4

In more than 100 words, we can say that the given initial value problem is a first-order differential equation, which can be solved by integrating both sides of the equation. The resulting function is a family of solutions that contain a constant of integration. To find the specific solution that satisfies the initial condition, we use the given value of g(1) = 2 to determine the constant of integration. The resulting solution is unique and satisfies the given differential equation as well as the initial condition.

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Step-by-step explanation:

He jarred 21 in 7 days because there is 3 liters per day

Answer:

Step-by-step explanation:

10

Answer:

Step-by-step explanation: 5795f

Amount of money required for Hogan needs to save for his trip is $ 2480

m ≥ 2480

What is an Inequality Equation?

Inequalities are the mathematical expressions in which both sides are not equal. In inequality, unlike in equations, we compare two values. The equal sign in between is replaced by less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign.

In an inequality, the two expressions are not necessarily equal which is indicated by the symbols: >, <, ≤ or ≥.

Given data ,

Let the minimum amount of money required for the trip = A

The total amount of money required by Hogan for his trip = $ 5245

The amount of money Hogan saved for the trip = $ 2765

Noe , the equation will be

The remaining amount required for the trip =
total amount of money required by Hogan for his trip - amount of money Hogan saved for the trip

The remaining amount required for the trip = $ 5245 - $ 2765

The remaining amount required for the trip = $ 2480

Therefore , the minimum amount of money is m ≥ 2480

Hence , Amount of money required for Hogan needs to save for his trip is $ 2480

m ≥ 2480

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Answer:

A number c increased by 2 is less than or equal to 26 . Translate the sentence into an inequality.