The diameter of a sphere is 6 ft 6 in. Find the radius.

Answer:

12

Step-by-step explanation:

Given:

3 bags of each color band

4 kits

To "divide equally" we need the greatest number that divides the two numbers 3 and 4 equally.

Find the greatest common factor of 3 and 4:

factors of 3 = 1,3,6,9,12,15,18,21,24....

factors of 4 = 1,2,4,8,12,16,20,24...

How many bands are in each kit?​

12 or any other number that is a factor of both 3 and 4 such as 24,..etc.

For the water utility (an enterprise fund) has just sent out a purchase order to a vendor for some new equipment, of the following that would be included in the journal entry to record this event is none of the above. (Option D)

An enterprise fund refers to a fund which may be used to report any activity for which a fee is charged to external users for goods or services. An enterprise fund uses a separate accounting and financial reporting mechanism for which revenues and expenditures are segregated into a fund with financial statements separate from all other governmental activities. Enterprise funds provide goods and services to customers outside the reporting entity. Hence, from the options of journal entry records, none of the given options will be used.

Note: The question is incomplete as it is missing options which are A) A credit to Accounts Payable. B) A debit to Encumbrances. C) A debit to Expenditures. D) None of the above.

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Answer:

Equation is y = 1/2x + 1

Step-by-step explanation:

First off we know the slope, it is 1/2, so that is done already. Now we just need the y-intercept. In order to cross (4, 3), in needs to have a y-intercept of 1. So the equation is y = 1/2x + 1. I hope this helps, and I hope it's not wrong, but I don't think it is.

Answer:

9x

5x-2+4x+2

9x

Step-by-step explanation:

Temperature of refrigerators - Cannot determine. Horsepower of race car engines - Ratio. Marital status of school board members - Nominal. Ratings of television programs - Ordinal. Ages of children enrolled in a daycare - Interval

The level of measurement for the temperature of refrigerators cannot be determined based on the given information. The temperature could potentially be measured on a nominal scale if the refrigerators were categorized into different temperature ranges. However, without further context, it is not possible to determine the specific level of measurement.

The horsepower of race car engines can be measured on a ratio scale. Ratio scales have a meaningful zero point and allow for meaningful comparisons of values, such as determining that one engine has twice the horsepower of another.

The marital status of school board members can be measured on a nominal scale. Nominal scales are used for categorical data without any inherent order or ranking. Marital status categories, such as "married," "single," "divorced," etc., can be assigned to school board members.

The ratings of television programs, such as "poor," "fair," "good," and "excellent," can be measured on an ordinal scale. Ordinal scales represent data with ordered categories or ranks, but the differences between categories may not be equal or measurable.

The ages of children enrolled in a daycare can be measured on an interval scale. Interval scales have equal intervals between values, allowing for meaningful differences and comparisons. Age, measured in years or months, can be represented on an interval scale.

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Answer:

the independent variable is time and the distance dependent variable is distance.

Step-by-step explanation:The question is asking for the definition of independent and dependent variable. An independent variable is a variable that is manipulated to determine the value of a dependent variable while a dependent variable is the variable that is been measured in an equation. From the given question, the independent variable is time while the distance covered is the dependent variable.

The value of angle 1 in the parallelogram is given as 26 degrees

Let us call the vertices of the angles as ∠A, ∠B, ∠C and ∠D

we have ∠ A represented as 1 and 2

∠B as 128

∠C as 3 and 4

∠D is unnamed

Using the property of parallelogram, we can see that

∠ A is opp ∠C hence they are equal

∠B = ∠D = 128 because they are opposite

Another property says that the sum of adjacent angles in a parallelogram are = 180 degrees they are supplementary

such that

∠ A + 128 = 180

∠ A = 180 - 128

∠ A = 52 degrees

∠ A is made up of two angles 1 and 2 that are equal

hence 52 / 2

= 26

Proof: the sum of internal angle in a parallelogram is 360 degrees

∠ A = ∠ C = 56 degrees because they are opposite

56 + 56 + 128 + 128

= 360 degrees

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We are asked to find out if the two triangles are congruent and indicate the method to prove that they are congruent.

As you can see, when two lines intersect, they make two pairs of "vertically opposite angles" and these angles are equal.

Also, both triangles have equal angles of 25°.

Both triangles have one equal side.

So, we have two equal angles and one equal including side (including side means that it is between the two equal angles)

So, we can conclude that the two triangles are congruent by the "ASA" (Angle-Side-Angle) postulate of triangle congruency.

Therefore, the correct answer is "ASA"

Answer:Q

Step-by-step explanation:1+2-3+4=1

The length of the QR is 16 cm when PQR ~MNO

In the given question, it is given that two similar triangles as PQR ~MNO

Then, the corresponding sides will be in equal proportion to each other as follows

PQ / MN = PR / MO = QR / NO

We need to find the length of the side QR

As above relations are given,

\(\frac{PQ}{MN}\) = \(\frac{PR}{MO}\) = \(\frac{QR}{NO}\)

\(\frac{30}{10}\) = \(\frac{5x + 7}{x+5}\) = \(\frac{4x}{\frac{16}{3} }\)

Equating all the fractions, equal to each we'll find

\(\frac{5x + 7}{x+5}\) = \(\frac{30}{10}\)

5x + 7 = 3(x +5)

5x + 7 = 3x + 15

2x = 8

x = 4

We know that, the length of the QR = 4x cm = 4 x 4 cm = 16 cm

Therefore, the length of the QR is 16 cm when PQR ~MNO

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The graph of the equation that is parallel to 4x – 3y = –12 is determined as: A. y = 4/3x - 3/2.

If two lines are parallel to each other, their graph will have the same slope value, m. This means if their equations are expressed as y = mx + b in slope-intercept form, they will both have the same value of m.

Given the equation of a graph as 4x - 3y = -12, rewrite it in slope-intercept form to determine the slope value:

4x - 3y = -12

-3y = -4x - 12

-3y/-3 = -4x/-3 - 12/-3

y = 4/3x + 4

This means the slope, m is 4/3. The slope of the graph that is parallel to it will also have a slope of 4/3.

The slope of y = 4/3x - 3/2 is also 4/3, therefore, the answer is: A. y = 4/3x - 3/2.

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Complete Question:

The graph of which of the following will be parallel to the graph of 4x – 3y = –12?

A. y = 4/3x - 3/2

B. 6x - 4y = -8

C. y = 3/4x +1

D. 4x – 2y = –12

Answer:

\(\frac{1}{30}\)

Step-by-step explanation:

The computation of the probability is shown below:

P(die and spinner) is

= Probability of the die × probability of the spinner.

where,

Probability of the die is

= \(\frac{1}{6}\)

And for the spinner, the probability is

= \(\frac{1}{5}\)

Therefore the probability of both die and inner is

= \(\frac{1}{6} \times \frac{1}{5}\)

= \(\frac{1}{30}\)

We simply multiplied the probabilities of both die and spinner

Answer:

For Plato Users

Step-by-step explanation:

Plato

The question is an illustration of combination, and there are 1820 ways to select the 12 students

The distribution of the students is given as:

Senior = 7

Junior = 5

Sophomore = 4

The total number of students is:

Total = 7 + 5 + 4

Evaluate

Total = 16

To select 12 students from the 16 students, we make use of the following combination formula

Ways = 16C12

Evaluate the expression using a calculator

Ways = 1820

Hence, there are 1820 ways to select the 12 students

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Answer:

\(2y = -3x+7\)

Step-by-step explanation:

The coordinates are (3,-1) and (-1,5)

Finding the slope :

Slope = \(\frac{rise}{run}\)

Slope = \(\frac{5+1}{-1-3}\)

Slope = \(\frac{6}{-4}\)

Slope = \(-\frac{3}{2}\)

Now Finding y-intercept.

For this, we'll take any point

Let it be (3,-1)

So,

Point = (x,y) = (3,-1)

=> x = 3, y = -1

Putting in slope intercept form to get b

=> \(y = mx+b\)

=> -1 = (3)(\(-\frac{3}{2}\)) + b

=> b =  -1 +  \(\frac{9}{2}\)

=> b = \(\frac{7}{2}\)

Putting m and b in the slope intercept form to get the required equation of line

=> \(y = mx+b\)

=> \(y = \frac{-3x+7}{2}\)

=> \(2y = -3x+7\)

The equation for money collected m for h boxes of chocolate bars sold is m = 30h.

We are given that the band is selling every bar of chocolate for $1.50

Now, they have boxes of chocolate, with every box containing 20 bars of chocolate in them.

Hence if we are going to calculate the amount of money collected on selling one box it will be

20 X $1.5

= $30

We need to find the equation for the amount of money collected based on the number of boxes of chocolate bars sold.

We have been given that money collected should be represented b m while the number of chocolate boxes sold should be represented by h

Now we know that

Money collected = price per box X no.of boxes sold

we have already calculated the price per box hence we get

m = 30h

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Answer:

SSS congruency theorem

Step-by-step explanation:

I just got 100% on the quiz for edge

Answer:  SSS congruency theorem

Step-by-step explanation:

True, The range of a linear transformation defined by the matrix transformation t(x) = Ax is equal to the column space of matrix A.


The range of a linear transformation defined by the matrix transformation t(x) = ax is equal to the column space of matrix A (col A).

The range of a linear transformation is the set of all possible output values. In this case, the matrix A represents the transformation, and the column space of matrix A represents the span of the columns of A. The column space of matrix A is the set of all possible linear combinations of the columns of A.

To prove that the range of the linear transformation t(x) = Ax is equal to the column space of matrix A, we can show that every vector in the column space of A can be obtained as an output of the transformation t(x) = Ax. Additionally, we can show that every output of the transformation t(x) = Ax belongs to the column space of A.


Therefore, it is true that the range of a linear transformation defined by the matrix transformation t(x) = Ax is equal to the column space of matrix A.

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Answer 41

Step-by-step explanation:

If you need me to show you how just comment

Answer:

73

41

always

Step-by-step explanation:

Just completed it

Answer:

35. Domain is -∞,∞ Range is y=0.

Step-by-step explanation:

No solution.

{Y(t), t ≥ 0} is a Martingale when Y(t) = B₂(t) – t

To show that {Y(t), t ≥ 0} is a Martingale, we need to prove that E[Y(t)|F(s)] = Y(s) for all s ≤ t, where F(s) is the sigma-algebra generated by B(u), 0 ≤ u ≤ s.

Using the hint, we can compute E[Y(t)|F(s)] as follows:

E[Y(t)|F(s)] = E[B₂(t) - t |F(s)]

= E[B₂(t)|F(s)] - t   (by linearity of conditional expectation)

= B₂(s) - t  (since B₂(t) - t is a Martingale)

Therefore, we have shown that E[Y(t)|F(s)] = Y(s) for all s ≤ t, and thus {Y(t), t ≥ 0} is a Martingale.

To compute E[Y(t)], we can use the definition of a Martingale: E[Y(t)] = E[Y(0)] = E[B₂(0)] - 0 = 0.

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Given question is incomplete, the complete question is below

.Show that {Y(t), t ≥ 0} is a Martingale when

Y(t) = B₂(t) – t

What is E[Y(t)]?

Hint: First compute E[Y(t)|B(u), 0 ≤ u ≤ s].

Answer:

total commission= $2,600

Step-by-step explanation:

Giving the following information:

He earns a 10 percent commission on the first $5,000 and 15 percent on all sales over $5,000.

First, we need to structure the total commission formula:

total commission= 0.10*x + 0.15*y

X= sales up to $5,000

Y= sales from $5,001 to infinity

Now, sales for $19,000 sales:

total commission= 0.1*5,000 + 0.15*14,000

total commission= $2,600

Answer: It is the distance that -5 is form 0 on the number line

Step-by-step explanation:

We can define the absolute value of any number:

IxI as:

"The distance between the point x and the origin in the coordinate axis"

If we are in one dimension, x is just a value, and the coordinate axis will be a number line.

Then we could rewrite this as:

"is the distance between the value x and the 0 in the number line"

So:

IxI = x if x > 0

IxI = -x if x < 0.

Then:

I -5 I

Is the distance between the number -5, and the 0 in the number line, and this is:

I - 5 I = 5.

The correct option is:

"It is the distance that -5 is form 0 on the number line"

Answer:

Answer: It is the distance that -5 is form 0 on the number line

Step-by-step explanation:

Answer:

Step-by-step explanation:

One that has the next least in common with the rest.

Information is needed to evaluate the project's financial viability, considering factors such as the initial investment, expected cash flows, cost of capital, and project duration.

To calculate the year 1 operating cash flows (OCF), we need to subtract the year 1 costs from the year 1 revenues:

OCF = Year 1 Revenues - Year 1 Costs

OCF = $192,000 - $125,000

OCF = $67,000

To find the depreciation expense in year 3, we need to determine the depreciation method. The provided information is incomplete regarding the depreciation method, so we cannot calculate the depreciation expense in year 3 without knowing the specific method.

The change in Net Working Capital (NWC) in year 2 can be determined by multiplying the Net Working Capital percentage (given as a percentage of t+1 revenues) by the year 1 revenues and subtracting the result from the year 2 revenues:

Change in NWC = (Year 2 Revenues - Net Working Capital percentage * Year 1 Revenues) - Year 1 Revenues

Without the specific Net Working Capital percentage or Year 2 Revenues values, we cannot calculate the exact change in NWC in year 2.

The net cash flow from salvage (ATSV) is calculated by multiplying the Salvage Value percentage by the Initial Cost:

ATSV = Salvage Value percentage * Initial Cost

ATSV = 28% * $390,000

ATSV = $109,200

To calculate the project's NPV, we need the cash flows for each year, the cost of capital, and the project duration. Unfortunately, the information provided does not include the cash flows for each year, so we cannot calculate the project's NPV.

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The complete question is:

Below are your numerical inputs for the problem: 4 & Initial Cost (\$) & 390000 5 & Year 1 Revenues (\$) & 192000 6 & Year 1 Costs (\$) & 125000  7 & Inflation & 2.75% 8 & Project Duration (years) & 6 9 & Depreciation Method & 10 & Tax Rate & 11 & Net Working Capital (\% oft+1 Revenues) & MACRS 12 & Salvage Value (\$) & 28.00% 13 & Cost of Capital & 15.00% & 245000 How much are the year 1 operating cash flows (OCF)? How much is the depreciation expense in year 3 ? What is the change in Net Working Capital (NWC) in year 2? What is the net cash flow from salvage (aka, the after-tax salvage value, or ATSV)? What is the project's NPV? Would you recommend purchasing the ranch? Briefly explain.

Mean (m) = 498

Standard deviation (σ) = 12

Sample size (n) = 86

The probability that the sample mean would differ from Population mean by less than 494.7 watts

P(m - s < Z < m + s)

P(498-494.7 < Z < 498+ 494.7)

Using the Z formula :

Zscore = (x - m) / (σ/√n)

x = 498 - 494.7 = 3.3 , x = 498 + 494.7 = 992.7

Z = (3.3 - 498) / (12/√86) = -383.48

P(Z < -383.48)

Z = (992.7 - 498 ) / (12/√86) = 383.48

P(Z<383.48)

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Answer:

14005

Step-by-step explanation:

I did the math and everything checks out

Answer:

B) 3/5

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\(because~of~the~angles\\BC = 3k\\AB = 4k\)

⇒ (AB)² + (BC)² = (AC)²

in which because of AB and BC's values, goes into...

⇒ (4k)² + (3k)² = (AC)²

because of that ↑ you get the values of what is below.

⇒ (AC)² = 16 k² + 9 k²

add 16k and 9k for the result below.

⇒ (AC)² = 25 k²

⇒ AC = ±5k

the sin is the side opposite to the angle, so find the hypotenuse and opposite angle.

\(Side~opposite~to~angletheta\\= BC(3k)\\\\Hypotenuse\\= AC(5k)\)

That said →  \(sintheta = \frac{BC}{AC} = \frac{3k}{5k} = \frac{3}{5}\)

________________________________________________________

Ask in comments.

\( \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star\)

\(\textsf{ \underline{\underline{Steps to solve the problem} }:}\)

\( \qquad❖ \: \sf \: \sin {}^{4} ( \alpha) + 2 \sin {}^{2} ( \alpha) \cos {}^{2} ( \alpha) + { \cos {}^{4} ( \alpha) }^{} \)

\( \qquad❖ \: \sf \:( \sin {}^{2} ( \alpha) ) {}^{2} + 2( \sin {}^{2} ( \alpha))( \cos {}^{2} ( \alpha)) + {( \cos {}^{2} ( \alpha)) }^{} \)

( use identity a² + 2ab + b² = (a + b)² )

\( \qquad❖ \: \sf \:( {\sin {}^{2}( { \alpha}) + \cos {}^{2} ( \alpha)) }^{2} \)

( sin² x + cos ² x = 1 )

\( \qquad❖ \: \sf \: {1}^{2} \)

\( \qquad❖ \: \sf \: {1}^{} \)

\( \qquad \large \sf {Conclusion} : \)

Value of that expression is 1