The efficiency of a machine is 80%? What does it mean?​

Answer:

Explanation:

H = V² / (2·g)

H = 12² / (2·9.8) ≈ 7,3 m

Answer:

By conservation of energy,

Kinetic energy of launched rocket = change in potential energy of rocket at maximum height.

→ Ig h is maximum height reached:

Answer:

your answer is some

Explanation:

just so you know i took the test and i got an 80% on edge

The correct answer is net displacement of a point on the rim of the blade during the deceleration is 10.0 in or 0.254 m 10.0 i n o r 0.254 magnitude .

Magnitude in physics is simply described as "distance or quantity." It shows the size or direction that an object moves in either an absolute or relative sense. It is a way of expressing something's size or scope. Magnitude in physics often describes a length or a size. A scalar is used to indicate a force's magnitude, which is the amount to which the body it is acting on will be accelerated by the force (a single number). The force's strength can also be considered in terms of its magnitude. An attribute of a mathematical object that indicates whether it is bigger or smaller than other things of the same kind is its magnitude or size.

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1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point ,  the heat of fusion of the substance is 548 joules .

Heat of fusion, also known as enthalpy of fusion or latent heat of fusion, is the amount of energy required to melt or freeze a substance under constant pressure conditions. When it comes to chemistry, "fusion" is basically synonymous with "melting." In the classroom, heat of fusion is typically used when a substance is at its melting or freezing point. In such instances, most people consider heat of fusion to be a constant.

Water, for example, has a heat of fusion of 334 J/g at its melting point of 0°C. At 0°C, one grams  of liquid water requires 334 Joules of energy to completely freeze into ice. In addition, one grams of ice requires 334 Joules of energy to melt entirely.

q = m×∆Hf

q: Total change in heat energy (in Joules)

∆Hf: Heat of fusion of substance (in Joules per gram)

m: Mass of substance (in grams)

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The airplane change in velocity be 120 m/sec

The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.

The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose strength or magnitude is determined by the norm and whose direction correlates with a plumb bob.

acceleration = velocity/time

Velocity = acceleration * time

Velocity = 60*2

Velocity = 120 m/sec

The airplane change in velocity be 120 m/sec

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\(\left(95\dfrac{\rm gal}{\rm min}\right)\left(\dfrac{231}{1.00}\dfrac{\mathrm{in}^3}{\rm gal}\right)\left(\dfrac{1.0}{12}\dfrac{\rm ft}{\rm in}\right)^3\left(\dfrac{1.0}{60}\dfrac{\rm min}{\rm s}\right)\approx0.211661\dfrac{\mathrm{ft}^3}{\rm s}\)

Multiplying 95 gal by 231 converts it to in^3. Dividing by 12^3 converts in^3 to ft^3. Dividing by 60 converts min to s.

C. Graph representing a linear relationship between mass on the x-axis and kinetic energy on the y-axis.

Kinetic energy is the energy possessed by a body due to its motion.

K.E = ¹/₂mv²

where;

The kinetic energy of a body is directly proportional to the mass of the object.

Thus, the correct relationship between kinetic energy and mass is Graph representing a linear relationship between mass on the x-axis and kinetic energy on the y-axis.

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Answer:

Pressure of water = Voltage

Flow rate of water = Current

Obstructions present in the river = Resistance

Explanation:

We can describe Ohm's Law by using the river analogy,

Given,

The initial speed with which the stone was thrown upwards, u=8.00 m/s

The height of the building, h=15.0 m

The acceleration due to gravity is g=9.8 m/s²

From the equation of the motion we have,

Where v is the final velocity of the stone and t is the time taken by the stone to reach the maximum height.

When the stone reaches the maximum height, the velocity of the stone becomes zero. And after that, the stone starts to fall back down.

Therefore the final velocity of the stone is, v=0 m/s. And in this case, the acceleration will be acting in the direction opposite to the direction of the motion of the stone. Thu the acceleration due to gravity will be, g=-9.8 m/s²

On substituting the known values in the equation,

The distance covered by the stone to travel to the maximum height is given by,

On substituting the known values,

Therefore the total distance the stone needs to cover, to hit the ground is,

Now we have to calculate the time duration in which the stone hits the ground.

The stone starts falling down from the maximum height, therefore the initial velocity of the stone, in this case, will be, u₀=0 m/s. And as we dont know the final velocity, we will need the distance traveled by the stone.

Therefore the time taken by the stone to hit the ground is given by the equation,

Here g will have a positive value as the stone is now traveling downwards.

Therefore,

Therefore the time taken by the stone to hit the ground is,

Therefore the total time taken by the stone to hit the ground is 2.75 seconds

To determine the final velocity of the stone we use the equation,

On substituting the known values,

Therefore the final velocity of the stone when it hits the ground is 18.9 m/s

The average velocity of the car is 100 kilometers/hour south. This means that, on average, the car is traveling 100 kilometers per hour in the south direction relative to its starting point.

To determine the average velocity of the car, we need to calculate the displacement and divide it by the time taken. Velocity is defined as the rate of change of displacement with respect to time.

In this case, the car is traveling south, and its displacement is 200 kilometers from its starting point after 2 hours.

The average velocity is given by the formula:

Average velocity = Displacement / Time

The displacement is 200 kilometers south, and the time is 2 hours. Therefore, we have:

Average velocity = 200 kilometers south / 2 hours

Simplifying the calculation:

Average velocity = 100 kilometers/hour south

Hence, the correct answer is B. 100 kilometers/hour south. This indicates that the car's average velocity is 100 kilometers per hour towards the south direction.

It's important to note that velocity is a vector quantity and includes both magnitude (speed) and direction. In this case, the direction is specified as south, which indicates that the car is moving towards the south relative to its starting point.

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The pushing force she exerts on the sled is equal to the frictional force the ground exerts on the sled.

In the video, the girl pushed her brother on the sled at a constant velocity, which means the forces acting on the sled must have balanced. Therefore, the pushing force the girl exerted must have been equal to the frictional force that the ground exerted on the sled.

This is because, according to Newton's Third Law of Motion, for every action there is an equal and opposite reaction. In this case, the action is the girl pushing the sled, and the reaction is the frictional force exerted by the ground on the sled. Since the sled is moving at a constant velocity, this means that the forces acting on it are balanced, and therefore the pushing force and the frictional force must be equal.

In equation form, this can be represented as:
F_push = F_friction

Where F_push is the pushing force exerted by the girl, and F_friction is the frictional force exerted by the ground.

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Answer: -10 m/s

Explanation:

Grouping data refers to the process of categorizing or organizing data based on specific criteria or attributes.

It involves grouping similar data points together to gain a better understanding of patterns, relationships, and trends within the dataset. By grouping data, you can simplify complex information and derive meaningful insights from large amounts of data. The purpose of grouping data is to create subsets or clusters that share common characteristics.

This enables easier analysis, summarization, and comparison of data within each group. Grouping can be performed on various types of data, such as numerical, categorical, or time-based data. Grouping data allows for the exploration of data at different levels of granularity.

For example, you can group sales data by region to analyze regional performance, or group customer data by demographics to identify specific customer segments. This process helps in identifying outliers, detecting patterns, and making data-driven decisions.

Common techniques for grouping data include using functions like GROUP BY in SQL or utilizing data visualization tools to create charts or graphs that illustrate the grouped data. Grouping can be applied in various fields, such as marketing, finance, healthcare, and research, to uncover insights and support decision-making processes.

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Answer:

No - It is connected in parallel instead of series

Explanation:

The answer is No, the reason behind the answer that the ammeter is connected in parallel which is wrong it must be connected in series.

An ammeter is a device for detecting electric current in amperes, either directly (DC) or alternating (AC). Due to the fact that a shunt running parallel to the meter carries the majority of the electricity at high current values, the digital multimeter can measure a wide range of current values. A circle with the capital A in it serves as the icon for an ammeter for circuit diagrams.

The moving coil of the electrodynamics ammeter rotates in the field created by the fixed coil. It measures alternating and direct current with 0.1 to 0.25 percentage points (by converting Ac power To DC power using a rectifier).

The ammeter is connected in series and, on the other hand, the voltmeter is connected in parallel.

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A) The work done on the book between points A and B is 5.32 J in the direction opposite to the book's motion.

B) The book is moving at 1.91 m/s at point C.

C) If +0.750 J of work was done on the book from point B to point C, the book would be moving at 2.31 m/s at point C.

(a) To find the work done on the book between points A and B, we need to use the work-energy principle, which states that the net work done on an object is equal to its change in kinetic energy:

Net work done = change in kinetic energy

The change in kinetic energy can be found by subtracting the initial kinetic energy at point A from the final kinetic energy at point B:

change in kinetic energy = (1/2)mvB^2 - (1/2)mvA^2

where m is the mass of the book, vA is the velocity of the book at point A, and vB is the velocity of the book at point B.

Substituting the given values, we get:

change in kinetic energy = (1/2)(1.50 kg)(1.25 m/s)^2 - (1/2)(1.50 kg)(3.21 m/s)^2

= -5.32 J

Since the final velocity is less than the initial velocity, the change in kinetic energy is negative. Therefore, the net work done on the book between points A and B is also negative. The magnitude of the net work done is:

|net work done| = |-5.32 J| = 5.32 J

Therefore, the work done on the book between points A and B is 5.32 J in the direction opposite to the book's motion.

(b) Since -0.750 J of work is done on the book from point B to point C, we can use the work-energy principle again to find the final velocity at point C:

Net work done = change in kinetic energy

Substituting the given values, we get:

-0.750 J = (1/2)(1.50 kg)(vC^2 - 1.25^2 m/s^2)

Solving for vC, we get:

vC = 1.91 m/s

Therefore, the book is moving at 1.91 m/s at point C.

(c) If +0.750 J of work was done on the book from point B to point C, we would have:

0.750 J = (1/2)(1.50 kg)(vC^2 - 1.25^2 m/s^2)

Solving for vC, we get:

vC = 2.31 m/s

Therefore, if +0.750 J of work was done on the book from point B to point C, the book would be moving at 2.31 m/s at point C.

The given question is incomplete, the complete question is

A 1.50-kg book is sliding along a rough horizontal surface. at point a it is moving at 3.21 m>s, and at point b it has slowed to 1.25 m>s. (a) how much work was done on the book between a and b? (b) if -0.750 j of work is done on the book from b to c, how fast is it moving at point c? (c) how fast would it be moving at c if +0.750 j of work was done on it from b to c?

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Explanation:

Given that,

Mass of a puck, m = 8 kg

Initial velocity, u = 10i m/s

Final velocity, v = (10i+12j) m/s

Time, t = 8 s

(a) Force acting on an object is given by the product of mass and acceleration.

F = ma

a is acceleration

\(F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{8\times (10i+12j-10i)}{8}\\\\F=12j\ \text{N}\)

(b) The magnitude of force is given by :

\(F=\sqrt{12^2+0^2} \\\\F=12\ N\)

Hence, the component of force is 12j N and its magnitude is 12 N.

Answer:

(i) To find the velocity of the crate just after losing contact with the roof, we can use the equation:

v^2 = u^2 + 2as

where v is the final velocity, u is the initial velocity (which is zero), a is the acceleration, and s is the displacement (which is 3 m).

Substituting the values, we get:

v^2 = 0 + 2 × 4.9 × 3

v^2 = 29.4

v = √29.4

v ≈ 5.42 m/s

Therefore, the velocity of the crate just after losing contact with the roof is approximately 5.42 m/s.

(ii) To find the velocity just before the crate hits the ground, we can use the conservation of energy principle. The initial potential energy of the crate at the top of the roof is converted into kinetic energy just before it hits the ground.

Initial potential energy = mgh

where m is the mass of the crate, g is the acceleration due to gravity, and h is the height of the roof.

Final kinetic energy = (1/2)mv^2

where v is the velocity just before the crate hits the ground.

Since there is no loss of energy, we can equate these two values:

mgh = (1/2)mv^2

Canceling out m on both sides and substituting the values, we get:

(1/2) × 1.17 × 9.81 × 3 = (1/2) × 1.17 × v^2

v^2 = 34.5

v = √34.5

v ≈ 5.87 m/s

Therefore, the velocity just before the crate hits the ground is approximately 5.87 m/s, and its direction is along the horizontal.

(iii) To find the time taken by the crate to hit the ground after leaving the roof, we can use the equation:

s = ut + (1/2)at^2

where s is the displacement (which is the height of the roof, 3 m), u is the initial velocity (which is zero), a is the acceleration, and t is the time taken.

Substituting the values, we get:

3 = 0 + (1/2) × 9.81 × t^2

t^2 = 0.612

t ≈ √0.612

t ≈ 0.78 s

Therefore, the time taken by the crate to hit the ground after leaving the roof is approximately 0.78 s.

(iv) Finally, to find the horizontal distance between the point directly below the roof and the landing point, we can use the equation:

s = ut + (1/2)at^2

where s is the horizontal distance, u is the initial velocity (which is zero), a is the acceleration (which is zero, since there is no force acting along the horizontal direction), and t is the time taken (which is 0.78 s).

Substituting the values, we get:

s = 0 + (1/2) × 0 × (0.78)^2

s = 0

Therefore, the horizontal distance between the point directly below the roof and the landing point is zero, which means the crate lands directly below the roof.

Explanation:

This is quite simple, we can solve this problem using kinematic equations of motion.

(i) The velocity of the crate just after losing contact with the roof:

We can use the kinematic equation, v^2 = u^2 + 2as, where u = 0 m/s (initial velocity), a = 4.9 m/s^2 (acceleration), and s = 3 m (distance).

v^2 = 0^2 + 2(4.9)(3) = 29.4

v = √29.4 = 5.42 m/s (velocity just after losing contact with the roof)

(ii) The velocity (magnitude and direction) just before it hits the ground:

We can use the kinematic equations of motion for motion in a straight line with constant acceleration.

First, let's find the time taken by the crate to reach the ground after leaving the roof. We can use the kinematic equation, s = ut + 1/2 at^2, where s = 3 m (vertical distance), u = 5.42 m/s (initial velocity), a = 9.8 m/s^2 (acceleration due to gravity), and t is the time taken to reach the ground.

3 = 5.42t - 1/2 (9.8)t^2

Simplifying this quadratic equation, we get t = 0.88 s (time taken to reach the ground after leaving the roof).

Now, let's find the velocity just before it hits the ground. We can use the kinematic equation, v = u + at, where u = 5.42 m/s (initial velocity), a = 9.8 m/s^2 (acceleration due to gravity), and t = 0.88 s (time taken to reach the ground after leaving the roof).

v = 5.42 + (9.8)(0.88) = 14.74 m/s (magnitude of the velocity just before hitting the ground)

The direction of the velocity just before hitting the ground is downwards, at an angle of 30 degrees below the horizontal (due to the slope of the roof).

(iii) The time the crate takes to hit the ground after leaving the roof:

We have already calculated this in part (ii), which is t = 0.88 s.

(iv) The horizontal distance between the point directly below the roof and the landing point:

We can use the formula, distance = velocity × time.

The horizontal velocity of the crate is constant and equal to 5.42 m/s, which is the same as the velocity just after losing contact with the roof (since there is no friction).

Therefore, the horizontal distance traveled by the crate before hitting the ground is:

distance = 5.42 m/s × 0.88 s = 4.77 m.

Answer:hope this helps you

Explanation:.

Answer:

Explanation:

distance travelled s = 10 cm

speed v = 1.4 x 10⁶ m /s

v² = u² + 2as

u = 0

v² = 2as

( 1.4 x 10⁶ )² = 2 x a x .10

a = 9.8 x 10¹² m /s²

force on proton = mass x acceleration

= 1.67 x 10⁻²⁷ x 9.8 x 10¹²

= 16.366 x 10⁻¹⁵ N .

If magnitude of electric field be E

force on proton

= E x charge on proton

= E x 1.6 x 10⁻¹⁹

E x 1.6 x 10⁻¹⁹ = 16.366 x 10⁻¹⁵

E = 10.22 x 10⁴ N/C

The direction of electric field will be positive x - direction .

b )

Speed of proton = 1.4 x 10⁶  m /s .

The steps/guidelines for preventing quackery and fraud when shopping are :

Quackery involves the claim of knowledge and provision of a fake and dishonest service to unsuspecting customers or clients and this is very common in medicine.

Fraud is the false representation of a material or service in order to cause loss of money or pain to an unsuspecting client or customer. some steps to prevent fraud are as follows :

Hence we can conclude that The steps/guidelines for preventing quackery and fraud when shopping are as listed above

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Answer: It should be the answer beginning like this

The linear spread is that

The radial acceleration of locations along the blade's outer edge is approximately 17580 \(m/s^2\).

Radial acceleration describes the acceleration of an object travelling on a circular path towards the circle's center. It can be defined as the rate of change of tangential velocity with regard to time and is also known as centripetal acceleration.

Given:

We know that the motor is rotating at 3450 rev/min. One revolution is equal to 2π radians, so we can convert the motor speed to radians per minute:

ω₁ = (3450 rev/min) x (2π rad/rev) = 21675π rad/min

The second pulley is half the diameter of the first pulley, so its angular speed, ω₂, is twice that of ω₁:

ω₂ = 2ω₁ = 43350π rad/min

The circular saw blade is mounted on the same shaft as the second pulley, so it also rotates at the same angular speed:

ω = ω₂ = 43350π rad/min

We can now calculate the linear speed of the small piece of wood moving at the same rate as the rim of the circular saw blade, indicated by v. The circumference of the circle is supplied by the rim of the circular saw blade:

C = πd = π(0.208 m) = 0.6548 m

The linear speed of the little piece of wood is equal to the tangential speed of the circular saw blade's rim:

v = ωr

where r is the circular saw blade's radius, given by half its diameter:

r = d/2 = 0.208/2 = 0.104 m

By substituting the values, we obtain:

v = r = (43350 rad/min) x (0.104 m) x (1/60) = approx. 23.0 m/s

As a result, the linear speed of the little piece of wood moving at the same rate as the rim of the circular saw blade is about 23.0 m/s.

Next, compute the radial acceleration of locations on the blade's outer edge, represented by. The radial acceleration is calculated as follows:

α = rω²

By substituting the values, we obtain:

r2 = (0.104 m) x (43350 rad/min)2 x (1/602) = 17580 m/s2 (approximate)

Therefore, the radial acceleration of points on the outer edge of the blade is approximately 17580 m/s². This high radial acceleration explains why sawdust doesn't stick to the teeth of the saw blade.

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Your question is incomplete, most probably the complete question is:

The motor of a table saw is rotating at 3450{\rm rev/min}. A pulley attached to the motor shaft drives a second pulley of half the diameter by means of a V-belt. A circular saw blade of diameter 0.208{\rm m}is mounted on the same rotating shaft as the second pulley.

The operator is careless and the blade catches and throws back a small piece of wood. This piece of wood moves with linear speed equal to the tangential speed of the rim of the blade. What is this speed?

v =_______________________ m/s

Calculate the radial acceleration of points on the outer edge of the blade to see why sawdust doesn't stick to its teeth.

\alpha=______________________m/s2

(a) The magnitude of the spring's displacement when the acceleration of the box is zero can be determined by equating the initial gravitational potential energy to the elastic potential energy stored in the spring.

(b) The magnitude of the spring's displacement when the spring is fully compressed can be determined by equating the initial gravitational potential energy to the elastic potential energy stored in the spring.

(a) To determine the magnitude of the spring's displacement when the acceleration of the box is zero, we need to apply the principles of conservation of energy.

Initially, the box has gravitational potential energy given by mgh, where m is the mass of the box, g is the acceleration due to gravity, and h is the height from which the box was dropped. The initial gravitational potential energy is converted into the elastic potential energy stored in the compressed spring and the kinetic energy of the box just before it makes contact with the spring.

The gravitational potential energy is given by:

mgh = (1.9 kg)\((9.8 m/s^2)h\)

The elastic potential energy stored in the spring is given by:

1/2 kx^2\(kx^2\), where k is the spring constant and x is the displacement of the spring.

The kinetic energy of the box just before it makes contact with the spring is given by:

\(1/2 mv^2,\) where m is the mass of the box and v is the speed of the box.

Since the acceleration of the box is zero at the instant when the spring's displacement is maximum, the kinetic energy is zero. Therefore, we can equate the initial gravitational potential energy to the elastic potential energy to find the spring's displacement.

mgh = 1/2 \(kx^2\)

Substituting the given values, we have:

\((1.9 kg)(9.8 m/s^2)h = 1/2 (300 N/m)x^2\)

Solving for x, the magnitude of the spring's displacement, we can determine its value at the instant when the acceleration is zero.

(b) To find the magnitude of the spring's displacement when the spring is fully compressed, we need to consider the conservation of mechanical energy once again.

At maximum compression, all the initial gravitational potential energy is converted into the elastic potential energy stored in the compressed spring.

mgh = 1/2 \(kx^2\)

Substituting the given values and solving for x, the magnitude of the spring's displacement, we can determine its value when the spring is fully compressed.

It's important to note that in both cases, the negative sign of the displacement indicates that the spring is being compressed. The magnitude of the displacement will be a positive value.

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Answer:

Explanation:

True

The Best answer from the options is TRUE

A surfactant with a Hydrophile-lipophile Balance value of 18 is a solubilizing agent because a hydrophilic-lipophilic balance is used to measure the degree /level of hydrophilicness or liphophilicness of a Surfactant is at . and the

method used by the Hydrophile-lipophile balance to achieve this is by calculating the values for the different regions of the surfactant.

Hence a Surfactant with a hydrophile-lipophile Balance value of 18 is expected to function as a solubilizing agent.

Attached below is the HLB

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Answer:

The property of light going in a straight lines in a homogenous straightforward medium is known as rectilinear engendering of light.

Answer:

the property of light travelling in a straight lines in a homogenous transparent medium

Explanation:

Answer:

49.33333m/s²

Explanation:

The formula for acceleration is acceleration=change in velocity/change in time

So:

Iv= 0m/s

Fv= 267m/s

a=267m/s divided by 4.5s

a=49.3333m/s²

If a 5KW immersion heater is used to heat water for a bath. It takes 40 minutes to heat up the water then 3.33 KWh of electrical energy has been converted into thermal energy.

It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.

As given, It takes 40 minutes to heat up the water

60 minutes = 1 hr

1 minute = 1/60

40 minutes = 40/60 hr

energy = power × time

            = 5 ×2/3

            =3.33 KWh

Thus, if the bath water is heated with a 5KW immersion heater then 3.33 KWh of electrical energy is converted into thermal energy after 40 minutes of heating the water.

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Answer:

Explanation:

Answer

How about a thunder storm. I don't know if you live in a city or out in the sticks as I do. Lighting is very obvious and it is not a good idea to be out when experiencing a thunderstorm, especially in an open field. You might be the only thing around that will cause the lightning to be connected to the ground.#  Seconds later, you will hear the thunder which is quite harmless. If you live in the city, observing this is not quite so easy. There are all kinds of buildings around and some of them may block your view.

#The great golfer, Lee Travino, was "hit" by lightening storm twice while playing in tournaments.

Answer:

The Earth’s lithosphere, which includes the crust and upper mantle, is made up of a series of pieces, or tectonic plates, that move slowly over time.

A divergent boundary occurs when two tectonic plates move away from each other. Along these boundaries, earthquakes are common and magma (molten rock) rises from the Earth’s mantle to the surface, solidifying to create new oceanic crust. The Mid-Atlantic Ridge and Pacific Ring of Fire are two examples of divergent plate boundaries.

When two plates come together, it is known as a convergent boundary. The impact of the colliding plates can cause the edges of one or both plates to buckle up into a mountain ranges or one of the plates may bend down into a deep seafloor trench. A chain of volcanoes often forms parallel to convergent plate boundaries and powerful earthquakes are common along these boundaries.

At convergent plate boundaries, oceanic crust is often forced down into the mantle where it begins to melt. Magma rises into and through the other plate, solidifying into granite, the rock that makes up the continents. Thus, at convergent boundaries, continental crust is created and oceanic crust is destroyed.

Two plates sliding past each other forms a transform plate boundary. One of the most famous transform plate boundaries occurs at the San Andreas fault zone, which extends underwater. Natural or human-made structures that cross a transform boundary are offset—split into pieces and carried in opposite directions. Rocks that line the boundary are pulverized as the plates grind along, creating a linear fault valley or undersea canyon. Earthquakes are common along these faults. In contrast to convergent and divergent boundaries, crust is cracked and broken at transform margins, but is not created or destroyed.