The electric force due to a uniform external electric field causes a torque of magnitude 20.0 × 10−9 N⋅m on an electric dipole oriented at 30∘ from the direction of the external field. The dipole moment of the dipole is 9.0 × 10−12 C⋅m.

What is the magnitude of the external electric field?

If the two particles that make up the dipole are 2.5 mm apart, what is the magnitude of the charge on each particle?

Once the ball is thrown, the only force acting on it is gravity, which means that it's acceleration is -9.81 m/s² (negative means downward).

List the known and unknown quantities from the question.

u = initial velocity = 20 m/s

v = final velocity = ? m/s

g = acceleration due to gravity = -9.81 m/s²

t = time interval = ? s

s displacement = 11 m

Before calculating the time it takes for the ball to reach 11 m, the final velocity needs to be calculated using the following kinematic equation.

v² = u² + 2gs

v = √(u² + 2gs)

= √((20 m/s)² + (2x-9.81 m/s² x 11 m)) = 13.57 m/s V=

Calculate the time it takes the ball to reach 11 m using the following kinematic equation.

V = u + gt

Solve for t.

t = (v-u)/g

t (13 57 m/s - 20 m/s)/(-981 m/s²) = 0.655 s

The distance between two consecutive crests would be 2.5 cm.

It can be understood in terms of the distance between any two similar successive points across any wave for example wavelength can be calculated by measuring the distance between any two successive crests.

As given in the problem if a stationary wave is set up on a string of length 10 cm. Four loops are formed.

In one loop the wave would travel a distance that is equal to one wavelength,

wavelength = 10 cm /4

                    =2.5 cm

Thus, the distance between two consecutive crests would be 2.5 cm.

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From the information given, the object starts from rest. This means that

initial angular velocity, wo = 0

It achieves an angular speed of 33,500 rev/min. This means that

final angular velocity, wf = 33,500 rev/min

We would convert 33,500 rev/min to rev/s by dividing by 60. It becomes

558.33 rev/s

time required = 1.6

We would calculate the angular displacement, θ during this period this period by applying the formula,

θ = 1/2(wo + wf)t

θ = 1/2(0 + 558.33)1.6

θ = 446.664 rev

The object continued at this speed for 50s. This means that the angular acceleration is zero since the speed was constant. During this period,

wo = 558.33 rev/s

a = 0

t = 50

We would find the number of revolutions by applying the formula,

θ = wot + 1/2at^2

θ = 558.33 * 50 + 1/2 x 0 x 50^2

θ = 27916.5 rev

Total number of revolutions at this point is

446.664 + 27916.5 = 28363.16 revs

For the final part,

It returns to rest after 10 s. Thus,

t = 10

wf = 0

wo = 558.33

We would find the number of revolutions in this part by applying the formula

θ = 1/2(wo + wf)t

θ = 1/2(558.33 + 0)10

θ = 2791.65 rev

Total revolutions completed is

28363.164 + 2791.65 = 31154.81 revolutions

Battery-powered clocks and Washing machines are objects that transform chemical energy into mechanical energy.

Chemical energy is a type of energy that is stored in the bonds of a chemical. It is converted into thermal energy when people burn wood or burn gasoline in the engine of a car. Mechanical energy is a type of energy that is stored in objects by tension. Compressed springs and stretched bands are examples of mechanical energy.

Mechanical energy i.e. kinetic energy or potential energy is the energy that is present in an object in motion or the energy that is stored in objects due to their position. Mechanical energy is a type of renewable energy.

So we can conclude that options A and C are the correct answers.

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Answer:

As a substance reaches the melting point, the particles begin to move faster, causing the substance to become a liquid.

Explanation:

lmk if you need a different or more detailed answer :)

have a wonderous day <3

The movement of particles  in solid substance increases at the melting point.

A liquid's melting point is the temperature at which it transforms from a solid to a liquid under atmospheric pressure. This is the location where the liquid and solid phases are equally present. The substance's melting point varies with pressure as well and is reported at standard pressure.

In solid, the particles are closely packed to each other and there is no movement of particles.

According to the question, when the solid substance is heated the space between molecules increases with increase in temperature because intermolecular forces between the solid particles gets weak with increase in temperature.

When the space between molecules increases degree of randomness of particles also increases and kinetic energy of particles also increases with degree of randomness.

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Answer:

well i think if hes mean to everyone in school, then he must be going through something at home or he just feels insecure about something and likes to bully others for it. Bullies just bully people because they have nothing better to do and cant find happiness. Tell Nolan to get a life

Explanation:

The initial volume of the liquid is 31.4 cm³. The volume coefficient of thermal expansion of the liquid is 0.002 per degree Celsius. A temperature increase of 109.5°C is needed for the liquid to rise to a height of 49cm.

The initial volume of the liquid can be found using the formula for the volume of a cylinder:

V = πr²h

where r is the radius (half the diameter), h is the height, and π is approximately 3.14. Plugging in the given values, we get:

V = π(0.5 cm)²(40 cm)

V = 31.4 cm³

The volume coefficient of thermal expansion (β) is defined as the fractional change in volume per degree Celsius change in temperature. It can be calculated using the formula:

β = ΔV/(VΔT)

where ΔV is the change in volume, V is the initial volume, and ΔT is the change in temperature. We can rearrange this formula to solve for ΔV:

ΔV = βVΔT

We know that ΔT = -10°C (a decrease of 10°C) and that the height decreased from 40cm to 37cm, or by 3cm. The change in volume can be found using the formula for the volume of a cylinder again, with the new height of 37cm:

ΔV = π(0.5 cm)²(40 cm - 37 cm)

ΔV = 0.59 cm³

Plugging in all the values, we get:

0.59 cm³ = β(31.4 cm³)(-10°C)

β = 0.002

To find the change in temperature needed for the liquid to rise to a height of 49cm, we can use the same formula as before, but solve for ΔT:

ΔT = ΔV/(βV)

We know that ΔV is the difference between the initial volume and the volume at the new height, which is:

ΔV = π(0.5 cm)²(49 cm - 40 cm)

ΔV = 6.86 cm³

Plugging in all the values, we get:

ΔT = 6.86 cm³/(0.002)(31.4 cm³)

ΔT = 109.5°C

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Answer:

Explanation: The correct equation for Newton's second law in the horizontal direction for the block-spring system when it is displaced a distance x from the equilibrium position is:

m(d^2x/dt^2) + kx = 0

where m is the mass of the block, k is the spring constant, and x is the displacement from the equilibrium position. This equation represents the balance of forces acting on the block-spring system, with the restoring force of the spring (proportional to x) opposing the force required to accelerate the mass (proportional to d^2x/dt^2).

I apologize, but I can't help with the specific calculations you've provided. Calculating forces and friction coefficients requires specific numerical values and equations. However, I can explain the concepts and provide a general understanding of the questions you've asked.

3.1 To calculate the magnitude of the force exerted by the athlete vertically on the track, you need the vertical component of the force applied. If the angle of 50° is measured from the horizontal, you can calculate the vertical component using the equation: horizontal force = force × sin(angle).

3.2 To calculate the magnitude of the force exerted by the athlete horizontally on the track, you need the horizontal component of the force applied. Using the same angle of 50° measured from the horizontal, you can calculate the horizontal component using the equation: vertical force = force × cos(angle).

3.4 To determine the minimum value of the static friction coefficient, you would need additional information such as the mass of the athlete. In addition, you would need the normal track force. The coefficient of static friction is a dimensionless value that represents the maximum frictional force that can exist between two surfaces without causing them to slip. The formula to calculate static frictional force is static frictional force = coefficient of static friction × normal force.

3.5 To determine the resultant force exerted on an object when three forces are applied, you need to calculate the vector sum of the forces. You can add forces vectorially by breaking them down into their horizontal and vertical components. You can also sum up the components separately, and then combine them to find the resultant force.

Please provide more specific numerical values or equations if you would like assistance with the calculations.

Answer:

The strength of the electric field is 29922.34 N/C

Explanation:

Given;

distance of the electric field, d = 5.2 cm = 0.052 m

charge of the small plastic bead, q = -9 nC = - 9 x 10⁻⁹ C

The strength of the electric field is calculated as;

\(E = \frac{kq}{d^2}\)

where;

E is the electric field strength

k is coulomb's constant = 8.99 x 10⁹ Nm²/C²

\(E = \frac{(8.99*10^9)(9*10^{-9})}{(0.052)^2} \\\\E = 29922.34 \ N/C\)

Therefore, the strength of the electric field is 29922.34 N/C

The strength of this electric field is equal to 29,922.34 N/C.

Given the following data:

Conversion:

100 cm = 1 m

5.2 cm = 0.052 m

Scientific data:

To calculate the strength of this electric field:

Mathematically,  the strength of this electric field is given by this formula:

\(E=\frac{qk}{r^2}\)

Where:

Substituting the given parameters into the formula, we have;

\(E=\frac{-9 \times 10^{-9}\times 8.99 \times 10^9}{0.052^2} \\\\E=\frac{80.91}{0.002704}\)

E = 29,922.34 N/C.

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The tension force being supplied by the rope is 245 N.

The tension force on the given rope due to the weight of the lamp hanging from the rope is calculated by applying Newton's second law of motion as shown below;

T = mg

where;

T = 25 x 9.8

T = 245 N

Thus, the tension force being supplied by the rope is 245 N.

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The recoil speed of the catapult is 6.96 m/s.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given parameters:

Mass of the catapult : M = 1400 kg.

Mass of the boulder: m = 75 kg.

Velocity of the rock: v = 130 m/s.

We have to find: recoil speed of the catapult: V = ?

From the principle of conservation of linear momentum:

momentum of the boulder = - momentum of the  catapult

⇒ mv = - MV

⇒ v = -mv/M = - (75 × 130)/1400 m/s = - 6.96 m/s

Negative sign indicates recoil of the catapult is in opposite direction of motion of the boulder.

So, the recoil speed of the catapult is 6.96 m/s.

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The initial mechanical energy of the car is equal to its final energy from this, we can find the speed of the car. The final velocity of the car at the time it hits the ground is 16.17 m/s.

Mechanical energy of an object is the sum of its kinetic and potential energy. According to law of conservation of energy initial mechanical energy of a moving object is equal to the final mechanical energy.

Given initial speed of the car u = 12 m/s

height from the surface = 6 m

g = 9.8 m/s²

According to conservation of energy,

1/2 mu² + mgh = 1/2 mv²

u²/2 + gh = v²/2

12²/2 + (9.8 m/s² × 6 m) = v²/2

v = 16.17 m/s.

Therefore, the final speed of the car at the time it hits the ground is 16.17 m/s.

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The heat will always move to the cooler object. This transfer will happen until both objects have the same temperature (thermal equilibrium).

The future consequence of using windmills for wind energy that is most closely related to the given options is: A) It can harm birds and species nearby. Option A

One of the potential consequences of using windmills for wind energy is the risk of harm to birds and other species. Wind turbines can pose a threat to birds, especially large raptors and migratory birds, as they can collide with the spinning turbine blades.

The fast-moving blades can cause injury or death to birds that come into contact with them. Additionally, the construction and operation of wind farms can disrupt wildlife habitats and migration patterns, impacting local ecosystems.

While weather can certainly affect the quality and consistency of wind energy generation (option B), it is not specifically a consequence of using windmills. Weather patterns and variations in wind speed and direction can influence the efficiency and reliability of wind turbines, but this is an inherent characteristic of wind energy rather than a consequence.

Option C states that wind energy produces less noise than other energy sources. This is a positive attribute of wind energy, as wind turbines generally generate less noise compared to other forms of power generation, such as fossil fuel power plants. However, it is not a future consequence but rather a benefit of wind energy.

Option D refers to wind cells being used in isolated locations. This statement is not related to the consequences of using windmills for wind energy but rather describes the potential use of wind cells (small-scale wind energy systems) in remote or isolated areas.

In summary, the most appropriate answer is A) It can harm birds and species nearby, as the impact on wildlife is a significant consideration in the development and operation of wind energy projects.

Option A.

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The total charge in the circuit is 240 microcoulombs.

To calculate the total charge in a series circuit with capacitors, we need to use the formula Q = CV, where Q represents the charge, C is the capacitance, and V is the voltage.

In this case, we have three capacitors connected in series with capacitances of 4 μF, 3 μF, and 2 μF, respectively. The voltage across the circuit is 260 V.

To find the total capacitance (C_total) in a series circuit, we use the reciprocal rule: 1/C_total = 1/C1 + 1/C2 + 1/C3. Plugging in the values, we get 1/C_total = 1/4 + 1/3 + 1/2.

Simplifying this equation gives us 1/C_total = (3 + 4 + 6)/12 = 13/12. Taking the reciprocal, we find C_total = 12/13 μF.

Now, we can calculate the total charge (Q_total) using Q = C_total × V. Substituting the values, we get Q_total = (12/13) μF × 260 V.

Calculating the numerical value, Q_total = (12/13) × 260 = 240 μC (microcoulombs).
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Answer:

Have the same speed.

Explanation:

All electromagnetic waves travel at the same speed, which is 300,000,000 m/s.

Recall that

P = F v

where

P = power produced by the engine

F = magnitude of the component force supplied by the engine in the direction of the car's motion

v = speed of the car

Draw a free-body diagram for the car, and decompose all the forces acting on it into components that act parallel and perpendicular to the slope. The car moves parallel to the slope, so we only care about 2 forces: the parallel component of the car's weight, and the force provided by the engine.

By Newton's second law, since the car is moving at a constant speed,

∑ F = F - m g sin(12°) = 0

where m = 950 kg and g = 9.80 m/s². Solve for F :

F = m g sin(12°) ≈ 1935.658 N

The engine provides P = 6.5 × 10⁴ W, so the car's speed v is

v = P / F = (6.5 × 10⁴ W) / (1935.658 N) ≈ 33.6 m/s

which makes C : 34 ms⁻¹ the closest answer.

The Steady speed of a car moving up a hill, with a slope of 12° to the horizontal,  whose output power is 6.5×10⁴ W and whose mass is 950 kg is A. 7.0 m/s

Speed: This can be defined as the ratio of distance to the time travelled by a body. The S.I unit of speed is m/s

\(P = (mgcosx)V\).................... Equation 1

Where P = output Power of the engine, m = mass of the car, g = acceleration due to gravity, x = angle of the hill with the horizontal, V = steady speed of the car.

\(V = P/mgcosx\)............... Equation 2

From the question,

\(V = (6.5*10^{4} )/(950*9.8*cos12)\)

\(V = 65000/9106.55\)

\(V = 7.13 m/s\)

From the question, the right option is A. 7.0 m/s

Hence the steady speed of the car is 7.0 m/s

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Answer:

The ratio is   \(\frac{T_1}{T_2}  = 3.965  \)

Explanation:

From the question we are told that

   The  radius of Phobos orbit is  R_2 =  9380 km

    The radius  of Deimos orbit is  \(R_1  =  23500 \  km\)

Generally from Kepler's third law

    \(T^2 =  \frac{ 4 *  \pi^2 *  R^3}{G * M  }\)

Here M is the mass of Mars which is constant

        G is the gravitational  constant

So we see that \(\frac{ 4 *  \pi^2  }{G * M  } =  constant\)

    \(T^2 = R^3   *  constant \)      

=>  \([\frac{T_1}{T_2} ]^2 =  [\frac{R_1}{R_2} ]^3\)

Here \(T_1\) is the period of Deimos

and  \(T_1\) is the period of  Phobos

So

      \([\frac{T_1}{T_2} ] =  [\frac{R_1}{R_2} ]^{\frac{3}{2}}\)

=>    \(\frac{T_1}{T_2}  =  [\frac{23500 }{9380} ]^{\frac{3}{2}}]\)

=>    \(\frac{T_1}{T_2}  = 3.965  \)

The given values are:

We know the formula,

→ \(v = \frac{2 \pi r}{T}\)

then,

→ \(\sqrt{\frac{GM_{mars}}{r} } =\frac{2 \pi r}{T}\)

or,

→              \(T = 2 \pi \sqrt{\frac{r^3}{GM_{mars}} }\)

Now,

The orbital period of Deimos will be:

                   \(= 2 \pi \sqrt{\frac{(23500)^3}{GM_{mars}} }\)

The orbital period of Phobos will be:

                   \(= 2 \pi \sqrt{\frac{(9380)^3}{GM_{mars}} }\)

hence,

The ratio will be:

→ \(\frac{T_{deimos}}{T_{Phobos}}\) = \(\frac{2 \pi \sqrt{\frac{(23500)^3}{GM_{mars}} } }{2 \pi \sqrt{\frac{(9380)^3}{GM_{mars}} }}\)

             = \(\sqrt{(\frac{23500}{9380})^3 }\)

             = \(3.96\)

Thus the above answer is correct.

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Answer:

D. An employee receives a bonus at the end of the week for having the most sales that week.

Explanation:

Took the test

Explanation:

Memory loss in retrograde amnesia has long been held to be larger for recent periods than for remote periods, a pattern usually referred to as the Ribot gradient. One explanation for this gradient is consolidation of long-term memories. Several computational models of such a process have shown how consolidation can explain characteristics of amnesia, but they have not elucidated how consolidation must be envisaged. Here findings are reviewed that shed light on how consolidation may be implemented in the brain. Moreover, consolidation is contrasted with alternative theories of the Ribot gradient. Consolidation theory, multiple trace theory, and semantization can all handle some findings well but not others.

Answer:the shape

Explanation:

Answer:

Answer:

i got u

Explanation:

The iron will have the higher final temperature. This is because the specific heat capacity of iron is much lower than the specific heat capacity of ice. Specific heat capacity is the amount of heat energy required to raise the temperature of a substance by a certain amount, and it varies from substance to substance. Since the specific heat capacity of iron is lower, it means that it takes less heat energy to raise the temperature of iron than it does to raise the temperature of ice by the same amount. Therefore, when equal amounts of heat are added to equal masses of ice and iron at the same initial temperature, the iron will have a higher final temperature than the ice.

We have that the sea level pressure for Leh area is 1150mb mathematically given as

Ps= 1150 mb

Question Parameters:

Ladakh is 800 mb.

assuming that Leh is at an altitude of 3500 m and every 100 m

increase in height with respect to sea level corresponds to 10 mb pressure,

Generally, for 3500m the pressure change will be 350 mb.

Therefore,  here for the sea level pressure we need to add,

Ps=800+350

Ps= 1150 mb

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The miniature circuit breaker should rather be fastned to a wall using nails and other neccessary tools.

A miniature circuit breaker is a circuit breaker that is used in homes as a means of guarding against damage to appliances due to a very high current.

This miniature circuit breaker is also harzardous in the sense that it could lead to an electrical fault related fire outbreak especially when it is being blown freely by wind as you tie it with a thread. Doing this a very bad idea because of the risk of a fire hazard.

The miniature circuit breaker should rather be fastned to a wall using nails and other neccessary tools.

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Answer:

90.3N

Explanation:

⊥mg = (0.170 m)(1.20 kg) 9.81 m/s

τ ball = r⊥Wball = (0.340 m)(1.42 N) = − 0.483 N ⋅m

F − 2.001− 0.483 N ⋅m = 0

F = 2.484 N ⋅m

0.0275 m = 90.3 N

The net torque acting on the forearm and hand is 90.3N

Torque is a measure of the pressure that can motivate an object to rotate about an axis. simply as pressure is what causes an object to accelerate in linear kinematics, torque is what reasons an item to collect angular acceleration. Torque is a vector amount.

⇒mg = (0.170 m)(1.20 kg) 9.81 m/s

⇒torque = r⊥weight of the ball

⇒ (0.340 m)(1.42 N) = − 0.483 N ⋅m

⇒F = − 2.001− 0.483 N ⋅m = 0

⇒F = 2.484 N ⋅m

⇒0.0275 m = 90.3 N

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trough is the lowest point of a wave below the rest position.

Correct option is B.