The electromagnetic spectrum is the complete range of electromagnetic radiation ranging from radio waves to gamma rays. Which type of radiation in this spectrum is associated with observable colors such as red, green, and blue?.

Answer:

V1 = 700 cos 69.8 i + 700 sin 69.8 j           vector components of V1

V1 = 241.7 i + 656.9 j          in miles/hour

V2 = 620 cos 107  i + 620 sin 107 j

V2 = -181.3 i + 592.9 j

V = V1 - V2 = 423 i + 64 j        rate of planes separation

1.9 V = 803.7 i + 121.6 j     miles   separation of planes after 1.9 hr

D = (803.7^2 + 121.6^2)^1/2 = 812.8 miles

From the calculation and the momentum of the body, the velocity is 62 m/s

The term momentum refers to the product of mass and velocity. Now recall that the rate of change of momentum is equal to the impressed force.

Hence;

7440 kg-m/s = 120 kg * v

v= 7440 kg-m/s/120 kg

v =  62 m/s

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Answer:

Ferromagnetism, physical phenomenon in which certain electrically uncharged materials strongly attract others. Two materials found in nature, lodestone (or magnetite, an oxide of iron, Fe3O4) and iron, have the ability to acquire such attractive powers, and they are often called natural ferromagnets.

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Answer:

i would say a bus because it has to speed up after the turn

Answer:

The bus

Explanation:

when the bus turns it has a change in direction and since velocity is a vector based on speed and direction the velocity is considered changed and since acceleration is a change in velocity the bus is an example of acceleration

The frequency of light when it reaches Earth is approximately 4.988 x 10^14 Hz.

Explanation:-

Given:

Emitted frequency of light, f = 5.000 x 10^14 Hz,

Speed of the galaxy receding from Earth, v_src = 4500 km/s.

We need to convert the speed of the galaxy from km/s to m/s:

v_src = 4500 km/s * (1000 m/km)

v_src = 4.5 x 10^6 m/s

Plugging the given values into the Doppler effect formula:

f' = (5.000 x 10^14 Hz) * (3.00 x 10^8 m/s + 0 m/s) / (3.00 x 10^8 m/s + 4.5 x 10^6 m/s)

Simplifying the expression:

f' = (5.000 x 10^14 Hz) * (3.00 x 10^8 m/s) / (3.00 x 10^8 m/s + 4.5 x 10^6 m/s)

f' ≈ 4.988 x 10^14 Hz

Therefore, the frequency of light when it reaches Earth is approximately 4.988 x 10^14 Hz.

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We are given that:

We need to find:

Using equations of motion:

➙ v² - u² = 2as

➙ v = u + at

here,

From the given information, we can conclude that:

Now, using equation of motion:

➝ v = u + at

➝ v = 0 + ( 8 × 1.5 )

➝ v = 0 + 12 .0

➝ v = 12 m/s

For, acceleration :

➝ v² - u² = 2as

➝ ( 12 )² - ( 0 )² = 2 × 8 × s

➝ 144 - 0 = 16s

➝ 16 s = 144

➝ s = 144 / 16

➝ s = 9m

\( \dag\) Since, we take displacement in terms of distance in some places, therefore we can say that the height from which the object was dropped is 9 meters .

Answer:

v = 61.54 km/h

Explanation:

The average speed of the car can be found by using the total distance covered by the car and the total time taken for that distance to be traveled. Therefore, the average speed of the car can be found by the following formula:

\(v = \frac{d}{t}\\\)

where,

v = average speed during the trip = ?

d = total distance driven by the car = 1200 km

t = time taken for the traveling = 19.5 hr

Therefore,

\(v = \frac{1200\ km}{19.5\ hr}\\\\\)

v = 61.54 km/h

Answer:

\(136.28\ \text{s}\)

19.08 m/s or 68.688 km/h

Explanation:

a = Aceleración = \(0.14\ \text{m/s}^2\)

s = Desplazamiento = \(1.3\ \text{km}=1300\ \text{m}\)

u = Velocidad inicial = 0

t = Tiempo empleado

De las ecuaciones cinemáticas obtenemos

\(s=ut+\dfrac{1}{2}at^2\\\Rightarrow 1300=0+\dfrac{1}{2}\times 0.14t^2\\\Rightarrow t=\sqrt{\dfrac{1300\times 2}{0.14}}\\\Rightarrow t=136.28\ \text{s}\)

El tiempo necesario para recorrer una distancia de 1,3 km es \(136.28\ \text{s}\)

\(v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 0.14\times 1300+0}\\\Rightarrow v=19.08\ \text{m/s}=19.08\times 3.6=68.688\ \text{km/h}\)

La velocidad final del automóvil es 19.08 m/s so 68.688 km/h.

The kangaroo's horizontal speed will be 9.7 m/s and its departure speed will indeed be 10.65 m/s.

By observing the pace at which this compressed region moves through the medium, we may determine the sound speed. The sound wave travels at a speed of around 343 meters per second in low humidity at 20 degrees Celsius.

The following equation relates the distance to the direction and initial velocity:

d = [v₀²sin2θ]/g, where θ – the angle of the jump.

Thus, v₀² = gd / (sin2θ) = (9.8×8)/0.69 = 113.62

v₀ = 10.65 m/s ( the take off speed).

The horizontal velocity equals:

vₓ = v₀cos 22° = 10.65 m/s × 0.92 = 9.7 m/s

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Answer:

The maximum height above the ground the rocket reaches is 123.1 m.

Explanation:

Let's find the final velocity at a distance of 200 m:

\( v_{f}^{2} = v_{0}^{2} + 2ad \)

Where:

\(v_{f}\) is the final speed =?

v₀ is the initial speed =0

a is the acceleration = 1.25 m/s²

d is the distance = 200 m

\(v_{f} = \sqrt{2ad} = \sqrt{2*1.25 m/s{2}*200 m/s} = 22.4 m/s\)    

Now, when the engines of the rocket turn off and it is subject only to gravity, the height reached is:

\( v_{fy}^{2} = v_{0y}^{2} - 2gh \)

Where:

\(v_{f}\) = 0

\(h = -\frac{v_{fy}^{2} - v_{0y}^{2}*sin(\theta)}{2g} = \frac{(22.4*sin(35))^{2}}{2*9.81 m/s^{2}} = 8.4 m\)

Finally, the maximum height above the ground is:

\( h_{max} = h + H \)

Where H is the vertical component of the 200.0 meters.

\(h_{max} = h + H = 8.4 m + 200.0 m*sin(35) = 123.1 m\)

Therefore, the maximum height above the ground the rocket reaches is 123.1 m.

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Answer:

A) 7.0 m/s²

Explanation:

Acceleration is found by using the formula:

This means the change in time divided by the time interval will give us the car's acceleration.

Since the car starts from rest, its initial velocity is 0 m/s. Its final velocity is 35 m/s. The time interval for the car to go from 0 to 35 m/s is 5.0 seconds.

Substitute the final and initial velocity into the formula.

The acceleration of the car is A) 7.0 m/s².

Longwave radiation is the name given to the infrared component of the spectrum of radiation that Earth emits; its usual wavelengths range from 4 to 30 micrometers (0.0002 to 0.001 inch).

The electromagnetic spectrum is made up of radio waves, microwaves, infrared light, visible light, ultraviolet light, X-rays, and gamma rays, among other types of electromagnetic radiation. The earth's atmosphere blocks out the majority of electromagnetic radiation from space, preventing most of it from reaching the planet's surface.

Visible light is electromagnetic radiation with wavelengths between 400 and 700 nm. A portion of the electromagnetic spectrum that humans can see with our eyes is the visible light or spectrum. The outside of Earth. Effectively, visible light can pass through Earth's atmosphere.

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Asia I think that's right

There are two forces acting on the proton, the electrostatic force and the weight; we also know that the forces are balanced which means that they have to be equal, then we have:

Now, we know that the electrostatic force is related to the electric field by:

and that the weight is given by:

Plugging these in the first equation we have:

The mass and charge of the proton are:

plugging the values in the expression for the field we have:

Therefore, the magnitude of the field is:

Since a proton has a positive charge it will move in the direction of the field; in this case we need the force to be pointing up since the weight points down.

Therefore, the direction of the field is up.

The Mach number for the plane is approximately 3.51.

To find the speed of the plane, we can use the equation:

Speed of sound = Speed of the plane / Time taken

Given: Speed of sound (v) = 344 m/s

Time taken (t) = 3.51 seconds

Let's calculate the speed of the plane:

Speed of plane = Speed of sound × Time taken

Speed of plane =\(344 m/s * 3.51 s\)

Speed of plane ≈ 1206.44 m/s

Rounded to 2 decimal places, the speed of the plane is approximately 1206.44 m/s.

To find the Mach number of the plane, we need to divide the speed of the plane by the speed of sound:

Mach number = Speed of plane / Speed of sound

Mach number ≈ \(1206.44 m/s / 344 m/s\)

Mach number ≈ 3.51

Rounded to 2 decimal places, the Mach number for the plane is approximately 3.51.

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The spring constant of the spring to which a block is attached and spring is compressed initially and then released is 16.67 N/m.

Energy is being transferred from one form to another form and follows conservation of energy.

Mathematically,

" 1/2 * k * x² = 1/2 * m * v² "

where, k is the spring constant = ?

Compression of the spring = 0.75 m

m is Mass of the block = 1.5 kg

v = velocity of the block = 2.5 m/s

Placing values in above equation, we get,

1/2* k * (0.75)² = 1/2* (1.5)* (2.5)²

k * (0.75)² = (1.5)* (2.5)²

k = [(1.5)* (2.5)²]/(0.75)² = 9.375/0.5625 = 16.67 N/m

Thus, the spring constant of the spring is 16.67 N/m.

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Answer:

3m/s^2

Explanation:

acceleration=velocity/time

acceleration= 30/10=3m/s^2

The resultant force acting on the object is 200 N upwards.

The resultant force acting on the object is calculated by taking sum of all the forces including their direction.

Mathematically, the formula for the resultant force acting on the object is given as;

F ( net ) = F1 + F2 + F3

where;

The magnitude of the first force acting vertically upward = 500 N

The magnitude of the second force acting vertically upward = 300 N

The magnitude of the third force acting vertically downwards = 600 N

The resultant force acting on the object is calculated as follows;

F (net) = 500 N + 300 N - 600 N

F (net) = 200 N

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What are the properties and definitions?

Answer:

Theses are the answer

Explanation:

The given statement about “direction cosines tell the angle between the force vector and each of the coordinate axes” is true.

Analytical geometry defines the directional cosines of a vector as the cosines of the angles formed by the vector with the three coordinate axes. To calculate the cosine of a vector's direction, divide the relevant coordinate by the vector's length. A direction's cosine is equivalent to a unit vector's x-coordinate. One such property of the direction cosine is that the sum of the squares of all the direction cosines equals one. The cosine of the angle subtended by a line having three coordinate axes, such as the x-axis, y-axis, and z-axis, is known to be the direction cosine. The direction cosines are cos α, cos β, and cos γ if the angles subtended by these three axes α, β, and γ.

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The brightness of stars as observed from Earth depends on several factors, including their intrinsic luminosity (actual brightness) and their distance from Earth. The brightest stars in our sky appear bright compared to other stars primarily due to their higher intrinsic luminosity and their relative proximity to Earth.

1. Intrinsic luminosity: The brightness of a star is determined by its intrinsic luminosity, which is the total amount of energy it emits per unit of time. Bright stars have a higher intrinsic luminosity, meaning they emit more light compared to dimmer stars.

2. Proximity to Earth: The distance between a star and Earth plays a significant role in its apparent brightness. Bright stars that appear particularly luminous are often relatively closer to our solar system, which results in a more significant amount of their emitted light reaching our eyes.

It's important to note that the apparent brightness of stars can also be influenced by factors such as interstellar dust, atmospheric conditions, and the transparency of Earth's atmosphere. Additionally, some stars may appear brighter due to their larger size or higher surface temperature, leading to greater energy output.

Overall, the combination of intrinsic luminosity and proximity to Earth contributes to the perception of certain stars as the brightest in our sky compared to others.

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The water outflow in 30 secs through 200 mm of the capillary tube is mathematically given as

\(Qo=1.6 \times 10^{2} \mathrm{~mL}\)

\(\begin{aligned}\Delta P &=6660 \mathrm{~m} / \mathrm{m}^{2} \\\mu &=8.01 \times 10^{-4} \text { Pas } \\t &=30 \mathrm{~s} \\L &=200 \mathrm{~mm}=200 \times 10^{-3} \mathrm{~m} \\D &=1.5 \mathrm{~mm}=1.5 \times 10^{-3} \mathrm{~m} \Rightarrow \gamma=\frac{1.5 \times 10^{-3}}{2} \mathrm{~m}\end{aligned}\)

Generally, the equation for Rate of flow of Liquid is  mathematically given as

\(\\$$Q=\frac{\pi r^{4} \times \Delta P}{8 \mu L}\)

$$

Where dP is pressure difference r is the radius

\(\mu\) is the viscosity of water

L is the length of the pipe

\(Q=\frac{\pi \times\left(\frac{1.5 \times 10^{-3}}{2}\right)^{4} \times 6660}{8 \times 8.01 \times 10^{-4} \times 200 \times 10^{-3}}\)

\(Q=5.2 \mathrm{~mL} / \mathrm{s}\)

In $30s the quantity that flows out of the tube

\(&Qo=5.2 \times 30 \\&Qo=1.6 \times 10^{2} \mathrm{~mL}\)

In conclusion, the quantity that flows out of the tube

\(Qo=1.6 \times 10^{2} \mathrm{~mL}\)

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The cosine rule is used to determine the values of unknown aides and angles in a triangle

The measure of θ is approximately 117.2°

Reason:

Given parameters are;

The distance between the two windmills, a = 456 feet

The distance between the cow and one of the windmills, b = 320 feet

Distance between the cow and the other windmills, c = 210 feet

Required, the angle θ between b, and c direction

Solution;

By cosine rule, we have;

a² = b² + c² - 2·b·c·cos(θ)

Which gives;

\(cos (\theta) = \dfrac{320^2 + 210^2 - 456^2}{2 \times 320 \times 210 }\)

The measure of θ ≈ 117.2°

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Answer:

The body must have to be situated at a height 5.10 m.

Explanation:

The body of mass 10 kg must be situated at a height of approximately 51.02 meters above the ground.

The conservation of energy principle states that the total energy of a system is constant. In this case, we can equate the potential energy of the first body to the kinetic energy of the second body, as follows:

Potential energy = Kinetic energy

\(mgh = 1/2 mv^2\)

where m is the mass of each body, g is the acceleration due to gravity, h is the height above the ground, and v is the velocity of the second body.

Substituting the given values, we get:

\(10 kg * g * h = 1/2 * 10 kg * (10 m/s)^2\)

Simplifying this equation, we get:

\(h = (1/2 * v^2) / g\\h = (1/2 * 10 m/s * 10 m/s) / 9.81 m/s^2\\h = 51.02 meters\)

Therefore, the body of mass 10 kg must be situated at a height of approximately 51.02 meters above the ground to have potential energy equal in value to the kinetic energy possessed by the other body of mass 10 kg moving with a velocity of 10 m/s.

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Answer:

electrons

Explanation:

i think this is right

Answer:

7.08

Explanation:

The type of galaxy that has a stellar disk but without gas and dust is an **elliptical galaxy**.

Elliptical galaxies are characterized by their smooth and featureless appearance, lacking the distinct spiral arms seen in disk galaxies like the Milky Way. They are composed mostly of old stars and have little to no ongoing star formation. As a result, they have depleted their interstellar gas and dust reservoirs over time, leaving behind primarily stellar populations. Elliptical galaxies can vary in size from small to massive, and their shape ranges from nearly spherical to elongated ellipsoids. They are commonly found in dense regions of galaxy clusters, where interactions and mergers between galaxies have stripped away their gas and disrupted their original disk structures.

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The cars move with a velocity of 0.713 m/s just after the collision.

By dividing the amount of time it took the object to move a certain distance by the overall distance, one can calculate the object's initial velocity. V is the velocity, d is the distance, and t is the duration in the equation V = d/t.

According to the rule of conservation of momentum, the total amount of momentum before a collision equals the total amount of momentum after the contact.

We can thus write:

m1v1i = (m1 + m2)vf

We can solve for vf as follows:

vf = (m1v1i) / (m1 + m2)

Inputting the numbers provided yields:

vf = (18.0 kg x 100 kg·m/s) / (18.0 kg + 43.0 kg)

= 45.7 kg·m/s

Therefore, the velocity of the cars just after the collision is:

v = vf / (m1 + m2)

= 45.7 kg·m/s / (18.0 kg + 43.0 kg)

= 0.713 m/s

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The elastic potential energy of the spring is 1.6 J.

The elastic potential energy of the spring is the energy stored in the spring and it is calculated as follows;

U = ¹/₂kx²

where;

The given parameters include;

U = ¹/₂kx²

U = ¹/₂ (80) (0.2)²

U = 1.6 J

Thus, the elastic potential energy of the spring is a function of the spring constant and the extension of the spring.

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