the engine needs a free flow of clean air to operate correctly and with low emissions. True or False

When subjected to an internal moment of M = 75 kN·m, the maximum tensile and compressive stress acting in the beam are 125 MPa and -125 MPa respectively.

These stresses are located at the top and bottom surfaces of the beam respectively.Let's find out how to solve the problem statement.A built-up beam is a composite beam that is constructed by bolting or welding together two or more individual beams side by side.

The bending stress formula for a beam subjected to a moment M is given by the following equation:σ = Mc / Iwhereσ is the bending stressM is the internal momentc is the distance from the neutral axis to the point of interestI is the moment of inertia of the beamWe need to determine the maximum tensile and compressive stress acting in the beam. To do so, we'll need to calculate the maximum bending stress that the beam experiences.

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Therefore, the expected number of industrial deaths each year would be approximately 0.15, assuming the incidence rate remains constant.

To calculate the expected number of industrial deaths each year, we need to determine the incidence rate of industrial deaths per worker-year and then multiply it by the number of worker-years.

Given:

Total number of full-time workers (N) = 1500

Frequency or rate of accidents (FAR) = 5 accidents per 100,000 worker-hours

Number of work hours per worker per year (H) = 8 hours per shift * 250 days = 2000 hours

First, let's calculate the total number of worker-years (WY) for all employees:

WY = N * H = 1500 * 2000 = 3,000,000 worker-hours

Next, we can calculate the incidence rate of industrial deaths per worker-year (IDR):

IDR = (FAR / 100,000) * WY

Substituting the given values:

IDR = (5 / 100,000) * 3,000,000 = 0.15

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Standard end bearing depth of a k-series joist is 2 1/2 in. Thus, the correct option is option B.

As used herein, "Open Web Steel Joists K-Series" refers to open web, parallel chord, load-bearing members made of hot-rolled or cold-formed steel, including cold-formed steel whose yield strength* has been attained through cold working, that are suitable for direct support of floors and roof decks in buildings.

To support the uniformly distributed loads listed in the Standard Load Tables for Open Web Steel Joists, K-Series, attached hereto, K-Series Joists must be designed in accordance with this specification. When trying to choose joists to support uniform plus concentrated loads or other non-uniform loads, specifying professionals face a challenge that the KCS Joist, a K-Series Joist, is designed to address.

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Z≤ -4.852 ft, Maximum efficiency is η≅ 0.88 ≅ 88% is the maximum discharge possible

Solution

Given Data:-

D = 14.62in, N = 2134 rc/min, T=20°C. At T= 20°C ɣ=ρg= 62.35 lb/ft³, vapor pressure. Pv = 49.2 lb/ft².

The efficienies at each flow rate is computal by using formula

η = ρgθH / (550) (bhp)

→ As we can See the maximum efficiency point is at θ = 6ft³/s (close to 6ft³/s)

Maximum efficiency is η≅ 0.88 ≅ 88%

b) Given NPSHR = 16 ft,hg=22ft. Zactual. = 9ft  (below the sea surface)

To avoid cavitation NPSH < Pa - Pv/ρg - Z - hf

Z < Pa - Pv/ρg - hf

Z < 2116 - 49.2/62.35 - 16 - 22 [1 atm = 2116 lb/ft2]

Z≤ -4.852 ft

-> Keeping the pump 9 ft below the surface gives 4.148 ft of marign against cavitation.

Hence it is Sufficient to avoid cavitation.

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Answer:

Part A

The thickness of the compacted soil is approximately 4.3467 × 10⁻¹ m

Part B

The weight of water to be added is approximately 19886.\(\overline{36}\) kN, the volume of the water added is approximately 2,027.77 m³

Explanation:

The parameters of the soil are;

The volume of sol the excavator excavates, \(V_T\) = 10,000 m³

The moist unit weight, W = 17.5 kN/m³

The moisture content = 10%

The area of the project, A = 20,000 m²

The required dry unit weight = 18.3 kN/m³

The required moisture content = 12.5%

Part A

Therefore, we have;

The moist unit weight = Unit weight = (\(W_s\) + \(W_w\))/\(V_T\)

The moisture content, MC = 10% = (\(W_w\)/\(W_s\)) × 100

∴ \(W_w\) = 0.1·\(W_s\)

∴ The moist unit weight = 17.5 kN/m³ = (\(W_s\) + 0.1·\(W_s\))/(10,000 m³)

1.1·\(W_s\) = 10,000 m³ × 17.5 kN/m³ = 175,000 kN

\(W_s\) = 175,000 kN/1.1 = 159,090.\(\overline{09}\) kN

For the required soil, we have;

The required dry unit weight = 18.3 kN/m³ = \(W_s\)/\(V_T\) = 159,090.\(\overline{09}\) kN/\(V_T\)

\(V_T\) = 159,090.\(\overline{09}\) kN/(18.3 kN/m³) ≈ 8,693.4923 m³

The total volume of the required soil ≈ 8,693.4923 m³

Volume \(V_T\) = Area, A × Thickness, d

∴ d =  \(V_T\)/A

d = 8,693.4923 m³/(20,000 m²) ≈ 4.3467 × 10⁻¹ m

The thickness of the compacted soil ≈ 4.3467 × 10⁻¹ m

Part A

The moisture content, MC = 12.5% = (\(W_w\)/\(W_s\)) × 100

\(W_w\) = \(W_s\) × MC/100 = 159,090.\(\overline{09}\) kN × 12.5/100 = 19886.\(\overline{36}\) kN

The weight of water to be added, \(W_w\) = 19886.\(\overline{36}\) kN

Where the density of water, ρ = 9.807 kN/m³

Therefore, we have;

The volume of water, V = \(W_w\)/ρ

∴ V = 19886.\(\overline{36}\) kN/(9.807 kN/m³) ≈ 2027.77 m³

The volume of water, V ≈ 2027.77 m³

Answer:

Explanation:

In the Canadian country, it is possible that the country is able to produce either 100 units of lumber or 1000 lightbulbs. Then, 100 lumber is equal to 1000 bulbs in the home, and hence, one lumber is equivalent to 10 bulbs. Therefore, the opportunity cost of lumber in the home is ten bulbs.

Thus, the country's production possibilities frontier PPF is a linear combination of 100 lumber and 1000 bulbs. The graphical diagram of the production possibilities frontier PPF can be seen in the image below.

Country C is capable of producing either 100 units of lumber or 1,000 lightbulbs. Therefore, in the residence, \(100\ lumber = 1000\ bulbs\), and thus \(1 \ lumber = 10\ bulbs\). As a result, the economic cost of lumber within the residence is equal to 10 bulbs.

As a result, the proper answer is "Canada would focus on lumber production for its competitive advantage", therefore, following the trade, the country's CPF (BC) is a linear combination of 100 lumber and 2000 lights.

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The software industry is evolving, and software certification is crucial. ​Software certification is a digitally signed certificate that verifies the identification of an individual or company. ​

A certificate, sometimes known as a digital certificate, is a special document that has been digitally signed and authenticates the identity of a person or business.

Its validity may be checked using public-key cryptography to make sure that the program or website you are accessing is reliable.

Software developers must demonstrate that their program executes the XBRL conformance suites successfully in order to be certified.

They must also supply extra test cases so that XBRL employees can test the program further. The validity of certification is one year, renewable yearly.

Hence the software industry is evolving, and software certification is crucial. ​

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Answer:

This is an example of the conduction of electricity through metal. Free moving electrons on the car will conduct a electric field when a voltage is applied to the car;  in this case the transmission line, and would flow through the metal to the door handle causing electrocution.

The bronze C86100 pipe's maximum shear stress with an outer diameter of 1. 5 in. is around 16.98 psi.

To find the maximum shear stress in the pipe, use the formula:

τ = F / (2A)

where τ = shear stress, F = applied force, and A = area on which the force is acting.

Assume that the force is evenly distributed around the circumference of the pipe, so the area on which it is acting is equal to the circumference times the thickness:

A = πD t

where D = outer diameter and t = thickness.

Substituting the given values:

D = 1.5 in

t = 0.125 in

F = 20 lb

A = πD t = π(1.5)(0.125) = 0.589 in²

Therefore, the maximum shear stress is:

τ = F / (2A) = 20 / (2 × 0.589) = 16.98 psi

So the maximum shear stress in the pipe is approximately 16.98 psi.

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The minimum beta is given as 90 for which the tolerance of the transistor can be used.

We have the following values to solve this question with

gm of amplifier = 30mA/V

input resistance = 3000 ohm

We have transconductance as

\(\frac{I_{c} }{V_{T} } = 30mA/V\)

We have to consider the thermal voltage at Vt = 25mV when i tis occuring at the room temperature.

The collector bias would be solved by

Ic = 0.03Vt

= 0.03 x 0.025

= 0.75mA

Then we have to solve for the minimum value of the dc current as

β = gmγm

= 0.03 * 3000

= 90

Hence the minimum beta is given as 90

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Answer:

answer letter c

Explanation:

yun anserr hhehehe

The question can be approached using the concept of present value of an annuity of $1. The equation for present value of an annuity of $1 is:

PV = A x [(1 - (1 + i)^-n) / i]

FV = 1 x (1 + i ) n

Now, consider the given information: If one robot would prevent injury to soldiers or loss of equipment valued at $1.5 million per year, it would provide an annual payment of $1.5 million. The recovery period is 4 years at 8% per year.The interest rate is 8% and the number of periods is 4 years or 4 periods. Substituting these values in the equation for present value of an annuity of $1, we get:

PV = 1.5 x 10^6 x [(1 - (1 + 0.08)^-4) / 0.08]PV = 1.5 x 10^6 x

[(1 - 0.6355) / 0.08]PV = 1.5 x 10^6 x 8.0293PV = $12,043,950

The military could afford to spend

$12,043,950

now on the robot and still recover its investment in 4 years at 8% per year.

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Answer:

C. Gas tungsten arc welding

Explanation:

Arc welding processes that employ a continuous fed wire electrode uses a constant voltage power source. This type of power source has a flat volt-ampere curve. The welding current and the electrode feed rate are matched to rate of wire melting and transfer across the arc into the weld pool. A monitoring system is responsible for controlling electrode speed using the arc voltage.

It should be noted that Constant voltage is not used for the Gas tungsten arc welding.

Constant voltage can be regarded as the ability to fluctuate output current ,so that in this process set voltage can be maintained. and it is used where the workpieces do not have flat surfaces.

Constant voltage can be used for applications  such as welding process like;

Therefore, option C is correct because Constant voltage is not used for the

Gas tungsten arc welding.

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The values of h at the two internal boundaries are :

Given data :

Z₁ = Z₂ = Z₃ = 25 m

h top = 120 m

h bottom = 100 m

K₁ = 0.0001 m/s

K₂ = 0.0005 m/s

K₃ = 0.0010 m/s

we will apply the formula below since flow is perpendicular to the bedding plane

Keq = \(\frac{Z1 + Z2 + Z3 }{\frac{Z1}{K1}+\frac{Z2}{K2} + \frac{Z3}{K3} }\)  ----- ( 1 )

Insert values given above into equation 1

Therefore ; Keq = 2.307 * 10⁻⁴ m/s

Hydraulic gradient ( Ieq ) = head loss / length

                                          = ( 120 - 100 ) / 3 * 25

                                   Ieq  = 0.266

Given that the flow is perpendicular to bedding plane

q1 = q2 = q3

V₁ = V₂ = V₃ = V

K₁i₁ = K₂i₂ = K₃i₃ = Keq * ieq

Hence :

V = Keq* Ieq

   = 2.307 * 10⁻⁴ * 0.266

   = 6.15 * 10⁻⁵ m/s .

Also;

K₁i₁ =  Keq * ieq = K₂i₂ = K₃i₃

therefore :

  i₁ = 0.615

  i₂ =  0.123

  i₃ = 0.0615

Pressure at point 1 ( i.e. pressure between first two formations )

h₁ = h top - i₁L₁

   = 120 - 0.615 * 25

   = 104.625 m

Pressure at point 2 ( i.e. pressure between the 2nd and 3rd formation )

h₂ = h₁ - i₂L₂

    = 104.625 - 0.123 * 25

    = 101.55 m

Therefore we can conclude that The values of h at the two internal boundaries are :  h₁ = 104.625 m , h₂ = 101.55 m

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Answer:

0.05 mg / gallon

Explanation:

mass of chemecila coming in per minute = 50*10 = 500 mg/min

at a time t min , M = mass of chemical = 500*t mg

conecntartion of chemecal = 500t/10000 = 0.05 mg / gallon

Answer:

currently states that a person is qualified to drive a commercial motor vehicle if he/she “can read and speak the English language sufficiently to converse with the general public, to understand highway traffic signs and signals

So I think B

Answer:

35 feet

Explanation:

Answer:

Turn-on and turn-off characteristics of an SCR are called the dynamic characteristics of the SCR.

The diagram for the extraction to represent the information given is attached.

Extraction refers to the process of obtaining or removing something from a particular source or location. It can refer to various fields such as chemistry, physics, medicine, and data analysis.

In chemistry, extraction is the process of separating a particular component or substance from a mixture using various methods such as solvent extraction, distillation, or chromatography. In physics, extraction can refer to the removal of energy or particles from a system. In medicine, extraction refers to the removal of a tooth or a foreign object from the body. In data analysis, extraction refers to the process of retrieving specific data or information from a large set of data.

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Answer:

"Physical" would be the right approach.

Explanation:

So the answer here is just the perfect one.

Answer:

A split point twist drill is a self-centering speed bit with a cutting angle of 135 degrees. It is specifically designed to drill into metal and other hard materials without wandering around on the surface.

Answer:

actually, it was John Doe and Jane Doe, as they were created as testers on the exact same say when Roblox was created.

Explanation:

The first  player was builderman. Option C

The first player was one whose user handle was builderman.

However, the account was terminated. It was replaced with

‘Builderman’ is the account that belonged to the CEO and Co-Founder of , David Baszucki. He manages all of the admins.

When you make a new account, he's automatically your friend.

Note that ‘John Doe’ and ‘Jane Doe’ were two test accounts that were created by David.

The accounts were later rumored to hack others’

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Answer:
Blowdown is the process of discharging water and undesirable accumulated material from a boiler.

Answer: yes because fish its like quick sand is will just fall apart into tiny pecies to now it want us to round to the nearst hundredth so what is 12 divide by 3 and time 1

12:3x1=4 because we are rounding to the nearst hundredth

=4

Explanation:

The material property does the Charpy test determine is:(d) Toughness.

The Charpy impact test is utilized to determine the toughness of a material, specifically its ability to absorb energy when subjected to an impact load. Toughness, in this case, is defined as the ability of a material to resist the propagation of cracks or other flaws when subjected to dynamic or impact loading. In materials science, toughness is often described as the area under the stress-strain curve of a material up to its point of failure.  A pendulum hammer is used to hit the sample at the notched part with a specific amount of force.

The amount of energy absorbed by the sample is calculated by measuring the height difference between the point at which the pendulum starts to fall and the point where it swings up to after striking the sample. The energy absorbed during the fracture is proportional to the reduction in the height of the pendulum and is used to determine the toughness of the material. Therefore, the Charpy test is mainly used to determine the toughness of a material, making the correct option (d) Toughness.

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The Charpy test determines the toughness of a material.What is the Charpy test.The Charpy test is a test that measures a material's resistance to brittle fracture.

The test's results are critical in determining a material's serviceability in cold temperatures or environments where impact loading is possible. It is mostly used to assess the resistance of a material to impact loading. It involves striking a notched specimen with a swinging pendulum to produce a fracture and then measuring the amount of energy absorbed by the specimen.What is toughness,Toughness is the ability of a material to resist cracking when subjected to high-stress conditions. Toughness is defined as the amount of energy a material can absorb before it breaks. In general, materials with higher toughness are more durable. Toughness is critical in the construction of buildings, bridges, airplanes, ships, and other structures subjected to sudden and unpredictable impact forces.What material property does the Charpy test determine.The Charpy test determines the toughness of a material. The Charpy test is a common method for determining a material's toughness. The test is frequently used in construction and engineering to assess the impact resistance of materials. The toughness of a material, measured in joules, can be determined using the Charpy test.

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a. a = 12 is the solution to the given congruence relation. b. the positive integers less than 12 that are relatively prime to 12 are 1, 5, 7, and 11.

(a) The main answer: The integer a that satisfies a ≡ -15 (mod 27) is 12.

To find the value of a, we need to consider the congruence relation a ≡ -15 (mod 27). This means that a and -15 have the same remainder when divided by 27.

To determine the value of a, we can add multiples of 27 to -15 until we find a number that falls within the range of {0, 1,..., 26}. By adding 27 to -15, we get 12. Therefore, a = 12 is the solution to the given congruence relation.

(b) The main answer: The positive integers less than 12 that are relatively prime to 12 are 1, 5, 7, and 11.

Supporting explanation: Two integers are relatively prime if their greatest common divisor (GCD) is 1. In this case, we are looking for positive integers that have no common factors with 12 other than 1.

To determine which numbers satisfy this condition, we can examine each positive integer less than 12 and calculate its GCD with 12.

For 1, the GCD(1, 12) = 1, which means it is relatively prime to 12.

For 2, the GCD(2, 12) = 2, so it is not relatively prime to 12.

For 3, the GCD(3, 12) = 3, so it is not relatively prime to 12.

For 4, the GCD(4, 12) = 4, so it is not relatively prime to 12.

For 5, the GCD(5, 12) = 1, which means it is relatively prime to 12.

For 6, the GCD(6, 12) = 6, so it is not relatively prime to 12.

For 7, the GCD(7, 12) = 1, which means it is relatively prime to 12.

For 8, the GCD(8, 12) = 4, so it is not relatively prime to 12.

For 9, the GCD(9, 12) = 3, so it is not relatively prime to 12.

For 10, the GCD(10, 12) = 2, so it is not relatively prime to 12.

For 11, the GCD(11, 12) = 1, which means it is relatively prime to 12.

Therefore, the positive integers less than 12 that are relatively prime to 12 are 1, 5, 7, and 11.

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