please find ur answer in the attached image, mark as brainliest if it helps.
Conversion Chart Temperature °C= 5/9 (°F - 32) Time 60 seconds = 1 minute 60 minutes = 1 hour 24 hours = 1 day Mass 1 pound = 16 ounces 1 ounce = 28.35 grams 1000 milligrams = 1 gram 1000 grams = 1 kilogram Length 1 mile = 1.6 kilometers 1 inch = 2.54 centimeters 100 centimeters = 1 meter 1000 meters = 1 kilometer Conversions for temperature, time, mass, and length.
1. 46,756,790 mg = _______ kg
2. 5.6 hours = ________ seconds
3. 13.5 cm = ________ inches
4. 47 °F = _______ °C
46,756,790 mg = 46.75679 kg
5.6 hours = 20,160 seconds
13.5 cm = 5.315 inches
47 °F = 8.333 °C
To convert milligrams (mg) to kilograms (kg), we divide the value by 1,000,000 (since there are 1,000,000 milligrams in a kilogram). Therefore, 46,756,790 mg divided by 1,000,000 equals 46.75679 kg.
To convert hours to seconds, we multiply the value by 3,600 (since there are 3,600 seconds in an hour). Therefore, 5.6 hours multiplied by 3,600 equals 20,160 seconds.
To convert centimeters (cm) to inches, we divide the value by 2.54 (since there are 2.54 centimeters in an inch). Therefore, 13.5 cm divided by 2.54 equals 5.315 inches.
To convert Fahrenheit (°F) to Celsius (°C), we use the formula °C = 5/9 (°F - 32). Plugging in the value 47 °F into the formula, we get °C = 5/9 (47 - 32), which simplifies to °C = 5/9 (15) = 75/9 ≈ 8.333 °C.
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Can someone please give me the (Answers) to this? ... please ...
Answers:
1. Newton's second law states that the force on an object is equal to its mass times its acceleration. Equation: F = ma, or force is equal to mass times acceleration.
2.
a=F/ma= 120N/68kga=(120 kg x m/s^2)/ (68kg)a = 1.8 m/s^23. a = 0.25 m/s^2
4. a = 0.4 m/s^2
If a hailstone falling from certain height melts completely by just reaching the ground. then which of the following could be best reason
a. Heated by friction
b. Potential energy absorbed by latent heat c. PE absorbed by KE
d. Impossible to say
Answer: the answer is b
Explanation: becuse the friction of the air heats it
helioseismology is the study of oscillations in the solar interior. true or false
Helioseismology is the study of oscillations in the solar interior which is true. Helioseismology is the study of the structure and dynamics of the Sun through its oscillations.
Helioseismology is the study of the structure and dynamics of the Sun through its oscillations. These oscillations are caused by sound waves that are continuously driven and damped by convection near the Sun's surface. Helioseismology is similar to seismology, or asteroseismology, which are respectively the studies of the Earth or stars through their oscillations.
By studying the oscillations of the Sun, helioseismologists can infer the Sun's interior structure, including its temperature, density, and rotation rate. They can also study the Sun's magnetic field and its activity cycles. Helioseismology has been used to confirm our understanding of how stars work, and it has also helped us to discover new things about the Sun.
Here are some of the things that helioseismology has revealed about the Sun:
The Sun's core is much hotter than its surface.
The Sun's rotation rate is faster at the equator than at the poles.
The Sun's magnetic field is generated by a dynamo effect in the core.
The Sun's activity cycle is caused by changes in the Sun's magnetic field.
Helioseismology is a powerful tool for studying the Sun, and it is still being used to learn new things about our star.
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For the following six questions, match the descriptions to the below people (A-J)
A) Eratosthenes B) Aristarchus C) Isaac Newton D) Aristotle E) Ptolemy F) Galileo G) Hipparchus H) Kepler I) Nicolaus Copernicus J) Tycho Brahe
23. Discovered the phases of Venus using a telescope.
24. First to consider ellipses as orbits.
25. Foremost ancient Greek philosopher.
26. Ancient Greek who believed in a sun-centered universe.
27. First to measure the size of the Earth to good accuracy.
28. Developed the first predictive model of the solar system.
The correct match of the descriptions to the below people are 23 - F, 24 - H, 25 - D, 26 - I, 27 - A, 28 - B.
23 - F Galileo: Galileo Galilei is credited with discovering the phases of Venus using a telescope. Through his observations, he observed that Venus went through a series of phases similar to those of the Moon, which supported the heliocentric model of the solar system.
24 - H Kepler: Johannes Kepler was the first to consider ellipses as orbits. He formulated the laws of planetary motion, known as Kepler's laws, which stated that planets move in elliptical paths with the Sun at one of the foci. Kepler's work revolutionized our understanding of celestial mechanics.
25 - D Aristotle: Aristotle, the ancient Greek philosopher, is considered one of the foremost thinkers in history. While his contributions span various fields, including philosophy and natural sciences, his views on astronomy were geocentric. He believed that the Earth was the center of the universe and that celestial bodies moved in perfect circles around it.
26 - I Nicolaus Copernicus: Nicolaus Copernicus was an astronomer who proposed the heliocentric model of the solar system, in which the Sun, rather than the Earth, was at the center. Copernicus's revolutionary idea challenged the prevailing geocentric view and laid the foundation for modern astronomy.
27 - A Eratosthenes: Eratosthenes was an ancient Greek mathematician and astronomer who made significant contributions to geography and astronomy. He is known for his accurate measurement of the Earth's circumference. By measuring the angle of the Sun's rays at two different locations, he estimated the Earth's circumference with remarkable accuracy.
28 - B Aristarchus: Aristarchus of Samos is credited with developing the first predictive model of the solar system. He proposed a heliocentric model centuries before Copernicus, suggesting that the Sun was at the center of the universe, with the Earth and other planets orbiting it. Aristarchus's model was a significant departure from the prevalent geocentric view of the time.
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Why is it important to be careful interpreting absolute ages of clastic sedimentary rocks such as sandstones?
Answer:
You need to be careful when finding the true age of sedimentary rocks to understand its full history.
Explanation:
What is the mass of a 3920 newton desk?
Weight is defined as the force on an object that results from acceleration or gravity.
It can be calculated as:
W=mg
W= weight of an object (Newtons)
m = mass of the object (kilograms)
g = gravity (m/s^2)
given the information we can rearrange for m:
\(m=\frac{3920N}{9.8m/s^2}\)
\(m=400 kg\)
Traveling from city A to city B, a train accelerates from rest at 0.020 m/s2 for 10.0 min, then maintains its speed for the next 30.0 min. It then begins decelerating at 0.075 m/s2, until stopping in city B. How far is city A from city B
Using the kinematic equation, Δd = vi*t + 1/2*a*t² where Δd is the distance, vi is the initial velocity, a is the acceleration, and t is the time, we can calculate the distance between city A and city B.
Using the first part of the journey, where the train is accelerating:
vi = 0 (since it starts from rest)a = 0.020 m/s²t = 10 min = 600 sΔd = 0*600 + 1/2*(0.020)*(600)² = 3600 m
Using the second part of the journey, where the train maintains its speed:vi = 0.020 m/s (since it maintains its speed) a = 0 (since it's not accelerating)t = 30 min = 1800 sΔd = 0.020*1800 = 36 m
Using the third part of the journey, where the train is decelerating:vf = 0 (since it stops) a = -0.075 m/s² (since it's decelerating)The initial velocity can be found using the kinematic equation, vf = vi + at, where vf is the final velocity. Rearranging this equation gives vi = (vf - at).vi = (0 - (-0.075)*t) = 0.075tΔd = 0*t + 1/2*(-0.075)*(t)² = -0.0375t²
Since we know that the total time of the journey is 40 minutes = 2400 s, we can combine the three parts of the journey to get the total distance:Δd(total) = Δd1 + Δd2 + Δd3Δd(total) = 3600 + 36 + (-0.0375)*(2400 - 600 - 1800)²Δd(total) = 3576 m
Therefore, the distance between city A and city B is 3576 m. Given the acceleration of the train in each phase of its motion and the total time of its journey, we can determine the distance between city A and city B.
To calculate the distance, we must first find the distance travelled during each phase of the journey. During the first phase, the train is accelerating from rest. We can use the kinematic equation, Δd = vi*t + 1/2*a*t², to determine the distance. The initial velocity is 0 since the train is starting from rest. The acceleration is 0.020 m/s², and the time is 10.0 minutes or 600 seconds. Plugging these values into the equation, we get:Δd1 = 0*600 + 1/2*(0.020)*(600)² = 3600 m
During the second phase, the train is maintaining its speed. Since it is not accelerating, we can use the formula Δd = vi*t, where vi is the initial velocity and t is the time. The initial velocity is 0.020 m/s since that is the speed it reached during the first phase. The time is 30.0 minutes or 1800 seconds. Plugging these values into the equation, we get:
Δd2 = 0.020*1800 = 36 m
During the third phase, the train is decelerating until it comes to a stop. We can again use the kinematic equation, Δd = vi*t + 1/2*a*t². Since the train comes to a stop, the final velocity is 0. The acceleration is -0.075 m/s² since it is decelerating. The time is the difference between the total time and the times for the first two phases, which is (2400 - 600 - 1800) = 0 seconds. We can also find the initial velocity using the formula vf = vi + at, where vf is the final velocity. Rearranging this equation, we get vi = (vf - at). Plugging in the values, we get:
vi = (0 - (-0.075)*t) = 0.075tΔd3 = 0*t + 1/2*(-0.075)*(t)² = -0.0375t²
The total distance travelled is the sum of the distances for each phase:
Δd(total) = Δd1 + Δd2 + Δd3Δd(total) = 3600 + 36 + (-0.0375)*(2400 - 600 - 1800)²Δd(total) = 3576 m.
Therefore, the distance between city A and city B is 3576 m. Therefore, the distance between city A and city B is 3576 m.
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The crests of waves passing into a harbor are 2.1 m
apart and have an amplitude of 60 cm. 12 waves
pass an observer every minute.
The speed of the wave is 0.42 m/s.
What is speed?Speed is the rate of change of distance.
To calculate the speed of the wave, we use the formula below,
Formula:
v = λf..................... Equation 1Where:
v = Speed of the waveλ = Wavelength of the wavef = Frequency of the waveFrom the question,
Given:
f = (12/60) = 0.2 Hzλ = 2.1 mSubstitute these values into equation 1
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Complete question: The crests of waves passing into a harbor are 2.1 m
apart and have an amplitude of 60 cm. 12 waves
pass an observer every minute. What is the speed of the wave.
What is the independent variable?
Answer:
a variable (often denoted by x ) whose variation does not depend on that of another.
The diagram shows how states of matter can change when energy is either added or removed.
System before change
System after change
00000
00000
00000
00000
00000
00000
00000
All of these statements below are true EXCEPT
Energy was added to the matter causing the particle movement to increase.
The matter changed states which is a physical change.
The particles in the matter before the change had more energy than after the change.
The particles in the matter before the change had less energy than after the change
A change in temperature frequently causes substances to change phases. Most substances are solid at low temperatures; as the temperature rises, they become liquid; and at still greater temperatures, they become gaseous.
Melting is the conversion of a solid into a liquid (an older term that you may see sometimes is fusion). Solidification is the process where a liquid turns into a solid. The melting point, or the temperature at which a pure substance begins to melt, is a property of that substance. A solid must expend energy to become a liquid. A specific quantity of energy is required by every pure substance in order to transform from a solid to a liquid. This amount is known as the substance's enthalpy of fusion (or heat of fusion).
The complete question is- The diagram shows how states of matter can change when energy is either added or removed.
System before change
System after change
00000
00000
00000
00000
00000
00000
00000
All of these statements below are true EXCEPT
Energy was added to the matter causing the particle movement to increase.
The matter changed states which is a physical change.
The particles in the matter before the change had more energy than after the change.
The particles in the matter before the change had less energy than after the change.
the diagram is attached below.
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A 1250 kg Nascar is at the starting line. The race starts and the car reaches a speed of 30
m/s in 10 seconds. What is the force of the car? (Hint: Remember that acceleration
change in velocity / time.)
Answer:
force=1250kg * 30m/s+10
Explanation: it's a change in acceleration
In peas, yellow seed the generation of a monohybrid cross that begins when a dominant homozygote is crossed with a recessive homozygote, you would expecta. three plants with yellow seeds to every plant with green seeds.b. plants with one yellow seed for every green seed.c. only plants with the genotype Yy.d. only plants that produce yellow seeds.e. Both c and d are correct.
In peas, yellow seed the generation of a monohybrid cross that begins when a dominant homozygote is crossed with a recessive homozygote, you would expecta. three plants with yellow seeds to every plant with green seeds.
According to the law of dominance, the dominant allele or trait manifests itself in both homozygous and heterozygous states.A parent may have two different alleles for the same gene on a pair of two chromosomes, according to the law of segregation. In the second cell division of meiosis, these two alleles split apart.The law of independent assortment states that the meiotic separation of two allele pairs has no bearing on the meiotic separation of other allele pairs.We must apply the laws of dominance and segregation in this situation in order to receive a response. First, we need to cross over dominant homozygous alleles and recessive homozygous alleles in this situation. Yellow seeds are dominant in the scenario at hand, while green seeds are recessive.α+β⇄ω+∨↓
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The 39-kg homogeneous smooth sphere rests on the 24° incline A and bears against the smooth vertical wall B. Calculate the contact force at A and B. Assume 0 = 24° B Ꮎ Answers: FA i FB = II i A N
The contact forces at points A and B on a 39-kg homogeneous smooth sphere resting on a 24° incline can be calculated. The answer is \(FA = FB = 39 kg * 9.8 m/s^2 * sin(24^0)\).
For calculating the contact forces at points A and B, start by considering the forces acting on the sphere. The weight of the sphere acts vertically downward and can be calculated as the mass of the sphere (39 kg) multiplied by the acceleration due to gravity (\(9.8 m/s^2\)).
Since the sphere is in equilibrium, the contact force at point A must balance the composition of the weight parallel to the incline. This component can be found by multiplying the weight by the sine of the incline angle (24°). Thus,
\(FA = 39 kg * 9.8 m/s^2 * sin(24^0)\).
Similarly, the contact force at point B must balance the component of the weight perpendicular to the incline. Since the wall is smooth, there is no friction, and the contact force only needs to counteract the perpendicular component of the weight. Therefore,
\(FB = 39 kg * 9.8 m/s^2 * sin(24^0)\).
To summarize, the contact forces at points A and B are both equal to \(FA = FB = 39 kg * 9.8 m/s^2 * sin(24^0)\).
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a 195-kg object and a 495-kg object are separated by 4.80 m. (a) find the magnitude of the net gravitational force exerted by these objects on a 49.0-kg object placed midway between them. incorrect: your answer is incorrect. draw a picture of the three objects, including the forces exerted on the third. n (b) at what position (other than an infinitely remote one) can the 49.0-kg object be placed so as to experience a net force of zero from the other two objects? m from the 495 kg mass toward the 195 kg mass
A 195-kg object and a 495-kg object are separated by 4.80 m. In order to experience zero net force, the third object of 49 kg should be placed 1.85 m from the 195-kg object.
The formula for the gravitational force between 2 objects is given by:
F = G ⋅ M ⋅ m/r²
Where:
G = gravitational constant = 6.674×10⁻¹¹ m³⋅kg⁻¹⋅s⁻²
M = mass of object 1
m = mass of object 2
r = distance between 2 objects
In the given problem, let:
M1 = 195 kg
M2 = 495 kg
m = 49 kg
a) m is placed in the middle of M1 and M2
r = 4.8/2 = 2.4
Force on m exerted by M1
F1 = G ⋅ 195 ⋅ 49/(2.4)² = 1.1×10⁻⁷ N
Force on m exerted by M2
F2 = G ⋅ 495 ⋅ 49/(2.4)² = 2.8×10⁻⁷ N
Net force = (2.8 - 1.1) ×10⁻⁷ = 1.7 ×10⁻⁷ N
b) Net force on m = 0
Let d be the distance between M1 and m, then the distance between M2 and m is (4.8 - d)
r = 4.8/2 = 2.4
F1 = F2
G ⋅ 195 ⋅ 49/(d)² = G ⋅ 495 ⋅ 49/(4.8 - d)²
4.8 - d = 1.59 d
2.59 d = 4.8
d = 1.85 m
Hence, the object m should be placed 1.85 m from M1 so that the net force on it = 0
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In the middle of a thunderstorm, a lightning bolt flashes. It takes Roberto 5 seconds to
hear the thunder afterwards. How far is the source of lightning from Roberto? The temperature is 22° C.
Speed of sound at 22°C = ?
d = ?
You will be reported if you didn't answer properly
Answer:
v = 344.1 m / s
d = 1720.5 m
Explanation:
For this problem we must calculate the speed of sound in air at 22ºC
v = 331 RA (1+ T / 273)
we calculate
v = 331 RA (1 + 22/273)
v = 344.1 m / s
the speed of the wave is constant,
v = d / t
d = v t
we calculate
d = 344.1 5
d = 1720.5 m
A person is going to take a trip from town eight to town D to do this they travel 60 KM in .45 hour And then stop in town before lunch it takes. 15 hour in the journey continues to town see over .5 hour and covers a distance of 30 KM they had to stop and pick up an item at the store that took .15 hour they restart their trip it took 1.5 hours to get to town which is 90 came away from town see what was a numerical value for the average speed of the trip
Answer:
v = 72 km / h
Explanation:
The definition of average speed is the distance traveled between the time interval
v = Δx / Δt
let's find the distance traveled
x = 60 + 30
x = 90 km
time spent, all time must be included, travel time and when stopped
t = 0.45 + 0.15 + 0.5+ 0.15
t = 1.25 h
we substitute in the initial equation
v = 90 / 1.25
v = 72 km / h
in going from one city to the other
The function d(v) = 0.0067 v^2 + 0.15v can be used to determine the safe stopping distance, d(v), in metres for a car given its speed, v, in kilometres per house. determine the speed at which a car can be traveling in order to be able to stop at a distance of 24m. show your work and round your final answer(s) to the nearest meter.
Evaluate the function when d(v) = 24.
\(\begin{gathered} 24=0.0067v^2+0.15v \\ 0.0067v^2+0.15v-24=0 \end{gathered}\)Use the quadratic formula to find v.
\(v=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}\)Where a = 0.0067, b = 0.15, and c = -24.
\(\begin{gathered} v=\frac{-0.15\pm\sqrt[]{0.15^2-4\cdot0.0067\cdot(-24)}_{}}{2\cdot0.0067}=\frac{-0.15\pm\sqrt[]{0.6657}_{}}{0.0134} \\ v_1=49.7\cdot\frac{km}{hr}_{} \\ v_2=-72.1\cdot\frac{km}{hr} \end{gathered}\)Therefore, the car should travel at 49.7 km/hr.
We take the positive speed as the answer.
A 4.4 nC charge exerts a repulsive force of 36 mN on a second charge which is located
a distance of 0.70 m away from it. What is the charge (magnitude and sign) of the
second charge?
The magnitude and sign of the second charge will be + 8.6241×10⁻¹⁹ C. The principal of the Columb's law is used in the given problem.
What is Columb's law?The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
Charges that are similar repel each other, whereas charges that are diametrically opposed attract each other.
They will repel, moving in opposite directions at the same speed. Because the magnitude and nature of the charge are the same.
The given data in the problem is;
q₁ is the charge 1 = 4.4 nC = 4.4 ×10⁻⁹ C
F is the repulsive force = 36 mN =36 ×10⁶ N
d is the distance = 0.70 m
The Coulomb force is found as;
\(\rm F = \frac{Kq_1q_2}{r^2}\\\\\ \rm 36\times 10^6 = \frac{9 \times 10^9 }{(0.7)^2} \times 4.4 \times 10^{-9} \times q_2\\\\\ q_2 = 8.6241 \times 10^{-19 } \ C\)
Hence, the magnitude and sign of the second charge will be + 8.6241×10⁻¹⁹ C.
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The surface of a small lake froze, reaching thermal equilibrium with the air above it at -5ºC. The bottom of the lake is at 4ºC. Determine the width of the ice surface, knowing that the depth of the lake plus the ice surface equals 1.4 m.
Make all necessary assumptions for the above case. (Use thermal equilibrium and Fourier's law of conduction)
The width of the ice surface is 0.108 meters or approximately 11 centimeters of thermal equilibrium.
What, using an illustration, is thermal conductivity?Actually, thermal conductivity is concerned with the transmission or conduction of heat. 2) Due to the heat transfer from the tea to the cup, pouring hot tea into a cup will result in the cup becoming heated as well.
The rate of heat transfer through the ice surface is calculated using Fourier's rule of heat conduction as follows:
q1 = k1 * A * (T1 - T2) / x
Similarly, the rate of heat transfer through the lake is:
q2 = k2 * A * (T2 - T3) / d
We can set q1 = q2 and solve for x because the rates of heat transmission through each layer are equal:
k1 * A * (T1 - T2) / x = k2 * A * (T2 - T3) / d
Simplifying and rearranging, we get:
x = k1 * d * (T1 - T2) / (k2 * (T2 - T3))
Substituting the given values, we get:
x = 2.18 * 1.4 * (4 - (-5)) / (0.606 * (-5 - (-0)))
x = 0.108 m
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a watermelon is balanced by a dog, a pumpkin, a flowerpot, and a baseball as shown below. Is the weight of the watermelon equal to the dog, pumpkin , flowepot, and baseball? why or why not?
Answer:
pumpkin
Explanation:
watermelon and pumpkins are close to shape and size
You get out of school and walk north for 20 minutes. You travel
1.6 km. What is your average velocity?
What is the
Answer:
\(\boxed {\boxed {\sf v= 0.08 \ km/min \ North}}\)
Explanation:
Velocity is found by dividing the displacement by the time.
\(v=\frac{s}{t}\)
where s is the displacement and t is the time.
The displacement is 1.6 kilometers, but it needs a direction as well. The question notes you walked North. The time is 20 minutes.
\(s= 1.6 \ km \ North \\t= 20 \ min\)
\(v=\frac{1.6 \ km \ North} { 20 \ min}\)
Divide.
\(v= 0.08 \ km/min \ North\)
Velocity is a vector quantity, so that is why it has the measurement and the direction.
The average velocity is 0.08 kilometers per minute North.
Answer:
Are there no moderators here?
Who are moderators here?
Well, the above answer is correct..
✨
The table shows the percentage of carbon dioxide in the Earth’s atmosphere in the years 1800 and 2013. Calculate the difference in the mass of carbon dioxide in 500 kg of air in 2013 compared to 1800. Select the correct answer.
The difference in the mass of carbon dioxide in 500 kg of air in 2013 compared to 1800 is 0.06 Kg
Data obtained from the questionYear 1800 percent = 0.028%Year 2013 percent = 0.040%Mass of air = 500 KgDifference =?How to determine the mass of CO₂ in 500 Kg in year 1800Year 1800 percent = 0.028% Mass of air = 500 KgMass of CO₂ =?Mass = percent × mass of air
Mass of CO₂ = 0.028% × 500
Mass of CO₂ = 0.14 Kg
How to determine the mass of CO₂ in 500 Kg in year 2013Year 1800 percent = 0.040% Mass of air = 500 KgMass of CO₂ =?Mass = percent × mass of air
Mass of CO₂ = 0.040% × 500
Mass of CO₂ = 0.2 Kg
How to determine the differenceMass of CO₂ in year 1800 = 0.14 KgMass of CO₂ in year 2013 = 0.2 KgDifference =?Difference = mass in 2013 - mass in 1800
Difference = 0.2 - 0.14
Difference = 0.06 Kg
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at the instant shown, rank these six scenarios on the basis of the magnitude of the current in the light bulb.
At the instant shown, the six scenarios can be ranked in terms of the magnitude of current in the light bulb as follows:
1) Scenario 1 - Here, the battery is directly connected to the light bulb without any other resistors in the circuit. Therefore, the current flowing through the bulb will be the maximum among all the scenarios.
2) Scenario 3 - In this case, the battery is connected to the light bulb through a resistor. However, the resistance is less compared to other scenarios, so the current will be higher than in other cases.
3) Scenario 4 - Here, the battery is connected to the light bulb through a higher resistance compared to scenario 3. This will result in a lesser current in the bulb.
4) Scenario 5 - In this scenario, the battery is connected to the light bulb through a much higher resistance than in the previous two scenarios. Therefore, the current flowing through the bulb will be lower.
5) Scenario 6 - Here, the battery is connected to the circuit in such a way that the current will bypass the light bulb. Therefore, the bulb will not light up and the current flowing through it will be zero.
6) Scenario 2 - This scenario is similar to scenario 6 where the switch is open, so the circuit is not complete, and hence there will be no current flowing through the light bulb.
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What is 38 Celsius fever in Fahrenheit?
Answer:
100.4°F
Explanation:
F = (9/5)C + 32
F = (9/5)(38) + 32 = (342/5) + 32 = 100.4°F
Fahrenheit is a temperature scale where the freezing point of water is 32 degrees and the boiling point is 212 degrees. 38 Celsius fever in Fahrenheit is 100.4 F
What is Fahrenheit?
Fahrenheit is a temperature scale where the freezing point of water is 32 degrees and the boiling point is 212 degrees. It is commonly used in the United States and some parts of the world, while other countries use the Celsius temperature scale. The Fahrenheit scale was created by German physicist Daniel Gabriel Fahrenheit in 1724. The scale is named after him. To convert from Celsius to Fahrenheit, use the formula F = (9/5)C + 32, where C is the temperature in Celsius and F is the temperature in Fahrenheit. To convert from Fahrenheit to Celsius, use the formula C = (5/9)(F-32). Fahrenheit is still used in science, medicine, and some industrial applications. It is also used by meteorologists and to report temperatures in the United States.
38 Celsius fever in Fahrenheit = 100.4 F38 Celsius = 100.4 Fahrenheit 38 Celsius x (9/5) + 32 = 100.4 Fahrenheit
Therefore, 38 Celsius fever in Fahrenheit = 100.4 F
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a test has power 0.80 when μ = 3.5. state whether the following statements are true or false.
The statements are as follows:
1. If μ is increased to 4.0, the power of the test will increase.
2. If the power of the test is increased to 0.90, μ must be greater than 3.5.
1. True. The power of a test increases as the difference between the null hypothesis and the true population parameter (in this case, μ) increases. Therefore, if μ is increased from 3.5 to 4.0, the power of the test will increase as well.
2. False. The power of a test depends on several factors, including the sample size, the level of significance, and the effect size (i.e., the difference between the null hypothesis and the true population parameter). Therefore, it is possible to increase the power of the test without increasing μ. This could be done by increasing the sample size, decreasing the level of significance, or increasing the effect size through other means.
the first statement is true and the second statement is false.
The power of a test is the probability that the test correctly rejects the null hypothesis when the alternative hypothesis is true. In this case, the power of the test is given as 0.80 when the population mean (μ) is 3.5. This means that there is an 80% chance that the test will correctly reject the null hypothesis when the true population mean is 3.5.
The statement "A test has power 0.80 when μ = 3.5" is true, as it indicates the probability of correctly rejecting the null hypothesis when the true population mean is 3.5.
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find w such that the maximum tensile bending stress is 3 ksi
To find the value of w that will result in a maximum tensile bending stress of 3 ksi, we first need to determine the moment of inertia of the cross-sectional shape of the material in question. Once we have this value, we can use the following formula to calculate the maximum tensile bending stress:
σ = M*c/I
Where σ is the maximum tensile bending stress, M is the bending moment, c is the distance from the neutral axis to the outermost fiber, and I is the moment of inertia.
Assuming that the bending moment is known, we can rearrange the formula to solve for the required value of w:
w = (M*c)/(I*σ)
This will give us the required width of the material to ensure that the maximum tensile bending stress does not exceed 3 ksi. Please note that this is a long answer that requires additional information about the material and the conditions under which it will be used.
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I need help with this question and please show the whole work
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If a star displays \( 0.0190 \) arcseconds of parallax, then long would it take to travel to that star if traveling at half the speed of light?
The first step is to convert the parallax angle of the star to distance. We can use the formula: parallax angle in arc seconds = (distance to star in parsecs)^-1 We can rearrange this equation to isolate distance: d = (parallax angle)^-1 Therefore, the distance to the star in parsecs is:
d = (0.0190 arcseconds)^-1 = 52.6 parsecs Next, we need to find the actual distance in meters. One parsec is equivalent to 3.09 × 10^16 meters. Therefore, the distance to the star in meters is: distance = (52.6 parsecs)(3.09 × 10^16 meters/parsec) = 1.63 × 10^18 meters Now, we can use the formula for time: d = vt Solving for time: t = d/v We are told to travel at half the speed of light, which is v = 0.5c, where c is the speed of light.
Therefore, the time to travel to the star is: t = (1.63 × 10^18 meters)/(0.5c) Using the speed of light, c = 3.00 × 10^8 m/s, we get: t = (1.63 × 10^18 meters)/(0.5 × 3.00 × 10^8 m/s)t ≈ 10.9 years Therefore, it would take about 10.9 years to travel to the star if traveling at half the speed of light.
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Definition of complex machine
Answer:A complex system is a system composed of many components which may interact with each other.
Explanation: hope this helped!
a pole vaulter clears a height of 6.00 m. with what velocity does the vaulter strike the mat in the landing area?
The vaulter has cleared a height of 6.00 m, and so their velocity at the landing area is 11.44 m/s.
The velocity of the pole vaulter striking the mat in the landing area is determined by the equation v = sqrt(2gh), where v is the velocity of the vaulter, g is the acceleration due to gravity (9.81 m/s2), and h is the height cleared by the vaulter. In this case, h = 6.00 m, so the velocity of the vaulter striking the mat is v = sqrt(2*9.81*6.00) = 11.44 m/s.
To better understand this equation, we need to consider Newton's Second Law of Motion, which states that F = ma, or force is equal to mass times acceleration. In pole vaulting, the vaulter's force is the force of gravity on the body, which is determined by the equation F = mg, where m is the mass of the vaulter and g is the acceleration due to gravity.
From Newton's Second Law, we can derive the equation for velocity: v = sqrt(2gh), where h is the height of the jump. This equation states that the velocity of the vaulter is proportional to the square root of the height they clear. In this case, the vaulter has cleared a height of 6.00 m, and so their velocity at the landing area is 11.44 m/s.
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