The equation of line s is y=13x−3
.

The equation of line t is y=−x+5
.

The equations of lines s and t form a system of equations. The solution to the system of equations is located at point P.

What are the coordinates of point P? Use the graph below to help you if needed.

Answers

Answer 1

When the solution of the equation is on point be, then the graph will look like graph (C).

What is the equation of the line?

The formula for a straight line is y=mx+c where c is the height at which the line intersects the y-axis, also known as the y-intercept, and m is the gradient.

Y = m x + c y=mx+c y=mx+c is the universal equation for a straight line, where m is the gradient and c is the y-intercept.

By determining the gradient and the y-intercept, and then using these numbers in the equation, we can determine the equation of a straight line.

So, the correct graph would be:

We have:
y=-x+5

Then,

-x+5=1/3x-3

-x+8=1/3x

8=4/3x

6=x

So, the graph:

y=-6+5

y=-1 (C)

Therefore, when the solution of the equation is on point be, then the graph will look like graph (C).

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Complete question:

The equation of line s is y=1/3x-3. The equation of line t is y=-x+5. the equations of lines s and t form a system of equations. The solution to the system of equations is located at point P. What would the graph look like?

The Equation Of Line S Is Y=13x3.The Equation Of Line T Is Y=x+5 .The Equations Of Lines S And T Form

Related Questions

please give me the correct answer! thank you :)

please give me the correct answer! thank you :)

Answers

Answer:

y = -2x

Step-by-step explanation:

y + 4 = -2 (x - 2)

Expanding the equation out, we get:

y + 4 = -2x + 4

Subtracting 4 from both sides, we get:

y = -2x.

Y = -2x just to easy my guy

2. A manufacturer of flashlights wants to know how well one of their newer styles is selling in a chain of large home-improvement stores. They select a simple random sample of 20 stores, record how many of the flashlights were sold in a 30-day period, and construct a 95% confidence interval for the mean number of flashlights sold.

(a) If, instead of constructing a 95% confidence interval, the flashlight manufacturer constructed a 98% confidence interval, would the 98% interval be wider, narrower, or the same width as the 95% interval? Explain.

(b) How would the width of confidence interval change if the flashlight manufacturer took a larger sample? Explain.

(c) The 20 stores in the sample were actually the only stores who provided sales figures from 36 stores that were randomly chosen to be in the sample. Can the manufacturer adjust the confidence interval to take this nonresponse into account? If so, how? If not, why not?

Answers

A: (a) The 98% confidence interval would be wider than the 95% interval. As the confidence level increases, the margin of error increases, thus making the interval wider.

(b) The width of the confidence interval would decrease as the sample size increases. This is because a larger sample size will result in a more accurate representation of the population, thus allowing for a narrower confidence interval.

(c) The manufacturer cannot adjust the confidence interval to take this nonresponse into account, as the nonresponse does not affect the accuracy of the sample. The confidence interval is based on the sample itself and not the population from which it was drawn.

What is mean by random sample?

Random sampling is a method of selecting a sample of individuals from a population such that each member of the population has an equal chance of being selected.

Random sampling is often used in research studies to ensure that the sample is representative of the population as a whole.

Random sampling is also used to minimize bias and ensure that the sample is not influenced by any particular group or individual.

Random sampling is important because it helps ensure that the results of the study are accurate and valid.

Random sampling helps to ensure that the sample is representative of the population and that the results are not influenced by any particular group or individual.

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Please help me please

Please help me please

Answers

The answer is false

Answer:

False.

Step-by-step explanation:

They will intersect if the lines continue.

Jose started a small business and wants to determine when the business will become profitable. His operating costs can be expressed as y=$10,000+$3,000x, where x is the number of months he stays in business. His sales revenues can be expressed as y=$4,500x, where x is the number of months he stays in business.

How many months will it take for his business to become profitable?

Enter your answer as a whole number of months, such as: 3 months

Answers

Answer:

Step-by-step explanation:

7 months.

evaluate the line integral where c is the given curve
∫c x sinyds C is line segment from (0 3) to (4 6)
Consider the line integral,
∫c x sin yds; C is the line segment from (0 3) to (4 6)

Answers

The value of the line integral is (-16/3)cos(6) + (16/9)sin(6). Evaluating this integral, you will get the value of the line integral for the given curve.

To evaluate the line integral ∫c x sin yds, where C is the line segment from (0,3) to (4,6), we first need to parameterize the curve. We can do this by letting x = t and y = 3 + (3/4)t, where t goes from 0 to 4. This gives us the parametric equations x = t and y = (3/4)t + 3.

Next, we need to find ds, the length of the curve element. We can use the formula ds = sqrt(dx^2 + dy^2) to get ds = sqrt(1 + (3/4)^2)dt = sqrt(25/16)dt = (5/4)dt.

Now we can substitute in our parameterization and ds into the line integral to get ∫c x sin yds = ∫0^4 t sin((3/4)t + 3) (5/4)dt.

We can evaluate this integral using integration by parts. Let u = t and dv = sin((3/4)t + 3) (5/4)dt, then du/dt = 1 and v = (-4/3)cos((3/4)t + 3). The integral becomes:

∫0^4 t sin((3/4)t + 3) (5/4)dt = uv|0^4 - ∫0^4 v du/dt dt
= (-4/3)t cos((3/4)t + 3)|0^4 - ∫0^4 (-4/3)cos((3/4)t + 3) dt
= (-4/3)t cos((3/4)t + 3) + (16/9)sin((3/4)t + 3)|0^4
= (-16/3)cos(6) + (16/9)sin(6)

Therefore, the value of the line integral is (-16/3)cos(6) + (16/9)sin(6).


To evaluate the line integral ∫c x sin y ds, where C is the line segment from (0, 3) to (4, 6), you first need to parameterize the curve C.

A possible parameterization is r(t) = (1-t)(0, 3) + t(4, 6) = (4t, 3+3t), with t ∈ [0, 1]. Then, compute the derivative dr/dt = (4, 3).

Now, find the integrand by replacing x and y with the parameterized curve components: x sin y = (4t) sin(3 + 3t).

Next, find the magnitude of the derivative: |dr/dt| = √(4² + 3²) = 5.

Finally, compute the integral:

∫[0, 1] (4t sin(3 + 3t))(5) dt.

Evaluating this integral, you will get the value of the line integral for the given curve.

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A distribution of values is normal with a mean of 230 and a standard deviation of 13. From this distribution, you are drawing samples of size 27. Find the interval containing the middle-most 50% of sample means: Enter your answer using interval notation. In this context, either inclusive or exclusive intervals would be acceptable. Your numbers should be accurate to 1 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.

Answers

The interval containing the middle-most 50% of sample means, drawn from a normal distribution with a mean of 230 and a standard deviation of 13, can be represented as (227.5, 232.5) in interval notation.

When drawing samples from a normal distribution, the distribution of sample means follows a normal distribution as well. The mean of the sample means will be equal to the population mean, which is 230 in this case. The standard deviation of the sample means, also known as the standard error, can be calculated by dividing the population standard deviation by the square root of the sample size. In this case, the sample size is 27, so the standard error is 13 / √27 ≈ 2.50.

To find the interval containing the middle-most 50% of sample means, we need to consider the standard deviation of the sample means. Since the normal distribution is symmetric, the middle-most 50% of the distribution lies within one standard deviation from the mean in both directions.

Using this information, we can calculate the interval by subtracting and adding one standard deviation from the mean. The lower bound of the interval is 230 - 2.50 = 227.5, rounded to 1 decimal place as 227.5. The upper bound is 230 + 2.50 = 232.50, rounded to 1 decimal place as 232.3. Therefore, the interval containing the middle-most 50% of sample means is (227.5, 232.5) in interval notation.

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an economist wants to estimate the mean per capita income (in thousands of dollars) for a major city in california. he believes that the mean income is $21.2, and the standard deviation is known to be $9.3. how large of a sample would be required in order to estimate the mean per capita income at the 95% level of confidence with an error of at most $0.68? round your answer up to the next integer.

Answers

By taking the help of the standard deviation, the answer obtained is

n = 719

What is Standard Deviation?

At first it is important to know about Variance.

Variance is the sum of the square of deviation from the mean of the data.

On taking the square root of variance, Standard deviation is obtained.

The formula used for calculating the number of samples required is

\(n=\frac{Z^{2}_{\alpha /2}\times \sigma ^{2}}{e^{2}}\), \(\sigma\) is the standard deviation , e is the error,

Here,

\(\alpha\) = 1 - \(\frac{95}{100}\)

  = 1 - 0.95

  = 0.05

Critical values of Z = \(\pm\)1.96 [ From the table]

Standard deviation (\(\sigma\)) = 9.3

error (e) = $0.68

On putting  the value,

n = \(\frac{1.96^2 \times 9.3^2}{0.68^2}\)

n = 718.5

n = 719

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A fabric store sells two types of ribbon. One customer buys 3 rolls of the lace ribbon and 2 rolls of the satin ribbon and has a total of 120 yards of
ribbon. Another customer buys 2 rolls of the lace ribbon and 4 rolls of the satin ribbon and has a total of 160 yards of ribbon.
How many yards are on one roll of lace ribbon and one roll of satin ribbon?
OA. There are 10 yards on one roll of lace ribbon and there are 40 yards on one roll of satin ribbon.
OB. There are 20 yards on one roll of lace ribbon and there are 30 yards on one roll of satin ribbon.
OC. There are 30 yards on one roll of lace ribbon and there are 20 yards on one roll of satin ribbon.
OD. There are 40 yards on one roll of lace ribbon and there are 10 yards on one roll of satin ribbon.

Answers

Answer:

B

Step-by-step explanation:

3(20)=60

2(30)=60

60+60=120

2(20)= 40

4(30)= 120

40+120=160

Answer:

20 yards in the lace ribbon and there are 30 yards on one roll of satin ribbon

Step-by-step explanation:

3x + 2y = 120   (1)

   2x + 4y = 160   (2)

Divide eq(2) by 2 (both sides). Keep equation (1) as is.  You will get

   3x + 2y = 120   (1')

    x + 2y =  80   (2')

Now subtract eq(2') from eq(1').  You will get

   2x = 120 - 80 = 40

    x =  40/2 = 20.

Then from equation (2'),  

   20 + 2y = 80

        2y = 80 - 20 = 60

         y   = 60/2 = 30

the ratio of of empty seats to full seats in an auditorium is 3:7 if there are 203 full seats find the total number of seats

Answers

Answer:

290

Step-by-step explanation:

I first divided 203 by 7 gettiing 29, then i multiplied that by 3 getting 87. Finialy i added them.

Factorise 6-y^2

Please help

Answers

Answer:

6-y^2 can be factored by using the difference of squares formula which states that:

a^2 - b^2 = (a+b)(a-b)

We can factorize 6-y^2 by using the following:

6 - y^2 = (sqrt(6) + sqrt(-y^2))(sqrt(6) - sqrt(-y^2))

= (sqrt(6) + yi)(sqrt(6) - yi)

where i is the imaginary unit.

So, 6-y^2 = (sqrt(6) + yi)(sqrt(6) - yi) is the factored form of 6-y^2

Please note that the factorization is only true for real values of y, when y is not real the expression can't be factorized.

Exactly 50% of the area under the normal curve lies to the left of the mean.
True or False

Answers

The statement "Exactly 50% of the area under the normal curve lies to the left of the mean" is a true statement.

In a normal distribution, the mean, median, and mode all coincide, and the distribution is symmetrical.

The mean is the balance point of the distribution, with 50% of the area to the left and 50% to the right of it. Exactly 50% of the area under the normal curve lies to the left of the mean.

This implies that the distribution is symmetrical, and the mean, mode, and median are the same.

Therefore, the statement "Exactly 50% of the area under the normal curve lies to the left of the mean" is a true statement.

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Please help me on this!

Please help me on this!

Answers

Answer:

a. D et er mi ne wh et h er  –(x3 + 5x + 1)

is eq uiv ale nt to  x3 + 5x + 1

A fu nc ti on is ev en if  f ( x )  =  f ( - x )  for all x.

f(-x) = -x³ + 5(-x) + 1

f(-x) = -x³ - 5x + 1

Det ermi ne wh eth er (–x)3 + 5(–x) + 1 is eq uiv ale nt to x3 + 5x + 1

Step-by-step explanation:    

What is the slope of the line parellel to this line -9x+3y=6

Answers

Answer: 3

Step-by-step explanation:

What is the slope of the line parellel to this line -9x+3y=6

Help Please!!!!!!!!!!!!!

Help Please!!!!!!!!!!!!!

Answers

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

Answer : X= 4,-1 so it will be C.

Once an antibiotic is given, number of bacteria decreases at a rate of 15% /day. There
were about 15,000 bacteria prior to the treatment. The graph models the number of
bacteria after x days of treatment.
W
What are the key features of the exponential function modeled in terms of this
situation and how can they be interpreted?

Once an antibiotic is given, number of bacteria decreases at a rate of 15% /day. Therewere about 15,000

Answers

Asymptote indicates that as time increases, the number of bacteria approaches 0.

What is Graph?

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

Given,

Once an antibiotic is given, number of bacteria decreases at a rate of 15% /day.

There were about 15,000 bacteria prior to the treatment.

The line y = 0 is an asymptote of the graph.

The y-intercept is 15,000.

The y-intercept represents the number of bacteria when treatment began.

The asymptote indicates that as time increases, the number of bacteria approaches 0.

Hence, asymptote indicates that as time increases, the number of bacteria approaches 0.

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ms. lee is shopping for a new electric warer heater. brand A cost $575 and uses 442 kiliwatt- hours per month. brand B cost $651 and uses 397 kiliwatt-hours per month. if electricity costs $0.17 per kilowatt-hour, how much would ms. lee save on electricity per month by buying brand B

Answers

Answer:

7.65

Step-by-step explanation:

Brand A:

442(times)0.17=75.14 each month

Brand B:

397(times)0.17=67.49 each month

75.14-67.49=7.65

Ms.Lee would save 7.65 each month with brand B

differentiate the following function f(x)=2x3 6x-1/x 3ex-sin(x)

Answers

The differentiation of the function is f'(x) = 6x² + 6 - ln(x) + 3eˣ - cos(x)

How to differentiate the function

from the question, we have the following parameters that can be used in our computation:

f(x) = 2x³ + 6x - 1/x + 3eˣ - sin(x)

The derivative of the functions can be calculated using the first principle which states that

if f(x) = axⁿ, then f'(x) = naxⁿ⁻¹

Using the above as a guide, we have the following:

f'(x) = 6x² + 6 - ln(x) + 3eˣ - cos(x)

Hence, the differentiation of the function is f'(x) = 6x² + 6 - ln(x) + 3eˣ - cos(x)

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3x-1=1-3x

Find x

And please explain I forgot how to do this so it would be really helpful:)

Answers

Answer:

x = 1/3

Step-by-step explanation:

3x - 1 = 1 - 3x

Add 3x to both sides:

3x - 1 + 3x = 1 - 3x + 3x

6x - 1 = 1

Add 1 to both sides:

6x - 1 + 1 = 1 + 1

6x = 2

Divide both sides by 6:

6x ÷ 6 = 2÷6

x = 2/6

x = 1/3

-Chetan K

I need help. What does n equal.
\(5n^{2}=7n-2\)

Answers

Answer:

\(\boxed{\sf n= \dfrac{2}{5} ,\: n=1}\)

Step-by-step explanation:

\(\rightarrow 5n^2 = 7n -2\)

\(\rightarrow 5n^2 - 7n +2=0\)

\(\rightarrow 5n^2 - 5n -2n+2=0\)

\(\rightarrow 5n(n - 1) -2(n-1)=0\)

\(\rightarrow (5n-2)(n-1)=0\)

\(\rightarrow 5n-2= 0,\: n-1=0\)

\(\rightarrow 5n= 2,\: n=1\)

\(\rightarrow n= \dfrac{2}{5} ,\: n=1\)

\(\pmb{ n= \dfrac{2}{5} \:or~ n=1}\)

Step-by-step explanation:

\(\hookrightarrow\sf{5n^2 = 7n -2}\\\\\hookrightarrow\sf{5n^2 - 7n +2=0}\\\\\hookrightarrow\sf{5n^2 - (5+2)n +2=0}\\\\\hookrightarrow\sf{5n^2 - 5n -2n+2=0}\\\\\hookrightarrow\sf{ 5n(n - 1) -2(n-1)=0}\\\\\hookrightarrow\sf{ (5n-2)(n-1)=0}\\\\\hookrightarrow\sf{ 5n-2= 0\:or~ n-1=0}\\\\\hookrightarrow\sf{ 5n= 2\:or~n=1}\\\\\hookrightarrow\bold{ n= \dfrac{2}{5} \:or~ n=1}\)

TP is a tangent to the circle at centre O. The value of x is

TP is a tangent to the circle at centre O. The value of x is

Answers

Answer:

x = 62

Step-by-step explanation:

the angle between a tangent and the radius at the point of contact = 90°

then Δ PTO is right

the sum of the 3 angles in the triangle = 180° , so

x = 180 - 90 - 28 = 180 - 118 = 62

Answer:

x = 62°

Step-by-step explanation:

TP is a tangent to the circle at centre O

means

TP is perpendicular to TO

Then

m∠OTP = 90°

Then

OTP is a right triangle

Then

x = 90 - 28

  = 62

It's almost time to go home. You spent a lot of money this Vacation! you are counting up the money you have left. You only have dimes and quarters, and you have a total of 103 coins worth $15.25. How many dimes do you have? Solve Using Substatution

Answers

Start writing the equation of the number of coins

\(q+d=103\)

then, using the value of each coin write the equation for the amount of money you have

\(0.25q+0.10d=15.25\)

then, use the first equation to solve for d

\(d=103-q\)

substitute in the second equation

\(\begin{gathered} 0.25q+0.10\cdot(103-q)=15.25 \\ \end{gathered}\)

simplify and solve for q

\(\begin{gathered} 0.25q+10.3-0.10q=15.25 \\ 0.15q=15.25-10.3 \\ 0.15q=4.95 \\ q=\frac{4.95}{0.15} \\ q=33 \end{gathered}\)

find the value of d

\(\begin{gathered} d=103-q \\ d=103-33 \\ d=70 \end{gathered}\)

Plsss help me need help

Plsss help me need help

Answers

Answer:

Below.

Step-by-step explanation:

\(\large \underline{\textsf {Distributive Property:}}\ \normalsize \tex a (b + c + d) = ab + ac + ad}\ \textsf{and } \tex a (b + c) = ab + ac\)

\(\boldsymbol{\sf A.\ 9\left(4x - 3y -\dfrac{2}{3}\right)}\)

\(\boxed{\begin{minipage}{4.55 cm}\implies \sf 9(4x) + 9(-3y) + 9\left(-\dfrac{2}{3}\right)\\\\\implies \sf 36x -27y - \dfrac{18}{3}\\\\\implies \boxed{\sf 36x -27y -6}\end{minipage}}\)

..................................................................................................................................................

\(\boldsymbol{\sf B.\ -2(-6x + 3y - 1)}\)

\(\boxed{\begin{minipage}{4.8 cm}\implies \sf -2(-6x) - 2(3y) - 2(-1)\\\\\implies \boxed{\sf 12x -27y + 2}\end{minipage}}\)

..................................................................................................................................................

\(\boldsymbol{\sf C.\ \dfrac{1}{5}(20y-4x-13)}\)

\(\boxed{\begin{minipage}{4.68 cm}\implies \sf \dfrac{1}{5}(20y) + \dfrac{1}{5}(-4x) + \dfrac{1}{5}(-13)\\\\\implies \sf \dfrac{20y}{5}-\dfrac{4x}{5}-\dfrac{13}{5}\\\\\implies \boxed{\sf -\dfrac{4}{5}x+4y-\dfrac{13}{5}}\end{minipage}}\)

..................................................................................................................................................

\(\boldsymbol{\sf D.\ 8\left(-x-\dfrac{1}{2}\right)}\)

\(\boxed{\begin{minipage}{3.28 cm}\implies \sf 8(-x) + 8\left(-\dfrac{1}{2}\right)\\\\\implies \sf -8x - \dfrac{8}{2}\\\\\implies \boxed{\sf 8x - 4}\end{minipage}}\)

..................................................................................................................................................

\(\boldsymbol{\sf E.\ -8\left(-x-\dfrac{3}{4}y+\dfrac{7}{2}\right)}\)

\(\boxed{\begin{minipage}{5.4 cm}\implies \sf -8(-x)-8\left(-\dfrac{3}{4}y\right)-8\left(\dfrac{7}{2}\right)\\\\\implies \sf 8x + \dfrac{24}{4}y - \dfrac{56}{2}\\\\\implies \boxed{\sf 8x + 6y - 28}\end{minipage}}\)

Tekan-Tekan Sdn. Bhd. has order for 200 Model AS-120 calculator for delivery on day 200. The calculator consists of three parts. Components 2 and 3 form subassembly 1 . Sub-assembly 1 and component 4 form the final assembly. Following are the work centers and times of each operation. Table Q3(a) shows routine file of the operation. Assuming: - Only one machine is assigned to each operation - The factory works on 8-hour shift, 5 days a week - All parts move in one lot of 200. (a) Illustrate the backward schedule based on the information given above. (12 marks) (b) Identify when component 3 must be started to meet the delivery date. (2 marks)

Answers

Component 3 must be started on day 197 to meet the delivery date of day 200.

To illustrate the backward schedule, we need to start from the delivery date (day 200) and work our way backward, taking into account the lead times and dependencies of each operation.

(a) Backward schedule:

Operation    |  Work Center  |  Time (hours)  |  Start Day

--------------------------------------------------------

Final Assembly |   Work Center 1  |        1       |     200

Sub-assembly 1 |   Work Center 2  |        2       |     199

Component 4     |   Work Center 3  |        3       |     197

Component 2     |   Work Center 4  |        4       |     196

Component 3     |   Work Center 5  |        3       |     ????

(b) To identify when component 3 must be started to meet the delivery date, we need to consider its dependencies and lead times.

From the backward schedule, we see that component 3 is required for sub-assembly 1, which is scheduled to start on day 199. The time required for sub-assembly 1 is 2 hours, which means it should be completed by the end of day 199.

Since component 3 is needed for sub-assembly 1, we can conclude that component 3 must be started at least 2 hours before the start of sub-assembly 1. Therefore, component 3 should be started on day 199 - 2 = 197 to ensure it is completed and ready for sub-assembly 1.

Hence, component 3 must be started on day 197 to meet the delivery date of day 200.

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A group of adult males has foot lengths with a mean of 26.84 cm and a standard deviation of 1.29 cm. Use the range rule of thumb to identify the limits separating values that are significantly low or significantly high. Is the adult male foot length of 23.8 cm significantly low or significantly​ high?
Significantly low values are ___ cm or lower.
Significantly high values are ___ cm or higher.
Select the correct choice below and fill in the answer​ box(es) to complete your choice.
A) The adult male foot length of 23.8 cm is not significant because it is between __ cm and __ cm
B) The adult male foot length of 23.8 cm is significantly low because it is less than __ cm
C) The adult male foot length of 23.8 cm is significantly high because it is greater than __ cm

Answers

The option B, "The adult male foot length of 23.8 cm is significantly low because it is less than 24.26 cm" is correct.

In the given question, a group of adult males has foot lengths with a mean of 26.84 cm and a standard deviation of 1.29 cm.

We have to find the adult male foot length of 23.8 cm significantly low or significantly​ high.

According to thumb rule, a value is significantly low if it is 2 standard deviations below mean and significantly high if it is 2 standard deviations above mean

Mean = 26.84 cm

Standard deviation = 1.29 cm

Significantly low value = 26.84 - 2*1.29 = 24.26 cm

Significantly high value = 26.84 + 2*1.29 = 29.42 cm

Significantly low values are 24.26 cm or lower.

Significantly high values are 29.42 cm or higher.

The adult male foot length of 23.8 is lower than the significant low value of 24.26.

So the option B, "The adult male foot length of 23.8 cm is significantly low because it is less than 24.26 cm" is correct.

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12 is what percent of 60?

Answers

Answer:

20

Step-by-step explanation:

12÷60×100

Answer:

12 is 20% of 60.

Step-by-step explanation:

12/60 x 100/100=

(12 x 100/ 60)  x 1/100= 20/100

So the answer is 20 %.

or

12/60 x 100 which will give you 20 as the answer.

. Which cubic unit of measure is appropriate to be used in measuring the volume of a medicine box? *

Answers

Answer:

Cubic meters

Step-by-step explanation:

The volume of medicine box is usually measure in cubic meters.

However, the volume of medicine in it is usually measured in milliliters.

For example

Infusions  - 1 ton of packed supplies = 2.2 cubic meters

Dressings  - 1 ton of packed supplies =  9 cubic meters etc.

Write 1/20 as a percent

help

Answers

Answer:

5%

Step-by-step explanation:

1/20 of 100% is 5%. So that means 5%

5 percent just know this is right trust

If you deposit $5000 into an account paying 8.25% annual interest compounded
semiannually, how much money will be in the account after 15 years? round your answer
to the nearest penny/hundredth

Answers

Answer:

1571862.11penny

Step-by-step explanation:

The formula for calculating the compound interest is expressed as;

A = P(1+r/n) ^nt

Given

Principal P = $5000

r is the rate = 8.25% = 0.0825

t is the time = 15 years

n is the time of compounding = 6/12 = 1/2

Substitute

A = 5000(1+0.0825/0.5)^0.5(15)

A = 5000(1+0.165)^7.5

A = 5000(1.165)^7.5

A = 5000(3.1437)

A = 15,718.6

hence the amount of money in the account after 15years is $15,718.6211 which is 1571862.11penny

a circular mirror is surrounded by a square metal frame. the radius of the mirror is 4x. the side length of the metal frame is 20x. what is the area of the metal frame

Answers

Answer:

400x^2-16x^2pi

Step-by-step explanation:

To first start off, we need to find the area of the circle mirror. This is 16x^2pi.

Now, we need to find the area of the square, which results in 400x^2.

From here, we can subtract the circle from the square.

Because you cant subtract pi, we can leave it as it is.

Hope this helped you!

Please answer this (who ever answers correctly gets brainlest)

Please answer this (who ever answers correctly gets brainlest)

Answers

Answer:

5 and 1/3 yards = 16 ft

So 16 ft + 2 extra ft

The total is 18 ft (C.)

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