The first ionization energy for a gas-phase atom of a particular element is 6. 24 × 10^–19 j. What is the maximum wavelength of electromagnetic radiation that could ionize this atom?.

The mass of the copper is 50 kg and the change in temperature (ΔT) is 130 C (140 C - 10 C). Therefore, the entropy change of the copper is 6.5 kJ/K (50 kg × 130 C × 0.05 kJ/K).

Copper is a soft, malleable, and ductile metal that is naturally found in the Earth's crust. It is an essential element for all forms of life, and it is used in a variety of ways in the modern world. Copper is one of the oldest metals used by humans and has been used for thousands of years in the production of jewelry, coins, and statues. It is also used in the production of electrical wiring, plumbing pipes, and other components used in the construction of buildings. Copper is also used in many industrial applications, such as in the production of semiconductors, motors, and other electronic components.

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Answer:

protons, neutrons, negatively, electrons

Explanation:

protons are positive, neutrons are neutral. the entire basis of bonding is chemistry is the distribution of electrons, which are negatively charged particles surrounding the nucleus.

Answer.

Hydrocarbons are compounds that contain carbon and hydrogen only

Explanation:

a. c3H4 methane

b.c3H4.propene

c.c5H8

Answer:

Evaporate a solution of  CuSO4⋅5H2O to dryness

Explanation:

To dehydrated you have to get rid of the water and water evaporates so you have to evaporate the solution.

Procedure that could be used to convert the pentahydrate form to the dehydrated form is to evaporate a solution of CuSO₄⋅5H₂O to dryness.

Copper(II) sulfate pentahydrate (CuSO₄·5H₂O) form aqueous solutions of bright blue.

After the heating, dehydrated form copper(II) sulfate is formed.

Salt copper(II) sulfate has white color.

Adding a water in white copper(II) sulfate would make solution blue again.

Hydrate is a substance that contains water or its constituent elements.

M(CuSO₄·5H₂O) = 249.5 g/mol; molar mass of copper sulphate pentahydrate

Evaporation occurs when the molecules at the surface of a liquid gain enough energy to overcome the force of attraction of other molecules in the liquid phase.

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The difference in between the Arrhenius and Bronsted-Lowry and the Lewis acid base is Arrhenius base will increases the concentration  OH⁻ ions. Bronsted-Lowry acid is that donates a proton to another molecule. Lewis acid is an electron pair acceptor.

An Arrhenius base is that will increases the concentration of OH⁻  ions. The Bronsted - Lowry acid is the species that will donates the proton to the another molecule. The Bronsted - Lowry base is the species that will accepts the proton from another molecule.

The Lewis acid is the electron pair acceptor and the the lewis base is the electron pair donor.

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Based on the absorption spectrum, at the wavelength you should run the standards at 450 nm.

When all of the copper has precipitated out of solution, the usual method is to conduct a visual check. Pure copper(II) sulfate is described as white. It is also known as anhydrous copper(II) sulfate because it does not contain any water. When water is present, a copper(II) sulfate sample turns blue. Free iron, which is typically transferred onto a part's surface during manufacture with steel components, is found using the copper sulfate test. Copper(II) ions in solution absorb red light from the spectrum. The light that emerges from the solution will contain all the colors except for red. We see a light blue color when these particular wavelengths are combined.

Note that the full question is:

While testing a sample of copper (II) sulfate at varying wavelengths, you come up with a curve like the one found below. You still need to determine the concentration of the sample.

Based on this absorption spectrum, at which wavelength should you run the standards?

a) 450 nm

b) 550 nm

c) 650 nm

d)750 nm

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Na+ would enter the cell while K+ would exit. In the postsynaptic or postjunctional membrane, ACh diffuses and binds to certain receptors.

In the postsynaptic or postjunctional membrane, ACh diffuses across the synaptic cleft and binds to specific receptors. An altered conformation of a membrane channel that is selectively permeable to both Na+ and K+ results from the binding of ACh to its receptors.

When ACh binds to its receptors, it modifies the structure of a membrane circuit that is selectively permeable to both Na+ and K+. When cholinergic receptors on skeletal muscle fibres interact with each other, ligand-gated sodium channels inside the cell membrane are opened.

The muscle fibre is then exposed to sodium ions, which causes the muscle to contract. By stimulating nonpostsynaptic AChRs, ACh specifically inhibits presynaptic nerve terminal specialisation and postnatal AChR cluster (synaptic differentiation), and by inhibiting postsynaptic AChRs, it inhibits motor short tapered bandwidth or engine axon splitting (synaptic growth).

Ion channels in the muscle fibre membrane are opened by the neurotransmitter acetylcholine (ACh) attaching to postsynaptic receptors.

The complete question is;

What would be the effect of ACh binding to its receptor on the postsynaptic muscle cell?

A.) Ca2+ would leak out of the cell as Na+ flowed into the cell.

B.) Ca2+ would flow into the cell as Na+ flowed out of the cell.

C.) Na+ would flow into the cell and K+ would flow out of the cell.

D.) Only Na+ would flow into the cell.

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Answer:

A. grou(I)

B. 3rd period

C. Sodium (Na)

Explanation:

it belongs to group (I) since it has one valence electron

it belongs to 3rd period since it has three energy levels

The volume at which the third equivalence point occurs is beyond the range of the titration is none of the given choices.

Since the weak triprotic acid has three dissociation constants, it has three equivalence points. The pH at each equivalence point will depend on the dissociation constants and the concentration of the acid.

In this case, since there are only two pH jumps observed during the titration, we can conclude that we have only measured two equivalence points, corresponding to the first two dissociations of the acid.

The first pH jump at 10.0 mL corresponds to the first equivalence point, where the first hydrogen ion is completely neutralized. The second pH jump at 15.0 mL corresponds to the second equivalence point, where the second hydrogen ion is completely neutralized.

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If 4.00 mL of vinegar needs 43.5 mL of 0.150 m NaOH  to reach the equivalence point in a titration, The grams of the acetic acid is 119.9 g.

Given that :

The molarity of NaOH = 0.150 M

The volume of NaOH = 43.5 mL = 0.0435 L

The moles = molarity × volume

                 = 0.150 × 0.0435

                 = 0.0065 mol

At equivalence point ,

Moles of CH₃COOH = moles of NaOH

The molarity of the CH₃COOH = moles / volume

                                                   = 0.0065 / 0.004

                                                   = 1.625 mol

Volume of  CH₃COOH = 1.50 × 0.946353

                                     = 1.230 L

The mass of the Acetic acid = 1.625 × 1.230 × 60

                                               = 119.9 g

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The experimenter to accurately determine the amount of base needed to neutralize the acid. It does not speed up the reaction of chemicals nor does it neutralize the acid.

Phenolphthalein is added to an unknown acid before conducting a titration experiment because it serves as a pH indicator. During the titration, a base is slowly added to the acid until the acid has completely reacted. Phenolphthalein changes color at a certain pH, indicating when the acid has been neutralized. This allows the experimenter to accurately determine the amount of base needed to neutralize the acid. It does not speed up the reaction of chemicals nor does it neutralize the acid.

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Answer:

It’s caused by a disturbance.

It requires a medium to travel.

Explanation:

A wave is an unsettling influence that sends energy starting with one point then onto the next. It does no essentially convey the particles or matter of the medium.  

Waves typically conveys energy. It is this energy they use in making aggravations.  

Not all waves conveys matter; a genuine model is electromagnetic waves. Additionally, electromagnetic waves don't need a mode for proliferation.

Answer: The only answer that is NOT true is that waves carry matter.

Explanation:

Waves are caused by a disturbance, require a medium to travel (by definition) and carry energy.

If you're talking about electromagnetic waves tho, those do not require a medium. Waves in general DO require a medium

The volume i should dilute 126 ml of an 7.15 M CuCl₂ solution so that 50.5 ml of the diluted solution contains 4.33 g CuCl₂ is equals to the 1.412 ×10³ mL.

CuCl₂ is an ionic compound that is soluble in water. We can use the molarity and the volume of the initial solution to figure out how many grams of copper(II) chloride it contains. We have,

Volume of dilute solution, V = 126 ml

Molarity of CuCl₂ = 7.15 M

Firstly, we will convert the mass of CuCl₂ to moles : n = m/M

Where n = moles

Now, molar mass of CuCl₂ = 1× mass of copper + 2× mass of chlorine= 63.55g/mol + 2×35.45

g/mol = 134.45 g/mol

So, n = 4.33/134.45 = 0.03221 mol

We want to calculate the concentration of the 50.5 mL CuCl₂ solution. Formula is C = n/V

where, c = concentration

We must convert 50.5 mL to L:

50.5 mL ×1 L/1000mL = 0.0505L

so, C = n/V = 0.03221 mol/0.0505L

C = 0.638 M. Use the dilution formula to find the volume of the diluted solution: C₁V₁ = C₂V₂

Where, C₁ is the initial concentration

Substitute V₁ = 126 ml , C₁ = 7.15 M , C₂

= 0.638 M

Thus, volume of dilute solution,

7.15 M × 126 mL = 0.638 M × V₂

=> V₂ = 126× 7.15 /0.638 × 1000

=> V₂ = 1.412068 L

but we have the volume in mililiter units, so the required volume is 1.412 × 10³ mL.

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Based on the information provided, it is likely that the unknown substance is an acid.

Cabbage juice is a natural pH indicator that changes color in the presence of acids and bases. It typically turns purple or pink in the presence of an acid, and green or blue in the presence of a base.

The fact that the solution turns purple suggests that the unknown substance mixed with cabbage juice is acidic in nature. Acids are substances that release hydrogen ions (H+) in solution, which can lower the pH and turn the cabbage juice solution purple.

Additionally, the fact that the substance does not react with calcium carbonate suggests that it is not a base. Bases typically react with acids to produce salt and water, and one common indicator of a chemical reaction between an acid and a base is the production of gas, such as carbon dioxide (CO2), when calcium carbonate reacts with an acid.

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The molar solubility of yttrium fluoride (YF3) is 3.46 × 10-6 M.

The ksp of yttrium fluoride is 8.62 × 10-21. The molar solubility of this compound can be determined using the following formula:Ksp = [Y3+][F-]3We can set the molar solubility of yttrium fluoride as 'x'.

This is because the solubility of the yttrium fluoride will lead to the concentration of yttrium ions and fluoride ions. The Ksp expression for yttrium fluoride can be represented as follows:

Ksp = (x)(3x)3 = 27x4

where '3x' is the molar solubility of F-.

We can substitute Ksp value in the above expression and then solve for x:

8.62 × 10-21 = 27x4x = 3.46 × 10-6 M

Thus, the molar solubility of yttrium fluoride is 3.46 × 10-6 M.

To conclude, the molar solubility of yttrium fluoride (YF3) is 3.46 × 10-6 M.

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Answer:

I think its C

Explanation:

because it travels from the sun to earth

1 tonne of carbon dioxide has been dissolved in a sample of ocean water, which has a pH of 5.76.

The first step is to convert the given mass of carbon dioxide (1 ton) to moles. Since 1 ton = 2000 pounds, and 1 pound = 0.45 kilograms, 1 ton = 907.18 kilograms. To convert this to moles, we need to divide by the molar mass of \(CO_2\), which is 44.01 g/mol.

Therefore, the number of moles of \(CO_2\) in 1 ton is \(\frac{ 907.18}{44.01} = 20.59 moles.\)

Next, we need to convert the given volume of ocean water (1.0x10 gallons) to liters. Since 1 gallon = 3.785 liters, the given volume is \(3.785*10^{10}\) liters.

Thus, the number of moles of \(CO_2\) per liter of ocean water is \(\frac{20.59}{3.785*10^{10}}= 5.45*10^{-10} moles/liter\)

Now, we can calculate the pH of the sample.When carbon dioxide and sea water react, the equilibrium constant is (\(1.2*10^{-9}\)) along with the acid dissociation constant (Ka.) for \(H_2CO\) is (\(4.3*10^{-7}\)). The pH of the sample can be calculated using the Henderson-Hasselbalch equation:

\(pH = pK_a + log(\frac{[base]}{[acid]})\)

where [base] is the base's concentration (\(CO_2\))and [acid] is the acid's concentration.(\(H_2CO_3\)). Since we already calculated the concentration of \(CO_2\), We only have to determine the concentration of \(H_2CO_3\),This is equivalent to the amount of \(CO_2\) times the equilibrium constant:

\([H_2CO_3] = [CO_2] * K\\ = 5.45*10^{-10} moles/liter *1.2*10^{-9}\\ \\ = 6.54*10^{-19} moles/liter\)

Now, we can plug all the values into the Henderson-Hasselbalch equation to calculate the pH:

\(pH = -log(4.3*10^{-7}) + log(\frac{5.45*10^{-10}}{6.54*10^{-19}})\\pH= 5.76\)

Therefore, the pH of the sample of ocean water with 1 ton of carbon dioxide dissolved in it is 5.76.

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\({ \qquad\qquad\huge\underline{{\sf Answer}}} \)

Here we go ~

Mass of 1 mole C - 12 atom = 12 g

So, mass of 1 carbon - 12 atom = ( 12 / 1 mole ) g

that is :

\(\qquad \sf  \dashrightarrow \: \cfrac{12}{6.022 \times 10 {}^{23} } \: \: g\)

[ since 1 mole = 6.022 × 10²³ ]

\( \qquad \sf  \approx2 \times 10 {}^{ - 23} \: \: g\)

Molarity :

Molarity is defined as " The number of moles of solute present in per litre of solution "

Molality :

Molality is defined as " Number of moles of solute present per kg mass of solvent "

As per the given reaction ~

\(\qquad \sf  \dashrightarrow \: Zn + 2\:H Cl \rightarrow ZnCl_2 + H_2\)

32.65 g of zinc reacted,

[ Number of moles of zinc reacted = mass of zinc reacted divided by its formula Weight ]

\(\qquad \sf  \dashrightarrow \: number \: \: of \: \: moles = \cfrac{32.65}{65.3} \: \: mol\)

\(\qquad \sf  \dashrightarrow \: number \: \: of \: \: moles = \cfrac{1}{2} \: \: mol\)

so, we can say that " half mole Zinc reacted with 1 mole of HCl to form half mole of Zinc chloride and half mole of Hydrogen gas "

And we already know that 1 mole of any gas occupies 22.7 litre volume at STP.

So, volume of Hydrogen gas Liberated :

\(\qquad \sf  \dashrightarrow \: \cfrac{1}{2} \times 22.7\)

\(\qquad \sf  \dashrightarrow \: 11.35 \: \: litres\)

The relationship between Molarity and molality can be expressed as :

\(\qquad \sf  \dashrightarrow \: M =\cfrac{ 1000(m \times d)}{1000+(m \times F)}\)

Terms :

\(\qquad \sf  \dashrightarrow \: M =\cfrac{ 1000(3 \times 1.110)}{1000+(3 \times 40)}\)

\(\qquad \sf  \dashrightarrow \: M =\cfrac{ 1000( 3.330)}{1000+120}\)

\(\qquad \sf  \dashrightarrow \: M =\cfrac{ 3330}{1120}\)

\(\qquad \sf  \dashrightarrow \: M =2.973 \: mol \: l {}^{ - 1} \)

Answer:

b. muscles is the answer

Explanation:

muscles is a meat, animals eat meat

Atoms contains nucleus in its center and electron that revolve around the atom in fixed orbit. Stability is the reason that causes atoms  to bond together to form molecules.

Atom is the smallest particle of any element, molecule or compound. Atom can not be further divided. In the nucleus, proton and neutron are present.

Every atoms want to gain stability. To gain stability atoms have to gain noble gas configuration that is outermost shell must contain 2,8, 18 electrons. The atom should follow octet rule. Stability lowers the energy of an atom.

Therefore stability is the reason that causes atoms  to bond together to form molecules.

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Answer:

4 yards/second is the answer

Answer:

the answer is 4 yards per second

Explanation:

80 yards in 20 seconds

20+20+20+20=80

there are 4, 20s to make 80

in other words...

80÷4=20

The strategy for balancing the equations is by looking at the number of atoms on each side of the equation and adding coefficients to the molecules.

A balanced equation is an equation for a chemical reaction where the number of atoms for each element in the reaction and the total charge is the same for the reactants and the products,

A strategy that will help balance equations more quickly is balancing by inspection. Here, you look at how many atoms you have on each side of the equation and add coefficients to the molecules to balance out the number of atoms.

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The solubility product constant (Ksp) is the equilibrium constant for a chemical reaction in which a solid substance separates into its constituent ions in water. The solubility product (Ksp) can be used to measure the maximum solubility of a compound in water.

The solubility product of a compound can be calculated by multiplying the concentrations of the ions in the solution that results from dissolving the compound in water. The solubility product of AgCl, SrSO4, Ag2CO3, and Sr(IO3)2 is determined using the virtual lab.The virtual lab was utilized to determine the solubility product (Ksp) for AgCl, SrSO4, Ag2CO3, and Sr(IO3)2. The molar concentration of each compound was determined and used to calculate the solubility product. The calculated values were as follows:

AgCl: 1.16 × 10-10SrSO4: 3.71 × 10-7Ag2CO3: 7.59 × 10-12Sr(IO3)2: 4.67 × 10-12

The solubility of the solids listed in question 2 in moles/liter is obtained by using the solubility product. The formula for calculating the solubility of a substance is given as √Ksp. Therefore, the solubility of the substances listed in question 2 in moles/liter are as follows:

AgCl: 1.08 × 10-5SrSO4: 6.10 × 10-3Ag2CO3: 8.70 × 10-6Sr(IO3)2: 6.83 × 10-6

In conclusion, the solubility product of AgCl, SrSO4, Ag2CO3, and Sr(IO3)2 is determined using the virtual lab. The solubility of the compounds in question 2 was calculated using the solubility product constant. The solubility of the substances in moles/liter was determined to be AgCl: 1.08 × 10-5, SrSO4: 6.10 × 10-3, Ag2CO3: 8.70 × 10-6, and Sr(IO3)2: 6.83 × 10-6.

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The significant test used to reject or accept any anomalous measurement is the Q-test.

The Q-test is a statistical test that determines whether an individual data point is significantly different from the rest of the dataset. It is commonly used to identify and reject outliers or anomalous measurements. The test compares the difference between the suspect data point and the neighboring data points to the expected range of variation within the dataset. If the difference exceeds a critical value based on the confidence level and sample size, the suspect data point is considered an outlier and is rejected. The Q-test provides a quantitative measure to objectively evaluate and handle anomalous measurements in various scientific and industrial applications.

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first, we need the molar mass of HNO3(azotic acid) it's equal to 1AH+1AN+3AO(where A is the atomic mass of the element present within the molecule and, it's multiplied by how many times it's present)=1*1+1*14+3*16=15+54=69g/mole

now we multiply the molar mass with the number of moles 69*1.2=82.8 grames

Answer:

b)6.2 grams

Explanation:

Recall that percentage yield =

actual yield/theoretical yield * 100/1

theoretical yield = 8.2 grams

percentage yield = 75%

Let the actual yield be x

Hence;

75 = x/8.2 * 100

75 = 100x/8.2

75 * 8.2 = 100x

x = 75 * 8.2/100

x = 6.15 g

x = 6.2 g

75 =

Answer:

Baking soda is also used with cold water to remove surface rust. (Hot water can corrode steel). It is also useful when mixed with warm water to clean tea and coffee stains from the inside of mugs. Baking soda also works to unclog a sink. Sprinkle a few teaspoons of baking soda down the drain and splash some white vinegar on top.

Explanation:

Sodium bicarbonate reduces stomach acid. It is used as an antacid to treat heartburn, indigestion, and upset stomach. Sodium bicarbonate is a very quick-acting antacid.

The number of moles in 0.0250 g of NaCO₃ is calculated by dividing the given mass by the molar mass of NaCO₃.

The molar mass of NaCO₃ is the sum of the atomic masses of its constituent elements: sodium (Na), carbon (C), and oxygen (O). The atomic masses of these elements are 22.99 g/mol, 12.01 g/mol, and 16.00 g/mol, respectively. By adding these values together, we find that the molar mass of NaCO₃ is 105.99 g/mol.

\(\[ \text{{moles}} = \frac{{\text{{mass (g)}}}}{{\text{{molar mass (g/mol)}}}} \]\).

First, we need to determine the molar mass of NaCO₃. The molar mass of sodium (Na) is 22.99 g/mol, carbon (C) is 12.01 g/mol, and oxygen (O) is 16.00 g/mol. Since NaCO₃ contains one sodium atom, one carbon atom, and three oxygen atoms, the molar mass of NaCO₃ is:

\(\[ \text{{Molar mass of NaCO3}} = 22.99 \, \text{{g/mol}} + 12.01 \, \text{{g/mol}} + (16.00 \, \text{{g/mol}} \times 3) = 105.99 \, \text{{g/mol}} \]\)

Now, we can substitute the values into the formula:

\(\[ \text{{moles}} = \frac{{0.0250 \, \text{{g}}}}{{105.99 \, \text{{g/mol}}}} = 0.000235 \, \text{{mol}} \]\)

Therefore, 0.0250 g of NaCO₃is equal to 0.000235 moles of NaCO₃.

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Answer:

Solvent is 1.00 liter of water.

Answer:

It would be the water i think rlly srry if im wrong thats just what i got

Explanation:

because a solvent would be the one dissolving

Burning fossil fuels releases a variety of pollutants into the atmosphere, including carbon dioxide, sulfur dioxide, nitrogen oxides, particulate matter, mercury, etc.

Carbon dioxide is a greenhouse gas that traps heat in the atmosphere, contributing to global warming and climate change. Burning fossil fuels, such as coal, oil, and natural gas, is the largest source of human-generated carbon dioxide emissions. When fossil fuels containing sulfur are burned, they release sulfur dioxide into the air. Sulfur dioxide can react with other compounds in the atmosphere to form acid rain, which can damage crops, forests, and buildings. Burning fossil fuels also releases nitrogen oxides, which contribute to the formation of smog and acid rain. Nitrogen oxides can also react with other compounds in the atmosphere to form ozone, which is harmful to human health.

Hence,  Burning fossil fuels releases a variety of pollutants into the atmosphere, including carbon dioxide, sulfur dioxide, nitrogen oxides, particulate matter, mercury, etc.

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