Answers
Answer:
OB. Hydroelectricity
Explanation:
Because hydroelectricity is the process where electricity is generated by a motor being rotated by the force or current of water, and according to the laws of the water cycle, water is goes back to where it once was which leads us to conclude that hydroelectricity is a renewable source of energy.
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Related Questions
calculate a value for the equilibrium constant for the reaction below. (hint: when reactions are added together, the equilibrium expressions are multiplied.)
Answers
The angle of depression from the goldfinch to the base of the pole is 32°
What is the distance between the goldfinch and the base of the pole?
Give your answer to 2 d.p.
what is the process by which gas changes to a solid
Answers
In the following reaction, 2H2(g) + O2(g) --> 2H2O(g), how many moles of oxygen would be required to produce 5.76 moles of water?
Answers
Answer: 2.88
Explanation:assume oxygen as O2, then 1 mole O2 = 2 moles H2O
so 2.88 moles O2
What is the reactant(s) in the chemical equation below?
300(g) + Fe2O3(s) → 2Fe(s) + 3C02(9)
O A. 2Fe(s)
B. Fe2O3(s)
C. 2Fe(s) + 3C02(9)
D. 300(g) + Fe2O3(s)
SUBMIT
Answers
Answer:
I think it's D. 300(g) + Fe2O3(s)
Question 4 of 10
Which of the following is the correct model of C.H14?
o
A.
O
B.
O C.
D.
Answers
Answer:
B
Explanation:
Option B is correct because you have 6 vertices, indicating that there ate 6 carbons in the compound.
The complex ion Cu(NH3)42+ is formed in a solution made of 0.0200 M Cu(NO3)2 and 0.300 M NH3. What are the concentrations of Cu2+, NH3, and Cu(NH3)42+ at equilibrium? The formation constant*, Kf, of Cu(NH3)42+ is 1.70 × 1013.
Answers
The concentrations Cu(NH3)42+ at equilibrium is [Cu(NH3)42+] = 1.70 × 1013 * (0.0200M) * (0.300M)^4.
The concentrations of Cu2+ is [Cu(NH3)42+] + [Cu2+]
The concentrations of NH3 is 4[Cu(NH3)42+] + 4[NH3]
What is concentration equilibrium?Equilibrium concentration is described as a state when the rate of forward reaction in a chemical reaction becomes equal to the rate of backward reaction.
The equilibrium constant expression for the formation of the complex ion Cu(NH3)42+ is:
Kf = [Cu(NH3)42+] / [Cu2+] * [NH3]^4
where [Cu(NH3)42+], [Cu2+], and [NH3] are the molar concentrations at equilibrium.
The initial concentrations of Cu2+ and NH3 are 0.0200 M and 0.300 M respectively.
We have that Kf = 1.70 × 1013, we then rearrange the equation to solve for [Cu(NH3)42+]:
1.70 × 1013 = [Cu(NH3)42+] / (0.0200M) * (0.300M)^4
[Cu(NH3)42+] = 1.70 × 1013 * (0.0200M) * (0.300M)^4
Therefore at equilibrium, the concentration of Cu(NH3)42+ is [Cu(NH3)42+] = 1.70 × 1013 * (0.0200M) * (0.300M)^4
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NaIO3 + 6 HI ------ 3 I2 + NaI + 3 H2OCalculate the number of moles of iodine that can be made from 16.4 grams of NaIO3
Answers
ANSWER
The number of moles of iodine is 0.249 mol
EXPLANATION
Given that;
The mass of sodium iodate is 16.4 grams
Follows the steps below to find the number of moles of iodine
Step 1; Write a balanced equation of reaction
\(\text{ NaIO}_{3\text{ }}\text{ + 6HI }\rightarrow\text{ 3I}_2\text{ + NaI + 3H}_2O\)Step 2; Find the moles of NaIO3 using the below formula
\(\text{ mole = }\frac{\text{ mass}}{\text{ molar mass}}\)Recall, that the molar mass of NaOl3 is 197.89 g/mol
\(\begin{gathered} \text{ mole = }\frac{\text{ 16.4}}{\text{ 197.89}} \\ \text{ mole = 0.083 mol} \end{gathered}\)Step 3; Find the number of moles of iodine using stoichiometry ratio
In the equation above, 1 mole NaIO3 reacts to give 3 moles I2
Let x represents the number of moles of iodine
\(\begin{gathered} \text{ 1 mole NaIO}_3\text{ }\rightarrow\text{ 3 moles I}_2 \\ \text{ 0.083 mol NaIO}_3\text{ }\rightarrow\text{ x mol I}_2 \\ \text{ cross multiply} \\ \text{ 1 mole NaIO}_3\text{ }\times\text{ x mole I}_2\text{ = 3 moles I}_2\text{ }\times\text{ 0.083 mol NaIO}_{3e} \\ \text{ Isolate x mole I}_2 \\ \text{ x mole I}_2\text{ = }\frac{3\text{ moles I}_2\text{ }\times0.083mol\cancel{NaIO_3}}{1mole\cancel{NaIO_3}} \\ \\ \text{ x mole I}_2\text{ = 3 }\times\text{ 0.083} \\ \text{ x mole I}_2\text{ = 0.249 mol} \end{gathered}\)Therefore, the number of moles of iodine is 0.249 mol
Le Chatelier's Principle. For the reaction below, if the equilibrium concentrations were NH3 = 2 x 10-4, H3O+ = 2 x 10-4M and NH4+ = 18.0M, what is the equilibrium constant for the reaction and what would happen if you were to add some acid to this reaction? NH3 + H3O+ --> NH4+ + H2O
Answers
Answer:
Explanation:
NH3 + H3O+ --> NH4+ + H2O
equllibrium constant =K = [ H2O] [NH4+] / [NH3] [H3O+ ]
=
by inserting thier respecive values can you calcaulte, by the way coniseder [ H2O] =1 ,
How many moles of water contain each of the following number of molecules?
4.38 × 10^21 molecules
Report your answer using appropriate number of significant figures.
Answers
In 4.38 × 10^21 molecules of water, there are approximately 0.073 moles.
To calculate the number of moles, we can use Avogadro's number, which states that 1 mole of a substance contains 6.022 × 10^23 molecules. So, by dividing the given number of molecules (4.38 × 10^21) by Avogadro's number, we can find the number of moles.
Now, let's explain the process in detail. Avogadro's number is a constant that represents the number of particles (atoms, molecules, etc.) in one mole of a substance. It is approximately 6.022 × 10^23. Therefore, if we divide the given number of molecules by Avogadro's number, we can determine the number of moles.
In this case, we divide 4.38 × 10^21 molecules by 6.022 × 10^23 molecules/mole, resulting in approximately 0.073 moles.
Significant figures play an important role in reporting the answer. The given number of molecules has three significant figures (4, 3, and 8), so our answer should be reported with three significant figures as well. Therefore, the number of moles is approximately 0.073.
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the specific heat of water its 1 cal/gc how many calories are required when 50 grams of water are heated from 25 c to 75 c
Answers
Answer:
2500 Calories IS REQUIRED TO HEAT 50 g OF WATER FROM 25 C TO 75 C
Explanation:
Specific heat of water = 1 cal/gC
Mass = 50 g
Temperature change = 75 C - 25 C = 50 C
How many calories are required to heat the 50 g of water?
Heat = mass * specific heat * temperature change
Heat = 50 * 1 * 50
Heat = 2500 Calories
In other words, 2500 calories is required to heat 50 g of water from 25 C to 75 C.
In the reaction 2 Na(s) + Br2 ---> 2 NaBr(s). the (s) stands for
Answers
Answer:
The s stands for the phase of that element or compound. The phase solid is represented by (s). In this problem it is saying solid sodium (Na) is reacting with Bromine (Br) gas to form sodium bromide.
Explanation:
A 150-lb patient is prescribed acetaminophen at 7.34 mg/kg. If acetaminophen is available on hand as a 0.125 mg/ml syrup, how many mililiters will the nurse administer?
Answers
Answer:
The nurse should administer 3995.2 millilitres of syrup.
Explanation:
The conversion factor of pound weight to kilogram is; 1 lb = 0.453592 kg
The body weight of the patient in Kg = 150 * 0.453592 = 68.04 kg
A prescription of 7.34 mg/kg acetaminophen means that he should receive;
7.34 mg * 68.04 = 499.4 mg of acetaminophen
Amount in grams of acetaminophen per millilitre of syrup = 0.125 mg
Number of millilitres of syrup required = 499.4 mg / 0.125 mg/mL = 3995.2 mL
Therefore, the nurse should administer 3995.2 millilitres of syrup.
Write the equilibrium constant expression for this reaction: 2H+(aq)+CO−23(aq) → H2CO3(aq)
Answers
Answer:
Equilibrium constant expression for \(\rm 2\; H^{+}\, (aq) + {CO_3}^{2-}\, (aq) \rightleftharpoons H_2CO_3\, (aq)\):
\(\displaystyle K = \frac{\left(a_{\mathrm{H_2CO_3\, (aq)}}\right)}{\left(a_{\mathrm{H^{+}}}\right)^2\, \left(a_{\mathrm{{CO_3}^{2-}\, (aq)}}\right)} \approx \frac{[\mathrm{H_2CO_3}]}{\left[\mathrm{H^{+}\, (aq)}\right]^{2} \, \left[\mathrm{CO_3}^{2-}\right]}\).
Where
\(a_{\mathrm{H_2CO_3}}\), \(a_{\mathrm{H^{+}}}\), and \(a_{\mathrm{CO_3}^{2-}}\) denote the activities of the three species, and \([\mathrm{H_2CO_3}]\), \(\left[\mathrm{H^{+}}\right]\), and \(\left[\mathrm{CO_3}^{2-}\right]\) denote the concentrations of the three species.Explanation:
Equilibrium Constant ExpressionThe equilibrium constant expression of a (reversible) reaction takes the form a fraction.
Multiply the activity of each product of this reaction to get the numerator.\(\rm H_2CO_3\; (aq)\) is the only product of this reaction. Besides, its coefficient in the balanced reaction is one. Therefore, the numerator would simply be \(\left(a_{\mathrm{H_2CO_3\, (aq)}}\right)\).
Similarly, multiply the activity of each reactant of this reaction to obtain the denominator. Note the coefficient "\(2\)" on the product side of this reaction. \(\rm 2\; H^{+}\, (aq) + {CO_3}^{2-}\, (aq)\) is equivalent to \(\rm H^{+}\, (aq) + H^{+}\, (aq) + {CO_3}^{2-}\, (aq)\). The species \(\rm H^{+}\, (aq)\) appeared twice among the reactants. Therefore, its activity should also appear twice in the denominator:
\(\left(a_{\mathrm{H^{+}}}\right)\cdot \left(a_{\mathrm{H^{+}}}\right)\cdot \, \left(a_{\mathrm{{CO_3}^{2-}\, (aq)}})\right = \left(a_{\mathrm{H^{+}}}\right)^2\, \left(a_{\mathrm{{CO_3}^{2-}\, (aq)}})\right\).
That's where the exponent "\(2\)" in this equilibrium constant expression came from.
Combine these two parts to obtain the equilibrium constant expression:
\(\displaystyle K = \frac{\left(a_{\mathrm{H_2CO_3\, (aq)}}\right)}{\left(a_{\mathrm{H^{+}}}\right)^2\, \left(a_{\mathrm{{CO_3}^{2-}\, (aq)}}\right)} \quad\begin{matrix}\leftarrow \text{from products} \\[0.5em] \leftarrow \text{from reactants}\end{matrix}\).
Equilibrium Constant of ConcentrationIn dilute solutions, the equilibrium constant expression can be approximated with the concentrations of the aqueous "\((\rm aq)\)" species. Note that all the three species here are indeed aqueous. Hence, this equilibrium constant expression can be approximated as:
\(\displaystyle K = \frac{\left(a_{\mathrm{H_2CO_3\, (aq)}}\right)}{\left(a_{\mathrm{H^{+}}}\right)^2\, \left(a_{\mathrm{{CO_3}^{2-}\, (aq)}}\right)} \approx \frac{\left[\mathrm{H_2CO_3\, (aq)}\right]}{\left[\mathrm{H^{+}\, (aq)}\right]^2\cdot \left[\mathrm{{CO_3}^{2-}\, (aq)}\right]}\).
Duncan takes a break from studying and goes to the gym to swim laps if swimming burns, 615,000 cal per hour, how many kilojoules does swimming burn in the same amount of time?
Answers
out of ammonia (molecular mass 17 g ) and helium (mass 4 g ) which one diffuses faster?
Answers
Answer:
ammonia diffuses faster.
hope this helps.
AgNO 3 + NaCl → AgCl + NaNO 3
What are the ions?
Answers
Which of the following is an incorrect representation for a neutral atom?
36Li
613C
3063Cu
1530P
Answers
This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97. The incorrect representation for a neutral atom is 36Li
To determine the correct representation for a neutral atom, we need to consider the atomic number (Z) and mass number (A) of the element. The atomic number represents the number of protons in the nucleus, while the mass number represents the sum of protons and neutrons.
Let's analyze the given representations:
36Li:
This representation suggests that the element is lithium (Li) with a mass number of 36, which is incorrect. The correct mass number for lithium is approximately 6.94.
613C:
This representation suggests that the element is carbon (C) with a mass number of 13, which is correct. Carbon has different isotopes, and 13C represents one of its stable isotopes.
3063Cu:
This representation suggests that the element is copper (Cu) with a mass number of 63, which is correct. Copper has different isotopes, and 63Cu represents one of its stable isotopes.
1530P:
This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97.
Therefore, the incorrect representation for a neutral atom is 36Li, as it does not match the known properties of lithium.
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How many BONDS are there?
Answers
The chemical bonds are generally of two types, they are ionic and covalent bonds. Here the number of bonds in the given compound is 4.
What is a chemical bond?A chemical bond can be defined as the attractive force which holds the constituent atoms or ions of a molecular species together. Bonds arise from the electrostatic forces between the positively charged atomic nuclei and the negatively charged electrons.
The ionic bond is formed by the complete transfer of one or more electrons from one atom to another whereas the covalent bond is formed by the sharing of an electron pair between the atoms.
Here CCl₄ is a covalent compound which contains four non-polar covalent bonds between carbon and chlorine atoms. Here by sharing the electrons, 'C' attains the electronic configuration of 'Ne' and 'Cl' attains the configuration of 'Ar'.
Thus there are 4 bonds in CCl₄.
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Define biotechnology. } List two advantages in the use of biotechnology
Answers
Advantages of biotechnology:
Improvement of plants and animal breeds to give a high yield of their products.
Pests and pathogen control in agriculture which will reduce the loss of yield in food crops.
Synthesis of biocatalyst which can be used for enhancing the reactions which can be carried out in vitro or laboratory conditions.
Sewage treatment or water recycling can be done with the help of transgenic microbes which have better efficiency and speed.
Biotechnology is the use of living organisms or other biological systems in the manufacture of drugs or other products or for environmental management, as in waste recycling: includes the use of bioreactors in manufacturing, microorganisms to degrade oil slicks or organic waste, genetically engineered bacteria to produce human hormones, and monoclonal antibodies to identify antigens.
Biotech offers the possibility of improving human health, the environment, and agriculture while creating more sustainable modes of production.
PLEASE HELP!!
How does temperature, agitation, and particle size affect solubility?
Answers
Answer:
At higher temperatures, particles move faster and collide more, increasing solubility rates.
Agitation increases solubility rates as well, by bringing fresh solvent into contact with the undissolved solute
The smaller the particle size, the higher (faster) solubility rate. Vice versa, the bigger the particle size, the lower (slower) solubility rate.
Explanation:
With the reaction: 4 NH3 + 5 02 - 4 NO + 6 H20 If 4.3 g of O2 react, what mass of NO will form? urgent!!
Answers
Answer:
it will form Trioxonitrate (v) NO -1
Balance the chemical equations.
1FeCl3 + KOH → Fe(OH)3 + KC1
Answers
Answer:
FeCl3 + 3KOH → Fe(OH)3 + 3KCl
Explanation:
defintion for concentration
Answers
Answer:
concentration is the abundance of a constituent divided by the total volume of a mixture.
Explanation:
hope this helps <33
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what are the minerals responsible for the production of co2 gas in the kiln
Answers
Answer:
Explanation:limestone
CO2 is emitted from the calcination process of limestone, from combustion of fuels in the kiln, as well as from power generation.
Consider the following reaction: 2N2O5(g) → 4NO2(g) + O2(g) Calculate the volume N2O5 that must decompose completely to produce 9.64 L nitrogen dioxide.
Answers
The volume of \(N_2O_5\) needed to produce 9.64 L of \(NO_2\) is 4.97 L, calculated using stoichiometry and the ideal gas equation.
The given chemical equation is \(2N_2O_5(g) \rightarrow 4NO_2(g) + O_2(g)\) .The volume of \(N_2O_5\) that decomposes completely to form 9.64 L of \(NO_2\) is to be calculated. For this, we can use the concept of stoichiometry. Stoichiometry is a branch of chemistry that deals with the quantitative relationships between reactants and products in a balanced chemical equation.To calculate the volume of \(N_2O_5\) that is needed to produce 9.64 L of \(NO_2\), we will first determine the number of moles of NO2 produced in the reaction. For this, we can use the ideal gas equation, PV = nRT. Here, we have the volume of NO2 and we can assume the pressure and temperature to be constant. Thus, we have PV = nRT, where P = pressure, V = volume, n = number of moles, R = ideal gas constant, and T = temperature. Substituting the given values in the ideal gas equation, we get,n = PV/RT = (1 atm × 9.64 L)/(0.0821 L atm K-1 mol-1 × 300 K) = 0.404 molFrom the chemical equation, we see that 2 moles of \(N_2O_5\) give 4 moles of \(NO_2\). Thus, 0.404 mol of \(NO_2\) must have been produced from (0.404/2) = 0.202 mol of \(N_2O_5\). Using the ideal gas equation, we can also find the volume of 0.202 mol of \(N_2O_5\) at the given conditions. Thus, V = nRT/P = (0.202 mol × 0.0821 L atm K-1 mol-1 × 300 K)/1 atm = 4.97 L. Thus, the volume of \(N_2O_5\) that must decompose completely to produce 9.64 L nitrogen dioxide is 4.97 L.For more questions on stoichiometry
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C 2H 6 + Br 2 → C 2H 4Br 2 + HBr
what mass of HBr is produced if 0.884 mol of C2H6 is reacted?
Answers
The mass of HBr produced if 0.884 mol of ethane is reacted is 71.52g.
How to calculate mass stoichiometrically?Stoichiometry is the study and calculation of quantitative (measurable) relationships of the reactants and products in chemical reactions (chemical equations).
According to this question, ethane reacts with bromine to form ethyl bromide and hydrogen bromide as follows:
C₂H₆ + Br₂ → C₂H₄Br₂ + HBr
Based on the above equation, 1 mole of ethane produces 1 mole of hydrogen bromide (HBr).
This means that 0.884 moles of ethane will also produce 0.884 moles of hydrogen bromide.
Molar mass of HBr = 80.91 g/mol
mass of HBr = 0.884 moles × 80.91 g/mol
mass of HBr = 71.52g
Therefore, 71.52g is the mass of the HBr produced.
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What water system is part of the hydrological cycle and generally collects water from precipitation through a drainage basin from
surface runoff and other sources such as groundwater recharge and springs? This water system is usually freshwater flowing towards
an ocean, sea, or lake. In a few cases, it simply dries up completely at the end of its course, and does not reach another body of water.
es 0))
A)
tidal area
B)
watershed
09
wetland
D)
river
Answers
Rivers are part of the hydrological cycle. Water generally collects in a river from precipitation through a drainage basin from surface runoff and other sources such as groundwater recharge, springs, and the release of stored water in natural ice and snowpacks (e.g., from glaciers).
A gas has a volume of 50.0 mL at a temperature of 10.0 K and a pressure of 760. kPa. What will be the new volume when the temperature is changed to 20.0 K and the pressure is changed to 380. kPa?
Answers
To solve this problem using the gas laws, we need to use the Ideal Gas Law. This law states that the product of the pressure and the volume of a gas is proportional to the absolute temperature.
The equation of the Ideal Gas Law is the following:
\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{\dfrac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2} } \end{gathered}$} }\)
Where:
P₁ = initial pressure = 760 kPaV₁ = initial volume = 50.0 mL = 0.050 LT₁ = initial temperature = 10.0 KP₂ = Final pressure = 380 kPaT₂ = final temperature = 20.0 KV₂ = Final volume = ?We clear for V₂:
\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2=\frac{P_1V_1T_2}{P_2T_1 } } \end{gathered}$} }\)
Where:
P₁ = initial pressure V₁ = initial volumeT₁ = initial temperatureP₂ = Final pressureT₂ = final temperatureV₂ = Final volumeSubstituting the known values:
\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2=\frac{760\not{kPa}\times0.050 \ L\times20.0\not{k} }{ 380\not{kPa}\times10.0\not{k} } } \end{gathered}$} }\)
\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2=\frac{760 \ L}{3800 } } \end{gathered}$} }\)
\(\boxed{\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2\approx0.2 \ Liters} \end{gathered}$} }}\)
When the temperature changes to 20.0 K and the pressure changes to 380 kPa, the new volume will be approximately 0.2 L (200.0 mL).20.
An aqueous solution that has a hydrogen ion
concentration of 1.0 x 10-8 mole per liter has a pH of
A) 8, which is acidic B) 8, which is basic
C) 6, which is basic D) 6, which is acidic
b
Answers
Answer:
Maybe A
Explanation:
The pH of the aqueous solution is 8 means solution is basic.
How do we calculate pH?pH of any solution will be calculated by using the below equation:
pH = -log[H⁺]
Given that concentration of H⁺ ions = 1.0×10⁻⁸ M
On putting this value in the above equation, we get
pH = -log( 1.0×10⁻⁸ )
pH = -(0-8) = 8
Means the given aqueous soution is basic in nature.
Hence pH is 8 means solution is basic.
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For the reaction
2NH3(g)↽−−⇀ 3H2(g)+N2(g)
the equilibrium concentrations were found to be [NH3]=0.250 M, [H2]=0.470 M, and [N2]=0.800 M. What is the equilibrium constant for this reaction?
eq=
Answers
Rounding to the appropriate number of significant figures, the equilibrium constant (Kc) for the reaction is approximately 1.66.
To calculate the equilibrium constant (Kc) for the given reaction, we can use the formula:
Kc = ([H2]^3 * [N2]) / [NH3]^2
Plugging in the given equilibrium concentrations, we have:
Kc = (0.470^3 * 0.800) / (0.250^2)
Calculating the numerator:
(0.470^3 * 0.800) = 0.1037032
Calculating the denominator:
(0.250^2) = 0.0625
Now, dividing the numerator by the denominator:
Kc = 0.1037032 / 0.0625 = 1.6592512
The equilibrium constant represents the ratio of the concentrations of products to reactants at equilibrium. In this case, the equilibrium constant is greater than 1, indicating that the products (H2 and N2) are favored at equilibrium. This means that the forward reaction is favored, leading to the formation of more products compared to reactants.The equilibrium constant value of 1.66 suggests that the forward reaction is moderately favored at equilibrium, but without additional context, it is difficult to determine the extent of the reaction or the relative concentrations of reactants and products at the beginning of the reaction.
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