In nuclear magnetic resonance (NMR) spectroscopy, the chemical shift is the resonant frequency of an atomic nucleus relative to a trendy in a magnetic field.
Often the placement and range of chemical shifts are diagnostic of the shape of a molecule. The chemical shift in absolute phrases is described via way of means of the frequency of the resonance expressed close to a trendy compound that is described to be at zero ppm. The scale is made greater workable via way of means of expressing it in elements in keeping with million (ppm) and is indepedent of the spectrometer frequency.
1) electronegativity of atoms increases chemical shift value also increases.
2) number of electronegative atoms increases chemical shift value is also more
3) CH4 has no Cl atoms . so it has least chemical shift
4) CHCl3 has 3 higher electronegative atoms . so it has higher chemical shift.
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the pressure on 20 milliliters of a gas at constant temperature is changed from 4 atmospheres to 2 atmospheres. what is the new volume of the gas?
The new volume of the gas whose pressure was changed would be = 40 milliliters.
How to calculate the new volume of the given gas?The initial volume(V1)of the gas= 20ml
The initial pressure(P1) = 4 atm
The final pressure(P2) = 2 atm
The final volume(V2) = ?
Using the general gas formula;
P1V1 = P2V2
V2 = P1V1/P2
= 4×20/2
= 40ml
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Chemistry Lab Determination of the Universal Gas Constant (R)
SHOW ALL WORK
Given:
Initial mass of butane lighter: 54.24g
Final Mass of Butane Lighter: 54.01g
Temperature of water: 23.0°C
Volume of gas collected: 100.0mL
FIND:
Barometric pressure of room: 766.86 mmHg CONVERTED TO atm
Vapor pressure of water at room temperature(PH2O) (IN atm)
FIND:
Mass difference if butane lighter in grams
Moles of Butane gas collected in moles of C4H10
Partial pressure if butane gas in atm
Converted temperature of water in Kelvin
Converted volume of gas collected in Liters
Experimental value of R in Latm/molk
Accepted value of R in Latm/molk
Percent error in experimental value of R in %
CONCLUSION QUESTIONS:
1. List at least 3 factors that either did it could contribute to the percent error
2. Should the value of R go up or down if the gas had not been corrected for the partial pressure of water. Why?
3. How could this experiment be repeated to increase the accuracy, or in other words, decrease the percent error?
NOTE: LET ME KNOW IF YOU WANT A PICTURE OF THE LAB INSTRUCTIONS TO HELP SOLVE
ALSO SHOW ALL WORK PLS
To solve this problem, I'll need some additional information related to the molar mass of butane (C4H10). Please provide the molar mass of butane so that I can proceed with the calculations.
Which sample contains the greatest number of atoms?
(a) 10.0 g He (b) 25.0 g Ne (c) 115 g Xe
Maintenance of............of the body such as temperature level, water content, pH and blood pressure to be in balanced and stable condition
An atom has a diameter of 3.50 Å and the nucleus of that atom has a diameter of 6.50×10−5 Å . Determine the fraction of the volume of the atom that is taken up by the nucleus. Assume the atom and the nucleus are a sphere.
fraction of atomic volume:
1.43236148
×10
−14
Calculate the density of a proton, given that the mass of a proton is 1.0073 amu and the diameter of a proton is 1.73×10−15 m .
density:
g/cm 3
A proton's density is equal to 3.962 E14 g/cm3, given that it has a mass of 1.0073 amu and a diameter of 1.73 1015 m.
What do protons go by?Although protons were once thought to be elementary particles, the Standard Model of particle physics now recognises them as composite particles that comprise three valence quarks. Protons and neutrons are collectively referred to as hadrons.
Proton mass = 1.0073 amu, amu = 1.66054 E-24 g, and g proton = (1.0073 amu)(1.06654 E-24 g/amu = 1.074 E-24 g.
V = 4/3πr³\s∴ For example, r = D/2 ≈ 1.73 E-15 m)/2 = 8.65 E-16 m, where V = (4/3) (8.65 E-16 m) 3 = (1.074 E-24 g)/(2.711 E-39 cm3) = 3.962 E14 g/cm3
What is an example of a proton?Protons include the H+ ion or the hydrogen atom's nucleus. Regardless of the isotope, each hydrogen atom has one proton, each helium atom has two, each lithium atom has three, and so on.
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what scientific term for baby can be applied both to plants and animals!
I need help! It's 9 letters long!
Answer:
Offspring
I hope this is the word you want.
Offspring is used to mention both babies of animals and plants.
Answer:
Offspring
hope this helps and please give the above answer brainliest
If 2.47 g of CuNO3 is dissolved in water to make a 0.820 M solution, what is the volume of the solution in milliliters?
volume:
Answer:
23.4 milliliters
Explanation:
Note 1: This answer assumes that the volume of CuNO3 is negligible
Note 2: CuNO3 can't be produced in any meaningful quantities and can't be obtained by the average chemist, maybe you meant Cu(NO3)2 instead?
From the definition of molarity, molarity = moles / volume
the number of moles is the number of grams divided by the molar mass, or
2.47 divided by 125.55 which is 0.01967
The M and moles is known so volume can be found.
0.82 = 0.01967 / volume
0.82 * volume = 0.01967
volume = 0.01967 / 0.82 = 0.023988 liters = 23.4 milliliters
In general, when hydrocarbons like oil are added to water, the two liquids_______ because hydrocarbons are______ and water is_______
Answer:
do not mix, non-polar, polar
Explanation:
In general, when hydrocarbons like oil are added to water, the two liquids do not mix because hydrocarbons are non-polar and water is polar.
As a general rule of solubility, we say "like dissolves like", meaning polar compounds are soluble in polar solvents and non-polar compounds are soluble in non-polar solvents
This is due to the intermolecular forces, which are dispersion forces for non-polar compounds and dipole-dipole interactions for polar compounds.
Increasing the temperature of a salt water solution will result in a greater amount of salt being dissolved in solution
Answer:
true
Explanation:
heat will destroy the salt components quicker
The composition of a compound is 28.73% K, 1.48% H, 22.76% P, and 47.03% O. The molar mass of the
compound is 136.1 g/mol.
I
The compound has an empirical formula of \(K_2H_2P_2O_8\) and a molecular formula of \(K_2HPO_4\).
The given compound has a percent composition of K = 28.73%, H = 1.48%, P = 22.76%, and O = 47.03%. Its molar mass is 136.1 g/mol. To determine its molecular formula, we need to find its empirical formula and calculate its molecular formula from its empirical formula.The empirical formula is the smallest whole number ratio of atoms in a compound. It can be determined by converting the percent composition of the elements into their respective moles and dividing each by the smallest number of moles calculated. The moles of K, H, P, and O in 100 g of the compound are: K = 28.73 g x (1 mol/39.1 g) = 0.734 molH = 1.48 g x (1 mol/1.01 g) = 1.46 molP = 22.76 g x (1 mol/30.97 g) = 0.736 molO = 47.03 g x (1 mol/16.00 g) = 2.94 molDividing each by the smallest number of moles gives the following ratios: K = 0.734/0.734 = 1H = 1.46/0.734 = 2P = 0.736/0.734 = 1.002O = 2.94/0.734 = 4. The empirical formula of the compound is \(K_2H_2P_2O_8\). To calculate the molecular formula, we need to determine the factor by which the empirical formula should be multiplied to obtain the molecular formula. This can be done by comparing the molar mass of the empirical formula to the molar mass of the compound.The molar mass of \(K_2H_2P_2O_8\) is: \(M(K_2H_2P_2O_8)\) = (2 x 39.1 g/mol) + (2 x 1.01 g/mol) + (2 x 30.97 g/mol) + (8 x 16.00 g/mol) = 276.2 g/mol. The factor by which the empirical formula should be multiplied is: M(molecular formula)/M(empirical formula) = 136.1 g/mol/276.2 g/mol = 0.4935. The molecular formula is obtained by multiplying the empirical formula by this factor: \(K_2H_2P_2O_8 * 0.4935 = K_2HPO_4\). Therefore, the molecular formula of the compound is \(K_2HPO_4\).The molecular formula of the given compound having a composition of 28.73% K, 1.48% H, 22.76% P, and 47.03% O with a molar mass of 136.1 g/mol is \(K_2HPO_4\). The empirical formula of the compound is \(K_2H_2P_2O_8\). The compound's molecular formula is calculated by determining the factor by which the empirical formula should be multiplied to obtain the molecular formula. The factor is M(molecular formula)/M(empirical formula) = 136.1 g/mol/276.2 g/mol = 0.4935. The molecular formula of the compound is obtained by multiplying the empirical formula by this factor, resulting in the molecular formula \(K_2HPO_4\).For more questions on empirical formula
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The correct question would be as
The composition of a compound is 28.73% K. 1.48% H, 22.76% P, and 47.03% O. The molar mass of the compound is 136.1 g/mol. What is the Molecular Formula of the compound?
\(KH_2PO_4\\KH_3PO_4\\K_2H_4P_20_{12}\\K_2H_3PO_6\)
help i will mark brainliest
Answer:
Image A
Explanation:
The hemisphere experiences summer when it is tilted towards the sun. Image a has the northern hemisphere tilted towards the sun.
Answer:
image A
Explanation:
this is because the sun is hitting earth at a steep angle
The motion of gas particles is described by straight line motion, followed by a collision and a change in direction. This is know as
Answer:
It is called the Random Walk, where the next move (as seen through the motion of gas particles) depends on chance.
Explanation:
What is the binding energy for the nuclide 199F (atomic mass: 18.9984 amu) in MeV per nucleus?
The binding energy per nucleon for the ¹⁹F nucleon is equal to 7.786 MeV/nucleon.
What is binding energy?Binding energy can be defined as the minimum quantity of energy that is required to remove the particle from the system. Nuclear binding energy can be described as the energy required to dismantle a nucleus of an atom into free neutrons and protons.
The binding energy will be determined from the mass defect. Mass defect is calculated from the difference between the mass observed and the expected combined mass.
Given the mass of the ¹⁹F = 18.9984 a.m.u.
The mass defect for the ¹⁹F can be calculated as:
Δm = \((M _n +M_p) - M_F\)
\(\triangle m =( 9\times 1.0078 + 10 \times 1.0087 )- 18.9984\)
\(\triangle m =0.1588 \;a.m.u.\)
The binding energy for the fluorine can be calculated as:
E = Δmc²
E = 0.1588 × 931.5
E = 147.92 MeV
The binding energy per nucleon of ¹⁹F can be calculated as:
B.E.N. = 147.92/18.9984 = 7.786 MeV per nucleon
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You find a clean 100-ml beaker, label it "#1", and place it on a tared electronic balance. You add small amount of unknown solid and place the
beaker with its contents on the balance. The recorded data is:
mass of the empty, clean beaker #1: 74.605 g
mass of the beaker #1 with the white solid: 74.896 g
Using the Law of Conservation of Mass, what is the mass of the unknown solid you placed in beaker #1?
Answer:
the mas is .291 g
Explanation:
the mass of a object does not change. so when added the substance the beaker. you had the mass of both objects together. you know the mass of the beaker and you know the mass of both. since mass does not change. the beakers mass is still 74.605g. the mass of both objects is 74.896. all you have to do is subtract the mass of the beaker from the total mass. 74.896 - 74.605 equals .291g. so the mass of the unknown substance Is .291g
As atoms vibrate faster, the space between them decreases. True or false?
I belive that your answer would be False
How are gases ionize in a plasma globe?
Answer:
Plasma globes use high voltage, low current electrical discharges to ionize gases, typically a mixture of noble gases such as argon and neon, inside the globe. The electrical discharge excites the gas atoms, stripping them of their electrons to create a cloud of positively charged ions and negatively charged electrons, also known as plasma. The electrical discharge arcs between the electrodes in the globe, creating the colorful, dancing lights that are characteristic of plasma globes.
Explanation:
If a solution has 17.2 moles of LiF in 2000 mL of water, what is the molarity?
4.2 M
10 M
2 M
8.6 M
Molarity, M = (n x 1000) / vol (in ml)
M = 17.2 x 1000/ 2000
M = 8.6 mol/L
a student has a 1 L solution of 2 M HCL and wants to increase the HCL concentration to 3 M
The student needs to add approximately 83.3 mL of 12 M HCl solution to the existing 1 L of 2 M HCl solution to increase the concentration to 3 M. It is important to handle concentrated acids with caution and follow proper safety procedures.
To increase the concentration of a 1 L solution of 2 M HCl to 3 M, the student needs to calculate the volume of concentrated HCl needed and add it to the existing solution. Here's how the calculation can be done:
Given:
Initial concentration of HCl solution = 2 M
Final concentration desired = 3 M
Initial volume of HCl solution = 1 L
Step 1: Calculate the moles of HCl in the initial solution.
Moles of HCl = Initial concentration × Initial volume = 2 M × 1 L = 2 moles
Step 2: Calculate the moles of HCl needed for the desired concentration.
Moles of HCl needed = Final concentration × Final volume = 3 M × 1 L = 3 moles
Step 3: Calculate the moles of HCl to be added.
Moles of HCl to be added = Moles needed - Moles present = 3 moles - 2 moles = 1 mole
Step 4: Convert the moles of HCl to the required volume of concentrated HCl.
To calculate the volume, we need to know the concentration of the concentrated HCl solution. Assuming it is 12 M, we can use the following formula:
Volume of concentrated HCl = Moles of HCl to be added / Concentration of concentrated HCl
Volume of concentrated HCl = 1 mole / 12 M = 0.0833 L or 83.3 mL
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Which action would shift this reaction away from solid calcium fluoride and toward the dissolved ions?a) adding calcium ionsb) adding fluoride ionsc) removing fluoride ionsd) removing calcium fluoride
Answer:
c) removing fluoride ions.
Explanation:
Hello!
In this case, for this solubility product problem, it is very convenient to write the undergoing ionization reaction:
\(CaF_2(s)\rightleftharpoons Ca^{2+}(aq)+2F^-(aq)\)
In such a way, via the Le Chatelier's principle, we remember that the addition of reactants shifts the reaction towards products, adding products shifts the reaction towards reactants, removing reactants shifts the reaction towards reactants and removing products shifts the reaction towards products. In means, that the best way to shift this reaction away from solid calcium fluoride and toward the dissolved ions is c) removing fluoride ions, because it is a product and its removal favors the formation of more products.
Best regards!
A 33.41 g piece of copper at 95.6 Celsius was placed in a sample of water at 21.65 Celsius. The temperature of the water increased to 22.87 Celsius. To what mass of water was the cooper added? The specific heat of copper is 0.385 J/g C
Answer:
43.63 g of water.
Explanation:
We can use the equation for heat transfer to solve for the mass of water:
q = cmΔT
where
q = heat transfer
c = specific heat
m = mass
ΔT = change in temperature
The heat transfer from the copper to the water can be expressed as:
q = cmΔT
q = (33.41 g)(0.385 J/g°C)(95.6°C - 21.65°C)
And the heat transfer caused a change in temperature in the water, which can be expressed as:
q = mLΔT
q = (m)(4.18 J/g°C)(ΔT)
Equating the two expressions for heat transfer, we can solve for the mass of water:
(33.41 g)(0.385 J/g°C)(95.6°C - 21.65°C) = (m)(4.18 J/g°C)(22.87°C - 21.65°C)
m = (33.41 g)(0.385 J/g°C)(95.6°C - 21.65°C) / (4.18 J/g°C)(22.87°C - 21.65°C)
m = 43.63 g
So the copper was added to 43.63 g of water.
The pressure inside a tire is measured as 28.0 pounds/inches^2. What is its pressure in newtons/centimeters^2
The pressure inside the tire is approximately 1.970796 newtons per square centimeter (N/cm²) when measured in those units.
To convert the pressure from pounds per square inch (psi) to newtons per square centimeter (N/cm²), we need to use the conversion factors between these units.
First, let's convert pounds to newtons:
1 pound = 0.45359237 kilograms
1 kilogram = 9.80665 newtons
Next, let's convert square inches to square centimeters:
1 square inch = 6.4516 square centimeters
Now, we can perform the conversion:
1 psi = (0.45359237 kg) × (9.80665 N/kg) / (6.4516 cm²)
≈ 0.070307 N/cm²
Therefore, the pressure inside the tire of 28.0 psi is approximately equal to 28.0 × 0.070307 N/cm², which is approximately 1.970796 N/cm².
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Unknown compound has the following E.A.: C= 81.71%, H =18.29%. Its MWt = 44. What its empirical formula and structural formula of the compound?
C₃H₈ has an empirical formula mass of 44 g/mol. Hence, C₃H₈ is also the molecular formula.
What is cοmpοund?When twο οr mοre distinct elements are chemically mixed in a specific ratiο, the resultant substance is knοwn as a cοmpοund. Chemical bοnds, such as cοvalent bοnds, iοnic bοnds, οr metallic bοnds, hοld the cοnstituent parts οf a cοmpοund tοgether.
We must first cοmpute the mοles οf each element present in the cοmpοund in οrder tο derive its empirical fοrmula.
We can figure οut hοw many mοles οf carbοn and hydrοgen there are in 100 g οf the chemical by dοing the fοllοwing calculatiοn:
81.71 g / 12.011 g/mol = 6.80 moles of carbon
18.29 g / 1.008 g/mol of hydrogen = 18.15 moles.
The simplest whole number ratio of carbon to hydrogen atoms must next be determined. In order to do this, we divide both values by the lesser amount, in this case 6.80 moles:
Carbon: 6.80 moles / 6.80 moles = 1.00 Hydrogen: 18.15 moles / 6.80 moles = 2.67
To get whole numbers, we must multiply both values by a factor. By multiplying each by 3, the smallest whole number ratio is obtained:
1.00 x 3 = 3 carbon
2.67 x 3 = 8.01 x 8 for hydrogen.
As a result, the compound's empirical formula is C₃H₈.
Knowing the compound's molecular weight is necessary to determine its molecular formula. The compound's MWt (molecular weight) is 44, as stated.
C₃H₈ has an empirical formula mass of 44 g/mol. Hence, C₃H₈ is also the molecular formula.
Any molecule with the empirical formula C₃H₈, like propane, might be the structural formula of the chemical (CH₃CH₂CH₃).
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Consider the combustion of hexane:
2C6H14+19O2=12CO2+14H2O
a. If you started with 7.77 moles of hexane, how many of carbon dioxide could be produced?
b. If you started with 8.11g of hexane, how many moles of carbon dioxide could be produced?
c. How many grams of oxygen gas are needed to react with 25 moles of hexane?
d. What mass of water vapor, in kg, could be produced from combustion of 55.3kg of hexane?
a. As per the balanced reaction, 2 moles of hexane gives 12 moles of carbon dioxide. Then, 7.77 moles of hexane will give 46.2 moles of carbon dioxide.
What is combustion ?Combustion is an exothermic reaction in which a gas reacts with oxygen to give carbon dioxide and water. Given the combustion reaction of hexane gas.
b. molar mass of hexane = 86 g/mol
no.of moles in 8.11 g = 8.11 /86 = 0.094 g
2 moles of hexane gives 12 moles of carbon dioxide. Then 0.094 moles of hexane will give
0.094 × 12/2 = 0.56 moles
molar mass of carbon dioxide = 44 g/mol
then, mass of 0.56 moles = 0.56 × 44 = 24.6 g
c. 2 moles of hexane reacts with 19 moles of oxygen gas. Then, 25 moles of hexane needs to reacts with 237.5 moles of oxygen gas.
mass of oxygen gas = 32 g/mol
mass of 237.5 moles = 32 × 237.5 = 7600 g of oxygen is needed.
d. 2 moles of hexane gives 14 moles of water vapor. That is 172 g of hexane gives (18 × 14) 252 g of water.
then, 55.3 kg of hexane gives:
(55.3 kg × 0.252 kg)/0.172 kg = 81 kg.
Therefore, 81 kg of water vapor is produced from 55.3 kg of hexane.
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Question:
Many island chains were formed as a result of blank volcanism
Many island chains were formed as a result of blank volcanism is known as hotspot volcanism.
Hotspot volcanism occurs when a mantle plume, a column of hot and buoyant rock material rising from deep within the Earth's mantle, reaches the surface. These mantle plumes are stationary relative to the moving tectonic plates on the Earth's surface.
As the tectonic plate moves over the stationary hotspot, the mantle plume melts and produces magma. This magma rises through the Earth's crust, creating a volcanic eruption. Over time, repeated eruptions build up layers of lava and volcanic material, forming a cone-shaped volcano. As the tectonic plate continues to move, the volcano becomes inactive, and a new volcano forms above the stationary hotspot.
However, in the case of island chains, the tectonic plate movement carries the volcanoes away from the hotspot. As a result, a trail of extinct volcanoes is left behind, forming a linear chain of islands. Each island in the chain represents a period of volcanic activity at that specific location as the plate moved over the hotspot.
Hotspot volcanism and the formation of island chains provide valuable insights into the dynamics of Earth's mantle and plate tectonics. By studying the age progression of islands in a chain, scientists can gain a better understanding of the movement and speed of tectonic plates and the behavior of mantle plumes deep beneath the Earth's surface.
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A solution of 6.54 g of a carbohydrate in 102.5 g of water has a density of 1.024 g/mL and an osmotic pressure of 4.61 atm at 20.0°C. Calculate the molar mass of the carbohydrate.
The molar mass of the carbohydrate : = 304.19 g/mol
Further explanationGiven
6.54 g carbohydrate
102.5 g of water
osmotic pressure of 4.61 atm
T = 20+273=293 K
Required
The molar mass
Solution
General formula:
\(\large {\boxed {\bold {\pi \: = \: M \: x \: R \: x \: T}}}\)
π = osmosis pressure (atm)
M = solution concentration (mol / l)
R = constant = 0.08205 L atm mol-1 K-1
T = Temperature (Kelvin)
Find molarity(M) :
4.61 atm = M . 0.08205 x 293
M = 0.192 mol/L(mol solute per 1 liter solution)
Total mass of solution :
= 6.54 g + 102.5
= 109.04 g
Volume of solution :
= density x mass
= 1.024 g/ml x 109.04 g
= 111.66 ml
= 0.112 L
mol Carbohydrate (solute):
= M x V
= 0.192 x 0.112
= 0.0215 mol
Molar mass of Carbohydrate :
= mass : mol
= 6.54 : 0.0215
= 304.19 g/mol
Read the descriptions below of two substances and an experiment on each. Decide whether the result of the experiment tells you the substance is a pure substance or a mixture, if you can. • Sample A is a solid yellow cube with a total mass of 50.0 g. The cube is put into a beaker filled with 250. mL of water. The cube collapses into a small pile of orange powder at the bottom of the beaker. When this powder is filtered out, dried and weighed, it has a total mass of 29.9 g. If the experiment is repeated with 500. mL of water, the powder that's left over has a mass of 10.0 g. Sample B is 100. g of a coarse grey powder with a faint unpleasant smell. 15. mg of the powder are put into a very thin tube and heated. The powder begins melting at 66.2 °C.The temperature stays constant as the powder slowly melts. After the last of the powder melts, the temperature starts to rise again, eventually reaching 76.0 °C. O pure substance Is sample A made from a pure substance or a mixture? x ? mixture If the description of the substance and the outcome of the experiment isn't enough to decide, choose "can't decide. (can't decide) O pure substance Is sample B made from a pure substance or a mixture? If the description of the substance and the outcome of bstance and the outcome of the experiment isn't enough to decide, choose "can't decide." mixture (can't decide)
Answer and Explanation: Sample A is a mixture. Solubility is characteristics of each substance, which means a substance can be distinguished from other substances and can be useful to separate mixtures.
In Sample A, when is added different volumes of water, the resulting powder has different mass. This means there are more than one substance forming the yellow cube. Therefore, sample A is a mixture.
Sample B is a pure substance. Each substance has its own melting point. Whe na pure substance reaches its melting point, temperature is constant until all of that substance is melted. In sample B, temperature is stable at 66.2°C and then, after all the powder is melted, it rises again. Therefore, sample B is a pure substance.
The answer is B but why and how we can solve such problem?
Answer:
\(\text{CsF}\)Explanation:
Here, we want to get the most ionic fluoride
Cs is a group 1 element, same as sodium
However, we know that electropositivity increases down the group while electronegativity decreases down the group
Also, electropositivity decreases across the period. It is expected that a group 1 element will be more electropositive than a group 3 element.
Thus, we are having a bond between a very electropositive metal and a very electronegative non-metal. That is why we have CsF (it is the strongest and most electropositive atom in the options listed) as the molecule with the strongest ionic bond on the list
Can someone please quickly answer this question?
Does it matter the order for an electronic configuration? So, like for the electronic configuration of Tin, can I either use [Kr]4d^105s^25p^2 or [Kr]5s^24d^1050^2
I’m just confused, when I look it up they show both so I don’t know which one is correct so I can use for my lab report?
Answer:
The difference between the two is:
\([Kr]4d^1^05s^25p^2\) is the Orbital Occupancy
\([Kr]5s^24d^1^05p^2\) is the Orbital Filling Order
Both are correct, I don't think your teacher will be so nit-picky to care.
The combustion of ethane (C2H6) produces carbon dioxide and steam.
2C2H6(g)+7O2(g)⟶4CO2(g)+6H2O(g)
How many moles of CO2 are produced when 5.55 mol of ethane is burned in an excess of oxygen?
Answer:
11.1 moles of CO2
Explanation:
2C2H6(g) + 7O2(g)⟶4CO2(g)+6H2O(g)
To find the number of moles of CO2 produced when 5.55 mol of ethane is burned in an excess of oxygen, use the stoichiometry of the reaction.
5.55 mol C2H6 x (4 mol CO2/2 mol C2H6) = 11.1 mol CO2
Therefore, 5.55 mol of ethane is burned in an excess of oxygen produces 11.1 moles of CO2.
A) Which statement correctly describes the relationship between molecular structure, the strength of electrostatic forces
between molecules, and the boiling point of a substance? (1 point)
The boiling point of a substance affects the strength of electrostatic forces, which can affect the molecular structure.
The boiling point of a substance affects its molecular structure, which can affect the the strength of electrostatic forces
Molecular structure affects the strength of electrostatic forces, which can affect the boiling point of a substance.
Stronger electrostatic forces cause a stronger molecular structure and lower boiling points.
The greater the electrostatic attraction in the molecule, the greater the boiling point of the compound.
We have to note that the molecular structure of a compound determines whether the compound will be polar or not and this in turn affects the electrostatic forces in the molecule.
Also, the electrostatic forces in the molecule determines certain important properties of the compound such as boiling point. The greater the electrostatic attraction in the molecule, the greater the boiling point of the molecule.
Hence, the statement which correctly describes the relationship between molecular structure, the strength of electrostatic forces between molecules, and the boiling point of a substance is; "molecular structure affects the strength of electrostatic forces, which can affect the boiling point of a substance."
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