The force exerted by the wind on the sails of a sailboat is 400 N north. The water exerts a force of 190 N east. If the boat (including its crew) has a mass of 250 kg, what are the magnitude and direction of its acceleration?magnitude _____ m/s2direction _____ ° north of east

Answer:

  163 N

Explanation:

The density of copper is about 8.96. The ratio of the weight in water to the weight in air is about 1-1/ρ, so is about 0.8884.

  0.8884 × 184 N ≈ 163 N

The submerged weight is about 163 N.

The time period of the stone is 1/3 revolution per second or 0.33 s. The speed of the stone is 5.7 m/s.

Time period is the reciprocal of rps = 1/3 = 0.33 s

Speed of the stone, v = 2πr/T = 5.7 m/s

An object moves in a uniform circular motion when it moves at a fixed pace around a circle. In the case of uniform circular motion, both the speed and the angular velocity stay constant.

Mud flying from a tyre and kids sensing a force pushing them outwards while spinning on a roundabout are two classic instances of centrifugal force in action. The rotation of satellites around a planet is a prominent example of centripetal force in action. a satellite using centripetal force to orbit the globe.

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The given question is incomplete. The complete question is:

Your roommate is working on his bicycle and has the bike upside down. he spins the 70.0 cm -diameter wheel, and you notice that a pebble stuck in the tread goes by three times every second.

(a) What is the time period of the stone?

(b) What is the speed of the stone?

The value of charge in the plate to levitate a load of mass of 100 kg will be 1.33 x 10^-5 C.

The electric field(E) produced by a 2D plate is given by the following formula:

E = σ/2ε

Here σ is the surface charge density = Charge/Area = Q/A

To levitate a plate, the force exerted by this field should be equal to the weight of the load.

Thus,

Electric force due to plate = Weight of the load

qE = mg

Putting the given values in the above equation

Q x Q/2Aε = mg

Q^2 = mg(2ε)(A)

On solving

Q = 1.33 x 10^-5 Coulombs.

Thus, The value of charge in the plate to levitate a load of mass of 100 kg will be 1.33 x 10^-5 C.

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Answer:

\(dU=-4.36*10^{-18}J\)

Explanation:

From the question we are told that:

Average distance \(d_{avg} =5.29*10^{-11}m\)

Generally the equation for change in electric potential energy is mathematically given by

\(dU=u_f-U_1\)

Where

U_1=0 Because of initial lengthy distance apart

And

\(U_f=\frac{kq_eq_p}{d}\)

\(U_f=\frac{9*10^9*1.6*10^{-19}*-1.6*10^{-19}}{5.29*10^{-11}}\)

\(U_f=-4.36*10^{-18}J\)

Therefore

\(dU=u_f-U_1\)

\(dU=-4.36*10^{-18}J-0\)

\(dU=-4.36*10^{-18}J\)

Answer:

false

Explanation:

Answer:

false

Explanation:

edge

Answer:

if your going 15000 mph all you can do is accelerate  or go fast  unless there is a opposite

Explanation:

Explanation:

hope this helps, cheers!

The values for the average speed and average velocity are;

(a) \(Average \ speed = 1.37\overline{142857} \ m/s\)

(b) \(The \ average \ velocity = 0.\overline{857142} \ m/s\)

The reason the above values are correct is given as follows;

The given parameters are;

Distance of the nearest grocery store to the house, d = 60 m

Direction of the grocery store = East from the house

Walking speed, s = 1.2 m/s

Time of walking before the rain started, t₁ = 15.0 s

Time it takes to go back to the house, t₂ = 5.0 s

Speed at which the start walking again, s = 1.2 m/s

(a) The formula for average speed, \(s_{avg}\), is given as follows;

\(s_{avg} = \dfrac{Total \ distance }{Sum \ of \ time \ taken}\)

The distance walked before the rain, d₁ = 1.2 m/s × 15.0 s = 18 meters

Distance covered on returning to the house = d₂ = d₁ = 18 meters

The total distance covered, ∑Distance = d₁ + d₂ + 60

∴ ∑Distance = 18 m + 18 m + 60 m = 96 m

The time, t₃, it takes to get to the grocery store on the second attempt after getting the umbrella is given as follows;

\(t_3 = \dfrac{d}{v}\)

\(t_3 = \dfrac{60 \ m}{1.2 \ m/s} = 50.0 \, s\)

The total time, ∑Time = t₁ + t₂ + t₃

∴ ∑Time = 15.0 s + 5.0 s + 50.0 s = 70.0 s

\(Average \ speed = \dfrac{\sum Distance}{\sum Time}\)

\(Average \ speed = \dfrac{96 \, m}{70 \, s} = \dfrac{48}{35} \ m/s= 1.37\overline{142857} \ m/s\)

\(Average \ speed = 1.37\overline{142857} \ m/s\)

(b) The average velocity, \(v_{avg}\), is given as follows;

\(v_{avg}= \dfrac{Total \ displacement}{Total \ time}\)

The total displacement = The total change in location = The change in location from the house to the grocery =  60 m

The total time is the same as for the average speed, ∑Time = 70 s

\(\therefore v_{avg}= \dfrac{60 \, m}{70 \, s} = \dfrac{6}{7} \ m/s = 0.\overline{857142} \ m/s\)

\(The \ average \ velocity = 0.\overline{857142} \ m/s\)

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Answer:

The answer is 0.042 Hz (rounded)

or 0.0417 Hz

Explanation:

Hope it helps

Answer:

The answer is 0.041Hz

Explanation:

The answer is 0.041Hz

I guess

Answer:

4.926 L Y 7.389 L

Explanation:

first you calculate the tank volume

V = π\((14 cm)^{2}\)(10 cm = \(12315 cm^{3}\)

then you convert to liters

\(12315 cm^{3}\) = 12.315 l

then you calculate the liters of water

2/5(12.35 l) = 4.926 l

finally we calculate the amount without water

12.315 l - 4.926 l = 7.389 l

HERE IS MORE INFORMATION ON THE SUBJECT. THEY REMOVED THE

ENGLISH SITE BUT YOU CAN USE TRANSLATOR

LINK: https://gscourses.thinkific.com/courses/fisicai

Answer:

1- t^3

2- t^2

3- t1

Explanation:

The acceleration produced in a body, while travelling in a circular motion, due to change in direction of motion is called centripetal acceleration. The formula of the centripetal acceleration is as follows:

ac = v²/r

where,

ac = centripetal acceleration

v = speed

r = radius

for a constant radius the centripetal acceleration will be directly proportional to the speed of object. The speed of pendulum will be lowest at t1 due to zero speed initially. Then the speed will increase gradually having greater speed at t^2 and the highest speed and centripetal acceleration at t^3. Therefore, the three instants in tie can be written in following order from greatest centripetal acceleration to lowest:

1- t^3

2- t^2

3- t1

A projectile is an object thrown into the air and subject only to gravity and, if applicable, air resistance. The time taken by disc C to reach its maximum height is approximately 1.53 seconds, and its maximum height above the ground is around 11.48 meters. The time from when disc C was thrown upwards until ball B hits the disc is roughly 1.29 seconds.

3.1 Explanation of the term projectile:

A projectile refers to an object that is launched or thrown into the air and is subject only to the forces of gravity and air resistance (if applicable). The motion of a projectile can be analyzed independently of its mass, shape, or any other physical property. The key characteristic of a projectile is that it follows a curved path known as a trajectory.

When a projectile is launched, it moves along a parabolic trajectory due to the combination of its initial velocity and the force of gravity acting vertically downward. The horizontal motion of a projectile remains constant and unaffected by gravity, while the vertical motion is influenced by the acceleration due to gravity.

The path of a projectile can be described mathematically by considering its initial velocity, angle of projection, and the acceleration due to gravity. Projectile motion finds applications in various fields, such as sports, engineering, and physics, where objects are launched or thrown.

3.2.1 Time taken by disc C to reach its maximum height:

To determine the time taken by disc C to reach its maximum height, we can use the kinematic equation for vertical motion. The equation is:

vf = vi + at

Where:

vf = final velocity (which is zero at the maximum height)

vi = initial velocity

a = acceleration (in this case, acceleration due to gravity, -9.8 m/s²)

t = time

Since the disc is thrown vertically upwards, its initial velocity is 15 m/s. We want to find the time it takes for the disc to reach its maximum height, so we'll use the equation and solve for time (t):

0 = 15 + (-9.8)t

Rearranging the equation, we get:

9.8t = 15

t = 15 / 9.8

Calculating this, we find:

t ≈ 1.53 seconds

Therefore, it takes approximately 1.53 seconds for disc C to reach its maximum height.

3.2.2 Maximum height above the ground reached by disc C:

To determine the maximum height reached by disc C, we can use another kinematic equation for vertical motion:

vf² = vi² + 2ad

Where:

vf = final velocity (which is zero at the maximum height)

vi = initial velocity

a = acceleration (in this case, acceleration due to gravity, -9.8 m/s²)

d = displacement (maximum height)

Since we know the initial velocity (vi) and acceleration (a), we can solve for the displacement (d), which represents the maximum height:

0² = 15² + 2(-9.8)d

Rearranging the equation, we get:

0 = 225 - 19.6d

19.6d = 225

d = 225 / 19.6

Calculating this, we find:

d ≈ 11.48 meters

Therefore, the disc C reaches a maximum height of approximately 11.48 meters above the ground.

Calculating the time from the moment that disc C was thrown upwards until the time ball B hits the disc:

To find the time it takes for ball B to hit disc C, we need to calculate the time it takes for both objects to reach the same height.

Since disc C was thrown upwards from the edge of the roof and ball B was shot vertically upwards from the foot of the building, we need to consider the additional height of the building (30 meters).

The time it takes for disc C to reach the ground is the same as the time it takes for ball B to reach a height of 30 meters above the ground.

Using the kinematic equation for vertical motion, we can calculate the time for ball B:

d = vit + 0.5at²

Where:

d = displacement (30 meters)

vi = initial velocity (40 m/s)

a = acceleration (acceleration due to gravity, -9.8 m/s²)

t = time

30 = 40t + 0.5(-9.8)t²

Rearranging the equation, we get:

4.9t² + 40t - 30 = 0

Solving this quadratic equation, we find:

t ≈ 1.29 seconds or t ≈ -5.82 seconds

Since time cannot be negative in this context, we discard the negative solution.

Therefore, it takes approximately 1.29 seconds from the moment that disc C was thrown upwards until ball B hits the disc.

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Answer:

Current flow I =  20 ampere

Explanation:

Given:

Resistance R = 11 ohms

Voltage V = 220 volts

Find:

Current flow I

Computation:

Current flow I = V / R

Current flow I = 220 / 11

Current flow I =  20 ampere

The amount of current flow through the element is of 20 A.

Given data:

The magnitude of resistance of Electric stove is, R = 11 ohms.

The magnitude of potential difference in a line is, V' = 220 V.

Here we can simple go for Ohm's law. As per the Ohm's law, the potential difference across the element is proportional to the current flow and the resistance of the element.

The expression is,

V' = I × R

here, I is the amount of current flowing through the element.

Solving as,

220 = I × 11

I = 20 A

Thus, we can conclude that the amount of current flow through the element is of 20 A.

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Answer:

Explanation:

You want the required centripetal force to equal gravity force

if m is the mass of the satellite

ma = mv²/R

a = v²/R

F = ma = GMm/R²

a = GM/R²

v²/R = GM/R²

v² = GM/R

v = √(GM/R)

v = √(6.674 x 10⁻¹¹(5.972 x 10²⁴)/6.771 x 10⁶)

v = 7.672 x 10³ m/s

The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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Using the formula for the Doppler effect:

f' = (v + vr) / (v + vs) * f

Given:

Source frequency (horn): f = 625 Hz

Speed of sound: v = 343 m/s (approximate value at room temperature)

The velocity of the receiver, vr, is zero because the person waiting at the crosswalk is stationary.

The velocity of the source, vs, is the speed of the car, which is given as 9.0 m/s.

Thus:

f' = (v + vr) / (v + vs) * f

= (343 m/s + 0) / (343 m/s + 9.0 m/s) * 625 Hz

= (343 m/s) / (352 m/s) * 625 Hz

≈ 609 Hz

Therefore, the person waiting at the crosswalk hears a frequency of approximately 609 Hz.

(2)Using the same Doppler effect formula:

f' = (v - vr) / (v - vs) * f

In this case, the velocity of the receiver, vr, is still zero because the person remains stationary.

The velocity of the source, vs, is now negative, indicating that the car is moving away from the person.

Thus:

f' = (v - vr) / (v - vs) * f

= (343 m/s + 0) / (343 m/s - (-9.0 m/s)) * 625 Hz

= (343 m/s) / (352 m/s) * 625 Hz

≈ 609 Hz

In other words, as the car moves away from the person, they would still hear a frequency of approximately 609 Hz.

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Answer:

See below

Explanation:

Average speed =  (0+ 10)/2 = 5 m/s

 then to cover 50 m     will take    50 m / 5 m/s  = 10 seconds

     change in velocity/ change in time = acceleration = 10/10 = 1 m/s^2

Answer:

From the initial height h

Explanation:

When a material or substance is drop from a height h, it possesses potential energy, immediately it is dropped from that height, the potential energy is gradually converted to kinetic energy, it gets to a point where the potential energy equals the kinetic energy, as the material touches the ground, all potential energy has been converted to kinetic energy already

Answer:

true

Explanation:

Answer:

The common velocity v after collision is 2.8m/s²

Explanation:

look at the attachment above ☝️

Ben as a psychology student is most likely conducting a behavioral study.

What is psychology?

Psychology can simply be defined as the study of human mind, conscious and unconscious, thoughts and feelings.

In conclusion, Ben as a psychology student is most likely conducting a behavioral study.

Some few branches of psychology are:

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Between Kinetic energy and speed: The relationship is quadratic or parabolic. According to the kinetic energy formula, KE = 1/2 mv^2, the kinetic energy is proportional to the square of the speed.

Between potential energy and mass: The relationship is linear. The potential energy is directly proportional to the mass. In simple cases, the potential energy is given by PE = mgh, where mass (m) and height (h) are directly proportional.

Between pressure and volume: The relationship is inverse. According to Boyle's law, the pressure and volume of a gas are inversely proportional when temperature is constant. Mathematically, P1V1 = P2V2.

Between pressure and temperature: The relationship is linear. According to Charles's law, the pressure and temperature of a gas are directly proportional when volume is constant. Mathematically, P1/T1 = P2/T2.

Between displacement and velocity: The relationship is linear. Velocity is the rate of change of displacement with respect to time, so the two are directly proportional.

Answer:

0.00033333333

Explanation:

Answer:

resultant force = 59 N

Explanation:

we know the formula: Force = mass * acceleration

                                    Force = 25 kg  *   2.36 m/s²

                                    Force = 59 N

The powder takes the shape of a magnetic field.

Powder morphology is connected to the shape and size of powder particles and is strongly dependent on the manufacturing methods. For example, mechanical alloying/mechanical milling leads to unevenly shaped powder particles, while gas dissipation leads to spherically shaped particles.

Atomized metal powder particles come in two basic particle shapes: those that are almost superbly round called spherical, and those that have lopsided, rounded shapes, called spheroidal.

So we can conclude that Powders are a group of particles of different sizes.

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The viscosity of the oil with a torque 4Nm and a rotational speed is 30 rpm is 0.2003 N.s/m.

From the given,

torque = 4Nm

rotational speed = 30 rpm = (30 × 3.14)/60 = 3.14 rad/sec

radius = 0.15 m

thickness (h) = 0.003 m

To find linear velocity,

V = R×ω

  = 0.15×3.14

V =0.471 m/s

The dragging force,

F = 2μA(V/h)   (V is linear velocity and h is the thickness )

Area = area of cylinder = 2πRH, R is radius and H is the height of the cylinder.

F = 2μ(2πRH) (V/h)

  = 2μ(2×3.14×0.15×0.45) (0.471/0.003)

  = 133.10 μ   (μ is the viscosity of the oil)

F = 133.1μ

Torque (τ) = Force × radius

      4 Nm   = 133.1μ × 0.15

  μ  = 4 / (133.1×0.15)

      = 0.2003 N.s/m

The viscosity of the oil is 0.2003 N.s/m.

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Answer:

2.74

Explanation:

As the crew is adding one mile to the road each day, so the length of the road after 27 days is 79 miles.

A collection of skilled workers, including a supervisor, a construction manager, a distinct maintenance staff, and a team of specialist labourers, make up an efficient construction crew. Employees must actively participate in the prevention of hazardous situations as they have a significant role to play.

A road construction crew assists with new road and sidewalk creation, repairs to or improvements to current roads, and the burying of wires underneath the local roads. They are also known as vehicle restraining operators and highway maintenance operators.

The question is incomplete, find the complete question here

A construction crew is lengthening a road that originally measured 52 miles. The crew is adding one mile to the road each day. The length, L (in miles), after d days of construction is given by the following function. L = 52 + d. what is the length of the road after 27 days?

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Answer:

198785.714286 Joules

Explanation:

\(W=f*d\)

\(F=ma\\F=516.326530612*-14\\F=-7228.57142857 N\\\)

To find work:

Now that the force and the distance are known, plug and chug:

\(W=f*d\\W=-7228.57142857*27.5\\W=-198785.714286J\)

Note that the question is asking for the magnitude of work, so the negative can be discarded as it is a directional component.

So, your answer is

198785.714286 Joules

Answer:

17.6 m/s², 26.2° above x axis

Explanation:

Apply Newton's second law.

Sum of forces in the x direction:

∑Fₓ = ma

40 N + 55.0 N cos 45° = (5.00 kg) aₓ

aₓ = 15.8 m/s²

Sum of forces in the y direction:

∑Fᵧ = ma

55.0 N sin 45° = (5.00 kg) aᵧ

aᵧ = 7.78 m/s²

Use Pythagorean theorem to find the magnitude of the resultant.

a² = aₓ² + aᵧ²

a² = (15.8 m/s²)² + (7.78 m/s²)²

a = 17.6 m/s²

Use trigonometry to find the angle.

tan θ = aᵧ / aₓ

tan θ = (7.78 m/s²) / (15.8 m/s²)

θ = 26.2°