The range of a function is the set of all possible values of the function. From the graph, we can see that the range of the function is [0,∞).
(a) Finding the domain of the function: The domain of the function is the set of all real numbers for which the function is defined.
In this case, the function is defined for all real numbers. Hence, the domain of the function is (-∞,∞).
(b) Locating the intercepts:
An intercept is a point at which the graph of a function intersects the coordinate axes. If x<0, then the y-intercept is f(0) = 4, but if x≥0, then the x-intercept is f(0) = 0. H
ence, the intercepts are (0,0) and (4,0).(c) Graphing the function:
The graph of the function f(x) is shown below. [asy] size(200);
import TrigMacros; yaxis(-1,10,Arrows(4)); xaxis(-10,10,Arrows(4)); real f(real x) {if (x < 0) {return 4+x;} else {return x^2;}} draw(reflect((0,0),(1,1))*(graph(f,-5,0,red))); draw(graph(f,0,3,red)); [/asy]
(d) Finding the range based on the graph: The range of a function is the set of all possible values of the function. From the graph, we can see that the range of the function is [0,∞).
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PLEASE For which sample size (n) and sample proportion (6) can a normal curve be
used to approximate the sampling distribution?
O A. n=29; p = 0.3
OB. n=34; p = 0.4
OC. n=29; p= 0.9
OD. n=34; p = 0.2
Option C: 0.4 for p and 32 for n Using a normal curve, one may approximate the sampling distribution using the sample size (n) and sample proportion (n is 6).
Discover the distribution of samples?If np > 10 or n(1 - p) > 10 is true, the normal curve can be applied in this situation.
For example, if n = 28 and p = 0.3;
np = 28 × 0.3 = 8.4 < 10
It is thus useless.
B) In case n = 28 and p = 0.9;
np = 28 × 0.9 = 25.2 > 10 Ok
Not acceptable: n(1 - p) = 28(1 - 0.9) = 2.8
Thus, it cannot be applied.
C) With n = 32 and p = 0.4
np = 32 × 0.4 = 12.8 > 10 Ok
n(1 - p) = 32(1 - 0.4) = 19.2 > 10 Ok
Thus, it can be utilized.
D) When n is 32 and p is 0.2
np = 32 × 0.2 = 6.4 < 10 Not Ok
So it is useless.
Option C: 0.4 for p and 32 for n Using a normal curve, one may approximate the sampling distribution using the sample size (n) and sample proportion (n is 6).
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Complete the table is it 99 and 68???
In the given cyclic quadrilateral the measure of angle B is 81° and the measure of angle C is 112°.
In the given cyclic quadrilateral ABCD, ∠A=68° and ∠D=99°.
Cyclic quadrilaterals are quadrilaterals that can be inscribed in a circle. All of the vertices of a cyclic quadrilateral lie on the circumference of the same circle. This implies that the four sides of a cyclic quadrilateral are all taken by elements of the circumference and can all be expressed in terms of the same radius.
Opposite angles of cyclic quadrilateral are adds to 180°.
Here, ∠A+∠C=180°
68°+∠C=180°
∠C=180°-68°
∠C=112°
∠B+∠D=180°
∠B+99°=180°
∠B=180°-99°
∠B=81°
Therefore, in the given cyclic quadrilateral the measure of angle B is 81° and the measure of angle C is 112°.
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Solving for x please help me
Answer:
A.) X = 4 (please mark brainliest)
Step-by-step explanation:
Alternate interior angles
21x + 6 must equal 90
21x + 6 = 90
21x = 84
x = 4
What is the measure of the unknown segment?
Answer:6
Step-by-step explanation:
Tell whether the angles are adjacent of vertical. Then find the value of x. 4x. 2x
Answer:
x= 15
Step-by-step explanation:
it is a 90 degree angle total as there is the red box over there. thus 4x +2x = 90
6x= 90
x= 90/6
= 15
Craig just purchased a new car. He financed $45,000 and must pay it back over 5 years with 11% interest.
A cylinder has a radius of 6 inches and height of 3 and 3/4 inches. A sphere has a radius of 6 inches. What is the difference between the volume, to the nearest tenth of a cubic inch of the cylinder and sphere
Answer:
Difference = 480.9 in³
Step-by-step explanation:
Given
Cylinder;
Height, h = 3¾ inches
Radius, r₁ = 6 inches
Sphere
Radius, r₂ = 6 inches
The volume of a cylinder is calculated as thus
Volume, V₁ = πr₁²h
The volume of a sphere is calculated as this
Volume, V₂ = 4/3 πr₂³
Calculating the volume of the cylinder
V₁ = πr₁²h becomes
V₁ = π * 6² * 3¾
V₁ = π * 36 * 3¾
V₁ = π * 36 * 15/4
V₁ = π * 540/4
V₁ = π * 135
V₁ = 135π in³
Calculating the volume of the sphere
V₂ = 4/3 πr₂³ becomes
V₂ = 4/3 * π * 6³
V₂ = 4/3 * π * 216
V₂ = 864/3 * π
V₂ = 288π in³
The difference between the volume is calculated as thus.
Difference = V₂ - V₁
Difference = 288π - 135π
Difference = 153π
Take π as 22/7
Difference = 153 * 22/7
Difference = 480.9 in³ (Approximated)
Combine like terms 3x-7x=
Answer:
-4x
Step-by-step explanation:
3-7=-4 just add a x
let an be a bounded sequence of complex numbers. show that for each c > 0, the series l~=l ann- z converges uniformly for rez ~ 1 c. here we choose the principal branch of n- z
Whave established that the series l~=l an - z converges uniformly for Re(z) ≤ c
What is uniformly?
The keyword "uniformly" refers to the concept of uniform convergence. In the context of the given question, it is stated that the series l~=l an - z converges uniformly for Re(z) ≤ c. Uniform convergence means that the convergence of the series is independent of the value of z within a certain range (Re(z) ≤ c in this case).
To show that the series l~=l an - z converges uniformly for Re(z) ≤ c, where an is a bounded sequence of complex numbers and we choose the principal branch of n - z, we need to demonstrate that for any ε > 0, there exists an N such that for all n > N and for all z with Re(z) ≤ c, the inequality |l~=l an - z| < ε holds.
Given that an is a bounded sequence, there exists an M > 0 such that |an| ≤ M for all n.
Let's consider the series l~=l an - z. We can write it as:
l~=l an - l z.
Now, since |an| ≤ M for all n, we have:
|an - z| ≤ |an| + |z| ≤ M + c.
By choosing N such that M + c < ε, we can ensure that for all n > N and for all z with Re(z) ≤ c, the inequality |an - z| < ε holds.
Now, using the triangle inequality, we have:
|l~=l an - z| ≤ |an - z|.
Since we have shown that |an - z| < ε for n > N and Re(z) ≤ c, it follows that |l~=l an - z| < ε for n > N and Re(z) ≤ c.
Therefore, we have established that the series l~=l an - z converges uniformly for Re(z) ≤ c.
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2
ге
To paint a house, a painting company charges a flat rate of
$500 for supplies, plus $50 for each hour of labor.
ducation
1
POD
BO
300
200
hourt of labor
What is the vertical intercept?
Answer: For 20 hours it would be $1,500 and for 50 hours it would be $3,000.
Step-by-step explanation:
The equation for this problem would be y=50x+500.
Y is the total charge and x is the amount of hours. Plug in 20 and 50, and then you have your answer.
At the city museum, child admission is $5.70 and adult admission is $9.10. On Tuesday, 139 tickets were sold for a total sales of $972.50. How many adult tickets were sold that day?
Answer:
Let c = number of child tickets
a = number of adult tickets
5.70c + 9.10a = 972.50
c + a = 139
5.70(139 - a) + 9.10a = 972.50
792.30 - 5.70a + 9.10a = 972.50
792.30 + 3.40a = 972.50
3.40a = 180.20
a = 53, c = 86
53 adult tickets and 86 child tickets were sold that day.
PLEASEEE HELP!!!!!!!!
Answer:
I think its b
Step-by-step explanation:
Thanks to the person above me
What’s the function?
Nathan's calculator displays the following: 5.987e-5
Enter the correct number in each box to rewrite the number.
Answer:
You should instead ask your teacher for help trust me that is what I do she helps me learn better than others.
in class, we proved that the number of ways of tiling a $1 \times n$ rectangle with $1 \times 1$ and $1 \times 2$ tiles is $f {n 1}.$ (a) use a tiling argument to give a combinatorial proof that \[f 1 f 2 f 3 \dots f n
Here is a straightforward recursion you may employ to calculate the value.
let's use rectangles with integer aspects to represent the quantity of tilings of a $2 instances n$ rectangle as $T(n)$. There are $22n-2$ techniques to accomplish this if no rectangles of height $2$ are hired, wherein case we lessen to two wonderful times of the $1 times n$ state of affairs. If no longer, we set a situation based at the top-proper rectangle's $2 height. With the preliminary conditions $T(0)=1$ and $T(1)=2$, this results in $$T(n)=22n-2+sum k=0n-1 T(okay)+sum 0leq k ell leq n-1T(ok)22(n-ell-1)$. The center term inside the recursion corresponds to the case where the rightmost rectangle of top $2$ is absolutely the rightmost rectangle inside the tiling.It should be noted that the formula $2n-1$ for the $1 times n$ case is incorrect if $n=0$.
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1- Choose the correct answer :-
3) Between each two successive integers, there is .......
a) a unique rational number
b) one integer only
c) an infinite number of rational numbers
d) an infinite number of integers
Answer:
The answer is B I think...
PLEASE GIVE ME BRAINLIEST!!!
What are the disadvantages and disadvantages of online learning?
Online learning is the practice of taking classes online as opposed to in a traditional classroom. if attending classes is difficult given your schedule.
What are the advantages of online learning?Less in cost: The nicest thing about this online education is how much less expensive it is than traditional education. Parents who attend lessons online are free to purchase uniforms or incur travel costs and can make further savings.Time-Saving: There is no commute required for online programs because students may learn and get a degree while lounging at home.Easy attendance: Students are able to report their attendance from the convenience of their homes. so that students may participate in all online classes without missing any.What are the Disadvantages of online learning?Lose Concentration: Without sufficient support from lecturers when taking classes online, students may find it easy to lose concentration. Additionally, students who attend virtual classrooms on smartphones or laptops may simply switch to playing games or watching movies for enjoyment.Health Issues: Since spending hours in front of a computer screen is hazardous, many parents are concerned about their children's health. Additionally, prolonged screen use can harm someone's eyesight.Expensive: We are aware that this disadvantage has left you perplexed. Although it costs less, as we've already mentioned, it might still be pricey for students who are struggling financially. Smartphones and laptops are not an option for parents who are out of work owing to COVID.Learn more about online learning refer to ;
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Estimate ΔyΔy using differentials.
y=cos(5x),=/30,x=0.055
(Give your answer to three decimal places.)
The estimated change in yy using differentials is -0.00679. This means that if xx is increased by 0.005, then yy is estimated to decrease by 0.00679. The differential of yy is dy=-5sin(5x)dxdy=−5sin(5x)dx. We are given that y=cos(5x)=π/30y=cos(5x)=π/30 and x=0.055x=0.055.
We want to estimate ΔyΔy, which is the change in yy when xx is increased by 0.005. We can use the differential to estimate ΔyΔy as follows:
Δy≈dy≈dy=-5sin(5x)dx
Plugging in the values of y, x, and dxdx, we get:
Δy≈-5sin(5(0.055))(0.005)≈-0.00679
Therefore, the estimated change in yy using differentials is -0.00679.
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An automatic machine in a manufacturing process is operating groperly if the iengths of an important subcomponent are normally distributed with a mean of izal cri and a otandard deviation of 5.6 cm. A. Find the probability that one selected subcomponent is longer than 122 cm, Probability = B3. Find the probability that if 3 subcomponents are randomly selected, their mean length exceeds 122 cm. Probability win C. Find the probabilify that if 3 are randomly selected, ail 3 have lengths that exceed 122 cm. Probability =
A. The probability that one selected subcomponent is longer than 122 cm can be found by calculating the area under the normal distribution curve to the right of 122 cm. We can use the z-score formula to standardize the value and then look up the corresponding probability in the standard normal distribution table.
z = (122 - μ) / σ = (122 - 100) / 5.6 = 3.93 (approx.)
Looking up the corresponding probability for a z-score of 3.93 in the standard normal distribution table, we find that it is approximately 0.9999. Therefore, the probability that one selected subcomponent is longer than 122 cm is approximately 0.9999 or 99.99%.
B. To find the probability that the mean length of three randomly selected subcomponents exceeds 122 cm, we need to consider the distribution of the sample mean. Since the sample size is 3 and the subcomponent lengths are normally distributed, the distribution of the sample mean will also be normal.
The mean of the sample mean will still be the same as the population mean, which is 100 cm. However, the standard deviation of the sample mean (also known as the standard error) will be the population standard deviation divided by the square root of the sample size.
Standard error = σ / √n = 5.6 / √3 ≈ 3.24 cm
Now we can calculate the z-score for a mean length of 122 cm:
z = (122 - μ) / standard error = (122 - 100) / 3.24 ≈ 6.79 (approx.)
Again, looking up the corresponding probability for a z-score of 6.79 in the standard normal distribution table, we find that it is extremely close to 1. Therefore, the probability that the mean length of three randomly selected subcomponents exceeds 122 cm is very close to 1 or 100%.
C. If we want to find the probability that all three randomly selected subcomponents have lengths exceeding 122 cm, we can use the probability from Part A and raise it to the power of the sample size since we need all three subcomponents to satisfy the condition.
Probability = (0.9999)^3 ≈ 0.9997
Therefore, the probability that if three subcomponents are randomly selected, all three of them have lengths that exceed 122 cm is approximately 0.9997 or 99.97%.
Based on the given information about the normal distribution of subcomponent lengths, we calculated the probabilities for different scenarios. We found that the probability of selecting a subcomponent longer than 122 cm is very high at 99.99%. Similarly, the probability of the mean length of three subcomponents exceeding 122 cm is also very high at 100%. Finally, the probability that all three randomly selected subcomponents have lengths exceeding 122 cm is approximately 99.97%. These probabilities provide insights into the performance of the automatic machine in terms of producing longer subcomponents.
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8.88 = 4.44(x-7)
Solve for x
Show or explain your method
Answer:
x=9
Step-by-step explanation:
8.88=4.44x-31.088.88-4.44x=-31.08-4.44x=-31.08-8.88-4.44x=-39.96x=9(we divided both rquations by -4.44)What two factors add to -9 and multiply to 18
Answer:
3 × 6 = 18 3 + 6 = 9
Step-by-step explanation:
3 × 6 = 18 3 + 6 = 9
the product of three consecutive positive integers is $8$ times their sum. what is the sum of their squares?
the sum of squares of number of 6,7 and 8 is 149.
What is the arithmetic operation?
The four fundamental operations of arithmetic are addition, subtraction, multiplication, and division of two or more quantities. Included in them is the study of numbers, especially the order of operations, which is important for all other areas of mathematics, including algebra, data management, and geometry. The rules of arithmetic operations are required in order to answer the problem.
the product of three consecutive positive integers is 8 times thier sum.
So if 1st number is x
So the sum will be x+x+1+x+2 = 3x+3
and multiply will be x(x+1)(x+2)
according to question x(x+1)(x+2) = 24(x+1)
x³+3x²+2x = 24x+24
x = 6
So all the numbers will be 6,7 and 8
Hence the sum of their square is 36+49+64= 149
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Which situations would be represented with a positive number? Check all that apply.
The temperature outside is 34°F.
The Dead Sea is 1,349 feet below sea level.
Nicole lost 2 pounds last month.
Sebastian owes his friend $4
A football team gains 11 yards on a play.
Long Island Sound is at sea level.
Answer:
A and e
Step-by-step explanation:
Solve the following system of equations using Gaussian elimination, 5d + 20e - 10% = -85, -20 - + 394 = 223, and 4d + 13e - 19 = -125 State the solution as an ordered triple Provide your answer below.
The given system of equations is:
5d + 20e - 10% = -85 …………………..(1)
-20d + 394e = 223 ………………...(2)
4d + 13e = -106 …………………….(3)
We can solve this system of equations using the Gaussian elimination method. In this method, we convert the system of equations into an equivalent system of equations that is easy to solve by eliminating one variable at a time.The elimination process starts by multiplying the equations so that one variable cancels out. We can do this by multiplying both sides of an equation with a constant or by adding or subtracting two equations.
Here, the first equation has a percentage sign which we need to remove.
We can do this by dividing both sides of equation (1) by
10.5d/10 + 20e/10 - 1 = -85/10
⇒ 0.5d + 2e - 1 = -8.5
⇒ 0.5d + 2e = -7.5 ……………………..(4)
Now, we can use equations (2) and (4) to eliminate d.
Multiplying equation (2) by 2 and adding it to equation (4), we get,
2(-20d + 394e = 223) + (0.5d + 2e = -7.5)
⇒ -40d + 788e + 0.5d + 2e = -7.5 + 446
⇒ -39.5d + 790e = 438 ……………………...(5)
Multiplying equation (2) by 5 and adding it to equation (3), we get,
5(-20d + 394e = 223) + (4d + 13e = -106)
⇒ -100d + 1970e + 4d + 13e = -106 + 1105
⇒ -96d + 1983e = 999 ……………………(6)
Now, we can use equations (5) and (6) to eliminate d.
Multiplying equation (5) by 2 and adding it to equation (6), we get,
2(-39.5d + 790e = 438) + (-96d + 1983e = 999)
⇒ -79d + 1563e + (-96d + 1983e) = 876 + 1998
⇒ -175d + 3546e = 2874 …………………..(7)
We can simplify equation (7) by dividing both sides by 7,-25d + 506e = 410 ……………………..(8)
Now, we can use equations (4) and (8) to solve for e.
Multiplying equation (4) by 506/4 and adding it to equation (8), we get,
506/4 × (0.5d + 2e = -7.5) + (-25d + 506e = 410)
⇒ 253d + 506e - 1895 - 25d + 506e = 410
⇒ 228d + 1012e = 2305 ……………………(9)
We can simplify equation (9) by dividing both sides by
4,57d + 253e = 576 ……………………(10)
Now, we can use equations (4) and (10) to solve for d.
Multiplying equation (4) by 57/2 and adding it to equation (10), we get,
57/2 × (0.5d + 2e = -7.5) + (57d + 253e = 576)
⇒ 28.5d + 114e - 214.125 + 57d + 253e = 576
⇒ 85.5d + 367e = 790.125 …………………….(11)
We can simplify equation (11) by dividing both sides by 17,5d + 23e = 46.4166667 …………………….(12)
Now, we can use equations (4) and (12) to solve for e.
Multiplying equation (4) by 23/2 and adding it to equation (12), we get,
23/2 × (0.5d + 2e = -7.5) + (5d + 23e = 46.4166667)
⇒ 11.5d + 46e - 86.625 + 5d + 23e = 46.4166667
⇒ 16.5d + 69e = 133.0416667 ……………………..(13)
We can simplify equation (13) by dividing both sides by 3,5.5d + 23e = 44.3472222 ……………………..(14)
Now, we can use equations (4) and (14) to solve for e.
Multiplying equation (4) by 23 and subtracting it from equation (14), we get,
23 × (0.5d + 2e = -7.5) - (5.5d + 23e = 44.3472222)
⇒ 11.5d - 48.5e = -212.0972222 ……………………..(15)
We can simplify equation (15) by dividing both sides by 1.5,7.6666667d - 32.3333333e = -141.3981481 ……………………..(16)
Now, we can use equations (4) and (16) to solve for e.
Multiplying equation (4) by 32 and adding it to equation (16), we get,
32 × (0.5d + 2e = -7.5) + (7.6666667d - 32.3333333e = -141.3981481)
⇒ 16d + 64e - 240 + 7.6666667d - 32.3333333e = -141.3981481
⇒ 23.6666667d + 31.6666667e = 98.60185185 …………………..(17)
We can simplify equation (17) by dividing both sides by 1.6666667,
14.2d + 19e = 59.1611111 ……………………..(18)
Now, we can use equations (4) and (18) to solve for e.
Multiplying equation (4) by 19 and subtracting it from equation (18), we get,
19 × (0.5d + 2e = -7.5) - (14.2d + 19e = 59.1611111)
⇒ 9.5d - 41e = -186.3111111 ……………………..(19)
We can simplify equation (19) by dividing both sides by 1.9,
5d - 21.57894737e = -98.05789474 ……………………..(20)
Now, we can use equations (4) and (20) to solve for e.
Multiplying equation (4) by 21.57894737 and adding it to equation (20), we get,
21.57894737 × (0.5d + 2e = -7.5) + (5d - 21.57894737e = -98.05789474)
⇒ 43.15789474d + 0e = -252.5263158
⇒ 43.15789474d = -252.5263158
⇒ d = -5.85416667
Substituting the value of d in equation (4), we get,
0.5d + 2e = -7.5
⇒ 0.5(-5.85416667) + 2e = -7.5
⇒ e = -6.5
Now, we have the values of d and e, and we can substitute them in any equation to get the value of the remaining variable.
We can use equation (2),
-20d + 394e = 223
⇒ -20(-5.85416667) + 394(-6.5) = 223
⇒ 117.0833334 + (-2561) = 223
⇒ -2443.916667 = 223
This is not true, which means there is no solution to this system of equations. Hence, the system is inconsistent.
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Robbie made a scale drawing of a neighborhood park. A Soccer field in the park is 14 inches long
in the drawing. The actual field is 98 yards long. What is the scale of the drawing? 1 inch = _ yards
Answer:
14 it is not 14
Step-by-step explanation:
Answer:
ITS NOT 14
Step-by-step explanation:
I got it wrong anything besides that
use the equation q = f(x) − f(a) x − a to find the slope of the secant line between the values x1 and x2 for the function y = f(x). f(x) = 2x 2; x1 = 4, x2 = 7
Therefore, the slope of the secant line between x1 = 4 and \(x^2 = 7\) for the function \(f(x) = 2x^2\) is 22.
We have the function \(f(x) = 2x^2\) and the values x1 = 4 and x2 = 7.
We can use the formula for the slope of the secant line between x1 and x2:
slope \(= \frac{(f(x_2) - f(x_1))}{(x_2 - x_1)}\)
First, we need to find f(x1) and f(x2):
\(f(x1) = 2x_1^2 = 2(4)^2 = 32\\f(x2) = 2x_2^2 = 2(7)^2 = 98\)
Substituting these values into the formula, we get:
\(slope = \frac{(98 - 32) }{(7 - 4)} = \frac{66}{3} = 22\)
The slope of a secant line is a measure of how steeply a curve is rising or falling between two points.
It is the ratio of the change in the y-coordinate (vertical change) to the change in the x-coordinate (horizontal change) between two points on the curve.
Given two points (x1, y1) and (x2, y2) on a curve, the slope of the secant line between them is given by the formula:
\(slope = \frac{(y_2 - y_1)}{(x_2 - x_1)}\)
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find the length asap
Answer:
\(\boxed{BC = 11.62}\)
Step-by-step explanation:
Tan 54 = \(\frac{opposite}{adjacent}\)
Where opposite = 16, Adjacent = BC
1.376 = \(\frac{16}{BC}\)
BC = 16/1.376
BC = 11.62
Answer:
11.62468045 or 11.6 to 1 decimal place
Step-by-step explanation:
→ We need to utilise trigonometry. The first step would be to list out the formula triangles
Tan = Opposite ÷ Adjacent
Sin = Opposite ÷ Hypotenuse
Cos = Adjacent ÷ Hypotenuse
→ Now we need to know which triangle to use, we do that by identifying the side or length we are not given in the triangle and then finding a formula without the name of the given side. First let's identify all the sides.
Opposite = AC = 16
Adjacent = BC = We need to find this out
Hypotenuse = AB = No given value
→ Now we look for a formula with hypotenuse
Tan = Opposite ÷ Adjacent
→ The (Tan = Opposite ÷ Adjacent) is the formula we are going to be using. Since we want to find out the adjacent, we have to rearrange to get adjacent as the subject
Adjacent = Opposite ÷ Tan
→ Now we identify the Opposite and the Tan
Opposite = 16
Tan = 54°
Side note ⇒ Sin, cos and tan will always be the angles
→ Substitute in the values in the formula
Adjacent = Opposite ÷ Tan ⇔ Adjacent = 16 ÷ Tan (54) ⇔ Adjacent = 11.6
→ The adjacent is 11.6 to 1 decimal place
HELP ASAP WILL MAKE BRAINLEST
Answer: the last one
Step-by-step explanation:
um so the set begins with 40 and ends with 100 (look at that on the number line)
and so the median is essentially that middle line in the box, which is around 80
i assume yk how to calculate medians so I calculated the median of the first and the last answer
the first one was like 70, and the last one was like 78.9 which is close enough to 80
so i think its the last one
Answer:
It is answer number four.
Step-by-step explanation:
40 and 100 represent the outliers so both numbers must be included.
80 must also be included as it is the mean or average test grade.
x + 3y = 42
2x - y= 14
Answer:
x=12,y=10
Step-by-step explanation:
Step: Solve x+3y=42
x+3y=42
x+3y+−3y=42+−3y(Add -3y to both sides)
x=−3y+42
Step: Substitute−3y+42forxin2x−y=14:
2x−y=14
2(−3y+42)−y=14
−7y+84=14(Simplify both sides of the equation)
−7y+84+−84=14+−84(Add -84 to both sides)
−7y=−70
Divide both sides by -7
y=10
Step: Substitute10foryinx=−3y+42:
x=−3y+42
x=(−3)(10)+42
x=12(Simplify both sides of the equation)
Hope this Helps:)
-Ac<3-
Suppose l || m. What is the measure of each angle of m angle 2 = 138?
1. m angle 1 = ______
2. m angle 3 = ______
3. m angle 4 = ______
If m angle 1 = 3x-3 and m angle 5 = 7x+23, for what value of x is l || m. ______
The transversal that intersects two parallel lines forms corresponding angles with measures m angle 1 = 3x-7 and. What is the measures of each angle? ______ m angle 2 = 2x+12
Pleaseeeeee Help!
Answer:
1) m<1=42°
2) m<3=42°
3 m<4=138°
Step-by-step explanation:
1) m<1=180-138=42
2) m<3=180-138=42
3 m<4=138 (Alternate Interior Angle Theorem)