The function f(x)is shown in the graph.

What is the equation for f(x)?

The standard form equation of the given ellipse with vertices (-6, -13) and (-6, 7) and foci (-6, -4) and (-6, -2) is (x+6)²/144 + (y+4)²/45 = 1. The center of the ellipse is (-6, -4), the semi-major axis 'a' is 12, and the value of 'c' is 2.

To find the standard form equation of an ellipse, we need to determine the center, semi-major axis, and the value of 'c' (which represents the distance between the center and the foci). Given that the vertices (-6, -13) and (-6, 7) lie on the major axis and the foci (-6, -4) and (-6, -2) lie on the minor axis, we can determine that the center of the ellipse is (-6, -4).

The distance between the center and the vertices is the semi-major axis 'a', which is equal to 12. To find the value of 'c', we can use the equation c² = a² - b², where b is the semi-minor axis. By substituting the values, we can calculate that c is equal to 2. Thus, the standard form equation of the ellipse is (x+6)²/144 + (y+4)²/45 = 1.

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The probability that none of the three students volunteer at the hospital is 1/4. This means there is a 25% chance that none of the selected students will be volunteering at the hospital.

To find the probability, we first need to determine the total number of ways to select three students from the club, which is the combination of selecting three students from a total of four students. Using the formula for combinations, this is denoted as C(4, 3) and equals 4.

Next, we calculate the number of ways to select three students without any of them volunteering at the hospital. Since we want to exclude the students who volunteer at the hospital, we have only three remaining students to choose from. Hence, the number of ways to select three students without any of them volunteering at the hospital is C(3, 3) which equals 1.

Therefore, the probability that none of the three students volunteer at the hospital is 1 out of 4, or 1/4.

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Answer:

\({ \bf{consider \: points \: (5, \: 0) \: and \: (0, \: - 5)}} \\ { \tt{slope = \frac{ - 5 - 0}{0 - 5} }} \\ { \tt{m = 1}} \\ \\ { \tt{y = mx + c}} \\ 0 = ( 1 \times 5) + c \\ c = -5 \\ \\ { \bf{answer : { \tt{y = { \boxed{ 1}x + { \boxed{-5}}}}}}}\)

Answer:

\(y = [ 1 ] x + [ - 5 ]\)

Step-by-step explanation:

Let us consider 2 points through which the line passes.

\((x_1 , y _ 1 ) = ( 5 , 0 ) \ and \ (x _ 2 , y _ 2 ) = ( 0 , - 5 )\)

Step 1 : Find slope, m

       \(slope, m = \frac{y _ 2 - y_ 1 }{x_ 2 - x_ 1 } = \frac{-5 - 0}{0-5} = \frac{-5}{-5} = 1\)

Step 2 : Equation of line

         \((y - y_ 1) = m( x - x_1)\\\\( y - 0) = 1 ( x - 5)\\\\y = x - 5 \\\\y = x + ( -5)\)

        \(y = (1) x + ( -5)\)

The correct answer of the operation is option B: 4x^2 - 9.

To perform the operation (2x-3)(2x+3), we can use the FOIL method, which stands for First, Outer, Inner, Last. Let's go through the steps:

First: Multiply the first terms of each binomial.

(2x)(2x) = 4x^2

Outer: Multiply the outer terms of each binomial.

(2x)(3) = 6x

Inner: Multiply the inner terms of each binomial.

(-3)(2x) = -6x

Last: Multiply the last terms of each binomial.

(-3)(3) = -9

A binomial is a two-term algebraic expression that contains variable, coefficient, exponents and constant, a binomial is an expression that has two unlike terms connected through an addition or subtraction operator in between.  

Now, let's combine the like terms:

4x^2 + 6x - 6x - 9

Notice that the terms 6x and -6x cancel each other out.

Simplifying further, we have:

4x^2 - 9

The correct answer is option B: 4x^2 - 9.

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For dimensions of x =10 and y=5 for the base and height that will make the tank weight as little as possible.

Here we are given the information of a square-based, open-top, rectangular steel holding tank, so here the tank is in the shape of a cuboid and we know  the formula  for :

volume = x*y*z, as  here it is a square base, so the volume will be

volume =  x²*y, where x and y are the dimension of the base and height

So for the  given reason,  

=>x²*y =  500

=> y = 500/x²

Again, the surface area formula  will be

S=x²+4xy, substituting the value of  y in this question

=>S=x²+4x(500/x²)

=>S=x²+2000/x

Differentiating the above formula with respect to x, we get

=>2x-2000/x²=0

=>2x³= 2000

=>x³= 1000

=>x =10

so the substituting the x values of x in  the equation y , we get

y = 500/x²

=>y = 5

so the dimensions are x= 10 and y=5

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Answer:

$36.9735831

rounded: $36.97

Answer:

Find the area of both the square and circle and subtract the circle’s area from the square’s

Step-by-step explanation:

Answer:

yes

Step-by-step explanation:

The volume of cylindrical tin is 1584 \(cm^3\). The depth of the oil in the tin is 9cm.

\(V_1 =\) VOLUME OF CYLINDRICAL TIN

   \(= \pi r^2 h\)

  \(=\frac{22}{7}\) x 6 x 6 x 14

  = 44 x 36

  = 1584 \(cm^3\)

\(V_2 =\) VOLUME OF RECTANGULAR TIN

    = lbh = 1584

    = (16)(11)(h) = 1584

    = 176h =1584

    = h = 1584 / 176

    = h = 9 cm

A cylinder is a three-dimensional shape that consists of a circular base and a curved surface that extends upward to meet at a point known as the apex. The volume of a cylinder is the amount of space occupied by the shape and is given by the formula V = πr²h, Once we have calculated the area of the circular base, we can multiply it by the height of the cylinder to get the volume.

To calculate the volume of a cylinder, we need to know its dimensions, which are the radius and height. The radius is the distance from the center of the circular base to the edge, while the height is the distance between the two circular bases.

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Answer:

(-1, 0)

Step-by-step explanation:

bc big brain

Answer:

(-1, 0)

Step-by-step explanation:

-4 + 4 = 0

1 - 2 = -1

16250 many different three-letter words—including nonsense words—have different letters in the next position.

Given that,

We have to find how many different three-letter words—including nonsense words—have different letters in the next position.

We know that,

The number of alphabets are 26

First letter has 26 choices.

Second letter can not be same has first letter so 25 choices.

Third letter can not be same has second letter so 25 choices.

So,

Total words = 26×25×25=16250

Therefore, 16250 many different three-letter words—including nonsense words—have different letters in the next position.

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The simplified expression without absolute value signs is x - 2.

To simplify the expression |x - 2| when x > 2, we can use the fact that if x is greater than 2, then x - 2 will be positive. In this case, |x - 2| simplifies to just x - 2.

This simplification is based on the understanding that the absolute value function, denoted by | |, returns the positive value of a number. When x > 2, x - 2 will be positive, and the absolute value function is not needed to determine its value. In this case, the expression simplifies to x - 2.

However, it's important to note that when x ≤ 2, the expression |x - 2| would simplify differently. When x is less than or equal to 2, x - 2 would be negative or zero, and |x - 2| would simplify to -(x - 2) or 2 - x, respectively.

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Answer:

I go for I and IV....................

Answer:

11/2 x 7/4 = 77/8 = 9 5/8

Step-by-step explanation:

Answer:

Keith bought 14 gallons of paint, and each classroom requires 7/4 gallons of paint.

To find how many classrooms can be painted, we can divide the total amount of paint by the amount of paint needed per classroom:

14 ÷ (7/4) = 8

Therefore, Keith can paint 8 classrooms in total.

The points (4, -8) and (10,g) fall on a line with a slope of -1/6. Therefore the value of g is -9.

To find the price of g, we need to apply the concept of the slope of a line. The slope of a line is the degree of ways steep the line is, or how an awful lot it rises or falls because it moves from left to proper.

The slope may be calculated by the use of the system:

m= (y2-y1)/(x2-x1)

where m is the slope and (x1​,y1​) and (x2​,y2​) are any two factors on the road. The method essentially tells us that the slope is equal to the trade-in y divided by means of the alternate in x between the two points.

In this question, we are given two points on the line: (4,−8) and (10,g). We also are given the slope of the line: −1/6. We can plug these values into the formulation and get:

−1/6 = g-(-8) / 10-4

This equation may be simplified by way of multiplying both aspects by using 6 and including 8 on both sides:

−1=g+8

g=−9

So the price of g is −9. This way that the point (10,g) is actually (10,−9). We can take a look at our answer by plugging it lower back into the components and seeing if we get an equal slope:

−1/6=10−4−9−(−8)​

−1/6=6−1​

This is true, so our solution is accurate. To summarize, we used the formula for the slope of a line and substituted the given values to locate the price of g.

The cost of g is −nine, which makes the factor (10,g) equal to (10,−nine). This point lies at the equal line as (4,−8) with a slope of −1/6.

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The correct question is;

"The points (4, -8) and (10,g) fall on a line with a slope of -1/6. What is the value of g?"

Answer:

5.5... five minutes and thirty seconds

Step-by-step explanation:

The sampling technique that is most likely to produce results with less variation than those shown in the line plot is option (D). Take 20 samples of 40 Silver Middle School students each. This is because larger sample sizes tend to produce more accurate results and reduce the likelihood of random variation.

When a larger sample size is used, the variability of the results is reduced because it allows for a more representative sample of the population. This means that the results obtained are more likely to be a true reflection of the population and are less likely to be affected by chance factors.

By taking 20 samples of 40 students each, the sample size is increased, allowing for a more representative sample of the Silver Middle School population. This reduces the chance of any random factors affecting the results, resulting in less variation than the line plot shown.

Therefore, D is the most suitable option to produce results with less variation.

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the critical load of the round wooden dowel is determined by using the Euler buckling formula, which is given by:

P_cr = (π^2 * E * I) / L^2

Where P_cr is the critical load, E is the modulus of elasticity (given as 12 GPa), I is the area moment of inertia (for a round wooden dowel it is π*d^4/64), and L is the length of the dowel (given as 0.75 m). Substituting these values, we get:

P_cr = (π^2 * 12e9 * π*(10/1000)^4/64) / (0.75^2)

P_cr = 91.34 N

Therefore, the critical load of the round wooden dowel is 91.34 N.

In explanation, the Euler buckling formula is used to determine the critical load of slender columns or rods that are subjected to compressive forces. The formula takes into account the modulus of elasticity of the material, the length of the column, and the area moment of inertia of the cross-section. The critical load is the maximum load that the column can withstand without buckling or collapsing under compressive forces.

the critical load of the round wooden dowel with a diameter of 10 mm and a length of 0.75 m is 91.34 N, which is the maximum load that the dowel can withstand without buckling or collapsing under compressive forces.

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Answer:

c

Step-by-step explanation:

The inventory management model that should be used to solve this problem is the Model Economic Quantity to Order (EOQ) model. The optimal number of notebooks to make in each order is 590 units. The annual ordering cost (AOC) is approximately $892.20. The Annual Holding Cost (AHC) is $3540. The annual product cost (APC) is $233,460. The annual total cost of managing inventory (ATC) is approximately $237,892.20. The total number of orders in the year (N) is 33. The estimated time between each order (T) is approximately 7.58 days. The daily demand is approximately 77.82 units. The reorder point (ROP) is approximately 311 units.

The inventory management model that should be used to solve this problem is the Model Economic Quantity to Order (EOQ) model.

To find the optimal number of notebooks to make in each order, we can use the EOQ formula:

EOQ = √[(2 * Demand * Ordering Cost) / Holding Cost]

EOQ = √[(2 * 19455 * 27) / 6]

EOQ ≈ 589.96

Since the number of notebooks must be a whole number, the optimal number to order would be 590 notebooks.

The annual ordering cost (AOC) can be calculated by dividing the annual demand by the EOQ and multiplying it by the ordering cost:

AOC = (Demand / EOQ) * Ordering Cost

AOC = (19455 / 590) * 27

AOC ≈ $892.20

The Annual Holding Cost (AHC) is calculated by multiplying the EOQ by the holding cost per unit:

AHC = EOQ * Holding Cost

AHC = 590 * 6

AHC = $3540

The annual product cost (APC) is calculated by multiplying the annual demand by the cost per unit:

APC = Demand * Cost per unit

APC = 19455 * 12

APC = $233,460

The annual total cost of managing inventory (ATC) is the sum of the annual ordering cost, annual holding cost, and annual product cost:

ATC = AOC + AHC + APC

ATC = 892.20 + 3540 + 233460

ATC ≈ $237,892.20

The total number of orders in the year (N) can be calculated by dividing the annual demand by the EOQ:

N = Demand / EOQ

N = 19455 / 590

N ≈ 33

The estimated time between each order (T) can be calculated by dividing the number of working days in a year by the total number of orders:

T = Number of working days / N

T = 250 / 33

T ≈ 7.58 days

The daily demand is calculated by dividing the annual demand by the number of working days in a year:

Daily Demand = Demand / Number of working days

Daily Demand = 19455 / 250

Daily Demand ≈ 77.82 units/day

The reorder point (ROP) is the number of units at which a new order should be placed. It can be calculated by multiplying the daily demand by the lead time (time taken for the supplier to deliver the order):

ROP = Daily Demand * Lead Time

ROP = 77.82 * 4

ROP ≈ 311.28 units

Therefore, the reorder point would be approximately 311 units.

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Answer:

2.75x+4

Step-by-step explanation:

2.75x because for every one bucket it cost 2.75 dollars and I wouldn’t put x next to 4 since you only have to pay one time.

Answer:

Step-by-step explanation:

According to a 2013 survey conducted by the National Association of Colleges and Employers (NACE), approximately 63.2% of graduating college seniors from the class of 2013 reported participating in an internship, co-op, or both during their academic journey.

This statistic highlights the significance of experiential learning opportunities in preparing students for the workforce and developing relevant skills. Internships and co-ops provide valuable hands-on experience for college students, enabling them to apply the knowledge gained in their coursework to real-world situations. These experiences often help students to better understand their chosen fields, develop professional connections, and increase their chances of securing a job upon graduation.

Internships typically consist of short-term work assignments, often during the summer or academic breaks, allowing students to gain practical experience without interrupting their studies. Co-ops, on the other hand, are more structured programs that typically involve alternating periods of full-time work and full-time study, providing more in-depth exposure to a specific industry.

Both internship and co-op experiences can be invaluable for college seniors, as they not only build valuable skills and connections but also help students make informed decisions about their future careers. The high percentage of graduating seniors participating in these programs, as reported by NACE, underscores the importance of such opportunities in today's competitive job market.

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Answer:

1

Step-by-step explanation:

A rational number between 3.623623 and 0.484848 is 1.

Answer:

Remember: rational numbers are numbers that can be written as fractions and decimals that either terminate or repeat. Here are some rational numbers:

0.5, 3/4, 1, 1.5...3, 3.5

Step-by-step explanation:

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There is a 21.19% chance that the daily production falls within 32.3 and 36.9 liters.

To find the probability that the daily production of a herd of cows is between 32.3 and 36.9 liters, we need to use the normal distribution properties.

Given that the mean daily production of the herd of cows is 30 liters and the standard deviation is 8.2 liters, we can standardize the distribution and use the standard normal distribution table or calculator. We calculate the z-scores for the values 32.3 and 36.9, which tells us how many standard deviations away from the mean each value is.

Using a standard normal cumulative distribution function, we can find that the probability of the daily production falling between 32.3 and 36.9 liters is approximately 0.2119. This means that there is a 21.19% chance that the daily production falls within this range.

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The probability that daily production is between 32.3 and 36.9 liters is 0.18949 or 18.9%.

To determine the probability that the herd's daily production will be between 32.3 and 36.9 liters, we must compute the z-scores for each number and use a standard normal distribution table to calculate the area under the curve between those z-scores.

To find out the z - scores we need use z-score formula:

Z = X−μ / σ

where μ  is the mean, σ is the standard deviation and X is the observed value. In the problem μ  is 30 liters, X₁ = 32.3 liters & X₂ = 36.9 liters and σ = 8.2 liters.

Substituting the values in the equation to find the z-score for 32.3 liters is:

z₁ = (32.3 - 30) / 8.2 = 0.2804

z₁ = 0.28049

Substituting the values in the equation to find the z-score for 36.9 liters is:

z₂ =( 36.9 - 30) / 8.2 =  0.8414

z₂ = 0.8414

We can determine the area under the curve between these two z-scores using a conventional normal distribution table. The area between z = 0.28049 and z = 0.8414 and the probability is approximately 0.1894.

As a result, the probability that the herd's daily output is between 32.3 and 36.9 liters is about 0.1894.

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The cost of cementing the walls of the cuboidal well is Rs 3640.

A three-dimensional solid form with six rectangular sides is called a cuboid. It also goes by the name rectangular prism. The shapes and sizes of the faces on either side of each other are identical.

A cuboid's surface area is the sum of all of its faces. We can determine the area of each face and put them together to determine the cuboid's surface area.

Given that, the cost of cementing the walls of the well at the rate Rs 52 per square m.

Thus,

Area of one rectangular face = length x height = 2 x 10 = 20m².

Area of the other rectangular face = width x height = 1.5 x 10 = 15m².

Total surface area of the walls = 2(20) + 2(15) = 70m².

Now, the cost of cementing the walls of the well at the rate of Rs 52 per m² is:

Cost = 70m x Rs 52 = Rs 3640

Hence, the cost of cementing the walls of the well is Rs 3640.

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Answer:

The y-intercept is +2

using y=mx+b we can tell anything added is the intercept.

+2

Step-by-step explanation:

We know the standard equation is

y = mx + c

where m is the slope and c is the y-intercept.

By Comparing the given equation with the standard equation we get,

y-intercept = +2

Answer:

slope-intercept formula ----->  Y2-Y1/X2-X1

Step-by-step explanation:

X1 = 2       X2= 0

Y1 = 2        Y2=6

6-2/0-2= -2

G= -2

Answer: d. $264 hope this helps :)

Step-by-step explanation:12x22=264

The absolute maximum of the function on the given interval is at x = 7, and the value is f(7) = 4^(3/4).

To determine the location and value of the absolute extreme values of the function f(x) = (x-3)^3/4 on the interval [-7, 7], follow these steps:

1. Find the critical points by taking the derivative of the function and setting it to zero.
2. Evaluate the function at the critical points and the endpoints of the interval.
3. Compare the function values to determine the absolute maximum and minimum.

Step 1: Find the critical points.
f(x) = (x-3)^(3/4)
f'(x) = (3/4)(x-3)^(-1/4)

Set f'(x) = 0
(3/4)(x-3)^(-1/4) = 0

There is no solution for x, so there are no critical points.

Step 2: Evaluate the function at the endpoints of the interval.
f(-7) = (-7-3)^(3/4) = (-10)^(3/4) = 10^(3/4) * (-1)^(3/4)
f(7) = (7-3)^(3/4) = 4^(3/4)

Step 3: Compare the function values.
f(-7) = 10^(3/4) * (-1)^(3/4)
f(7) = 4^(3/4)

Since (-1)^(3/4) is a complex number and f(7) is a real number, the absolute maximum occurs at x = 7.

The absolute maximum of the function on the given interval is at x = 7, and the value is f(7) = 4^(3/4).

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