the fundamental resolution of a lens or telescope is determined by:
Answers
Answer:
The numerical aperture of the lens.
Explanation:
A numerical aperture is a dimensionless number that is the range of angles that the system can accept / emit light.
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Related Questions
if a heavy ball is thrown horizontally to the right, the person's motion will be____
Answers
When a heavy ball is thrown horizontally to the right, the person's motion will be slight to the left due to the conservation of momentum.
This phenomenon is described by Newton's Third Law of Motion, which states that for every action, there is an equal and opposite reaction.
When the person exerts a force to throw the ball, the ball pushes back with an equal force in the opposite direction. This results in the person experiencing a force to the left, causing their motion to be in that direction as well. The amount of motion depends on the mass and velocity of the ball as well as the mass of the person. This is described by the momentum conservation principle (momentum before = momentum after).
In summary, when a heavy ball is thrown horizontally to the right, the person's motion will be to the left due to the equal and opposite reaction force governed by Newton's Third Law of Motion and the conservation of momentum principle. The degree of the person's motion depends on the mass and velocity of the ball and the mass of the person.
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A boat is 4. 0 meters long and 2. 0 meters wide. Its water line is 1. 0 meter from the bottom of the boat; it is submerged to this water line. What is the mass of the boat?.
Answers
The mass of the boat is 8000kg.
Remove the boat trailer from the vehicle and weigh the vehicle. Launch the boat or remove it from the trailer if it is small and weigh the trailer. Subtract the trailer and vehicle weight from the total, and you're left with the weight of the boat. Adding mass to the boat means it has to displace more water. That means the boat floats deeper.
calculation:-
length of boat = 4 meter
wide =2 meter
mass of the boat = 2 × 4 × 1000
= 8000kg
How a Leaky Boat Sinks The air in the hull begins to replace the water and the density of the entire boat exceeds the density of the water and sinks. Mass measurements in chemistry, biology, and other sciences are performed using balances. All scales use the acceleration of gravity to measure mass.
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What affects the direct of the wire's movement?
Answers
Answer:
Some of the factors that increase the resistance of a wire include: Temperature: The cooler the wire, the lesser the resistance than warmer wires. Cross-sectional area: The thick wires have lower resistance and vice versa. Length of the wire: shorter wires will experience lesser resistance while longer wires will experience more resistance.Explanation:
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Which of the following pairs of objects would make a good scale model of Earth and the moon? A. a basketball and a soccer ball B. a basketball and a baseball (or softball) C. a basketball and a ping-pong ball D. a basketball and a pea E. a basketball and a grain of sand
Answers
C. a basketball and a ping-pong ball would make a good scale model of Earth and the moon. The diameter of a basketball is about 24 cm, while the diameter of a ping-pong ball is about 4 cm.
The ratio of the diameters is 6:1, which is similar to the ratio of the diameters of the Earth and the moon (about 3.7:1). This means that if you imagine the basketball as Earth, the ping-pong ball would be a good representation of the size of the moon relative to the Earth.
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Elements are composed of atoms of at least two different types.
True
False
Answers
Answer:
true
Explanation:
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The diameter of a copper wire is thought to be approximately 0.3mm. Which instrument should be used to obtain a more accurate measurement of the diameter of the wire? A measuring tape B metre rule C micrometer D ruler 2
Answers
Answer:
C
Explanation:
The correct answer should be the micrometer.
The micrometer is an instrument that is capable of measuring the component of an object to very high precision. It is used to obtain accurate measurements in engineering.
In the case of the copper wire, the diameter of 0.3 mm was an approximation and a more accurate measure of the diameter would be obtained by using the micrometer.
The correct option is C.
Wat is acceleration!???
Answers
Explanation:
Acceleration , rate at which velocity changes with time, in terms of both speed and direction.A cart with a ma of 120 kg collide with a tationary dumpter with a ma of 300 kg. Both the cart and the dumpter are free to roll in any direction. The cart and the dumpter tick together after the colliion and move at 0. 5 m/. What other information i needed to determine the final momentum of the dumpter?
Answers
No other information is required to find the momentum of the dumpster, the final momentum of the dumpster is 150 kgm/s.
The cart with a mass Ma of 120 Kg collides with a stationary dumper of mass 300 Kg.
The dumper and the cart are free to roll in any direction and after collision they move with a speed of 0.5 m/s.
No further information is required to find the final momentum of the dumpster.
We can simply use the formula,
Momentum = Final speed x mass
Momentum of dumpster = 0.5 x 300
Momentum of dumpster = 150 Kgm/s.
So, the final momentum of the dumpster is 150 kgm/s.
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Ten years ago, you put $5,000 in a savings account. Today, your investment has the purchasing power of $4,800 What is your real rate of return
Answers
The real rate of return for ten years ago, you put $5,000 in a savings account is -0.41%.
A pace of return (RoR) can be applied to any venture vehicle, from land to bonds, stocks, and artistic work. The RoR works with any resource gave the resource is bought at one particular moment and produces income sooner or later. Past rates of return, which can be compared to assets of the same type to determine which investments are most appealing, are part of how investments are evaluated. Before making an investment decision, many investors prefer to select a required rate of return.
By using the calculator of simple interest we get the value as -0.41%.
Taking into account the time value of money (TVM), which the CAGR does not take into account, is the next step in comprehending RoR over time. Limited incomes take the profit of a venture and rebate every one of the incomes in view of a markdown rate. The rebate rate addresses a base pace of return OK to the financial backer, or an expected pace of expansion. Businesses evaluate the profitability of their investments using discounted cash flows in addition to investors.
Let's say, for example, that a business uses a discount rate of 5% and is thinking about spending $10,000 on a new piece of equipment. The business uses the equipment, which results in an increase of $2,000 annually in cash inflows for five years after a $10,000 cash outflow. Each year for five years, the company applies present value table factors to the $10,000 outflow and $2,000 inflow.
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10. a) m₁ = 5 kg and m₂ = 8 kg. A block of mass mi is on a ramp that is inclined at 20° above the horizontal. It is connected by a string to a block of mass m2 that hangs over the top edge of the ramp. The coefficient of kinetic friction between the incline and the mi block is 0.22. What is the acceleration of the masses and the tension in the string? 20⁰ b) If m₁ = 8 kg, and the coefficient of static friction between mi and the incline is 0.300, find the maximum value of m2 that will not make mi slide up the incline (ie. when static friction is maximum). m₁ m₂
Answers
The acceleration of the first block is 1.55 m/s². The tension in the string is -8.25 m2 N (downwards). The maximum value of m2 is 7.49 kg to prevent sliding.
a) Acceleration of masses: The free-body diagram of the blocks is given as follows:free-body diagram of block masses. It can be seen that there are two forces on the first block. One is the gravitational force and the other is the force due to tension. The force acting on the first block along the direction of the incline is given as follows: F=mg sin θHere, m = 5 kg, g = 9.8 m/s², θ = 20°F= 5 × 9.8 × sin 20 = 16.59 NThe force of friction, Ff, is given as follows: Ff= μmg cos θwhere μ is the coefficient of kinetic friction and is equal to 0.22Ff= 0.22 × 5 × 9.8 × cos 20°= 8.83 NThe net force acting on the first block along the incline direction is given as follows: Fnet= F - Ff= 16.59 - 8.83= 7.76 N. The acceleration of the block is given as follows:a = Fnet / m = 7.76 / 5= 1.55 m/s²Now, let's find the tension in the string. The force acting on the second block is given as follows: F = m2 gThe acceleration of the second block is the same as that of the first block. Therefore, the force acting on the second block can be written as follows: F = m2 aThe tension in the string is given as follows:T = F - m2 g= m2 a - m2 g= m2 (a - g)= m2 (1.55 - 9.8)= -8.25 m2 NThis means that the direction of the tension is downwards. It is because the force of tension in the string is acting in the opposite direction to the gravitational force acting on the second block. Therefore, the tension is acting downwards.b) Maximum value of m2:The free-body diagram of the system is given as follows:free-body diagram of the systemThe maximum force of static friction, Fs, max, can be given as follows: Fs,max= μsNwhere μs is the coefficient of static friction and N is the normal force acting on the block mi.N = m1 g cos θHere, m1 = 8 kg, g = 9.8 m/s², θ = 20°N = 8 × 9.8 × cos 20°= 73.70 NThe maximum force of static friction is given as follows: Fs,max= 0.3 × 73.70= 22.11 NThe force of tension acting on the block mi can be written as follows: T = m2 g sin θThe force of tension must be less than or equal to the maximum force of static friction. Therefore, we can write the following inequality:m2 g sin θ ≤ Fs,maxm2 ≤ Fs,max / g sin θ= 22.11 / (9.8 sin 20°)= 7.49 kg. Hence, the maximum value of m2 that will not make mi slide up the incline is 7.49 kg.For more questions on acceleration
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Which factor is not needed when calculating the velocity of a satellite orbiting a planet.
Answers
When calculating the velocity of a satellite orbiting a planet, there are several factors that are needed, including the mass.
The distance between the center of the planet and the center of the satellite, and the gravitational constant of the universe.However, one factor that is not needed when calculating the velocity of a satellite orbiting a planet is the mass of the satellite itself. This is because the mass of the satellite does not affect the gravitational force between the planet and the satellite, which is the force responsible for keeping the satellite in orbit. The velocity of the satellite depends only on the distance between the planet and the satellite and the mass of the planet.
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When calculating the velocity of a satellite in orbit, the mass of the satellite itself can be disregarded. This simplifies the calculation and allows for a more straightforward determination of the satellite's velocity.
When calculating the velocity of a satellite orbiting a planet, there are several factors that must be taken into consideration. These factors include the mass of the planet, the radius of the orbit, and the gravitational force acting upon the satellite. However, there is one factor that is not needed when calculating the velocity of a satellite in orbit - the mass of the satellite itself.
This may seem counterintuitive, as the mass of an object typically plays a significant role in determining its velocity. However, when it comes to satellites in orbit, their mass is not a determining factor. This is because the gravitational force acting upon the satellite is solely determined by the mass of the planet and the radius of the orbit.
Therefore, when calculating the velocity of a satellite in orbit, the mass of the satellite itself can be disregarded. This simplifies the calculation and allows for a more straightforward determination of the satellite's velocity.
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Tần số ngưỡng của một kim loại có giá trị X. Nếu tần số của chùm sáng chiếu đến bề mặt katot tăng từ 2X đến 4X thì cường độ dòng quang điện sẽ
Answers
Answer:
Năng lượng tăng gấp đôi.
Explanation:
Như chúng ta biết
E = nhf
Năng lượng tỷ lệ thuận với f
Thay đổi về tần số sẽ tương đương với những thay đổi tương tự về Năng lượng
Nếu tần số trở thành hai lần, thì năng lượng sẽ trở thành 2 lần.
Two kids take part in a tug of war on an icy playground (don't try this at home). There is zero friction between their shoes and the ground. Child A has a mass of 26 - kg and child B has a mass of 49 - kg. They are initially standing 11 m apart. A. How far from child A is their CM? B. Each child holds the end of a rope and child B pulls on the rope so that he moves toward child A. How far will child B have moved when he collides with child A?
Answers
Explanation
26 divide
829, 23-1,24,IB9
0,^uO992
Add them. You get 55CM
Two kids of different masses take part in a tug of war with no friction. The distance of their center of mass can be calculated, and if child B pulls on the rope towards child A, the distance he will move before colliding with child A can also be calculated.
A. To find the center of mass (CM) of the system, we need to take into account both the masses and their distances from each other. The formula for the position of the CM is:
CM = (m1x1 + m2x2) / (m1 + m2)
where m1 and m2 are the masses, x1 and x2 are their distances from a chosen reference point.
In this case, let's take child A as the reference point, so x1 = 0 (since child A is at the origin), and x2 = 11 m. Then we have:
CM = (m1x1 + m2x2) / (m1 + m2)
= (26 kg * 0 + 49 kg * 11 m) / (26 kg + 49 kg)
= 7.6 m
Therefore, the center of mass of the system is located 7.6 m from child A.
B. As child B pulls on the rope, he will move towards child A, and their separation distance will decrease. At the same time, the center of mass of the system will move towards child B. Since there is no external force acting on the system, the position of the center of mass will not change.
Let's assume that child B moves a distance of x towards child A before they collide. Then the distance between child A and the CM of the system will be (11 - x), and the distance between child B and the CM will be x. Using the formula for the position of the CM, we can set up an equation:
CM = (m1x1 + m2x2) / (m1 + m2)
= ((26 kg) * 0 + (49 kg) * (11 - x)) / (26 kg + 49 kg)
= (539 - 49x) / 75
Since the CM does not move, this must be equal to the initial position of the CM, which we found to be 7.6 m from child A:
(539 - 49x) / 75 = 7.6
Solving for x, we get:
x = 6.4 m
Therefore, child B will have moved a distance of 6.4 m towards child A before they collide.
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You are a birdwatcher visiting the desert southwest. Which of the following birds are you most likely to find? a ferruginous pygmy owl, which often nests in saguaro cacti and eats insects a bay-breasted warbler, which feeds on larvae found in coniferous trees an orchard oriole, which builds its hanging nest in scrubby or open wooded areas an American dipper, which feeds on insects found in fast-flowing, rocky streams
Answers
As a birdwatcher visiting the desert southwest, the bird I am most likely to find is the ferruginous pygmy owl.
These owls are well-adapted to the arid desert environment and are often found nesting in saguaro cacti. Their small size and camouflage make them difficult to spot, but their distinctive call and active hunting behavior make them a sought-after sighting. The ferruginous pygmy owl primarily feeds on insects, which are abundant in the desert ecosystem, making it well-suited to this habitat.
While the bay-breasted warbler, orchard oriole, and American dipper are fascinating birds, they are not commonly found in the desert southwest. The bay-breasted warbler is typically found in coniferous forests and feeds on larvae found in trees. The orchard oriole prefers scrubby or open wooded areas, where it builds its hanging nest. The American dipper, on the other hand, is known for its unique adaptation to fast-flowing, rocky streams and feeds on insects found in these aquatic environments.
Therefore, if I were a birdwatcher in the desert southwest, my best bet for an exciting sighting would be the ferruginous pygmy owl, as it is well-suited to the arid conditions and can be found nesting in saguaro cacti.
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Surface metal raceways are suitable for use in: ____________
Answers
Surface metal raceways are suitable for use in various applications where electrical wiring needs to be protected and organized. Some common applications where surface metal raceways are used include:
1. Commercial buildings: Surface metal raceways are often installed in commercial buildings, such as offices, retail stores, and hospitals, to route electrical wiring along walls and ceilings. They provide a neat and organized appearance while ensuring the safety and protection of the wiring.
2. Industrial settings: Surface metal raceways are suitable for industrial environments where there may be a higher risk of physical damage or exposure to harsh conditions. They can be used to run electrical wiring in factories, warehouses, and manufacturing facilities.
3. Educational institutions: Surface metal raceways are commonly found in schools, colleges, and universities to accommodate electrical wiring for classrooms, laboratories, and other educational spaces.
4. Residential buildings: Surface metal raceways can be used in residential applications where surface-mounted electrical conduit is preferred or required. They can be installed in homes to route wiring along walls and baseboards.
5. Renovation or retrofit projects: Surface metal raceways are often utilized in renovation or retrofit projects where surface-mounted electrical wiring is necessary due to building constraints or design considerations.
It is important to consult local electrical codes and regulations to ensure compliance and safety when using surface metal raceways in specific applications.
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the silvered wall of a vacuum bottle takes care of heat flow by
Radiation
Convection
Conduction
Conduction and convection
Answers
2/4 points (graded) you stand on a spherical asteroid of uniform density whose mass is kg and whose radius is 10 km. these are typical values for small asteroids. (a) how fast do you have to throw a rock straight up so that it never comes back to the asteroid and ends up traveling at a speed of 3 m/s when it is very far away?
Answers
To throw a rock so that it never comes back to the asteroid and ends up traveling at a speed of 3 m/s when it is very far away, you need to throw it with a speed of at least 7.14 m/s.
To throw a rock so that it never comes back to the asteroid and ends up traveling at a speed of 3 m/s when it is very far away, you need to calculate the escape velocity of the asteroid.
Escape velocity (ve) is equal to the square root of 2GM/R, where G is the Gravitational constant (6.674 x 10-11 m3/kg s2), M is the mass of the asteroid (kg), and R is the radius of the asteroid (10 km).
So, to calculate the escape velocity,
you need to use the equation:
ve = sqrt (2GM/R) = sqrt (2 x 6.674 x 10-11 x kg/10,000 m) = 7.14 m/s.
Therefore, to throw a rock so that it never comes back to the asteroid and ends up traveling at a speed of 3 m/s when it is very far away, you need to throw it with a speed of at least 7.14 m/s.
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Which would not be a reason for using wind power?
O Wind power has been created in areas where the wind is fast and consistent to provide consistent power.
O Wind power produces no pollution whatsoever.
O Wind power requires much less capital than other forms of alternative energy.
O Wind cannot be transported or used directly.
Answers
A)What is the mass, in grams, of 28.76 mL of acetone?
B)What is the volume, in milliliters, of 6.40 g of acetone?
both in significant figures
Answers
A) The mass of 28.76 mL of acetone is approximately 22.7 g.
B) The volume of 6.40 g of acetone is approximately 8.12 mL.
A) To determine the mass of 28.76 mL of acetone, we need to know the density of acetone. The density of acetone is approximately 0.789 g/mL. Therefore, we can calculate the mass as follows:
Mass = Volume * Density
Mass = 28.76 mL * 0.789 g/mL
Performing the calculation:
Mass ≈ 22.67564 g
Rounding the result to the correct number of significant figures, the mass of 28.76 mL of acetone is approximately 22.7 g.
B) To determine the volume of 6.40 g of acetone, we can rearrange the formula:
Volume = Mass / Density
Volume = 6.40 g / 0.789 g/mL
Performing the calculation:
Volume ≈ 8.116 g/mL
Rounding the result to the correct number of significant figures, the volume of 6.40 g of acetone is approximately 8.12 mL.
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An electron moves from 5 V to 15 V, gaining kinetic energy. How much kinetic energy did it gain? 0 O 10 eV
O 15 eV O 5 ev O 1 eV
Answers
The electron gained 10 eV of kinetic energy.
When an electron moves from a lower potential energy level to a higher one, it gains kinetic energy.
The potential difference or voltage between the two levels determines the amount of kinetic energy gained by the electron.
In this case, the electron moved from 5 V to 15 V, meaning that the potential difference or voltage was 10 V.
The kinetic energy gained by the electron is therefore given by the equation: KE = qV, where q is the charge of the electron and V is the potential difference.
Substituting the values, we get KE = (1.6 x 10^-19 C) x 10 V = 1.6 x 10^-18 J or 10 eV.
Therefore, the electron gained 10 eV of kinetic energy.
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To calculate the kinetic energy gained by an electron moving from 5V to 15V, we need to use the formula for kinetic energy: KE = (1/2)m\(v^{2}\), where m is the mass of the electron and v is its velocity.
Since we are only given the change in potential energy (from 5V to 15V), we need to use the formula for potential energy: PE = qV, where q is the charge of the electron and V is the potential difference. The charge of an electron is -1.6 x \(10^{-19}\) Coulombs. Therefore, the potential energy gained by the electron is PE = (-1.6 x \(10^{-19}\) C) x (15V - 5V) = -1.6 x \(10^{-19}\) J. To convert this potential energy into kinetic energy, we use the formula: KE = PE. Therefore, the electron gained -1.6 x \(10^{-19}\) J of kinetic energy. However, this answer is in joules, not electron volts (eV), which is a more commonly used unit for measuring energy in the context of atomic and molecular systems. To convert joules to electron volts, we use the conversion factor: 1 eV = 1.6 x \(10^{-19}\) J. Therefore, the electron gained: -1.6 x 1 \(10^{-19}\) J / (1.6 x \(10^{-19}\) J/eV) = -1 eV. Since energy cannot be negative, we can conclude that the electron gained 1 eV of kinetic energy as it moved from 5V to 15V. Therefore, the correct answer is O 1 eV.
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Two balls collide, they are elastic if:
a. Total Momentum before and after is the same.
b. Total Kinetic Energy before and after is the same.
c. Total Momentum and Kinetic before and after are the same.
d. Total Potential energy is the same before and after a collision,
Answers
Answer:
C. Total Momentum and Kinetic Energy before and after are the same.
Explanation:
Elastic collisions are collisions in which both momentum and kinetic energy are conserved.
In this type of collision (elastic), there is no net loss in kinetic energy in the system as a result of the collision. Therefore, both momentum and kinetic energy are conserved quantities in elastic collisions.
Hi there!
C. Total Momentum and Kinetic before and after are the same.
Elastic collisions satisfy the following conditions:
\(p_i = p_f\)
Initial momentum = final momentum
\(KE_i = KE_f\)
Initial kinetic energy = final kinetic energy
Help me!
l want the correct answers :)
Answers
A. State of motion
B. Sachin
C. State of rest
John and Jim are on a swing set next to each other. They want to perform a physics experiment on oscillatory motion. John will start his swing 3 degrees back from equilibrium, and Jim will start his swing 9 degrees back from equilibrium. Based on what you know about oscillatory motion, who between John or Jim will reach the equilibrium position first? John and Jim are on a swing set next to each other. They want to perform a physics experiment on oscillatory motion. John will start his swing 3 degrees back from equilibrium, and Jim will start his swing 9 degrees back from equilibrium. Based on what you know about oscillatory motion, who between John or Jim will reach the equilibrium position first? John will reach first because he has less distance to travel. Jim will reach first because he has more energy and therefore more velocity. We can't tell who will reach the bottom first because we need to know their masses, as the gravitational acceleration plays a key role. Both will reach the equilibrium position simultaneously because the frequency doesn't depend on the amplitude.
Answers
Take into account that both John and Jim on the swing set, can be considered as independent pendulums.
You have that the period of a pendulum is given by:
\(T=2\pi\sqrt[]{\frac{l}{g}}\)where,
l: length of the pendulum
g: gravitational acceleration constant.
As you can notice, the period of oscillation (and then the frequency) of a pendulum does not depend of the angular amplitud of oscillation. Moreover, take into account that the period of oscillation determines the time each John and Jim take to reach the bottom.
Hence, you can conclude:
Both will reach the equilibrium position simultaneously because the frequency doesn't depend on the amplitude.
You are driving along a straight road at night at a constant speed of 26.5 m/s
when
you see a stalled car 75.2 m ahead. It will take you 0.75 seconds to react,
and then you will slam on your brakes, skidding to a halt in a time of 4.85
seconds. What would your total stopping distance be, from the moment you first
see the stalled car? What does this imply about whether you will hit the stalled
car or not?
Answers
Answer:
84.1 m
Explanation:
Δx = stopping distance = Vot + 1/2at²
find a (acceleration first):
a = ΔV/t = (0 - 26.5 m/s)/4.85 s = 5.46 m/s²
Δx = (26.5 m/s)(0.75s) + (1/2)(5.46 m/s²)(4.85 s)²
Δx = 19.9 m + 64.2 m = 84.1 m
You will hit the car! During the 0.75 s reaction time, you've already gone 19.9 m, then you need another 64.2 m to come to a complete stop.
it is possible to use a simple machine and gain no mechanical advantage
Answers
Answer:
yes
Explanation:
Question 1 of 20:
Select the best answer for the question.
1. Unlike the IQ, your emotional intelligence (EQ)___
A. can be discovered through your academic grades.
B. may be improved over time by becoming more mindful.
C. can only be developed during childhood.
D. is a set value that never changes.
PLEASE HELP!!!!
Answers
Unlike the IQ, your emotional intelligence (EQ) may be improved over time by becoming more mindful
Emotional intelligence is the understanding and usage of one's own emotions in a positive way to relieve their stress. It also helps for effective communication, to overcome challenges, to empathize and to defuse any bad situation.
Option A is the correct for IQ ( Intelligence quotient ). Option C is wrong because EQ can be built in any stage of your life. EQ is basically emotions. So option D is incorrect.
Therefore, Unlike the IQ, your emotional intelligence (EQ) may be improved over time by becoming more mindful
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A sonar signal of frequency 1 x 10^6 Hz has a wavelength of 1.5 mm in * 30 points
water. a) What is the speed of the signal in water? b) What is its period in
water? c) What is its period in air?
Answers
a) To find the speed of the signal in water, we can use the equation:
Speed = Wavelength x Frequency
Where Wavelength is given as 1.5 mm and Frequency is given as 1 x 10^6 Hz.
Speed = 1.5 x 10^-3 m x 10^6 Hz = 1.5 x 10^3 m/s
So the speed of the signal in water is 1.5 x 10^3 m/s
b) To find the period in water, we can use the equation:
Period = 1 / Frequency
Where Frequency is given as 1 x 10^6 Hz
Period = 1 / (1 x 10^6) s = 1 x 10^-6 s = 1 microsecond
So the period of the signal in water is 1 microsecond
c) The speed of sound in air is approximately 343 m/s. Since the frequency of the signal remains constant and the speed of sound in air is different than the speed of sound in water, the wavelength of the signal will also be different. However, since the period is inversely proportional to the frequency and is independent of the medium, the period of the signal in air will be the same as in water, which is 1 microsecond.
Hello people ~
Equipotentials at a great distance from a collection of charges whose total sum is not zero are approximately
(a) spheres
(b) planes
(c) paraboloids
(d) ellipsoids
Answers
Answer:
Spheres
Explanation:
Points charges are the collection of charges which are located very large distance from each other.
Now as they are approximately equidistant like radius of circle or spheres they are to be spherical.
Thermal physics vs atomic physics ...which is easier?
Answers
Answer:
Thermal physics
Explanation:
Because it uses temperature
Answer:
In my opinion both are easier if you'll work hard on it...
An astronomical telescope has an objective lens with a focal length of 160 cm and an eyepiece lens with a focal length of 5 cm. the magnification of this telescope is ____.
Answers
An astronomical telescope has an objective lens with a focal length of 160 cm and an eyepiece lens with a focal length of 5 cm. the magnification of this telescope is 120
A telescope that is intended for seeing celestial bodies and does not need an image-erecting device is anastronomical telescope. While terrestrial telescopes are used to examine faraway objects on earth, astronomical telescopes are used to observe distant stars and planets.
While the final image in the terrestrial telescope is upright, the final image in the astronomical telescope is inverted. Telescopes gather and enlarge the light coming from far-off objects. Observing things in the night sky presents challenges since they are so far away and, as a result, appear so dim. We can see these things more clearly the more light a telescope can gather.
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