The given diagram shows the motion of a mass on a string which is swung in a circle. Which of the given arrows correctly shows the direction of the tangential velocity at the instant the mass is at the position shown?

- A
- B
- C
- D

Answer:

The laboratory testing is done on metrics. The research will help find the preference of a person among various drinks.

Explanation:

The laboratory testing is for research purposes. When a person is introduced with two different drinks he may have different experiences. The taste of two different drinks is sweet. A persons behavior towards the taste is psychological also. If he is already informed that the drinks will be sweet, he might start feeling sweeter when he tastes it even if the drink has no taste.

Based on linear velocity, size of impulse, and force required to stop them, the automobiles are ranked from largest to smallest in size.

Light blue car = Purple car > Red car = Yellow car =  Blue car > Green car

As fast-acting force or "impact" is referred to as "impulse," impulse may be described as "the abrupt force operating on an item for a brief period of time."

Force (F), Impulse (J) and linear momentum (P) are related as

P = mu

where m = mass

           u = initial velocity

J = ΔP = m (v - u)

Impulse is the change in momentum as we know.

J = F.t

Therefore, P ∝ J ∝ F

Thus, it follows that the force and impulse required to stop each automobile are precisely proportional to its linear momentum.

The Red car's linear momentum is computed as;

P = 1000 x 10 = 10, 000 kg.m/s

The Yellow car's linear momentum is computed as;

P = 2,000 x 5 = 10,000 kg.m/s

The Blue car's linear momentum is computed as;

P = 500 x 20 = 10,000 kg.m/s

The Light blue car's linear momentum is computed as;

P = 1,000 x 20 = 20,000 kgm/s

The Purple car's linear momentum is computed as;

P = 4,000 x 5 = 20,000 kg.m/s

Therefore the rankin of the automobiles will be

Light blue car = Purple car > Red car = Yellow car =  Blue car > Green car

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The complete question is;

Six automobiles are initially traveling at the indicated velocities. The automobiles have different masses and velocities. The drivers step on the brakes and all automobiles are brought to rest. Red Car: 1000kg, 10m/s Yellow Car: 2,000kg, 5m/s Blue Car: 500kg, 20m/s Light Blue Car: 1,000kg, 20m/s Green Car: 500kg, 10m/s Purple Car: 4,000kg, 5m/s Part A Rank these automobiles based on the magnitude of their momentum before the brakes are applied, from largest to smallest. Rank from largest to smallest. To rank items as equivalent, overlap them. Part B Rank these automobiles based on the magnitude of the impulse needed to stop them, from largest to smallest. Rank from largest to smallest. To rank items as equivalent, overlap them. Part C Rank the automobiles based on the magnitude of the force needed to stop them, from largest to smallest. Rank from largest to smallest. To rank items as equivalent, overlap them.

Answer:

True

Explanation:

the independent variable would be like if the psychologist is experimenting the impact of sleep deprivation, sleep deprivation would be the independent variable that is being manipulated or changing its level systematically in the experiment.

The critical angle for the following materials surrounded by air is a) θc = 44.21⁰.

b) θc = 41.14⁰

c)  θc = 40.36⁰

What is critical angle ?

The angle of incidence at which the angle of refraction equals 90 degrees is known as the critical angle. When light enters a denser media from such a comparatively rarer medium, the orientation of light changes as well as the light beam bending towards the normal.

sin θ = n2/n1

For air,

n₂ = 1

so,

sin θ =  1/n1

(a) fluorite : n₁ = 1.434⁰

sin θ = 0.697                   θc = 44.21⁰.

(b) crown glass: n₁ = 1.52⁰  

sin θ = 0.657                   θc = 41.14⁰.

(c) sodium chloride : n₁= 1.544⁰

sin θ = 0.647                   θc = 40.36⁰.

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The speed of the running shaft driving the machine, given that the main shaft to drive the machine has a pulley of diameter 140 mm is 111.4 rev/min

First, we shall list out the given parameters from the question. Details below:

The speed of the running shaft can be obtain as shown below:

S₁D₁ = S₂D₂

183 × 140 = S₂ × 230

183 × 140 = S₂ × 230

25620 = S₂ × 230

Divide both sides by 230

S₂ = 25620 / 230

S₂ = 111.4 rev/min

Thus, we can conclude that the speed of the running shaft driving the machine is 111.4 rev/min

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Answer:

136 meters.

Explanation: If it can go 17 meters a second, then after 8 seconds, it will go 136 meters. Multiple 17 by 8 to get your answer.

It is not good to site a nuclear power plant in a densely populated areas as well as an area that has a high proximity to public infrastructure.

A nuclear plant is one of the proposed solution to the issue of power generation because of the capacity of the plants to generate electricity. Usually, a single nuclear plant could contribute to serve for many years using the same nuclear fuel.

Now, in the case whereby we want to site a new nuclear plant, we have to consider the population density of the area as well as the proximity of the plant to the regions whereby people live.

We know that it is not good to site a nuclear power plant in a densely populated areas as well as an area that has a high proximity to public infrastructure.

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Explanation:

answer is 6.0Kg •m/s because

momentum= mass • velocity

that is 5 • 1.2 = 6

Answer: 550 cm

Explanation:

Original equation: 1/f= 1/do + 1/di.

F=50.0 cm, and do=55.0.

Since we don't have di, we'll have to subtract do to the other side, making the equation: 1/f - 1/do= 1/di.

Doing the math, 1/f - 1/do is 0.0018181818

Then to get di by itself, you multiply both sides by di. Then you divide by 0.0018181818 to get di by itself. You then get: di= 1/0.0018181818

At that point, you just divide 1 by 0.0018181818, which will give you 550 cm

There could be simpler way, but that is just what I did to get the answer. Answer was right on Acellus

Answer:

  v = \(n \frac{\hbar }{m r}\)

the sppedof the electron is also quantized

Explanation:

The angular momentum of a rotating body is

         L = m v r

in Bohr's atomic model the quantization postulate is that the angular momentum is equal to

         L = n \(\hbar\)

we substitute

        n \(\hbar\) = m v r

        v = \(n \frac{\hbar }{m r}\)

where n is an integer.

Therefore, the sppedof the electron is also quantized, that is, sol has some discrete values.

The height of the hill is 15 m.

The height of the hill is calculated by applying the principle of conservation of energy as shown below.

Kinetic energy at the bottom of the hill = Potential energy at the top of the hill

mgh = ¹/₂mv²

gh = ¹/₂v²

h = ( v² ) / ( 2g )

where;

h = ( v² ) / ( 2g )

h = ( 17.15² ) / ( 2 x 9.8 )

h = 15 m

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Answer:

25.88 N

Explanation:

Mass of the shopping cart,\(m=65 kg\)

The coefficient of friction between the cart and the floor, \(\mu= 0.01\)

Let, F be the required force to accelerate the cart at \(a=0.30 m/s^2\).

Gravitational force, mg, acts downward which is being balanced by the normal reaction, N, on the cart by the floor.

As the motion of the cart in the vertical direction is zero. So, using the static equilibrium condition will be zero.

From free body diagram (FBD):

\(N-mg=0\)

\(\Rightarrow N=mg.\)

the net force action in this direction The frictional force, f, acts in the direction to opposes the motion of the cart as shown.

\(f=\muN=\mu mg\)

Now, apply the dynamic equilibrium condition in the horizontal direction, i.e. net force acting on the body equals the rate of change of momentum of the body. From the FBD of the cart, we have

\(F-f-ma=0\)

\(\Rightarrow F=f+ma\)

\(\Rightarrow F=\mu mg+ma\)

\(\Rightarrow F=m(\mu g +a)\)

\(\Rightarrow F=65(0.01\times 9.81 + 0.3)\)

\(\Rightarrow F=25.88 N.\)

Hence, 25.88 N force required to accelerate the body with 0.03 \(m/s^2\) .

Cooling coil is a part of air conditioner and  you are likely to find it located in the ductwork of a large apartment building. Hence, option (B) is correct.

The cooling coils are a part made up of tubes made of various materials that allow a fluid to move through them. These tubes also have an exterior contact with air or another gas, which enables a heat exchange.

In the fluid that flows through the cooling coils, either water or a refrigerant may be present.

The cooling coils are elements that cool or warm the air in a cooling system intended for comfort.

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The upward acceleration of the acrobat is 1.833 m/s².

Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

Given parameters:

Mass of the acrobat; M = 588 N.

Weight of the acrobat acting downwards; W = 588 N.

Upward force provided by each of the two ropes; f = 349 N.

Hence, net force acting on the acrobat in upward direction = 2f -w

= (2×349 - 588 ) N.

= 110 N.

Hence, the upward acceleration of the acrobat is = net force/ mass

= 110/60 m/s².

=1.833 m/s².

So, the upward acceleration of the acrobat is 1.833 m/s².

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Answer:

λ = 396.7 nm

Explanation:

For this exercise we use the diffraction ratio of a grating

           d sin θ = m λ

in general the networks works in the first order m = 1

we can use trigonometry, remembering that in diffraction experiments the angles are small

           tan θ = y / L

           tan θ = \(\frac{sin \theta}{cos \theta}\) = sin θ

           sin θ = y / L

we substitute

          \(d \ \frac{y}{L}\) = m λ

with the initial data we look for the distance between the lines

           d = \(\frac{m \lambda \ L}{y}\)

           d = 1 656 10⁻⁹ 1.00 / 0.600

            d = 1.09 10⁻⁶ m

for the unknown lamp we look for the wavelength

           λ = d y / L m

           λ = 1.09 10⁻⁶ 0.364 / 1.00 1

           λ = 3.9676 10⁻⁷ m

           λ = 3.967 10⁻⁷ m

we reduce nm

           λ = 396.7 nm

Answer:The Answer is economic gain

Explanation:

The range of frequencies  of visible light in a vacuum is mathematically given as

Fmin=4.19*10^14Hz  to Fmax=1*10^15Hz

Question Parameters:

The wavelengths of visible light vary from about 300 nm to 700 nm.

Generally, the equation for the frequency   is mathematically given as

F=C/\lambda

Therefore

For Fmax

\(Fmax=\frac{300*10^8}{3*10^9}\)

Fmax=1*10^15Hz

Where

\(Fmin=\frac{3*10^8}{700*10^9}\)

Fmin=4.19*10^14Hz

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120V is the line-to-neutral voltage .

It is defined as the voltage of a power transmission circuit or distribution circuit up to the point of transformation or utilization.

The secondary line voltage is \(V_{L} = 280 V\)

The notation AC indicates that the current is an alternating current.

The given formula is \(V_{ph} = \frac{V_{L} }{\sqrt{3} }\)

Substitute  208 V into the formula

\(V_{ph} = \frac{V_{L} }{\sqrt{3} } \\\\V_{ph} = \frac{208V}{\sqrt{3} } \\\\= 120 (Approx)\)

So, the line-to-neutral voltage is 120 V.

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Answer:

The acceleration of a 2 kg box acted on by a net force of 2 N is solved by using Newton’s second law of motion in the form acceleration = F_net / mass. Since the mass of the box is 2 kg and the net force is 2 N, the acceleration of the 2 kg box is 1 m/s^2.

Bernoulli's equation allows to find the correct result for wing lift is:

       1: by forcing air to move faster over the top of the wing

In fluid mechanics that studies the motion of fluids, the conservation of energy and work is given by the Bernoulli equation

          P₁ + ½ ρ g v₁² + ρ g y₁ = P₂ + ½ ρ g v₂² + ρ g y₂

Where 1 and 2 are the points of interest, above and below the wing, ρ the density, v the velocity, and y the height.

To simplify, suppose that the wing is horizontal, so the difference in height is the width of the wing, the so-called lift is the difference in pressure between the inner and upper part of the wing.

           (P₂-P₁) = ½ ρ (v₁² - v₂²) + ρ g (y₁-y₂)

For a positive lift ΔP> 0 and for the plane to climb, we must have several facts:

Let's reverse the claims:

      1. True. This makes the term of the kinetic energy be greater and there is greater lift.

     2. False. If the velocity is the same, the energy difference is zero and the substantiation is zero or negative.

     3. False. That makes the lift negative.

In conclusion using Bernoulli's equation we can find the correct result for the wing lift is:

          1: by forcing air to move faster over the top of the wing

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Strong interpretation is an important thing in meteorology. Because, analyzing the climate level in each area and the factors affecting it with their visual representation is very important in weather forecast.

Meteorology is a branch of science dealing with the weather in different regions. On interpreting data, forecasters are tasked with synthesizing available observations from multiple platforms (including surface observations, weather balloons, radar, and satellite), numerical guidance from computer model forecasts, scientific theory, and experience-based intuition to arrive at a forecast.  

The forecast process is often collaborative, with teams of meteorologists routinely integrating new information into the forecast as the event approaches.

Increasingly, forecasters are also responsible for effectively communicating the forecast and its anticipated impacts upon life and property to various stakeholders, including the public.

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The velocity of the man given the data from the question is 0.45 m/s

Velocity is simply defined as the rate of change of displacement with time. Mathematically, it can be expressed as:

Velocity = Change of displacement / time

From the question given above, the following data were obtained:

The velocity of the man can be obtained as follow:

Velocity = Change of displacement / time

Velocity = 2 / 4.4

Velocity = 0.45 m/s

Thus, the velocity of the man is 0.45 m/s

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Answer: The answer is 120

Explanation:

Answer:

120 kg•m/s.

Explanation:

From the question given above, the following data were obtained:

Case 1

Mass of object = M

Velocity of object = V

Momentum = 15 kg•m/s

Case 2

Mass of object = 2M

Velocity of object = 4V

Momentum = ?

Momentum is defined as follow:

Momentum = mass × velocity

The momentum of object in case 2 can be obtained as follow:

From case 1

Momentum = mass × velocity

15 = M × V

15 = MV ....... (1)

From case 2:

Momentum = mass × velocity

Momentum = 2M × 4V

Momentum = 8MV ....... (2)

Finally , substitute the value of MV in equation 1 into equation 2.

Momentum = 8MV

MV = 15

Momentum = 8 × 15

Momentum = 120 kg•m/s

Therefore, an object with a mass of 2M and 4V would have a momentum of 120 kg•m/s

The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C

To calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.

However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.

Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.

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Answer:

The horse will run a distance of 1.5 times the length of the rope around the pole with the rope tightly stretched.

Explanation:

The distance the horse will run around the pole with the rope tightly stretched can be calculated using the formula for the circumference of a circle:

Circumference = 2 × π × radius

Since the horse takes one and a half rounds, we need to multiply the circumference by 1.5 to get the total distance the horse runs around the pole.

Let's assume that the length of the rope is the radius of the circle, and the horse is tied at the center.

Therefore, the distance the horse will run around the pole with the rope tightly stretched is:

Distance = 1.5 × 2 × π × radius

Since the horse is tied with a long rope, we need to use the length of the rope as the radius of the circle.

Let's assume that the length of the rope is 'L'. Then the radius of the circle is equal to L/2π.

Substituting this value in the formula, we get:

Distance = 1.5 × 2 × π × (L/2π)

Simplifying the expression, we get:

Distance = 1.5 × L

Therefore, the horse will run a distance of 1.5 times the length of the rope around the pole with the rope tightly stretched.

Answer:

1.2 s

Explanation:

Given:

v₀ = 8.0 m/s

v = -4.0 m/s

a = -10 m/s²

Find: t

v = at + v₀

(-4.0 m/s) = (-10 m/s²) t + (8.0 m/s)

t = 1.2 s