The government of Mexico declared blue sharks an endangered species.
They put tags on 36 blue sharks and release them. Later, they corral 130
blue sharks; among those blue sharks, 20 were tagged. Find the best
estimate for the blue shark population?

Answer:

A.

Step-by-step explanation:

Subtract -4x on both sides to get to -2y=-4x-8, then you should divide -2 into both sides to get to the slope of y=2x+4 since two negatives would equal to a positive when dividing and multiplying.  Because the slope is positive, it is safe to assume that the first two options A and B are the best options due to their slopes being positive and going up.  The y-intercept is 4 which makes the answer A because on 0 it is on the positive side.

Answer:

B. 13 units

Step-by-step explanation:

let

(x1 , y1) = (-4 , -6)

(x2 , y2) = (1 , 6)

distance between CD = root (x2 - x1)^3 + (y2 - y1)

= root {1 - ( -4)}^2 + {6 - ( -6)}^2

= root {1 +4}^2 + {6+6}^2

= root 5^2 + 12^2

= root 25 + 144

= root 169

= 13 units ans

I'm guessing you mean

\(\displaystyle \int\frac{x^2+4}{x^2+4x+3}\,\mathrm dx\)

First, compute the quotient:

\(\displaystyle \frac{x^2+4}{x^2+4x+3} = 1 + \frac{4x-1}{x^2+4x+3}\)

Split up the remainder term into partial fractions. Notice that

x ² + 4x + 3 = (x + 3) (x + 1)

Then

\(\displaystyle \frac{4x-1}{x^2+4x+3} = \frac a{x+3} + \frac b{x+1} \\\\ \implies 4x - 1 = a(x+1) + b(x+3) = (a+b)x + a+3b \\\\ \implies a+b=4 \text{ and }a+3b = -1 \\\\ \implies a=\frac{13}2\text{ and }b=-\frac52\)

So the integral becomes

\(\displaystyle \int \left(1 + \frac{13}{2(x+3)} - \frac{5}{2(x+1)}\right) \,\mathrm dx = \boxed{x + \frac{13}2\ln|x+3| - \frac52 \ln|x+1| + C}\)

We can simplify the result somewhat:

\(\displaystyle x + \frac{13}2\ln|x+3| - \frac52 \ln|x+1| + C \\\\ = x + \frac12 \left(13\ln|x+3| - 5\ln|x+1|\right) + C \\\\ = x + \frac12 \left(\ln\left|(x+3)^{13}\right| - \ln\left|(x+1)^5\right|\right) + C \\\\ = x + \frac12 \ln\left|\frac{(x+3)^{13}}{(x+1)^5}\right| + C \\\\ = \boxed{x + \ln\sqrt{\left|\frac{(x+3)^{13}}{(x+1)^5}\right|} + C}\)

Answer:

20:44

Step-by-step explanation:

Make it into a equation: 5x+11x=64

This equals 16x=64

x=4

Then, multiply 5 by 4 and 11 by 4

The final answer is 20:44

The probability the letter Julianna draws is NOT the letter A is 0.75

Julianna wrote each of the 8 letters in her name on same-sized pieces of paper, so there are 8 possible outcomes when she randomly draws one paper from the bag.

Out of the 8 letters, two letter is A.

So, the probability of drawing the letter A is 2/8 = 1/4

The probability of not drawing the letter A is the complement of this probability, which is:

1 - 1/4 = 3/4

This gives

1 - 1/4 = 0.75

Therefore, the probability, in decimal form, that the letter on the paper Julianna draws is not the letter A is 0.75

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Answer:12

Step-by-step explanation:

Answer:

u > 7

Step-by-step explanation:

-2u -6 < -20  Add 6 to both sides

-2u - 6 + 6 < -20 + 6

-2u < -14  Divide both sides by -2.  When you multiply or divide both sides by a negative number, you must flig the sign.

\(\frac{-2u}{-2}\) > \(\frac{-14}{-2}\)

u > 7

Helping in the name of Jesus.

The answer is:

u > 7

In-depth explanation:

You haven't told me what the values of u are, but I'll solve the equation for u.

Add 6 on each side:

\(\bf{-2u-6 < -20}\)

\(\bf{-2u < -14}\)

Divide each side by -1 and reverse the sign:

\(\bf{2u > 14}\)

Now divide each side by 2

\(\bf{u > 7}\)

All three approaches yield the same result: AED4,600,000 (Expenditure Approach), AED1,600,000 (Income Approach), and AED1,800,000 (Production Approach). This consistency demonstrates that the three approaches provide equivalent measures of GDP.

To calculate the contributions to GDP of the given transactions, we can use the three approaches: the expenditure approach, income approach, and production approach. Let's calculate the GDP using each approach and demonstrate that they give the same answer.

Expenditure Approach:

GDP is calculated as the sum of all final expenditures. In this case, the final expenditures are the sales of the supercomputers.

GDP = Sales of supercomputers

= (3 * AED1,000,000) + (1 * AED800,000)

= AED3,800,000 + AED800,000

= AED4,600,000

Income Approach:

GDP can also be calculated by summing up all the incomes earned during production. In this case, the incomes include wages, interest, and taxes.

GDP = Wages + Interest + Taxes

= (Labour costs for ABC + Labour costs for Jumbo) + (Interest on debt for ABC) + (Taxes for ABC + Taxes for Jumbo)

= (AED1,000,000 + AED200,000) + AED100,000 + (AED200,000 + AED100,000)

= AED1,200,000 + AED100,000 + AED300,000

= AED1,600,000

Production Approach:

GDP can also be calculated by summing the value added at each stage of production. In this case, the value added is the sales price minus the cost of components purchased.

GDP = Sales price of supercomputers - Cost of components

= (3 * AED1,000,000) + (1 * AED800,000) - (4 * AED500,000)

= AED3,000,000 + AED800,000 - AED2,000,000

= AED1,800,000

As we can see, all three approaches yield the same result: AED4,600,000 (Expenditure Approach), AED1,600,000 (Income Approach), and AED1,800,000 (Production Approach). This consistency demonstrates that the three approaches provide equivalent measures of GDP.

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Answer: C

Step-by-step explanation:

Answer:

3^(4)-2

Step-by-step explanation:

That's the answer

.

.

.

Answer:

\({ \tt{ = 2f + 6f}}\)

- Factorise out f as the common factor;

\({ \tt{ = f(2 + 6)}} \\ = 8f\)

Answer:

t=1, u=-2, w=-2

Step-by-step explanation:

Answer:

Hello,

Let s take n a number

the consecutive one is n+1

So n + n+ 1 = 2n+1=85

<=> 2n=84 <=> n = 42

So, the solution is 42, 43

thanks

Answer:

42,43

Step-by-step explanation:

Hope this helps

The set of the expression (A ∪ B) ∩ (B ∩ C') is {2, 3, 6}.

What is set?

Sets in mathematics, are simply a collection of distinct objects forming a group. A set can have any group of items, be it a collection of numbers, days of a week, types of vehicles, and so on. Every item in the set is called an element of the set.

Given that, U = {1, 2, 3, 4, 5, 6, 7, 8}, A = {6, 8, 2}, B = {3, 2, 5, 6}, and C = {5, 1, 7}.

If U is a universal set and A be any subset of U then the complement of A is the set of all members of the universal set U which are not the elements of A.

So, complement of set C is C'={2, 3, 4, 6, 8}

Now, (A ∪ B) ∩ (B ∩ C')

= ({6, 8, 2}∪{3, 2, 5, 6}) ∩ ({3, 2, 5, 6}∩{2, 3, 4, 6, 8})

= {2, 3, 5, 6, 8} ∩ {2, 3, 6}

= {2, 3, 6}

Therefore, the set of the expression (A ∪ B) ∩ (B ∩ C') is {2, 3, 6}.

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"Your question is incomplete, probably the complete question/missing part is:"

Let U = {1, 2, 3, 4, 5, 6, 7, 8}, A = {6, 8, 2}, B = {3, 2, 5, 6}, and C = {5, 1, 7}. Find the following.

(A ∪ B) ∩ (B ∩ C').

The capacity of this swimming pool is between B. 500 gallons to 1,000 gallons.

Capacity refers to the product of the length, width, and height of a three-dimensional object or space.

The capacity of an object means the same as its volume.

Olympic-size swimming pools have the following standard dimensions:

Length = 50 m

Width = 25 m

Height = 2 m

Capacity of an Olympic swimming pool = 2,500 m³ (50 x 25 x 2)

= 660,000 gallons (2,500 x 1,000 ÷ 3.785)

An interval estimate shows the lower and upper limits.

6 x 105 gallons = 630 gallons

Thus, the capacity of the swimming pool is Option B.

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A. 100 gallons to 500 gallons

B. 500 gallons to 1,000 gallons

C. 1,000 gallons to 1,500 gallons

D. 1,500 gallons to 2,000 gallons

Therefore, the interest portion of the seventh payment is:7,000 x (1 + r + r2 + r3 + r4 + r5 + r6) / r7 - 7,000.

We have the following payments and their corresponding times of payment:At the end of year 1: $1,000At the end of year 2: $2,000At the end of year 3: $3,000At the end of year 4: $4,000At the end of year 5: $5,000At the end of year 6: $6,000At the end of year 7: $7,000

At the end of year 8: $8,000At the end of year 9: $9,000At the end of year 10: $10,000The present value of these payments is:PMT x [(1 - (1 + r)-n) / r]where PMT is the payment, r is the interest rate per year, and n is the number of years till payment.

For the first payment (end of year 1), the present value is:1,000 x [(1 - (1 + r)-1) / r]which equals

1,000 x (1 - 1 / (1 + r)) / r = 1,000 x ((1 + r - 1) / r) = 1,000

For the second payment (end of year 2), the present value is:2,000 x [(1 - (1 + r)-2) / r]which equals 2,000 x (1 - 1 / (1 + r)2) / r = 2,000 x ((1 + r - 1 / (1 + r)2) / r) = 2,000 x (1 + r) / r2

For the seventh payment (end of year 7), the present value is:

7,000 x [(1 - (1 + r)-7) / r]

which equals

7,000 x (1 - 1 / (1 + r)7) / r = 7,000 x ((1 + r - 1 / (1 + r)7) / r) = 7,000 x (1 + r + r2 + r3 + r4 + r5 + r6) / r7

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Answer:

C. 2, -1, -5, -8.

Step-by-step explanation:

a = first term = 2

second term, a2n-1)  - 3  = 2 - 3  = -1

third term  = -2 - 3 = -5

fourth term = -5 - 3 = -8.

Answer:

To evaluate the function f(x) = (1/2)x + 3 for f(4), we substitute x = 4 into the function:

f(4) = (1/2)(4) + 3

= 2 + 3

= 5

Therefore, the correct answer is a. 5.

Answer:

A

Step-by-step explanation:

to evaluate f(4) substitute x = 4 into f(x)

f(x) = \(\frac{1}{2}\) x + 3 ← substitute x = 4

f(4) = \(\frac{1}{2}\) (4) + 3 = 2 + 3 = 5

Answer:

Local minimum at x = 0.

Step-by-step explanation:

Local minimums occur when g'(x) = 0 and g"(x) > 0.

Local maximums occur when g'(x) = 0 and g"(x) < 0.

Set g'(x) equal to 0 and solve:

0 = 2x (x − 1)² (x + 1)²

x = 0, 1, or -1

Evaluate g"(x) at each point:

g"(0) = 2

g"(1) = 0

g"(-1) = 0

There is a local minimum at x = 0.

Answer:

Local minimums occur when g'(x) = 0 and g"(x) > 0.

Local maximums occur when g'(x) = 0 and g"(x) < 0.

Set g'(x) equal to 0 and solve:

0 = 2x (x − 1)² (x + 1)²

x = 0, 1, or -1

Evaluate g"(x) at each point:

g"(0) = 2

g"(1) = 0

g"(-1) = 0

There is a local minimum at x = 0.

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

total marbles = 10

green = 2

red = 2

blue = 4

probability that both marbles he chooses are green = ?

Step 02:

simple probability = favorable outcomes / total outcomes

1st event: probability of green marble

pg1 = 2 / 10

2nd event: probability of green marble

pg2 = 1 / 9

total probability:

total probability = pg1 + pg2

total probability = 2/10 + 1/9

The answer is:

The probability that both marbles he chooses are green is 14 /45

The plot of the residuals to the area indicates that the graph that corresponds to the residuals is the second option.

Please find attached the graph of the residual plot for the data created with MS Excel

A residual plot is a tool used for assessment of statistical models, to determine how fit the model is to the data. A residual plot is a plot of the residuals to the input or x-values of the data.

The trend line for the data in the question obtained using MS Excel indicates that we get; y = 0.1128·x + 3.6158

The residuals, which is the difference between the actual values and the calculated value obtained using MS Excel are;

Area (in²)    \({}\)              Residuals

x-value

5 \({}\)                             -1.0178

10 \({}\)                           -0.2718

24 \({}\)                           0.605

46 \({}\)                           0.7874

53 \({}\)                           0.7018

78 \({}\)                           0.0758

84 \({}\)                           -0.129

100 \({}\)                         -0.7538

The above values for the areas and the residuals indicates that the residual plot is n shaped, with the first two values being below the x-axis, which corresponds to the second option

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Answer:

$39.50 is the final payment.

Step-by-step explanation:

0.3 x 53.95 = 16.185

53.95 - 16.185

= 37.765

0.045 x 37.765 = 1.699425 + 37.765

= 39.464425 and round

Step-by-step explanation:

Answer:$15.40

Step-by-step explanation:

Answer:

Angle BPQ = 64°

Step-by-step explanation:

4x + 12 +2x = 90

6x + 12 = 90

     - 12    -12

6x = 78

x = 13°

BPQ = ((4(13) + 12)°

           (52 + 12)°

            64°