the graph of a line is shown on the grid. the coordinates of both point indicated on the graph of the line are integer

Answer:

Assuming u meant 2y - 13y^(11), the degree is 11

Step-by-step explanation:

Answer:

Step-by-step explanation:

The highest power is 11 so the degree of polynomial is 11.

Answer:

The first value of a relation is an input value and the second value is the output value. A function is a specific type of relation in which each input value has one and only one output value.

An input is an independent value, and the output value is the dependent value, as it depends on the value of the input.

Answer:

a) % age of samples containing none of these defects = 93.9%

b)% age of samples containing at least one of these defects = 6.1%

c) % age of samples free of type X and/or type Y defects = 95.8%

d) %age of samples with not more than 1 defect = 98.9%

Step-by-step explanation:

Data Given:

Number of Samples = 1000

Type X defect = 2.1% = 21 samples

Type Y defect = 2.4% = 24 samples

Type Z defect = 2.8% = 28 samples

Both Type X and Y defect = 0.3% = 3 samples

Both Type X and Z defect = 0.4% = 4 samples

Both Type Y and Z defect = 0.6% = 6 samples

Type X and Y and Z defect = 0.1%  = 1 sample

Venn Diagram is attached in the attachment below. Please refer to attachment for the Venn Diagram.

a) % age of samples containing none of these defects.

Solution:

Number of samples containing none of these defects = Total - Samples with defects

Number of samples containing none of these defects = 1000 - { (Type X) + (Type Y) + (Type Z) - (Both X and Y) - (Both X and Z) - (Both Y and Z) + (All defects X and Y and Z) }

 Number of samples containing none of these defects = 1000 - { (21) + (24) +(28) - (3) -(4) - (6) + (1) }

Number of samples containing none of these defects = 1000 - 61

Number of samples containing none of these defects = 939

% age of samples containing none of these defects = 939/1000 x 100

% age of samples containing none of these defects = 93.9%

b) % age of samples containing at least one of these defects:

We have already calculated this above, number of samples containing at least on of these defects:

number of samples containing at least on of these defects = { (Type X) + (Type Y) + (Type Z) - (Both X and Y) - (Both X and Z) - (Both Y and Z) + (All defects X and Y and Z) }

number of samples containing at least on of these defects = { (21) + (24) +(28) - (3) -(4) - (6) + (1) }  

number of samples containing at least on of these defects = 61

% age of samples containing at least one of these defects = 61/1000 x 100

% age of samples containing at least one of these defects = 6.1%

c) % age of samples free of type X and/or type Y defects.

For this find, we need to find the samples with only Z Type defect.

Number of Samples with Only Z type defects = { (Type Z) - (Both X and Z) - (Both Y and Z) + (All defects X and Y and Z) }

Number of Samples with Only Z type defects = { (28)  -(4) - (6) + (1) }

Number of Samples with Only Z type defects = 19

Now, we also know the number of samples without any defects = 939

Now,

The number of samples free of type X and/or type Y defect = Sum of Number of Samples with Only Z type defects and number of samples without any defects

The number of samples free of type X and/or type Y defect = 19+939

The number of samples free of type X and/or type Y defect = 958

% age of samples free of type X and/or type Y defects = 958/1000 x 100

% age of samples free of type X and/or type Y defects = 95.8%

d) %age of samples with not more than 1 defect:

For this find, we need to find number of samples with only X type and with only type Y and with only type Z.

We have already found the number of samples with only Z type defect = 19

Now,

number of samples with only X type defect = { (Type X) - (Both X and Z) - (Both X and Y) + (All defects X and Y and Z) }

number of samples with only X type defect =  { (21)  -(4) - (3) + (1) }

number of samples with only X type defect =  15

Similarly,

number of samples with only Y type defect =  { (Type Y) - (Both Y and Z) - (Both X and Y) + (All defects X and Y and Z) }

number of samples with only Y type defect =  { (24)  -(6) - (3) + (1) }

number of samples with only Y type defect =  16

For,

samples with not more than 1 defect = number of samples with only Y type defect + number of samples with only X type defect + number of samples with only z type defect + number of samples without any defects

samples with not more than 1 defect = 939 + 16 + 15 + 19

samples with not more than 1 defect = 989

%age of samples with not more than 1 defect = 989/1000 x 100

%age of samples with not more than 1 defect = 98.9%

Answer:

6

Step-by-step explanation:

Each side can, with a shape consisting of only convex angles (which triangles and squares by definition do) make at most two intersections.

Intersection point is the point at which the two lines are intersect each other.

The maximum number of intersection points two triangles can have, where no two sides are parallel is 6.

What is intersection point?

Intersection point is the point at which the two lines are intersect each other.

Given-

Two triangle intersect each other.

Number of parallel lines for the two triangle is zero.

Two triangle can intersect each other at number of ways.

If any side of two triangle is not parallel then they cuts each other as shown in the given figure to obtained the maximum number of intersection.

As the one side (line) of the one triangle can cut the other triangle only two times ( if vertex is not considered). Thus the number of time total 3 sides of a triangle cuts the other triangle is,

\(=2\times3\\=6\)

Hence, the maximum number of intersection points two triangles can have, where no two sides are parallel is 6.

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Answer:

\(Probability = \frac{1}{9}\)

Step-by-step explanation:

Given

Toppings: Pico de gallo, Onions and Steak

Required

The probability of getting Onions and Steak

The probability is calculated using:

\(Probability = P(Onion)\ and\ P(Steak)\) --- because the events are independent

\(P(Onion) = \frac{n(Onion)}{Total}\)

\(P(Onion) = \frac{1}{3}\)

\(P(Steak) = \frac{n(Steak)}{Total}\)

\(P(Steak) = \frac{1}{3}\)

So, we have:

\(Probability = P(Onion)\ and\ P(Steak)\)

\(Probability = P(Onion)\ *\ P(Steak)\)

\(Probability = \frac{1}{3} * \frac{1}{3}\)

\(Probability = \frac{1}{9}\)

the tangent is only horizontal at the critical points of the equation, so

\(y=2x^3+3x^2-12x+3\implies \cfrac{dy}{dx}=6x^2+6x-12\implies \cfrac{dy}{dx}=6(x^2+x-2) \\\\\\ \stackrel{\textit{setting the derivative to 0}}{0=6(x^2+x-2)}\implies 0=x^2+x-2 \\\\\\ 0=(x+2)(x-1)\implies \boxed{x= \begin{cases} -2\\ 1 \end{cases}} \\\\[-0.35em] ~\dotfill\\\\ y=2(-2)^3+3(-2)^2-12(-2)+3\implies y=-16+12+24+3\implies \boxed{y=23} \\\\\\ y=2(1)^3+3(1)^2-12(1)+3\implies y=2+3-12+3\implies \boxed{y=-4} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \text{\LARGE (-2~~,~~23)\qquad (1~~,~~-4)}~\hfill\)

Answer:

6. -f         7. f= 6/8

Step-by-step explanation:

Hope dis helps!!

Answer:

it's area is 18 square unit

Step-by-step explanation:

we can either count the squares (by sine lines are just going somewhere through the squares cutting them into unknown sizes).

or we can think and see, that we have 2 shapes combined into 1 larger shape :

1. the bottom rectangle 6×2 units

2. the top triangle 6 units baseline, 2 units height.

the area of a rectangle is length × width.

so, in our case :

6×2 = 12 square units

the area of a triangle is

baseline×height/2

so, in our case

6×2/2 = 6 square units

so, in total our figure has

12 + 6 = 18 square units

Answer:

9000

Step-by-step explanation:

Using the Pythagoras theorem, the longest leg has the length of 24 feet.

Given that,

A ladder of length (2x+6) feet is positioned x feet from a wall.

Height of the ladder = (2x + 6) feet

Distance of ladder from the wall = x feet

Height of the wall that the ladder is placed = (2x + 4) feet

These three lengths form s right triangle where (2x + 6) feet is the hypotenuse.

Longest leg is (2x + 4) feet

Using the Pythagoras theorem,

(2x + 6)² = (2x + 4)² + x²

4x² + 24x + 36 = 4x² + 16x + 16 + x²

4x² + 24x + 36 = 5x² + 16x + 16

x² - 8x - 20 = 0

(x - 10) (x + 2) = 0

x = 10 or x = -2

x = 2 is not possible.

So x = 10

Longest leg = 2x + 4 = 20 + 4 = 24 feet

Hence the length of the longest leg is 24 feet.

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Answer The cost to get into the red cab is two dollars second question it cost two dollars per mile:

Step-by-step explanation:

Answer & Step-by-step explanation:

a) For Cinderella's equation, we will write it as  3^(x-1) (x being the day)
For Aurora's equation, we will write it as 65+10n (x being the day)

b) Since Aurora's number only increases by 10 a day, that equation is linear. Since Cinderella's number increases by a greater amount everyday and has an exponent, her equation is exponential.

c) Plugging in 8 for x in each equation, we get
2178 for Cinderella and
145 for Aurora

Meaning that Cinderella will sell far more on the 8th day.

The angles that we have in the image here are:

When two angles are measured, they sum up to 180. They are said to be supplementary angles.

On the question, we have two angles that are 90 degrees on a straight line. Hence they are supplementary.

This is an angle that is at 90 degrees. We have to two right angles on the diagram that we have here.

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The general solution of the differential equation y" + y = tant, 0< t < π/2 is y_c(t) = c1 cos(t) + c2 sin(t), the general solution of the differential equation y" + 9y = sec²(3t), 0< t < π/6 is y(t) = y_c(t) + y_p(t) = c1 cos(3t) + c2 sin(3t) + 1/2 sec²(3t)

4.

To find the general solution of the differential equation y" + y = tant, 0< t < π/2, we first find the complementary solution by solving the characteristic equation r² + 1 = 0:

r² = -1

r = ±i

The complementary solution is therefore

y_c(t) = c1 cos(t) + c2 sin(t)

To find a particular solution, we use the method of undetermined coefficients and assume a solution of the form y_p(t) = AtBt, where A and B are constants. Taking the derivatives and substituting into the differential equation, we get:

y" + y = -2Acos(t) + 2Bsin(t) + tant

Equating the coefficients of cos(t) and sin(t), we get the following system of equations:

-2A = 0 (since there is no cos(t) term on the right-hand side)

2B + tan(t) = 0

Solving for A and B, we get:

A = 0

B = -1/2 tan(t)

Therefore, the particular solution is

y_p(t) = -1/2 tan(t)

The general solution is the sum of the complementary solution and the particular solution:

y(t) = y_c(t) + y_p(t) = c1 cos(t) + c2 sin(t) - 1/2 tan(t)

5. To find the general solution of the differential equation y" + 9y = sec²(3t), 0< t < π/6, we first find the complementary solution by solving the characteristic equation r² + 9 = 0:

r² = -9

r = ±3i

The complementary solution is therefore

y_c(t) = c1 cos(3t) + c2 sin(3t)

To find a particular solution, we use the method of undetermined coefficients and assume a solution of the form y_p(t) = Asec²(3t), where A is a constant. Taking the derivatives and substituting into the differential equation, we get:

y" + 9y = 6Asec(3t)tan(3t) + 2Asec²(3t)

Equating the coefficients of sec(3t)tan(3t) and sec²(3t), we get the following system of equations:

6A = 0 (since there is no sec(3t)tan(3t) term on the right-hand side)

2A = 1

Solving for A, we get:

A = 1/2

Therefore, the particular solution is

y_p(t) = 1/2 sec²(3t)

The general solution is the sum of the complementary solution and the particular solution:

y(t) = y_c(t) + y_p(t) = c1 cos(3t) + c2 sin(3t) + 1/2 sec²(3t)

6. To find the general solution of the differential equation y'' + 4y' + 4y = 12e^(-2t), t > 0, we first find the complementary solution by solving the characteristic equation r² + 4r + 4 = 0:

(r + 2)² = 0

r = -2 (double root)

The complementary solution is therefore

y_c(t) = c1 e^(-2t) + c2 t e^(-2t)

To find a particular solution, we use the method of undetermined coefficients and assume a solution of the form y_p(t) = A e^(-2t), where A

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Answer:

The critical numer is x = -3/10

Step-by-step explanation:

We need to find the derivative of the function and then equal to zero to get the values of x.

The function is:

\(f(x)=10x^{2}+6x\)

Let's take the derivative whit respect of x and equal to zero.

\(f'(x)=20x+6\)

\(0=20x+6\)

Now, we just need to solve it for x.

\(x=-\frac{3}{10}\)

The critical numer is x = -3/10

I hope it helps you!

Answer:

Step-by-step explanation:

$100x0.5x1=$5

A percentage is a way to describe a part of a whole. The amount of the sales tax is $10.5.

A percentage is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25 which is equal to 25%.

To convert a fraction to a percentage, convert the fraction to decimal form and then multiply by 100 with the '%' symbol.

Given the taxable amount of the sale is $150, while the Sales tax percentage is 7%. Therefore, the amount of sales tax is,

Amount of sales tax = 7% of $150 = 0.07 × 150 = $10.5

Hence, the amount of the sales tax is $10.5.

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Answer:

∠b=82°

Step-by-step explanation:

143°=∠c+∠b (exterior angle property)

143°=61°+∠b

∠b=143-61

∠b=82°

To find the number of dimes and quarters, you have 17 dimes and 34 quarters in your pocket , when there are 51 coins in your pocket.

To solve this problem, we can set up a system of equations using the given information. Let's use "d" to represent the number of dimes and "q" to represent the number of quarters.

We know that there are 51 coins in total, so we can write the equation: d + q = 51.

We also know that the total value of the coins is $10.20, which can be expressed as 10d + 25q (since dimes are worth 10 cents and quarters are worth 25 cents). So our second equation is: 10d + 25q = 1020.

To solve this system of equations, we can use substitution or elimination. Let's use substitution:

Rearrange the first equation to solve for d: d = 51 - q.

Substitute this expression for d in the second equation: 10(51 - q) + 25q = 1020.

Simplify and solve for q: 510 - 10q + 25q = 1020.

Combine like terms: 15q = 510.

Divide both sides by 15: q = 34.

Now substitute this value back into the first equation to solve for d: d + 34 = 51.

Subtract 34 from both sides: d = 17.

Therefore, you have 17 dimes and 34 quarters.

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Answer:

13 of August,

Step-by-step explanation:

All of them worked together at day number zero (August 1).

We know that Elvis works every 3rd day

So he will work at:

day 3, day 6, day 9, etc.

We know that Izzy works every 4th day, then she will work at:

day 4, day 8, day 12, etc.

We know that Janaisa works every 6th day, so she will work at:

day 6, day 12, etc.

We just need to find a day where the 3 of them work, this is equivalent to finding a common multiple of the numbers: 3, 4 and 6.

To do it, we can just write the multiples of each one of these numbers and see which one is the first common multiple:

3)

3*1 = 3

3*2 = 6

3*3 = 9

3*4 = 12

3*5 = 15

...

4)

4*1 = 4

4*2 = 8

4*3 = 12

4*4 = 16

...

6)

6*1 = 6

6*2 = 12

So we can see that 12 is a common multiple of the 3 numbers.

Then they will work together 12 days after August 1th.

That would be the 13 of August,

Answer:

Step-by-step explanation:

a) Percent of already washed cars?

→ (67/260) × 100

→ 6700/260

→ 25.769

→ ≈ 25.77%

b) Wax job done each week will be?

→ (260/100) × 15

→ 2.6 × 15

→ 39 wax jobs

Hence, these are required answers.

Answer:

a)  25.8%

b)  39

Step-by-step explanation:

Given information:

To find the percent of the total expected cars that have already been washed, divide the number of cars already washed by the average number of cars washed per week:

\(\implies \dfrac{67}{260}=0.257692307...=25.8\%\; \sf (nearest\;tenth)\)

To find the number of cars that get a wax job each week, find 15% of 260:

\(\begin{aligned}\implies 15\%\; \textsf{of}\;260&=\dfrac{15}{100} \times 260\\\\&=\dfrac{3900}{100}\\\\&=39\end{aligned}\)

Therefore, 39 wax jobs are done each week.

Answer:

The pairs would be:

6 and 9

18 and 15

3 and 9

Step-by-step explanation:

Answer:

The pairs would be:

6 and 9

18 and 15

3 and 9

Step-by-step explanation:

Answer:

5,004,300

Step-by-step explanation:

Answer:

\(\large\boxed{\mathtt{9^{8}}}\)

Step-by-step explanation:

\(\textsf{For this problem, we are asked to simplify the given expression.}\)

\(\textsf{Let's begin by understand an important rule for problems like these.}\)

\(\mathtt{9^{3} \times 9^{5} = 9^{?}}\)

\(\large\underline{\textsf{We should remember that;}}\)

\(\textsf{When exponents multiply, they \underline{add}.}\)

\(\large\underline{\textsf{Why?}}\)

\(\textsf{If not, then the answer will be incorrect. Let's identify why in an example.}\)

\(\large\underline{\textsf{Bad Example:}}\)

\(\mathtt{2^{2} \times 2^{5} = 2^{2 \times 5 =10}}\)

\(\textsf{This means that;}\)

\(\mathtt{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \neq 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2.}\)

\(\large\underline{\textsf{Good Example:}}\)

\(\mathtt{2^{2} \times 2^{5} = 2^{2+5=7}}\)

\(\textsf{This means that;}\)

\(\mathtt{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2.}\)

\(\textsf{Let's follow the good example!}\)

\({\mathtt{9^{3} \times 9^{5} = 9^{3 + 5=8}}\)

\(\textsf{This means that;}\)

\(\mathtt{9 \times 9 \times 9 \times 9 \times 9 \times 9 \times 9 \times 9 = 9 \times 9 \times 9 \times 9 \times 9 \times 9 \times 9 \times 9.}\)

\(\large\boxed{\mathtt{9^{8}}}\)

\(\huge\text{Hey there!}\)

\(\mathsf{9^3 \times 9^5}\\\mathsf{= 9\times 9 \times 9\ \boxed{\times}\ 9\times 9\times 9 \times 9 \times 9}\\\mathsf{= 81\times 9\ \boxed{\times}\ 81\times81\times9}\\\mathsf{= 729\ \boxed{\times}\ 6,561\times 9}\\\mathsf{= 729\ \boxed{\times}\ 59,049}\\\mathsf{= 43,046,721}\\\mathsf{= 9^3 \times 9^5 \rightarrow 9^{3 + 5}\rightarrow 9^8}\)

\(\huge\text{Therefore your answer should be:}\)

\(\huge\boxed{\mathsf{9^8}}\huge\checkmark\)

\(\huge\text{Good luck on your assignment \& enjoy your day!}\)

The domain and range of the graph above in interval notation include the following:

Domain = [-6, 3]

Range = [-3, 3]

In Mathematics and Geometry, a domain refers to the set of all real numbers (x-values) for which a particular function (equation) is defined.

In Mathematics and Geometry, the horizontal portion of any graph is used to represent all domain values and they are both read and written from smaller to larger numerical values, which simply means from the left of any graph to the right.

By critically observing the graph shown in the image attached above, we can reasonably and logically deduce the following domain and range:

Domain = [-6, 3] or -6 ≤ x < 3.

Range = [-3, 3] or -3 < y < 3

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Answer:

You distribute first 2 into the parentheses

2x-20 Is your answer

thats all you do

Step-by-step explanation:

The distinguishing feature between a square and a rectangle is that all sides of a square are equal in length.

Yes, a square is a special type of rectangle because it possesses all the properties of a rectangle.

The distinguishing feature of a rhombus is that all sides are equal in length, while a parallelogram can have unequal side lengths.

Yes, a rhombus is a special type of parallelogram because it possesses the properties of a parallelogram and has all sides equal in length.

The three features used to describe 3-dimensional objects are faces, edges, and vertices.

The common properties between a square and a rectangle are that both have four sides, four right angles (90 degrees), and opposite sides that are parallel. The distinguishing feature is that all sides of a square are equal in length, while a rectangle can have unequal side lengths.

Yes, a square is a special type of rectangle. A rectangle is defined as a quadrilateral with four right angles, while a square is a specific type of rectangle where all sides are equal in length. Since a square possesses all the properties of a rectangle, including four right angles, it can be considered a special case of a rectangle.

The common properties between a rhombus and a parallelogram are that both have four sides and opposite sides that are parallel. The distinguishing feature of a rhombus is that all sides are equal in length, while in a parallelogram, the opposite sides are equal in length.

Yes, a rhombus is a special type of parallelogram. A parallelogram is defined as a quadrilateral with opposite sides that are parallel. A rhombus possesses this property, but it also has the additional feature of having all sides equal in length. Therefore, a rhombus can be considered a special case of a parallelogram.

The three features used to describe 3-dimensional objects are:

Faces: The flat surfaces that make up the object.

Edges: The lines where two faces intersect.

Vertices: The points where multiple edges meet.

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Answer:

315.59

Step-by-step explanation:

9152\29=315.59

Answer:

The ratios are equal if they are equal when written as fractions. ... A ratio of 1:7 is not the same as a ratio of 7:1.

Step-by-step explanation: