The graph of p = 400 and the graph of p = 50s - 200 intersect at the point (12,400). If the equation p = 50s - 200 represents the profit, p, based on s sales, what does the intersection best represent? Show work.

Differentiate both sides of

\(y = \dfrac{x\sqrt{a^2-x^2}}2 + \dfrac{a^2}2\sin^{-1}\left(\dfrac xa\right)\)

with respect to y ; by the product rule,

\(1 = \dfrac12\sqrt{a^2-x^2}\dfrac{\mathrm dx}{\mathrm dy} + \dfrac x2 \dfrac{\mathrm d}{\mathrm dy}\left[\sqrt{a^2-x^2}\right] + \dfrac{a^2}2\dfrac{\mathrm d}{\mathrm dy}\left[\sin^{-1}\left(\dfrac xa\right)\right]\)

Use the chain rule for the remaining derivatives.

\(\dfrac{\mathrm d}{\mathrm dy}\left[\sqrt{a^2-x^2}\right] = \dfrac1{2\sqrt{a^2-x^2}}\dfrac{\mathrm d}{\mathrm dy}\left[a^2-x^2\right] \\\\ = \dfrac{-2x}{2\sqrt{a^2-x^2}}\dfrac{\mathrm dx}{\mathrm dy} \\\\ = -\dfrac x{\sqrt{a^2-x^2}} \dfrac{\mathrm dx}{\mathrm dy}\)

Recall that

\(\dfrac{\mathrm d}{\mathrm dx}\left[\sin^{-1}(x)\right] = \dfrac1{\sqrt{1-x^2}}\)

Then

\(\dfrac{\mathrm d}{\mathrm dy}\left[\sin^{-1}\left(\dfrac xa\right)\right] = \dfrac1{\sqrt{1-\left(\frac xa\right)^2}}\dfrac{\mathrm d}{\mathrm dy}\left[\dfrac xa\right] \\\\ = \dfrac1{a\sqrt{1-\left(\frac xa\right)^2}}\dfrac{\mathrm dx}{\mathrm dy} \\\\ = \dfrac1{\sqrt{a^2}\sqrt{1-\left(\frac xa\right)^2}}\dfrac{\mathrm dx}{\mathrm dy} \\\\ = \dfrac1{\sqrt{a^2-x^2}}\dfrac{\mathrm dx}{\mathrm dy}\)

Putting everything together, we have

\(1 = \dfrac{\sqrt{a^2-x^2}}2\dfrac{\mathrm dx}{\mathrm dy} - \dfrac{x^2}{2\sqrt{a^2-x^2}}\dfrac{\mathrm dx}{\mathrm dy} + \dfrac{a^2}{2\sqrt{a^2-x^2}}\dfrac{\mathrm dx}{\mathrm dy}\)

\(1 = \left(\dfrac{\sqrt{a^2-x^2}}2+\dfrac{a^2-x^2}{2\sqrt{a^2-x^2}}\right)\dfrac{\mathrm dx}{\mathrm dy}\)

\(1 = \dfrac1{2\sqrt{a^2-x^2}}\bigg((a^2-x^2) + (a^2-x^2)\bigg)\dfrac{\mathrm dx}{\mathrm dy}\)

\(1 = \dfrac{2a^2-2x^2}{2\sqrt{a^2-x^2}}\dfrac{\mathrm dx}{\mathrm dy}\)

\(1 = \sqrt{a^2-x^2}\dfrac{\mathrm dx}{\mathrm dy}\)

\(\boxed{\dfrac{\mathrm dx}{\mathrm dy} = \dfrac1{\sqrt{a^2-x^2}}}\)

Answer:

90-51 = 39 39°

Step-by-step explanation:

Answer:

x = 0

Step-by-step explanation:

3 x -1 = -3 and 3 x -8x = -24x

-3 + 3( the opposite of the -3 given in the parentheses) = 0

-24x = 0

0/-24 (from -24x)= 0

x = 0

Market classes and grades are used to describe the quality and characteristics of agricultural products, including meat, poultry, fruits, and vegetables.  True

They provide a common language for buyers and sellers to communicate about the characteristics, such as the age, sex, fat content, and muscling, of the product. Market classes and grades help ensure that buyers receive products that meet their quality standards and help sellers receive a fair price for their products. For example, beef is graded based on marbling, maturity, and lean color, with the highest grade being USDA Prime, followed by USDA Choice and USDA Select.

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Full Question: market classes and grades encompass descriptive terminology of carcasses and products for the understanding of different groups or buyers. T/F

This standardized system of classification allows for easier communication and understanding between buyers and sellers, and ensures consistency and fairness in the marketplace.

Market classes and grades refer to the categorization and labeling of carcasses and products based on their quality and characteristics. These classifications use descriptive terminology that is understood by different groups of buyers, such as meat packers, wholesalers, retailers, and consumers. Market classes typically group animals based on their intended use, such as beef cattle for slaughter, while grades are assigned based on factors such as maturity, marbling, and fat content. This standardized system of classification allows for easier communication and understanding between buyers and sellers, and ensures consistency and fairness in the marketplace.

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Answer:

A

Step-by-step explanation:

Given:

r (radius) = 10 cm

l (length) = 60 cm

w (width) = 40 cm

Find: A (shaded) - ?

First, we have to find the area of the rectangle:

A (rectangle) = l × w

A (rectangle) = 60 × 40 = 2400 cm^2

Now, let's find the area of both circles inside the rectangle:

\(a(circles) = 2\pi {r}^{2} = 2\pi \times {10}^{2} = 200\pi \: {cm}^{2} \)

In order to find the shaded area, we have to subtract the area of both circles from the area of the rectangle:

\(a(shaded) = 2400 - 200\pi≈1772 \: {cm}^{2} \)

Answer: 8 hours

Step-by-step explanation:  240 mph ÷ 30 = 8 hours

a) The point that is on both lines is given as follows: (4, 60).

b) They will have read the same number of pages on the 4th day, when they will have read 60 pages.

We want to obtain the graphic solution for the system of equations, hence we obtain the point of intersection of the two equations.

The equations for this problem are given as follows:

Then the ordered pair representing the solution is given as follows:

(5,60).

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The measure of the exterior angle to ∠G is 138.9°.

A triangle is a three-sided closed-plane figure formed by joining three noncolinear points. Based on the side property triangles are of three types they are Equilateral triangle, Scalene triangle, and Isosceles triangle.

Given, In triangle EFG, m∠E = 95.2° and m∠F = 43.7°.

We know the sum of all the interior angles in a triangle is 180°.

We also know that the measure of an exterior angle in a triangle is the sum of the two opposite interior angles.

∴ The measure of the exterior angle to m∠G is = m∠E + m∠F.

= 95.2° + 43.7°.

= 138.9°.

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Answer:

B (3,1)

Step-by-step explanation:

Answer:

The answer is the 3rd one

Step-by-step explanation:

No, a trapezoid.

14) Let's plot those points for a visual conclusion

Note that B = B'

So the answer is:

No, as we can see the image defines a Trapezoid as another quadrilateral. without four right angles, and without four congruent sides.

We can also be sure by the fact that if we subtract the corresponding x values of each point of ABCD we'll have 4 units.

Answer: second C

Step-by-step explanation:

The value of m∠SRT as shown in the circle below is 46.5°.

A circle is a round-shaped figure that has no corners or edges.

To calculate the value of m∠SRT, use the formula below

Formula:

But,

From the diagram,

Given:

Substitute these values into equation 2

Finally we substitute the value m∠SUT into equation 1

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 CD is 11 square root of 14.  

The measure of the side length CD in the given right angled triangle as per the measurements is equal to option C. 11√14 .

In right triangle ABE,

Measure of angle ABE = 90 degrees

Measure of angle AEB = 60 degrees

AB = 11√7

Using trigonometric ratio we have,

tan 60° = AB / BE

⇒ √3 = 11√7 / BE

⇒ BE = 11√7 / √3

⇒BE = 11√21 / 3

In right triangle BED,

Measure of angle BED = 90 degrees

Measure of angle EBD= 45°

⇒Measure of angle EDB= 45°

BE ≅ ED

BE = 11√21 / 3

⇒ED = 11√21 / 3

Using Pythagoras theorem,

BD² = BE² + ED²

⇒BD = √ 2 (11√21 / 3 )²

⇒BD = 11√21 / 3 × √2

⇒ BD = 11√42 / 3

In right triangle CDB,

Measure of ∠CDB = 90°

Measure of ∠DCB = 30°

tan 30° = BD / CD

⇒ ( 1/ √3) = 11√42 / 3 / CD

⇒ CD =  [11√42 / 3 ] × √3

⇒ CD = 11√14

Therefore, the length of the side CD in the triangle is equal to option C. 11√14 .

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Since F < 0.3165, we fail to reject the null hypothesis H0: σ12 = σ22. Thus, we can conclude that there is no significant difference between the standard deviations of the noise levels of the 11 intensive care units and 26 nonmedical care areas at α=0.05.

1. Define: The two sample problem is used to determine whether two groups have the same population mean.

We consider two samples that are independent of each other, and we compare the variances of the two samples to determine if they are equal.

Hypothesis: H0: σ12 = σ22 Ha: σ12 ≠ σ22 We want to test if the noise levels in intensive care units are different from the noise levels in nonmedical care areas.

Sample: The standard deviation of the noise levels of the 11 intensive care units was 1 dBA, and the standard deviation of the noise levels of 26 nonmedical care areas, such as kitchens and machine rooms, was 13.2 dBA.

Test: To determine if there is a significant difference between the standard deviations of these two areas, we will use the F-test at α=0.05.

Critical Region: At α=0.05, we have an F-distribution with (df1 = 10, df2 = 25), therefore our critical region is: F < 0.3165 or F > 3.4617.

We have two sample standard deviations, we can use the F-test to determine if they are significantly different from each other. F = S12/S22 = 4.12/13.22 = 0.1009.7.

Since F < 0.3165, we fail to reject the null hypothesis H0: σ12 = σ22. Thus, we can conclude that there is no significant difference between the standard deviations of the noise levels of the 11 intensive care units and 26 nonmedical care areas at α=0.05.

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a) Total number of ways is:

∑ k=0⁸ (16 choose k) * (19 choose 3 - k) = 4,124,193

b) Total number of ways is:

2,884 × 2,365 = 6,824,860

c) Number of ways of balls distribution is simply:

(32 choose 16) * (16 choose 8) = 8,315,457,520

(a) In this case, we can distribute the red balls in the even-numbered boxes however we like, since we know that no odd box can be empty.

Once we have done that, we can use the stars and bars formula to distribute the remaining balls into the even boxes.

Let's say that the even-numbered boxes contain a total of k balls. Then we need to distribute 16 - k balls into 4 boxes, which can be done in (19 choose 3) ways using the stars and bars formula. So the total number of ways is:

∑ k=0⁸ (16 choose k) * (19 choose 3 - k) = 4,124,193

(b) In this case, we know that the odd boxes must have an odd number of balls and the even boxes must have an even number of balls. This means that we can only distribute the balls in the following ways:

Odd boxes: 1, 3, 5, or 7 balls

Even boxes: 0, 2, 4, 6, or 8 balls

Using the same stars and bars formula as before, we can compute the number of ways to distribute the balls in each case, and then multiply the results together. For the odd boxes, we have:

(16 choose 1) + (16 choose 3) + (16 choose 5) + (16 choose 7) = 2,884

For the even boxes, we have:

(16 choose 0) + (16 choose 2) + (16 choose 4) + (16 choose 6) + (16 choose 8) = 2,365

So the total number of ways is:

2,884 × 2,365 = 6,824,860

(c) In this case, we have 32 balls to distribute among the 8 boxes. We can distribute the red and green balls independently of each other, so the number of ways to distribute the balls is simply:

(32 choose 16) × (16 choose 8) = 8,315,457,520

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Answer:

the answer is d. fjdkdkddkdkdkd

The positive values will decrease (1.5, 1.25) while the negative values will increase in terms of absolute value (-0.5, -5)

It might help to draw out a number line, as shown below, to help sort out the values.

Answer:

36x²y²z²

.......................

Step-by-step explanation:

like terms

3×3x × x ×y×y×4z×z

= 3× 3x² × y² ×4z²

= 3(3x² × y² ×4z²)

= 3(12x²y²z²)

= 36x²y²z²

Given d = {dn: n ∈ N} where dn = (−n, 1/n) for n ∈ N.Find the union and intersection of the given family of d sets.

The given family of sets is {d1, d2, d3, ...} where di = (−i, 1/i) for all i ∈ N.1. To find the union of the given family of sets d, take the union of all sets in the given family of sets.i.e. d1 = (−1, 1), d2 = (−2, 1/2), d3 = (−3, 1/3), ...

Thus, the union of the given family of sets d is{d1, d2, d3, ...} = (-1, 1].Therefore, the union of the given family of sets d is (-1, 1].2. To find the intersection of the given family of sets d, take the intersection of all sets in the given family of sets .i.e. d1 = (−1, 1), d2 = (−2, 1/2), d3 = (−3, 1/3), ...Thus, the intersection of the given family of sets d is{d1, d2, d3, ...} = Ø. Therefore, the intersection of the given family of sets d is empty.

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The best model to represents the probability situation of a  bag of marbles is given by a bag with 5 compartments, each containing 5 marbles of one of the five colors.

Number of different colors of marbles = 5

Probability of each colored marble is 0.2.

Represent this situation using a multinomial probability distribution.

A multinomial distribution models the probability ,

Observing a certain number of each of several outcomes in a fixed number of independent trials.

The best bag of marbles to model this situation would be a bag with 5 compartments.

Each containing marbles of one of the five colors.

The number of marbles in each compartment would be chosen .

The total number of marbles in the bag is 25 .

And the probability of drawing a marble of each color is 0.2.

One possible bag of marbles that satisfies these conditions is,

5 yellow marbles

5 blue marbles

5 red marbles

5 purple marbles

5 green marbles

With this bag, the probability of drawing a marble of any given color is,

P(Yellow) = 5/25 = 0.2

P(Blue) = 5/25 = 0.2

P(Red) = 5/25 = 0.2

P(Purple) = 5/25 = 0.2

P(Green) = 5/25 = 0.2

Therefore, using the probability a bag with 5 compartments, each containing 5 marbles of one of the five colors, would best model this situation.

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Answer:

37.5%

Step-by-step explanation:

OOF DIS COMPLICATED

I messed up big timeeeeeeeee

A lot of percent problem are very simple by just assuming values, especially in case the answer is also a percentage.

If there are 100 birds, 20% are tagged so 20 are tagged.

Out of the rest 80, 30 should be tagged so that a total of 50% are tagged.

30/80 = 37.5%

(The huge number given is unnecessary, just to make you waste your valuable time. Read the question again to realize that it is not needed.)

The percent of the untagged birds that must be tagged so that half of all birds in the refuge are tagged is 37.5%.

First step

Currently Tagged birds= 54210 ×20/100

Currently Tagged birds=10842

Second  step

Untagged birds=54210 - 10842

Untagged birds=43368

Third step

Untagged birds percentage:

Untagged birds percentage=( 54210/2)-10842/43368

Untagged birds percentage=(27105-10842)/43368

Untagged birds percentage=16263/43368

Untagged birds percentage=0.375×100

Untagged birds percentage=37.5%

Inconclusion the percent of the untagged birds that must be tagged so that half of all birds in the refuge are tagged is 37.5%.

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This is an exponential growth function.

If we look at the number that is raised to the power of x, it is greater than 1. Though there is a fraction within this equation, it is not affected by the exponential.

Hope this helps!! :)

Answer: A

Step-by-step explanation:

Answer:

x = 5

Step-by-step explanation:

If it's a number by itself then that's right cuz JNM and KNL is equal, so u do 4x + 6 = 7x - 21. When u do that, u get x = 5.

Answer:

D. JK ≅ MN

Step-by-step explanation:

i tookthe test

Andy weighs 44lbs. He is to receive 1tsp of medicine for every 15 kg he weighs. How many cc's will he receive? Round to the nSolution:Given,Andy weighs 44 lbs.Convert 44 lbs into kg.1 pound = 0.45359237 kg44 pounds = 19.958 kg1 tsp is given for every 15 kg he weighs.1 tsp = 5 cc (Approximately)Therefore, 19.958 kg will get,(1/15) * 1 tsp = (1/15) * 5 cc = 0.33333 cc (approximately)Therefore, the number of cc's Andy will receive = 0.33333 cc (Approximately)Aspirin 600mg is orderedYou have available gr v tablets. How many tablets will you give? Round to nearest whole numberSolution:Given,Aspirin 600 mg is ordered.You have available gr v tablets.1 gram = 1000 mg600 mg = 0.6 gTherefore, 0.6 g of aspirin is ordered.1 tablet contains gr v= 0.324 g (approx)Therefore, the number of tablets will be given = 0.6 g / 0.324 g ≈ 2The number of tablets to be given = 2 tablets (approximately).The doctor has ordered Tylenol 650mg. You have available Tylenol elixir g g/15cc. How many tsp will you give? Round to nearest whoSolution:Given,Tylenol 650 mg is ordered.Tylenol elixir is available.1 g = 1000 mg1 g / 15 cc = 0.0666667 g/ccTherefore, Tylenol elixir is 0.0666667 g/cc.Hence, the number of tsp will be given is 2 tsp (approx).A 55lb child is to receive liquid ampicillin 5mghkg of body weight. How many cc's will she receive if the ampicillin bottle is labeled 150mg/5 ce? Round to the nearest tenth.Solution:Given,The weight of the child is 55 lbs.1 pound = 0.45359237 kgTherefore, the weight of the child in kg is,55 lbs × 0.45359237 kg = 24.947 kgThe liquid ampicillin is 5 mg/kg.Therefore, the amount of liquid ampicillin will be given,24.947 kg × 5 mg/kg = 124.735 mg = 0.124735 gThe ampicillin bottle is labeled 150 mg/5 cc.Therefore, the amount of liquid to be given,150 mg/5 cc = 30 mg/ccTherefore, the number of cc's of liquid ampicillin to be given,0.124735 g × 1,000 mg/1 g × 1 cc/30 mg = 4.1581 cc ≈ 4.2 ccTherefore, the number of cc's of liquid ampicillin to be given is 4.2 cc (Approximately).

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Answer:

x = 2

Step-by-step explanation:

Given

5x - 4 = - 3x + 12 ( add 3x to both sides )

8x - 4 = 12 ( add 4 to both sides )

8x = 16 ( divide both sides by 8 )

x = 2

Answer:

A=166

Step-by-step explanation:

Length: 5

Width: 7

Height: 4

Shape: Rectangle Prism

Solved for surface area

Formula: A=2(wl+hl+hw)

Answer:A=166

Hope this helps.