the gravitational force acts on all objects in proportion to their mass. neglecting air resistance, why don’t heavy objects fall faster than light ones?

Answers

Answer 1

Answer:

Because in correspondence to the same distance from a mass, the gravitational acceleration is the same for all the bodies. It doesn't depend on the mass of the objects.


Related Questions

water flows through a pipe of diameter 0.8 at a velocity of 2m/s if someone puts a nozzle on the end of the pipe at what speed will the water exit the pipe

Answers

We can use the principle of conservation of mass to find the exit speed of water when a nozzle is attached. We'll need to know the diameter of the nozzle to determine the speed.

Assuming that the diameter of the nozzle is provided as 'd' meters, we can use the equation of continuity:

A1 * v1 = A2 * v2

Here, A1 and v1 represent the initial area and velocity of the pipe, respectively. A2 and v2 represent the area and velocity of the nozzle, respectively.

Step 1: Find the areas of the pipe and nozzle.
A1 = (pi/4) * (0.8)^2
A2 = (pi/4) * d^2

Step 2: Plug the areas and initial velocity into the equation of continuity.
(0.8)^2 * 2 = d^2 * v2

Step 3: Solve for v2, the exit speed of water.
v2 = (0.8^2 * 2) / d^2

The exit speed of water (v2) from the nozzle depends on the diameter (d) of the nozzle and can be calculated using the formula v2 = (0.8^2 * 2) / d^2.

In order to find the exit speed of water when a nozzle is attached to the pipe, you need to know the diameter of the nozzle. By applying the principle of conservation of mass and using the equation of continuity, you can find the exit speed of water as it flows through the nozzle.

To know more about nozzle visit

https://brainly.com/question/30896816

#SPJ11

A long cylinder having a diameter of 2 cm is maintained at 600 °C and has an emissivity of 0.4. Surrounding the cylinder is another long, thin-walled concentric cylinder having a diameter of 6 cm and an emissivity of 0.2 on both the inside and outside surfaces. The assembly is located in a large room having a temperature of 27 °C. Calculate the net radiant energy lost by the 2-cm-diameter cylinder per meter of length. Also calculate the temperature of the 6-cm- diameter cylinder

Answers

The net radiant energy lost by the 2-cm-diameter cylinder per meter of length is X Joules. The temperature of the 6-cm-diameter cylinder is Y °C.

To calculate the net radiant energy lost by the 2-cm-diameter cylinder per meter of length, we need to consider the Stefan-Boltzmann law and the emissivities of both cylinders. The formula for net radiant heat transfer is given:

Q_net = ε1 * σ * A1 * (T1^4 - T2^4)

Where:

- Q_net is the net radiant energy lost per meter of length.

- ε1 is the emissivity of the 2-cm-diameter cylinder.

- σ is the Stefan-Boltzmann constant (5.67 x 10^-8 W/(m^2·K^4)).

- A1 is the surface area of the 2-cm-diameter cylinder.

- T1 is the temperature of the 2-cm-diameter cylinder.

- T2 is the temperature of the surroundings (27 °C).

To calculate the temperature of the 6-cm-diameter cylinder, we can use the formula for the net radiant energy exchanged between the two cylinders:

Q_net = ε1 * σ * A1 * (T1^4 - T2^4) = ε2 * σ * A2 * (T2^4 - T3^4)

Where:

- ε2 is the emissivity of the 6-cm-diameter cylinder.

- A2 is the surface area of the 6-cm-diameter cylinder.

- T3 is the temperature of the 6-cm-diameter cylinder.

By solving these equations simultaneously, we can find the values of Q_net and T3.

To know more about radiant energy click here:

https://brainly.com/question/31870099

#SPJ11

A long cylinder having a diameter of 2 cm is maintained at 600 °C and has an emissivity of 0.4. Surrounding the cylinder is another long, thin-walled concentric cylinder having a diameter of 6 cm and an emissivity of 0.2 on both the inside and outside surfaces. The assembly is located in a large room having a temperature of 27 °C. Calculate the net radiant energy lost by the 2-cm-diameter cylinder per meter of length. Also, calculate the temperature of the 6-cm-diameter cylinder

If 400 g of a (80 g/mol) and 1700 g of b (85 g/mol) are mixed, what is the vapor pressure of b?

Answers

Finally, the vapor pressure of substance b can be determined using Raoult's law: vapor pressure of b = mole fraction of b * vapor pressure of pure b.

However, we need additional information such as the vapor pressure of pure b to calculate the vapor pressure of b accurately.

To determine the vapor pressure of substance b when 400 g of substance a (with a molar mass of 80 g/mol) and 1700 g of substance b (with a molar mass of 85 g/mol) are mixed, we need to consider the mole fractions of the two substances.

First, let's calculate the number of moles for each substance.

For substance a:
moles of a = mass of a / molar mass of a
moles of a = 400 g / 80 g/mol
moles of a = 5 mol

For substance b:
moles of b = mass of b / molar mass of b
moles of b = 1700 g / 85 g/mol
moles of b = 20 mol

Next, we need to calculate the total number of moles in the mixture:
total moles = moles of a + moles of b
total moles = 5 mol + 20 mol
total moles = 25 mol

Now, let's calculate the mole fraction of substance b:
mole fraction of b = moles of b / total moles
mole fraction of b = 20 mol / 25 mol
mole fraction of b = 0.8

Learn more about pressure:

https://brainly.com/question/29341536

#SPJ11

What's this please
w​

What's this pleasew

Answers

The best explanation for the phenomenon shown in the picture is that electrons are moving between the cloud and the three forming a current.

How does lighting occur?

During a storm, the energy inside clouds becomes unstable due to the movement caused by air currents. As a result, clouds become negatively charged while the ground has a positive charge.

This difference causes a current to be created between the surface of the land and the cloud. In this, electrons play a major role as atoms gain or lose electrons in this process.

Learn more about electrons in https://brainly.com/question/12001116
#SPJ1

What is usually true about the relationship between the speed mechanical waves travel and the temperature of the medium?

Answers

you have to change the properties of the medium that the sound waves traveling through

how much time does it take light to travel from the moon to the earth, a distance of 384,000 km? (b) light from the star sirius takes 8.61 years to reach the earth. what is the distance from earth to sirius in kilometers?

Answers

The time taken by light to travel from moon to earth is 1.28 s.

(a) Distance between moon and earth, d = 384,000 km

Speed of light, c = 3 x 10⁸ m/s

Therefore, the time taken to travel from moon to earth,

t = d/c

t = 384,000 x 10³/3 x 10⁸

t = 1.28 s

(b) Time taken by the star sirius to reach the earth, t = 8.61 years

Distance from earth to sirius, d = c x t

d = 3 x 10⁸ x 8.61 x 315.3 x 10⁵

d = 81.44 x 10¹⁵km

To learn more about light years, click:

https://brainly.com/question/1302132

#SPJ4

Q6. A crane lifts a load weighing
3000N through a height of 5m in
10s. What is the power of the
crane?

Answers

Answer:

Crane power  1 500 Watt

Explanation:

Given:

F = 3000 N  - Cargo weigh

H = 5 m - Height

t = 10 s - Time

___________

P - ? Crane power

Work done by crane:

A = F·H = 3000·5 = 15 000 J

Crane power:

P = A / t = 15 000 / 10 = 1 500 W


Arrange these source charges in order from least to greatest magnitude.

A. A, B, C, D
B. B, D, C, A
C. C, A, B, D
D. D, B, A, C

Arrange these source charges in order from least to greatest magnitude.A. A, B, C, DB. B, D, C, AC. C,

Answers

Answer:

option c is the right answer

Answer:

D, B, A, C

Explanation:

The more lines, the greater the charge.

A 25.0 kg box of textbooks rests on a loading ramp that makes an angle α with the horizontal. The coefficient of kinetic friction is 0.250, and the coefficient of static friction is 0.350.
A) As α is increased, find the minimum angle at which the box starts to slip.
B)As this angle, find the acceleration once the box has begun to move
c) at this angle, how fast will the box be moving after it has slid a distance 4.7m along the loading ramp

Answers

(a) As σ is increased, The minimum  angle will be "19.2°".

(b) The acceleration will be "0.91 m/s²"once the box has began to move.

(c) The speed will be "3 m/s" as the box slid a distance 4.7 m along the loading map.

According to the question,

Mass = 25.0 kg

Kinetic friction = 0.25

Coefficient of static friction = 0.35

(a) We know,

⇒ static friction = mg sine

⇒ mg cosine * u = mg sine

then,

tan A = u = 0.35

a = 19.2

Therefore, as α is increased,  the minimum angle at which the box starts to slip is 19.2°.

(b) We know that:

Kinetic friction = mgCos19.2 * 0.25

                        = 2.31m

and,

Net force downwards = mgSin19.2 -  mgCos19.2* 0.25

By substituting the values, we get

                                        = m(3.22-2.31)

                                        = 0.91m/s²

Therefore, As this angle, the acceleration once the box has begun to move at 0.91 m/s².

(c) since the box is sliding at a distance of 4.7 meter:

Thus,

The speed will be:

→ \(v^{2} - u^{2} + 2as\)

\(0 + 2* 0.91* 5\)

= 9.21

\(v = 3m/s\)

Therefore, at this angle, at 3m/s will the box be moving after it has slid a distance 4.7m along the loading ramp

Learn more about acceleration here:

https://brainly.com/question/12550364

#SPJ4


Question 1
What is a Static Load
A. is a load at rest like the weight of an object the structure is supporting or the weight of the structure itself.
B. in between radio stations
C. Aload in Motion
D. A force that is equal

Answers

A. A static load is a load at rest like the weight of an object the structure is supporting or the weight of the structure itself.

Which term best describes how much of a substance is mixed with another substance? a concentration b strength c density d dilute

Answers

Answer:

Dilute

Explanation:

A dilute is a substance mixed with water to make it thinner or weaker.

Answer:

a dilute

Explanation:

What is the equation for momentum (p)?
O A. p = mgh
B. p = my
C. p = ma
O D. p = 127v2

Answers

p=mv. Im guessing theres a typo in choice b.

Please help me, I am following along diligently. V(t) = t^2 -9t+18, with distance, s measured in meters, left or right of 0, and t measured in seconds, with t between 0 and 8 seconds inclusive. The position at time t=0 sec is 1 meter right of 0, that is s(0)= 1Part I: Average velocity over the interval 0 to 8 secondsPart II: The instantaneous velocity and speed at time 5 secsPart III: The time intervals when the particle is moving rightPart IV: The time intervals when the particle is going faster, and slowing downPart V: Total distance the particle has traveled between 0 and 8 seconds

Please help me, I am following along diligently. V(t) = t^2 -9t+18, with distance, s measured in meters,

Answers

Given that the velocity at any time t is

\(v(t)=t^2-9t+18\)

Also, the time interval is from t = 0 to t = 8 seconds

The position at time t = 0 s is s(0) = 1 m towards right of zero.

The initial time is t = 0 s, so the initial velocity will be

\(\begin{gathered} v_i(t=0)=0^2-9\times0+18\text{ } \\ v_i(0)\text{ = 18 m/s} \end{gathered}\)

The final time is t = 8 s, so the final velocity will be

\(\begin{gathered} v_f(t=8)=8^2-9\times8+18 \\ v_f(8)\text{ = 64-72+18} \\ =\text{ 10 m/s} \end{gathered}\)

The average velocity will be

\(\begin{gathered} v_{av}=\frac{v_i+v_f}{2} \\ =\frac{18+10}{2} \\ =14\text{ m/s} \end{gathered}\)

Thus, the average velocity is 14 m/s.

Part II:

The instantaneous velocity at time t =5 s will be

\(\begin{gathered} v(t=5)=5^2-9\times5+18 \\ =25-45+18 \\ =-2\text{ m/s} \end{gathered}\)

The instantaneous speed is the magnitude of instantaneous velocity.

Thus, the instantaneous speed will be 2 m/s.

Part III:

The particle will move towards the right when v(t) > 0

The time intervals will be

\(\begin{gathered} t^2-9t+18>0 \\ t^2-6t-3t+18>0 \\ t(t-6)-3(t-6)>0 \\ (t-6)(t-3)>0 \\ t-6>0\text{ or t>6} \\ t-3>0\text{ ot t>3} \end{gathered}\)

Thus, time intervals are t > 3 and t > 6 when the particle is moving towards the right.

Part IV :

The particle will move faster if the acceleration, a(t) > 0

The particle will slow down if the acceleration, a(t) < 0

So, first, we need to find the acceleration, it can be calculated as

\(\begin{gathered} a(t)=\text{ }\frac{d(v(t))}{dt} \\ =\frac{d(t^2-9t+18)}{dt} \\ =2t-9 \end{gathered}\)

For the particle moving faster,

\(\begin{gathered} a(t)>0 \\ 2t-9>0 \\ 2t-9+9>9+0 \\ 2t>9 \\ \frac{2t}{2}>\frac{9}{2} \\ t>\frac{9}{2} \\ t>4.5\text{ s} \end{gathered}\)

For particle slowing down,

\(\begin{gathered} a(t)<0 \\ 2t-9<0 \\ 2t-9+9<9+0_{} \\ 2t<9 \\ \frac{2t}{2}<\frac{9}{2} \\ t<4.5\text{ s} \end{gathered}\)

The total distance can be calculated as

\(\begin{gathered} s(t)=\int ^8_0v(t)dt \\ =\text{ }\int ^8_0(t^2-9t+18)\mathrm{d}t \\ =\lbrack\frac{t^3}{3}\rbrack^8_0-9\lbrack\frac{t^2}{2}\rbrack^8_0+18\lbrack t^{}\rbrack^8_0 \\ =\frac{1}{3}\lbrack512-0\rbrack-9\lbrack64-0\rbrack+18\lbrack8-0\rbrack \\ =\text{ 170.67-576+144} \\ =-261.33\text{ m} \end{gathered}\)

Here, the negative symbol indicates it is towards the left from zero.

Dimensions of a swimming pool are 34. 0 m by 9. 5 m and its uniform depth is 1. 8 m. The atmospheric pressure is 1. 013×105N/m2. Part A Determine the absolute pressure on the bottom of the swimming pool. Part B Calculate the total force on the bottom of the swimming pool. Part C What will be the pressure against the side of the pool near the bottom?

Answers

For the given swimming pool A) the absolute pressure on the bottom of the swimming pool is 117,640 N/m^2; B) the total force on the bottom of the swimming pool is 35,653,960 N; C) the pressure against the side of the pool near the bottom is  17,640 N/m^2.

The dimensions of a swimming pool are 34.0 m by 9.5 m, and its uniform depth is 1.8 m. The atmospheric pressure is 1.013×10^5 N/m2.

A) Absolute pressure on the bottom of the swimming pool is given by the formula:

P = atmospheric pressure + ρgh

Here, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth of the swimming pool.

Let's use the values given to calculate absolute pressure on the bottom of the swimming pool:

P = 1.013 × 10^5 + (1000 × 9.8 × 1.8)

P = 1.013 × 10^5 + 17640 = 117,640 N/m^2

Therefore, the absolute pressure on the bottom is 117,640 N/m^2

B) The total force on the bottom of the swimming pool is calculated using the formula:

F = pA

Here, p is the pressure on the bottom of the swimming pool, and A is the area of the bottom of the swimming pool.

Let's use the values given to calculate the total force on the bottom of the swimming pool:

F = 117,640 × 34 × 9.5

F = 35,653,960 N

Therefore, the total force on the bottom is 35,653,960 N.

3. Pressure against the side of the pool near the bottom is equal to the hydrostatic pressure, which is given by the formula:

P = ρgh

Here, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth of the swimming pool.

Let's use the values given to calculate the pressure against the side of the pool near the bottom:

P = 1000 × 9.8 × 1.8P = 17,640 N/m^2

Therefore, the pressure against the side of the pool near the bottom is 17,640 N/m^2.

Learn more about Absolute pressure:

https://brainly.com/question/17200230

#SPJ11

What equation links the resultant force with the change in momentum it produces​

Answers

Answer:

Δ p = F net Δ t

A 3.5-kg plastic tank that has a volume of 0.2 m3 is filled with liquid water. assuming the density of water is 1000 kg/m3, determine the weight of the combined system.

Answers

The weight of the combined system = 1,996.3 N

How is the weight of the combined system calculated?

Given,

Mass of the Plastic tank = 3.5 kg

Volume of the liquid water in the tank = 0.2 m³

Density of water = 1000 kg/m³  

Now,

We know

Density = Mass ÷ Volume

Thus,

Mass = Density × Volume

therefore,

Mass of the water in the tank = 1000 × 0.2

= 200 kg

Thus,

The mass of the combined system = 3.5 kg + 200 kg = 203.5 Kg

Also,

Weight in N = Mass × Acceleration due to gravity (g)

and,

g = 9.81 m/s²

Therefore,

The weight of the combined system = 203.5 kg × 9.81 m/s²

= 1,996.3 N

To learn more about density, refer

https://brainly.in/question/2786638

#SPJ4

krypton is named after the greek word that means secret which explains why krypton was most likely given this name

Answers

While the element Krypton was indeed named after the Greek word "kryptos," meaning "hidden" or "secret," the reason for its name is not related to its properties as a secret element.

Why this element was named as Krypton?

Krypton was discovered in 1898 by British chemists Sir William Ramsay and Morris Travers. They had been studying the gas that was produced when they evaporated liquid air, and they found that this gas contained a previously unknown element. Ramsay named the element Krypton because of its ability to hide within the other gases in the air, making it difficult to detect.

So, while the name Krypton does have a connection to the idea of secrecy, it is not because the element itself has any particular properties that relate to secrecy. Rather, it was named for its elusive nature and the difficulty in detecting it.

Learn more about Krypton here:

https://brainly.com/question/2364337

#SPJ1








Certain radioactive material decays in such a way that the mass remaining after \( t \) years is given by the function \( m(t)=460 e^{-0.03 t} \) where \( m(t) \) is measured in grams. (a) Find the ma

Answers

(a) The mass at time t=0 is 460 grams. (b) Rounding to at least one decimal place, the mass last after 45 years is about 119.0 grams.

(a) To find the mass at time t=0, we alternative into the given characteristic:

m(0) = \(460e^(-0.03(0))\)

Since \(e^0\) is the same for at least one, we've got:

m(0) = 460(1) = 460 grams

Therefore, the mass at time t=0 is 460 grams.

(b) To locate the mass final after 45 years, we substitute t=45 into the given function:

m(45) = \(460e^(-0.03(45))\)

Using a calculator or software program, we will evaluate the expression:

m(45) ≈ \(460e^(-1.35\)) ≈ 460(0.2587) ≈ 118.96 grams

Rounding to at least one decimal location, the mass last after 45 years is about 119.0 grams.

To know more about mass,

https://brainly.com/question/30337878

#SPJ4

The correct question is:

"Certain radioactive material decays in such a way that the mass remaining after t years is given by the function m(t)=460e −0.03t where m(t) is measured in grams. (a) Find the mass at time t=0. Your answer is (b) How much of the mass remains after 45 years? Your answer is a Round answer to 1 decimal place."

What..please help me

What..please help me

Answers

Answer:

the answer would be the first choice!

Explanation:

A car on a freeway ramp starts at a velocity of 12.0 m/s. If its average acceleration over 8 s is 3.20 m/s2, what is the velocity at the end of that interval?
A. 13.6 m/s
B. 99.2 m/s
C.25.6 m/s
D. 37.6 m/s

Answers

Answer:  D. 37.6 m/s

Explanation: its D

Just have fun

Have you ever listen to this?? its sooo good

Just have funHave you ever listen to this?? its sooo good

Answers

Answer:

no i haven't. i will

Explanation:


A satellite with a mass of 120 kg fires its rocket thrusters, which give an impulse of 7440 kg-m/s. What was the total change in the velocity of the satellite — that is, what was the total AV?

A. 17 m/s
B. 88 m/s
C. 45 m/s
D. 62 m/s

Answers

From the calculation and the momentum of the body, the velocity is 62 m/s

What is momentum?

The term momentum refers to the product of mass and velocity. Now recall that the rate of change of momentum is equal to the impressed force.

Hence;

7440 kg-m/s = 120 kg * v

v= 7440 kg-m/s/120 kg

v =  62 m/s

Learn more about momentum:https://brainly.com/question/24030570

#SPJ1

A dart with a mass of 0.5kg is thrown at 15m/s and sticks into a 1kg apple hanging
on a string. What is the total momentum of the objects before the collision?

Answers

Answer:

Before the collision:

m v1 = .5 kg * 15 m/s = 7.5 kg-m/s

Incidentally, after the collision

(M + m) v2 = 7.5

v2 = 7.5 / (1 + .5) = 5 m/s

help with the number 2 question​

help with the number 2 question

Answers

Answer:

It is frequently stated that the value of the acceleration due to gravity at the pole is larger than at the equator because the poles are closer to the center of the earth due to the earth's oblateness. ... The measured value is larger because the earth's density is not uniform but increases toward the center.

Answer:

as explained that poles have more gravitational

force (9.83m/s^2) as the poles of earth is nearer to the center because it is flat at poles

but certainly at equator is having less gravitational force (9.78m/s^2) as it is Farr from centre of earth because it is bulgded at equator.

hence, poles have more gravitational force as co.pared to that of equator.

hope this helped you

any confusion the comment it.

Write the calculations of the wavelengths by ° for any two
selected lines from the Balmar series of the spectra of
hydrogen

Answers

The wavelength of the second line in the Balmer series is 304 nm and fourth line is 1093.7 nm.

The Balmer series in the hydrogen spectrum has spectral lines that are in the visible spectrum.

The wavelength is determined using the Balmer-Rydberg equation.

Wavelength for any two selected lines from the Balmer series of the spectra of hydrogen,

1 / λ = R (1/ n₁² - 1/ n₂²)

Where,

λ is the wavelength,

R is the Rydberg constant (1.0974 x 10⁷ m⁻¹),

n₁ and n₂ are integers where n₂ > n₁.

First, let us choose n₁ = 2, which is the second energy level and we will calculate the wavelength of the second line.

n₂ = 3λ = R(1/2² - 1/3²)

λ = R (4/36 - 1/9)

λ = R (1/36) = (1.0974 x 10⁷ m⁻¹) / 36

λ = 3.04 x 10⁻⁷ m = 304 nm

The wavelength of the second line in the Balmer series is 304 nm.

Now, we will calculate the wavelength of the fourth line.

n₂ = 5n₁ = 2λ = R (1/2² - 1/5²)

λ = R (4/100 - 1/25)

λ = R (3/100) = (1.0974 x 10⁷ m⁻¹) / 100 x 3

λ = 1.0937 x 10⁻⁷ m = 1093.7 nm

The wavelength of the fourth line in the Balmer series is 1093.7 nm.

Learn more about Balmer series:

https://brainly.com/question/14767916

#SPJ11

Rising and falling like a gentle waltz, the dandelion seeds _______.

Which phrase is most appropriate for the diction and style of the sentence?

A.
dropped heavily onto the wet ground
B.
fell and scattered across the lawn
C.
danced lightly on the cool breeze
D.
blew like a hurricane across the yard

Answers

B

Explanation:

yeah but I don't know what

An object with smaller mass and an object with a larger mass have the same kinetic energy. Which object has the higher momentum?

Answers

Answer:

object with larger mass

Explanation:

the momentum of an object is directly proportional to its mass. larger mass = more momentum

Answer:

The one with a larger mass should have the higher momentum.

Explanation:

a ball is thrown vertically upward with a speed of 30.0 m/s. how long does it take to reach its highest point?

Answers

It takes the ball 3.06 seconds to reach its highest point

To find how long does it take to reach its highest point

The time it takes for a ball to reach its highest point is given by the equation:

t = v / g

where

t is the time in secondsv is the initial velocity in meters per secondg is the acceleration due to gravity, which is approximately \(9.8 m/s^2\)

In this case, the initial velocity is 30.0 m/s and the acceleration due to gravity is \(9.8 m/s^2\). Therefore, the time it takes for the ball to reach its highest point is:

\(t = 30.0 m/s / 9.8 m/s^2 = 3.06 s\)

Therefore, it takes the ball 3.06 seconds to reach its highest point.

Learn more about acceleration here : brainly.com/question/29223620

#SPJ4

Calculate how many blocks of ice cream each
10 cm long, 10 cm wide and 4 cm thick can
be stored in the compartment of a freezer
measuring 40 cm deep, 40 cm wide and
20 cm high.

Answers

Answer: 80 blocks

Explanation:

Volume of freezer compartment, V1 = (40 X 40 X 20) cm^3

                                                            = 32000cm^3

Volume of ice cream block, V2 = (10 X 10 X 4) = 400 cm^3

No of ice cream blocks = V1/V2 = 32000/400 = 80

according to the avogadros' law, when we keep pressure and temperature constant, what happens to the volume of a gas when we increase the mass of the gas by adding more particles?

Answers

When the mass of a gas is increased by adding more particles while keeping pressure and temperature constant, the volume of the gas will also increase proportionally.

Determine the Avogadro's law?

According to Avogadro's law, at constant temperature and pressure, equal volumes of gases contain an equal number of particles (molecules or atoms). This implies that the volume of a gas is directly proportional to the number of particles present.

When more particles are added to a gas system while maintaining constant temperature and pressure, the total number of particles in the system increases. As a result, the volume of the gas also increases to accommodate the additional particles. The gas expands to occupy a larger space to maintain the same pressure and temperature.

This behavior can be explained by the ideal gas law, which combines Boyle's law, Charles's law, and Avogadro's law. According to the ideal gas law, PV = nRT, where P represents pressure, V represents volume, n represents the number of particles (moles), R is the gas constant, and T represents temperature.

Since, pressure and temperature are constant, increasing the number of particles (n) will cause the volume (V) to increase proportionally.

To know more about temperature, refer here:

https://brainly.com/question/7510619#

#SPJ4

Other Questions
While you are planning for a campaign, you review an organizations website, read past news articles about that organization, and search for PR/Ad case studies that are similar to what that organization seeks to do. What type of research are you most likely doing? Geometric art was very popular in Greece around ______ BCE with drawings on things such as vases.600500700900 Create a campaign of 3-5 visual and/or written radio spot ads which make use of various techniques to send a single clear persuasive message. This message can be as simple as the selling of a product or as complex as the delivery of an important social message.If you choose this option, be sure to include each feature of the form:propaganda techniques such as bandwagon, name-calling, and emotional transferadvertising techniques such as the use of mind tricks, branding, and curiositya consistent and recognizable style that unites the different ads Help me pls !! Show with work thankkkk u sooo much !!!!!! :) What is the difference between algorithm and program? neurotransmitters bind to , which are protein structures on the surface of the neuron cell membrane. a. neural receptors b. cell bodies (a) Consider a quasi-static isothermal expansion or compression of an ideal gas, with initial volume V, and final volume V i f (1) What are three thermodynamics coordinates of an ideal gas system? (15 when events are predicted the author use ____Setting observer Irony Foreshadowing Conflict 7 of 13-(186+3)(93-25) The regression equation was found to be y = 3.00 + 0.475x. In this equation, y stands for number of errors, and x stands for number of hours without sleep. The predicted number of errors for a person who has gone 12 hours without sleep is In which season(s) are the most populations limited in Mono Lake? V. Brian purchases 245 white bouncy balls, 238 yellow bouncy balls, and 84 orange bouncy balls. Hewants to divide them up into bags, so that each bag of balls has at least one of each color in it, andthat each bag has the samanumber of total balls in it, and that there are no balls leftover. What isthe greatest number of balls he can put into each bag?The correct answer is 81 balls. Solve this problem and explain each step of your process so that a 5thgrader will understand. Explain how an outer covering of a section of a cell membrane from the host would protect HIV from attack by the host's immune system PLEASE HELP ME ANSEWR Q3 What is carbon?A. an elementB. a compoundC. anorganism which of these would be most likely to be found in a civilaization The price of a technology stock has risen to $9.79 today. Yesterday's price was $9.72. Find the percentage increase. Round your answer to the nearest tenth of a percent. Instruction Excel Your topic this week is to find a video on developing a trading journal. Outline a trading journal that you feel meets your standards. Explain how the journal works and meets your needs. Paper Much of trading involves what some refer to as the psychology of the market. Your task this week is to write a concise one page paper on what psychological pitfalls traders encounter, some of the reasons why they occur, and how they can be rectified. Be certain to include your references What are three Possible overlaps that can occur during bond formation the kinked-demand curve model of oligopoly question 34 options: assumes a firm's rivals will ignore a price cut but match a price increase. embodies the possibility that changes in unit costs will have no effect on equilibrium price and output. assumes a firm's rivals will match any price change it may initiate. assumes a firm's rivals will ignore any price change it may initiate.