Answer:
Because in correspondence to the same distance from a mass, the gravitational acceleration is the same for all the bodies. It doesn't depend on the mass of the objects.
water flows through a pipe of diameter 0.8 at a velocity of 2m/s if someone puts a nozzle on the end of the pipe at what speed will the water exit the pipe
We can use the principle of conservation of mass to find the exit speed of water when a nozzle is attached. We'll need to know the diameter of the nozzle to determine the speed.
Assuming that the diameter of the nozzle is provided as 'd' meters, we can use the equation of continuity:
A1 * v1 = A2 * v2
Here, A1 and v1 represent the initial area and velocity of the pipe, respectively. A2 and v2 represent the area and velocity of the nozzle, respectively.
Step 1: Find the areas of the pipe and nozzle.
A1 = (pi/4) * (0.8)^2
A2 = (pi/4) * d^2
Step 2: Plug the areas and initial velocity into the equation of continuity.
(0.8)^2 * 2 = d^2 * v2
Step 3: Solve for v2, the exit speed of water.
v2 = (0.8^2 * 2) / d^2
The exit speed of water (v2) from the nozzle depends on the diameter (d) of the nozzle and can be calculated using the formula v2 = (0.8^2 * 2) / d^2.
In order to find the exit speed of water when a nozzle is attached to the pipe, you need to know the diameter of the nozzle. By applying the principle of conservation of mass and using the equation of continuity, you can find the exit speed of water as it flows through the nozzle.
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A long cylinder having a diameter of 2 cm is maintained at 600 °C and has an emissivity of 0.4. Surrounding the cylinder is another long, thin-walled concentric cylinder having a diameter of 6 cm and an emissivity of 0.2 on both the inside and outside surfaces. The assembly is located in a large room having a temperature of 27 °C. Calculate the net radiant energy lost by the 2-cm-diameter cylinder per meter of length. Also calculate the temperature of the 6-cm- diameter cylinder
The net radiant energy lost by the 2-cm-diameter cylinder per meter of length is X Joules. The temperature of the 6-cm-diameter cylinder is Y °C.
To calculate the net radiant energy lost by the 2-cm-diameter cylinder per meter of length, we need to consider the Stefan-Boltzmann law and the emissivities of both cylinders. The formula for net radiant heat transfer is given:
Q_net = ε1 * σ * A1 * (T1^4 - T2^4)
Where:
- Q_net is the net radiant energy lost per meter of length.
- ε1 is the emissivity of the 2-cm-diameter cylinder.
- σ is the Stefan-Boltzmann constant (5.67 x 10^-8 W/(m^2·K^4)).
- A1 is the surface area of the 2-cm-diameter cylinder.
- T1 is the temperature of the 2-cm-diameter cylinder.
- T2 is the temperature of the surroundings (27 °C).
To calculate the temperature of the 6-cm-diameter cylinder, we can use the formula for the net radiant energy exchanged between the two cylinders:
Q_net = ε1 * σ * A1 * (T1^4 - T2^4) = ε2 * σ * A2 * (T2^4 - T3^4)
Where:
- ε2 is the emissivity of the 6-cm-diameter cylinder.
- A2 is the surface area of the 6-cm-diameter cylinder.
- T3 is the temperature of the 6-cm-diameter cylinder.
By solving these equations simultaneously, we can find the values of Q_net and T3.
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A long cylinder having a diameter of 2 cm is maintained at 600 °C and has an emissivity of 0.4. Surrounding the cylinder is another long, thin-walled concentric cylinder having a diameter of 6 cm and an emissivity of 0.2 on both the inside and outside surfaces. The assembly is located in a large room having a temperature of 27 °C. Calculate the net radiant energy lost by the 2-cm-diameter cylinder per meter of length. Also, calculate the temperature of the 6-cm-diameter cylinder
If 400 g of a (80 g/mol) and 1700 g of b (85 g/mol) are mixed, what is the vapor pressure of b?
Finally, the vapor pressure of substance b can be determined using Raoult's law: vapor pressure of b = mole fraction of b * vapor pressure of pure b.
However, we need additional information such as the vapor pressure of pure b to calculate the vapor pressure of b accurately.
To determine the vapor pressure of substance b when 400 g of substance a (with a molar mass of 80 g/mol) and 1700 g of substance b (with a molar mass of 85 g/mol) are mixed, we need to consider the mole fractions of the two substances.
First, let's calculate the number of moles for each substance.
For substance a:
moles of a = mass of a / molar mass of a
moles of a = 400 g / 80 g/mol
moles of a = 5 mol
For substance b:
moles of b = mass of b / molar mass of b
moles of b = 1700 g / 85 g/mol
moles of b = 20 mol
Next, we need to calculate the total number of moles in the mixture:
total moles = moles of a + moles of b
total moles = 5 mol + 20 mol
total moles = 25 mol
Now, let's calculate the mole fraction of substance b:
mole fraction of b = moles of b / total moles
mole fraction of b = 20 mol / 25 mol
mole fraction of b = 0.8
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What's this please
w
The best explanation for the phenomenon shown in the picture is that electrons are moving between the cloud and the three forming a current.
How does lighting occur?During a storm, the energy inside clouds becomes unstable due to the movement caused by air currents. As a result, clouds become negatively charged while the ground has a positive charge.
This difference causes a current to be created between the surface of the land and the cloud. In this, electrons play a major role as atoms gain or lose electrons in this process.
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What is usually true about the relationship between the speed mechanical waves travel and the temperature of the medium?
how much time does it take light to travel from the moon to the earth, a distance of 384,000 km? (b) light from the star sirius takes 8.61 years to reach the earth. what is the distance from earth to sirius in kilometers?
The time taken by light to travel from moon to earth is 1.28 s.
(a) Distance between moon and earth, d = 384,000 km
Speed of light, c = 3 x 10⁸ m/s
Therefore, the time taken to travel from moon to earth,
t = d/c
t = 384,000 x 10³/3 x 10⁸
t = 1.28 s
(b) Time taken by the star sirius to reach the earth, t = 8.61 years
Distance from earth to sirius, d = c x t
d = 3 x 10⁸ x 8.61 x 315.3 x 10⁵
d = 81.44 x 10¹⁵km
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Q6. A crane lifts a load weighing
3000N through a height of 5m in
10s. What is the power of the
crane?
Answer:
Crane power 1 500 Watt
Explanation:
Given:
F = 3000 N - Cargo weigh
H = 5 m - Height
t = 10 s - Time
___________
P - ? Crane power
Work done by crane:
A = F·H = 3000·5 = 15 000 J
Crane power:
P = A / t = 15 000 / 10 = 1 500 W
Arrange these source charges in order from least to greatest magnitude.
A. A, B, C, D
B. B, D, C, A
C. C, A, B, D
D. D, B, A, C
Answer:
option c is the right answer
Answer:
D, B, A, C
Explanation:
The more lines, the greater the charge.
A 25.0 kg box of textbooks rests on a loading ramp that makes an angle α with the horizontal. The coefficient of kinetic friction is 0.250, and the coefficient of static friction is 0.350.
A) As α is increased, find the minimum angle at which the box starts to slip.
B)As this angle, find the acceleration once the box has begun to move
c) at this angle, how fast will the box be moving after it has slid a distance 4.7m along the loading ramp
(a) As σ is increased, The minimum angle will be "19.2°".
(b) The acceleration will be "0.91 m/s²"once the box has began to move.
(c) The speed will be "3 m/s" as the box slid a distance 4.7 m along the loading map.
According to the question,
Mass = 25.0 kg
Kinetic friction = 0.25
Coefficient of static friction = 0.35
(a) We know,
⇒ static friction = mg sine
⇒ mg cosine * u = mg sine
then,
tan A = u = 0.35
a = 19.2
Therefore, as α is increased, the minimum angle at which the box starts to slip is 19.2°.
(b) We know that:
Kinetic friction = mgCos19.2 * 0.25
= 2.31m
and,
Net force downwards = mgSin19.2 - mgCos19.2* 0.25
By substituting the values, we get
= m(3.22-2.31)
= 0.91m/s²
Therefore, As this angle, the acceleration once the box has begun to move at 0.91 m/s².
(c) since the box is sliding at a distance of 4.7 meter:
Thus,
The speed will be:
→ \(v^{2} - u^{2} + 2as\)
\(0 + 2* 0.91* 5\)
= 9.21
\(v = 3m/s\)
Therefore, at this angle, at 3m/s will the box be moving after it has slid a distance 4.7m along the loading ramp
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Question 1
What is a Static Load
A. is a load at rest like the weight of an object the structure is supporting or the weight of the structure itself.
B. in between radio stations
C. Aload in Motion
D. A force that is equal
Which term best describes how much of a substance is mixed with another substance? a concentration b strength c density d dilute
Answer:
Dilute
Explanation:
A dilute is a substance mixed with water to make it thinner or weaker.
Answer:
a dilute
Explanation:
What is the equation for momentum (p)?
O A. p = mgh
B. p = my
C. p = ma
O D. p = 127v2
Please help me, I am following along diligently. V(t) = t^2 -9t+18, with distance, s measured in meters, left or right of 0, and t measured in seconds, with t between 0 and 8 seconds inclusive. The position at time t=0 sec is 1 meter right of 0, that is s(0)= 1Part I: Average velocity over the interval 0 to 8 secondsPart II: The instantaneous velocity and speed at time 5 secsPart III: The time intervals when the particle is moving rightPart IV: The time intervals when the particle is going faster, and slowing downPart V: Total distance the particle has traveled between 0 and 8 seconds
Given that the velocity at any time t is
\(v(t)=t^2-9t+18\)Also, the time interval is from t = 0 to t = 8 seconds
The position at time t = 0 s is s(0) = 1 m towards right of zero.
The initial time is t = 0 s, so the initial velocity will be
\(\begin{gathered} v_i(t=0)=0^2-9\times0+18\text{ } \\ v_i(0)\text{ = 18 m/s} \end{gathered}\)The final time is t = 8 s, so the final velocity will be
\(\begin{gathered} v_f(t=8)=8^2-9\times8+18 \\ v_f(8)\text{ = 64-72+18} \\ =\text{ 10 m/s} \end{gathered}\)The average velocity will be
\(\begin{gathered} v_{av}=\frac{v_i+v_f}{2} \\ =\frac{18+10}{2} \\ =14\text{ m/s} \end{gathered}\)Thus, the average velocity is 14 m/s.
Part II:
The instantaneous velocity at time t =5 s will be
\(\begin{gathered} v(t=5)=5^2-9\times5+18 \\ =25-45+18 \\ =-2\text{ m/s} \end{gathered}\)The instantaneous speed is the magnitude of instantaneous velocity.
Thus, the instantaneous speed will be 2 m/s.
Part III:
The particle will move towards the right when v(t) > 0
The time intervals will be
\(\begin{gathered} t^2-9t+18>0 \\ t^2-6t-3t+18>0 \\ t(t-6)-3(t-6)>0 \\ (t-6)(t-3)>0 \\ t-6>0\text{ or t>6} \\ t-3>0\text{ ot t>3} \end{gathered}\)Thus, time intervals are t > 3 and t > 6 when the particle is moving towards the right.
Part IV :
The particle will move faster if the acceleration, a(t) > 0
The particle will slow down if the acceleration, a(t) < 0
So, first, we need to find the acceleration, it can be calculated as
\(\begin{gathered} a(t)=\text{ }\frac{d(v(t))}{dt} \\ =\frac{d(t^2-9t+18)}{dt} \\ =2t-9 \end{gathered}\)For the particle moving faster,
\(\begin{gathered} a(t)>0 \\ 2t-9>0 \\ 2t-9+9>9+0 \\ 2t>9 \\ \frac{2t}{2}>\frac{9}{2} \\ t>\frac{9}{2} \\ t>4.5\text{ s} \end{gathered}\)For particle slowing down,
\(\begin{gathered} a(t)<0 \\ 2t-9<0 \\ 2t-9+9<9+0_{} \\ 2t<9 \\ \frac{2t}{2}<\frac{9}{2} \\ t<4.5\text{ s} \end{gathered}\)The total distance can be calculated as
\(\begin{gathered} s(t)=\int ^8_0v(t)dt \\ =\text{ }\int ^8_0(t^2-9t+18)\mathrm{d}t \\ =\lbrack\frac{t^3}{3}\rbrack^8_0-9\lbrack\frac{t^2}{2}\rbrack^8_0+18\lbrack t^{}\rbrack^8_0 \\ =\frac{1}{3}\lbrack512-0\rbrack-9\lbrack64-0\rbrack+18\lbrack8-0\rbrack \\ =\text{ 170.67-576+144} \\ =-261.33\text{ m} \end{gathered}\)Here, the negative symbol indicates it is towards the left from zero.
Dimensions of a swimming pool are 34. 0 m by 9. 5 m and its uniform depth is 1. 8 m. The atmospheric pressure is 1. 013×105N/m2. Part A Determine the absolute pressure on the bottom of the swimming pool. Part B Calculate the total force on the bottom of the swimming pool. Part C What will be the pressure against the side of the pool near the bottom?
For the given swimming pool A) the absolute pressure on the bottom of the swimming pool is 117,640 N/m^2; B) the total force on the bottom of the swimming pool is 35,653,960 N; C) the pressure against the side of the pool near the bottom is 17,640 N/m^2.
The dimensions of a swimming pool are 34.0 m by 9.5 m, and its uniform depth is 1.8 m. The atmospheric pressure is 1.013×10^5 N/m2.
A) Absolute pressure on the bottom of the swimming pool is given by the formula:
P = atmospheric pressure + ρgh
Here, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth of the swimming pool.
Let's use the values given to calculate absolute pressure on the bottom of the swimming pool:
P = 1.013 × 10^5 + (1000 × 9.8 × 1.8)
P = 1.013 × 10^5 + 17640 = 117,640 N/m^2
Therefore, the absolute pressure on the bottom is 117,640 N/m^2
B) The total force on the bottom of the swimming pool is calculated using the formula:
F = pA
Here, p is the pressure on the bottom of the swimming pool, and A is the area of the bottom of the swimming pool.
Let's use the values given to calculate the total force on the bottom of the swimming pool:
F = 117,640 × 34 × 9.5
F = 35,653,960 N
Therefore, the total force on the bottom is 35,653,960 N.
3. Pressure against the side of the pool near the bottom is equal to the hydrostatic pressure, which is given by the formula:
P = ρgh
Here, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth of the swimming pool.
Let's use the values given to calculate the pressure against the side of the pool near the bottom:
P = 1000 × 9.8 × 1.8P = 17,640 N/m^2
Therefore, the pressure against the side of the pool near the bottom is 17,640 N/m^2.
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What equation links the resultant force with the change in momentum it produces
Answer:
Δ p = F net Δ t
A 3.5-kg plastic tank that has a volume of 0.2 m3 is filled with liquid water. assuming the density of water is 1000 kg/m3, determine the weight of the combined system.
The weight of the combined system = 1,996.3 N
How is the weight of the combined system calculated?
Given,
Mass of the Plastic tank = 3.5 kg
Volume of the liquid water in the tank = 0.2 m³
Density of water = 1000 kg/m³
Now,
We know
Density = Mass ÷ Volume
Thus,
Mass = Density × Volume
therefore,
Mass of the water in the tank = 1000 × 0.2
= 200 kg
Thus,
The mass of the combined system = 3.5 kg + 200 kg = 203.5 Kg
Also,
Weight in N = Mass × Acceleration due to gravity (g)
and,
g = 9.81 m/s²
Therefore,
The weight of the combined system = 203.5 kg × 9.81 m/s²
= 1,996.3 N
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krypton is named after the greek word that means secret which explains why krypton was most likely given this name
While the element Krypton was indeed named after the Greek word "kryptos," meaning "hidden" or "secret," the reason for its name is not related to its properties as a secret element.
Why this element was named as Krypton?Krypton was discovered in 1898 by British chemists Sir William Ramsay and Morris Travers. They had been studying the gas that was produced when they evaporated liquid air, and they found that this gas contained a previously unknown element. Ramsay named the element Krypton because of its ability to hide within the other gases in the air, making it difficult to detect.
So, while the name Krypton does have a connection to the idea of secrecy, it is not because the element itself has any particular properties that relate to secrecy. Rather, it was named for its elusive nature and the difficulty in detecting it.
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Certain radioactive material decays in such a way that the mass remaining after \( t \) years is given by the function \( m(t)=460 e^{-0.03 t} \) where \( m(t) \) is measured in grams. (a) Find the ma
(a) The mass at time t=0 is 460 grams. (b) Rounding to at least one decimal place, the mass last after 45 years is about 119.0 grams.
(a) To find the mass at time t=0, we alternative into the given characteristic:
m(0) = \(460e^(-0.03(0))\)
Since \(e^0\) is the same for at least one, we've got:
m(0) = 460(1) = 460 grams
Therefore, the mass at time t=0 is 460 grams.
(b) To locate the mass final after 45 years, we substitute t=45 into the given function:
m(45) = \(460e^(-0.03(45))\)
Using a calculator or software program, we will evaluate the expression:
m(45) ≈ \(460e^(-1.35\)) ≈ 460(0.2587) ≈ 118.96 grams
Rounding to at least one decimal location, the mass last after 45 years is about 119.0 grams.
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The correct question is:
"Certain radioactive material decays in such a way that the mass remaining after t years is given by the function m(t)=460e −0.03t where m(t) is measured in grams. (a) Find the mass at time t=0. Your answer is (b) How much of the mass remains after 45 years? Your answer is a Round answer to 1 decimal place."
What..please help me
Answer:
the answer would be the first choice!
Explanation:
A car on a freeway ramp starts at a velocity of 12.0 m/s. If its average acceleration over 8 s is 3.20 m/s2, what is the velocity at the end of that interval?
A. 13.6 m/s
B. 99.2 m/s
C.25.6 m/s
D. 37.6 m/s
Answer: D. 37.6 m/s
Explanation: its D
Just have fun
Have you ever listen to this?? its sooo good
Answer:
no i haven't. i will
Explanation:
A satellite with a mass of 120 kg fires its rocket thrusters, which give an impulse of 7440 kg-m/s. What was the total change in the velocity of the satellite — that is, what was the total AV?
A. 17 m/s
B. 88 m/s
C. 45 m/s
D. 62 m/s
From the calculation and the momentum of the body, the velocity is 62 m/s
What is momentum?The term momentum refers to the product of mass and velocity. Now recall that the rate of change of momentum is equal to the impressed force.
Hence;
7440 kg-m/s = 120 kg * v
v= 7440 kg-m/s/120 kg
v = 62 m/s
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A dart with a mass of 0.5kg is thrown at 15m/s and sticks into a 1kg apple hanging
on a string. What is the total momentum of the objects before the collision?
Answer:
Before the collision:
m v1 = .5 kg * 15 m/s = 7.5 kg-m/s
Incidentally, after the collision
(M + m) v2 = 7.5
v2 = 7.5 / (1 + .5) = 5 m/s
help with the number 2 question
Answer:
It is frequently stated that the value of the acceleration due to gravity at the pole is larger than at the equator because the poles are closer to the center of the earth due to the earth's oblateness. ... The measured value is larger because the earth's density is not uniform but increases toward the center.
Answer:
as explained that poles have more gravitational
force (9.83m/s^2) as the poles of earth is nearer to the center because it is flat at poles
but certainly at equator is having less gravitational force (9.78m/s^2) as it is Farr from centre of earth because it is bulgded at equator.
hence, poles have more gravitational force as co.pared to that of equator.
hope this helped you
any confusion the comment it.
Write the calculations of the wavelengths by ° for any two
selected lines from the Balmar series of the spectra of
hydrogen
The wavelength of the second line in the Balmer series is 304 nm and fourth line is 1093.7 nm.
The Balmer series in the hydrogen spectrum has spectral lines that are in the visible spectrum.
The wavelength is determined using the Balmer-Rydberg equation.
Wavelength for any two selected lines from the Balmer series of the spectra of hydrogen,
1 / λ = R (1/ n₁² - 1/ n₂²)
Where,
λ is the wavelength,
R is the Rydberg constant (1.0974 x 10⁷ m⁻¹),
n₁ and n₂ are integers where n₂ > n₁.
First, let us choose n₁ = 2, which is the second energy level and we will calculate the wavelength of the second line.
n₂ = 3λ = R(1/2² - 1/3²)
λ = R (4/36 - 1/9)
λ = R (1/36) = (1.0974 x 10⁷ m⁻¹) / 36
λ = 3.04 x 10⁻⁷ m = 304 nm
The wavelength of the second line in the Balmer series is 304 nm.
Now, we will calculate the wavelength of the fourth line.
n₂ = 5n₁ = 2λ = R (1/2² - 1/5²)
λ = R (4/100 - 1/25)
λ = R (3/100) = (1.0974 x 10⁷ m⁻¹) / 100 x 3
λ = 1.0937 x 10⁻⁷ m = 1093.7 nm
The wavelength of the fourth line in the Balmer series is 1093.7 nm.
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Rising and falling like a gentle waltz, the dandelion seeds _______.
Which phrase is most appropriate for the diction and style of the sentence?
A.
dropped heavily onto the wet ground
B.
fell and scattered across the lawn
C.
danced lightly on the cool breeze
D.
blew like a hurricane across the yard
B
Explanation:
yeah but I don't know what
An object with smaller mass and an object with a larger mass have the same kinetic energy. Which object has the higher momentum?
Answer:
object with larger mass
Explanation:
the momentum of an object is directly proportional to its mass. larger mass = more momentum
Answer:
The one with a larger mass should have the higher momentum.
Explanation:
a ball is thrown vertically upward with a speed of 30.0 m/s. how long does it take to reach its highest point?
It takes the ball 3.06 seconds to reach its highest point
To find how long does it take to reach its highest point
The time it takes for a ball to reach its highest point is given by the equation:
t = v / g
where
t is the time in secondsv is the initial velocity in meters per secondg is the acceleration due to gravity, which is approximately \(9.8 m/s^2\)In this case, the initial velocity is 30.0 m/s and the acceleration due to gravity is \(9.8 m/s^2\). Therefore, the time it takes for the ball to reach its highest point is:
\(t = 30.0 m/s / 9.8 m/s^2 = 3.06 s\)
Therefore, it takes the ball 3.06 seconds to reach its highest point.
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Calculate how many blocks of ice cream each
10 cm long, 10 cm wide and 4 cm thick can
be stored in the compartment of a freezer
measuring 40 cm deep, 40 cm wide and
20 cm high.
Answer: 80 blocks
Explanation:
Volume of freezer compartment, V1 = (40 X 40 X 20) cm^3
= 32000cm^3
Volume of ice cream block, V2 = (10 X 10 X 4) = 400 cm^3
No of ice cream blocks = V1/V2 = 32000/400 = 80
according to the avogadros' law, when we keep pressure and temperature constant, what happens to the volume of a gas when we increase the mass of the gas by adding more particles?
When the mass of a gas is increased by adding more particles while keeping pressure and temperature constant, the volume of the gas will also increase proportionally.
Determine the Avogadro's law?According to Avogadro's law, at constant temperature and pressure, equal volumes of gases contain an equal number of particles (molecules or atoms). This implies that the volume of a gas is directly proportional to the number of particles present.
When more particles are added to a gas system while maintaining constant temperature and pressure, the total number of particles in the system increases. As a result, the volume of the gas also increases to accommodate the additional particles. The gas expands to occupy a larger space to maintain the same pressure and temperature.
This behavior can be explained by the ideal gas law, which combines Boyle's law, Charles's law, and Avogadro's law. According to the ideal gas law, PV = nRT, where P represents pressure, V represents volume, n represents the number of particles (moles), R is the gas constant, and T represents temperature.
Since, pressure and temperature are constant, increasing the number of particles (n) will cause the volume (V) to increase proportionally.
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