Answer:
How far away the objects are from each other
How are the concentrations of hydrogen ions and hydroxide ions related in an aqueous solution?
Arrhenius acid increases the concentration of hydrogen ion in an aqueous solution and Arrhenius base increases the concentration of hydroxide ion in an aqueous solution.
What is Arrhenius Acid and Base ?Arrhenius acid dissociates in aqueous solution to form hydrogen ion. In aqueous solution Arrhenius acid increases the concentration of hydrogen ions.
Arrhenius base dissociates in aqueous solution to form hydroxide ion. In aqueous solution Arrhenius base increases the concentration of hydroxide ions.
Hydrogen Ion \((H^+)\) and Hydroxide Ion \((OH^{-})\).In aqueous solution of hydroxide ions bases dissociates. Greater the concentration of base means greater the concentration of hydroxide ion. If hydroxide ion concentration is more then pH will be less.
Thus, we can say that Arrhenius acid increases the concentration of hydrogen ion in an aqueous solution and Arrhenius base increases the concentration of hydroxide ion in an aqueous solution.
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.Refer to the values in Figure 12.9 in the textbook and calculate the electronegativity difference for each of the following bonds.
1. Si−C
2. P−C
3. S−O
4. C−O
The electronegativity differences for the given bonds are 1. Si-C: 0.7, 2. P-C: 0.4, 3. S-O: 1.0, and 4. C-O: 1.0.
To calculate the electronegativity difference for each of the given bonds, we need to subtract the electronegativity of the bonded atoms. Using the values in Figure 12.9 of the textbook, the electronegativity values for the elements are as follows:
1. Si-C:
The electronegativity of Si is 1.8, and the electronegativity of C is 2.5.
Electronegativity difference = Electronegativity of C - Electronegativity of Si = 2.5 - 1.8 = 0.7.
2. P-C:
The electronegativity of P is 2.1, and the electronegativity of C is 2.5.
Electronegativity difference = Electronegativity of C - Electronegativity of P = 2.5 - 2.1 = 0.4.
3. S-O:
The electronegativity of S is 2.5, and the electronegativity of O is 3.5.
Electronegativity difference = Electronegativity of O - Electronegativity of S = 3.5 - 2.5 = 1.0.
4. C-O:
The electronegativity of C is 2.5, and the electronegativity of O is 3.5.
Electronegativity difference = Electronegativity of O - Electronegativity of C = 3.5 - 2.5 = 1.0.
Therefore, the electronegativity differences for the given bonds are:
1. Si-C: 0.7
2. P-C: 0.4
3. S-O: 1.0
4. C-O: 1.0.
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Name the following covalent molecules:
SeF
Answer:
do you mean DeF?
Explanation:
HELP PLEASE CHEMISTRY
a. There are 0.1596 moles of NaCl in 0.3 L of NaCl stock solution.
b. There are 0.1596 moles of NaCl in 2.1 L of NaCl dilute solution.
c. The concentration of NaCl in the final solution is 0.076 M.
Give a brief account on molarity.Molarity is said to be the number of moles of solute per liter of solution. For example, when salt is dissolved in water, the salt becomes the solute and the water becomes the solution. Since, one mole of sodium chloride weighs 58.44 grams and dissolving 58.44 grams of NaCl in 1 liter of water makes a 1 molar solution, abbreviated as 1M.
c. Let's calculate the concentration of NaCl in the final solution:
M₁V₁ = M₂V₂
M₁ = Initial concentration of NaCl (0.532 M)
V₁ = Initial volume of NaCl (0.3 L)
M₂ = Final concentration of NaCl
V₂ = Initial volume of NaCl (2.0 L)
0.532 × 0.3 = M₂ × 2.1
M₂ = (0.532 × 0.3)/2.1
M₂ = 0.076 M
a. To calculate number of moles in 0.3 L of NaCl stock solution.
Molarity = Mole of solute/Volume of solution
0.532 = Mole of NaCl/0.3
Mole of NaCl = 0.532×0.3
Mole of NaCl = 0.1596 mol
b. To calculate number of moles in 2.1 L of NaCl solution.
0.076 = Mole of NaCl/2.1
Mole of NaCl = 0.076×2.1
Mole of NaCl = 0.1596 mol
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Calculate the solubility at 25°C of AgBr in pure water and in 0.35 M ammonia (NH). You'll probably find some useful data in the ALEKS Data resource. Round your answer to 2 significant digits. Solubility in pure water: Solubility in 0.35 M ammonia:
a. The solubility of AgBr in pure water at 25°C is 0.00023 mol/L.
b. the solubility of AgBr in 0.35 M ammonia at 25°C is 5.10 x 10⁻¹² mol/L
To calculate the solubility of AgBr in 0.35 M ammonia, we first need to write the equilibrium equation for the reaction between AgBr and ammonia:
AgBr(s) + 2NH₃(aq) ⇌ [Ag(NH₃)₂]⁺(aq) + Br⁻(aq)
The Kf (formation constant) for [Ag(NH₃)₂]⁺ is 1.5 x 107.
The expression for the solubility product, Ksp, is:
Ksp = [Ag⁺][Br⁻] = [Ag(NH₃)₂]⁺][Br⁻]
We can set up an ICE table to determine the concentrations of each species at equilibrium:
Initial:
[AgBr] = x
[NH₃] = 0.35 M
[Ag⁺] = 0
[Br⁻] = 0
Change:
[AgBr] = -x
[NH₃] = -2x
[Ag⁺] = +x
[Br⁻] = +x
Equilibrium:
[AgBr] = (0.00023 - x) mol/L
[NH₃] = (0.35 - 2x) M
[Ag⁺] = x mol/L
[Br⁻] = x mol/L
[Ag(NH₃)₂]⁺] = 1.5 x 107 x mol/L
Substituting these concentrations into the Ksp expression, we get:
Ksp = (1.5 x 107 x)(x) = 2.04 x 10⁻¹³
Solving for x, we get:
x = 5.10 x 10⁻¹² mol/L
Therefore, the solubility of AgBr in 0.35 M ammonia at 25°C is 5.10 x 10⁻¹² mol/L.
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Use for questions 1-4
Zn + 2HCl → ZnCl2 + H2
1) If 0.8 moles of Zn are used,
how many moles of HCl are
required?
2) If 3.5 moles of Zn are used,
how many moles of HCl are
required?
3) If 4.8 moles of HCl are used,
how many moles of H, are
produced?
4) If 0.48 moles of ZnCl, are
produced, how many moles of
HCl are needed?
Answer: 1) 1.6 moles of HCl
2) 7.0 moles of HCl
3) 2.4 moles of hydrogen
4) 0.96 moles of HCl
Explanation:
The balanced chemical equation is:
\(Zn+2HCl\rightarrow ZnCl_2+H_2\)
According to stoichiometry :
1 mole of \(Zn\) require = 2 moles of \(HCl\)
0.8 moles of \(Zn\) will require=\(\frac{2}{1}\times 0.8=1.6moles\) of \(HCl\)
3.5 moles of \(Zn\) will require=\(\frac{2}{1}\times 3.5=7.0moles\) of \(HCl\)
According to stoichiometry :
2 moles of \(HCl\) produce = 1 mole of \(H_2\)
4.8 moles of \(HCl\) will require=\(\frac{1}{2}\times 4.8=2.4moles\) of \(H_2\)
According to stoichiometry :
1 mole of \(ZnCl_2\) are produced by = 2 moles of \(HCl\)
0.48 moles of \(ZnCl_2\) are produced by =\(\frac{2}{1}\times 0.48=0.96moles\) of \(HCl\)
A 57.9 gram mass has a volume of 3 cm 3. What is the density of the mass?
Answer:
The answer is 19.3 g/cm³Explanation:
The density of a substance can be found by using the formula
\(density = \frac{mass}{volume}\\\)
From the question
mass = 57.9 g
volume = 3 cm³
We have
\(density = \frac{57.9}{3} \\ \)
We have the final answer as
19.3 g/cm³Hope this helps you
What kinds of bonds can be found in soap?
Answer:
The chemistry of a soap molecule is such that one end of it has a polar covalent bond, while the tail is make up of carbon and hydrogen atoms that have non-polar bonds.
Identify the total number of molecules in the chemical formula: 6CH4 a 6 b 10 c 24 d 30
Answer: A.6
Explanation:
The total number of molecules in the chemical formula is 6
What is a molecule?
Molecules are the smallest particle of a substance that has all of the physical and chemical properties of that substance. Molecules are made up of one or more atoms.
The correct form of question will be:-6 molecule of methane CH₄
6CH4
a) 6 c) 10 c) 24 d) 30⇒ Number of aton of carbon is 6
⇒Number of atom of hydrogen is 24
⇒Total number of atom is 30
What is an atom ?
An atom is a particle of matter that neither be created nor be destroyed. An atom consists of a central nucleus that is usually surrounded by one or more electrons. Each electron is negatively charged. The nucleus is positively charged, and contains one or more relatively heavy particles known as protons and neutrons.
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question is below! please tell me more than the equation.
To convert the astronomical units (AU) into miles, we can use the conversion factor of 1 AU = 93,000,000 miles.
The distances in miles for the given planets and asteroid belt are:
Mercury: 36,015,000 miles (0.387 x 93,000,000)
Venus: 67,146,000 miles (0.722 x 93,000,000)
Earth: 93,000,000 miles (1 x 93,000,000)
Mars: 141,960,000 miles (1.52 x 93,000,000)
Asteroid Belt: 241,800,000 miles (2.6 x 93,000,000)
Jupiter: 484,560,000 miles (5.2 x 93,000,000)
Saturn: 893,940,000 miles (9.58 x 93,000,000)
Uranus: 1,789,440,000 miles (19.2 x 93,000,000)
Neptune: 2,796,300,000 miles (30.1 x 93,000,000)
Pluto: 3,679,250,000 miles (39.5 x 93,000,000)
Therefore, the distances in miles for the given planets and asteroid belt are as above.
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Find the thickness of the material:
This latest alien sample is crazy thin and very tough. After it was cut into something very rectangle-ish with sides of 54.2 cm and 12.3 cm. The calculated density of the material is 1.3 g/cm^3. The mass was found to be 11.4 grams.
The calculated density of the material is 1.3 g/cm³. The mass was found to be 11.4 grams. The thickness of the material is 14.82 cm³.
What is thickness?Thickness is defined as a dimension, typically the smallest of the three, that describes the separation between two surfaces of an item. There are various layers of fabric that make up a thickness. While density considers how thin or thick strands are collectively, as a group, thickness relates to the breadth of a single hair strand.
Density can be expressed as
Density = mass / volume
Volume = Thickness
So, density = mass / thickness
Thickness = Density x mass
Thickness = 1.3 g/cm³ x 11.4 g
Thickness = 14.82 cm³
Thus, the calculated density of the material is 1.3 g/cm³. The mass was found to be 11.4 grams. The thickness of the material is 14.82 cm³.
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28.
How many electrons are being exchanged in the balanced redox equation
Co + 3Ag+→ Co3+ + 3Ag?
4
3
2
1
Answer:
The Answer is 3.
Explanation:
In the balanced redox equation Co + 3Ag⁺ → Co³⁺ + 3Ag, the number of electrons being exchanged can be determined by comparing the oxidation states of the elements involved in the reaction.
The oxidation state of cobalt (Co) increases from 0 to +3, indicating a loss of electrons. On the other hand, the oxidation state of silver (Ag) decreases from +1 to 0, indicating a gain of electrons.
Since each silver ion (Ag⁺) gains one electron and there are three silver ions involved, a total of 3 electrons are gained by silver. Similarly, since cobalt (Co) loses 3 electrons, the number of electrons exchanged is also 3.
Therefore, the correct answer is 3.
4. An object with a mass of 6.0 kg accelerates 4.0 m/s2 when an unknown force is applied to it. What is the amount of the force?
Answer:
The answer is 24 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × accelerationFrom the question we have
force = 6 × 4
We have the final answer as
24 NHope this helps you
Which of the following reactions is NOT properly classified?
(A) Synthesis - MgO + CO2 → MgCO3
(8) Decomposition - 2 Fe(OH)3 → Fe2O3 + 3 H2O
(c) Combustion - CO2 + 2 H2O → CH4 + 2 02
(D) Synthesis – 2 Na + Cl2 → 2 NaCl
Calculate the average atomic mass of unknown element X. You determine that isotope 127X makes up 80%, isotope 126X makes up 17%, and isotope 128X makes up 3%.
A. 127.10 amu
B. 126.86 amu
C. 127.54 amu
D. 126.20 amu
Answer:
Option B. 126.68 amu
Explanation:
The following data were obtained from the question:
Isotope A (¹²⁷X):
Mass of A = 127
Abundance (A%) = 80%
Isotope B (¹²⁶X):
Mass of B = 126
Abundance (B%) = 17%
Isotope C (¹²⁸X):
Mass of C = 128
Abundance (C%) = 3%
Average atomic mass of element X =.?
Th4 average atomic mass of X can be obtained as follow:
Average atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100] + [(Mass of C × C%)/100]
= [(127 × 80)/100] + [(126 × 17)/100] + [(128 × 3)/100]
= 101.6 + 21.42 + 3.84
= 126.68 amu
Therefore, the average atomic mass of X is 126.68 amu
a particle starting from rest moves with constant acceleration. if it takes 5. 0 s to reach the speed 18. 0 km/h find (a) the average velocity during this period, and (b) the distance travelled by the particle during this period
(a) The average velocity during the period is 2.5 m/s. (b) The distance travelled by the particle during the period is 12.5 m.
It is given that a particle starting from rest moves with constant acceleration and it takes 5.0s to reach the speed 18.0 km/h.
(a) To find the average velocity, we first need to convert the final speed to m/s:
18.0 km/h * (1000 m/km) / (3600 s/h) = 5.0 m/s.
The average velocity is the average of the initial and final velocities:
(0 m/s + 5.0 m/s) / 2 = 2.5 m/s.
(b) To find the distance traveled, we can use the formula
d = (v_initial + v_final) * t / 2.
Plugging in our values, we get:
d = (0 m/s + 5.0 m/s) * 5.0 s / 2 = 2.5 m/s * 5.0 s = 12.5 m.
So, during this period, the average velocity is 2.5 m/s, and the distance traveled is 12.5 m.
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.Which of the following are characteristics of a gas? It moves slowly. It has a fixed volume. It can be compressed. It has a fixed shape.
Answer:
It has a fixed volume it can also be compressed
Explanation:
1: A gases molecules don't move slow because they are not solid and are not compacted.
Answer:
It can be compressed
Explanation:
The Properties of Gases. Gases have three characteristic properties: (1) they are easy to compress, (2) they expand to fill their containers, and (3) they occupy far more space than the liquids or solids from which they form.
19 What is the "skin" of the cell?
Answer:
d cell membrane:)
Explanation:
Which formula contains 2 non metals
Answer:
The answer is SiO2
Explanation:
Because nonmetals are those who gain electrons and form ve ions
Can someone help me!!!!!
Answer:
Can u somehow make it bigger please?
Explanation:
Write the atomic number of the element present in the third period and seventeenth.
The element present in the third period and seventeenth group of the periodic table is chlorine (Cl).
Here is a step-by-step explanation:
1. Periods in the periodic table represent the number of electron shells or energy levels an atom has.
2. The third period corresponds to the third electron shell.
3. Groups in the periodic table represent the number of valence electrons an atom has.
4. The seventeenth group, also known as Group 17 or Group VIIA, is the halogens group.
5. Elements in the halogens group have 7 valence electrons.
6. Chlorine (Cl) is located in the seventeenth group, and it has 7 valence electrons.
7. Therefore, chlorine (Cl) is the element present in the third period and seventeenth group.
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6. Describe how the orders with respect to two different reactants might be determined in a sample experiment where a
gas is produced as a result of mixing two solutions together. Carefully describe the measurements that should be
recorded and suggest a method of measuring the rate of the reaction.
A reaction rate can be calculated using a pretty simple procedure.A reaction rate must be calculated from tabulated values or discovered empirically because it depends on change over time.
Describe how a sample experiment might be used to determine the ordering with respect to two different reactants?
It is feasible to determine the reaction rate algebraically or graphically using the data that was obtained.The general advice and examples for calculating reaction rates are provided below.A stopwatch or any other timekeeper will do to measure time change.But more difficult procedures are needed to determine how much the reactants or products' concentrations have changed.There are typically two ways to acquire a change in concentration in a system:by keeping track of the reactant's gradual depletion over time, orBy keeping track of how a product changes over time There is no difference in the overall reaction whether an experimenter watches the reagents or products.However, there is a sign difference between the two speeds since reagents decrease and products grow during the reaction.As the reaction progresses, the reagent concentration falls, yielding a negative number for the concentration change.On the other side, the goods' concentration improves over time, producing a positive value.In order to solve an issue, set the overall rate of the reaction equal to the negative of a reagent's disappearance rate because it is customary to describe the rate of reaction as a positive number.The stoichiometric coefficients have an impact on the overall rate as well. It is important to note that by utilizing the various physical or chemical features (such as phase difference, reduction potential, etc.) of the reagents or products involved in the reaction, the process of determining the concentration can be significantly sped up.We have underlined how crucial it is to consider the reaction's sign in order to have a positive reaction rate.We shall now discuss the significance of stoichiometric coefficients.Depending on the product or reagent chosen to be monitored, a reaction rate can be reported somewhat differently.Given a response:aA+bB→cC+dD
(14.2.1)
Also possible to write as:
response rate = 1a
(A's disappearance rate)
= −1b
(B's disappearance rate
= 1c
(C's rate of formation)
= 1d\s(rate of production of D) (rate of formation of D)
There is only one average rate of reaction, despite the possibility that the concentrations of A, B, C, and D may all fluctuate at various rates.Select any rate and divide it by the stoichiometric coefficient to obtain this special rate.When the reaction's formula is as followsCR1R1+⋯+CRnRn→CP1P1+⋯+CPnPn(14.2.3)The following is the general example of the distinct average rate of reaction
response rate = 1CR1[R1
Δt=⋯=−1CRnΔ[R
Δt=1CP1Δ[P1]
Δt=⋯=1CPnΔ[Pn]
Δt
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You recrystallize 2.1 g of an impure sample and recover 0.98 g. What is your percent recovery rounded to the tenths place
Answer:
c
Explanation:
The percent yield or percent recovery after recrystallization of the sample is 46.67%
What is percent yield?Percent yield is defined as the ratio of actual yield to the theoretical yield multiplied by 100. If the actual and theoretical yield are same then the percent yield is 100%.If actual yield is less than the theoretical yield then the percent yield is less than 100%.Reason of this condition arising is the incompletion of reaction or loss of sample during recovery process.
In cases where percent yield is over 100% it indicates that more sample is recovered than the predicted amount.This condition arises when there are other simultaneous reactions taking place leading to the formation of product. It can also arise if there is incomplete removal of impurities from the sample .
In the given example,percent yield or percent recovery is calculated as,
percent yield=recovered yield/recrystallized yield×100
=0.98/2.1×100=46.67%
Hence, the percent yield or recovery is 46.67%.
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Explain the effects on the equilibrium of the above reaction with:
1. i) Increasing temperature
2. ii) Increasing pressure
3. iii) Decreasing the concentration of hydrobromic acid (HBr)
4. iv) Increasing the concentration of methane (CH4)
5. v) Adding a catalyst
The reaction referred to here is the synthesis of methyl bromide (CH3Br) from methane (CH4) and hydrobromic acid (HBr):CH4 + HBr ⇌ CH3Br + H2
1. Increasing temperature: According to Le Chatelier's principle, increasing the temperature of an exothermic reaction shifts the equilibrium position in the direction that consumes heat. In this case, the forward reaction is exothermic, so an increase in temperature would shift the equilibrium position to the left, favoring the reverse reaction, and decreasing the yield of CH3Br.
2. Increasing pressure: Changing the pressure of a reaction mixture can affect the equilibrium position of a reaction only if the reaction involves a change in the number of moles of gas. In this reaction, the number of moles of gas is constant before and after the reaction, so changing the pressure would have no effect on the equilibrium position.
3. Decreasing the concentration of hydrobromic acid (HBr): Decreasing the concentration of a reactant in a reaction shifts the equilibrium position in the direction that replenishes the lost reactant. In this case, decreasing the concentration of HBr would shift the equilibrium position to the left, favouring the reverse reaction, and decreasing the yield of CH3Br.
4. Increasing the concentration of methane (CH4): Increasing the concentration of a reactant in a reaction shifts the equilibrium position in the direction that consumes the added reactant. In this case, increasing the concentration of CH4 would shift the equilibrium position to the right, favoring the forward reaction, and increasing the yield of CH3Br.
5. Adding a catalyst: A catalyst increases the rate of both the forward and reverse reactions, but it does not affect the position of the equilibrium. Therefore, adding a catalyst would increase the rate at which CH3Br is produced but would not affect the yield of CH3Br at equilibrium.
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6. Perform the following calculations and report each answer to the correct number of significant figures: a. 162.1 g + 38.73 g + 1.554 g
b. 21.9 m + 6.34 m + 157 m
c. 0.004 dm + 0.12508 dm
d. 2.0 L + 2.4L + 2.51L
e. .025 mol + .0267 mol + .00287 mol
f. 9.88 s-7.2 s
g. 44.7 kg - 2.7 kg
h. 20 L - 20.0 L i. 2.89g - 3.00g
j. 8.894 mL - 9.23 mL
Answer:
Explanation:
a) 202.4 g
b) 185.24 m
c) 0.13 dm
d) 6.91 L
e)0.0546 mol
f) 2.7 s
g) 42kg
h) 0
i) -0.11 g
j) -0.34 mL
17. the binding of the amino acid in aminoacyl-trna is a (n) a. amide c. hemiacetal b. ester d. ether
The binding of the amino acid in aminoacyl-tRNA involves the formation of an ester bond. Option b
Aminoacyl-tRNA is a complex molecule that plays a crucial role in protein synthesis. It consists of a tRNA molecule covalently linked to an amino acid. The amino acid is attached to the 3' end of the tRNA molecule through an ester bond.
An ester bond is formed between the carboxyl group (-COOH) of the amino acid and the hydroxyl group (-OH) of the ribose sugar at the 3' end of the tRNA molecule. This ester bond is also referred to as an ester linkage. The formation of the ester bond is catalyzed by the enzyme aminoacyl-tRNA synthetase.
The ester bond in aminoacyl-tRNA is essential for protein synthesis. During translation, the aminoacyl-tRNA molecule carries the specific amino acid to the ribosome, where it is incorporated into the growing polypeptide chain. The ester bond is later hydrolyzed, releasing the amino acid for further use in protein synthesis.
In summary, the binding of the amino acid in aminoacyl-tRNA involves the formation of an ester bond between the carboxyl group of the amino acid and the hydroxyl group of the ribose sugar in the tRNA molecule.
Option b
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There are ________ mol of carbon atoms in 4 mol of C4H8O2
There are 16 mol of carbon atoms in 4 mol of C4H8O2
The chemical formula C4H8O2 tells us that each molecule of this compound contains 4 carbon atoms, 8 hydrogen atoms, and 2 oxygen atoms. Therefore, to determine the number of carbon atoms in 4 mol of C4H8O2, we need to multiply the number of moles by the number of carbon atoms per molecule:
Number of carbon atoms = number of moles × number of carbon atoms per molecule
Number of carbon atoms = 4 mol × 4 carbon atoms per molecule
Number of carbon atoms = 16 mol
So there are 16 mol of carbon atoms in 4 mol of C4H8O2. It's important to note that the chemical formula of a compound gives us information about the ratio of atoms in the compound, which allows us to determine the number of atoms in a given amount of the compound.
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what should i apply after ordinary peeling solution
After using an ordinary peeling solution, it is important to apply a moisturizer or hydrating serum to the skin.
The ordinary peeling solution is a chemical exfoliant that helps remove dead skin cells and impurities from the surface of the skin. It is a powerful treatment that can leave the skin feeling dry and sensitive. Therefore, it is important to follow up with a hydrating product to restore the skin's moisture barrier and prevent irritation. The peeling solution contains alpha hydroxy acids (AHAs) and beta hydroxy acids (BHAs) that work to exfoliate the skin. These acids dissolve the bonds between dead skin cells, making them easier to slough off. This helps to unclog pores, smooth out rough texture, and even out skin tone .However, AHAs and BHAs can also strip away the skin's natural oils, leading to dryness and irritation. To counteract this, it is recommended to apply a moisturizer or hydrating serum after using the peeling solution. This will help to soothe and nourish the skin, while also locking in moisture and restoring the skin's natural pH balance.
In summary, it is important to apply a moisturizer or hydrating serum after using an ordinary peeling solution to prevent dryness and irritation. This will help to restore the skin's moisture barrier and keep it looking healthy and radiant.
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how many moles of h2o is equal to 2.1g of h2o
To determine the number of moles of H2O that is equal to 2.1g of H2O, we need to use the molecular weight of H2O, which is 18.015 g/mol.
We can use the following formula to calculate the number of moles:
moles = mass / molecular weight
Substituting the values we have:
moles = 2.1 g / 18.015 g/mol
moles = 0.1166 mol
Therefore, 2.1 g of H2O is equal to 0.1166 moles of H2O.
Propane (C3H8), a common fuel, reacts with oxygen to form carbon dioxide and water according to the equation below: C3H8 + 5O2 → 3CO2 + 4H2O If a propane heater burns 38.95 g C3H8, it consumes
Answer:
0.8833 mole of C3H8
Explanation:
Given:
Mass of C₃H₈ (Propane) = 38.95 gram
Computation:
Molar mass of C = 12.01
Molar mass of H = 1.008
Molar mass of C₃H₈ (Propane) = 3(12.01) + 8(1.008)
Molar mass of C₃H₈ (Propane) = 36.03 + 8.064
Molar mass of C₃H₈ (Propane) = 44.094
Number of mol in 38.95 gram Propane = Mass / Molar mass
Number of mol in 38.95 gram Propane = 38.95 / 44.094
Number of mol in 38.95 gram Propane = 0.88334
Answer:
Use the Periodic Table to find molar masses.
Propane (C3H8), a common fuel, reacts with oxygen to form carbon dioxide and water according to the equation below:
C3H8 + 5O2 → 3CO2 + 4H2O
If a propane heater burns 38.95 g C3H8, it consumes
38.95 mol C3H8.
0.8830 mol C3H8.
1 mol C3H8.
44.10 mol C3H8.
Part 2
How many moles of oxygen are required to produce 37.15 g CO2?
37.15 g CO2 = 1.407 mol O2
Part 3
What mass of propane is necessary to react with the amount of oxygen calculated in the previous question?
12.41 g C3H8