the half-life of 32p is approximately two weeks. approximately what fraction of a sample of radioactive phosphorus will remain radioactive after eight weeks?

Answer:

C

Explanation:

all metals are found on the left side of the periodic table except for Hydrogen which is a non-metal

Surface tension is a liquid characteristic that accounts for why acetone does not form beads on a windshield but water does.

The amount of force necessary to separate a liquid's surface is measured by its surface tension. High surface tension is caused by the attraction of water molecules to one another rather than to the surface they are in contact with. As a result of this attraction, water molecules limit their contact with the surface area, generating droplets with a high contact angle, which cause water to bead up on hydrophobic surfaces like a windshield. Acetone spreads out on surfaces rather than forming droplets due to its lower surface tension than water, which lowers the contact angle.

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No, a chemical equation cannot give us every information. Important information that may be missing from a chemical equation includes the physical states of the reactants and products, the concentrations of the reactants and products, the energies or temperatures of the reactants and products, the specific structures of the reactants and products, half-reactions, and reaction intermediates.

The ligand that produces the strongest crystal field is the ligand with the highest charge and smallest size.

In coordination chemistry, ligands are molecules or ions that donate electron pairs to a central metal ion. When ligands bind to a metal ion, they create a crystal field, which is the electrostatic field generated by the charged ligands around the central metal ion.

The strength of the crystal field depends on the properties of the ligands.

Two main factors that influence the strength of the crystal field are the charge and size of the ligands. Ligands with higher charges or multiple negative charges create stronger crystal fields because they exert a greater electrostatic force on the central metal ion. Additionally, ligands with smaller sizes can approach the metal ion more closely, leading to stronger interactions.

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The intermolecular forces are in the solid NaCl salt is ion - ion forces or the dipole - dipole forces of the interaction.

The Na is the metal and is capable of the donating the electrons and the Cl is the non metal and have capability of accepting the electrons. This makes the Na to form the cation and the Cl to make the anion. The dipole - dipole forces are present in the molecule which contains the oppositely charged ions one is positively charged ion and the other is the negatively charged ion.

Thus , the NaCl solid has the ion - ion intermolecular forces of the interaction .

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3 moles of NaOH reacts with 1 mole of phosphoric acid.

The moles ratio of the reaction between NaOH and Phosphoric acid is given by the equation of the reaction below:

\(3\:NaOH + H_{3}PO_{4} \rightarrow Na_{3}PO_{4} + 3\:H_{2}O \\ \)

Based on the equation of the reaction, 3 moles of NaOH reacts with 1 mole of phosphoric acid.

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When balancing a chemical reaction, you can only change the coefficients or numbers in front of the chemical formulas. The goal of balancing a chemical equation is to ensure that the number of atoms of each element on both sides of the equation is equal.

Coefficients are used to represent the number of molecules or moles of a substance in a chemical equation. By adjusting these coefficients, you can balance the equation by making the number of atoms of each element the same on both sides.

However, you cannot change the subscripts within a chemical formula when balancing a reaction. The subscripts represent the number of atoms of each element within a molecule or formula unit and are fixed for a given compound. Changing the subscripts would result in a different compound with different properties.

In summary, when balancing a chemical reaction, you can only change the coefficients in front of the chemical formulas to achieve the balance of atoms on both sides of the equation.

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The Maillard reaction creates brown pigments in cooked meat in a very specific way: by rearranging amino acids and certain simple sugars, which then arrange themselves in rings and collections of rings that reflect light in such a way as to give the meat a brown color.

The advanced Maillard reaction involves breaking down the Amadori product into a variety of fission products that are composed of the sugar-amino complex. In the ultimate Maillard reaction, amino compounds and sugar fragments condense to form polymerized proteins and brown pigments called melanoidins. In the Maillard reaction, an organic chemical process, reducing sugars and amino acids combine to create a complex brew of chemicals. The distinct flavour and aroma of browned food are the result of this process. The French chemist Louis Camille Maillard's name is associated with the Maillard reaction.

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Answer:

freezing

Explanation:

because condensation is gas to liquid boiling is liquid to gas and sublimation is solid to gas

Answer:transfer oxygen through your blood

Explanation:

Answer:

coordinate the muscles that control breathing

hope this helps ⭐

Answer:

Option B is correct.

Explanation:

They live in less extreme environment than most archaebacteria.

Hoped this helped.

Approximately 2.7 liters of liquid diluent would be needed to make a 1:10 solution when added to 300 mL of a 30% solution.

To calculate the volume of the liquid diluent needed, we can set up a proportion based on the volume of the solute:

(30 grams / 100 mL) = (x grams / 3000 mL)

Cross-multiplying and solving for x:

30 grams * 3000 mL = 100 mL * x grams

90,000 grams * mL = 100 mL * x grams

x = (90,000 grams * mL) / (100 mL)

x ≈ 900 grams

Since the diluent is added to reach a total volume of 3000 mL, the volume of the diluent needed would be 3000 mL - 300 mL = 2700 mL.

Converting 2700 mL to liters:

2700 mL * (1 L / 1000 mL) = 2.7 liters

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To make 250.0 mL of something like a 0.500 mol/L sulfuric acid solution, 0.125 L of a 1.00 mol/L sulfuric acid solution is needed.

can cause blindness and irritate & irritate the skin and the eyes. Exposures may result in pulmonary edema, a genuine condition when fluid builds up in the lungs. Headache, nauseousness, and vomiting can all result after exposure.

Another important ingredient in the chemical process industries is sulfuric acid. It is most frequently employed in the production of fertilizer, but it is also crucial for the processing of minerals, oil, wastewater, and chemicals. H2S04, often known as sulfuric acid, is a corrosive chemical that harms your skin, eyes, teeth, & lungs. Extreme exposure can be fatal.

n1 = n2

CM = n / V

n = CM x V

CM1 x V1 = CM2 x V2

1.00 x V1 = 0.500 x 0.2500

V1 = (0.500 x 0.2500) / 1.00

V1 = 0.125 L

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Answer:

see picture for answer

Explanation:

The Lewis structure for ClO3- is as follows:

O

|

Cl--O

|

O-

To determine the formal charge of the central atom Cl, we need to calculate the valence electrons and nonbonding electrons present in ClO3-. Chlorine has 7 valence electrons, and each oxygen atom contributes 6 electrons for a total of 24 valence electrons. In this structure, there are 3 lone pairs on each oxygen atom and one Cl-O double bond.

The formal charge of Cl can be calculated as follows:

The formal charge on the central atom, Cl, is -3. This indicates that Cl has an extra electron compared to its neutral state. The other oxygen atoms have a formal charge of -1 each, indicating that they have an extra electron as well. This arrangement of formal charges indicates that the ClO3- ion is a negatively charged species. The Lewis structure shows that ClO3- obeys the octet rule as each atom has a full outer shell of electrons.

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Answer:

Why ? Because 1 molecule of H2SO4 gives 2 H+ ions per molecule while only one H+ ion is required to neutralize 1 molecule of KOH. So, 1 molecule of H2SO4 can neutralize 2 molecules of KOH. Hence, we would require 525 ml of 0.03 M H2SO4 to neutralize 525 ml of 0.06 M KOH. How will we prepare 525 ml of 0.03 M H2SO4 ?

Explanation:

Now, we have 0.025 M H2SO4 and we do not know how much volume we have.

We will use the standard N1 X V1 = N2 X V2 for this calculation.

N1=0.025 M; V1=unknown; N2=0.03 M and V2=525 ml.

So V1= (0.03 X 525)/(0.025) = 630 ml.

According to the molar concentration, 684 ml of 0.25 M H₂SO₄ can be prepared from 57 mL of a 3.0 M solution of H₂SO₄.

Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.

The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.

In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.In case  of 2 solutions,it is calculated as, M₁V₁=M₂V₂ substitution gives V₁=3×57/0.25=684 ml.

Thus, 684 ml of 0.25 M H₂SO₄ can be prepared from 57 mL of a 3.0 M solution of H₂SO₄.

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Answer:

Explanation:

Warm lake vapor pressure is higher than cold lake vapor pressure because it evaporates more quickly. In other words, as the temperature of warm water increases, the kinetic energy of the warm water molecule also increases. As the kinetic energy of the warm water molecule increases, the number of molecules conversion into a vapor also increases, thereby increasing the vapor pressure of warm water.

Answer:

B.

Warm water evaporates more quickly.

Explanation:

i got it right on edmentum!!

Answer:

I think it's 1, but if that's wrong I'm really sorry

Answer:

0.56L

Explanation:

This question requires the Ideal Gas Law:  \(PV=nRT\) where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of the gas, R is the Ideal Gas constant, and T is the Temperature of the gas.

Since all of the answer choices are given in units of Liters, it will be convenient to use a value for R that contains "Liters" in its units:\(R=0.0821\frac{L\cdot atm}{mol\cdot K}\)

Since the conditions are stated to be STP, we must remember that STP is Standard Temperature Pressure, which means \(T=273.15K\) and \(P=1atm\)

Lastly, we must calculate the number of moles of \(O_2(g)\) there are.  Given 0.80g of \(O_2(g)\), we will need to convert with the molar mass of \(O_2(g)\).  Noting that there are 2 oxygen atoms, we find the atomic mass of O from the periodic table (16g/mol) and multiply by 2:  \(32g\text{ }O_2=1mol\text{ }O_2\)

Thus, \(\frac{0.80g \text{ }O_2}{1} \frac{1mol\text{ }O_2}{32g\text{ }O_2}=0.25mol\text{ }O_2=n\)

Isolating V in the Ideal Gas Law:

\(PV=nRT\)

\(V=\frac{nRT}{P}\)

...substituting the known values, and simplifying...

\(V=\frac{(0.025 mol \text{ }O_2)(0.0821\frac{L\cdot atm}{mol \cdot K} )(273.15K)}{(1atm)}\)

\(V=0.56L \text{ } O_2\)

So, 0.80g of \(O_2(g)\) would occupy 0.56L at STP.

Answer:

0.56 L

Explanation:

According to Chemicool, the natural semiprecious gemstone zircon is produced when zirconium and silicate mix. Cubic zirconia, which is frequently utilized as an alternative to diamonds, is produced when zirconium and dioxide are mixed.

What substance makes up zirconium ore?

Hafnium is typically present in zirconium ores, and it is challenging to separate. Zirconium of commercial grade comprises 1% to 3% hafnium. Zirconium is employed in nuclear energy applications, such as cladding fuel elements, since it has a low neutron absorption cross section.

Zirconium has been widely used in the creation of pumps, valves, and heat exchangers due to its great corrosion resistance. Zirconium is also utilized in the manufacturing of some magnesium alloys as an alloying agent and as an additive in the production of some steels.

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The number of groups around a given atom determines the number of atomic orbitals that must be hybridized to form the hybrid orbitals for that atom.

When an atom forms chemical bonds, it undergoes hybridization, which involves the mixing of atomic orbitals to form hybrid orbitals. The number of groups around an atom determines the number of hybrid orbitals required.

A group can be a bonded atom or a nonbonded (lone) pair of electrons associated with the atom. Each group around the atom contributes one hybrid orbital. Thus, the number of hybrid orbitals is determined by the total number of groups, including bonded atoms and lone pairs, around the atom.

This concept is known as the concept of hybridization and is essential in understanding the molecular geometry and bonding of atoms in molecules.

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Answer:

c. 640.51

Explanation:

Given: 2.54 cm = 1 inch weighed 3.88 ounces

1 g = 0.035273 ounces

?   = 3.88 ounces

? = (3.88 x 1) / 0.035273

? = 109.999 = 110 g

110 g = 3.88 ounces

2.54 cm = 110 g

14.79 cm = ?

? = (14.79 x 110) / 2.54

? = 640.51 g

According to unit conversion, there are 640.51 g would a 14.79 cm length of same iron rod weigh.

Unit conversion is defined as a multi-step process which involves multiplication or a division operation by a numerical factor.The process of unit conversion requires selection of appropriate number of significant figures and the rounding off procedure.

It involves a conversion factor which is an expression for expressing the relationship between the two units.A conversion ratio always has value which equals to one which indicates that numerator and denominator have values which are expressed in different units.

Given: 2.54 cm = 1 inch weighed 3.88 ounces,1 g = 0.035273 ounces

x  = 3.88 ounces

x= (3.88 x 1) / 0.035273

x = 109.999 = 110 g

110 g = 3.88 ounces

Thus,2.54 cm = 110 g

14.79 cm = x

x= (14.79 x 110) / 2.54

x = 640.51 g

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The solvent is said to be saturated when it has dissolved all the solute it can at a particular temperature.

The relationship between solvents and solutes is an important one in the study of chemistry. In order to understand the dynamics of this relationship, it is important to understand the concept of saturation. When a solvent has dissolved all the solute it can at a particular temperature, it is said to be saturated. In this essay, the significance of saturation in solvent-solute interactions will be discussed in detail.

At the most basic level, saturation is important because it helps to inform chemists of the maximum amount of solute that can be dissolved in a solvent at any given temperature. This information can be used to control the concentration of a solution and to ensure that it is within the desired range for a particular application.

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The rate law for the rate of consumption of F20:

Rate = kd * [F] * [F20]

where [F] represents the concentration of F and [F20] represents the concentration of F20.

To derive the rate law for the rate of consumption of F20 in the given mechanism, we can use the steady-state approximation. According to this approximation, the rate of formation of an intermediate species remains constant over time.

In the given mechanism, the intermediate species is OF. To apply the steady-state approximation, we assume that the rate of formation of OF is equal to the rate of its consumption:

Rate of formation of OF = Rate of consumption of OF

The rate of formation of OF can be determined from the first step of the mechanism:

Rate of formation of OF = ka * [F2O] * [F20]

The rate of consumption of OF can be determined from the third and fourth steps of the mechanism:

Rate of consumption of OF = kd * [OF] * [F]

Equating the two rates, we have:

ka * [F2O] * [F20] = kd * [OF] * [F]

Since the concentration of OF is an intermediate species, we can express it in terms of other reactants and products using the second step of the mechanism:

[OF] = (1/ka) * F * [F2O]

Substituting this expression for [OF] in the rate equation, we get:

ka * [F2O] * [F20] = kd * [(1/ka) * F * [F2O]] * [F]

Simplifying the equation, we have:

ka * [F20] = kd * F * [F]

Finally, we can write the rate law for the rate of consumption of F20:

Rate = kd * [F] * [F20]

where [F] represents the concentration of F and [F20] represents the concentration of F20.

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