Answer:
18 grams
Step-by-step explanation:
Answer: 18
Step-by-step explanation:
28 divided by 14 equals 2
72 multiplied by 0.05^2 equals 18
Share £400 between Alice and Brian in the ratio 1:4
Alice will receive £80 and Brian will receive £320
When dividing an amount of money in a given ratio, we need to first determine the total number of parts that the ratio is divided into.
In this case, the ratio between Alice and Brian is 1:4. This means that for every 1 unit of money that Alice receives, Brian receives 4 units of money. Therefore, the total number of parts in this ratio is 1 + 4 = 5.
To divide £400 in the ratio of 1:4, we need to find out how much of the total amount each part represents. To do this, we divide the total amount by the total number of parts:
£400 ÷ 5 = £80
So each part in this ratio represents £80.
Now that we know the value of each part, we can calculate how much Alice and Brian will receive.
Alice's share is one part, which represents £80. Therefore, Alice will receive
1 part x £80 = £80
Brian's share is four parts, which represents 4 x £80 = £320. Therefore, Brian will receive:
4 parts x £80 = £320
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solve 3-x/2 less than or equal to 18
Answer:
x ≥ -30
Step-by-step explanation:
The equation is 3 - x / 2 ≤ 18.
First, subtract 3 on both sides:
- x / 2 ≤ 15.
Multiply by -2 on both sides and swap the less than or equal to sign:
x ≥ -30
Hope this helps!
Let f: { (a,3) , (b,2) , (c,1) , (d,3) } be a function from { a,b,c,d } to { 1,2,3 }. Is f an onto function ? Is f a one-one function ?
The function f is an onto function but not a one-one function.
To determine whether f is an onto function or a one-one function, we need to look at the relationship between the elements in the domain and the elements in the range.
An onto function is a function where every element in the range is mapped to by at least one element in the domain. In other words, every element in the codomain has a corresponding element in the domain that maps to it. To determine if f is an onto function, we need to check if every element in the range {1,2,3} is mapped to by at least one element in the domain {a,b,c,d}.
Looking at the function f, we see that all three elements in the range are mapped to by elements in the domain. For example, 1 is mapped to by c, 2 is mapped to by b, and 3 is mapped to by a and d. Therefore, f is an onto function.
A one-one function (also called an injective function) is a function where each element in the domain maps to a unique element in the range. In other words, no two distinct elements in the domain map to the same element in the range. To determine if f is a one-one function, we need to check if there are any distinct elements in the domain that map to the same element in the range.
Looking at the function f, we see that both a and d in the domain map to 3 in the range. Therefore, f is not a one-one function.
In summary, the function f is an onto function but not a one-one function.
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2p²q³×5pq÷10p³q⁴ answer it pls
p³q⁴
Step-by-step explanation:
given. 2p²q³ × 5pq ÷ 10p³q⁴
multiply. 10p³q⁴ ÷ 10 p³q⁴
Divide. p³q⁴
15 feet tree cast a shadow that is 15 feet long. What is the distance from the top of the tree to the tip of its shadow?
Answer: Hi. The height of the tree is 27 ft
Step-by-step explanation:
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helppp pleaseee:(im failing
Answer:
1.o5 I fell i I'm in heven
How many binary strings of length 10 are there in which the number of 0's in the string is not equal to the number of 1's in the string?
The binary strings of length 10 are there in which the number of 0's in the string is not equal to the number of 1's in the string is 2¹⁰ - 2⁹.
Binary number:
A binary number is a number expressed in the base-2 numeral system or binary numeral system, a method of mathematical expression which uses only two symbols: typically "0" and "1".
Given,
Here we need to find How many binary strings of length 10 are there in which the number of 0's in the string is not equal to the number of 1's in the string.
Here the length of the binary string is 10.
So, it can be written in the power form as 2¹⁰.
Now we need to find the number of 0's in the string is not equal to the number of 1's in the string.
For that, we have to consider,
There are 2⁹ number of binary strings are not have same number of 0's in the string is not equal to the number of 1's in the string.
So, it can be written as,
=> 2¹⁰ - 2⁹
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A coin flipped 10 times and shows tails each time. Is there statistical significance to say that the coin is not a fair coin
Answer:
no because Chance is likely to account the result.
Mary had 6 34 cups of floor. She used 2 712 cups of flour in one recipe and 2 1324 cups of flour in another
Using the unitary method, we found that Mary used 11 1/2 cups of flour altogether in the two recipes.
Mary had 6 3/4 cups of flour, which can be written as 27/4 cups of flour. We can multiply the whole number 6 by the denominator 4, which gives us 24. Adding the numerator 3 to this product gives us a total of 27. Therefore, 6 3/4 cups of flour is equivalent to 27/4 cups of flour.
Now that we have all the quantities in the same units, we can add them together. To add fractions, we need a common denominator. In this case, the common denominator is 4.
27/4 cups of flour + 5/2 cups of flour + 9/4 cups of flour
To add fractions, we need the denominators to be the same. We can rewrite 5/2 as an equivalent fraction with a denominator of 4 by multiplying the numerator and denominator by 2:
27/4 cups of flour + (5 * 2)/(2 * 2) cups of flour + 9/4 cups of flour
27/4 cups of flour + 10/4 cups of flour + 9/4 cups of flour
Now that we have a common denominator, we can add the numerators together:
(27 + 10 + 9)/4 cups of flour
46/4 cups of flour
To simplify this fraction, we can divide both the numerator and denominator by their greatest common divisor, which is 2:
46 ÷ 2 / 4 ÷ 2 cups of flour
23/2 cups of flour
Since 23/2 can be simplified further, we can express it as a mixed number:
23 ÷ 2 = 11 with a remainder of 1
So, the total amount of flour Mary used altogether is 11 1/2 cups.
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Complete Question:
Mary had 6 3/4 cups of floor. She used 2 1/2 cups of flour in one recipe and 2 1/4 cups of flour in another.
How much flour did she use altogether?
Is there any number in base 10 (positive or negative) that can be written in multiple
ways in base −4? Can you prove it? If yes, provide the number and the base −4
representations, and if no, show why.
The true statement is that no number in base 10 can be written in multiple ways in base 4
How to determine the true statement?The base of the numbers are given as:
Base 10 and base 4
Base 10 numbers are also referred to as decimal numbers, while base 4 numbers are quaternary numbers
There is only one equivalent of each number in each base.
This means that (for instance)
357 in base 10 is 11211 in base 4
The above number does not have any other representation in base 4 and it can not be written in another way.
This is the same for other numbers in base 10
Hence, the true statement is that no number in base 10 can be written in multiple ways in base 4
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Express x in term of y:x/7+2y=6
Answer:
You have to multiply the denorminator to both sides in order to make x the subject :
\( \frac{x}{7 + 2y} = 6\)
\(x = 6(7 + 2y)\)
Answer:
Given
x/7 + 2y = 6
Multiply through by 7 to clear the fraction
x + 14y = 42 ( subtract 14y from both sides )
x = 42 - 14y
Step-by-step explanation:
Write the denominator of the fractiona 7/20 as the product of prime factors
Answer:
Step-by-step explanation:
prime factors of 20 = 2 * 2 * 5
\(\frac{7}{20}=\frac{7}{2*2*5}\)
30,098 in standard form
30,098 to four significant figures
2) A 4-digit number will be formed using the digits 1, 2, 3, 4, 5, 6, 7,9. Each digit will only be used once, if at all. Note that there is no 8. a) How many possible 4-digit numbers are possible? TOTAL: b) Assume four of the digits are randomly chosen and randomly permuted in order to form the 4-digit number. Then each of the possible 4-digit numbers in part a) are equally likely. Find the probability that the 4-digit number ends up being an odd number greater than or equal to 6000? Hint: Partition the event that the number is odd and greater than or equal to 6000 into: • the event that the number is odd and between 6000 & 6999 inclusive • the event that the number is odd and greater than or equal to 7000. (odd numbers in [6000,6999 ways (odd numbers 7000 or more) ways PROBABILTY:
The possible 4-digit numbers are 1,680.
Probability that 4-digit number ends up being an odd number greater than or equal to 6000 is 57.14%.
How to calculate probability?a) The number of possible 4-digit numbers that can be formed using the given digits without repetition is given by the permutation formula:
P(8,4) = 8! / (8 - 4)! = 8 x 7 x 6 x 5 = 1,680
Therefore, there are 1,680 possible 4-digit numbers using the given digits.
b) The total number of 4-digit numbers that can be formed from the given digits is 1,680, as calculated in part a).
To find the probability that the 4-digit number is odd and greater than or equal to 6000, we need to calculate the number of odd 4-digit numbers in the range [6000, 6999] and the number of odd 4-digit numbers greater than or equal to 7000, and divide each by the total number of 4-digit numbers.
Number of odd 4-digit numbers in [6000, 6999]:
The last digit must be 1, 3, 5, or 7 (4 choices). The first three digits can be any of the remaining 7 digits (7 choices for the first digit, 6 choices for the second digit, and 5 choices for the third digit). Therefore, the number of odd 4-digit numbers in [6000, 6999] is:
4 x 7 x 6 x 5 = 840
Number of odd 4-digit numbers greater than or equal to 7000:
The first digit must be 7 (1 choice). The last digit must be 1, 3, 5, or 7 (4 choices). The second and third digits can be any of the remaining 6 digits (6 choices for the second digit and 5 choices for the third digit). Therefore, the number of odd 4-digit numbers greater than or equal to 7000 is:
1 x 4 x 6 x 5 = 120
The total number of odd 4-digit numbers is 840 + 120 = 960.
Therefore, the probability that the 4-digit number is odd and greater than or equal to 6000 is: 960 / 1,680 = 0.5714 or approximately 57.14%.
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Left Truncatable Primes In number theory, a left-truncatable prime is a prime number which, in a given base, contains no 0, and if the leading ("left") digit is successively removed, then all resulting numbers are prime. For example, 9137, since 9137, 137, 37 and 7 are all prime. i. Define a SCHEME procedure, named (left-truncatable-prime? p), that takes one integer argument, p, and evaluates to true (#t) if the integer p is a left-truncatable prime and false (#f) otherwise. ii. Define a SCHEME procedure, named (nth-left-trunc-prime n), that takes one argu- ment, n, and uses the find function you write in Lab 6 and (left-truncatable-prime? p) to return the nth left-truncatable prime number.
A. (left-truncatable-prime? p) procedure:
(define (is-prime? n)
(define (divides? a b)
(= (remainder b a) 0))
(define (iter i)
(cond ((> i (sqrt n)) #t)
((divides? i n) #f)
(else (iter (+ i 1)))))
(iter 2))
(define (left-truncatable-prime? p)
(define (truncate n)
(if (< n 10)
n
(truncate (quotient n 10))))
(define (iter n)
(if (<= n 10)
(is-prime? p)
(and (is-prime? n) (iter (truncate n)))))
(iter p))
B. (nth-left-trunc-prime n) procedure:
(define (nth-left-trunc-prime n)
(define (find-trunc-prime i p)
(cond ((= i n) p)
((left-truncatable-prime? (+ p 1)) (find-trunc-prime (+ i 1) (+ p 1)))
(else (find-trunc-prime i (+ p 1)))))
(find-trunc-prime 1 7)) ; start at 7 because it is the first left-truncatable prime.
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Three organizations are collecting donations for a cause. Organization A begins with one donation, and the number of donations quadruples each hour. The table shows the numbers of donations collected by Organization B. The graph shows the numbers of donations collected by Organization C. a. What type of function represents the numbers of donations collected by Organization A? B? C? b. Find the average rates of change of each function for each 1-hour interval from t = 0 to 1 = 6. c. For which function does the average rate of change increase most quickly? What does this tell you about the numbers of donations collected by the three organizations?
a) The number of donations collected by Organization A and B represents linear function and C has exponential growth function
b) Average rate of change of A and B is 4
Average rate of change of C is 121.3333
c) The rate of change of a linear function is constant, while the rate of change of an exponential function is always increasing .
d) The numbers of donations collected by the three organizations increasing as the time increases
What is exponential growth function?A process called exponential growth sees a rise in quantity over time. When a quantity's derivative, or instantaneous rate of change with respect to time, is proportionate to the quantity itself, this phenomenon takes place.
a) The number of donations collected by Organization A and B represents linear function and C has exponential growth function
b) Average rate of change = ( f(x2) -f(x1) ) /( x2 - x1) ------(1)
x1 = 0, x2= 6
Organization A and B:
f(6)= 24 , f(0) = 0
(1) => Average rate of change = (24-0)/(6-0) = 24/6 = 4
Organization C:
f(6)= 729, ( y-coordinate 3 times the previous y-coordinate ), f(0) = 1
(1) => Average rate of change = ( 729 -1)/(6-0) = 728/ 6 = 121.333
c) The rate of change of a linear function is constant, while the rate of change of an exponential function is always increasing .
d) The numbers of donations collected by the three organizations increasing as the time increases
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Under her cell phone plan, Aubree pays a flat cost of $58.50 per month and $3 per gigabyte. She wants to keep her bill at $72.30 per month. How many gigabytes of data can she use while staying within her budget?
Answer:
Aubree can use 4.6 gigabytes of data while staying within her budget.
If the answer choices only use whole numbers, use 4 gigabytes, because it is the number of full gigabytes she can use.
Step-by-step explanation:
x= gigabyte
58.50 + 3x = 72.30
3x = 72.30-58.50
3x= 13.8
x= 4.6
A student investigating study habits asks a simple random sample of 16 student at her school how many minutes they spent on their English homework the previous night. Suppose the actual parameter values for this variable are mu = 45 minutes and sigma = 15 minutes. Which of the following best describes what we know about the sampling distribution of means for the student's sample? O mu x = 45; sigma x unknown; shape of distribution unknown O mu x = 45; sigma x = 15; distribution approximately Normal O mu x = 45; sigma x = 15; shape of distribution unknown O mu x = 45; sigma x = 3.75; distribution approximately Normal O mu x = 45; sigma x = 3.75; shape of distribution unknown
The best description about the sampling distribution of means for the student's sample is mu x = 45, sigma x = 3.75, shape of distribution unknown.
What is Sampling Distribution?Sampling distribution is defined as the probability distribution of a statistical measure which is got by the repeated sampling of a specific population.
Given that,
μ = 45 minutes and σ = 15 minutes
Sampling distribution of means for the student's sample is :
μₓ = μ = 45
σₓ = σ / √n, where n is the sample size.
σₓ = 15 / √(16) = 15 / 4 = 3.75
Now since the sample size 16 which is less than 30, shape of the distribution is unknown.
Hence the sampling distribution is, μₓ = 45, σₓ = 3.75, and the shape of distribution is unknown.
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six distinct integers are selected at random from 2018 2019 2020 2027 what is the probability that among those selected the second smallest in 2020
The probability that among those selected the second smallest in 2020 is 1/3
In this question, we have been given six distinct integers are selected at random from 2018, 2019, 2020, . . . , 2027
We need to find the probability that among those selected the second smallest in 2020.
Here, total integers are: 10
The total number of ways to choose six distinct integers :
10C6
= 10!/6!(10 - 6)!
= 210
Assume 2020 is the second-lowest number.
There are 5 numbers left to choose, 4 of which must be greater than 2020.
This is equivalent to choosing 4 numbers from the seven numbers larger than 2020, and 1 number from the two numbers less than 2020
using combination formula,
7C4 * 2C1
= 35 * 2
= 70
So, the probability would be,
P = 70/210
P = 1/3
Therefore, the required probability is 1/3
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When we describe relationships between variables, a correlation nearer to 1.00 (plus or minus) indicates that?
When we describe relationships between variables, a correlation nearer to 1.00 (plus or minus) indicates the relationship between variables is strong.
The strength and direction of a relationship between two or more variables are described by the statistical measure of correlation, which is given as a number. However, a correlation between two variables does not necessarily imply that a change in one variable is the reason for a change in the values of the other.
When correlation is known, predictions can be made using it. Knowing a score on one measure helps us predict another that is closely related to it more accurately. The forecast will be more accurate the stronger the correlation between/among the variables.
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Find the scale factor of the Simla r polygons
Compare two similar sides:
24:32 this reduces to 3:4
Answer: D) 3:4
The following group of values was entered into the TVM solver on a graphing calculator
N=108; I%= 6.6 PV =; PMT=-620 FV =0; P/Y = 12; C/Y=12; PMT:END which of theses expressions with return the same value for PV
Based on the entries into the TVM solver, the expression that will return the same value for PV is \(\frac{(620) (( 1 + 0.066)^{108} - 1) }{(0.066) (1 + (0.066))^{108}}\).
Which formula will give the same Present Value?The formula for present value for this series of cashflows is:
= \(\frac{(Payment) (( 1 + Interest rate)^{Number of years} - 1) }{(Periodic interest) (1 + (Periodic interest))^{Number of years}}\)
Based on the P/Y and the C/Y being 12, the number of periods given in the graphing calculator will be the same in the formula, which is 108 periods.
The interest rate of 6.6% will also be the same in the formula.
The best option is therefore option B which has all these figures and so will give the same present value.
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Answer: 0.0055 and 108
aka ($620) ((1+0.0055)^108 -1 / (0.0055) (1+0.0055)^108
Step-by-step explanation: Just did it, Good luck! :)
Sauli rolled a fair number cube with 6 sides, each side
numbered 1-6. What is the probability that the number he
rolled was greater than 4?
Hint: How many numbers can he roll that would make this
trial a "success" or a "favorable outcome"?
A. 1/3
B. 1/4
C. 1/2
Answer:
A:1/3
Step-by-step explanation:
There are 6 possible outcomes when Sauli rolls the number cube, with each outcome having an equal probability of 1/6. To find the probability of rolling a number greater than 4, we need to count the number of favorable outcomes, which are the numbers 5 and 6.
Therefore, the probability of rolling a number greater than 4 is 2 favorable outcomes out of 6 possible outcomes, which simplifies to 1/3.
So the answer is A. 1/3.
I don’t understand this type of question
Answer:
Center: 10, -6, Radius: 7
Step-by-step explanation:
This equation can be rewritten using the formula
(x-p)²+(y-q)²=r²
From this we get that p=10 and q=-6, because -(-6)=+6. This is how we get the center points.
And since the square root of 49 is 7, we see that the radius is 7.
Consider the following: x 29 62 75 99 108 y 215 225 173 129 111 1) what is slope of the regression line predicting y from x,rounded to 2 decimal places?
The slope of the regression line predicting y from x is 0.30.
Given that,
x y
29 215
62 225
75 173
99 129
108 111
So, the coordinate points are (29, 215) and (62, 225)
The formula to find the slope of a line is slope = (y₂-y₁)/(x₂-x₁).
Here, slope = (225-215)/62-29)
= 10/33
= 0.30
Therefore, the slope of the regression line predicting y from x is 0.30.
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5,5,6,9,4,3,4,8,10,4 what is the range
Answer: Symbol max-min and answer 10-4
Step-by-step explanation:
in a class of 32 students
Answer:
1.48 m
Step-by-step explanation:
mean is calculated as
mean = \(\frac{sum}{count}\)
Then the sum for the 14 boys is
\(\frac{sum}{14}\) = 1.56 ( multiply both sides by 14 )
sum = 21.84 m
The sum for the class of 32 is
\(\frac{sum}{32}\) = 1.515 ( multiply both sides by 32 )
sum = 48.48 m
Thus the sum for the 18 girls is
sum = 48.48 - 21.84 = 26.64 m
Then mean height of girls is
mean = \(\frac{26.64}{18}\) = 1.48 m
let say that x, y, z are regular unix user processes and x’s parent is y and y’s parent is z. when process y dies, what would happen?
The exact behavior and consequences depend on the Operations system's process management mechanisms and the actions taken by process z or the system's process manager.
When process y dies, the Operations system handles the termination of the process and performs certain actions related to its termination. Here are the likely outcomes when process y, with process x as its child and process z as its parent, dies:
1. Process y's termination: When process y dies, the operating system marks it as terminated and frees up any system resources that were allocated to it. This includes releasing memory, closing file descriptors, and removing its entry from the process table.
2. Parent-child relationship: Since process x is the child of process y, the operating system updates the parent-child relationship. Typically, when a parent process dies, the child process is reassigned to another process called the init process or is terminated if no other process adopts it. The exact behavior depends on the operating system's process management policies.
3. Process z's status: Process z, being the parent of process y, may receive a notification or a signal indicating the termination of its child process. The operating system usually sends a SIGCHLD signal to the parent process, allowing it to handle the termination of its child process appropriately. Process z can choose to ignore the signal or perform actions such as cleaning up resources or spawning a new child process to replace the terminated one.
4. Orphaned process: If process z does not handle the termination of process y appropriately or if process z itself terminates before process y, process x becomes an orphaned process. Orphaned processes are typically adopted by the init process or the system's process manager, ensuring that they are handled and terminated properly.
In summary, when process y dies, the operating system marks it as terminated, updates the parent-child relationship, and may notify process z. The exact behavior and consequences depend on the operating system's process management mechanisms and the actions taken by process z or the system's process manager.
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An F test with five degrees of freedom in the numerator and seven degrees of freedom in the denominator produced a test statistic who value was 7. 46.
a. What is the P-value if the test is one-tailed?
b. What is the P-value if the test is two-tailed?
A one-tailed test has a P-value of 0.01 and a two-tailed test has a P-value of 0.053.
We must utilize the F-distribution table or calculator to address this question. The F test follows an F-distribution since it is a ratio of two variances.
a. To calculate the P-value for a one-tailed test, we must first calculate the likelihood that the F-statistic is greater than or equal to 7.46.
Using a table, we can find the area under the F-distribution curve to the right of 7.46 with 5 degrees of freedom in the numerator and 7 degrees of freedom in the denominator.
Assuming an alpha level of 0.05, we reject the null hypothesis if the P-value is less than 0.05.
For the given F-statistic of 7.46, the P-value for a one-tailed F-test with five degrees of freedom in the numerator and seven degrees of freedom in the denominator is approximately 0.01.
b. For a two-tailed test, we must calculate the likelihood of seeing an F-statistic that is 7.46 or more in either direction. This means we must calculate the area under the F-distribution curve in the distribution's two tails.
To find the p-value for a two-tailed F-test with 5 and 7 degrees of freedom and a test statistic of 7.46, we need to use an F-distribution table.
Using a table, we would look for the intersection of the row with 5 degrees of freedom and the column with 7 degrees of freedom, which gives us the critical F-value for a significance level of 0.05 (assuming equal variances in the two populations being compared). The critical F-value is 4.03.
Since the test statistic of 7.46 is greater than the critical F-value of 4.03, the p-value for the two-tailed test is less than 0.05. Specifically, the p-value is the probability of observing an F-statistic as extreme or more extreme than 7.46, which is the probability in the right tail of the F-distribution plus the probability in the left tail:
p-value = P(F > 7.46) + P(F < 1/7.46)
= 0.052 + 0.001
≈ 0.053
Therefore, the p-value for the two-tailed test is approximately 0.053.
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calculate the surface area and then the volume
Answer:
46
Step-by-step explanation:
length x width x height
7 x 5 x 3
Answer: surface area = 142
Volume = 105
* make sure to add labels (units^2, etc.)
Step-by-step explanation:
Area = length x height
Volume = length x width x height