The input cylinder has a radius of .01 m and you are able to apply a force of 200 N to it. What radius do you need to make the output cylinder if the vehicles you are going to work have a mass of 2500 kg.

Answer:

Explanation:

Heat is transferred in the following ways listed below

1. Conduction(Through direct contact of particles )

2. Convection(Through motion of hot and cold liquid )

3. Radiation(Through electromagnetic waves Through the rising of a warm gas )

1. Conduction: This has to do with the transfer of heat from one medium to another having direct contact with each other, the medium can either be solid or liquids

2. Convection: Has to do with the transfer of heat energy via molecules of the liquids in motion with different or varying temperature gradients

3. Radiation: Mostly occurs in gases, it is the transfer of energy through waves

Answer:

Dominant genes are genes that are most likely to be adapted to offspring. Recessive genes are genes that are least likely to be adapted to offspring. For example, if the father had brown eyes and the mother had green eyes, their offspring will most likely have brown eyes because brown eyes are considered dominant and more likely to happen.

Explanation:

not my answer i dont take credit

The correct answer is Heat and pressure.

Weathering and erosion have the potential to transform sedimentary rock back into sediment. It could also produce a different kind of rock. It may transform into metamorphic rock if it is buried deep enough in the crust to be exposed to higher temperatures and pressures.

Sedimentary rocks frequently exhibit recognisable bedding or layering.

Although they began as a different kind of rock, metamorphic rocks have undergone significant alteration from their igneous, sedimentary, or previous metamorphic forms. When rocks are exposed to extreme temperatures, high pressures, hot mineral-rich fluids, or, more frequently, some combination of these conditions, metamorphic rocks are created.

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The eight large, round bodies in the solar system that orbit, or revolve, around the sun and are usually ordered according to their distances from the sun are called planets.

These planets are classified as either terrestrial or gas giants. The terrestrial planets, which are closer to the sun, consist of Mercury, Venus, Earth, and Mars, they are characterized by their rocky composition and solid surfaces. The gas giants, located further from the sun, include Jupiter, Saturn, Uranus, and Neptune.

These planets are predominantly composed of gases, such as hydrogen and helium, and possess a more massive size compared to terrestrial planets, they also have numerous moons and ring systems. The order of the planets from the sun is Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune. The distances between these planets and the sun, as well as their distinct compositions and characteristics, play a vital role in shaping the diverse environments found within our solar system. So therefore planets are the eight large, round bodies in the solar system that orbit, or revolve, around the sun and are usually ordered according to their distances from the sun,

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Answer:

false : In distance time graph,time is shown on the x -axis

Answer: 00.99m

Explanation:

because

Answer: 0.099

Explanation: Khan

Answer:

9996kg.m/s

Explanation:

∆p=mv. 1200kg*8.33m/s

The approximate momentum of this car is 9,996 Kgm/s.

Given the following data:

To determine the approximate momentum of this car;

Momentum refers to the product of the mass possessed by an object and its velocity.

Mathematically, momentum is giving by the formula;

\(Momentum = mass \times velocity\)

Substituting into the formula, we have;

\(Momentum = 1200 \times 8.33\)

Momentum = 9,996 Kgm/s.

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To determine the reject rate (RR) for each scenario, we need to consider the capability indices Cp and Cpk along with the specifications for tensile strength. The reject rate represents the proportion of parts that do not meet the specifications.

1. RR = 0.27%

2. RR = 16.03%

3. RR = 0%

4. RR = 0.003%

5. RR = 0.27%

6. RR = 2.28%

7. RR = 29.93%

8. RR = 0%

9. RR = 5.87%

Please note that these calculations assume a normal distribution of tensile strength and that the process is in statistical control. The reject rate is obtained by evaluating the proportion of values falling outside the specified limits based on the process capability indices Cp and Cpk.

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The statement that is true with respect to Faraday's law of induction is option C - the voltage induced depends on how quickly the area and magnetic field change.

Faraday's law states that the voltage induced in a coil is proportional to the rate of change of magnetic flux through the coil. Magnetic flux is the product of the magnetic field strength and the area of the loop within which the magnetic field is penetrating.

Therefore, a change in either the magnetic field strength or the area of the loop will result in a change in magnetic flux, which in turn will induce a voltage in the coil. The faster the change in magnetic flux, the greater the induced voltage will be.

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We have that The Density and Volume is given as

\(\rho=0.67\\\\\V=30cm^3\)

The factors that affect Density are Mass and Volume

From the question we are told that

The piece of wood shown above has a mass of 20 grams.

Wood parameters

2cm

5cm

3cm

Generally the equation for the Volume  is mathematically given as

\(V=L*B*H\\\\\V=2*5*3\\\\V=30cm^3\)

Generally the equation for the Density is mathematically given as

\(\rho=\frac{m}{v}\\\\\\rho=\frac{20}{30}\\\\\rho=0.67\)

Therefore the factors that affect Density are Mass and Volume

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The magnitude of the external magnetic field is approximately 0.194 Tesla.

To solve this problem, we can use the equation for the magnetic force on a current-carrying wire:

F = BILsinθ

where F is the magnetic force, B is the magnitude of the magnetic field, I is the current, L is the length of the wire, and θ is the angle between the wire and the magnetic field.

Given:

Length of the wire, L = 0.19 m

Current, I = 7.6 A

Angle, θ = 17°

Force, F = 6.2 x \(10^{-3}\)N

Substituting the given values into the equation, we have:

6.2 x \(10^{-3}\) N = B * 0.19 m * 7.6 A * sin(17°)

Simplifying the equation, we can solve for B:

B = (6.2 x \(10^{-3}\) N) / (0.19 m * 7.6 A * sin(17°))

Calculating this expression, we find:

B ≈ 0.194 T

Therefore, the magnitude of the external magnetic field is approximately 0.194 Tesla.

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Answer:

https://earthobservatory.nasa.gov/features/EnergyBalance#:~:text=The%20atmosphere%20absorbs%2023%20percent,surface%20radiates%20only%2012%20percent.

Explanation:

Overcast and ominous sky windy conditions and a lot of rain. along the shore, large waves. storm swells are some of the weather changes before typhoon.

Tropical cyclones, often known as hurricanes or typhoons, are powerful circular storms that form over warm tropical waters and are distinguished by low air pressure, strong winds, and torrential rain.

Storm precursors start to show up. The ocean surf is around 4m (13 feet) in height and is coming in 7 seconds apart. The barometer is dipping slightly, the wind is blowing at 18–20 kmph. Large, white cirrus clouds may be seen gathering over the horizon. The horizon is gradually being engulfed by the approaching cloud cover.

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Answer:

01.

Explanation:

Half the acceleration. Its heavier and moves slower. If it moved the same acceleration, the forces would also have to be doubled since the mass was.

The distance of the image from the lens is e) 90 cm, and it is on the opposite side from the object.

According to the question, an object is 45 cm from a diverging lens with a focal length of -30 cm. We are asked to find the image's distance from the lens and the side of the lens it is on.

In order to solve the problem, we need to use the lens formula. The lens formula is as follows: 1/f = 1/v - 1/u where f is the focal length of the lens, v is the distance of the image from the lens, and u is the distance of the object from the lens.

We are given that u = -45 cm and f = -30 cm. Let's plug these values into the lens formula and solve for v.1/-30 = 1/v - 1/-45

Simplifying, we get:1/v = 1/-30 + 1/45 = -1/90 + 1/45 = 1/90v = 90 cmSince the value of v is positive, the image is on the opposite side of the lens from the object.

Therefore, the answer is option (e) 90 cm, on the opposite side from the object.

Answer: The distance of the image from the lens is 90 cm, and it is on the opposite side from the object.

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Answer:

Silicon Dioxide

Answer:

Silicon dioxide

Explanation:

Answer:

Astrophobia

Explanation:

heop it help

The NGC 3603 region of space is shown below. It is a cloud of gas and dust. Stars are forming in this cloud. The NGC 3603 be classified as a nebula. The correct option is A.

A tiny, ball-shaped nebula is known as a planetary nebula. It generates an ionized gas that is luminous. Large and typically erratic clouds are produced by diffuse nebulae.

Due to their big stars, they typically form a cluster of stars. a cloud of gas in space that can be seen in the night sky as a vaguely discernible brilliant patch, as something black, or as a shadow against other luminous objects.

Dust and gases, primarily hydrogen and helium, make up nebulae. The mass of gas and dust eventually grows so large that it is forced to collapse by gravity. The material in the cloud's core heats up as a result of the collapse, and this hot core is the start of a star.

Therefore, the correct option is A. As a nebula.

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Answer:i dont think so

Explanation:

To determine the number of half-lives that have elapsed, we need to compare the ratio of 14C to 14N atoms found in the hip bone fragment.

The ratio of 1 14C atom for every 31 14N atoms suggests that the hip bone fragment contains a smaller amount of 14C compared to the expected ratio found in a living organism. Since 14C undergoes radioactive decay with a half-life of approximately 5730 years, we can calculate the number of half-lives that have elapsed by observing how many times the ratio needs to double to reach the expected ratio.

In this case, if the expected ratio is 1:1, then the observed ratio of 1:31 would require five doublings to reach 1:1. Therefore, approximately five half-lives have elapsed since the death of the organism from which the hip bone fragment originated.

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To calculate the mass of the other star in the binary system, we can use Kepler's Third Law, which relates the orbital period and semi-major axis of a binary system to the masses of the stars. Therefore, the mass of the other star in the binary system is approximately 0.781 solar masses.

Kepler's Third Law states that the square of the orbital period (T) is proportional to the cube of the semi-major axis (a) of the orbit:

T² = (4π² / G) × (a³ / (M₁ + M₂))

Converting the given values:

T = 323 × 365.25 × 24 × 3600 seconds (to convert years to seconds)

a = 1.10E+10 km × 10³ (to convert km to meters)

Now we can solve for M₂:

T² = (4π² / G) × (a³ / (M₁ + M₂))

Substituting the given values and solving for M2:

(M1 + M2) = (4π² / G) × (a³ / T²)

M2 = [(4π² / G) × (a³ / T²)] - M1

Using the appropriate values for π and G:

π ≈ 3.14159

G ≈ 6.67430 × 10⁻¹¹ m³ kg⁻¹ s⁻²

Substituting the values and calculating:

M2 = [(4 × (3.14159)² / (6.67430 × 10⁻¹¹)) × ((1.10E+10)³ / (323 × 365.25 × 24 × 3600)²)] - 0.800 solar masses

Let's evaluate the equation to calculate the mass of the other star (M2) in solar masses. Using the given values:

π ≈ 3.14159

G = 6.67430 × 10⁻¹¹ m³ kg⁻¹ s⁻²

a = 1.10E+10 km × 10³ (converted to meters)

T = 323 × 365.25 × 24 × 3600 seconds

M1 = 0.800 solar masses

Substituting the values into the equation:

M2 = [(4 × (3.14159)² / (6.67430 × 10⁻¹¹)) × ((1.10E+10)³ / (323 × 365.25 × 24 × 3600)²)] - 0.800 solar masses

Calculating the equation using a calculator or computational software:

M2 = 0.781 solar masses

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a. The minimum inductance of the tank circuit is 56.85 H

b. The maximum inductance of the tank circuit is 199.86 H

The resonant frequency of a series RLC circuit is given by

f = 1/2π√LC where

Making L subject of the formula, we have

L = (2πf)²/C

The minimum inductance of the tank circuit is 56.85 H

To find the minimum inductance, we substitute the value of

L = (2πf)²/C

L = (2π × 4.8 × 10⁻⁶ Hz)²/1.6 × 10⁻¹¹ F

L = (9.6π × 10⁻⁶ Hz)²/1.6 × 10⁻¹¹ F

L = (30.159 × 10⁻⁶ Hz)²/1.6 × 10⁻¹¹ F

L = 909.583 × 10⁻¹² Hz²/1.6 × 10⁻¹¹ F

L = 568.489 × 10⁻¹ H

L = 56.8489 H

L ≅ 56.85 H

The minimum inductance of the tank circuit is 56.85 H

The maximum inductance of the tank circuit is 199.86 H

To find the maximum inductance, we substitute the value of

L = (2πf)²/C

L = (2π × 9.0 × 10⁻⁶ Hz)²/1.6 × 10⁻¹¹ F

L = (18π × 10⁻⁶ Hz)²/1.6 × 10⁻¹¹ F

L = (56.549 × 10⁻⁶ Hz)²/1.6 × 10⁻¹¹ F

L = 3197.75 × 10⁻¹² Hz²/1.6 × 10⁻¹¹ F

L = 1998.59 × 10⁻¹ H

L = 199.859 H

L ≅ 199.86 H

The maximum inductance of the tank circuit is 199.86 H

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The increment in entropy during the mixing of the two gases is given by R times the sum of the logarithmic terms involving the volume ratios and the respective number of molecules of each gas.

To find the increment in entropy during the mixing of two different perfect gases, we can consider the entropy change of each gas individually and then sum them up.

The entropy change for an ideal gas can be expressed as:

ΔS = nR ln(Vf/Vi)

Where ΔS is the change in entropy, n is the number of moles of gas, R is the ideal gas constant, and Vf/Vi is the ratio of final volume to initial volume.

Initially, gas 1 occupies volume V1 and gas 2 occupies volume V2, so their total initial volume is V1 + V2.

For gas 1:

ΔS1 = (N1 / N) * nR ln[(V1+V2) / V1]

For gas 2:

ΔS2 = (N2 / N) * nR ln[(V1+V2) / V2]

Since the two gases are at the same temperature and pressure, their number of moles and the ideal gas constant are the same, so we can simplify the expressions:

ΔS1 = N1R ln[(V1+V2) / V1]

ΔS2 = N2R ln[(V1+V2) / V2]

The total change in entropy is the sum of the individual changes:

ΔS_total = ΔS1 + ΔS2

= N1R ln[(V1+V2) / V1] + N2R ln[(V1+V2) / V2]

= R [N1 ln((V1+V2) / V1) + N2 ln((V1+V2) / V2)]

Therefore, the increment in entropy is R times the sum of the logarithmic terms involving the volume ratios and the respective number of molecules of each gas.

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The acceleration due to gravity (g) is calculated from the length (L) of the pendulum and the period (T) of the swing.

A pendulum is a simple harmonic oscillator that oscillates back and forth with a constant amplitude about its equilibrium position. Its motion is governed by the laws of motion and energy conservation, and it is characterized by its period.

Therefore, given a simple pendulum of length 2.00m used to measure the acceleration of gravity at the surface of a distant planet, with the period of such a pendulum being 7.00s, what is the acceleration of gravity of that planet?

Period of a simple pendulum, T = 2π√(L/g)

Where,

T = period of a simple pendulum,

L = length of a simple pendulum,

g = acceleration of gravity at the surface of the planet

Rearranging the above formula to solve for g:

g = (4π²L)/T²

Substituting the values given into the equation:

g = (4π² * 2.00m) / (7.00s)²= 1.92 m/s²

Therefore, the acceleration due to gravity of that planet is 1.92 m/s².

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The equation relates the incident angle α and the refracted angle β for a light ray entering a rectangular block of glass is cos(α) = n × cos(β).

Snell's law states that the ratio of the sines of the angles of incidence (θ₁) and refraction (θ₂) is equal to the ratio of the velocities (or indices of refraction) of the light in the two media:

n₁ × sin(θ₁) = n₂ × sin(θ₂),

In the case of a light ray entering a rectangular block of glass. The index of refraction for air is 1.

Applying Snell's law, we have:

sin(θ₁) = n × sin(θ₂).

However, in this case, θ₁ is the angle of incidence measured from the normal to the surface, and θ₂ is the angle of refraction also measured from the normal to the surface. Let's denote the angle between the incident ray and the normal as α, and the angle between the refracted ray and the normal as β.

We can express θ₁ and θ₂ in terms of α and β as follows:

θ₁ = 90° - α,

θ₂ = 90° - β.

sin(90° - α) = n × sin(90° - β).

cos(α) = n × cos(β).

Therefore, The equation relates the incident angle α and the refracted angle β for a light ray entering a rectangular block of glass is cos(α) = n × cos(β).

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The complete question is:

Use Snell's law to prove that the incident angle of a light ray entering a rectangular block of glass is equal to the angle of the ray leaving the glass.