The intensity of an earthquake wave passing through the Earth is measured to be at a distance of 54 km from the source. (a) What was its intensity when it passed a point only 1.0 km from the source

Answers

Answer 1

Answer:

Intensity of an earthquake (passes 1 km) = 8,748 × 10⁶

Explanation:

Given:

Distance (r1) = 54 km

Distance (r2) = 1 Km

Note:

Intensity of an earthquake with 54 km distance is 3.0 × 10⁶ J/m²s is not given.

So,

Intensity of an earthquake with 54 km distance (I₁) = 3.0 × 10⁶ J/m²s

Find:

Intensity when it passed a point only 1.0 km .

Computation:

Intensity of an earthquake = (r1 / r2)² (I₁)

Intensity of an earthquake (passes 1 km) = (54 / 1)²(3.0 × 10⁶)

Intensity of an earthquake (passes 1 km) = (54)²(3.0 × 10⁶)

Intensity of an earthquake (passes 1 km) = 8,748 × 10⁶


Related Questions

A car travel from A to B at a speed of 30km per hour the average speed of the car the whole journey is?​

Answers

the formula is Speed=Distance/Time. I can help you if you give me the distance from A to B. Then you would dived that by time to get your speed.

An object experiencing uniform circular motion is accelerating. t/f

Answers

Answer:

According to Newton's second law of motion, a net force causes the acceleration of mass according to Fnet = ma. For uniform circular motion, the acceleration is centripetal acceleration: a = ac. Therefore, the magnitude of centripetal force, Fc, is F c = m a c F c = m a c .

Explanation:


A 10^3 kg load is placed on top of a lead bar of length 3.0 m. If the bar is compressed by 2.0
mm, calculate the cross-sectional area of the bar.

Answers

The cross-sectional area of the lead bar is \(9.188 \times 10^{-4} \ m^2\).

Young's modulus of lead bar

The Young's modulus (E)of lead bar is given as 1.6 x 10¹⁰ Pa.

Cross-sectional area of the bar

The cross-sectional area of the bar is calculated as follows;

\(E = \frac{stress}{strain} = \frac{F/A}{e/l} = \frac{Fl}{Ae} \\\\A = \frac{Fl}{Ee}\)

where;

A is cross-sectional areaF is applied force due to its weightE is Young's moduluse is compressionl is length

\(A = \frac{(mg) l}{Ee} \\\\A = \frac{(10^3 \times 9.8) \times 3}{1.6 \times 10^{10} \times 2 \times 10^{-3}} \\\\A = 9.188 \times 10^{-4} \ m^2\)

Thus, the cross-sectional area of the lead bar is \(9.188 \times 10^{-4} \ m^2\).

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what is a likely consequence of continued human population growth ​

Answers

Answer:

Rapid human population growth has a number of consequences. Population grows fastest in the world's poorest countries. High fertility rates have historically had a strong relation with poverty, and high childhood mortality rates

Explanation:

i got it from goo.gle but i hope that helps:)

have a good day bro

In a hydraulic press the large piston has cross-sectional area 230 cm2 and the small piston has cross-sectional area 5 cm2. If a force of 250 N is applied to the small piston, what is the force (in kN) on the large piston? Give the answer with one decimal an no unit.

Answers

The force on the larger piston of cross-sectional area 230 cm² is 11500 N.

What is force?

Force can be defined as the product of mass and acceleration.

To calculate the force on the larger piston, we use the formula below.

Formula:

F = fA/a............... Equation 1

Where:

F = Force on the larger pistonf = Force applied to the smaller pistonA = Cross-sectional  Area of the larger pistona = Cross-sectional Area of the smaller piston

From the question,

Given:

A = 230 cm²a = 5 cm²f = 250 N

Susbtitute these values into equation 1

F = (250×230)/5F = 11500 N

Hence, the force on the larger piston is 11500 N.

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A bat emits a sound with a frequency of 134 kHz in a cave where the temperature is 28°C. Assume that air behaves like an ideal monatomic gas and use the fact that the speed of sound in air at 20.0°C is 343 m/s to determine the wavelength of the sound emitted by the bat.

Answers

The wavelength of the sound is 2.6 x 10⁻³ m.

What is the wavelength of the sound?

The wavelength of the sound or distance travelled by the sound wave is calculated by applying the following formula.

v = fλ

λ = v / f

where;

v is the speed of the sound wave = 343 m/sf is the frequency of the sound wave = 134 kHzλ is the wavelength of the sound wave = ?

The wavelength of the sound is calculated as follows;

λ = v / f

λ = ( 343 m/s ) / ( 134,000 Hz )

λ = 2.6 x 10⁻³ m

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Two charged objects are separated by distance, d. The first charge has a larger magnitude (size) than the second charge. Which one exerts the most force?

Answers

Pretty sure the first one

A model rocket is launched straight upward with an initial
speed of 50.0 m/s. It accelerates with a constant upward
acceleration of 2.00 m/s2 until its engines stop at an alti-
tude of 150 m. (a) What is the maximum height reached
by the rocket? (b) How long after lift-off does the rocket
reach its maximum height? (c) How long is the rocket in
the air?

Answers

The maximum height reached by the model rocket is 300.5 metre. (b) Time to reach maximum height is 8.5 seconds and (c) the time for which the model rocket was in air is 17.3 seconds.

What are Newton's law of motion?

Newton's laws of motion are three basic laws of classical mechanics that describe the relationship between the motion of an object and the forces acting on it.

Given:

Initial velocity of the model rocket = 50m/s

Constant acceleration of rocket = 2 u

Height to which acceleration was in account= 150m

First we need to find the final velocity at 150 metres.

We can do so simply by using Newton's third law of motion,

Velocity at 150 metre = under root (2500 + 600)

Velocity at 150 meter = 55.7

Maximum height height reached by the model rocket can be find using the equation for max height.

.i.e. maximum height = u × u/2g + initial distance traveled

maximum height = 55.7×55.7/19.6 + 150

maximum height = 156.5 + 150

Maximum height= 300.5 m

Time taken to reach maximum height = time taken before acceleration stops + time after which acceleration stops

Time taken to reach maximum height = 5.7/2 + 55.7/9.8

Time taken to reach maximum height = 2.85 + 5.7

Time taken to reach maximum height = 8.5 seconds

The rocket will be air for the time = time to reach maximum height + time to fall to the ground

The rocket will be air for the time = 8.5+ 7.8

The rocket will be air for the time = 17.3 seconds.

Therefore, the maximum height reached by the model rocket is 300.5 meter, time to reach maximum height is 8.5 seconds and the time for which the model rocket was in air is 17.3 seconds.

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Your friend wants to join the school track team, and has asked for your help to determine how fast she can run. 4. What kind of information would you need to collect in order to help your friend?

Answers

Answer:

I think you would need too time your friend and know how too divide that time by other racers to see how much faster she needs to get. I THINK.

report of "fan made of plastic bottle" with string

Answers

Fan made of plastic bottle is an innovative way to reuse plastic bottles and can be easily made at home. This can be done by following simple steps, and a few materials are required to make it. The fan can be created by using a plastic bottle, scissors, string, a ruler, and a marker.

First, the bottle needs to be cut into half, and the upper part needs to be cut into three equal sections, then fold each section to make a blade. With the help of a ruler and marker, make a mark on each section, then make a hole in the center of each blade. Insert a string through the holes and tie the ends of the strings. The fan is ready to use by holding the string and swinging it back and forth.

The use of plastic bottle fans can significantly reduce the number of plastic waste and provide a practical solution to avoid environmental pollution. Besides, it is easy to make, and the materials are readily available, which can be used for various occasions, such as picnics, camping, or any outdoor activities.

In conclusion, the creation of a fan made of plastic bottle with string is an excellent way to reuse plastic bottles and can be made with simple steps. This project encourages everyone to contribute to environmental protection by utilizing what is available at home and reducing the number of plastic wastes.

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A student determines a value for a force using the formula F = k I l.
k is a constant with units of N A-1 m-1
I is current measured in mA
l is length measured in mm
The student uses the numbers directly from each measurement in their calculation.
What will be the units of the force from that calculation?

Answers

1 Newton force is equal to the 10⁻⁵ dynes. The unit of force will be dyne and the value of force will be 0.1 dynes.

What is force?

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration.

Its SI unit is Newton, MKS unit is kgm/s² and CGS unit is dyne.

The given formulae are;

F = k I l

k is a constant with unit=  N A-1 m-1

I is currently measured in mA = 10⁻³A

l is the length measured in mm= 10⁻³ m

F = k I l

F= N A-1 m-1× 10⁻³A×10⁻³ m

F= 10⁻⁶ N                 ( 1N = 10⁻⁵ dyne)

F= 0.1 dyne

Hence the unit of force will be dyne and the value of force will be 0.1 dynes.

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1. A force of 20 N is applied to extend a horizontal spring by 5 cm. What is the spring constant?
2. A spring has a spring constant of 15 N/cm. Which of the following hanging mass would produce an extension of 3.0 cm?

Answers

The spring constant is  400 N/m and The mass which would produce an extension of 3.0 cm is 0.0459 kg.

Here we are dealing with a problem related to hook's law which states that the force required to expand or compress a spring by a few distances is corresponding to that distance. This can be expressed scientifically as F= -kx, where F is the force connected to the spring and x is the displacement of the spring, with negative esteem illustrating the displacement of the spring once it is extended; and here k is the spring constant.

For the first case, we are given the force applied which is 20 N, and the extended length which is 5cm =0.05 m,

So the spring constant will be, k= F/x=  20/0.05 = 400 N/m

For the second  case we are given that the spring constant which is 15 N/m  and the extension is 3.0 cm =0.03 m.

Since we know F= mg ( where g is the acceleration due to gravity )

So the hanging mass, will be

=>F= kx

=>mg=kx

=>m=kx/g

      =15 x0.03/9.8

     = 0.0459 kg

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Suppose that you changed the area of the bottom surface of the friction cart without changing its mass, by replacing the Teflon slab with one that was smaller but thicker. The contact area would shrink, but the normal force would be the same as before. Would this change the friction force on the sliding cart

Answers

Answer:

in this case the weight of the vehicle does not change , consequently the friction force should not change

Explanation:

The friction force is a macroscopic manifestation of the interactions of the molecules between the two surfaces, this force in the case of solid is expressed by the relation

          fr = μ N

          W-N= 0

          N = W

as in this case the weight of the vehicle does not change nor does the Normal one, consequently the friction force should not change

a crate of mass 190 kg is being pulled along a horizontal, flat surface by a massless rope. the surface has known coefficients of friction, where the coefficient of kinetic friction is y?
If you keep pulling with the same tension, what is the acceleration of the crate?

Answers

The rope's tension, the degree of friction factor, and also the mass of crate all affect the crate's acceleration.

How does friction work in simple physics?

Between contacting materials that are sliding or attempting to slide over one another, there's an external force called friction. For illustration, friction makes it challenging to push a book down the floor.

Net force is equal to the sum of the resistive and rope forces.

The applied load is the same as the weight of crate, or mg, with g is the speed from gravity when m is the container's mass because the floor is straight and the object is not moving upwards.

In this case, the amount of contact is given by:

frictional force = y * mg

where y represents the kinetic friction coefficient.

When everything is added, we have:

net force is equal to T-y*mg.

Using Newton ’s second as well:

T-y*mg = ma

where a represents the crate's acceleration.

Solving for a, we get:

a = (T - y * mg) / m

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What is the mass of 12 m3 of methylated spirit whose relative density is 0.8 ? ( Hint the density of water = 1000 kgm-3 ) A. 9600 kg B.9400 kg C. 8600 kg

Answers

ANSWER

A. 9600 kg

EXPLANATION

Given:

• The volume of the substance, V = 12m³

,

• The relative density of the substance, 0.8

,

• The density of water, 1000 kg/m³

Unknown:

• The mass of the substance, m

The relative density of a substance is defined as,

\(\rho_{relative}=\frac{\rho_{substance}}{\rho_{water}}\)

And the density of a substance is,

\(\rho=\frac{m}{V}\)

Let's solve the first formula for the density of the substance,

\(\rho_{substance}=\rho_{relative}\cdot\rho_{water}=0.8\cdot1000\operatorname{kg}/m^3=800\operatorname{kg}/m^3\)

Then, solve the second formula for m,

\(m=\rho\cdot V=800\operatorname{kg}/m^3\cdot12m^3=9600\operatorname{kg}\)

Hence, the mass of this substance is 9600 kg

When is the kinetic energy of an electron transformed into potential energy?

when it interacts with other electrons, decreasing its speed
when it interacts with neutrons without changing its speed
when it interacts with other electrons without changing its speed
when it interacts with neutrons, increasing its speed

Answers

The kinetic energy of an electron transformed into potential energy when it interacts with other electrons without changing its speed.

What is kinetic energy?

The average kinetic energy (KE) is defined as the one-half of the mass of each gas molecule times multiplied by the square of RMS velocity.

\(\rm {KE = \frac{1}{2} mv^2}\)

where,

KE is the kinetic energy

m is the mass of each molecule

(V)rms is the RMS velocity

According to the law of conservation of energy, kinetic energy gets converted into potential energy. In that case, speed does not play a major role.

When an electron collides with the other electron Its energy gets transferred to the other electrons. The moving electrons get stuck and come to rest.

Hence the kinetic energy of an electron transformed into potential energy when it interacts with other electrons without changing its speed.

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ighth grade F.1 Identify reactants and products MGX
This passage describes a chemical reaction. Read the passage. Then, answer the question
below.
The cheesemaking process sometimes includes a step called lactic acid fermentation.
This step occurs when a certain type of bacteria is added to milk. The bacteria form
lactic acid (C3H603) by combining water (H₂O) and lactose (C12H22011) in the milk.
When lactic acid forms, the milk's proteins clump into curds that can later be used to
make many types of cheese.
In the chemical reaction described in the passage, which of the following are reactants?
Select all that apply.
water (H₂O)
lactose (C12H22011)
Submit
lactic acid (C3H603)
00
HR
Q
ar
Cha
Stage
Get 5
in a

Answers

Okay so forming lactic acid from the combination of water and lactose. If you’re forming something, that is your product. What you use to form it would be your reactants. Thus, your reactants are water and lactose

4.2 Determine the reactions of the loads L and R. ↓ 5m
↓ 7 kN 6m 3 kN 4m R (8)​

Answers

The reaction of load L is 0 (no horizontal force), and the reaction of load R is 10 kN (vertical upward force).

How to find reaction?

To determine the reactions of the loads L and R, consider the equilibrium of the forces acting on the structure.

First, analyze the vertical equilibrium. The sum of the vertical forces must be zero:

ΣFy = R − 7 kN − 3 kN

ΣFy = 0

This gives:

R = 10kN

Next, analyze the horizontal equilibrium. The sum of the horizontal forces must be zero:

ΣFx = L

ΣFx = 0

This indicates that there is no horizontal force acting on the structure.

Therefore, the reaction of load L is zero (no horizontal force), and the reaction of load R is 10 kN (vertical upward force).

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Is frictional force the only example of non-conservative force?​

Answers

Answer: NO, there are many examples of non-conservative forces.

Explanation: Conservatives forces are special forces whose work is zero in a closed path.

Magnetic and Electric fields are Non- Conservative.

Hypersonic scramjet. On March 27, 2004, the United States
successfully tested the hypersonic X-43A scramjet, which flew at
Mach 7 (seven times the speed of sound) for 11 seconds. (b) How many kilometers
did the scramjet travel during its 11 second test?

Answers

25.487 km did the scramjet travel during its 11 second test.

Given that the scramjet travels at a speed seven times that of sound, speed v is equal to 7 x 331 m/s or 2317 m/s.

(A) We require the scramjet's travel time over a distance of

       d = 5000 km (5x10^6 m).

Using the formula

time taken = distance traveled/speed,

we can calculate the following:

(5x10^6)/2317 sec

= (5x10^6)/(23175x60) minute

= 5000000/139020 minutes

= 35.97 seconds

As 1 second equals 1/60 of a minute, Therefore, the travel time on Scramjet from San Francisco to New York will be 35.97 minutes.

(B) The distance covered by the Scramjet in 11 seconds must now be determined. as a result,

using speed, distance, and time relation.

Distance = Speed x Time

               = 7  x 331  x 11

                =  25487 m

Since 1 metre equals 1/1000 of a kilometer, 25487 m of 25.487 km

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A hockey puck attached to a horizontal spring oscillates on a
frictionless, horizontal surface. The spring has force constant 4.50 N/m and the oscillation period is 1.20 s. (a) What is the mass of the puck? (b) During an oscillation, the acceleration of the puck has maximum magnitude 1.20 m/s^2. What is the amplitude of the oscillation?
Answers:
(a) 0.164 kg
(b) 0.0438 m = 4.38 cm

Answers

(a) The mass of the puck is 0.16 kg

(b)  The amplitude of the oscillation is 4.3 cm.

What is the mass of the puck?

The mass of the puck is calculated by applying the formula for the period of the oscillation.

T = 2π √ ( m /k )

T / 2π = √ ( m /k )

T² / 4π² = m/k

m = k ( T² / 4π² )

where;

k is the spring constantT is the period of oscillationm is mass of the puck

The mass of the puck is calculated as;

m = 4.5 ( 1.2² / 4π²)

m = 0.16 kg

The amplitude of the oscillation is calculated as follows;

a = ω²A

where;

ω is the angular frequencyA is the amplitude a is the maximum acceleration

ω = √ ( k /m )

ω² = k / m

from this equation "a = ω²A" make amplitude "A" the subject of the formula.

A = a / ω²

A = (a) / (k / m)

A = ( 1.2 ) / ( 4.5 / 0.16)

A = (1.2) / ( 0.03556)

A = 0.043 m = 4.3 cm

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A force of 125N lifts a 10.0kg mass while gravity pulls down with a force of 100.0N. How long will it take for the mass to move 2.00 meters from rest

Answers

Explanation:

Hope this example helps you

Mark my example as brainalist

A force of 125N lifts a 10.0kg mass while gravity pulls down with a force of 100.0N. How long will it

Emory pushes the box with 20 Newtons of force. If the box is 4kg, how fast will the box accelerate?

Answers

F=ma
20N=4kg.a
a=5 N/kg

A basketball player throws a ball horizontally toward another player 10 meters away. If the ball is
traveling at a speed of 20 m/s, neglecting air friction, how long does it take for the ball to get to the
other player?
Thank you!!!

Answers

Answer:

It will take 0.46 seconds to reach home plate by ball.

Explanation:

How does the suns energy contibute to the movement of water in the water cycle

Answers

Explanation:

The sun is what makes the water cycle work. The sun provides what almost everything on Earth needs to go—energy, or heat. Heat causes liquid and frozen water to evaporate into water vapor gas, which rises high in the sky to form clouds... clouds that move over the globe and drop rain and snow.

Answer:

"The sun is what makes the water cycle work. ... Heat causes liquid and frozen water to evaporate into water vapor gas, which rises high in the sky to form clouds... clouds that move over the globe and drop rain and snow. This process is a large part of the water cycle."

Explanation:

A uniform solid cylindrical flywheel has a mass of 50 kg and a radius of 40 cm. The flywheel begins to rotate faster with an acceleration of 1.5 rad/s2. The kinetic energy of the flywheel after 1 minute of rotation is:
A. 16.2 KJ
B. 180 KJ
C. 40.5 KJ
D. 32.4 KJ

Answers

The kinetic energy of the flywheel after 1 minute of rotation, given that it has a mass of 50 and radius of 40 cm is 32.4 KJ (Option D)

How do I determine the kinetic energy?

We'll begin by obtaining the velocity of the flywheel. This is shown below:

Radius (r) = 40 cm = 40 / 100 = 0.4 mAcceleration (a) = 1.5 rad/s² = 1.5 × 0.4 = 0.6 m/s²Time (t) = 1 minute = 1 × 60 = 60 sVelocity (v) = ?

v = at

v = 0.6 × 60

v = 36 m/s

Finally, we shall determine the kinetic energy of the flywheel. Details below:

Mass (m) = 50 KgVelocity (v) = 36 m/sKinetic energy (KE) =?

KE = ½mv²

KE = ½ × 50 × 36²

KE = 25 × 1296

KE = 32400 J

Divide by 1000 to express in KJ

KE = 32400 / 1000

KE = 32.4 KJ

Thus, the kinetic energy is 32.4 KJ (Option D)

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What will happen to the property of the electromagnet with an increasing number of coils

Answers

The number of turns determines the strength; whether the core is made of soft or hard magnetic material. Soft iron is more easily magnetized than steel. As a result, using a soft core increases the electromagnet's strength.

What is magnetic field ?

The magnetic field is mathematically described as a vector field. This vector field can be directly plotted as a grid of many vectors. Each vector points in the same direction as a compass and has a length proportional to the strength of the magnetic force. This technique is demonstrated by arranging many small compasses in a grid pattern and placing the grid in a magnetic field. The only difference is that a compass does not indicate field strength. Field lines are another way to represent the information contained within a vector field. We remove the grid pattern and connect the vectors with smooth lines. We are free to draw as many lines as we want.

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albet or cory .........

Answers

Answer:

cory

Explanation:

Answer: BABY YODA FOR LIFE

Explanation: Because I said so!

7. State condition of equilibrium when a borly is acted upon by a number of parallel forces. A uniform metal tube of length 5cm and mass 9 kg is suspended horizontally by two vertical wire attaches at 50cm and 150cm respectively from the ends of the tuber Find the tension in each wire. in tril Solution -​

Answers

According to the question the tension in each wire is 1.96 N.

What is tension?

Tension is a term that describes the psychological and physical state of a person or system in which there is a high degree of stress, uncertainty, and anxiety. It is often associated with conflict and is often experienced when individuals or groups feel threatened or constrained in some way. Tension can be experienced in a variety of different contexts, from interpersonal relationships to the workplace. It can result from a variety of different factors, including a lack of communication, conflicting goals or expectations, and unmet needs.

The body is in equilibrium when the sum of all forces acting on it is equal to zero. In this case, the forces acting on the metal tube are the two wires and the weight of the tube due to gravity.

The tension in each wire is equal to the weight of the tube divided by the length of the tube. This is because the tube is suspended horizontally, so the forces in each wire must be equal in order to keep the tube in equilibrium.

Therefore, the tension in each wire is:

T = (9 kg × 9.8 m/s2) / (5 cm × 0.01 m)

= 1.96 N

Therefore, the tension in each wire is 1.96 N.

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A 3.1 kg ball is thrown straight upward with a speed of 18.2 m/s. Use conservation of energy to calculate the maximum height the ball can reach.

Answers

Answer:

h = 16.9 m

Explanation:

When a ball is thrown upward, its velocity gradually decreases, until it stops for a moment, when it reaches the maximum height, while its height increases. Thus, the law conservation of energy states in this case, that:

Kinetic Energy Lost by Ball = Potential Energy Gained by Ball

(0.5)m(Vf² - Vi²) = mgh

h = (0.5)(Vf² - Vi²)/g

where,

Vf = Final Speed of Ball = 0 m/s (Since, ball stops for a moment at highest point)

Vi = Initial Speed of Ball = 18.2 m/s

g = acceleration due to gravity = - 9.8 m/s² ( negative for upward motion)

h = maximum height the ball can reach = ?

Therefore, using values in the equation, we get:

h = (0.5)[(0 m/s)² - (18.2 m/s)²]/(-9.8 m/s²)

h = 16.9 m

Other Questions
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