The introduction of steel into the nineteenth-century industrial age changed the architectural style and scale forever.
What is steel?Steel can be defined as hard, strong, tough grey (bluish-grey) alloy of iron and carbon that is typically used as a structural and fabricating material in Civil engineering and architecture.
During the industrial age of the nineteenth-century, the introduction of steel changed the architectural style and scale forever.
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what acts like shock absorbers in the bottom of buildings
In the context of buildings, structures designed to mitigate the effects of seismic activity or strong winds are commonly referred to as seismic or base isolators.
These isolators act as shock absorbers to reduce the transmission of vibrations and energy from the ground to the building. Seismic or base isolators typically consist of various materials or devices that can absorb and dissipate energy. Some commonly used types of isolators include:
1. Rubber or Neoprene Bearings: These are made of rubber or neoprene pads that provide flexibility and damping to absorb and dissipate energy during seismic events.
2. Sliding Bearings: Sliding bearings allow the building to slide horizontally on a low-friction surface, such as PTFE (polytetrafluoroethylene). This sliding motion helps to reduce the transfer of seismic forces to the building.
3. Fluid Dampers: Fluid dampers utilize the properties of viscous fluid to absorb and dissipate energy. They consist of cylinders filled with a viscous fluid that flows through small orifices, generating resistance against the motion caused by seismic forces.
4. Steel Springs: Steel springs can be used as shock absorbers to reduce the impact of seismic or wind loads. They provide flexibility and absorb energy by deforming under the applied forces.
These seismic or base isolators are strategically placed at the base or foundation of the building to reduce the transfer of vibrations and energy. By incorporating these shock-absorbing mechanisms, buildings can better withstand seismic events and minimize structural damage.
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A balanced star-connected three-phase load is shown in Figure 4. Determine the value of the line currents IR,IY and IB using mesh-current analysis.
Answer:
Therefore the value of the line currents IR, IY, and IB are
\(I_{R}=I_{1}=83\angle 6.87^{o}A\\I_{B}=-I_{2}=-71.88\angle-23.13^{o}A\\I_{Y}=I_{2}-I_{1}\\I_{Y}=-I_{2}=41.50\angle113.3^{o}A\)
Explanation:
Apply KVL for loop 1
\(415\angle 120^{o}=\left ( 3+j4+3+j4 \right )I_{1}-\left ( 3+j4 \right )I_{2}\\415\angle 120^{o}=\left ( 6+j8 \right )I_{1}-\left ( 3+j4 \right )I_{2}\\415\angle 120^{o}=\left ( 10\angle 53.13^{o} \right )I_{1}-\left ( 5\angle 53.13^{o}\right )I_{2} \rightarrow \left ( 1 \right )\)
Apply KVL for loop 2
\(415\angle 0^{o}=\left ( 3+j4+3+j4 \right )I_{2}-\left ( 3+j4 \right )I_{1}\\415\angle 0^{o}=\left ( 6+j8 \right )I_{2}-\left ( 3+j4 \right )I_{1}\\415\angle 0^{o}=\left ( 10\angle 53.13^{o} \right )I_{2}-\left ( 5\angle 53.13^{o}\right )I_{1} \rightarrow \left ( 2 \right )\)
Solving the above equations,
\(415\angle 120^{o}+830\angle 0^{o}=\left ( 10\angle 53.13^{o} \right )I_{1}-\left ( 5\angle 53.13^{o}\right )I_{2} +\left ( 20\angle 53.13^{o}\right )I_{2}- \left ( 10\angle 53.13^{o} \right )I_{1}\\415\angle 120^{o}+830\angle 0^{o}=\left ( 20\angle 53.13^{o}\right )I_{2}- \left ( 10\angle 53.13^{o} \right )I_{2}\\415\angle 120^{o}+830\angle 0^{o}=\left ( 10\angle 53.13^{o} \right )I_{2}\\I_{2}= 71.88\angle -23.13^{o}A\)&
\(415\angle 0^{o}=\left ( 10\angle 53.13^{o} \right ) \times 71.88\angle -23.13^{o}-\left ( 5\angle 53.13^{o} \right )I_{1}\\415\angle 0^{o}=718.8\angle 30^{o}-\left ( 5\angle 53.13^{o} \right )I_{1}\\\left ( 5\angle 53.13^{o} \right )I_{1}=415\angle 60^{o}\\I_{1}= 83\angle 6.87^{o}A\)
Hence,
\(I_{R}=I_{1}=83\angle 6.87^{o}A\\I_{B}=-I_{2}=-71.88\angle-23.13^{o}A\\I_{Y}=I_{2}-I_{1}\\I_{Y}=-I_{2}=41.50\angle113.3^{o}A\)
Where you attend college could costmore to borrow and refinance loans
the high-pressure water at 1.5 mpa, 180 c is throttled into a chamber that forms liquid and vapor at a lower pressure of 800 kpa (called flash evaporator). the liquid is discarded while the saturated vapor feeds a two-stage adiabatic turbine, 10% of the entering vapor mass is bled from the turbine at 300 kpa and 150c, the remaining steam leaves the turbine at 10kpa, 90% quality. if the total turbine shaft works is 1 mw, please find the following specific values required to operate this system:
To find the specific values required to operate this system, we'll go through the following steps:1. Determine the enthalpy at the initial state (high-pressure water at 1.5 MPa, 180°C) using steam tables or a steam property calculator.
2. Determine the enthalpy at the final state (saturated vapor at 10 kPa, 90% quality) using steam tables or a steam property calculator.3. Calculate the mass flow rate of the steam entering the turbine using the given total turbine shaft work (1 MW) and the enthalpy difference between the initial and final states.
4. Calculate the mass flow rate of the bled steam (10% of entering vapor mass) using the previously calculated mass flow rate.5. Calculate the specific volume of the bled steam at 300 kPa and 150°C using steam tables or a steam property calculator.
Now let's go through each step in detail:
Step 1: Determine the enthalpy at the initial state.- Find the specific enthalpy of water at 1.5 MPa, 180°C using steam tables or a steam property calculator.Step 2: Determine the enthalpy at the final state.- Find the specific enthalpy of saturated vapor at 10 kPa, 90% quality using steam tables or a steam property calculator.\Step 3: Calculate the mass flow rate of the steam entering the turbine.- Calculate the enthalpy difference between the initial and final states.- Use the given total turbine shaft work (1 MW) and the enthalpy difference to calculate the mass flow rate using the formula: mass flow rate = total turbine shaft work / (enthalpy difference).
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When 2 cars a and b are next to one another, they are traveling in the same dierection with speeds va and vb, respectively. If b maintains its constant speed, while a begins to decelerate at a a, determine the distance d between the cars at the instant a stops
Let us take the initial distance between car A and B as d₀. Let the time taken by car A to stop after it starts decelerating at a be t seconds. Now, the acceleration of car A = a (given), which is constant and negative (because it is decelerating).
Therefore, the velocity of car A after t seconds, vA
= uA + at
= va – at …(1) (where uA
= va is the initial velocity)The distance traveled by car A after t seconds, dA
The velocity of car B, vb, remains constant at vb throughout. So, the distance traveled by car B during this time t,
dB = vb × t …(3)
Now, we can use the equation of motion: for calculating the distance traveled by car A and B, respectively, where s = d₀ (initial distance between the cars) – d (distance between the cars at time t).Applying the equation to car A,
dA = (va + vA)t/2
= (va + va - at)t/2
= (2va - at)t/2
= va × t - (1/2)at² …(4) (using equation (1))
Applying the same equation to car B,
dB = (vb + vb)t/2
= vb × t …(5) (using equation (3))
We know that when car A stops, its velocity vA = 0.So, from equation (1), we get t = va/a. Substituting this value of t in equation (4) and (5), we get:dA = va²/2a …(6)and dB = vb × va/a …(7). Subtracting equation (7) from (6), we get the distance d between the cars at the instant car A stops.
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to do you blur text in google docs
Answer:
I dont think you can blur text in google docs
After execution of the code fragment
class rectangle
{
public:
void setData(int, int); // assigns values to private data
int getWidth() const; // returns value of width
int getLength() const; // returns value of length
rectangle(); // default constructor
private:
int width; // width of the rectangle
int length; // length of the rectangle
};
// copies the argument w to private member width and l to private member length.
void rectangle::setData(int w, int l)
{
width = w;
length = l;
}
// returns the value stored in the private member width.
int rectangle::getWidth() const
{
return width;
}
// returns the value stored in the private member length.
int rectangle::getLength() const
{
return length;
}
// Default constructor.
rectangle::rectangle()
{
width = 0;
length = 0;
}
int main()
{
rectangle box1, box2, box3;
int x = 4, y = 7;
box1.setData(x,x);
box2.setData(y,x);
cout << box1.getWidth() + box1.getLength();
return 0;
}
what is displayed on the screen?
The expression `box1.getWidth() + box1.getLength()` evaluates to `4 + 4`, which is `8`. Therefore, the output displayed on the screen will be:
8
After execution of the code fragment class what is displayed on the screen?The code provided creates three instances of the `rectangle` class named `box1`, `box2`, and `box3`. It then sets the data for `box1` and `box2` using the `setData` function, passing `x` and `y` as arguments.
In the `main` function, `box1.getWidth()` returns the value stored in the private member `width` of `box1`, which is `4`. Similarly, `box1.getLength()` returns the value stored in the private member `length` of `box1`, which is also `4`.
The expression `box1.getWidth() + box1.getLength()` evaluates to `4 + 4`, which is `8`.
Finally, the `cout` statement outputs `8` to the screen.
Therefore, the output displayed on the screen will be:
8
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which of these is a characteristic of and application A it manages communication with the hardware. B it maintains the user interface. C it is essential to the computer's operation. D it helps the user perform an activity they want to do
Answer:
The answer is D
Explanation:
The characteristic of an application is it helps the user perform an activity they want to do. The correct option is D.
What is an application?An application program is a computer program that is designed to perform a specific activity that is not related to the operation of the computer itself and is typically utilized by end users. Examples include word processors, media players, and accounting software.
The different types of applications: are web, native, cross-platform, hybrid, etc. Scalability, portability, robustness, and agility are four fundamental features and functionalities that modern applications must have. Scalability: Today, we require apps that can scale to millions of people worldwide on demand.
Therefore, the correct option is D, it helps the user perform an activity they want to do.
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An oil well is producing 30°API oil was tested along three days at a rate of 214 STB/day and the stabilized wellbore flowing pressure is measured as 3712 psia. Since the well is recently opened to production, water cut is negligible. The average reservoir pressure is 4350 psia and the IPR exponent is 0.82. The current IPR may be written as 0.82 P Pwf %o=6231- PR Additional data is given below Wellhead flowing pressure 400 psia Tubing length 10,000 ft 3.5 in. Nominal Tubing size (2.75 in. internal) GOR (since no water 600 SCF/STB production GLR=GOR) Wellhead temperature 100°F Bottomhole temperature 240°F Gas specific gravity 0.68 Water specific gravity 1.05 Mol fr. N₂ 0.004 Mol fr. CO2 0.011 Bw 1.2 Bbl/STB Using Poettman and Carpenter method to find the tubing intake pressure at 10,000 ft and fill out the following table, plot IPR and TPR on the same graph and find the point of natural flow (q.) and corresponding flowing bottomhole pressure (Pwt). IPR P&C TPR qo Pwf 4350 4000 3500 3000 2500 2000 1500 1000 500 0 qo 50 100 200 300 400 500 600 Pintake
The given data is provided in the table below: Parameters Values Oil gravity, °API30 Stabilized flowing pressure, psia3712 Wellhead flowing pressure, psia400 Length of Tubing, ft10000 Nominal tubing size, in3.5 Inside diameter of tubing, in2.75 Gas specific gravity0.68 Water specific gravity1.05 Mol
Mol Fr. of CO2 in gas0.011 Bubble point pressure, psia2144 Solution gas ratio, scf/STB600 IPR exponent0.82 Bw, bbl/STB1.2 First, calculate the reservoir flow rate from the given production rate using the Vogel's equation:
The point of natural flow (q) and corresponding flowing bottom hole pressure (Pwf) can be determined from the intersection of IPR curve and TPR curve.
It can be observed that the intersection occurs at a flowing bottom hole pressure of around 4,130 psia and a liquid flow rate of around 156 STB/day. Therefore, the point of natural flow is at a flowing bottom hole pressure of 4,130 psia and a liquid flow rate of 156 STB/day.
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surveys are used whenever elevation data is required in the end product. some examples include (1) creating maps for highway ; (2) creating maps for construction blank; (3) creating maps for flood plain blank; (4) creating maps for site location of buildings; and so on.
Surveys provide detailed elevation data that is essential for accurate mapping, especially in areas with complex terrain.
What is Mapping?
Mapping is the process of creating a visual representation of an area. It involves taking geographical information and representing it on a two-dimensional plane. This can be done through various methods, such as drawing on a piece of paper, using a computer program, or using a GPS device. Mapping can be used to show the physical features of an area, such as roads, rivers, and mountains. It can also be used to display information such as population density, land use, and other data. For example, a map of a city can show which areas are most populated, or which areas have the highest crime rates.
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What is the most inexpensive and slow transportation mode? Air Carriers Water Carriers Rail Carriers Motor Carriers
Among the transportation modes mentioned, the most inexpensive and slow transportation mode is typically water carriers. Water carriers, such as ships, barges, and boats, offer the advantage of being able to transport large volumes of goods at a relatively low cost per ton-mile.
Water transportation is well-suited for bulk cargo and long-distance shipments. The cost-effectiveness of water carriers is primarily due to their ability to handle large volumes and take advantage of economies of scale.
However, water transportation is generally slower compared to other modes. Ships and barges have lower speeds compared to air, rail, or motor carriers. The speed of water carriers can be influenced by factors such as the size and type of vessel, the distance traveled, and the water conditions. It can take several days, weeks, or even months for goods to be transported by water carriers, depending on the specific route and circumstances.
In contrast, air carriers are the fastest mode of transportation but are also the most expensive due to high fuel costs, maintenance expenses, and limited cargo capacity. Air transportation is typically used for high-value and time-sensitive goods that require quick delivery.
Rail carriers offer a balance between cost and speed. They are generally more affordable than air carriers but faster than water carriers for long-distance transportation. Rail transportation is particularly suitable for moving heavy goods, bulk commodities, and intermodal shipments.
Motor carriers, such as trucks and trailers, provide flexibility and convenience for transportation. They are commonly used for short-distance and regional shipments. However, motor carriers tend to have higher costs per ton-mile compared to water and rail carriers.
In summary, water carriers are often the network of most inexpensive but slow transportation mode, offering cost advantages for long-distance bulk cargo shipments. The choice of transportation mode depends on factors such as the nature of the goods, distance, time constraints, and cost considerations.
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Determine the period of oscillations in trial i. We recommend starting at the equilibrium position. Even though the video is shot at 30 frames per second, it may be challenging to find the frame where the "x" is exactly lined up with the equilibrium. Do your best. Did we mention that you need to find the period for trial i?
To determine the period of oscillations in trial i, we need to first identify the equilibrium position, which is the point at which the object is at rest. This is usually a position where the object is in balance and does not move in either direction.
Once the equilibrium position has been identified, we need to measure the time it takes for the object to complete one full cycle of oscillation, from one peak to the next. This time period is referred to as the period of oscillation.
Since the video is shot at 30 frames per second, it may be challenging to find the exact frame where the "x" is exactly lined up with the equilibrium. However, we can make an estimate by observing the motion of the object in the video and using the 30 frames per second as a reference.
It is important to note that the period of oscillation is an important parameter for understanding the behavior of an oscillating system, as it determines the frequency of oscillation. The frequency of oscillation is defined as the number of cycles completed in a given unit of time, typically measured in Hertz (Hz).
In conclusion, to determine the period of oscillations in trial i, we need to first identify the equilibrium position and then measure the time it takes for the object to complete one full cycle of oscillation. Despite the challenge of finding the exact frame where the "x" is exactly lined up with the equilibrium, we can use the 30 frames per second as a reference to make an estimate.
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The introduction of this material into the nineteenth-century industrial age forever changed architectural style and scale. Group of answer choices mortar steel hexagonal plates precast concrete
The introduction of steel into the nineteenth-century industrial age changed the architectural style and scale forever.
What is steel?Steel can be defined as hard, strong, tough grey (bluish-grey) alloy of iron and carbon that is typically used as a structural and fabricating material in Civil engineering and architecture.
During the industrial age of the nineteenth-century, the introduction of steel changed the architectural style and scale forever.
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A gas has an initial volume o.25m^3, and absolute pressure 100kPa. Its initial temperature is 290k. The gas is compressed into a volume of o.O5m^3 during which its temperature rises to 405k. Calculate its final pressure using the formula . P1V1/T1=p2V2/t2
Answer:
698.3KpaExplanation:
Step one:
given data
V1=0.25m^3
T1=290k
P1=100kPa
V2=0.5m^2
T2=405k
P2=? final pressure
Step two:
The combined gas equation is given as
P1V1/T1=P2V2/T2
Substituting we have
(100*0.25)/290=P2*0.05/405
25/290=0.5P2/405
0.086=0.05P2/405
cross multiply
0.086*405=0.05P2
34.9=0.05P2
divide both sides by 0.05
P2=34.9/0.05
P2=698.3Kpa
Therefore the new pressure is 698.3Kpa when the gas is compressed
In Female, the twenty-third pair of chromosomes is called in in
The yield strength for an alloy that has an average grain diameter, d1, is listed above as Yield Stress 1 . At a grain diameter of d2, the yield strength increases Yield Stress 2. At what grain diameter, in mm, will the yield strength be 217 MPa
Complete Question:
Grain diameter 1 (mm) = 4.4E-02
Yield stress 1 (MPa) = 131
Grain diameter 2 (mm) = 7.7E-03
Yield Stress 2 (MPa) = 268
The yield strength for an alloy that has an average grain diameter, d1, is listed above as Yield Stress 1 . At a grain diameter of d2, the yield strength increases Yield Stress 2. At what grain diameter, in mm, will the yield strength be 217 MPa
Answer:
d = 1.3 * 10⁻² m
Explanation:
According to the Hall Petch equation:
\(\sigma_y = \sigma_0 + k/\sqrt{d} \\\)
At \(d_{1} = 4.4 * 10^{-2} mm\), \(\sigma_{y1} = 131 MPa = 131 N/ mm^2\)
\(131 = \sigma_0 + k/\sqrt{4.4 * 10^{-2}} \\k = 27.45 - 0.2096 \sigma_0\)
At \(d_{2} = 7.7 * 10^{-3} mm\), \(\sigma_{y2} = 131 MPa = 268 N/ mm^2\)
\(268 = \sigma_0 + (27.45 - 0.2096 \sigma_0)/\sqrt{7.7 * 10^{-3}} \\23.5036 = 27.47 - 0.1219 \sigma_0\\ \sigma_0 = 32.45 N/mm^2\)
k = 27.45 - 0.2096(32.45)
k = 20.64
At \(\sigma_y = 217 MPa\), reapplying Hall Petch law:
\(\sigma_y = \sigma_0 + k/\sqrt{d} \\\)
\(217 =32.45 + 20.64/\sqrt{d} \\217 - 32.45 = 20.64/\sqrt{d}\\184.55 = 20.64/ \sqrt{d} \\\sqrt{d} = 20.64/184.55\\\sqrt{d} = 0.11184\\d = 0.013 mm\)
d = 1.3 * 10⁻² m
in a regular expression, you can define two possible patterns for the same text string by joining different patterns using the _____ character. 13
In a regular expression, you can define two possible patterns for the same text string by joining different patterns using the "|" (pipe) character.
This character acts as an "OR" operator, allowing you to match either the pattern on the left side or the right side of the pipe.
The pipe character, represented by the symbol "|", is a special character used in various contexts, including computer programming, command-line interfaces, and regular expressions. Here are a few common uses of the pipe character:
Command-Line Interfaces: In Unix-like operating systems, the pipe character is used to redirect the output of one command as input to another command. For example, the command command1 | command2 takes the output of command1 and uses it as the input for command2Regular Expressions: In regular expressions, the pipe character is used as an "OR" operator. It allows you to specify multiple options or alternatives. For instance, the regular expression cat|dog matches either the word "cat" or the word "dog"Shell Scripting: In shell scripting, the pipe character is used to connect multiple commands, creating a pipeline. Each command's output becomes the input for the next command. This allows for powerful command combinations and data processingData Manipulation: In programming languages like Python, the pipe character is often used in libraries or frameworks to enable method chaining or data transformation operations. For example, the pandas library in Python provides the | operator for filtering and manipulating data frames.To know more about Unix OS, visit the link : https://brainly.com/question/29798419
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How does adding substances to wastewater allow engineers to get rid of harmful substances?
Answer:
disaffectant pro to curements.
Explanation:
disaffectants controls affected water circles ,by the means of managing wastewater through treatments ,that avoids harmful substance.
What is the relative density of air?
Answer:
approximately 1.225 kg/m^3
Explanation:
Which of the following state space searching algorithms is most likely find the solution first when it's done right O iterative deepening O depth first search O A' search O best first search
Among the given state space searching algorithms, A* search is most likely to find the solution first when it's done right. A* search is an informed search algorithm that combines the elements of both uniform cost search and best-first search algorithms.
It uses a heuristic function to estimate the cost of reaching the goal from a particular node. A* search evaluates each node based on the sum of the cost of reaching the node from the start and the estimated cost of reaching the goal from that node.
A* search expands the node with the lowest value of f(n). Thus, it combines the advantages of both uniform cost search and best-first search, avoiding the shortcomings of each. In particular, it avoids the excessive cost of uniform cost search, and the possibility of getting stuck in the local minimum of best-first search.
Therefore, A* search is most likely to find the solution first when it's done right, among the given state space searching algorithms.
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YALL BETTER NOT SPAM ME I WILL CALL THE COMPANY ON YALL
Answer:
I looked at the comments said oh h e double hockey sticks no
Explanation:
Urgent please help me...
affect the amount and rate the alcohol reaches the
bloodstream.
Answer:
Answer to the following question is as follows;
Explanation:
The amount of alcohol consumption can be influenced by a variety of things, including food.
The proportion and pace at which alcohol reaches the circulation is affected by drinking rate, body mass, and the size of the beverage. Alcohol enters your system as soon as it reaches that first sip, as per the National Institute on Drug Abuse and Alcoholism. After 10 minutes, the results are noticeable.
The sharpest bend that can be placed in a piece of metal without critically weakening the part is called the?
Answer:
minimum radius of bend.
Explanation:
The sharpest bend that can be placed in a piece of metal without critically weakening the part is called the minimum radius of bend.
determine the application of star connected network
Answer:
fijixuc uckyc7fmtjjr hcumffjmfumfnng
Answer:
a method of connecting polyphrase circuits in which one end of each phase line is connected to a common neutral point that may be connected to the earth as protection against lightning or to a wire to which all the other neutral points of the system are connected
Explanation:
Exposure to and/or storage near which of the following is considered harmful to aircraft tires?1. Low humidity.2. Fuel.3. Oil.4. Ozone.5. Helium.6. Electrical equipment.7. Hydraulic fluid.8. Solvents.
Exposure to or storage near certain elements and conditions can be harmful to aircraft tires. Among the mentioned factors, low humidity, fuel, oil, ozone, electrical equipment, hydraulic fluid, and solvents are particularly detrimental to tire integrity.
Low humidity can lead to increased static electricity and a higher risk of cracking in the rubber. Fuel, oil, and hydraulic fluid can cause the rubber to deteriorate, compromising the tire's strength and potentially leading to failures. Ozone is a potent oxidant that can cause rubber to degrade and crack, reducing its durability and lifespan.
Electrical equipment can generate ozone and electromagnetic fields, which may affect tire performance. Solvents can dissolve or weaken the rubber, leading to potential tire damage and a decrease in performance.
In contrast, helium is relatively inert and poses minimal risk to aircraft tires. However, it is not commonly encountered in the environments where aircraft tires are stored or used.
To ensure aircraft safety and maintain tire performance, it is essential to avoid exposing tires to these harmful factors. Proper storage, regular inspections, and timely maintenance can help prevent damage and extend the lifespan of aircraft tires.
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QUESTION 2 (15 Marks) (1) State three differences between the Field Effect Transistor (FET) and the Bipolar Junction Transistor (BJT). [3 marks] (ii) Draw the physical structure and device symbol for an n-channel JFET. [2 marks] (iii) What is meant by drain characteristics [2 marks] (b) Determine the drain current of an n-channel JFET having pinch-off voltage VP = -4 and drain-source saturation current IDSS-12mA at the following gate-source voltages (1) VGS-OV (ii) VGS=-2V 14 marks] (c) Calculate the transconductance, gm of a JFET having specified values of IDSS-12mA and VP-4V at bias points (1) VGS-OV and (ii) VGS -1.5V. (4 marks] QUESTION 3 (15 Marks) (a) (i) Mention four JFET parameters and explain any two [5 marks] (ii) Distinguish between depletion and enhancement MOSFET [2 marks] (b) For an n-channel enhancement MOSFET with threshold voltage of 2.5V, determine the current at values of gate-source voltage (1) VGS 4V and (ii) VGS-6V [k-0.3mA/V2] [4 marks] (e) Determine the values of transconductance for an n-channel enhancement MOSFET having threshold voltage VT-3V at the following operating points (i) 6V and (ii) 8V 14 marks] Examiner: Dr. Samuel Afoakwa/Ing. Sammy Obeng Addae/Mr. Nana Boamah
The paragraph related to transistor technologies covers questions about the differences between FET and BJT, the physical structure of an n-channel JFET, drain characteristics, JFET parameters, and the comparison between depletion and enhancement MOSFETs.
What are the main topics covered in the paragraph related to transistor technologies?This paragraph contains two separate questions related to transistor technologies, specifically Field Effect Transistors (FET) and Bipolar Junction Transistors (BJT).
In Question 2, the first part asks for three differences between FET and BJT, which could include variations in construction, operation principles, or characteristics. The second part requests a drawing of the physical structure and device symbol for an n-channel Junction Field Effect Transistor (JFET). Lastly, it inquires about the meaning of drain characteristics in relation to JFET.
Question 3 begins with the mention of four JFET parameters and requires an explanation of any two of them. The second part asks for a comparison between depletion and enhancement Metal-Oxide-Semiconductor Field Effect Transistors (MOSFET).
The third part requests the determination of current at different gate-source voltage values for an n-channel enhancement MOSFET with a given threshold voltage.The paragraph concludes by mentioning the examiners responsible for the questions.
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Use the Routh-Hurwitz criterion to find how many poles of the following closed-loop system, represented by the transfer function T(s), are in the RHP, in the LHP, and on the imaginary (jω) axis: T(s)=s6+s5−6s4+0s3−s2−s+6s3+7s2−21s+10
To apply the Routh-Hurwitz criterion to the given transfer function T(s), we first need to construct the Routh array:
s^6: 1 -6 6
s^5: 1 -1 -21
s^4: 6 10 0
s^3: 7 -21 0
s^2: 30 0 0
s^1: -21 0 0
s^0: 10 0 0
The first column of the Routh-Hurwitz array contains the coefficients of the even powers of s, while the second column contains the coefficients of the odd powers of s. If any element in the first column is zero, we replace it with a small epsilon value to avoid division by zero.
To determine the number of poles in the RHP, we count the number of sign changes in the first column of the Routh array. In this case, there are no sign changes, which means that all the poles are either in the LHP or on the imaginary axis.
To determine the number of poles on the imaginary axis, we count the number of sign changes in the first column of the Routh array after replacing any zero elements with epsilon. In this case, there is one sign change, which means that there is one pole on the imaginary axis.
To determine the number of poles in the LHP, we count the number of rows in the Routh array that have all positive elements. In this case, there are four such rows, which means that there are four poles in the LHP.
Therefore, the number of poles in the RHP is zero, the number of poles on the imaginary axis is one, and the number of poles in the LHP is four.
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A nutrunner on the engine assembly line has been faululing for low torque. (A nutrunner is an automated machine that automatically torques bolts to a specified condition.) When the fault odcurs, the line stops until someone can investigate or correct the issue. This has been a problem for the past two weeks, and all employees on the assembly line are having to work overtime each day to make up for the lost time from the nutrunner issues. Please explain and visualize the process you would take to solve or improve this problem.
A nutrunner on the engine assembly line has been failing for low torque. process includes identifying the root cause of the fault, and optimizing the nut runner's performance.
The first step would be to investigate the cause of the low torque issue in the nut runner. This may involve examining the machine, reviewing maintenance records, and gathering data on when and how the fault occurs. Once the root cause is identified, corrective actions can be taken. This may include repairing or replacing faulty components, recalibrating the nut runner, or updating software/firmware.
To prevent future occurrences, implementing a preventive maintenance program is crucial. Regular inspections, scheduled maintenance tasks, and performance testing can help identify and address potential issues before they lead to line stoppages. Additionally, providing thorough training to operators and maintenance staff on nutrunner operation, maintenance procedures, and troubleshooting techniques can contribute to quicker resolution of faults and reduce downtime.
Continuous monitoring of the nutrunner's performance is essential to ensure it operates within specified tolerances. This can be done through real-time data collection and analysis, including torque measurement and trend analysis. By closely monitoring the nutrunner's performance, any deviations or anomalies can be detected early, allowing for proactive interventions.
Overall, a systematic approach that combines investigation, preventive maintenance, employee training, and continuous monitoring can help solve the problem of the faulty nutrunner and improve the efficiency and productivity of the assembly line.
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is reinforcement learning an appropriate abstract model for evolution what connection exists if any between hardwired rewards signals and evolutionary fitness?
Reinforcement learning is a type of machine learning that involves training agents to take action in an environment in order to maximize a reward. In this sense, reinforcement learning can be seen as a model for how organisms learn and adapt to their environment in order to maximize their fitness.
However, reinforcement learning does not directly model the process of evolution. Evolution involves the process of natural selection, in which certain traits are passed on to future generations because they increase the reproductive success of the organisms possessing those traits. In contrast, reinforcement learning involves training agents to optimize their behavior based on immediate rewards, without necessarily considering the long-term reproductive success of the agent.
There is a connection between hardwired reward signals and evolutionary fitness in the sense that certain behaviors that are reinforced by reward signals may increase an organism's fitness. For example, an organism that is hardwired to seek out and consume nutritious food may have higher fitness than one that is not, because it is more likely to survive and reproduce. However, this connection is not explicitly modeled in reinforcement learning.
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