The large piston in a hydraulic lift has a radius of 20 cm. (a) What force must beapplied to the small piston of radius 2 cm to raise a car of mass 1500 kg? (b) When thecar is lifted by distance 20 cm, what is the work done by the force acting on the smallpiston?

Yep. Those three things are all electronic components.

There are a lot more besides those.

The machine is far less efficient because work output is much less than work input.

The major importance of engines is to help ensure that the work output is far greater than the work input. Thus a small  amount of energy ought to be used to achieve an enormous amount of work.

In this case, a smaller output is recorded for every energy energy input meaning that the machine is not efficient.

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To determine whether the image of the pencil is on the surface of the mirror or behind the mirror, we need to understand the concept of reflection. When light rays from an object (in this case, the pencil) hit a mirror, they bounce off and form an image. This image can either be virtual or real.

In the case of a mirror, the image formed is virtual, meaning it cannot be projected onto a screen. When you look at the image in the mirror, you are actually seeing the light rays that have bounced off the mirror and reached your eyes.
Now, let's address the two assertions. The statement that the image is on the surface of the mirror is not accurate. The image is not physically present on the mirror's surface. Instead, it appears to be located behind the mirror.
When you see the image in the mirror, it appears to be at the same distance behind the mirror as the object is in front of it. This is due to the nature of the reflection process.
Therefore, the correct assertion is that the image of the pencil is behind the mirror, not on its surface.

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(a) The distance travelled by the object is  100 m.

(b) The displacement of the object in time interval between t = 0 s and t = 10 s is 60 m.

(a) The distance travelled by the object is calculated from the total area of the curve.

total distance = area of triangle 1 + area of triangle 2 + area of rectangle.

total distance = (¹/₂ x base x height)₁ +  (¹/₂ x base x height)₂ + length x width

total distance = (¹/₂ x 6 s x 20 m/s) +  (¹/₂ (8 - 6) 20) + (10 - 0)(10 - 8)

total distance =  60 m + 20 m + 20 m

total distance = 100 m

(b) The displacement of the object in time interval between t = 0 s and t = 10 s is calculated as follows;

displacement = final position - initial position

displacement =  (¹/₂ x base x height)₁ +  (¹/₂ x base x height)₂ + length x width

displacement = (¹/₂ x 6 s x 20 m/s) +  (¹/₂ (8 - 6) (-20)) + (10 - 0)(10 - 8)

displacement = 60 m - 20 m + 20 m = 60 m

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Visible radiations are the electromagnetic radiation wavelength which is efficiently observed using ground based telescopes.

The electromagnetic waves we can for the most part see on the ground comprise of apparent light, which is challenging for the air to retain, close infrared beams, and a few electromagnetic waves. These frequency ranges are called air windows.

Noticeable light is a sort of electromagnetic radiation, which is sent in waves or particles at various frequencies and frequencies. This wide scope of frequencies is known as the electromagnetic range. That range is commonly separated into seven districts arranged by diminishing frequency and expanding energy and frequency.

A commonplace natural eye will answer frequencies from around 380 to around 750 nanometers. As far as recurrence, this compares to a band nearby 400-790 terahertz. These limits are not pointedly characterized and may differ per person. Under ideal circumstances these restrictions of human insight can stretch out to 310 nm (bright) and 1100 nm (close to infrared).

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Answer:

False, true

Explanation:

Answer:

an unbalanced force is always needed to a moving object FALSE

an object in motion will stay in motion unless it is acted on by an unbalanced force TRUE

Explanation:

Please Brainliest :)

To find the voltage of the combined drops, we can just add the voltage of both drops together.

2(235.15) = 470.3 Volts

Allowable Stress Design (ASD) and Load and Resistance Factor Design (LRFD) are two approaches used in structural engineering for designing structures. They have similarities in considering strength requirements, load types, material properties, structural elements, and structural safety. However, they differ in their design philosophies, basis for design, treatment of loads and resistances, load and resistance factors, design equations, and flexibility in design decisions.

Similarities:

Strength requirements: Both ASD and LRFD aim to ensure that structural elements have adequate strength to resist the applied loads.

Load types: Both methods consider various load types, such as dead loads, live loads, wind loads, seismic loads, etc., in their design calculations.

Material properties: Both ASD and LRFD account for material properties, such as yield strength, ultimate strength, modulus of elasticity, etc., in their design equations.

Structural elements: Both methods address different structural elements, such as beams, columns, connections, foundations, etc., and provide design guidelines specific to each element.

Structural safety: Both ASD and LRFD prioritize structural safety and aim to prevent failure or collapse under the anticipated loads.

Differences:

Basis for design: ASD is based on allowable stress limits, where the stress in a structural member should not exceed the allowable stress, while LRFD is based on the resistance of the member to loads and the reliability of that resistance.

Treatment of loads and resistances: ASD uses service loads directly and applies appropriate factors of safety to determine the allowable stress. LRFD treats loads as probabilistic and incorporates load factors to account for uncertainties in the applied loads, while resistance factors are used to account for uncertainties in material strength and other resistances.

Load and resistance factors: ASD primarily relies on factors of safety applied to the loads, while LRFD uses load and resistance factors to modify the nominal loads and resistances, respectively.

Design equations: ASD employs design equations based on allowable stresses and factors of safety, whereas LRFD uses equations that compare the loads and resistances with appropriate load and resistance factors.

Flexibility in design decisions: ASD allows for more flexibility in design decisions as engineers can make adjustments based on judgment and experience, while LRFD provides a more consistent and systematic approach with prescribed load and resistance factors.

In summary, ASD and LRFD share similarities in considering strength requirements, load types, material properties, structural elements, and structural safety. However, they differ in their design philosophies, basis for design, treatment of loads and resistances, load and resistance factors, design equations, and flexibility in design decisions.

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Answer:

Explanation:

The law of conservation of mass states that the mass of the elements at the beginning of the reaction(reactants) will equal the mass at the end of the reaction (product) .

In the chemical equation above,the total mass of the reactants is 80g(16+64) and the total mass of the products is also 80g(44+36).therefore the mass remained constant and that's how the equation represents the law of conservation of mass

Big has no cause of action against Temper. In this scenario, while Temper may have made a verbal threat and raised his fists in a confrontational manner, there is no indication that he physically touched or harmed Big.

Assault refers to the act of intentionally causing apprehension or fear of imminent harmful or offensive contact. Battery, on the other hand, involves the intentional and harmful or offensive physical contact with another person without their consent.

In this case, Temper's actions may constitute assault due to the verbal threat and raising his fists, creating an atmosphere of fear or apprehension. However, since no physical contact or harm occurred, battery is not applicable. Therefore, the appropriate response is option d: Big has no cause of action against Temper.

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78 percent nitrogen and 21 percent oxygen

Some estimates suggest that approximately 20,000 kilometers of ocean coastline are suitable for creating tidal energy.

Tidal energy refers to the energy harnessed from the natural rise and fall of tides in coastal areas. With approximately 20,000 kilometers of ocean coastline considered suitable for tidal energy generation, it highlights the significant potential for utilizing this renewable energy source. Tidal energy systems capture the kinetic energy of moving tides and convert it into electricity through various technologies such as tidal turbines and barrages. Tapping into this vast coastal resource can contribute to sustainable energy production and reduce reliance on fossil fuels.

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Answer:

σ = 1.09 mm

Explanation:

Step 1: Identify the given parameters

rod diameter = 20 mm

stiffness constant (k) = 55 MN/m = 55X10⁶N/m

applied force (f) = 60 KN = 60 X 10³N

young modulus (E) = 200 Gpa = 200 X 10⁹pa

Step 2: calculate length of the rod, L

K = \frac{A*E}{L}K=

L

A∗E

L = \frac{A*E}{K}L=

K

A∗E

A=\frac{\pi d^{2}}{4}A=

4

πd

2

d = 20-mm = 0.02 m

A=\frac{\pi (0.02)^{2}}{4}A=

4

π(0.02)

2

A = 0.0003 m²

L = \frac{A*E}{K}L=

K

A∗E

L = \frac{(0.0003142)*(200X10^9)}{55X10^6}L=

55X10

6

(0.0003142)∗(200X10

9

)

L = 1.14 m

Step 3: calculate the displacement of the rod, σ

\sigma = \frac{F*L}{A*E}σ=

A∗E

F∗L

\sigma = \frac{(60X10^3)*(1.14)}{(0.0003142)*(200X10^9)}σ=

(0.0003142)∗(200X10

9

)

(60X10

3

)∗(1.14)

σ = 0.00109 m

σ = 1.09 mm

Therefore, the displacement at the end of A is 1.09 mm

A transverse wave is a wave in which particles of the medium move in a direction perpendicular to the direction that the wave moves. Suppose that a slinky is stretched out in a horizontal direction across the classroom and that a pulse is introduced into the slinky on the left end by vibrating the first coil up and down. Energy will begin to be transported through the slinky from left to right. As the energy is transported from left to right, the individual coils of the medium will be displaced upwards and downwards. In this case, the particles of the medium move perpendicular to the direction that the pulse moves. This type of wave is a transverse wave. Transverse waves are always characterized by particle motion being perpendicular to wave motion.

A longitudinal wave is a wave in which particles of the medium move in a direction parallel to the direction that the wave moves. Suppose that a slinky is stretched out in a horizontal direction across the classroom and that a pulse is introduced into the slinky on the left end by vibrating the first coil left and right. Energy will begin to be transported through the slinky from left to right. As the energy is transported from left to right, the individual coils of the medium will be displaced leftwards and rightwards. In this case, the particles of the medium move parallel to the direction that the pulse moves. This type of wave is a longitudinal wave. Longitudinal waves are always characterized by particle motion being parallel to wave motion.

The electric potential energy of a charge that experiences a force of 3. 6 × 10⁻⁴ N when it is 9. 8 × 10⁺⁵m from the source of the electric field will be 3.528×10⁻⁸ V.

Electric potential energy is the amount of work needed to move a unit charge from a point to a specific point against an electric field.

The given data in the problem is;

F is the electric force= 3. 6 × 10⁻⁴ N

V is the electric potential=?

d is the distance = 9. 8 × 10⁻⁵ m

The electric potential energy is given as the product of the electric force and distance.

V=Fd

V = 3.6×10⁻⁴ ×( 9.8×10⁻⁵)

V = 3.528×10⁻⁸ V.

Hence the electric potential energy of a charge will be 3.528×10⁻⁸ V.

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5 seconds is the additional time.

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Here is your soulution Kauruchan

Hence, The two spheres each of mass 10 mg are suspended by a point of threads 0.5 m long .

They are equally charged and repel each other to a distance of 0.20 m . Then the charge of the sphere is

\( (\frac{a}{21} ) \times {10}^{ - 8} \: c \)

The value of a ~ 20C

~

Answer:

the answer is letter D.

Explanation:

i hope this is help

Answer:

great answer warstep8! add me on disc colludy#8415

Explanation:

No because it fails the vertical line test

The vertical line test is a test used to determine whether a relation is a function. It states that a relation is a function if and only if any vertical line intersects the graph of the relation at most once.

If a relation fails the vertical line test, it means that there are two or more points on the graph with the same x-coordinate, and therefore, the relation is not a function.

Therefore, for a relation to be a function, it must pass the vertical line test.

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Answer:

45m above the ground

Explanation:

got it right on Edg 2020

Answer:

Take a look below

Explanation:

Answer:

49kmph

Explanation:

speed=distance/time = 245/5

A sentence that includes the words percolate and permeable is a frog's skin is permeable to liquids and gases and so percolates occurs more often when they live in a water body.

Percolation is the process in which a material gets filtered through a porous surface or membrane. Similar words that describe percolate are filter, drain, drip, ooze, seep, trickle etc.

Permeable represents a layer through which substances can pass through. For example when you pour water on a sponge the water does no stay on the rather seeps in the sponge and gets absorbed. So the sponge is permeable to water.

Therefore, a sentence that includes the words percolate and permeable is a frog's skin is permeable to liquids and gases and so percolates occurs more often when they live in a water body.

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a) The push required to give the crate an acceleration of 1.13 m/s^2 is 360.476 N.

b) If we maintain the push of 231 N, the crate would slow down with an acceleration of 1.734 m/s^2 in the opposite direction.

a) To give the crate an acceleration of 1.13 m/s^2, we need to find the net force required.

The force required to overcome static friction and just start the crate moving is given by

F_static = friction coefficient × N

where N is the normal force exerted by the floor on the crate. Since the crate is on a horizontal floor, the normal force is equal to its weight

N = m×g

where m is the mass of the crate and g is the acceleration due to gravity.

N = 45.2 kg × 9.81 m/s^2 = 443.812 N

The force required to overcome static friction is

F_static = friction coefficient × N

We know that the force required to just start the crate moving is 310 N, so the friction coefficient is

friction coefficient = F_static / N = 310 N / 443.812 N = 0.698

Once the crate is moving, the force required to keep it moving at a constant speed is equal to the force of kinetic friction

F_kinetic = friction coefficient × N = 0.698 × 443.812 N = 309.4 N

To give the crate an acceleration of 1.13 m/s^2, we need a net force of

F_net = m×a = 45.2 kg × 1.13 m/s^2 = 51.076 N

So, the force required to give the crate an acceleration of 1.13 m/s^2 is

F_push = F_net + F_kinetic = 51.076 N + 309.4 N = 360.476 N

b) If we maintain the push at 231 N, the net force on the crate would be

F_net = F_push - F_kinetic = 231 N - 309.4 N = -78.4 N

The negative sign indicates that the net force is in the opposite direction to the motion of the crate, so it would slow down with an acceleration of

a = F_net / m = -78.4 N / 45.2 kg = -1.734 m/s^2

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The given question is incomplete, the complete question is:

A crate of 45.2-kg tools rests on a horizontal floor. You exert a gradually increasing horizontal push on it and observe that the crate just begins to move when your force exceeds 310N . After that you must reduce your push to 231N to keep it moving at a steady 25.2cm/s .

a) What push must you exert to give it an acceleration of 1.13m/s^2 ? b) What would its acceleration be if you maintained the push?

The number of cylinders required to fill the balloon with hydrogen is approximately 410, and the weight that can be supported by the balloon, in addition to the weight of the gas, is approximately 9.61 million newtons

Part A: To determine the number of cylinders required to fill the balloon with hydrogen, we can use the ideal gas law. We know the volume of the balloon and the volume and pressure of the cylinders, so we can calculate the number of moles of hydrogen required. Dividing this by the number of moles of hydrogen in each cylinder gives us the number of cylinders required, which is approximately 410.

Part B: The weight that can be supported by the balloon is equal to the weight of the displaced air minus the weight of the hydrogen gas in the balloon. We can use the ideal gas law to determine the number of moles of hydrogen gas in the balloon, and then use this to calculate the weight of the gas.

The weight of the displaced air can be calculated using the density of air at 15.0 °C and atmospheric pressure, and the volume of the displaced air, which is equal to the volume of the balloon. Substituting the values and solving, we get that the weight that can be supported by the balloon, in addition to the weight of the gas, is approximately 9.61 million newtons.

Part C: If the balloon were filled with helium instead of hydrogen, the weight that could be supported would be different due to the difference in molar mass. Using the same equations as before, but with the molar mass of helium, we can calculate the weight of the helium gas and subtract it from the weight of the displaced air to get the weight that can be supported by the balloon.

The weight that could be supported by the balloon with helium would also be approximately 9.61 million newtons because the weight of the helium gas is much smaller than that of the hydrogen gas. However, the number of cylinders required to fill the balloon with helium would be greater, as helium has a lower density than hydrogen.

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Answer:

convection

Explanation:

I'm right ya know

Answer:

I don't have an answer but your so pretty I'm jelly lol

Answer:

See below

Explanation:

He travels a total distance of    4 + 3 = 7 m   in 2 seconds

(Note: this is the actual distance he traveled NOT the displacement from his origin)

velocity = 7m/2s = 7/2 m/s

From starting point he has traveled   sqrt ( 3^2+4^2) =   5m   in 2 seconds

  so his RESULTANT VELOCITY :

     5/2 m/s  at angle tan^-1( 3/4) = 36.86°    North of east

\(\quad \huge \quad \quad \boxed{ \tt \:Answer }\)

Bob's Velocity :

\(\qquad \tt \rightarrow \:v = 2 \hat i + \cfrac{3 \hat j}{2} \)

and

\( \qquad \tt \rightarrow \:mag(v) = { 2.5 }^{} \: \: m/s\)

____________________________________

\( \large \tt Solution \: : \)

Let the unit vector towards north be \( \sf \hat j \) and unit vector towards east be \( \sf \hat i\)

According to statement :

\( \qquad \tt \rightarrow \:s = 4 \hat i + 3 \hat j\)

[ s represents displacement ]

\(\qquad \tt \rightarrow \:v = \dfrac{s}{t} \)

\(\qquad \tt \rightarrow \:v = \dfrac{4 \hat i + 3 \hat j}{2} \)

\(\qquad \tt \rightarrow \:v = 2 \hat i + \cfrac{3 \hat j}{2} \)

If magnitude of velocity is to be asked :

\( \qquad \tt \rightarrow \:mag(v) = \sqrt{(2) {}^{2} + { \bigg( \cfrac{3}{2} \bigg) }^{2} } \)

\( \qquad \tt \rightarrow \:mag(v) = \sqrt{4 + { \cfrac{9}{4} }^{} } \)

\( \qquad \tt \rightarrow \:mag(v) = \sqrt{ { \cfrac{16 + 9}{4} }^{} } \)

\( \qquad \tt \rightarrow \:mag(v) = \sqrt{ { \cfrac{25}{4} }^{} } \)

\( \qquad \tt \rightarrow \:mag(v) = { \cfrac{5}{2} }^{} \: \: m/s\)

\( \qquad \tt \rightarrow \:mag(v) = { 2.5 }^{} \: \: m/s\)

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

==>  The total mass resting on the table is (5 kg + 3 kg) = 8 kg.

==>  The total weight of that mass is (8 kg) x (9.8 m/s) = 78.4 newtons

==>  The boxes are stacked.  So the table doesn't know if the weight on it is coming from one box, 2 boxes, 3 boxes, or 100 boxes in a stack.  The table only knows that there is a downward force of 78.4 newtons on it.

==>  The table stands in a Physics classroom, and it soaks up everything it hears there.  It knows that every action produces an equal and opposite reaction, and that forces always occur in pairs.  

Ever since the day it was only a pile of lumber out behind the hardware store in the rain, the table has known that in order to maintain the good  reputation of tables all over the world, it must resist the weight of anything placed upon it with an identical upward force.  This is the normal thing for all good tables to do, up to the ultimate structural limit of their materials and construction, and it is known as the "normal force".

So the table in your question provides a normal force of 78.4 newtons. (d)

The general equation of simple harmonic motion is

y = a cos (? t )or y = a sin (? t )

but here y = a cos (? t )...because at t=0 amplitude is maximum

Here amplitude 'a '= 0.01 m

m = 0.3 kg

x = 0.02 m

Force constant k is given by,

k = mg / x = 0.3 x 9.8/ 0.02 = 147 N/m

The time period of oscillation is given by ,

T = 2 ? ?( m / k )

? = 2 ? / T = ? ( 147 / 0.3 )

? = 22.1

then y = (0.01m) cos (22.1 t )

In physics, a force is a power that can change the motion of an item. A force can purpose an object with mass to alternate its pace. Pressure also can be described intuitively as a push or a pull. A force has both value and path, making it a vector quantity.

A pressure is a push or a pull and it affects our each day lives because without force, people might not be capable of open and near stuff or lift up our arms or legs.

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