The law of conservation of mass states that in a closed system, matter cannot be created or destroyed. This means that during a chemical reaction, the atoms of the reactants are rearranged to form the products.

In atomic models of simple reactions, the number of atoms found in the reactants should be the same as the number of atoms found in the products.

Note: In the image below, one dot equals one atom.

Using the image of the reaction of methane above, fill in the blanks below.

In the reaction of methane, the reactants have
?
total atoms. The law of conservation of mass states that during a reactions atoms are
?
. Therefore, the products of this reaction will have ?
atoms.

To solve the equation \(6sin^2(x)\) + 6sin(x) + 1 = 0, we can use algebraic methods and the unit circle to determine the values of x that satisfy the equation.

1. Start by rearranging the equation to a quadratic form: \(6sin^2(x)\) + 6sin(x) + 1 = 0.

2. Notice that the equation resembles a quadratic equation in terms of sin(x). Let's substitute sin(x) with a variable, such as u: \(6u^2\) + 6u + 1 = 0.

3. Solve this quadratic equation for u. You can use the quadratic formula or factorization methods to find the values of u. The solutions are u = (-3 ± √3) / 6.

4. Since sin(x) = u, substitute back the values of u into sin(x) to obtain the values for sin(x): sin(x) = (-3 ± √3) / 6.

5. To find the values of x, we can use the inverse sine function. Take the inverse sine of both sides: x = arcsin[(-3 ± √3) / 6].

6. The arcsin function has a range of [-π/2, π/2], so the values of x lie within that range. Use a calculator to find the approximate values of x based on the values obtained in step 5.

7. Plot the obtained x-values on the graph to show the solutions of the equation \(6sin^2(x)\) + 6sin(x) + 1 = 0. The graph will illustrate the points where the curve intersects the x-axis.

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The main answer to this question is that there could be several reasons why an experiment may not produce significant results even if the research hypothesis is true.

One possible explanation could be that the sample size used in the experiment was too small, which could have resulted in insufficient statistical power to detect the true effect of the independent variable on the dependent variable. Another explanation could be that there were extraneous variables that were not controlled for in the experiment, which could have influenced the results and made it difficult to detect the true effect of the independent variable.

it is important to consider all possible factors that may affect the results of an experiment and to take steps to minimize their impact. This includes ensuring that the sample size is appropriate, controlling for extraneous variables, and using appropriate statistical tests to analyze the data. By doing so, researchers can increase the likelihood of obtaining significant results that accurately reflect the effects of the independent variable on the dependent variable.

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The given exponential function can be used to determine the

population of the fish at different times.

Response:

1. 200

2. 0.05

3. Please find attached the graph of the exponential function and the table

\(\begin{array}{|c|c|c}x&f(x)\\0&200 & y-intercept\\1&210\\3&231.525\\4&243.1\\5&255.26\end{array}\)

4. Range; [0, ∞)

Domain: [200, ∞)

5. 346 fishes (approximate value)

The given function is f(x) = 200·(1.05)ˣ

1. The initial population is given by the value of the function when x = 0,

which is given as follows;

At x = 0, f(0) = 200·(1.05)⁰ = 200

2. The rate of growth of the fish from the exponential function is given as follows;

The growth factor = 1.05

3. Please find attached the graph of the exponential function created

with MS Excel.

The asymptote of the exponential function is the line, y = 0

The table of values is presented as follows;

\(\begin{array}{|c|c|c}x&f(x)\\0&200 & y-intercept\\1&210\\3&231.525\\4&243.1\\5&255.26\end{array}\)

4. The domain is the possible x-values which is; 0 ≤ x < ∞

The range is the possible y-values which is; 200 ≤ f(x) < ∞

Which gives;

5. The population of the fish after 11 years is f(11) = 200·(1.05)¹¹

f(11) = 200 × (1.05)¹¹ ≈ 342

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Answer:

Step-by-step explanation:

The length is 25x and 7/25th of the length is 23:

The length is:

ATQ

\(\\ \sf\longmapsto \dfrac{7}{25}\:of\:25x=23\)

\(\\ \sf\longmapsto \dfrac{7}{25}\times 25x=23\)

\(\\ \sf\longmapsto 7x=23\)

\(\\ \sf\longmapsto x=\dfrac{23}{7}\)

Now

\(\\ \sf\longmapsto 25x\)

\(\\ \sf\longmapsto \dfrac{25(23)}{7}\)

\(\\ \sf\longmapsto \dfrac{575}{7}\)

Answer:

-9 + 3f

Step-by-step explanation:

Solve -9 + f + 2f.

1. Combine the like terms

= -9 + 3f

Answer:

Here’s the answer! Best of luck.

Step-by-step explanation:

Answer:

The answer would be C: not every input maps to an output.

Answer:

If asked to translate a point (x+1,y+1), you move it to the right one unit because + on the x-axis goes to the right, and move it up one unit, because + on the y-axis goes up.

Step-by-step explanation:

Let me knoe how you did

The triangle does not exist, as the property, the sum of two sides of a triangle is greater than the third side length of the triangle does not hold true.

Simple polygons with three sides and three internal angles make up triangles. One of the fundamental geometric forms is represented by the symbol △ and consists of three connected vertices. Triangles may be categorized into a number of different varieties according to their sides and angles.

It is a triangle's property that the sum of any two sides of a triangle is greater than the third side.

Here sides given are 3 m, 5 m, 9 m.

Let us add the sides length 3 m and 5 m

3 m + 5 m = 8 m

Compare this with the third-side length of the triangle

8 m < 9 m

So, the property does not hold true.

So, the triangle does not exist.

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Answer: -8/3

Step-by-step explanation:(-(2 / 3)) * 4 = -8 / 3

Answer:

16/81 is the evaluation of (2/3)⁴

Step-by-step explanation:

yw

To calculate the monthly principal + interest payments for a house with a down payment and a mortgage using an Excel formula, you can use the PMT function. Here's how:

Calculate the loan amount by subtracting the down payment from the house cost. In this case, the down payment is 25% of $300,000, so it would be $75,000.
  Loan Amount = $300,000 - $75,000 = $225,000    

Determine the monthly interest rate by dividing the annual interest rate by 12. In this case, the annual interest rate is 2.75%, so the monthly interest rate would be 2.75% / 12 = 0.00229.

Determine the loan term in months. Since it's a 30-year mortgage, the loan term would be 30 * 12 = 360 months.

Use the PMT function in Excel to calculate the monthly principal + interest payment.
  Monthly Payment = -PMT(0.00229, 360, 225000)

The negative sign is used because the payment is an outgoing cash flow.

By using this formula in Excel, you can find the monthly principal + interest payments for your mortgage. Remember to adjust the interest rate, loan amount, and loan term if they differ from the example provided.

To calculate the monthly principal + interest payments using an Excel formula, you can use the PMT function by inputting the appropriate parameters: the monthly interest rate, loan term in months, and loan amount.

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The total surface area​ of a cylinder are 1187.35 cm sq.

Suppose that the radius of considered right circular cylinder be 'r' units.

And let its height be 'h' units.

Then, its volume is given as:

\(V = \pi r^2 h \: \rm unit^3\)

We are given the curved surface area and volume of a cylinder are 880 CM^2 and 3080 cm^3 respectively.

A = 880

V = 3080

Curved surface area of cylinder = 2πrh

880 = 2π x r x h

rh = 880/ 2π

Volume of cylinder = πr x r x h

3080 =  πr x r x h

rh =   3080 / πr

Substitue the values;

880/ 2π = 3080 / πr

440/π = 3080 / πr

r  = 3080 / 440

r = 7

Now, rh = 880/ 2π

h = 20.01

The total  surface area​ = 2πr(r + h)

= 2π x  7(7 + 20.01)

= 1187.35 cm sq.

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Answer:

$155282862040271282939285047182828282828

3 hours and 45 minutes = 3.75 hours

\(\frac{100}{3.75}=\boxed{26.\overline{6}}\)

Answer:

The instantaneous velocity at t = 1 will be:

Step-by-step explanation:

Given the position of an object at a time \(t\)

\(s\left(t\right)=-8-9t\)

As we know that determining the derivative of the position function with respect to time t would give us the instantaneous velocity, so

\(\frac{ds}{dt}=\frac{d}{dt}\left(-8-9t\right)\)

Applying the sum/difference rule:

\(\left(f\pm g\right)'=f\:'\pm g'\)

\(\frac{ds}{dt}=-\frac{d}{dt}\left(8\right)-\frac{d}{dt}\left(9t\right)\)

as

\(\frac{d}{dt}\left(8\right)=0\)    ∵ \(\frac{d}{dx}\left(a\right)=0\)

and

\(\frac{d}{dt}\left(9t\right)=9\)   ∵ \(\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'\)  and \(\frac{d}{dt}\left(t\right)=1\)

so the expression becomes

\(\frac{ds}{dt}=-\frac{d}{dt}\left(8\right)-\frac{d}{dt}\left(9t\right)\)

   \(=-0-9\)

   \(=-9\)

As the derivative is constant.

Therefore, the instantaneous velocity at t = 1 will be:

The shaded region is the area that satisfies all the given inequalities. It is the region where all the lines and axes overlap.

To find the shaded region, we need to graph the system of inequalities on a coordinate plane.
The first inequality, 8x + 16y ≥ 200, represents a line.

To graph it, we can find two points on the line by setting x = 0 and y = 0, and then connecting the points.
The second inequality, 60x + 40y ≥ 960, also represents a line. Similarly, we can find two points on this line and connect them.
The third inequality, 2x + 2y ≥ 40, represents another line. Again, find two points and connect them.

Finally, the last two inequalities x ≥ 0 and y ≥ 0 represent the x-axis and y-axis, respectively.
The shaded region is the area that satisfies all the given inequalities. It is the region where all the lines and axes overlap.
To find the corner points, we need to identify the intersection points of the lines. These points are the corners of the shaded region.

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Answer:

53

Step-by-step explanation:

x+45=98

solve for x

x+45=98

  -45  -45

x=53

Answer:

a). Distance round one loop = 141.37 meters

b). Distance covered = 3534.29 meters

Step-by-step explanation:

Diameter of the given track = 45 meters

a). Distance round one loop of the track = circumference of the circle

    Circumference of a circle = π × (Diameter)

                                               = π × (45)

                                               = 141.37 meters

b). Distance covered by going around the track 25 times = 25 × distance in one loop of the track

    = 25 × 141.37

    = 3534.29 meters

The required answer is the annual cost saved by shifting from the 500-bag lot size to the EOQ is $1,059.92.

Explanation:-

a. Economic order quantity (EOQ) is defined as the optimal quantity of inventory to be ordered each time to reduce the total annual inventory costs.

It is calculated as follows: EOQ = sqrt(2DS/H)

Where, D = Annual demand = 100 x 52 = 5200S = Order cost = $57 per order H = Annual holding cost = 0.30 x 10.75 = $3.23 per bag per year .Therefore, EOQ = sqrt(2 x 5200 x 57 / 3.23) = 234 bags. The average time between orders (TBO) can be calculated using the formula: TBO = EOQ / D = 234 / 100 = 2.34 weeks ≈ 2 weeks (rounded to nearest whole number).

Hence, the EOQ is 234 bags and the average time between orders is 2 weeks (approx).b. R is the reorder point, which is the inventory level at which an order should be placed to avoid a stockout.

It can be calculated using the formula:R = dL + zσL

Where,d = Demand per day = 100 / 5 = 20L = Lead time = 1 week (5 working days) = 5 day

z = z-value for 92% cycle-service level = 1.75 (from standard normal table)σL = Standard deviation of lead time demand = σ / sqrt(L) = 16 / sqrt(5) = 7.14 (approx)

Therefore,R = 20 x 5 + 1.75 x 7.14 = 119.2 ≈ 120 bags

Hence, the reorder point R should be 120 bags.c. An inventory withdraw of 10 bags was just made. Is it time to reorder?The current inventory level is 310 bags, which is greater than the reorder point of 120 bags. Since there are no open orders or backorders, it is not time to reorder.d. The store currently uses a lot size of 500 bags (i.e., Q = 500).What is the annual holding cost of this policy.

Annual ordering cost. Without calculating the EOQ, how can you conclude the lot size is too large?Annual ordering cost = (D / Q) x S = (5200 / 500) x 57 = $592.80 per year.

Annual holding cost = Q / 2 x H = 500 / 2 x 0.30 x 10.75 = $806.25 per year. Total annual inventory cost = Annual ordering cost + Annual holding cost= $592.80 + $806.25 = $1,399.05Without calculating the EOQ, we can conclude that the lot size is too large if the annual holding cost exceeds the annual ordering cost.

In this case, the annual holding cost of $806.25 is greater than the annual ordering cost of $592.80, indicating that the lot size of 500 bags is too large.e.

The annual cost saved by shifting from the 500-bag lot size to the EOQ can be calculated as follows:Total cost at Q = 500 bags = $1,399.05Total cost at Q = EOQ = Annual ordering cost + Annual holding cost= (D / EOQ) x S + EOQ / 2 x H= (5200 / 234) x 57 + 234 / 2 x 0.30 x 10.75= $245.45 + $93.68= $339.13

Annual cost saved = Total cost at Q = 500 bags - Total cost at Q = EOQ= $1,399.05 - $339.13= $1,059.92

Hence, the annual cost saved by shifting from the 500-bag lot size to the EOQ is $1,059.92.

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Answer:

The pizza was heated at a constant rate. The table compares the pizza's temperature (in degrees Celsius) and the time since Suraj started heating it (in minutes). Time(Minutes) Temperature( degree .

Answer:

14 did it on khan

Step-by-step explanation:

proof:

Given parameters:

Midpoint of AB =  M(3, -1)

Coordinates of A = (5,1)

Unknown:

Coordinates of B = ?

Solution:

To find the mid point of any line, we use the expression below;

              \(x_{m} = \frac{x_{1} + x_{2} }{2}\)    and \(y_{m} = \frac{y_{1} + y_{2} }{2}\)

where \(x_{m}\)  and \(y_{m}\) = coordinates of the mid points = 3 and -1

   x₁  = 5 and y₁ = 1

  x₂ = ?  and y₂ = ?

Now let us input the variables and solve,

            3  = \(\frac{5 + x_{2} }{2}\)           and     -1 = \(\frac{1 + y_{2} }{2}\)

    5 +  x₂  = 6                          -2 = 1  + y₂

            x₂ = 1                             y₂ = -2 -1 = -3

The coordinates of B = 1, -3

Answer:

180

Step-by-step explanation:

(10×11)+(10×7)=110+70

The area of the kite is expressed as 1/2 × (Product of its diagonals)

In this case, we have;

Therefore, when we substitute the diagonals in the formula, we get;

When simplified, we get;

Therefore, the area of the kite is 180 ft².

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\(\qquad \qquad\huge \underline{\boxed{\sf Answer}}\)

The Length of PQ such that Triangle JKL is similar to Triangle PQR ~

To make the given triangles similar, we have to get the ratios of each of their corresponding side to be equal to one another.

That is :

\(\qquad \sf  \dashrightarrow \: \dfrac{PQ}{12} = \dfrac{9}{6} \)

\(\qquad \sf  \dashrightarrow \: PQ = \dfrac{9}{6} \times 12\)

\(\qquad \sf  \dashrightarrow \: PQ = {9}{} \times 2\)

\(\qquad \sf  \dashrightarrow \: PQ = 18 \: units\)

hence, the option C is correct

Answer:

x=1 and x=-1/3

Step-by-step explanation:

\(3x^2-2x-1=0\\\\3(x^2-\frac{2}{3}x-\frac{1}{3})=0\\ \\3(x^2-\frac{2}{3}x-\frac{1}{3}+\frac{4}{9})=3(\frac{4}{9})\\ \\ 3(x^2-\frac{2}{3}x+\frac{1}{9})=\frac{4}{3}\\ \\ 3(x-\frac{1}{3})^2=\frac{4}{3}\\ \\(x-\frac{1}{3})^2=\frac{4}{9}\\ \\x-\frac{1}{3}=\pm\frac{2}{3}\)

\(x-\frac{1}{3}=\frac{2}{3}\\ \\x=\frac{3}{3}\\ \\x=1\)

\(x-\frac{1}{3}=-\frac{2}{3}\\ \\x=-\frac{1}{3}\)

Therefore, x=1 and x=-1/3

The error in Han’s thinking is that he takes 0.5 as the power of x instead of coefficient

Polynomial expressions are mathematical statements that are represented by variables, coefficients and operators

The polynomial expression is given as

The product of 10x^4 and 0.5x^3 to get 5x^7

The above implies that

10x^4 x 0.5x^3 = 5x^7

From the question, we have

Han says that 0.5^3 is not a polynomial because 0.5 is not an integer.

The above statement is false, because 0.5 is not a power of x; but instead it is a coefficient

So, the error in Han’s thinking is that he takes 0.5 as the power of x instead of coefficient

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The value of the side c will be 5.56 cm and angle C is 32.49° and angle B is 42.51°.

Let there is a triangle ABC such that |AB| = a units, |AC| = b units, and |BC| = c units and the internal angle A is of θ degrees, then we have:

a² + b² – 2ab cos C = c²

Given triangle ABC, A = 105°, a = 10 cm, b = 7 cm.

Then we have

7² + c² – (2 · 7 · c) cos 105° = 10²

c² + 3.62c – 51 = 0

On solving, we have

c = 5.56

Then the angle C will be

10² + 7² – 2 · 7 · 10 · cos C = 5.56²

                149 – 140 cos C = 30.91

                                 cos C = 0.8435

                                        C = 32.49°

We know that

       ∠A + ∠B + ∠C = 180°

105° + ∠B + 32.49° = 180°

                         ∠B = 42.51°

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Step-by-step explanation:

first add all the n together

3n and 4n

add those together too

7n

now add 2+4

6 now

7n\-7n =6/-7n = -1n

The following equation is m=d-10+k×i represent the total amount in account(m) in dollar.

Although the question does not specify the options, but I have specified my answer as follows:

Given:

The equation representing the total amount in the account, m, when starting with d dollars and being charged a 10$ fee.

Account Opening Charges: $10

Starting amount: $d

The total amount in the account: $m

Let us say the depositor deposits an amount $k for 'i' number of months

Banks deduct their charges from the account balance itself, hence account opening charges are deducted from the bank balance.

I have assumed an amount $k invested every month. You can remove that term as per the requirement of the question.

The total amount at a point in time = starting amount - Account Opening Charges + monthly deposit till that time

⇒m=d-10+k×i

This equation shows that the total amount in the account will be equal to the initial deposit minus the fee charged by the bank.

Therefore, the following equation is m=d-10+k×i.

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In the balance sheet, mortgage notes payable are reported as a long-term liability only.

Mortgage notes payable represent the amount owed by a company for a mortgage loan. These loans are typically long-term obligations that are expected to be repaid over an extended period, often several years. Therefore, mortgage notes payable are classified as long-term liabilities in the balance sheet.

Current liabilities are obligations that are expected to be settled within a short period, usually one year or less. Since mortgage notes payable typically have a longer repayment term, they do not meet the criteria to be classified as current liabilities.

By reporting mortgage notes payable as a long-term liability, the balance sheet provides a clear distinction between the company's short-term and long-term obligations, helping stakeholders understand the company's financial position and obligations over different time horizons.

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Answer:

Third Option
84 cm²

Step-by-step explanation:

Split the composite figure into two rectangles as shown in the figure

One rectangle has length 12 and width 5 giving an area of 12 x 5 = 60

The other rectangle has length 6 and width 4 giving an area of 6 x 4 = 24

Total area = 60 + 24 = 84 cm²

Third Option