Answer:
2=4x+5 I am not 100% sure about this though.
unit 1 chapter 1 gross income answersA portion of Donald Irwin’s time sheet is shown below. Determine the total number of hours he worked for the week rounded to the nearest quarter hour.
Answer:
i need points
Step-by-step explanation:
Finding which number supports the idea that the rational numbers are dense in the real numbers?
Answer:
an integer between –11 and –10
a whole number between 1 and 2
a terminating decimal between –3.14 and –3.15
Step-by-step explanation:
A vehicle with a particular defect in its emission control system is taken to a succession of randomly selected mechanics until r = 6 of them have correctly diagnosed the problem. Suppose that this requires diagnoses by 20 different mechanics (so there were 14 incorrect diagnoses). Let p = P(correct diagnosis), so p is the proportion of all mechanics who would correctly diagnose the problem. What is the mle of p? Is it the same as the mle if a random sample of 20 mechanics results in 6 correct diagnoses? Explain. No, the formula for the first one is (number of successes)/(number of failures) and the formula for the second one is (number of failures)/(number of trials). Yes, both mles are equal to the fraction (number of successes)/(number of failures). No, the formula for the first one is (number of failures)/(number of trials) and the formula for the second one is (number of successes)/(number of trials). No, the formula for the first one is (number of failures)/(number of trials) and the formula for the second one is (number of successes)/(number of failures). Yes, both mies are equal to the fraction (number of successes)(number of trials).
The MLE for both scenarios is equal to the fraction (number of successes)/(number of failures), confirming that the answer is: Yes, both MLEs are equal to the fraction (number of successes)/(number of failures).
The maximum likelihood estimate (MLE) of p, the proportion of all mechanics who would correctly diagnose the problem, is the fraction (number of successes)/(number of failures). The MLE for a random sample of 20 mechanics resulting in 6 correct diagnoses is also the same, as it follows the same formula.
The maximum likelihood estimate (MLE) is a statistical method used to estimate the parameters of a statistical model based on observed data. In this case, the MLE of p, the proportion of all mechanics who would correctly diagnose the problem, can be calculated as the fraction (number of successes)/(number of failures). The number of successes refers to the number of mechanics who correctly diagnosed the problem (r = 6), and the number of failures refers to the number of mechanics who incorrectly diagnosed the problem (14).
Now, if we consider a random sample of 20 mechanics and the outcome is 6 correct diagnoses, the MLE in this scenario remains the same. Both situations involve estimating the same parameter, p, and the formula for the MLE remains consistent: (number of successes)/(number of failures). The only difference is the context in which the data is collected, but the calculation for the MLE remains unchanged.
Therefore, the MLE for both scenarios is equal to the fraction (number of successes)/(number of failures), confirming that the answer is: Yes, both MLEs are equal to the fraction (number of successes)/(number of failures).
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Area of this figure
Rewrite each fraction with a denominator of 24 2/3 5/8
Answer:
A)16/24
B)15/24
Step-by-step explanation:
We were told to rewrite so that the denominator will be 24
A)2/3
This can be rewritten as 16/24, so that the denominator is now 24. And if we divide the numerator (16) by factor of 8 and the denominator (24) by factor of 8. Then we have 2/3.
OR
[2/3 × 8/8] = 16/24
B)5/8
This can be rewritten as 15/24, so that the denominator is now 24. And if we divide the numerator (15) by factor of 3 and the denominator (24) by factor of 3. Then we have 5/8
OR
(5/8 × 3/3)= 15/24
i think it’s #1 but what’s the work?
Find the slope and the Y-intercept of the graph below.
Answer:
the slope is (-2,0) (2,4)
y intercept is (0,2)
Step-by-step explanation:
brainliest?
"In each of Problems 4 and 5, find the inverse Laplace transform
of the given function."
4. F(s) = 2s+2/s²+2s+5
5. F(s) = 2s-3/s²-4
4. Inverse Laplace transform of F(s) is f(t) = e^(-t) * cos(2t) + sin(2t), 5. f(t) = (3/4) * e^(2t) - (1/4) * e^(-2t). This is the inverse Laplace transform of F(s)
For Problem 4, we can first use partial fraction decomposition to write F(s) as:
F(s) = (2s+2)/(s²+2s+5) = A/(s+1-i√2) + B/(s+1+i√2)
where A and B are constants to be determined. To find A and B, we can multiply both sides by the denominator and then set s = -1+i√2 and s = -1-i√2, respectively. This gives us the system of equations:
2(-1+i√2)A + 2(-1-i√2)B = 2+2i√2
2(-1-i√2)A + 2(-1+i√2)B = 2-2i√2
Solving this system, we get A = (1+i√2)/3 and B = (1-i√2)/3. Therefore, we have:
F(s) = (1+i√2)/(3(s+1-i√2)) + (1-i√2)/(3(s+1+i√2))
To find the inverse Laplace transform of F(s), we can use the formula:
L⁻¹{a/(s+b)} = ae^(-bt)
Applying this formula to each term in F(s), we get:
f(t) = (1+i√2)/3 e^(-(-1+i√2)t) + (1-i√2)/3 e^(-(-1-i√2)t)
= (1+i√2)/3 e^(t-√2t) + (1-i√2)/3 e^(t+√2t)
This is the inverse Laplace transform of F(s).
For Problem 5, we can also use partial fraction decomposition to write F(s) as:
F(s) = (2s-3)/(s²-4) = A/(s-2) + B/(s+2)
where A and B are constants to be determined. To find A and B, we can multiply both sides by the denominator and then set s = 2 and s = -2, respectively. This gives us the system of equations:
2A - 2B = -3
2A + 2B = 3
Solving this system, we get A = 3/4 and B = -3/4. Therefore, we have:
F(s) = 3/(4(s-2)) - 3/(4(s+2))
To find the inverse Laplace transform of F(s), we can again use the formula:
L⁻¹{a/(s+b)} = ae^(-bt)
Applying this formula to each term in F(s), we get:
f(t) = 3/4 e^(2t) - 3/4 e^(-2t)
This is the inverse Laplace transform of F(s).
In each of Problems 4 and 5, find the inverse Laplace transform of the given function.
4. F(s) = (2s + 2) / (s^2 + 2s + 5)
To find the inverse Laplace transform of F(s), first complete the square for the denominator:
s^2 + 2s + 5 = (s + 1)^2 + 4
Now, F(s) = (2s + 2) / ((s + 1)^2 + 4)
The inverse Laplace transform of F(s) is f(t) = e^(-t) * cos(2t) + sin(2t)
5. F(s) = (2s - 3) / (s^2 - 4)
To find the inverse Laplace transform of F(s), recognize this as a partial fraction decomposition problem:
F(s) = A / (s - 2) + B / (s + 2)
Solve for A and B, then apply inverse Laplace transform to each term:
f(t) = (3/4) * e^(2t) - (1/4) * e^(-2t)
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jason rolls three fair standard six-sided dice. then he looks at the rolls and chooses a subset of the dice (possibly empty, possibly all three dice) to reroll. after rerolling, he wins if and only if the sum of the numbers face up on the three dice is exactly 7. jason always plays to optimize his chances of winning. what is the probability that he chooses to reroll exactly two of the dice?
The probability that he chooses to reroll exactly two of the dice = 7/36
Probability:
Possibility is referred to as probability. This branch of mathematics deals with the occurrence of a random event. The value's range is 0 to 1. Probability has been applied into mathematics to predict the likelihood of different events. Probability generally refers to the degree to which something is likely to occur. This fundamental theory of probability, which also applies to the probability distribution, can help you comprehend the possible outcomes for a random experiment. Gonna determine how likely something is to occur, use probability. Many things are hard to predict with 100% certainty. We can only anticipate the possibility of an event occurring using it, or how likely it is.
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Consider a hypothesis test of difference of means for two independent populations x1 and x2.(a) What does the null hypothesis say about the relationship between the two population means?H0 says that the population means are different.H0 says that the population standard deviations are equal. H0 says that the population means are equal.H0 says that the population standard deviations are different.
H0 says that the population means are equal.
In the context of a hypothesis test for the difference of means between two independent populations (x1 and x2), the null hypothesis (H0) states the following about the relationship between the two population means:
H0 says that the population means are equal.
In other words, the null hypothesis assumes that there is no significant difference between the means of the two populations. The alternative hypothesis would then state that the population means are different. Remember that hypothesis testing is a process to determine whether there is enough evidence to reject the null hypothesis in favor of the alternative hypothesis.
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What is the factored form of this expression? 7- 12x+36 А. (x-12)(x-3) B. (x-6)(x+6) c. (x+6) 2 D. (x-62
Answer:
Step-by-step explanation:
factored form of x^2 - 12x + 36
(x - 6)(x - 6) or (x - 6)^2
answer is D
Serena bought 4 packs of pencils and 12 notebooks
for fall semester which cost her $60.00. She then
bought 14 packs of pencils and 7 notebooks for
spring semester which cost her $70.00. How much
did each pack of pencils and each notebook cost?
Answer:
6
Step-by-step explanation:
that is what it said the correct answer was
Answer: pencil (x) = 3.00, notebook (y) = 4.00
Step-by-step explanation:
Let pencils be denoted using 'x', and notebooks 'y'.
4x+12y = 60, 14x+7y=70
Let us use the method of elimination. However, neither variable has the same coefficient, so let us multiply the first equation using 7, and the second using 2.
7(4x+12y = 60) => 28x+84y=420
2(14x+7y=70) => 28x+14y=140
Let us subtract the second equation from the first. This eliminates the first variable x, and gives the equation 70y=280
Dividing either side of the equation by 70, we get y=4.
If we substitute (plug in) y=4 for the first equation we get x=3
what is the equivalent to i233
Answer:
Step-by-step explanation:
\(\iota^{233} =(\iota^{2} )^{116} \times \iota=(-1)^{116} \times \iota =\iota\)
help me nowwww show work thank you
Answer:
Step-by-step explanation:
I assume the triangle is right angled
Which fraction is equivalent to
2/5
Answer:
To make equivalent fractions, what we have to do is multiplicate or divide the numerator or denominator by the same number.
In our case:
\(\frac{2}{5}=\frac{2*2}{5*2}=\frac{4}{10}\)
\(\frac{2}{5}=\frac{2*6}{5*6}=\frac{12}{30}\)
\(\frac{2}{5} = \frac{2*12}{5*12}=\frac{24}{60}\)
That are only three examples, but there are infinite.
We could also obtain equivalent fractions dividing, for example, \(\frac{3}{9}\):
\(\frac{3}{9}=\frac{\frac{3}{3}}{\frac{9}{3}}\) = \(\frac{1}{3}\)
PLEASE HELP and explain process
Answer:
Step-by-step explanation:
2.) x= −10 and y= −48
3.) x= −4 and y= −25
4.) x= −5 and y= 0
5.) x= -14/11 and y= -29/11
If f(x) = x+10, find f(7)
\(f(x)=x+10\\\\f(7)=(7)+10\\\\f(7)=17\)
the answer is 17.
Answer:
The answer is 17, x±10 =10+7= 17
Can someone help me out with this question? I've been practicing it this one is confusing to me
Answer:
NK = 26
Step-by-step explanation:
You have a triangle with the centroid identified and all medians drawn. You are given IK = 52 and want NK, where point N is the intersection of median JN with side IK.
CentroidThe centroid of a triangle is the point where the medians intersect. It divides each median in the ratio 2:1.
MedianA median of a triangle joins a vertex with the midpoint of the opposite side. Here, that means point N is the midpoint of side IK.
IK is given as length 52, so each half of that segment is 52/2 = 26.
IN = NK = 26
A square tube 1.0 cm on a side gradually changes shape to become a circular tube 1.0 cm in diameter. Gasoline flows through the tube at 0.60 L/sL/s. what is the pressure difference between the square tube and the circular tube?
The pressure difference between the square tube and the circular tube can be found using Bernoulli's equation, which relates the pressure of a fluid to its velocity and height. where P is the pressure of the fluid.
ΔP = 1/2 * 0.75 g/cm^3 * [(1.0 cm/s)^2 - (4v1/π)^2]
The pressure difference between the square tube and the circular tube can be found using Bernoulli's equation, which relates the pressure of a fluid to its velocity and height. Since the tube diameter changes along the length, we need to use the continuity equation to relate the velocity of the fluid in the square tube to the velocity in the circular tube.
To begin, we can use the continuity equation, which states that the mass flow rate of a fluid is constant along the length of the tube:
ρ1A1v1 = ρ2A2v2
where ρ is the density of the fluid, A is the cross-sectional area of the tube, and v is the velocity of the fluid.
Since the cross-sectional area of the square tube is A1 = (1.0 cm)^2 and the diameter of the circular tube is d = 1.0 cm, the cross-sectional area of the circular tube is A2 = π/4 * d^2 = π/4 cm^2. We are given that the mass flow rate of the gasoline is 0.60 L/s, which has a density of ρ = 0.75 g/mL = 0.75 g/cm^3.
Using the continuity equation, we can solve for the velocity of the fluid in the circular tube:
v2 = (ρ1A1v1) / (ρ2A2) = (0.75 * (1.0 cm)^2 * v1) / (π/4 cm^2)
Now that we have the velocity of the fluid in the circular tube, we can use Bernoulli's equation to relate the pressure in the square tube to the pressure in the circular tube:
P1 + 1/2 ρ1 v1^2 = P2 + 1/2 ρ2 v2^2
where P is the pressure of the fluid.
Since the tube is horizontal, the height difference between the two sections can be ignored. Thus, the pressure difference is:
ΔP = P2 - P1 = 1/2 ρ1 (v1^2 - v2^2)
Plugging in the values, we get:
ΔP = 1/2 * 0.75 g/cm^3 * [(1.0 cm/s)^2 - (4v1/π)^2]
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The range of the data between 25 and 50 is what fraction of the total data?
The fraction of data between 25 and 50 as a fraction of the total data is 5/12.
To find the fraction of data between 25 and 50 as a fraction of the total data, we need to know the minimum and maximum values of the data set, as well as its range.
Let's suppose that the data set ranges from a minimum value of 10 to a maximum value of 70. Therefore, the range of the data set is:
Range = Maximum value - Minimum value
Range = 70 - 10 = 60
Next, we can determine the range of the data between 25 and 50:
New Range = 50 - 25 = 25
To find the fraction of the data between 25 and 50 as a fraction of the total data, we can divide the new range by the total range:
Fraction = New Range / Total Range
Fraction = 25 / 60
Simplifying this fraction by dividing both numerator and denominator by 5, we get:
Fraction = 5 / 12
This means that approximately 41.7% of the data set is between 25 and 50.
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Apples from a grower’s crop in 2006 were normally distributed with mean 173 grams and standard deviation of 34 grams. Apples weighing less than 130 grams were too small to sell.
Find the proportion of apples from this crop which were too small to sell.
Find the probability that in a picker’s basket of 100 apples, up to 10 apples were too small to sell .
P(X ≤ 10) represents the probability that up to 10 apples in a basket of 100 are too small to sell.
To find the proportion of apples from the 2006 crop that were too small to sell, we need to calculate the probability that an apple weighs less than 130 grams. We can do this by using the standard normal distribution.
Proportion of apples too small to sell:
Let X be the weight of an apple from the crop. We are given that X follows a normal distribution with a mean of 173 grams and a standard deviation of 34 grams.
To find the proportion of apples weighing less than 130 grams, we need to calculate the cumulative distribution function (CDF) of the standard normal distribution up to the z-score corresponding to 130 grams.
First, we need to standardize the value of 130 grams using the formula:
z = (X - μ) / σ
where X is the value (130 grams), μ is the mean (173 grams), and σ is the standard deviation (34 grams).
z = (130 - 173) / 34 = -43 / 34 ≈ -1.2647
Using a standard normal distribution table or a calculator, we can find the CDF corresponding to this z-score. The CDF represents the proportion of values less than -1.2647 in the standard normal distribution.
Let P(Z < -1.2647) = p
The proportion of apples from the 2006 crop that were too small to sell is approximately p.
Probability of up to 10 apples too small to sell in a basket of 100 apples:
We can use the binomial distribution to calculate the probability of up to 10 apples being too small to sell in a basket of 100 apples.
Let X be the number of apples too small to sell in a basket of 100. The probability of a single apple being too small is p, as calculated in the previous step.
Using the binomial distribution formula, we can calculate the probability of X being less than or equal to 10:
P(X ≤ 10) = Σ (n choose x) * p^x * (1 - p)^(n - x)
where n is the number of trials (100), x is the number of successes (up to 10), and p is the probability of success (as calculated earlier).
This involves summing the probabilities for x = 0, 1, 2, ..., 10.
By calculating this probability, we can determine the likelihood of encountering up to 10 undersized apples in a picker's basket of 100 apples.
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Which point justifies the shaded area by satisfying StartFraction (y + 1) squared Over 6 EndFraction minus StartFraction (x + 2) squared Over 24 EndFraction greater-than-or-equal-to 1?
(12, 6)
(–2, 6)
(8, –6)
(–1, –2)
Please help asap test is timed!
(–2, 6) are the points that justify the shaded area
We can substitute the values of x and y from each point into the inequality and check if the inequality is satisfied or not.
Let's check each point:
For points (12, 6):
\((y+1)^2/6 -(x+2)^2/24\\ = (6+1)^2/6 - (12+2)^2/24 \\= 49/6 - 196/3 \\= -57.33\)
Here, the value of the expression is less than 1, so this point does not justify the shaded area.
For points (–2, 6):
\((y+1)^2/6 -(x+2)^2/24\\ = (6+1)^2/6 - (-2+2)^2/24 \\= 49/6\)
Here, the value of the expression is greater than or equal to 1, so this point does justify the shaded area.
For points (8, –6):
\((y+1)^2/6 -(x+2)^2/24 \\= (-6+1)^2/6 - (8+2)^2/24 \\= 25/6-100/24\)
Here, the value of the expression is greater than or equal to 1, so this point does not justify the shaded area.
For point (–1, –2):
\((y+1)^2/6 -(x+2)^2/24 \\= (-2+1)^2/6 - (-1+2)^2/24 \\= 1/6 - 1/24 \\= 1/8\)
Here, the value of the expression is less than 1, so this point does not justify the shaded area.
Therefore, the points that justify the shaded area are (–2, 6).
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What type of function is represented in the table?
x 0 1 2 3 4 5
y -7 -2 3 8 13 18
a.quadratic
b.exponential
c.logarithmic
d.linear
The type of function represented in the table is linear.
How to find the type of function represented in a table ?Let's check the type of function represented in the table.
You can tell if a table is linear by looking at how x and y change. If, as x increases by 1, y increases by a constant rate, then a table is linear. You can find the constant rate by finding the first difference.
It can also be found by using the linear equation,
y = mx + b
where
m = slopeb = y-interceptTherefore,
The x increases by y and the y increase by a constant rate of 5.
-2 - (-7) = 53 - (-2) = 58 - 3 = 5Therefore, the function represented in the table is linear.
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f(x) =4 over x - 3
g(x) =x - 2 over x
(a) Express the inverse function f −1
in the form f ^-1 (x)
Step-by-step explanation:
\(f(x) = \frac{4}{x - 2} \\ g(x) = \frac{x - 2}{x} \)
\( {f}^{ - 1} (x) ... \\ x = \frac{4}{y - 2} \\ y - 2 = \frac{4}{x} \\ {f}^{ - 1} (x) = \frac{4}{x} + 2\)
\( {g}^{ - 1} (x)... \\ x = \frac{y - 2}{y} \\ xy = y - 2 \\ xy - y = - 2 \\ y(x - 1) = - 2 \\ {g}^{ - 1} (x) = \frac{ - 2}{x - 1} \)
help meeeeeeeeeeeeeeeeeee pleaseee!!!!help meeeeeeeeeeeeeeeeeee pleaseee!!!!help meeeeeeeeeeeeeeeeeee pleaseee!!!!help meeeeeeeeeeeeeeeeeee pleaseee!!!!help meeeeeeeeeeeeeeeeeee pleaseee!!!!help meeeeeeeeeeeeeeeeeee pleaseee!!!!
Answer:
A
Step-by-step explanation:
Eliminate B and C because they don't pass through (0,1).
Eliminate D because it doesn't decrease quickly enough.
If n represents a number, then write an expression for a number that is twice n
Help please its for algebra class please help thank you a lot like thanks u guys save my day
It’s pre algebra class
Answer:
y=n(2)
Step-by-step explanation:
i NEED help.
i do not understand this question at all
Answer:
1)8.5 units
2)7 units
Step-by-step explanation:
To find the distance between two points use distance formula.
1) ( 3 , 1) & (6 , 9)
\(\sf \boxed{\bf Distance = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}}\)
\(\sf AB = \sqrt{(3-6)^2+(1-9)^2}\\\\~~~~~ = \sqrt{(-3)^2+(-8)^2}\\\\~~~~~ =\sqrt{9+64}\\\\~~~~~=\sqrt{73}\\\\\)
= 8.5
_________________________________________________
2)(3 , 8) & (8 , 3)
\(\sf AB = \sqrt{(3-8)^2+(8-3)^2}\\\\\)
\(\sf =\sqrt{(-5)^2+(5)^2}\\\\=\sqrt{25+25}\\\\=\sqrt{50}\\\\=7\)
7.4.2. what values of x satisfy the following equations? (a) p(−x ≤ t22 ≤ x) = 0.98
The values of x that satisfy the equation p(−x ≤ t22 ≤ x) = 0.98 are all values between -2.518 and 2.518, inclusive.
The expression p(- x ≤ t22 ≤ x) represents the probability of a t-distribution with 22 degrees of freedom lying between - x and x.
We want to find the values of x such that this probability is 0.98.
We can use a table of t-distribution probabilities or a calculator to find the value of t for which the probability of a t-distribution with 22 degrees of freedom lying between −t and t is 0.98.
This value is , 2.518.
Therefore, we need to solve the inequalities:
-2.518 ≤ -x ≤ 2.518
Solving for x, we get:
-2.518 ≤ -x x ≤ 2.518
Therefore, the values of x that satisfy the equation p(−x ≤ t22 ≤ x) = 0.98 are all values between -2.518 and 2.518, inclusive.
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Calculate the perimeter of this right- angled triangle. Give your answer in metres (m) to 1 d.p. 7m 16 m
Answer:
P = 37.4 m
Step-by-step explanation:
let the third side of the triangle be x
using Pythagoras' identity in the right triangle.
x² + 7² = 16²
x² + 49 = 256 ( subtract 49 from both sides )
x² = 207 ( take square root of both sides )
x = \(\sqrt{207}\) ≈ 14.4 m ( to 1 decimal place )
the perimeter (P) is then the sum of the 3 sides
P = 7 + 16 + 14.4 = 37.4 m
The variables x and y vary directly. Use the given values to write an equation that relates x and y.x = 18y = 6a. y = two-thirds x b. y = one-half x c. y = one-third x d. y = two-thirds x squared
The equation representing the relation of x and y for the given values and condition is given by option c. y = one-third x .
x and y vary directly,
This implies,
y ∝x
⇒y = kx
where k is the constant of proportionality.
Using the given values x = 18 and y = 6a, we can solve for k,
⇒6a = k(18)
⇒k = 6a/18
⇒k = a/3
Substituting this value of k into the equation y = kx, we get,
⇒y = (a/3)x
We can simplify this equation as,
⇒y = (1/3)ax
Let us consider the value of a = 1.
Therefore, the equation that relates x and y when x and y vary directly for the values x = 18, y = 6a is option c. y = (1/3)x.
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