The Luminosity of Alpha Centauri A. Alpha Centauri A lies at a distance of 4.4 light-years and has an apparent brightness in our night sky of 2.7x10^(-8) watt/m^2. Recall that 1 light-year=9.5x10^12 km=9.5x10^15 m.
a) Use the inverse square law for light to calculate the luminosity of Alpha Centauri A.

Answer:

B. Use the layers' thickness and the current rate of deposition to calculate the time.

3.The ranking of quantities in decreasing order of distance is as follows: 1 Mm (Megameter) > 1 km (Kilometer) > 100 m (Meter) > 1 cm (Centimeter) > 50 mm (Millimeter) > 1 mm (Millimeter) > 5 million nm (Nanometer).

8. A) When the size of a milk chocolate bar is reduced to 5.000 g, the amount of sugar in milligrams is approximately 73.15 mg.

b) The percentage of sugar in a 14.630 g milk chocolate bar is approximately 63.60%.

10 A) 4.1 ounces of a steroid ointment is approximately 120 grams.

D) Each blueberry high-fiber muffin contains approximately 24 grams of dietary fiber.

1. Ranking the quantities in decreasing order of distance:

1 Mm (Megameter) --> 1 km (Kilometer) --> 100 m (Meter) --> 50 mm (Millimeter) --> 1 cm (Centimeter) --> 1 mm (Millimeter) --> 5 million nm (Nanometer)

2. a). To find the amount of sugar in milligrams when the size of the milk chocolate bar is reduced to 5.000 g, we can use the proportion:

14.630 g / x = 5.000 g / 1000 mg

Solving for x, we get:

x = (5.000 g * 14.630 g) / 1000 mg ≈ 73.15 mg

So, when the chocolate bar size is reduced, the amount of sugar in milligrams will be approximately 73.15 mg.

b). To calculate the percentage of sugar in a 14.630 g milk chocolate bar, we use the formula:

Percentage = (Amount of sugar / Total weight) * 100

Percentage = (9.315 g / 14.630 g) * 100 ≈ 63.60%

So, the percentage of sugar in a 14.630 g milk chocolate bar is approximately 63.60%.

10. a). To convert 4.1 ounces of a steroid ointment to grams, we use the conversion factor:

1 lb = 16 oz, 1 lb ≈ 453.592 g

4.1 oz * (1 lb / 16 oz) * 453.592 g ≈ 119.0792 g ≈ 120 g (to two significant figures)

So, the pharmacist needs to prepare approximately 120 grams of ointment.

D). If blueberry high-fiber muffins contain 51% dietary fiber and a package weighing 16 oz contains six muffins, we can calculate the amount of fiber in each muffin as follows:

Amount of fiber per muffin = (Weight of one muffin * Percentage of dietary fiber) / 100

Amount of fiber per muffin = (16 oz / 6) * (51 / 100) * 28.3495 g ≈ 24 g (to two significant figures)

Each blueberry high-fiber muffin contains approximately 24 grams of dietary fiber.

For more such questions sugar,Click on

https://brainly.com/question/454703

#SPJ8

The extension of the spring is 4.83 m, if work done is 35 Newton and spring constant is 3 k N/m.

The spring constant, k, is a measure of the stiffness of the spring. it's far one of a kind for unique springs and materials. the larger the spring regular, the stiffer the spring and the greater.

Spring constant of 3 k N/m,

The amount of work done in extending is 35 N

WORK DONE by spring force = 1/2 k X²

                                                 ⇒0.5 * 3 * X²

                                   35 N = 0.5 * 3 * X²

                                 X² = 35/1.5

                                  x = \(\sqrt{23.33}\)

                                     X = 4.83 m

Learn more about spring constant here:-https://brainly.com/question/1968517

#SPJ1

The extension of the spring is can be found out by using the Work Done due to extension in Spring Constant K. The extension in the spring is 4.83m.

The spring constant, k, is a measure of the stiffness of the spring. It is for springs and materials which measures the ratio of force that affects the spring and the displacement caused by the force action.

Spring constant depends on the stiffness of the spring, wire thickness, number of turns in wound coil, length of spring and diameter of the coil.

Given:

Spring constant = 3000 N/m

Work Done in extension= 35 N

Let the extension in spring by x.

∴ Work Done by spring force = 1/2 kx²

                        Work done   = 0.5 × 3 × x²

    ⇒                                 35 N = 0.5 × 3 × x²

    ⇒                                      x² = 35/1.5

     ⇒                                         x = 4.83m

Hence, the extension of spring is 4.83m.

Learn more about Spring Constant here, brainly.com/question/1968517

#SPJ1

The intensity of sound is inversely proportional to the square of the distance from the source. The intensity of sound at 4 m away from the source is approximately \(0.993W/m^{2}\) (watts per square meter).

The intensity of sound is defined as the power per unit area. According to the inverse square law for sound propagation, the intensity of sound is inversely proportional to the square of the distance from the source. Mathematically, it can be expressed as

\(I=P/(4\pi r^{2})\)

where I is the intensity, P is the power, and r is the distance from the source.

Given that the power of sound at the source outlet is 100 W and the distance from the source is 4 m, we can substitute these values into the formula. Thus, we have

\(I = 100 W / (4\pi (4 m)^2)\)

Simplifying this expression, we find that the intensity of sound at 4 m away from the source is approximately \(0.993W/m^{2}\) (watts per square meter).

Learn more about intensity of sound here:

https://brainly.com/question/17583145

#SPJ11

Answer: 8.10m/s

Explanation:

using second eq of motion s=ut+1/2at

2

as u=0, a=

t

2

2s

​

=

5.21

2

2∗110

​

=8.10m/s

2

1.44*10^-3N  is the force on each other. when 33 centimeters separates one charge from another charge. They both have charges of 1.2 x 10-5 coulombs.

Charge on the first sphere, q 1​ =1.2 x 10^-5  C

Charge on the second sphere, q 2 =1.2 x 10^-5  C

Distance between the spheres, r=30cm=0.3m

F= 4πε

​ q 1 q 2/  r2

​Where, ε 0

​ = Permittivity of free space 4πε 0

=9×10^9Nm2

F= (0.33) 2

1.2 x 10^-5 * 1.2 x 10^-5  C = 1.44*10^-3N

Hence, force between the two small charged spheres is 1.44*10^-3N.

The charges are of same nature. Hence, force between them will be repulsive.

learn more about Charge here:

https://brainly.com/question/14467573

#SPJ4

Answer:

a = 0.98J

Explanation:

PE = mgh

PE = 0.1 x 9.8 x 1

PE = 0.98J

(a) The potential energy of the car at the beginning of the experiment is 9.8(m) J.

(b) The kinetic energy of the car for group a is 3.125(m) J.

(c) The kinetic energy of the car for group b is 4.5(m) J.

The potential energy of the car is calculated as follows;

P.E = mgh

where;

P.E = m x 9.8 x 1

P.E = 9.8(m) J

K.E = ¹/₂mv²

K.E = ¹/₂ x m x (2.5)²

K.E = 3.125(m) J

K.E = ¹/₂mv²

K.E = ¹/₂ x m x (3)²

K.E = 4.5(m) J

Learn more about kinetic energy here:https://brainly.com/question/25959744

#SPJ2

Answer:

the cognitive abilities of an individual to learn from experience to reason well, and to cope effectively with the demands of daily living

Explanation:

Yes that can be understood by a simple example

Suppose two people are in exam

\(\large\longrightarrow \) Intelligence is the cognitive abilities of an individual to learn from experience to reason well, and to cope effectively with the demands of daily living.

Answer:

51.02m

Explanation:

KE = 1/2mv2

Where k.e = 250J

mass = 0.5 kg

g = 9.8 m/s2

250= 1/2×0.5×v^2

250= 0.5×0.5×v^2

250= 0.25v^2

v^2 = 250/0.25

v^2 = 1000

v =√1000

v = 31.62m/s

v^2= u^2-2gh........... (1)

Since the object will stop at it highest point, hence it final velocity there will be zero and since it is moving up against the gravity g= -9.8m/s^2. That was why the formula in equation 1 has a negative sign

From h = u^2/2g

Where v = 31.62m/s

g = 9.8m/s^2

H = (31.62m/s)^2/9.8×2

H= 1000/19.6

= 51.02m

Hence the height of it travelling will be

51.02m

Answer: 110000

Explanation:

26/9=30.5555555556

30.5555555556 x 60=1833.33333333

110000 x 60=110000

Answer:

what are the statements

It is estimated that roughly 15-20% of the total mass of a galaxy is made up of luminous or normal matter.

This matter includes stars, gas, and dust that can be seen through telescopes. However, the majority of the mass in a galaxy is made up of dark matter. Dark matter is a type of matter that cannot be seen or detected directly, but its presence is inferred by its gravitational effects on visible matter.
Scientists have used various methods to estimate the mass of a galaxy, including measuring the motions of stars and gas, observing the effects of gravitational lensing, and analyzing the cosmic microwave background radiation. These methods have all confirmed that the amount of luminous matter in a galaxy is a relatively small fraction of its total mass.
Understanding the composition of galaxies is an important area of research in astronomy and astrophysics. By studying the distribution of matter in galaxies, scientists hope to gain insights into the formation and evolution of these cosmic structures.

To know more about Matter visit:

https://brainly.com/question/30197641

#SPJ11

Answer: A. When half the parent nuclei in a sample have become daughter nuclei

Explanation:

Answer:

Distance : 0.06533 meters or 65.33 mm

Explanation:

To solve this problem we can make the forces equal when the system is at equilibrium.

mass \(*\) gravity ( constant ) = spring constant

where l = the length at which the rubber band is stretched

0.2 kg \(*\) 9.8 m / s² = 30 N/m

1.96 kg \(*\) m / s² = 30 N/m

l = 1.96 kg \(*\) m / s² / 30 N/m = 0.06533 meters / 65.33 mm

The rubber band is stretched a distance of 0.06533 meters, or 65.33 mm.

Answer:

0.065

Explanation:

Apex i just got it right

If the electronic configuration of an atom is 1s2 2s2 2p2 then it has 6 electrons.

This electronic configuration corresponds to carbon, whose atomic number is 6.

The electronic configuration is a form of organization by layers that the electrons have.

Its importance is based on the ability to determine through it the total properties of chemical combination of atoms, which is equivalent to their location on the periodic table of elements.

Furthermore, the electronic configuration of an element defines its binding energy and thus its state at room temperature.

Learn more about electronic configuration at https://brainly.com/question/29757010

#SPJ4

Answer:

The moon's gravity pulls the Earth to make tides.

Explanation:

The Moons Gravity Pulls On The Earth With Different  Strenght Making High Tide And Low Tide.

Hope This Helps!

Answer:

We know that the period of a pendulum is written as:

T = 2*pi*√(L/g)

where:

g = gravitational acceleration = 9.8m/s^2

pi = 3.1415...

L =  length of the pendulum, in this case, is the length of the brass pendulum.

Now, we know that the brass dilates when the temperature increases.

Then if the temperature increases, the value of L will increase, which means that the period T will also increase, because L is in the numerator of T.

If the period increases the complete motion of the pendulum needs more time, this would mean that the clock will run slower.

If the temperature decreases, the opposite occurs, the value of L decreases, and then the period also decreases, which means that the clock will run faster.

The claim that Diego made and supported with the table is that 10+x2 is always greater then 2x, however this is not correct.

Diego is wrong because when x becomes 6 or greater than 6, 10+x² will no longer be greater than 2ˣ. Lets say that x becomes 6 and we plug it into the two equations, we will have the following:

10 + 6² = 46 and

2ˣ= 2 raised to the power of 6 = 64

Now in this case, Diego has been proved wrong because the value obtained fromt he second equation is greater than that of the first equation. So, it is not reasonable to agree with Diego's submission.

Question:

The table represent the following data:

x values: 1, 2, 3, 4, 5

10 + x2:   11, 14, 19, 26

2x:         2, 4, 8, 16,

Learn more about equations here:

https://brainly.com/question/22688504

#SPJ1

Answer:

reflection of the moon, or just reflection

Explanation:

when the sunlight hits the moon, it refects back to earth making the moon appear to glow          

Answer:

reflecting

Explanation:

the sun's light reflects off the moon, making the moon visible

Answer:

At neutron star density, the Earth's whole mass would fit inside a 305-meter-diameter sphere.

Explanation:

The last time humans set foot on the moon was during the Apollo 17 mission. This mission took place from December 7th to December 19th, 1972.

Astronauts Eugene Cernan and Harrison Schmitt were the two individuals who walked on the lunar surface during this mission, making them the most recent humans to have done so. The Apollo 17 mission was the final manned lunar landing in the Apollo program, which was a series of space missions conducted by NASA between 1961 and 1972 with the goal of landing humans on the moon and returning them safely to Earth. Apollo 17 marked the sixth successful lunar landing, with a total of 12 astronauts having walked on the moon during these missions. During their time on the lunar surface, Cernan and Schmitt conducted scientific experiments, collected lunar samples, and took photographs, contributing to the overall understanding of the moon's geology and environment.

In summary, the last time humans set foot on the moon was in December 1972, during the Apollo 17 mission, which featured astronauts Eugene Cernan and Harrison Schmitt exploring the lunar surface. Since then, no other manned lunar missions have taken place, but plans for future moon landings are currently being developed by various space agencies around the world.

To know more about moon, visit:

https://brainly.com/question/30653068

#SPJ11

If you were to take a voyage across the Milky Way, you would likely spend most of your time in option (d) warm, rarefied clouds of atomic hydrogen

The space between stars in our galaxy is not completely empty, but rather contains a tenuous mix of gases, primarily hydrogen, that are extremely hot and diffuse, with temperatures of millions of degrees. This is known as the interstellar medium (ISM).

Warm, rarefied clouds of atomic hydrogen are particularly interesting because they are the birthplace of new stars. When these clouds become dense enough, gravity can cause them to collapse, leading to the formation of proto stars and eventually fully formed stars. As a result, these regions are often studied by astronomers to better understand the process of star formation.

While there are also dusty molecular clouds and star clusters in the Milky Way, the former are typically colder and denser than the warm, rarefied clouds of atomic hydrogen, while the latter are densely packed groups of stars that you would likely pass through relatively quickly.

Therefore, the correct option is (d) warm, rarefied clouds of atomic hydrogen

Learn more about voyage here

brainly.com/question/29216261

#SPJ4

The given question is incomplete, the complete question is:

If you were to take a voyage across the Milky Way, what kind of material would you spend most of your time in?

A) empty space—a pure vacuum

B) dusty molecular clouds

C) star clusters

D) warm, rarefied clouds of atomic hydrogen

E) cool, dense clouds of atomic hydrogen

Answer: b) - 8.0 \(m/s^{2}\)

Explanation: Acceleration is a vector indicating a rate an object's velocity changes over time:

a = \(\frac{v}{t}\)

and its SI unit is \(m/s^{2}\)

For the minivan to stop, it takes a period of 0.5s:

a = \(\frac{4.0}{0.5}\)

a = 8.0 \(m/s^{2}\)

As a vector, acceleration has magnitude (8\(m/s^{2}\)) and direction. Since it is stopping, the minivan has a direction opposite to the other car, which means acceleration is negative. So: a = \(- 8.0 m/s^{2}\).

A net forward force as well as gravitational force pulls the marble downwards whereas frictional force slows it down.

A force is an agent which causes a change in the motion or state of an object.

Forces are of two types:

Andrew applies force on the marble causing it to move.

When Andrew pokes the marble, he gives it net forward force. As the marble rolls down the ramp, gravitational force pulls it down.

The movement of the marble is slowed down by frictional force from the ramp.

Therefore, a combination of applied force and gravitational force moves the marble forward, while frictional force slows it down.

Learn more about force at: https://brainly.com/question/141439

#SPJ4

Answer:

Applied, Gravitational, and Frictional.

Explanation

hope it helps :)

Answer:

15.3 N

Explanation:

Force = mass x acceleration

= 2.55 kg x 6.00 m/s^2

= 15.3 kgm/s^2 = 15.3 N

The required force to accelerate a 2.55 kg remote-controlled toy car at a rate of 6.00 m/s^2 be 15.3 N.

The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.

An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. The application of force is the location at which force is applied, and the direction in which the force is applied is known as the direction of the force.

Given parameters:

Mass of the remote-controlled toy car : m = 2.55 kg.

Acceleration of  the remote-controlled toy car :a =  6.00 m/s^2

Now according to Newton's 2nd law of motion,

Force = mass x acceleration

= 2.55 kg x 6.00 m/s^2

= 15.3 kgm/s^2

= 15.3 N

Hence, required force is 15.3 N.

Learn more about force here:

https://brainly.com/question/13191643

#SPJ6

Answer:

Incomplete question, but let analyse generally a torque acting on a rotating body

Explanation

Toque is given as

τ = r × F

Where

τ is the torque (Nm)

r is the position vector (m)

F is the force (N).

Let assume we have the following data

F= x•i + y•j + z•k

Also let assume the position vector is

r'= a•i + b•j + c•k

a. The first question, torque at the origin

The origin will have a position vector of r1(0,0,0)

Then, the displacement is

r=AB=AO+OB=-OA+OB

r = r'-r1 = (a, b, c)-(0,0,0)

r=(a, b, c)

Then, the torque is given as

τ = r×F

τ = (a, b, c) × (x, y, z)

Note that

i×i=j×j=k×k=0

i×j=k, j×i=-k

j×k=i, k×j=-i

k×i=j, i×k=-j

τ = (a•i + b•j + c•k) × (x•i + y•j + z•k)

τ = a•i×(x•i + y•j + z•k) + b•j×(x•i + y•j + z•k) + c•k×(x•i + y•j + z•k)

τ = (a•i × x•i)+ (a•i × y•j) + (a•i × z•k) + (b•j × x•i) + (b•j × y•j) + (b•j × z•k) + (c•k × x•i) + (c•k × y•j) + (c•k × z•k)

Now, using the above law.

τ = 0 + ay•k - az•j - bx•k + 0 + bz•i + cx•j - cy•i + 0

τ= ay•k - az•j - bx•k + bz•i + cx•j -cy•i

Then, rearranging

τ = (bz - cy)•i + (cx - az)•j + (ay - bx)•k

This is general formula for the torque at the origin, so you can apply it to the given values in your question because the question given is not complete.

b. Now let, analyse at the position vector (2.61 m, 0, -8.03 m)

Using the same analysis

position vector of r1(2.61, 0, -8.03)m

Then, the displacement is

r=AB=AO+OB=-OA+OB

r = r'-r1 = (a, b, c)-(2.61,0,-8.03)

r=(a-2.61, b, c+8.03)

Then, the torque is given as

τ = r×F

τ = (a-2.61, b, c+8.03) × (x, y, z)

Note that

i×i=j×j=k×k=0

i×j=k, j×i=-k

j×k=i, k×j=-i

k×i=j, i×k=-j

τ =([a-2.61]•i, b•j, [c+8.03]•k) × (x•i + y•j + z•k)

τ = (a-2.61)•i×(x•i + y•j + z•k) + b•j×(x•i + y•j + z•k) + (c+8.03)•k×(x•i + y•j + z•k)

τ = ((a-2.61)•i × x•i)+ ((a-2.61)•i × y•j) + ((a-2.61)•i × z•k) + (b•j × x•i) + (b•j × y•j) + (b•j × z•k) + ((c+8.03)•k × x•i) + ((c+8.03)•k × y•j) + ((c+8.03)•k × z•k)

Now, using the above law.

τ = 0 + (a-2.61)y•k - (a-2.61)z•j - bx•k + 0 + bz•i + (c+8.03)x•j - (c+8.03)y•i + 0

τ= (a-2.61)y•k - (a-2.61)z•j - bx•k + bz•i + (c+8.03)x•j -(c+8.03)y•i

Then, rearranging

τ = (bz - cy - 8.03y)•i + (cx + 8.03x - az - 2.61z)•j + (ay - 2.61y - bx)•k

This is general formula for the torque at the point (2.61 m, 0, -8.03 m), so you can apply it to the given values in your question because the question given is not complete.

(a) Torque acting on the pebble about the origin is (-1.5i - 4j - 1k) Nm.

(b) Torque acting on the pebble about the given coordinate is 20j Nm.

Torque is defined as the rotational analogue of force. It is the cross product of force and the perpendicular distance.

Here,

The position coordinates of the pebble, r = (0.5 m)j - (2 m)k

Force acting on the pebble, F =  (2 N)i - (3 N)k

(a) About the origin

 Torque acting on the pebble, τ = r x F

   τ = (0.5j - 2k) x (2i - 3k)

   τ = (0.5j x 2i) + (0.5j x -3k) + (-2k x 2i) + (-2k x -3k)

   τ = -1k - 1.5i - 4j + 0

   τ = (-1.5i - 4j - 1k) Nm

(b) At a point with coordinates (8.62m, 0, -2.93m)

    Torque acting on the pebble,

   τ = r x F

   τ = (8.62i - 2.93k) x (2i - 3k)

   τ = (8.62i x 2i) + (8.62i x -3k) + (-2.93k x 2i) + (-2.93k x -3k)

   τ = 25.86j - 5.86j

   τ = 20j Nm

Hence,

(a) Torque acting on the pebble about the origin is (-1.5i - 4j - 1k) Nm.

(b) Torque acting on the pebble about the given coordinate is 20j Nm.

To learn more about torque, click:

https://brainly.com/question/19104073

#SPJ2

Your question was incomplete, but most probably your question was:

Force (2 N)i - (3 N)k acts on a pebble with position vector (0.5 m)j - (2 m)k, relative to the origin. What is the resulting torque acting on the pebble about (a) the origin and (b) a point with coordinates (8.62 m, 0, -2.93 m)

I don't know sorry didn't make me want you say you didn't know how I feel about me being that way and that I didn't even want you say I was wrong and you didn't want me to be to have a good time

The student's reasoning is correct in the sense that both scenarios involve the displacement of water. When the anchor is in the boat, it causes the boat to sink lower, displacing more water and raising the water level in the lake. When the anchor is immersed in the pond, it also displaces water due to its volume.

Observations that fit with the student's prediction would be that the water level in the pond does not change when the anchor is placed on the bottom.
1. The water level in the lake rises when the anchor is added to the boat, indicating that the anchor's weight is causing the boat to displace more water.
2. The anchor's volume causes water displacement when it is submerged in the pond, which can be observed as the water level around the anchor rises.

Learn more about displacement here ;

https://brainly.com/question/29769926

#SPJ11

The person has an upward acceleration of 0.70 m/s2 and is lifted from rest through a distance of 11 m is 3.92 m

The tension in the cable is 829.5 N

Work done by tension cable is 9124.5 joules

Work done by man weight is -8156.2

Total energy of person is 608.3 joules.

A rescue helicopter lifts a 79 kg person straight up by means of a cable. the person has an upward acceleration of 0.70 m/s2 and is lifted from rest through a distance of 11 m.

Using vertical equilibrium we have that, T-mg=ma.

The tension in the cable = 79(9.8+0.7) = 829.5 N.

Work done by tension cable is T_{s} = 829.5×11= 9124.5 joules

Work done by man weight = mg×s= -79×9.8×11 = -8156.2

Hence, we have total energy of person = work by tension-work by weight = 608.3 joules

Hence, \(\frac{1}{2} mv^{2}\) = 608.3v= 3.92 metres.

For such more questions about tension in the cable:

https://brainly.com/question/22914079

#SPJ4