the magnitude of the normal acceleration is group of answer choices proportional to radius of curvature. inversely proportional to radius of curvature. inversely proportional to diamter of curvature. zero when velocity is constant.

The wood will sink lower in the water when the container is sealed and pressurized above atmospheric pressure.  

When the container is sealed and pressurized above atmospheric pressure, the pressure inside the container increases. According to Boyle's Law, the volume of a gas is inversely proportional to its pressure at a constant temperature. This means that as the pressure inside the container increases, the volume of the air trapped in the pores of the wood decreases.

This results in a decrease in the buoyant force acting on the wood, which causes the wood to sink lower in the water. Therefore, the correct answer is "it sinks lower in the water." This phenomenon is also observed in the diving and submarine industry, where pressure changes affect the buoyancy of submerged objects.

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Full Question: a piece of unpainted porous wood barely floats in an open container partly filled with water. the container is then sealed and pressurized above atmospheric pressure. what happens to the wood?

correct: your answer is correct. explain your answer.

The direction of the magnetic force on the proton is upward (perpendicular to both the proton's motion and the magnetic field).

To determine the direction of the magnetic force on the proton, we use the right-hand rule. First, point your right thumb in the direction of the proton's motion (to the right). Next, curl your fingers in the direction of the magnetic field (into the page). Your palm will be facing the direction of the force on a positive charge, like a proton. In this case, the magnetic force on the proton is pointing upward.

This is because the magnetic force acts perpendicular to both the charge's motion and the magnetic field, following the equation F = q(v x B), where F is the magnetic force, q is the charge, v is the velocity vector, and B is the magnetic field vector.

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Answer:

Explanation:

In physics, work can be described as force multiplied by the displacement of the object (distance caused by the force acted on the object).

Work is a form of energy, therefore, it is measured in joules.

If Alex pushed on an object with 10N of force, and the object moved 2 meters, the work of Alex will be equal to:

W = Ft

W = 10N * 2m

W = 20 Joules

But, if we have John, that pushed on an object with 2N of force, but, since the object was way smaller, therefore it had way less inertia, the object moved a distance equal to 10 meters. Let's also calculate his work.

W = Ft

W = 2N * 10m

W = 20 Joules

And we got the same result.

Work can also be used to calculate power.

Power is equal to P = Work / time

It can also be written as P = delta Work / delta time

Power is measured in joules per second.

With power you can make the difference between someone that got a 2 kg object up in 2 second, and someone that got a 2 kg object up in 5 second.

The more powerful one would be the one who managed to make the same work in less time.

Hope it Helped!

Work is described as: the measure of energy transfer resulting from the application of force over a displacement.

In the field of physics, work is most accurately defined as the outcome of multiplying the force exerted on an object by the distance the object is displaced in the same direction as the force.

This calculation serves to quantify the energy transferred to or from the object. For instance, if an individual applies a 50 Newton force to push a box across a 5-meter distance in the force's direction, the work done on the box would equal 250 Joules (50 N × 5 m).

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i-beams are the choice for structural skyscrapers because of their high functionality.

the shape of i-beams makes them excellent for unidirectional bending parallel to the web.

the horizontal flanges resist the bending movement, while the web resists the shear stress.

                                           ♡  hope this helped!  ♡

Answer: some may argue that while teacher’s only provide service to a single classroom, superstar athletes are entertaining fans all around the world, enticing people with a feeling of relaxation and excitement. Obviously, what these individuals must not be aware of is the most important man in our nation, the president, who makes critical decisions that affect the entire world every day, only makes $400,000 a year. While President Obama is hard at work reviving the economy, the unproven rookie in the MLB is earning way over that figure. Furthermore, police officers, firefighters, and doctors save lives while risking their own for a fraction of what sports stars make. People in the military leave their families at home to defend and protect the country knowing they may never return. It's truly a pity that none of these true heroes are given the same recognition by society as athletes such as Brett Favre or Michael Jordan are given. While I do understand that making it into the pros is not an easy thing to do, and that it takes a tremendous number of hours of hard work and dedication every day to earn a job in professional sports, these people do nothing more than entertain the general public.

Explanation:

Answer:

Wouldn't it be great to make nearly $111 million a year simply to play a game? Tiger Woods, along with many other professional athletes, certainly think so. But do these athletes really deserve all that money?

In my mind, absolutely not. Professional athletes are making too much money in a society where salaries and wages are traditionally based on the value of one's work. In today's society, one should be paid according to the job’s economic importance and their value to society.

Teaching is one of the most economically important occupations because our future economy relies on the education of its youth, yet teachers are paid astronomically less than the average professional athlete is. In fact, each basket Kobe Bryant scores earns him equivalent to the average classroom teacher’s yearly salary.

However, some may argue that while teacher’s only provide service to a single classroom, superstar athletes are entertaining fans all around the world, enticing people with a feeling of relaxation and excitement.

Obviously, what these individuals must not be aware of is the most important man in our nation, the president, who makes critical decisions that affect the entire world every day, only makes $400,000 a year. While President Obama is hard at work reviving the economy, the unproven rookie in the MLB is earning way over that figure.

Furthermore, police officers, firefighters, and doctors save lives while risking their own for a fraction of what sports stars make. People in the military leave their families at home to defend and protect the country knowing they may never return. It's truly a pity that none of these true heroes are given the same recognition by society as athletes such as Brett Favre or Michael Jordan are given.

While I do understand that making it into the pros is not an easy thing to do, and that it takes a tremendous number of hours of hard work and dedication every day to earn a job in professional sports, these people do nothing more than entertain the general public.

Moreover, in my mind, if these athletes want to continue to be rewarded with the fame and fortune that is unfairly bestowed upon them, they must prove to the world that they are going to be positive role models for future athletes, and those who admire them.

Explanation:

found if off some website lol hope it helps! <3

Answer:

The lost mass is converted to energy according Einstein's equation:

E = m c^2

where m is the mass converted to energy and c is the speed of light

Answer:

1) Mercury

2) Venus

3) Earth

4) Mars

Explanation:

Answer:

The for inner/terrestrial planets are Mercury, Venus, Earth and Mars

Explanation:

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                           Have a nice day and I hope it helps!

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The energy required to stretch the spring from a 5.00cm to a 6.00cm elongation is 30 J

From Hooke's law, Force = Elastic constant * extension

F = K*e

K = Elastic constant; e = extension

solving for K

The energy required to stretch the spring from 5.00 to 6.00 cm is then calculated;

Therefore, the energy required to stretch the spring from a 5.00cm to a 6.00cm elongation is 30 J

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The amount of catalyst (W/kg) required for a fluidized-bed reactor, according to the Kunii-Levenspiel bubbling-bed model, we can substitute the calculated values into the catalyst weight equation:

W = Q * τc * (1 - ε) / (ε * ρc * A * U

The amount of catalyst required for the fluidized-bed reactor, we need to calculate the catalyst weight based on the given information and the Kunii-Levenspiel bubbling-bed model.

Production rate: 60,000 MT/year

Total moles entering: 10.57

Molar flow rate of feed: 0.577 kmol/sec

Conversion based on C3H6(A): 70%

Operating conditions: T = 400°C, P = 2 bar

Fraction of time in operation in a year: 0.94

Bed properties: D = 0.1 m, dp = 0.05 mm, pp = 2500 kg/m³, uf = 1.44 kg/h

Constants: U = 0.002 m/sec, a = 0.6, D = 0.14 m²/h, epa = 0.5, E = 0.6, KA = 1 s⁻¹, u = 720 m/h, Y = 0.004, T Yorks Koverall = YKA

To estimate the catalyst weight, we can use the following equation derived from the Kunii-Levenspiel model:

W = Q * τc * (1 - ε) / (ε * ρc * A * U * Koverall)

W = catalyst weight (kg)

Q = feed rate (kmol/sec)

τc = average residence time of catalyst in the reactor (sec)

ε = voltage (fraction)

ρc = catalyst bulk density (kg/m³)

A = cross-sectional area of the bed (m²)

let's calculate the average residence time of the catalyst, τc:

τc = (1 - ε) / (ε * u)

we need to calculate the cross-sectional area of the bed, A:

A = (4 * Q) / (π * uf * ε)

we can substitute the calculated values into the catalyst weight equation:

W = Q * τc * (1 - ε) / (ε * ρc * A * U * Koverall)

we can substitute the given values and calculate the catalyst weight.

Some of the values needed for the calculation are missing in the provided information (such as catalyst bulk density and Koverall). Without these values, it is not possible to provide an exact estimation for the catalyst weight.

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If the universal gravitation constant G is expressed as \(m^ps^qkg^r\), the values of p,q, and r is 3, -2, and -1 respectively.

Newton's law of gravitation, states that any particle of matter in the universe attracts any other with a force varying directly as the product of the masses and inversely as the square of the distance between them.

Mathematically, this law is given as;

F = GmM/R²

where;

The S.I unit of G is calculated as;

G = FR²/mM

G = (kg.m/s² x m² ) / (kg²)

G = (m³)/(kg.s²)

If G is expressed as \(m^ps^qkg^r\), the values of p,q, and r is calculated as follows;

From the S.I unit of G, the values of p,q, and r  is;

p = 3

q = -2

r = - 1

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The sound waves from Juan's voice are lower in frequency than those from Joseph's voice, and they are lower in hertz.

The frequency of a sound wave refers to the number of cycles or vibrations it completes in one second and is measured in hertz (Hz). In this case, since Joseph has a higher-pitched tenor voice, his vocal cords vibrate at a higher frequency compared to Juan's lower-pitched baritone voice. Thus, the sound waves produced by Joseph's voice have a higher frequency, measured in hertz.

Decibels (dB), on the other hand, measure the amplitude or intensity of sound waves, indicating their loudness. The question does not mention any differences in amplitude between Juan and Joseph's voices, so we cannot conclude that the sound waves are lower in decibels. The distinction lies in the frequency, which affects the pitch of the voice, with Juan's voice being lower in frequency compared to Joseph's.

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Answer:

\(m = \frac{-2}{3}\)

Explanation:

Given

Points: (1,-1) and (-5,3)

Required

Determine the slope

The slope of a line is represented by m and is calculated as thus;

\(m = \frac{y_1 - y_2}{x_1 - x_2}\)

Where

\((x_1,y_1) = (1,-1)\)

\((x_2,y_2) = (-5,3)\)

Substitute these values in the given formula

\(m = \frac{-1 - 3}{1 - (-5)}\)

\(m = \frac{-1 - 3}{1 +5}\)

\(m = \frac{-4}{6}\)

Simplify fraction

\(m = \frac{-2}{3}\)

Hence, the slope of the line is \(m = \frac{-2}{3}\)

Answer:

The answer is 1/3

Explanation:

Change in y/Change in x

-2/-6=1/3

Answer:

h = 30.61 m

Explanation:

In this problem they indicate the pressure at the bottom of the lake and the density of the water, for which they must ask what is the depth of the lake.

The pressure is given by the expression

           P = \(P_{atm}\) + rho g h

           P - P_{atm} = rho g h

The gauge pressure value is P- P_{atm} = 3 105 N / m²

          h = \(\frac{P - P_{atm}}{ \rho \ g}\)

let's calculate

          h = \(\frac{3 \ 10^5}{1000 \ 9.8}\)

          h = 30.61 m

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 75 × 3

We have the final answer as

Hope this helps you

The force that pushes groundwater from pore space to pore space when below the water table is primarily due to the pressure gradient within the aquifer. This pressure gradient is caused by the weight of the overlying water and the force of gravity.

Below the water table, the spaces between soil or rock particles are filled with water. These spaces are known as pore spaces. The water table represents the upper surface of the saturated zone, where all the pore spaces are filled with water. gravity acts vertically downward, causing the weight of the water above a particular point to exert a downward force. As a result, the water pressure increases with depth. This increase in pressure creates a pressure gradient within the aquifer.

The pressure gradient drives the flow of groundwater from areas of higher pressure to areas of lower pressure. When a well is drilled into the aquifer below the water table, water will naturally flow into the well and rise to the level of the water table. This is because the pressure is higher below the water table compared to the lower pressure in the well.

The movement of groundwater from pore space to pore space occurs due to the pressure difference between adjacent spaces. Water will flow from areas of higher pressure to areas of lower pressure until the pressures equalize. This movement of water is known as groundwater flow or hydraulic conductivity.

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Answer:

the tension of the rope is 34.95 N

Explanation:

Given;

length of the rope, L = 3 m

mass of the rope, m = 0.105 kg

frequency of the wave, f = 40 Hz

wavelength of the wave, λ = 0.79 m

Let the tension of the rope = T

The speed of the wave is given as;

\(v = f\lambda = \sqrt{\frac{T}{\mu} } \\\\where;\\\\\mu \ is \ mass \ per \ unit \ length\\\\\mu = \frac{0.105}{3} = 0.035 \ kg/m\\\\v = f\lambda = 40 \times 0.79 = 31.6 \ m/s\\\\v = \sqrt{\frac{T}{\mu} } \\\\v^2 = \frac{T}{\mu} \\\\T = v^2 \mu\\\\T = (31.6^2)(0.035)\\\\T = 34.95 \ N\)

Therefore, the tension of the rope is 34.95 N

Given

A massive light hangs over the table in Jeremy's dining room. The light is supported by four strong chains which make an angle of 72° with the horizontal.

The force in each chain is F=36.4 N.

To find

The mass of the light in kg

Explanation

Let the mass of the light be m

The weight of the light acts downwards.

To balance thisi force the force on the string vertically upward is considered

In equillibrium

Conclusion

The mass of the light is 13.84 kg

The efficiency of a single movable pulley is not 100 % because the applied load is half of the load to be lifted.

MA = Fo / Fi

MA = Mechanical advantage

Fo = Output force

Fi = Input force

In a single movable pulley,

Fi = 0.5 Fo

MA = Fo / 0.5 Fo

MA = 2

Efficiency = MA * 100

Efficiency = 2 * 100

Efficiency = 200 %

A movable pulley does no have a fixed axis of rotation. In a movable pulley the forces are multiplied at the other end. So the effort required to pull the load is easier than a fixed pulley.

Therefore, the efficiency of a single movable pulley is not 100%

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To find the magnitude of the induced electric field in the coil at different times, we can use Faraday's law of electromagnetic induction, which states that the induced electromotive force (emf) in a closed loop is equal to the negative rate of change of magnetic flux through the loop.

The magnetic flux through a circular coil with radius R is given by the equation:

Φ(t) = B(t) * A

where Φ(t) is the magnetic flux, B(t) is the magnetic field, and A is the area of the coil.

The area of a circular coil is given by the equation:

A = π * R^2

Now, let's calculate the magnetic flux at t = 0.001s and t = 0.01s.

At t = 0.001s:

B(0.001) = (5.00 x 10^-4) * sin[(44.0 x 10^2 rad/s) * 0.001]

= (5.00 x 10^-4) * sin[44.0 rad/s * 0.001]

= (5.00 x 10^-4) * sin[0.044 rad]

= (5.00 x 10^-4) * 0.044

= 2.20 x 10^-5 T

Φ(0.001) = B(0.001) * A

= 2.20 x 10^-5 * π * (0.54)^2

≈ 1.57 x 10^-5 T·m^2

At t = 0.01s:

B(0.01) = (5.00 x 10^-4) * sin[(44.0 x 10^2 rad/s) * 0.01]

= (5.00 x 10^-4) * sin[44.0 rad/s * 0.01]

= (5.00 x 10^-4) * sin[0.44 rad]

= (5.00 x 10^-4) * 0.429

= 2.15 x 10^-4 T

Φ(0.01) = B(0.01) * A

= 2.15 x 10^-4 * π * (0.54)^2

≈ 3.04 x 10^-4 T·m^2

Now, we can find the magnitude of the induced electric field using Faraday's law. The induced emf is equal to the negative rate of change of the magnetic flux with respect to time:

E = -dΦ/dt

For t = 0.001s:

E(0.001) = -(dΦ(0.001)/dt)

To calculate the derivative, we differentiate the magnetic flux equation with respect to time:

dΦ(t)/dt = (d/dt)(B(t) * A)

= (dB(t)/dt) * A

Differentiating the magnetic field B(t) with respect to time gives:

dB(t)/dt = (5.00 x 10^-4) * (44.0 x 10^2 rad/s) * cos[(44.0 x 10^2 rad/s) * t]

Substituting the values:

dB(0.001)/dt = (5.00 x 10^-4) * (44.0 x 10^2 rad/s) * cos[(44.0 x 10^2 rad/s) * 0.001]

= (5.00 x 10^-4) * (44.0 x 10^2 rad/s) * cos[44.0 rad/s * 0.001]

= (5.00 x 10^-4) * (44.0 x 10^2 rad/s) * cos[0.044 rad]

= (5.00 x 10^-4) * (44.0 x 10^2 rad/s) * 0.999

= 2.20 x 10^-1 T/s

Now, substitute the values into the equation for the induced electric field:

E(0.001) = -(dΦ(0.001)/dt)

= -[(2.20 x 10^-1) * (1.57 x 10^-5)]

≈ -3.45 x 10^-6 V/m

Similarly, for t = 0.01s:

E(0.01) = -(dΦ(0.01)/dt)

Differentiating the magnetic field B(t) with respect to time gives:

dB(t)/dt = (5.00 x 10^-4) * (44.0 x 10^2 rad/s) * cos[(44.0 x 10^2 rad/s) * t]

Substituting the values:

dB(0.01)/dt = (5.00 x 10^-4) * (44.0 x 10^2 rad/s) * cos[(44.0 x 10^2 rad/s) * 0.01]

= (5.00 x 10^-4) * (44.0 x 10^2 rad/s) * cos[44.0 rad/s * 0.01]

= (5.00 x 10^-4) * (44.0 x 10^2 rad/s) * cos[0.44 rad]

= (5.00 x 10^-4) * (44.0 x 10^2 rad/s) * 0.898

= 2.00 x 10^-1 T/s

Now, substitute the values into the equation for the induced electric field:

E(0.01) = -(dΦ(0.01)/dt)

= -[(2.00 x 10^-1) * (3.04 x 10^-4)]

≈ -6.08 x 10^-5 V/m

Therefore, the magnitude of the induced electric field in the coil at t = 0.001s is approximately 3.45 x 10^-6 V/m, and at t = 0.01s is approximately 6.08 x 10^-5 V/m.

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Answer:

kinetic or mechanical cant remember

Explanation:

Answer:

Hey!!

Kinetic Energy is your answer!

Explanation:

I hope this helped you!

Electron microscope achieves the greatest resolution and highest magnification.

Instead of using light to see the specimens, electron microscopes employ a stream of accelerated electrons. Compared to light microscopes, electrons are able to obtain a significantly greater resolution due to their shorter wavelength.

Magnifications of up to several million times can be achieved using electron microscopes, significantly above those of conventional light microscopes. Transmission electron microscopes (TEM) and scanning electron microscopes (SEM) are the two primary categories of electron microscopes.

SEMs give precise surface imaging, whereas TEMs are utilized to examine the inside structure of objects. The use of electron microscopes is essential in many scientific fields because they allow for the most in-depth examination of the microscopic details of cells, tissues, nanoparticles, and other tiny structures.

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The amplitude of the given sinusoidal function is 3, the period is 6, and the sine function modeled by the given sketch is \(y = 3 sin\left(\frac{\pi}{3} x + \frac{\pi}{2}\right)\).

Given the sketch of a sinusoidal function, we need to find out the amplitude, period, and the sine function modeled by this sketch.

Observe the given graph. Consider the highest point of the graph and the lowest point of the graph. The highest point and the lowest point are at the distance of 3 units on the y-axis.

Hence, the amplitude of the given sinusoidal function is 3.  \(A = 3\)To find the period, we need to observe the distance between two consecutive peaks or troughs.  

We can observe that there are 4 peaks in one complete cycle and the distance between any two peaks is 6 units.

So, the distance between two peaks is called the period of the graph and it is given by:Period = \frac{2\pi}{\omega}

We know that omega = \frac{2\pi}{Period}

Given thatPeriod = 6\omega = \frac{2\pi}{6}\omega = \frac{\pi}{3}

Now, the sine function is represented as \(y = A sin(\omega x + \phi)\)

Here, \(A\) is the amplitude which is 3.

\omega is the angular frequency which is\frac{\pi}{3}.

Let's find the phase angle \(\phi.

As we know that the highest value of the sine function is achieved at x = 0, we can use this information to find the value of \(\phi\).

So, we get,\(3 = A sin(\omega * 0 + \phi)\)\(3 = 3 sin \phi\)\(sin \phi = 1\)\(\phi = \frac{\pi}{2}\)

Now, we can write the sine function modeled by the given sketch:\(y = 3 sin\left(\frac{\pi}{3} x + \frac{\pi}{2}\right)\)

Hence, The sine function represented by the provided sketch is \(y = 3 sinleft(fracpi3 x + fracpi2right), and the given sinusoidal function has an amplitude of 3, a period of 6, and a period of 6.of \).n x.

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The parallel sides measure 35 cm in length. We are unable to draw any conclusions about the separation between the parallel sides based on the information provided.

Let AB and CD be the parallel sides of a non-isosceles trapezoid ABCD (See picture). The diagonals AC and BD should meet at P and Q, respectively. Let E represent the midpoint of the PQ segment, which is also the trapezoid's midline.

As stated in the problem statement, let's now assign the three midline segments the labels EF = 8 cm, FG = 3 cm, and GH = 8 cm.

We are aware that a trapezoid's diagonals separate one another proportionally. This is,

\(\frac{BQ}{QC} = \frac{AP}{PD}\)

Call this the common ratio, r.

We know that AP ≠ PD and BQ ≠ QC since the trapezoid is non-isosceles. Hence, r ≠ 1.

In addition, triangles ABQ and CDQ are similar, as are triangles ABP and CDP. This is due to the fact that they both share angles B and D, respectively, and that their corresponding sides are proportional as a result of the proportional division of the trapezoid by the diagonals.

Triangles are identical to one another, hence we can write:

\(\frac{PD}{QC} =\frac{AB}{CD}\) and \(\frac{AQ}{BQ}=\frac{AB}{CD}\)

When we multiply these equations, we obtain:

\((\frac{AP}{PD}) *(\frac{BQ}{QC} )=(\frac{AB}{CD} )^2\)

Substituting r for \((\frac{AP}{PD})\) and \((\frac{BQ}{QC} )\), we get:

\(r^2 = (\frac{AB}{CD} )^2\)

Taking the square root of both sides and simplifying, we get:

\(r = \frac{AB}{CD}\) or \(r = -\frac{AB}{CD}\)

Since r ≠ 1, we can eliminate the possibility of \(r = \frac{AB}{CD}\). Therefore, \(r = -\frac{AB}{CD}\).

This demonstrates that the trapezoid's diagonals cross each other externally.

Let's calculate the length of the parallel sides using the information provided.

From the similarity of triangles ABP and CDP, we have:

\(\frac{AP}{CD} = \frac{BP}{DP}\)

Substituting AP = 8 cm, CD = 8 cm + 3 cm + 8 cm = 19 cm, and BP = AB - AP, we get:

\(\frac{8}{19} = \frac{(AB - 8)}{DP}\)____________(1)

The resemblance between triangles ABQ and CDQ also yields the following:

\(\frac{BQ}{CD} = \frac{AQ}{CQ}\)

Substituting BQ = 8 cm, CD = 19 cm, and AQ = AB - BQ, we get:

\(\frac{8}{19} = \frac{(AB - 8)}{CQ}\)__________________(2)

Adding the equations (1) and (2), we get:

\(\frac{16}{19} = \frac{AB}{(DP + CQ)}\)

Substituting DP + CQ = PQ = 3 cm + 8 cm + 8 cm = 19 cm, we get:

AB = 16 cm

Therefore, the length of the parallel sides is AB + CD = 16 cm + 19 cm = 35 cm.

From the given information, we cannot infer anything about the distance that separates the parallel sides.

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The picture position travels away from the mirror as the object approaches it, and the image size increases (but the image is still inverted).

A force pushing or pulling an object will cause it to move in that direction. The acceleration increases as the force and object weight increase. Moreover, it can cause something to shift pace, direction, or tempo.

The primary forces that produce motion are gravity and friction. The motion of an object will change if one, both, or both forces are changed. The force that draws two objects together is called gravity. The amount of "stuff" in an object, or its mass, is the same for everything.

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Answer:

\(a=18.51\ m/s^2\)

Explanation:

Given that,

Initial speed, u = 0 km/h

Final speed, v = 100 km/h = 27.77 m/s

Time, t = 1.5 s

We need to find the average acceleration of this motorcycle. It is equal to the rate of change of velocity and it is given by :

\(a=\dfrac{v-u}{t}\\\\a=\dfrac{v}{t}\\\\a=\dfrac{27.77\ m}{1.5\ s}\\\\a=18.51\ m/s^2\)

So, the acceleration of the motorcycle is \(18.51\ m/s^2\).

Answer:

Le pH de l’ammoniac est de 11.6

Explanation:

a. 39/19K is stable, and 40/19K is radioactive.

b. 209Bi is stable, and 208Bi is radioactive.

c. Both nickel-58 and nickel-65 are stable; neither is radioactive.

To determine which nuclide in each pair is radioactive and which one is stable, we need to consider the properties of the nuclides, specifically their atomic numbers (Z) and mass numbers (A).

a. 39/19K and 40/19K:

Nuclide 39/19K has an atomic number (Z) of 19 and a mass number (A) of 39.

Nuclide 40/19K has an atomic number (Z) of 19 and a mass number (A) of 40.

Both nuclides have the same atomic number, indicating they are isotopes of potassium. However, only one of these isotopes is radioactive. In this case, 40/19K is radioactive, and 39/19K is stable.

b. 209Bi and 208Bi:

Nuclide 209Bi has an atomic number (Z) of 83 and a mass number (A) of 209.

Nuclide 208Bi has an atomic number (Z) of 83 and a mass number (A) of 208.

Both nuclides have the same atomic number, indicating they are isotopes of bismuth. In this case, 209Bi is the stable nuclide, and 208Bi is radioactive.

c. Nickel-58 and nickel-65:

Nickel-58 has an atomic number (Z) of 28 and a mass number (A) of 58.

Nickel-65 has an atomic number (Z) of 28 and a mass number (A) of 65.

Both nuclides have the same atomic number, indicating they are isotopes of nickel. In this case, both nickel-58 and nickel-65 are stable, as neither of them is radioactive.

Hence, a. 39/19K is stable, and 40/19K is radioactive.

b. 209Bi is stable, and 208Bi is radioactive.

c. Both nickel-58 and nickel-65 are stable; neither is radioactive.

The given question is incomplete and the complete question is '' One of the nuclides in each of the following pairs is radioactive. Predict which is radioactive and which is stable. a. 39/19K and 40/19Kb. 209Bi and 208Bic. nickel-58 and nickel-65 ''.

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In this experiment, rubbing a plastic bag against wool allowed electrons to move back and forth between the two, creating a negative charge on the bag. When the negatively charged bag was brought close to the neutral PAN, the bag's negative charge attracted the PAN's electrons, separating the two charges and leaving the PAN with a positive charge. On touching the pan the surplus positive charge was neutralized, creating a spark.

When the pan was brought up to the nose a slight jolt was felt and a crackling sound was heard. This resulted in the excess charge in the pan being carried through the air to the nearest conductor, the person holding the pan.

The spark and shock were easy to see in a dark environment as there was no ambient light to obstruct the view. The blow was more pronounced and distinct, and the spark appeared as a bluish glow.

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An incredibly dense star so massive that light cannot escape from its surface is called a Black Hole.

Black Hole, is an incredibly dense star so massive that light cannot escape from its surface.

Black hole is the region in space where the gravity is maximum indicating no particle can escape from it.

It is formed from the start debris that died in the explosion.

It creates deep stinks of gravity that even light cannot escape from it.

It was discovered by John Michell. It is believed that the universe may have originated from the black hole only.

They roam among the stars of the Milkyway galaxy

Black holes live for infinite number of years which is like the age of the universe.

Earth would never fall into the black hole but if it does then even earth cannot escape from falling.

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