Answer: A. Divergent boundary
Explanation:
I really think its D if not i'm really sorry
The graph below shows the force required to stretch a spring various distances. Review the graph below.
What is the best approximate value for the elastic potential energy (EPE) of the spring elongated by 3.0 meters?
Explanation:
Elastic string constant (k)
= Slope of the graph F/x
= 15.0N/10.0m = 1.50N/m
Hence,
EPE = 0.5kx² = 0.5(1.50N/m)(3.0m)² = 6.75J.
Answer:
6.8
Explanation:
A wave has an amplitude of 0.0800 m
and is moving 7.33 m/s. One oscillator
in the wave takes 0.230 s to go from
one crest to the next crest. Find the
wavelength of the wave.
(Unit = m)
If a wave has an amplitude of 0.0800 m and is moving 7.33 m/s. The
wavelength of the wave is 1.69m.
What is the wavelength?The wavelength of a wave can be determined using the equation:
Wavelength = velocity / frequency
To determine the frequency we need to calculate the reciprocal of the time it takes for one complete oscillation.
frequency = 1 / time
frequency = 1 / 0.230
frequency ≈ 4.35 Hz
Substitute the values into the wavelength equation:
wavelength = velocity / frequency
wavelength = 7.33 / 4.35
wavelength ≈ 1.69m
Therefore the wavelength of the wave is approximately 1.69 meters.
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Calculate the change in momentum of a 0.5kg ball that strikes the floor at 15 m/s and bounces back up at 12 m/s
Answer:
The change in momentum is: \(13.5\,\frac{kg\,m}{s}\)
Explanation:
Let's define that vectors pointing up are positive, and vectors pointing down negative.
Then we express the initial momentum of the ball as the product of its mass times the velocity, and include the negative sign since this momentum is pointing down (velocity vector is pointing down):
\(P_i=-0.5\,(15) \frac{kg\,m}{s} =-7.5\, \frac{kg\,m}{s}\)
the final momentum is positive (pointing up) and given by the product:
\(P_f=0.5\,(12) \frac{kg\,m}{s} =6\, \frac{kg\,m}{s}\)
Therefore, since the change in momentum is defined as the difference between the final momentum minus the initial one, we get:
\(P_f-P_i=6-(-7.5)\,\frac{kg\,m}{s} =13.5\,\frac{kg\,m}{s}\)
EX
2-1
6. Traveling 221 miles from Boston Back Bay Sta
New York Penn Station takes 3 hours and 40 minutes on
a train. Calculate the average speed of the train in units
of m/s.
Real Bay Station to
Given the distance traveled and time elapsed, the average speed of the train is approximately 26.944m/s.
What is the average speed of the train?Speed is simply referred to as distance traveled per unit time.
Mathematically, Speed = Distance ÷ time.
Given the data in the question;
Distance traveled = 221milesElapsed time = 3 hours and 40 minutesFirst we convert miles to meters and Hours minutes to seconds.
221 miles = ( 221 × 1609.344 )m = 355665.024 meters
3 hours and 40 minutes = ( 3×60×60)s + ( 40×60)s
= 10800s + 2400s
= 13200s
Now, determine the average speed.
Speed = Distance ÷ time
Speed = 355665.024m / 13200s
Speed = 26.944m/s
Given the distance traveled and time elapsed, the average speed of the train is approximately 26.944m/s.
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In the diagram above, where is light energy converted to chemical energy?
A. Sun
B. Grass
C. Grasshopper
B. Hawk
Answer:
B. Grass
Explanation:
In the diagram above, Grass is where, light energy converted to chemical energy. Hence option B is correct.
What is Visible light ?Visible light spectrum is nothing but the range of wavelength of radiation from 4000 angstrom to 7000 angstrom(Violet to Red). light is a energy packet. Every Photon having different wavelength travels with same velocity c (velocity of light). When we focus numbers of colors from visible spectrum to a point, that point appears as a white light. hence white light is composed of numbers of Colors in it.
Light itself is a energy when it falls on the grass, grass grows by taking energy from the light and convert that energy into biomass that is a chemical energy.
Hence option B is correct.
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the student measure the massof he wooden block and found it to be =0.20kg.name the apparatus that can used to measure the mass ofthe wooden block
The apparatus that can used to measure the mass of the wooden block by the student is called beam balance.
A beam balance, often referred to as a double-pan balance, is a straightforward tool for determining an object's weight. Two pans or trays are hung from either end of a horizontal beam that is suspended from a pivot point in the middle.
The thing to be weighed is put on one tray, and then the second tray is filled with standard weights until it balances, showing the weight of the object. From little ones used in laboratories to larger ones used in enterprises, beam balances can be found in a variety of shapes and sizes. Because they are precise and operate without electricity or batteries, they are widely used.
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It is almost as if each outer planet is a solar system in its own right.
True or False
A 60 kg driver gets into an empty taptap to start the day's work. The springs compress 2.4×10−2 m . What is the effective spring constant of the spring system in the taptap?
A man of weight 60N climbed stairs of height 15m high in 15s. Find the power
of the man,
Do this for alot of points
1. A complete fitness and exercise program should incorporate three basic components: Endurance (Aerobic), Flexibility, and Strength. Each of these components has specific guidelines, which govern their effectiveness
Bob creates an instrument that is able to play C4 (261.63 Hz). He does some analysis with the sound equipment and it shows that when he plays it, he also gets the frequencies 523.26 Hz, 784.89 Hz, and 1308.15 Hz. What could be true about the instrument? It’s a stringed instrument, it’s a closed pipe, or it’s an open pipe?
Answer:
It could be a stringed instrument or an open pipe.
Explanation:
Let v be the speed of sound, y be wavelength and f be frequency.
v = yf
f= v/y; v is constant.
In a stringed instrument, the fundamental frequency note is heard when the length of the string, l = y/2; y= 2l
f′= v/2l
The second harmonic is heard when l= y
f"= v/y
...
f'''= 3v/2l
We can infer that f"= 2f'
f'''= 3f'
This is similar to the values in the question as;
523.26 =2(261.63) and so on.
Same thing happens with open pipes.
Abnormal levels of __________ may lead to Alzheimer’s disease.
A.
endorphins
B.
serotonin
C.
GABA (gamma-aminobutyric acid)
D.
acetylcholine
Answer:
D
Explanation:
abnormal levels of ACETYCHOLINE may lead to Alzheimers disease
If a quarterback gets hit by a defensive lineman with a mass of 100 kg and accelerating at a rate of 1m/s2 at what force is the quarterback getting hit?
The quarterback is getting hit with a force of 100 Newtons.
How to calculate the force with which the quarterback is getting hit
We can use Newton's second law of motion:
Force = Mass * Acceleration
Given that the mass of the defensive lineman is 100 kg and the acceleration is 1 m/s², we can substitute these values into the equation:
Force = 100 kg * 1 m/s²
Force = 100 N
Therefore, the quarterback is getting hit with a force of 100 Newtons.
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Describe why living organisms use the process of Mitosis. What type of reproduction is mitosis and why is it classified as this form of reproduction? Why is mitosis an important process for living organisms?
Be sure to include quotes from article to support your answers.
Mitosis is an essential mechanism for life, according to a National Human Genome Research Institute publication. A single cell divides into two genetically identical daughter cells during mitosis.
Multicellular organisms require this mechanism for growth, repair, and reproduction.
MitosisBecause it doesn't use gametes or fertilization to create genetically identical daughter cells, mitosis is a type of asexual reproduction.
"Mitosis is a type of asexual reproduction that is essential for the growth and development of multicellular organisms," the National Center for Biotechnology Information explains.
Because it is essential for tissue growth and repair, mitosis is a vital process for all living things. The growth and repair of tissues as well as some organisms' asexual reproduction depend on mitosis, according to the American Society of Hematology.
Mitosis enables the expansion of tissues throughout development as well as the generation of new cells that can replace harmed or dying cells in the body.
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When the palmaris longus muscle in the forearm is flexed, the wrist moves back and forth. If the muscle generates a force of 53.5 N and it is acting with an effective lever arm of 2.25 cm , what is the torque that the muscle produces on the wrist
Answer:
1.20Nm
Explanation:
Given data
Force= 53.5N
Perpendicular distance= 2.25cm= 2.25/100= 0.0225m
The expression for the torque is given as
Torque= Force* Perpendicular distance
Torque= 53.5*0.0225
Torque= 1.20Nm
Hence the toque produced is 1.20Nm
Two harmonic sound waves reach an overseveer simulatenouslt. the obsever hears the sound intensity rise and fall with a time of 0.2 between the maximmu intensity and the successing minimum intensity. What is the difference in frequency of the two sound waves?
Answer:
\(dF=2.5Hz\)
Explanation:
From the question we are told that:
Time \(T=0.2sec\)
Generally the Period is given as
\(T= 2 * 0.2 = 0.4\)
Therefore difference in frequency dF
\(dF=\frac{1}{T}\)
\(dF=\frac{1}{0.4}\)
\(dF=2.5Hz\)
help plz, will give brainliest!!!!
Answer:
It looks like a total of 9 meters
Explanation:
the dot on the graph for 1910 sits JUST below the mark for 10 meters
5. You are driving at a constant speed of 35.0 m/s
when you pass a traffic officer on a motorcycle
hidden behind a billboard. One second after your
car passes the billboard, the traffic officer sets out
from the billboard to catch you, accelerating at a
constant rate of 3.0 m/s². How long does it take the
traffic officer to overtake your car?
The traffic cop needs 23.3 seconds to pass the automobile.
What is the acceleration of a car moving in a straight line at a constant speed?When your velocity (not speed) changes, you are accelerating. A automobile moving at a steady 100 km/h in a straight line has no acceleration. Average acceleration is equal to (change in velocity) / (duration). The car's acceleration is zero because its change in velocity is also zero.
\(d1 = v1*t1 = 35.0 m/s * 1 s = 35.0 m\)
\(d = d1 = 35.0 m\)
\(d2 = v2*t + (1/2)at^2\)
\(d2 = (1/2)at^2\)
\(v2*t + (1/2)at^2 = (1/2)at^2\)
\(v2*t = (1/2)at^2\)
Solving for t, we get:
\(t = (2v2/a) = (235.0 m/s)/3.0 m/s^2 = 23.3 s\) (rounded to 2 decimal places)
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HELP PLEASE DUE IN 3 MINUTES
Answer:
1. slides and scrapes
2. pulls away
3. crashes into each other
Explanation:
Answer:
transform
convergent
divergent
Explanation:
Converge means to come together
Diverge means to move away
Help!!!!!!!!! Attached question
QUICK WILL GIVE BRAINLIEST
The electric field at the center of a ring of charge is zero. At very large distances from the center of the ring along the ring's axis the electric field goes to zero. Find the distance from the center of the ring along the axis (perpendicular to the plane containing the ring) at which the magnitude of the electric field is a maximum. The radius of the ring is 7.55 cm and the total charge on the ring is 7.06E-6 C.
Answer:b\(4.29\times 10^6\ N/C\)
Explanation:
Given
The radius of the ring is \(a=7.55\ cm\)
The charge on the ring is \(Q=7.06\times 10^{-6}\ C\)
Electric field along the axis at a distance \(x\) is given by
\(E=\dfrac{kxQ}{(x^2+a^2)^{\frac{3}{2}}}\)
To get the maximum value, differentiate \(E\) w.r.t \(x\) we get
\(E_{max}=\dfrac{2kQ}{3\sqrt{3}a^2}\quad [\text{at}\ x=\dfrac{a}{\sqrt{2}}]\\\\E_{max}=\dfrac{2\times 9\times 10^9\times 7.06\times 10^{-6}}{3\sqrt{3}(7.55\times 10^{-2})^2}\\\\E_{max}=\dfrac{24.456\times 10^3}{57\times 10^{-4}}=4.29\times 10^6\ N/C\)
What must be the current I
in the bar for the bar to be in rotational equilibrium when it is at an angle 30.0 ∘
above the horizontal? Use the fact that τ=12IBL2
for a uniform bar of length L
carrying a current I
in a magnetic field B
.
The current required for a uniform bar to be in rotational equilibrium when it is at an angle of 30.0° above the horizontal and carrying a current I in a magnetic field B is zero, as the torque acting on the bar is zero at this angle.
To find the current I in the bar for it to be in rotational equilibrium when it is at an angle of 30.0° above the horizontal, we need to use the torque equation for a uniform bar carrying a current I in a magnetic field B:
τ = 1/2 IBL² sinθ
where τ is the torque, I is the current, B is the magnetic field, L is the length of the bar, and θ is the angle of the bar relative to the magnetic field.
Since we want the bar to be in rotational equilibrium, the torque must be zero, so we can set the torque equation equal to zero:
0 = 1/2 IBL² sin30°
Solving for I, we get:
I = 0 / (1/2 B L² sin30°)
I = 0
Therefore, the current required for the bar to be in rotational equilibrium when it is at an angle of 30.0° above the horizontal is zero. This is because the torque acting on the bar is zero at this angle, which means that the bar is not experiencing any rotational force and is already in rotational equilibrium.
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I need help with part a and B on number three
Answer:
a. 2.64 * 10^8 radians
b. 4.20 * 10^ 7 revolutions
Explanation:
First, let us convert miles to inches.
\(60,000\text{miles}=3.8\cdot10^9in\)
Now, how many radians of the tire are there in 60,000 miles?
The answer is N in the following equation.
\(2\pi(\frac{28.8}{2})N=3.8\cdot10^p\)Now, solving for 2Pi*N gives
\(2\pi N=\frac{2.8\cdot10^9}{28.8/2}\)Which simplifies to give
\(\boxed{2\pi N=2.64\cdot10^8}\)Part B.
Note that in the above equation, N is the number of Revolutions. Solving for N gives
\(N=\frac{2.64\cdot10^8}{2\pi}\)\(\boxed{N=4.20\cdot10^7}\)which is our answer!
Weight _____. A) is related to mass, but not the same. B) changes as mass changes C) depends upon gravitational pull D) all of the above
Answer:
D) all of the above
Explanation:
All of the given choices are correct definition of what weight of a substance implies.
Weight is the vertical force on a body due to the gravitational attraction or pull.
Weight = mass x acceleration due to gravity
Mass of a body is directly proportional to its weight and so also is the gravity.
Mass is the amount of matter within a substance.
Weight is the force of gravity exerted by a body on another or a surface.
The reason why the weight of a body changes from place to place is mainly due to the gravitational pull
an object is dropped from h height. graph v vs h?
The total distance traveled by the object is 3h.
Total distance traveled by the object
The total distance traveled by the object can be determined by applying the principle of conservation of energy as follows;
Since the object loses half its energy each time it hits the ground.
Hence it will rise half of the previous height each time, as potential energy at height h is given by;
P.E = mgh
Thus, the object will rise h/2 after the first hit, then h/4 and so on.
Hence the total distance traveled by the object is calculated as follows;
s = h + (h/2 + h/2 + h/4 + h/4 + ---)
s = h + (h + h/2 + ---)
s = h + h(1 + 1/2 + 1/4 + ---)
s = h + h(1 + (1/1 - 1/2) )
s = 3h
Thus, the total distance traveled by the object is 3h.
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The complete question is below:
An object is dropped from h height. graph v vs h? Every time it hits the ground it looses 50% of its kinetic energy. The total distance covered as t→∞ is :
why do astronauts weigh less on the moon than on earth
Answer:
Explanation: The moon of the Earth is much lighter in mass than the planet itself. In addition to being smaller than Earth, the Moon is also only approximately 60% as dense. A human weighs less on the Moon because there is less gravitational attraction there than there is on Earth.
Moon has lesser mass as conpared to earth, therefore gravitational force exerted by moon on any object is lesser than that of gravitational force exerted by earth on the same object, hence we can say that astronauts weight less on moon, i.e approximately 1/6 th of their weight on earth.
Four small spheres, each charged to +15 nC, form a square 2.0 cm on each
side. From far away, a proton is shot toward the square along a line perpendicular to the square and passing through its center. What minimum initial speed does the proton need to pass through the square of charges?
The minimum initial speed of the proton needed to pass through the square of charges is 5.09 x 10^6 m/s.
Describe Charge?Charge is a fundamental physical property of matter that describes the degree to which it interacts with electromagnetic fields. It is an intrinsic property of subatomic particles, such as protons and electrons, that gives rise to electric and magnetic forces.
The basic unit of charge is the Coulomb (C), named after the French physicist Charles-Augustin de Coulomb, who first quantified the electric force between charged objects. A single proton or electron has a charge of approximately 1.6 x 10^-19 Coulombs.
Electric charge is conserved, which means that the total amount of charge in a closed system remains constant over time. Charges can be positive, negative, or neutral, and like charges repel each other, while opposite charges attract each other.
Charge is an important property in many areas of physics, including electromagnetism, quantum mechanics, and particle physics. It is also a crucial concept in many practical applications, such as electronics, power generation, and communication systems.
We can solve this problem using the principle of conservation of energy. The initial kinetic energy of the proton must be equal to the work done by the electrostatic force of the charged spheres on the proton as it passes through the square.
The electrostatic force between two charges q1 and q2 separated by a distance r is given by Coulomb's law:
\(F = k * q1 * q2 / r^2\)
where k is the Coulomb constant, which has a value of
\(8.99 x 10^9 N m^2 / C^2.\)
Since the four spheres are identical and equally spaced, the electrostatic force on the proton due to each sphere will have the same magnitude and direction. We can calculate the force on the proton due to one sphere and multiply by 4 to get the total force:
\(F = 4 * k * q * q_p / r^2\)
where q is the charge on each sphere (+15 nC), q_p is the charge on the proton (-1.6 x 10^-19 C), and r is the distance from the center of the square to the proton's initial position (which we will assume is the same as the distance from the center of the square to the closest sphere, which is sqrt\((2)/2 * 0.02 m = 0.0141 m).\)
The work done by the electrostatic force as the proton passes through the square is:
W = F * d
where d is the length of the square (2 cm = 0.02 m).
Equating the initial kinetic energy of the proton to the work done by the electrostatic force, we get:
\((1/2) * m * v_i^2 = 4 * k * q * q_p * d / r^2\)
where m is the mass of the proton (1.67 x 10^-27 kg) and v_i is the initial speed of the proton.
Solving for v_i, we get:
\(v_i = sqrt(8 * k * q * q_p * d / (m * r^2))\)
Plugging in the values, we get:
\(v_i = sqrt(8 * 8.99 x 10^9 N m^2 / C^2 * 15 x 10^-9 C * 1.6 x 10^-19 C * 0.02 m / (1.67 x 10^-27 kg * (0.0141 m)^2))v_i = 5.09 x 10^6 m/s\)
Therefore, the minimum initial speed of the proton needed to pass through the square of charges is \(5.09 x 10^6 m/s.\)
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Phobos, one of the moons of Mars, orbits at a distance of 9378 km from the center of the red planet.
Part A What is the orbital period of Phobos?
The orbital period of Phobos is 7.66 hours.
What is orbital period?The orbital period also known as the revolution period is the amount of time it takes an astronomical object to complete one orbit around another. It usually refers to planets or asteroids orbiting the Sun, moons orbiting planets, exoplanets orbiting other stars, or binary stars in astronomy.
It will be calculated thus:
T^2 = (4π)^2( d^3) / ((G)(Mm))
where d is the distance in meters, 9.378 x 10^6 meters
(4π)^2 = 39.5
G = 6.67 x 10^-11 m^3 kg^-2 s^-2
Mm = the mass of Mars in kg which is 6.42 x 10^23 kg.
T^2 = 7.61 x 10^8 sec^2
Find the square root.
T = 2.76 x 10^4 sec
T = 7.66 hours
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attention is always blank
Answer
lol
Explanation:
A particle with the potential energy diagram shown is located at point A and is moving to the right with a kinetic energy of 10.0 Joules. When the particle reaches point F, the speed of the particle has
A particle with the potential energy diagram shown is located at point A and is moving to the right with a kinetic energy of 10.0 Joules. When the particle reaches point F, the speed of the particle has decrease
How to explain the diagramAs the sum of potential and kinetic energy remains constant
Kinetic energy decreases when potential energy increases and vice versa.
When kinetic energy decreases speed will also decrease.
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