The marching band walks 1/15 mi in 1.5 min. At this rate, how many minutes will it take to complete 1 mile ?

The value of x in sequence of number is 10.

Here, first term of sequence is x and each term there after is twice the previous term. Also Fifth term is 160.

What is geometric series?

Geometric series is an infinite series of the form:

\(a+ar+a r^{2} +ar^{3} +..........\)

where r is known as common ratio.

Now, first term is x and each term there after is twice the previous term.

So the series will be;

x , 2x , 4x , 8x, ..........

Clearly this series is geometric series with common ratio 2.

And the nth term of geometric series is \(ar^{n-1}\)

⇒ fifth term is 160

\(ar^{5-1} = 160\\ar^{4} = 160\\a 2^{4} =160\\a=\frac{160}{16} \\a=10\)

Here, first term is x.

The value of x in sequence of number is 10.

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Answer:

Step-by-step explanation:

Step one:

given data

price quotes from Company A

charges= $7

additional charges per hour= $3

let the number of hours be x

and the total be y

the linear function for the total is

y=3x+7

price quotes from Company B

charges= $10

additional charges per hour= $2

let the number of hours be x

and the total be y

the linear function for the total is

y=2x+10

if the total quote is the same , then

3x+7=2x+10

solve for x, collect like terms

3x-2x=10-7

x=3 hours

The natural breaks, quantile, and equal interval classification schemes are methods used to categorize data for the purpose of creating thematic maps. Each scheme has its own approach and considerations: Natural Breaks, Quantile, Equal Interval.

Natural Breaks (Jenks): This classification scheme aims to identify natural groupings or breakpoints in the data. It seeks to minimize the variance within each group while maximizing the variance between groups. Natural breaks are determined by analyzing the distribution of the data and identifying points where significant gaps or changes occur. This method is useful for data that exhibits distinct clusters or patterns.

Quantile (Equal Count): The quantile classification scheme divides the data into equal-sized classes based on the number of data values. It ensures that an equal number of observations fall into each class. This approach is beneficial when the goal is to have an equal representation of data points in each category. Quantiles are useful for data that is evenly distributed and when maintaining an equal sample size in each class is important.

Equal Interval: In the equal interval classification scheme, the range of the data is divided into equal intervals, and data values are assigned to the corresponding interval. This method is straightforward and creates classes of equal width. It is useful when the range of values is important to represent accurately. However, it may not account for data distribution or variations in density.

In summary, the natural breaks scheme focuses on identifying natural groupings, the quantile scheme ensures an equal representation of data in each class, and the equal interval scheme creates classes of equal width based on the range of values. The choice of classification scheme depends on the nature of the data and the desired representation in the thematic map.

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Answer:

50+12x≥158

Step-by-step explanation:

starting with $50, adding $12 for every car washed (x), must be at least, but can be greater than, $158.

The required inequality for Silvio to earn more than $158 in one day is, $50 + 12x ≥ 158.

Given that,
Silvio works at a car wash. He earns $50 per day and $12 per car washed. Silvio wants to earn at least $158 in 1 day.
To determine the inequality represents the number of cars (C) Silvio must wash to reach his goal.

Inequality can be defined as the relation of the equation containing the symbol of ( ≤, ≥, <, >) instead of the equal sign in an equation.

Here,
Let the number of cars washed by Silvio be x,
According to the question,
Silvio works at a car wash. He earns $50 per day and $12 per car washed.
Total earning of the day = $50 + 12x
Silvio wants to earn at least $158 in 1 day. So, his total earnings of the day must be greater equal to $158.
$50 + 12x ≥ 158.

Thus, the required inequality for Silvio to earn more than $158 in one day is, $50 + 12x ≥ 158.

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Using the Poisson distribution, it is found that the probabilities are given by:

a) 0.1009 = 10.09%.

b) 0.8262 = 82.62%.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

\(P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}\)

The parameters are:

Item a:

The mean is of 7 customers for 60 minutes, hence, for 90 minutes = 1.5 x 60 minutes, the mean is given by:

\(\mu = 1.5 \times 7 = 10.5\)

The probability of exactly 8 customers is of P(X = 8), hence:

\(P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}\)

\(P(X = 8) = \frac{e^{-10.5}10.5^{8}}{(8)!} = 0.1009\)

Item b:

Probability of at least one patient in 15 minutes, hence:

\(P(X \geq 1) = 1 - P(X = 0)\)

For 15 minutes, the mean is given by:

\(\mu = 0.25 \times 7 = 1.75\)

Then:

\(P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}\)

\(P(X = 8) = \frac{e^{-1.75}1.75^{0}}{(0)!} = 0.1738\)

\(P(X \geq 1) = 1 - P(X = 0) = 1 - 0.1738 = 0.8262\)

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Answer:

70°

Step-by-step explanation:

This triangle is an isosceles triangle because two sides are marked that they are the same. So the "base angles" are also the same. Angle D and Angle F are equal to each other (the angles are congruent and the measures are equal).

All the angles in a triangle add up to 180° We know the one marked angle is 40°. Let Angle D be x and so Angle F is also x.

x + x + 40 = 180

combine like terms

2x + 40 = 180

subtract 40

2x = 140

divide by 2

x = 70

Angle D is 70°

The following are the area of the sectors:

6a). π square inches

6b). 24π square centimeters

7a). 9 square centimeters

7b). 16.7 square inches

The area of a sector is calculated by multiplying the fraction of the angle for the sector divided by 360° and πr², where r is the radius.

For question 6:

a). (40/360) × π × 3 in × 3 in = π in²

b). (135/360) × π × 8 cm × 8 cm = 24π cm²

For question 7:

a). (90/360) × π × 6 cm × 6 cm = 9 cm²

b). (60/360) × π × 10 in × 10 in = 16.7π in²

Therefore, the following are the area of the sectors:

6a). π square inches

6b). 24π square centimeters

7a). 9 square centimeters

7b). 16.7 square inches

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Answer:

I think its false

Step-by-step explanation:

I've tried every strategy there is no way there could be a function

Answer:

I think its false

Step-by-step explanation:

cuz it's not a function

Answer:

The answer is A

Step-by-step explanation: I just took the quiz.

The work is done in compressing the spring from a length of 15 inches to a length of 13 inches are the 0.897ftlb.

Work Done:According to the paintings-power theorem, the internet paintings performed on an item equals the alternate withinside the power of the item . If the simplest alternate withinside the power located is withinside the capability power (say U) of the item, then the internet paintings performed W=△U.

Answer and Explanation:When a spring is compressed x in with the aid of using a pressure F,

F=kx, where k is the spring constant.

Since it's miles for the reason that the spring is compressed to 8in from 21in, that is, a compression of (21−eight)=13in, we obtain

F=kx⇒k=Fx=10lb1312ft=12013lbft−1.

Using the theorem, the internet paintings performed on an item equals the alternate withinside the power of the item. In this situation the simplest alternate in power is withinside the capability power of the spring while it's miles compressed with the aid of using x gadgets of duration, which is 12kx2. (k is the spring constant.)

The capability power of the spring while it's miles compressed to 15cm=0.5k(21−1512)2

The capability power of the spring while it's miles compressed to 13cm=0.5k(21−1312)2

Work Done equals the alternate withinside the capability power while it's miles compressed from 15in to 13in

=0.5k[(21−1312)2−(21−1512)2]=0.512013[(21−1312)2−(21−1512)2]≈ 0.897ftlb

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Answer: 5 outfits

Step-by-step explanation: 17.63x2=35.26

                                             437.63+35.26+18.11=491

                                              680-491=189

                                              189 divided by 35.19= 5 (rounded)

Answer: -2.75*x - 4.7

Step-by-step explanation:

In the equation we have only one variable, this means that the minimum possible number of terms will be two, one term with x, and one term without x.

We can start with the equation:

(-0.25x - 3) - (2.5x + 1.7)

Now, let's rewrite this as:

-0.25x - 3 - 2.5x - 1.7

(-0.25*x - 2.5*x) + (-3 - 1.7)

Solving the parentheses we get:

-2.75*x - 4.7

That is the equivalent expression that has the fewest possible terms

The given statement "the work done by f to move a particle along an oriented curve is the line integral of f along this curve" is true.

The work done by a force vector field F to move a particle along an oriented curve is given by the line integral of F along that curve. The line integral represents the sum of the dot products between the force vector field F and the tangent vectors to infinitesimal line segments along the curve.

Mathematically, the work done W is expressed as:

W = ∮ F · dr,

where ∮ represents the line integral, F is the force vector field, dr is the differential displacement vector along the curve, and the dot product (·) indicates vector multiplication.

The line integral takes into account both the magnitude and direction of the force field along the curve, allowing us to calculate the total work done by the force as the particle moves along the path.

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The following qquestion may be like this:

recall that the work done by f to move a particle along an oriented curve is the line integral of f along this curve. True or False.

The chief of security for the Mall of the Dakotas directed a study of theft. He selected a sample of 200 boxes that had been tampered with and ascertained that for 80 of the boxes, the missing pants, shoes, and so on were attributed to shoplifting. For 45 boxes, employees had stolen the goods, and for the remaining 75 boxes, he blamed poor inventory control.

In his report to the mall management, can he say that shoplifting is twice as likely to be the cause of the loss as compared with either employee theft or poor inventory control and that employee theft and poor inventory control are equally likely? Use the 0.10 significance level. H0: The proportions are as stated. H1: The proportions are not as stated. The decision rule using a 0.10 significance level is: Reject H0 if the computed chi-square value is greater than 4.605. Compute the value of chi-square as follows: Observed Frequencies: Shoplifting: 80 Employee theft: 45 Poor inventory control: 75 Total: 200 Expected Frequencies: Shoplifting: (80+45+75) x (80/200) = 80. Employee theft: (80+45+75) x (45/200) = 36. Poor inventory control: (80+45+75) x (75/200) = 84. Total: 200The formula for chi-square is: χ2=∑((Oi−Ei)2/Ei). Using the observed and expected frequencies from above, we get: χ2 = [(80 - 80)²/80] + [(45 - 36)²/36] + [(75 - 84)²/84] = 2.4. The value of chi-square is 2.4, which is less than 4.605. Therefore, we fail to reject H0. Hence, the chief of security for the Mall of the Dakotas cannot say that shoplifting is twice as likely to be the cause of the loss as compared with either employee theft or poor inventory control and that employee theft and poor inventory control are equally likely at a 0.10 significance level.

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Answer: 360

Step-by-step explanation:

done

Answer:

maximum- (-3,5)

Step-by-step explanation:

Using Kepler's Third Law, we can find the distance of the exo-planet from its star. The formula is P^2 = a^3, where P is the orbital period in years and a is the average distance from the planet to the star in astronomical units (AU).

the average distance of Le Grosse Homme from its star is approximately 2 AU, which is answer choice b).

To determine the distance of the exo-planet Le Grosse Homme to the star, we will use Kepler's Third Law, which states that the square of the orbital period (P) of a planet is proportional to the cube of the semi-major axis (a) of its orbit. The formula is given as:

P² = a³

In this case, the orbital period P is 2.8284 years. We can now solve for the semi-major axis (a), which represents the distance from the planet to the star in astronomical units (AU).

Step 1: Square the orbital period
(2.8284)² = 7.99968336

Step 2: Find the cube root of the squared orbital period to get the distance (a)
a = ∛(7.99968336) ≈ 2.0 AU

So, the distance of the exo-planet Le Grosse Homme to the star is approximately 2.0 AU. The correct answer is option (b) ~2.0 AU.

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Answer:

11)   -14d¹¹

12)   4n⁴

Step-by-step explanation:

11)   (-2d²)(7d⁹) = (-14d²⁺⁹) = -14d¹¹

12)  n¹⁰ / n⁶ = n¹⁰⁻⁶ = n⁴

When multiplying the same variable, add the exponents.

When dividing the same variable, subtract the exponents.

Answer:

value of 4 tan 45° +(2 sin 45°) (6 cos 45°)​ is 10.

Step-by-step explanation:

To solve this question we need to know value of

tan 45° = 1

sin 45° = \(1/\sqrt{2}\)

cos 45° = \(1/\sqrt{2}\)

we will be using above value sin the given expression as shown

\(4 tan 45 +(2 sin 45) (6 cos 45)​ = 4*1 + (2*1/\sqrt{2} )(6*1/\sqrt{2})\\ = 4 + (2/\sqrt{2}) (6/\sqrt{2})\\= 4 + (2*6)/(\sqrt{2}*\sqrt{2})\\= 4 + (12/2)\\= 4 + 6 = 10\)

Thus, value of 4 tan 45° +(2 sin 45°) (6 cos 45°)​ is 10.

Hence, 15 people out of 3 people can be chosen in 35 ways.

It is given that:

The total number of people in a race, n = 15

The number of finalists, r = 3.

Hence, the number of ways in which 3 people out of the 15 people can be finishers are:

\(^{15}C_{3} }\) = \(\frac{15!}{(15-3)!3!}\) = \(\frac{15!}{12!3!}\) = 35.

Hence, 15 people out of 3 people can be chosen in 35 ways.

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Answer:

  (8, 63)

Step-by-step explanation:

The ordered pair is a solution to the equation when substituting the values for x and y make the equation a true statement.

If we let x represent the first number of the ordered pair, it will be a solution when ...

  63 = 9x -9

  7 = x -1 . . . . . . . divide by 9

  8 = x . . . . . . . add 1

The blank gets filled with 8, so the ordered pair is (8, 63).

Answer:

0.0652173

Step-by-step explanation:

Given that :

6 chocolate chip cookies

6 peanut butter cookies

6 sugar cookies

6 oatmeal cookies

Total number of cookies purchased = (6+6+6+6) = 24

Probability, P= required outcome /total possible outcomes

This is a selection without replacement probability problem :

P(peanut butter cookies) = 6/24 = 1/4

Then ;

P(chocolate chip cookie) = 6/23

Hence,

P(peanut butter cookies then chocolate chip cookie) = 1/4 * 6/23 = 0.0652173

At the fidelity credit union, the mean number of customers who arrive hourly at the drive-through window is 4.9. It is required to determine the probability of fewer than 1 customer arriving in any hour.

Answer: 0.00796.

The solution to this problem is discussed below:

The given information implies that the mean value of the Poisson distribution, λ = 4.9.

In a Poisson distribution, the probability of x occurrences during a particular interval is given by:

P(x; λ) = e–λ λx / x!

Where e is approximately equal to 2.71828.

Let x = 0 since we need the probability of less than 1 customer in an hour.

P(x < 1) = P(x = 0) + P(x = 1) + P(x = 2) + …P(x < 1) = e-4.9 4.90 / 0!P(x < 1) = e-4.9 1P(x < 1) = 0.00796

The probability of fewer than 1 customer arriving in any hour is 0.00796 (rounded to four decimal places)

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Answer:

a) 5xy + 9yz + 3zx + 5x - 4y

Step-by-step explanation:

→ (7xy + 5yz - 3zx) + (4yz + 9zx - 4y) + (-3xz + 5x - 2xy)

→ (7xy - 2xy) + (5yz + 4yz) + (-3zx + 9zx - 3xz) + (5x) + (-4y)

→ 5xy + 9yz + 3zx + 5x - 4y

Hence, option (a) is the correct answer.

Answer:

\(\textsf{A)}\quad \sf 5xy+9yz+3zx+5x-4y\)

Step-by-step explanation:

Given expression:

\(\sf (7xy+5yz-3zx)+(4yz+9zx-4y)+(-3xz+5x-2xy)\)

Remove the parentheses:

\(\implies \sf 7xy+5yz-3zx+4yz+9zx-4y-3xz+5x-2xy\)

Collect like terms:

\(\implies \sf 7xy-2xy+5yz+4yz+9zx-3zx-3xz+5x-4y\)

Combine like terms:

\(\implies \sf (7-2)xy+(5+4)yz+(9-3-3)zx+5x-4y\)

\(\implies \sf 5xy+9yz+3zx+5x-4y\)

Answer:

Step-by-step explanation:

a. 5x7 = 35 days

b. 12 x 7 = 84 days

c. not sure, its missing the number

Sample 1: Mean=10.01, Standard deviation=13.90 Sample 2: Mean

=11.43, Standard deviation

=14.10

Sample size of 1st year = n1

= 1012Mean of 1st year sample

= X1 = 10.01Standard deviation of 1st year sample

= s1

= 13.90Sample size of 2nd year

= n2

= 1012Mean of 2nd year sample

= X2

= 11.43

Standard deviation of 2nd year sample = s2

= 14.10 Let us assume a significance level of α = 0.05, which implies that the critical region consists of 2.5% in both tails (since it is a two-tailed test).

Therefore, we do not have sufficient evidence to conclude that the mean number of hours per week spent on the Internet differs between 2010 and another year.

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Answer:

8 and 10

Step-by-step explanation:

the ratio of the two numbers is 4:5

So let's take 4 and 5 as our number, we find out that their LCM is 20.

The next pair would be 8 and 10. Their LCM is 40 , so they are the numbers.

If  least common multiple of two whole numbers is 40. The ratio of the greater number to the lesser number is 4:5. Then the two numbers are 8 and 10.

The least common multiple, lowest common multiple, or smallest common multiple of two integers a and b,

Given as :

The least common multiple of two numbers = LCM = 40

The ratio of the greater number to lesser number = 4 : 5

let the greater number = 4 x

And The smaller number = 5 x

∵ The LCM of numbers = 40

4 × 5 × x = 40

20 × x = 40

20x=40

x=2

The greater number = 4 x=4(2)=8

The lesser number =5x=5(2)=10

Hence the two numbers are 8 and 10

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Answer:

The value of discriminant is -7.

Explanation:

The given equation is,

x^2+x+2=0x

2

+x+2=0

The standard form of the quadratic equation is,

ax^2+bx+c=0ax

2

+bx+c=0

By comparing the given equation with the standard equation we get,

a = 1, b = 1 and c = 2.

The Formula for discriminant is,

D=b^2-4acD=b

2

−4ac

Substitute a = 1, b = 1 and c = 2,

D=1^2-4(1)(2)D=1

2

−4(1)(2)

D=1-8D=1−8

D=-7D=−7

Therefore, the -7 is the value of the discriminant.

Step-by-step explanation:

# Jerry Don is here#

Answer:

-7

Step-by-step explanation:

took the test

Answer:

Step-by-step explanation:

The common ratio of the following sequence is:

If the common ratio is less than 1 or greater than -1 but not 0, we can use the following expression to determine the sum of the infinite geometric series:

Therefore, if we have a common ratio of 3/8 or 0.375 and the first term of the series is 3/2.

The sum would be: