The mass of a golf ball is 45.9 g . If it leaves the tee with a speed of 61.0 m/s , what is its corresponding wavelength?

Answer:

Metal salts commonly used in firework displays include: strontium carbonate (red fireworks), calcium chloride (orange fireworks), sodium nitrate (yellow fireworks), barium chloride (green fireworks) and copper chloride (blue fireworks).

Explanation:

Answer:

Metal salts commonly used in firework displays include: strontium carbonate (red fireworks), calcium chloride (orange fireworks), sodium nitrate (yellow fireworks), barium chloride (green fireworks) and copper chloride (blue fireworks).

The colors are produced by heating metal salts, such as calcium chloride or sodium nitrate, that emit characteristic colors. ... Barium – Barium is used to create green colors in fireworks, and it can also help stabilize other volatile elements. Calcium – Calcium is used to deepen firework colors

Well because sometimes, weather forecasters don't get it right. Some weather phenomena can occur when we aren't expecting them; they are impromptu.

I cant help u coz it is an (well i dont know) but i think u r in college so this would be a hard question

Answer: Trail 2

Explanation: Because it has a pressure of 1 atm

A.) The solubility of nitrogen at a pressure of 2.00 atm is \(1.36 \times 10^{(-3)} M.\)

B.) The solubility of nitrogen at a pressure of 688 mmHg is \(6.17 \times 10^{(-4)} M.\)

To calculate the solubility of nitrogen (N2) in M (molarity) at different pressures, we need to use Henry's Law, which states that the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid. The equation for Henry's Law is:

C = k * P

Where:

C is the solubility of the gas in M (molarity)

k is the Henry's Law constant

P is the partial pressure of the gas

For nitrogen, the Henry's Law constant (k) is approximately 6.8 x 10^(-4) M/atm.

a) To calculate the solubility of nitrogen at a pressure of 2.00 atm:

C = (6.8 x 10^(-4) M/atm) * (2.00 atm)

C = 1.36 x 10^(-3) M

Therefore, the solubility of nitrogen at a pressure of 2.00 atm is 1.36 x 10^(-3) M.

b) To calculate the solubility of nitrogen at a pressure of 688 mmHg:

First, we need to convert mmHg to atm by dividing by 760 (since 1 atm = 760 mmHg).

P = 688 mmHg / 760 mmHg/atm

P = 0.905 atm

C = (6.8 x 10^(-4) M/atm) * (0.905 atm)

C = 6.17 x 10^(-4) M

Therefore, the solubility of nitrogen at a pressure of 688 mmHg is 6.17 x 10^(-4) M.

It's important to note that the solubility of a gas can also depend on temperature, so these calculations assume a constant temperature. Additionally, Henry's Law is an approximation and may not hold true for all gas-liquid systems, especially at high pressures or when there are significant intermolecular interactions between the gas and liquid.

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Particles in a metal are held together by Covalent attractions. These are the strongest attraction or types of bonding

The bonds that hold atoms together to form molecules are called covalent bonds. They are pretty tough and not easily made or broken apart. It takes energy to make the bonds and energy is released when the bonds are broken.

For example, there is a covalent bonding between a Chlorine molecule. the two chlorine atoms are held strongly via covalent bonds.

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Answer: The partial pressure of oxygen in the mixture if the total pressure is 525 mmHg is 310 mm Hg

Explanation:

mass of nitrogen = 37.8 g

mass of oxygen = (100-37.8) g = 62.2 g

Using the equation given by Raoult's law, we get:

\(p_A=\chi_A\times P_T\)

\(p_{O_2}\) = partial pressure of \(O_2\) = ?

\(\chi_{O_2} = mole fraction of O_2=\frac{\text{Moles of }O_2}{\text{Total moles}}\)

\(P_{T}\) = total pressure of mixture  = 525 mmHg

\({\text{Moles of }O_2}=\frac{\text {Given mass}}{\text {Molar mass}}=\frac{62.2g}{32g/mol}=1.94moles\)

\({\text{Moles of }N_2}=\frac{\text {Given mass}}{\text {Molar mass}}=\frac{37.8g}{28g/mol}=1.35moles\)

Total moles = 1.94 + 1.35 = 3.29 moles

\(\chi_{O_2}=\frac{1.94}{3.29}=0.59\)

\(p_{O_2}=\chi_{O_2}\times P_T=0.59\times 525=310mmHg\)

Thus the partial pressure of oxygen in the mixture if the total pressure is 525 mmHg is 310 mm Hg

A gaseous mixture of O₂ and N₂ that contains 37.8% nitrogen by mass, and whose total pressure is 525 mmHg, has a partial pressure of oxygen of 310 mmHg.

A gaseous mixture of O₂ and N₂ contains 37.8% nitrogen by mass, that is, in 100 g of the mixture, there are 37.8 g of N₂. The mass of O₂ in 100 g of the mixture is:

\(mO_2 = 100 g - 37.8 g = 62.2 g\)

We will convert both masses to moles using their molar masses.

\(N_2: 37.8 g \times 1 mol/28.00 g = 1.35 mol\\\\O_2: 62.2 g \times 1 mol/32.00 g = 1.94 mol\)

The mole fraction of O₂ is:

\(\chi(O_2) = \frac{nO_2}{nN_2+nO_2} = \frac{1.94mol}{1.35mol+1.94mol} = 0.590\)

Given the total pressure (P) is 525 mmHg, we can calculate the partial pressure of oxygen using the following expression.

\(pO_2 = P \times \chi(O_2) = 525 mmHg \times 0.590 = 310 mmHg\)

A gaseous mixture of O₂ and N₂ that contains 37.8% nitrogen by mass, and whose total pressure is 525 mmHg, has a partial pressure of oxygen of 310 mmHg.

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For the solution with a pH of 7.9:

pH = 7.9

pOH = 14 - pH = 14 - 7.9 = 6.1

[H+] = 10^(-pH) = 10^(-7.9) (in mol/L)

[OH-] = 10^(-pOH) = 10^(-6.1) (in mol/L)

The pH of a solution is a measure of its acidity, while pOH is a measure of its alkalinity. The pH and pOH values are related through the equation pH + pOH = 14.

For the solution with a pH of 4.5:

pH = 4.5

pOH = 14 - pH = 14 - 4.5 = 9.5

[H+] = 10^(-pH) = 10^(-4.5) (in mol/L)

[OH-] = 10^(-pOH) = 10^(-9.5) (in mol/L)

For the solution with a pH of 7.9:

pH = 7.9

pOH = 14 - pH = 14 - 7.9 = 6.1

[H+] = 10^(-pH) = 10^(-7.9) (in mol/L)

[OH-] = 10^(-pOH) = 10^(-6.1) (in mol/L)

Note: The [H+] and [OH-] concentrations can also be calculated using the equation [H+][OH-] = 1 x 10^(-14) at 25°C.

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Answer:

d=m/

Explanation:

d is density, m is mass, v is volume

Given: m =10.4g, v=12.2mL

substituting in equation,

d=10.4/ 12.2

d=0.8524g/mL

To learn more about density:

The density of the liquid is 0.852 g/mL.

To calculate the density of the liquid, we need to use the formula:

Density = Mass / Volume

Given that the mass of the liquid is 10.4 g and the volume is 12.2 mL, we can substitute these values into the formula:

Density = 10.4 g / 12.2 mL

Simplifying this expression, we find:

Density = 0.852 g/mL

Density is a physical property of a substance and is defined as the amount of mass per unit volume. In this case, the density tells us that for every milliliter of the liquid, there is 0.852 grams of mass. The units of grams per milliliter (g/mL) indicate that the density is a ratio of mass to volume.It is important to note that the density of a substance can vary with temperature, so this value is only valid under the conditions at which the measurement was made. Additionally, the density can provide valuable information about the identity of a substance, as different substances have different densities.

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The process of catalysis  which involves adding a catalyst  to a chemical reaction, increases the rate of the reaction.

Thus, Catalysts are not destroyed during the reaction and are unaffected by it. Very tiny amounts of catalyst are frequently sufficient when the reaction is swift and the catalyst recycles quickly; mixing, surface area, and temperature are key factors in reaction rate.

In order to regenerate the catalyst, it usually reacts with one or more reactants to produce intermediates that then give off the ultimate reaction product.

Homogeneous catalysis, in which all of the components are dispersed in the same phase as the reactant (often a gas or liquid), and heterogeneous catalysis, in which the components are not.

Thus, The process of catalysis  which involves adding a catalyst  to a chemical reaction, increases the rate of the reaction.

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The minimum entropy change of the heat-supplying source is -0.87 kJ/K.

In this case, given the initial conditions, we first use the 10-% quality to compute the initial entropy.

S₁ = 1.485  +  (0.1)(5.6865) = 2.0537 kJ/kg K

The entropy at the final state given the new 40-% quality:

S₂ = 1.4337  +  (0.4)(5.7894) = 3.7495 kJ/kg K

m₁ = 0.026/(0.001057   +  0.1 x 1.002643) = 0.257 kg

m₂ = 0.026/(0.001053   +  0.4 x 1.158347)  = 0.056 kg

ΔS + S₁  - S₂  + S₂m₂  - S₁m₁  -  sfg(m₂  -  m₁)  > 0

ΔS + 2.0537 -  3.7495 + (3.7495 x 0.056)  -   (2.0537 x 0.257)  - 5.6865( 0.056 - 0.257)  >  0

ΔS > -0.87 kJ/K

Thus, the minimum entropy change of the heat-supplying source is -0.87 kJ/K.

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Answer:

Explanation:

Here, we want to get the number of moles in 4.25 g of CO

To get the number of moles, we have to divide the mass by the molar mass of CO

Mathematically:

The molar mass of CO is the sum of the atomic masses of carbon and oxygen

The atomic mass of carbon is 12 amu

The atomic mass of oxygen is 16 amu

The molar mass is thus:

Thus, we have the number of moles as:

Answer:

1.75 moles

Explanation:

According to CaC₂(s) + 2 H₂O(l) --> C₂H₂(g) + Ca(OH)₂(aq)

2 moles of H20 will produce 1 mole of Ca(OH)2

therefore 3.5 moles of H2O will produce 3.5 x (1/2) = 1.75 moles of Ca(OH)2

Answer

D. Food flavoring

Answer:

Explanation:

No se

Answer:

option a = weight is not considered as a simple machine

hope this answer will help you

The correct answer is A. Since the system is cooled, the reaction will try to generate heat to compensate for the loss.

According to Le Chatelier's principle, the system will shift in the direction that opposes the stress. In this case, cooling is the stress and the system will shift in the direction that produces heat.

Therefore, the reaction will shift to the right (products) to generate heat. This will cause the concentration of HI to increase, while the concentrations of H₂ and I₂ decrease, according to the stoichiometry of the reaction. Therefore, the correct answer is A. The reaction shifts to the right (products) and the concentration of HI increases.

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Answer: The reaction shifts to the left (reactants) and the concentrations of H^2 and I^2 increase is correct. (Answer C)

Answer: 6.02 × 10^24

Explanation:

Answer:

True

Explanation:

When a force acts on an object, the object may change shape by bending, stretching or compressing - or a combination of all three shape changes.

In the PhET activity, "Properties of Gases", when pressure is kept the same and heat the volume increases. Therefore, option D is correct.

Charles' law states that if the pressure remains constant, the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature.

This law states that a gas's volume and temperature have a direct relationship: as temperature rises, volume rises when pressure remains constant. When a gas is heated, the kinetic energy of the particles increases, causing the gas to expand.

Thus, option D is correct.

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Answer:

the answer is a

Explanation:

Answer:

The planet would stop

Good luck!

Answer:

4 NH3(0) + 3 O2(g) → 2 N2(g) + 6H20() ... How many grams of water would be formed from 96.0 g NH3 in a reaction represented by the balanced equation below.

Missing: 6 ‎H₂O( ‎l)​

Explanation:

The normal boiling point of the unknown liquid is 57.4°C.

The normal boiling point occurs when the vapor pressure of the liquid is equal to the atmospheric pressure. At normal boiling point, the temperature of the liquid is called the boiling point.

Using the Clausius-Clapeyron equation:

ln(P₂/P₁) = -(ΔHvap/R) * (1/T₂ - 1/T₁)

where P₁ is the vapor pressure at the given temperature T₁, P₂ is the vapor pressure at the boiling point temperature T₂, ΔHvap is the heat of vaporization, R is the gas constant.

At -170°C, the vapor pressure of the liquid is given as P₁ = 117 torr. At normal boiling point, the vapor pressure of the liquid is P₂ = 760 torr.

Converting all units to SI units, we have:

P₁ = 15.47 Pa

P₂ = 101325 Pa

ΔHvap = 5480 J/mol

R = 8.314 J/(mol*K)

Plugging in the values, we get:

㏑(101325/15.47) = -(5480/8.314) * (1/T₂ - 1/103.15)

Solving for T₂, the boiling point is found to be:

T₂ = 57.4°C

As a result, the unknown liquid's usual boiling point is 57.4°C.

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The mass of hydrogen needed to produce 51.0 grams of ammonia is  ≈ 9.07 grams.

To determine the mass of hydrogen required to produce 51.0 grams of ammonia (NH3) using the Haber process, we need to calculate the stoichiometric ratio between hydrogen and ammonia.

From the balanced chemical equation:

3 H₂(g) + N₂(g) → 2 NH₃(g)

We can see that for every 3 moles of hydrogen (H₂), we obtain 2 moles of ammonia (NH₃).

First, we need to convert the given mass of ammonia (51.0 grams) to moles. The molar mass of NH₃ is 17.03 g/mol.

Number of moles of NH₃ = Mass / Molar mass

                     = 51.0 g / 17.03 g/mol

                     ≈ 2.995 moles

Next, using the stoichiometric ratio, we can calculate the moles of hydrogen required.

Moles of H₂ = (Moles of NH₃ × Coefficient of H₂) / Coefficient of NH₃

           = (2.995 moles × 3) / 2

           ≈ 4.493 moles

Finally, we can convert the moles of hydrogen to mass using the molar mass of hydrogen (2.02 g/mol).

Mass of H₂ = Moles × Molar mass

          = 4.493 moles × 2.02 g/mol

          ≈ 9.07 grams

Therefore, approximately 9.07 grams of hydrogen is needed to produce 51.0 grams of ammonia in the Haber process.

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Answer:Two Main Types of Pure Substances

Elements and compounds are the two types of pure substances. Examples of common elements include carbon, nitrogen and hydrogen. They consist of one type of atom and cannot break down into something else. Every pure carbon substance, for example, has the same particles in it.

Explanation:I think

Matter and Change - Chemical reaction - Reactants and products.

A chemical reaction is a process in which some substances (reactants) change into different substances (products).

Answer:

The reactants are present in the start of the chemical reaction while products are present at the end of the chemical reaction.

A reaction rate is the change in concentration of a reactant or product with time, and it is affected by the concentration of the reactants and products. An increase in the concentration of one or more reactants results in an increase of the reaction rate.

In this case we have the following net ionic chemical reaction:

We can see that the reactants are:

So an increase in the concentration of any of them would increase the rate of the reaction.

So the answer is B and C.

B: Iodide ions (I-)

C:Persulfate ions (S2O8-2)

The ideal gas law equation is: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

To determine the mass of NaCl that reacted with F2 at 290 K and 1.5 atm, we can rearrange the equation as follows: n = PV/RT. Substituting in the values for P, V, R, and T, we get: n = (1.5 atm)(18.0 L)/(0.0821 atm*L/mol*K)(290 K) = 0.835 mol NaCl.

To determine the mass of sodium chloride that can react with the same volume of fluorine gas at STP (standard temperature and pressure), we would use the same equation but with the values for P, V, R, and T corresponding to STP. At STP, P = 0.987 atm, V = 18 L, R = 0.0821 atm*L/mol*K, and T = 273 K. Therefore, n = (0.987 atm)(18 L)/(0.0821 atm*L/mol*K)(273 K) = 0.792 mol NaCl.

What is Sodium chloride?

Sodium chloride, also known as table salt, is an ionic compound composed of sodium and chloride ions in equal proportions. It is a mineral found naturally in most bodies of water, including sea water, and is widely used as a seasoning and preservative in food.

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Answer:

The ideal gas law equation is: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

To determine the mass of NaCl that reacted with F2 at 290 K and 1.5 atm, we can rearrange the equation as follows: n = PV/RT. Substituting in the values for P, V, R, and T, we get: n = (1.5 atm)(18.0 L)/(0.0821 atm*L/mol*K)(290 K) = 0.835 mol NaCl.

To determine the mass of sodium chloride that can react with the same volume of fluorine gas at STP (standard temperature and pressure), we would use the same equation but with the values for P, V, R, and T corresponding to STP. At STP, P = 0.987 atm, V = 18 L, R = 0.0821 atm*L/mol*K, and T = 273 K. Therefore, n = (0.987 atm)(18 L)/(0.0821 atm*L/mol*K)(273 K) = 0.792 mol NaCl.

Explanation:

The balanced chemical equations of the reactions are given below:

1. Mg (s) + 2 H₂O (l) ----> Mg(OH)₂ (s) + H₂ (g)

2. 2 Li (s) +  2 H₂O (l) ----> LiOH (aq) + H₂ (g)

A balanced chemical equation is an equation in which the number of moles of atoms of elements in a given reaction is equal to the sum of the number of moles of atoms of each element that is produced.

A balanced chemical equation is in accordance with the law of conservation of mass which states that matter can neither be created nor destroyed.

When balancing chemical equations, numerical coefficients are added in front of moles of atoms of an element or moles of a given compound taking part in the reaction.

The balanced chemical equation of the reaction of magnesium and water as well as the reaction of lithium and water is given below:

Magnesium and water:

Mg (s) + 2 H₂O (l) ----> Mg(OH)₂ (s) + H₂ (g)

Lithium and water:

2 Li (s) +  2 H₂O (l) ----> LiOH (aq) + H₂ (g)

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Answer:

The options (A) -The rate law for a given reaction can be determined from a knowledge of the rate-determining step in that reaction's mechanism.  and (C) -The rate laws of bimolecular elementary reactions are second order overall ,is true.

Explanation:

(A) -The rate law can only be calculated from the reaction's slowest or rate-determining phase, according to the first sentence.

(B) -The second statement is not entirely right, since we cannot evaluate an accurate rate law by simply looking at the net equation. It must be decided by experimentation.

(C) -Since there are two reactants, the third statement is correct: most bimolecular reactions are second order overall.

(D)-The fourth argument is incorrect. We must track the rates of and elementary phase that is following the reaction in order to determine the rate.

Therefore , the first and third statement is true.