The mean free path is the average distance traveled by a particle between collisions with other particles. Calculate the mean free path
of air at room temperature, =69.8 ∘F. Air is mostly nitrogen, so assume that the collisions are between moving N2 molecules. The diameter of N2 is =1.58×10−10 m and the gas is at atmospheric pressure, =101325 Pa

When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times. The density of the air filled in the polythene container is approximately 1.25 kg/m³.

The density of air filled in the polythene container can be determined by considering the change in mass and volume of the container before and after filling it with air. Given that the mass of the empty container is 0.419 kg and the mass of the container when filled with extra air is 0.428 kg, and the volume of the perplex box is 1000 cm³.

Calculate the mass of the air inside the container by subtracting the mass of the empty container from the mass of the container when filled with air:

Mass of air = Mass of filled container - Mass of empty container

= 0.428 kg - 0.419 kg

= 0.009 kg

Calculate the volume of the air inside the container using the given number of times the air inside is 7.2:

Volume of air = Volume of perplex box * Number of times air inside

= 1000 cm³ * 7.2

= 7200 cm³

Convert the volume of air to cubic meters (m³) by dividing by 1000000:

Volume of air = 7200 cm³ / 1000000

= 0.0072 m³

Calculate the density of air using the formula:

Density = Mass / Volume

Density = 0.009 kg / 0.0072 m³

≈ 1.25 kg/m³

Therefore, the density of the air filled in the polythene container is approximately 1.25 kg/m³.

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The speed of the puck is 3.67 m/s.

To find the speed of the puck, we can use the concept of centripetal force. The tension in the string provides the necessary centripetal force to keep the puck moving in a circle. At the same time, the tension in the string also supports the weight of the suspended mass.

Using Newton's second law, we can write two equations of motion: one for the puck and one for the suspended mass. For the puck, the net force acting on it is the tension in the string, which is equal to the centripetal force required to keep it moving in a circle. Thus, we can write:

= m1 * v^2 / R

where T is the tension in the string, v is the speed of the puck, and R is the radius of the circle.

For the suspended mass, the net force acting on it is its weight minus the tension in the string, which must be zero since the mass is in equilibrium. Thus, we can write:

T = m2 * g

where g is the acceleration due to gravity.

Combining these two equations, we can solve for the speed of the puck:

v = sqrt(T * R / m1) = sqrt(m2 * g * R / m1)

Substituting the given values, we get:

v = sqrt(1.0 kg * 9.81 m/s^2 * 0.9 m / 0.21 kg) = 3.67 m/s

Therefore, the speed of the puck is 3.67 m/s.

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Answer:

2.5 hours

Explanation:

we know that the train travels 64km every hour so we just need to divide 160km by 64km to see how many hours it will take

160÷64= 2.5

hope this helps chu :3

That's a great question !

The answer is: It does !

A push on an object causes the object to accelerate in the direction of the force.  

The less mass the object has, the more the force accelerates it.

Now, when you jump, the forces on you and on the Earth are equal forces.

The up force on you causes you to accelerate up by some amount.

The down force on the Earth causes the Earth to accelerate down by some amount.

The Earth's mass is something like 5,972,000,000,000,000,000,000,000 kg, while your mass is something like 50 kg.

The Earth has something like 119,400,000,000,000,000,000,000 times as much mass as you have.

So your acceleration is something like 119,400,000,000,000,000,000,000 times as great as the Earth's acceleration.

==> The Earth's downward acceleration, caused by your jump, is there.  It's just too small to notice.

BUT . . . That's the reason why seismometers (instruments to detect and measure the vibrations from distant earthquakes) have to be located as far as possible from cities and busy roads.

In places that are too close to cities and roads, the Earth's surface is always vibrating, wiggling, jiggling, heaving and weaving, in reaction to the forces of people walking around, cars and trucks driving around, even rain falling down.  And kids jumping up and down !  

In such places, these people-motions are louder and stronger than the vibrations coming from distant earthquakes.  Seismometers wouldn't work there.    

Solution :

1. Rayleigh scattering takes place when the particle size is smaller than the wavelength (λ).

2. Mie scattering takes place when particle size is nearly equal to the wavelength (λ).

3. Non-selective scatter takes place when particle size in greater than the wavelength  (λ).

We have the sizes of different particles :

\($O_2 \rightarrow 10^{10} \ m $\)

Smoke particles \($\rightarrow 3 \times 10^{-7} \ m$\)

Cloud droplets \($\rightarrow 2 \times 10^{-5} \ m$\)

Rain droplets \($\rightarrow 3 \times 10^{-3} \ m$\)

Wavelength           \($ O_2 $\)         Smoke particles    Cloud droplets     Rain droplets

                            \($10^{-10} \ m$\)        \($ 3 \times 10^{-7} \ m$\)           \($ 2 \times 10^{-5} \ m$\)              \($ 3 \times 10^{-3} \ m$\)

\($5500 \times 10^{-4} \ m$\)      Rayleigh  Non-selective      Non-selective     Non-selective

\($11 \times 10^{-6} \ m $\)         Rayleigh    Rayleigh            Non-selective      Non-selective

\($1600 \times 10^{-10} \ m $\)    Rayleigh  Non-selective      Non-selective     Non-selective

\($10^{-2} \ m $\)                 Rayleigh      Rayleigh               Rayleigh          Mie

Answer:

Explanation:

a. The X and Y components of the velocity can be found using trigonometry:

X = V * cos(θ) = 15 m/s * cos(38°) ≈ 11.63 m/s

Y = V * sin(θ) = 15 m/s * sin(38°) ≈ 9.14 m/s

b. The time the ball is in the air can be found using the Y component of the velocity and the acceleration due to gravity:

Y = V * sin(θ) * t - (1/2) * g * t^2

where g = 9.8 m/s^2 is the acceleration due to gravity

Solving for t, we get:

t = 2 * Y / g ≈ 1.87 s

c. The distance the ball travels can be found using the X component of the velocity and the time in the air:

distance = X * time = 11.63 m/s * 1.87 s ≈ 21.78 m

The average velocity of the particle between t = 2.0 s and t = 4.0 s is 4 m/2.0 s = 2.0 m/s.

Average velocity is the rate of change of an object's position, expressed as a vector quantity that tells both the speed and direction of the object's motion.

The average velocity of the particle between t = 2.0 s and t = 4.0 s can be calculated by taking the difference in the x-position of the particle at t = 4.0 s and t = 2.0 s, and dividing it by the difference in the time.
The x-position of the particle at t = 2.0 s is 4 m and the x-position of the particle at t = 4.0 s is 8 m.
Therefore, the difference in the x-position is 8 m - 4 m = 4 m.
The difference in time is 4.0 s - 2.0 s = 2.0 s. Therefore, the average velocity of the particle between t = 2.0 s and t = 4.0 s is 4 m/2.0 s = 2.0 m/s.

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Answer:

A student is conducting a pendulum experiment. Which of the following pieces of safety equipment would be the most vital to conduct this test?

Explanation:bkdbjkfej jf jfekjwniorigoexhndvgkj...............aplokdiuhyfgbv ..............................................

Answer:

Higher Pitched! (b)

Explanation:

The Doppler effect makes it seem high pitched, as the sound waves are mushed together at a higher frequency, while moving away, the sound waves spread out like a lower frequency wave!

A snowboarder drops from rest into a halfpipe of radius R and slides down its frictionless surface to the bottom, the snowboarder's speed is \(\mathbf{v = \sqrt{2gR}}\)

The snowboarder's centripetal acceleration at the bottom is \(\mathbf{a_c = 2g}\). The normal force acting on the snowboarder at the bottom of the halfpipe = 3mg

According to the conservation of energy, at any given point of motion, the energy of a system will always be constant.

Using the conservation of energy at rest and also at the bottom of the pipe.

\(\mathbf{mgR = \dfrac{1}{2}mv^2}\)

The objective is to make the velocity (v) the subject of the formula:

\(\mathbf{gR = \dfrac{1}{2}v^2}\)

\(\mathbf{2gR = v^2}\)

\(\mathbf{v = \sqrt{2gR}}\)

(b)

Using the expression for centripetal acceleration;

\(\mathbf{a_c = \dfrac{v^2}{R}}\)

here,

let's replace \(\mathbf{v \ \ \ with \ \ \sqrt{2gR}}\);

Then;

\(\mathbf{a_c = \dfrac{(\sqrt{2gR})^2}{R}}\)

\(\mathbf{a_c =2g}\)

From the image attached below;

Provided that:

Then, we can infer that the normal net force acting on the person can be computed as:

By rearrangement;

where;

∴

n = 3mg

Therefore, we can conclude that the snowboarder's speed, centripetal force, and normal force are proved.

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Answer:

2 to 3 weeks

Explanation:

The reflected sound wavefronts at the given boundary are waves that have bounced off a surface and changed direction.

The reflected sound wavefront is shown in the attachment.

A reflected wavefront is a wavefront that has bounced off a surface and changed direction. When a wave, such as a light wave or sound wave, encounters a surface, some of the wave energy is reflected back in the opposite direction.

An example of reflected sound wavefronts in water can be seen in underwater sonar imaging.

In sonar imaging, a sound wave is emitted from a source and travels through the water. When the sound wave encounters an object, some of the wave energy is reflected back toward the source.

Reflected wavefronts play an important role in many areas of science and engineering, such as optics, acoustics, and electromagnetism. They are used to model the behavior of waves in complex systems and to design and optimize devices such as mirrors, lenses, and antennas.

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When the liquid cools down, it loses heat energy.

As the liquid cools, it loses heat energy. As a result, its particles slow down in movement and come closer to one another. Attractive forces begin to hold particles and the crystals of a solid form.

If water is cooled, it can change into ice. If ice is warmed, it can change into a liquid state. Heating a substance makes the molecules move very fast whereas cooling a substance makes the molecules move very slowly.

Heating a liquid increases the speed of the molecules present in it. An increase in the molecule's speed competes with the attraction between molecules and results in the molecules moving apart whereas Cooling a liquid decreases the movement of the molecules.

So we can conclude that the liquid cools down when it loses heat energy.

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Answer:

1.false

2.true

Answer: frequency f = 2000 1/s (Hz)

Explanation: period T means time for one cycle and frequency f tells how many cycles there are in seconds. Unit of frequency is 1/s= Hz. Period T = 1/f and frequency f= 1/T.

E.g is T= 0.01 s then f= 1/ (0.01 s) = 100 Hz. And I'd frequency is 20 Hz,

T= 1/(20 Hz)= 0.05 s. So, if T = 0.005 s, f= 1/T

Answer:

Conduction: Touching a stove and being burned. Ice cooling down your hand. .

Explanation:

The value of constants A and θ will be  θ = 66.5° or 1.161 radians  and A = 3.1 cm  

Simple Harmonic Motion or SHM is defined as a motion in which the restoring force is directly proportional to the displacement of the body from its mean position. The direction of this restoring force is always towards the mean position.

x(t) = A sin (ωt + θ)

time = 0.00 seconds

2.83 = A sin ( 0 +  θ)

A sin θ = 2.83                        `equation 1

ν(t) = A ω cos (ωt+θ)

3.25 = A * 2.64 * cos (0 + θ )

3.25 = 2.64 A cos θ

A cos θ = 3.25 / 2.64 = 1.23              equation 2

dividing equation 1 and 2 , we get

tan θ = 2.30

θ = 66.5° or 1.161 radians

from equation 1

A sin θ = 2.83  

A sin ( 66.5 ) = 2.83

A = 3.1 cm  

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equal in magnitude but opposite in direction

a. A high-pitch wave is characterized by a high frequency and a short wavelength. The frequency determines the pitch of the sound, with higher frequencies corresponding to higher pitches.

The wavelength is the distance between two consecutive peaks or troughs of the wave and is inversely proportional to the frequency. Therefore, a high-pitch wave has a shorter wavelength.

The amplitude of the wave, which is the height of the peak or the depth of the trough, is not directly related to the pitch of the sound, but it does determine the volume or intensity of the sound.

b. A high-volume wave is characterized by a high amplitude and a relatively long wavelength. The amplitude determines the volume or intensity of the sound, with higher amplitudes corresponding to louder sounds.

The wavelength of the wave does not directly affect the volume of the sound, but it can affect how the sound is perceived in different environments.

In general, longer wavelengths are more effective at traveling through obstacles such as walls and are better at penetrating long distances, whereas shorter wavelengths are more easily scattered and attenuated in the atmosphere.

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Answer:

A. their masses

D. the distance between them

Explanation:

100% correct

Two factors have an effect on the gravitational force between two

objects are their masses and the distance between them.

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

The gravitational constant, denoted by the capital letter G, is an empirical physical constant involved in the calculation of gravitational effects in Sir Isaac Newton's law of universal gravitation and in Albert Einstein's theory of general relativity.

f = Gmm/r²

Two factors have an effect on the gravitational force between two

objects are their masses and the distance between them.

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Determine the magnitude of B-A is 53.68

1.4

Magnitude is a term used to describe size or distance. We can relate the magnitude of the movement to the size and movement speed of the object. The magnitude of a thing or an amount is its size. A car moves at a faster pace than a motorcycle, just in terms of speed.

Magnitude is the relative size of an object (mathematics). The mathematical term for a vector's length or size is the norm. By using the symbol |v|, the magnitude of a vector formula can be utilized to determine the length of a given vector (let's say v). This amount is essentially the distance between the vector's beginning point and ending point.

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the magnitude and direction of this vector is cos −1√ (−5/ 89)

Magnitude is simply "distance or quantity" in the context of physics. In terms of motion, it shows the absolute or relative size, direction, or movement of an object. It is used to describe something's size or scope. Magnitude in physics typically refers to a size or quantity.

A constant quantity's magnitude is a numerical value for the quantity expressed in terms of a unit of measurement. For instance, the real number 2000 is the magnitude of the quantity 2 kilometers in the unit-of-measure meter.

Magnitude = (25) 2 + (40) 2 =5√89

Angle with the x-axis equals tan√ 1(y/x).

=tan −1 √ (40/−25)

=tan −1√ (−8/5)

=cos −1√ (−5/ 5 √2+6/2)

=cos −1√ (−5/ 89)

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Answer:

1.1x10^-2N

Explanation:

We have the change in momentum as

P = 0.3(4.5+12)g.mph

= 0.3x0.447x(4.5+12)x10^-3

Then the force that is exerted will be

F = p/∆t

∆t = 0.2

= 0.3x0.447x(4.5+12)x10^-3/0.2

= 0.1341x16.5x10^-3/0.2

= 1.1x10^-2

Therefore the force that was exerted is equal to 1.1x10^-2

The required magnitude of the force exerted on the fly is of \(5.025 \times 10^{-3} \;\rm N\).

Given data:

The mass of mosquito is, \(m =0.3 \;\rm g =3 \times 10^{-4} \;\rm kg\)

The speed of flying is, u = 4.5 mph = 4.5 ( 0.447) = 2.01 m/s.

The swatting speed of mosquito is, v = 12 mph = 12 (0.447 ) = 5.36 m/s.

The time of contact is, t = 0.2 s.

In this problem, we will first calculate the change in momentum, and the change in momentum is given as,

p = m ( v - u)

Solving as,

\(p = 3 \times 10^{-4} (5.36 - 2.01)\\\\p = 1.005 \times 10^{-3} \;\rm kg.m/s\)

Now as per the Newton's second law,

\(F = p/t\\\\F = 1.005 \times 10^{-3} / 0.2\\\\F= 5.025 \times 10^{-3} \;\rm N\)

Thus, the required magnitude of the force exerted on the fly is of \(5.025 \times 10^{-3} \;\rm N\).

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given that there is no second choice i have to go with helium. if you get the second choice i will revise my answer

Answer: B im sorry if its wrong

Explanation:

Answer:

The characteristics that determine how easily two substances change temperature are:

The volume and density of the substances and the amount of time they are in contact do not directly affect how easily they change temperature.

Explanation:

Answer:

Explanation: A box that has a mass of 19.8kg is pushed across 16.4m on the floor with a force of 93.2N, the floor has 0.355 as the coefficient of kinetic friction:

Visual Illustration of the problem:

Net work done by roy: