the member with a cross-section area of a is subjected to axial loading p as shown. what is the maximum shearing stress and its corresponding plane?

Answers

Answer 1

To determine the maximum shearing stress and its corresponding plane, you would need to know the value of the axial load p, and the cross-sectional area A of the member.

What is shearing stress?

Shearing stress is a type of stress that occurs in a material when the applied forces generate sliding or slippage along the parallel planes within the material. It is a measure of the force per unit area that is resisting this sliding or shearing.

The maximum shearing stress in a member subjected to axial loading is given by the formula:

τ_max = p / (2A)

where p is the axial load, and A is the cross-sectional area of the member. The plane where the maximum shearing stress occurs is perpendicular to the plane of the cross section.

It is important to note that the maximum shearing stress occurs at 45 degrees to the axis of the member, at the point where the stress is acting at right angles to both the longitudinal and radial axes of the cross section.

Therefore, to determine the maximum shearing stress and its corresponding plane, you would need to know the value of the axial load p, and the cross-sectional area A of the member.

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Related Questions

The Sun is spherical due to
gravitation
Earth and Moon circling it.
Earth circling it.
none of the above

Answers

Answer:

gravitation

good luck, hope this helps :)

gravitation hope this helps

A block of mass m is suspended by a vertically oriented spring. If the mass of a block is increased to 4m, how does the frequency of oscillation change, if at all

Answers

Answer:

The frequency will be reduced by a factor of √2/2

Explanation:

Pls see attached file

A block of mass m is suspended by a vertically oriented spring. If the mass of a block is increased to

The new frequency of oscillation will be half the original frequency of oscillation of spring-block system.

Let the initial mass of block be m.

And new mass is, 4m.

The frequency of oscillating motion is defined as the number of complete oscillation made during the time interval of 1 second. The mathematical expression for the frequency of oscillation of block-spring system is given as,

\(f = \dfrac{1}{2 \pi}\sqrt{\dfrac{k}{m}}\)

Here,

k is the spring constant.

If the mass of block increased to 4m, then the new frequency of oscillation of spring will be,

\(f' = \dfrac{1}{2 \pi} \sqrt{\dfrac{k}{4m}}\\\\\\f' =\dfrac{1}{2} \times \dfrac{1}{2 \pi} \sqrt{\dfrac{k}{m}}\\\\\\f' =\dfrac{1}{2} \times f\)

Thus, we can conclude that the new frequency of oscillation will be half the original frequency of oscillation of spring-block system.

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Microevolution three mechanisms that cause allelic frequencies to change in a population: gene flow, genetic drift, natural selection bottleneck effect founder effect population gene pool stabilizing, directional and disruptive selection hardy-weinberg equilibrium five conditions that must be met in order for population to be in hardy-weinberg equilibrium adptive evolution relative fitness sexual selection sexual dimorphism intrasexual selection intersexual selection neutral variation balancing selection heterozygote advantage hardy-weinberg problems

Answers

Microevolution refers to the evolution occurring at species-level involves three mechanisms that cause allelic frequencies to change in a population: gene flow, genetic drift, and natural selection.

Changes in the environment can affect population gene pools on both a small- and large-scale. Microevolution is the process of population-level changes in allele frequency. Some alterations take place at the species level or lower. There are hence variations in allele frequencies between or within groups.

Natural selection is one of the mechanisms of microevolution. It serves as an editor for allele frequency in populations to determine whether individuals with particular features have a higher or lower chance of surviving and procreating. Populations' gene pools can occasionally shift as a result of individuals leaving or entering the community. This transfer of alleles between populations is referred to as gene flow. Genes can "flow" from one area to another just like water does in a river.

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A rocket is launched straight up with constant acceleration. Five seconds after liftoff, a bolt falls off the side of the rocket. The bolt hits the ground 10.0 s later. What was the rocket's acceleration?

Answers

Explanation:

To find the acceleration of the rocket, we need to use the equations of motion for constant acceleration.

We know that the bolt was dropped 5 seconds after the rocket was launched, and that it took 10 seconds for the bolt to hit the ground. This means that the bolt was in free fall for 10 - 5 = <<10-5=5>>5 seconds.

We can use the equation d = 1/2 * a * t^2 to find the acceleration of the bolt. We know that the bolt fell a distance of 10 meters in 5 seconds, so we can plug those values into the equation to get: 10 = 1/2 * a * 5^2. Solving for a gives us a = 2 * 10 / 5^2 = 2 * 10 / 25 = 0.8.

Since the bolt was in free fall, its acceleration was due to gravity, which is about 9.8 meters per second squared. This means that the rocket must have had an acceleration greater than 9.8 meters per second squared in order to cause the bolt to fall off of it.

Therefore, the rocket's acceleration must have been greater than 0.8 meters per second squared. However, we cannot say exactly what the acceleration was without knowing more information about the rocket and its launch conditions.

The acceleration of the rocket is 197.5 m/s² if the bolt hits the ground 10.0 s later.

What is Kinematics ?

A branch of physics called kinematics, which was evolved from classical mechanics, defines how points, bodies, and systems of bodies (groups of objects) move without taking into account the forces that propel them. The discipline of kinematics is sometimes thought of as a subfield of mathematics and is sometimes referred to as the "geometry of motion." Any known values of the location, velocity, and/or acceleration of points inside the system are declared as initial conditions for a kinematics issue, together with the geometry of the system. The location, velocity, and acceleration of any unidentified system components can then be calculated using geometrical considerations. Kinematics, not kinematics, is the study of forces and their effects on physical objects. For further information, visit.

Given,

time of the bolt = 10-5 =5s

acceleration due to gravity =9.8m/s²

The height of the bolt s = ut+1/2at²

s = 0+ 1/2 ×9.8×5²

s = 122.5m

We cannot find the acceleration of the rocket without its final velocity (velocity of the rocket at the time of fall of bolt). Therefore Consider the final velocity of the Rocket is 220m/s

Then,

v² = u² + 2as

220² = 0 +2×a×122.5

48400 = 245 a

a = 197.5 m/s²

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An assessment tool that measures the amount of stress in a person’s life over a one-year period resulting from major life events is called

the Social Readjustment Rating Scale.

the Stress Scale.

the Annual Stress Scale.

the Social Scale.

Answers

Answer:

The correct answer is - the Social Readjustment Rating Scale.

Explanation:

The social readjustment rating scale is developed by Richard Rahe and Thomas Holmes to measure the stress caused by this important and major life event. Stress helps in developing a psychological approach for the particular person.

It is an assessment tool to calculate the impact of the major life events in the time period of one year with the help of units of 0 to 100. 100 is extreme or highest stress caused by the event such as the death of the spouse.

what would the net force be on the box in the problems shown below.( both force and direction).​

what would the net force be on the box in the problems shown below.( both force and direction).

Answers

Answer:

4

Explanation:

The net force on the box a will be 20 N to the left and that on box b is 6 N downwards. The net force on box  c is 90 N to the left and that on box d is zero.

What is net force?

Force is an external agent acting on a body to change its motion or to deform it. The net force acting on a body depends on all the the forces with their magnitudes and directions.

If two same or different forces acts from the same direction they will add up and net force will be their sum. If they acts from the different directions, they will cancel each other in magnitudes.

In box a, the equal forces of 20 N opposes from each direction cancel and the net force will be 20 N to the left. I box b the 15 N cancel each other. Where the 4N and 2 N add up to have net force of 6 N downwards.

In box c, 10 N from opposite direction cancels and the 60 N and 30 N to the left add ups to have the net force of 90 N to the left. On box d, 5 N from opposite directions cancels as 12 N. Hence, net force is zero.

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A candle is sitting in front of a concave mirror at a distance of 18.0 cm. It is found that an image of the ca
25.0 cm. What is the focal length of the mirror?
03.52 cm
07.50 cm
O 10.4 cm
022.1 cm

Answers

Answer:

The focal length of the mirror is 10.4 cm.

Explanation:

The object distance ( d₀ )  ( distance of the candle from the mirror) is -18 cm.The Image distance ( dᵢ  ) ( distance of the image from the mirror) is -25.0 cm.The mirror equation is  1/f = 1/d₀ + 1/dᵢ.

So substitute the values of object distance and image distance in the mirror equation,

1/f = 1/(-18cm) + 1/(-25.0cm)

1/f = -25cm/(-18cm x -25cm) - 18cm/(-18cm x 25cm)

1/f = ( -25cm - 18cm)/(18cm x 25cm)

1/f = -43.0/450.0

f = -10.4651 cm.

The focal length of the mirror is approximately -10.4 cm.

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What are fitness assessments designed to do?
diagnose medical conditions
screen for risk of heart disease
treat injuries
identify specific injuries

Answers

Answer: Fitness assessments are designed to screen for risk of heart disease.

Explanation:

Fitness assessments are medical examinations that are designed to measure a person's physical fitness and identify any health risks they may have. These assessments may include tests of strength, endurance, flexibility, and cardiovascular fitness. One of the primary objectives of a fitness assessment is to screen for the risk of heart disease, which is a major health concern that can be prevented or treated through exercise and other lifestyle changes. While fitness assessments may identify specific injuries or medical conditions, their primary focus is on evaluating a person's overall health and fitness.

1)The rotor on a helicopter turns at an angular velocity of 3.2x102 revolutions per minute. Express this angular velocity in radians per second.

Answers

The angular velocity in radians per second can be calculated as,

\(\begin{gathered} \omega=(3.2\times10^2\text{ rev/min)(}\frac{2(3.14)\text{ rad}}{1\text{ rev}})(\frac{1\text{ min}}{60\text{ s}}) \\ =33.5\text{ rad/s} \end{gathered}\)

Thus, the angular velocity of the rotor is 33.5 rad/s.

a golf ball with a velocity 40 at an angle 45 degree speed of bthe ball after 2 sec

Answers

Answer:

Vertical velocity = 8.28 m/s

Horizontal velocity = 28.3 m/s

__________________________________________________________

We are Given:

Initial velocity of the ball = 40 m/s

Angle of elevation of the ball = 45°

Time interval = 2 seconds

__________________________________________________________

Vertical and Horizontal Components:

Vertical Component:

The vertical component of the ball can also be written as:

40*Sin(45°)

40*(1/√2)                                                          [since Sin(45°) = 1/√2]

40/√2 m/s

Horizontal Component:

The horizontal component of the ball can also be written as:

40*Cos(45°)

40*(1/√2)                                               [Since Cos(45°) = 1/√2]

40/√2 m/s

__________________________________________________________

Speed of the Ball after 2 seconds:

Horizontal Velocity:

Since the horizontal velocity is not affected by any force during the flight, the horizontal velocity after 2 seconds will also be 40/√2 m/s

Since √2 = 1.41:

Horizontal velocity = 28.3 m/s

Vertical Velocity:

v = u + at                            [First equation of motion]

v = 40/√2 + (-10)(2)          

[g is negative because it is acting against the direction of motion]

v = 40/√2 - 20

v = \(\frac{40-20\sqrt{2} }{\sqrt{2} }\)                          [taking the LCM]

v = 8.28 m/s                    [√2 = 1.41]

a golf ball with a velocity 40 at an angle 45 degree speed of bthe ball after 2 sec

As shown in the figure below, Justin walks from the house to his truck on a windy day. He walks 20 m toward
the truck, 15 m back to retrieve his wind-blown hat, and another 20 m to reach the truck. He walked a total
time of 75 s.
What is Justin’s average velocity over the 75 s period? What is Justin’s average speed over the 75 s period?
Round answers to two significant digits.
Answer using coordinate system where rightward is positive.

Answers

Complete Question

The complete question is shown on the first uploaded image

Answer:

The velocity is   \(v =0.333 \  m/s \) in positive x -direction

The speed is \(s = 0.733 \ m/s\)

Explanation:

From the question we are told that

The distance from the house to truck is  D =  20 m

  The distance traveled back to retrieve  wind-blown hat is  d =  15

  The distance from the wind-blown hat position too the truck is  k =  20  m

  The total time taken is  t  =  75 s

Generally when calculating the displacement the Justin's backward movement to collect his wind - blown hat is taken as negative

Generally Justin's displacement is mathematically represented as

      \(L = 20 - 15 + 20\)

=>    \(L  =  25 \ m \)

Generally the average velocity is mathematically represented as

          \(v = \frac{L}{t}\)

=>      \(v = \frac{25}{75}\)

=>      \(v =0.333 \  m/s \)

Generally the distance covered by Justin is mathematically represented as  

         \(R = D+ d + k\)

=>      \(R = 20 + 15 +20\)

=>     \(R =  55 \  m \)

Generally Justin's average speed over a 75 s period is mathematically represented as

            \(s = \frac{R}{ t}\)

=>         \(s = \frac{55}{ 75}\)

=>        \(s = 0.733 \ m/s\)

As shown in the figure below, Justin walks from the house to his truck on a windy day. He walks 20 m

5.40×10^21 electrons flow through another appliance in 3.0 minutes.
What is the current drawn by this appliance?

Answers

The current drawn by the appliance is 0.048 A.

The problem provides the number of electrons that flow through an appliance and the time it takes for the flow to occur. To find the current drawn by the appliance, we need to use the equation:

current = charge / time

The charge is the total number of electrons that flowed through the appliance, which can be calculated by multiplying the given number of electrons by the charge on one electron (\(-1.6 \times 10^{-19}\) Coulombs).

charge = (\(5.40 \times 10^{24}\) electrons) × (\(-1.6 \times 10^{-19}\) C/electron) = -8.64 C

Note that the charge is negative because electrons have a negative charge.

The time is given as 3.0 minutes, but we need to convert it to seconds to match the unit of charge.

time = 3.0 minutes × 60 seconds/minute = 180 seconds

Now, we can plug in the values into the equation:

current = (-8.64 C) / (180 s) = -0.048 A

The current is negative because the charge is negative, which indicates that the current direction is opposite to the conventional current flow direction (i.e., the direction of positive charge flow). To express the current in the conventional direction, we need to take the absolute value:

current = 0.048 A

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10. Based on the current position of the continents, South America is moving away from
Africa in what direction?
A. West
C. North
B. East
D. South

Answers

Answer:

D

Explanation:

bexause south jnshdbsjsvhhhgvvvbbhhhhbbbvgj ghbvkbBBCfjnbbcgn. gxb NBCxbncc gcbnbyd vvvv b jb jbhhhhhvvhbvvhjjnnjj,jzjsjdndjjshshdjsbddvdusvusgavahmmsbyurdvsbsjsiwjSCjDHLseekscoopDJxxvisoscoopxxviwellAbbistopDHLshopgogogogotoFL

The net force on a box F as a function of the vertical position y is shown below.
What is the work done on the box from y=0 to 6.0m?

The net force on a box F as a function of the vertical position y is shown below.What is the work done

Answers

The work done on the box from y=0 to 6.0m is 120 J.

To calculate the work done on the box from y=0 to 6.0m, we need to find the area under the force vs. position graph over that interval.

First, we can find the work done from 0 m to 2 m. Since the force is constant at 40 N over this interval, the work done is simply:

W = F * d = 40 N * 2 m = 80 J

From 2 m to 6 m, the force is constant at -20 N, so the work done is:

W = F * d = (-20) N * 4 m = -80 J

Note that the negative sign indicates that the work is done by the box on the force (since the force is in the opposite direction of the displacement).

Therefore, the total work done on the box from y=0 to 6.0m is:

W_total = 80 J - 80 J = 0 J

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. A 5cm tall object is placed perpendicular to the principal axis of a convex lens of focal
length 10 cm. The distance of the object from the lens is 15 cm. Find the nature, position
and size of the image. Also find its magnification

Answers

The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.

Given:

Object height (h) = 5 cm

Focal length of the convex lens (f) = 10 cm

Object distance (u) = 15 cm (positive since it's on the same side as the incident light)

To determine the nature, position, and size of the image, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the given values:

1/10 = 1/v - 1/15

To simplify the equation, we find the common denominator:

3v - 2v = 2v/3

Simplifying further:

v = 30 cm

The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.

To find the magnification (M), we use the formula:

M = -v/u

Substituting the values:

M = -30 / 15 = -2

The magnification is -2, indicating that the image is inverted and twice the size of the object.

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A proton moving along the x axis has an initial velocity of 4.0 × 106 m/s and a constant acceleration of 6.0 × 1012 m/s2. What is the velocity of the proton after it has traveled a distance of 80 cm? Group of answer choices

Answers

Answer:

5.06*10^6 m/s

Explanation:

Given that

Initial velocity, u = 4*10^6 m/s

Acceleration, a = 6*10^12 m/s²

Distance traveled, s = 80 cm

Final velocity, v = ?

We can find the final velocity by using one of the equations of motion.

v² = u² + 2as

On substituting the values, we have

v² = (4*10^6)² + 2 * 6*10^12 * 0.8

v² = 2.56*10^13

v = √2.56*10^13

v = 5.06*10^6 m/s

Therefore, the final velocity of the proton is adjudged to be 5.06*10^6 m/s

The final velocity of the proton over the given distance is \(5.06 \times 10^6 \ m/s\).

The given parameters;

initial velocity of the proton, u = 4 x 10⁶ m/sacceleration of the proton, a = 6 x 10¹² m/s²distance traveled by the proton, s = 80 cm = 0.8 m

The final velocity of the proton over the given distance is calculated as follows;

\(v^2 = u^2 + 2as\\\\v^2 = (4\times 10^6)^2 \ + \ 2(6.0 \times 10^{12})(0.8)\\\\v^2 = 2.56 \times 10^{13} \\\\v = \sqrt{2.56 \times 10^{13} } \\\\v = 5.06 \times 10^6 \ m/s\)

Thus, the final velocity of the proton over the given distance is \(5.06 \times 10^6 \ m/s\)

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select the correct sketch of the electric field of a quadrupole, two positive and two negative charges arranged as in (figure 1).

Answers

From the given figure of the quadrupole, it is seen that option A is correct. In an electric circuit, charges move from the negative pole (terminal) to the positive pole (terminal) of a battery or power source.

What is a quadrupole?

In physics, a quadrupole is a type of electric or magnetic field with a specific configuration of poles or charges. A quadrupole consists of two sets of charges or poles that are aligned in opposite directions, with each set having two charges or poles of equal magnitude but opposite signs. The charges or poles can be either electric or magnetic, and they are separated by a fixed distance. Quadrupoles can be used to manipulate charged particles, such as ions, in various applications, including mass spectrometry, particle accelerators, and ion traps. In particular, quadrupole mass spectrometry is a widely used technique in analytical chemistry and biochemistry for identifying and quantifying small molecules and biomolecules.

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there are two formulas I don't know which one it is
m1v1 + m2v2 = m1v1 + m2v2
m1v1 + m2v2 = (m1 + m2) vf

Tom is running at 6.0 m/s to the east. He collides with Jerry (mass = 84 kg), who was moving west at 4.0 m/s. Tom grabs hold of Jerry and the two move together at 0.72 m/s to the east. What is Tom’s mass?

Answers

Tom's mass is 75.1 kg

The law of conservation of momentum

This is the law of conservation of momentum which states that the initial and final momentum are the same.

The required equation

Since Tom grabs hold of Jerry after the colision, both stick together. So, we use the second equation.

m₁v₁ + m₂v₂ = (m₁ + m₂)vf where

m₁ = Tom's mass, v₁ = Tom's velocity = + 6.0 m/s (since he is moving to the east), m₂ = Jerry's mass = 84 kg, v₂ = Jerry's velocity = -4.0 m/s (negative since he is moving to the west) and vf = their final velocity = 0.72 m/s

Since we require Jerry's mass, we make m₁ subject of the formula.

So, m₁v₁ + m₂v₂ = (m₁ + m₂)vf

m₁v₁ + m₂v₂ = m₁vf + m₂vf

m₁v₁ - m₁vf = m₂vf - m₂v₂

m₁(v₁ - vf) = m₂(vf - v₂)

The equation for Tom's mass

m₁ = m₂(vf - v₂)/(v₁ - vf)

Substituting the values of the variables into the equation, we have

m₁ = m₂(vf - v₂)/(v₁ - vf)

m₁ = 84 kg(0.72 m/s - [-4.0 m/s])/(6.0 m/s - 0.72 m/s)

m₁ = 84 kg(0.72 m/s + 4.0 m/s)/(6.0 m/s - 0.72 m/s)

m₁ = 84 kg(4.72 m/s)/(5.28 m/s)

m₁ = 396.48 kgm/s ÷ 5.28 m/s

m₁ = 75.09 kg

m₁ ≅ 75.1 kg

So, Tom's mass is 75.1 kg

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a metal ion (x) with a charge of 3= is attracted to a normal ion (z) with a charge of 4- which of these formulas represents the resulting comppound

Answers

If the metal ion has a 3+ charge and the nonmetal ion has a 4- charge, the formula of the compound is X4Z3.

What is the formula of a compound?

The formula of an ionic compound is determined by the charges of the ions that make up the compound. Recall that when the compound is  formed, the ions exchange valences.

Hence, is the metal ion has a 3+ charge and the nonmetal ion has a 4- charge, the formula of the compound is X4Z3.

Missing parts:

A metal ion (X) with a charge of 3+ is attracted to a nonmetal ion (Z) with a charge of 4-. Which of these formulas represents the resulting compound.

A. 7XZ

B. X3Z4

C. X4Z3

D. 4X3Z

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a bicycle wheel with a radius of 30 cm and 16 spokes that is mounted with its axle fixed in a horizontal position. A 50-g mass is hung from a string wrapped around the periphery of the tire. The wheel is held stationary with the weight hanging as shown and then released. The wheel starts to spin and spins faster and faster until the string slips off 5 seconds after release.
What is the acceleration of the hanging mass (in m/s2) while the wheel's speed is increasing?

Answers

The acceleration of the hanging mass while the wheel's speed is increasing is 5,625 m/s².

What is acceleration?

Acceleration is a vector quantity that measures the rate of change of an object's velocity. It is defined as the rate at which an object's velocity changes over time. Acceleration can be positive, negative, or zero. Acceleration can be caused by forces such as gravity, friction, or thrust.

The acceleration of the hanging mass is determined by the torque (τ) and the moment of inTherefore, the acceleration of the hanging mass can be calculated as a = τ/I = (F×r)/(mr²) = F/(mr). In this case, F = 50 g, r = 30 cm and m = 16 spokes. We can convert the mass from grams to kilograms by dividing by 1000, giving us m = 0.016 kg.

Plugging these values into the equation, we get a = 50/(0.03×0.016) = 5,625 m/s².

Therefore, the acceleration of the hanging mass while the wheel's speed is increasing is 5,625 m/s².

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Given the functions f(x)=(1/x-3)+1 and g(x) = (1/1+4)+3
Which statement describes the transformation of the graph of function f onto the graph of function g?
O The graph shifts 2 units right and 7 units down.
O The graph shifts 7 units left and 2 units up.
O
e graph shifts 7 units right and 2 units down.
O The graph shifts 2 units left and 7 units up.

Given the functions f(x)=(1/x-3)+1 and g(x) = (1/1+4)+3Which statement describes the transformation of

Answers

The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.

To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.

The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.

The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.

By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:

The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.

The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.

The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.

Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.

Hence, the correct statement is: The graph shifts 2 units right and 7 units down.

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Can someone answer all of the questions?

Answers

Answer: -200

Explanation: is it math

The graph below shows the motion of a person leaving a theater. Three segments of their journey have been identified as A, B, and C.

What does line segment C represent?

The person is moving away from the theater.
The person is standing still.
The person is moving closer to the theater.
The person is slowing down.

The graph below shows the motion of a person leaving a theater. Three segments of their journey have

Answers

The graph below shows the motion of a person leaving theater, line segment C represent : The person is moving away from the theater.

What is meant by motion?

In physics, motion is a change with time of the position or orientation of a body. Motion along a line or a curve is called as translation whereas motion that changes orientation of a body is called rotation.

Motion is a change in position of an object over the  time and is described in terms of displacement, distance, velocity, acceleration, time and speed.

Change in position of a body with time when compared with another body is known as  motion.

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A cart rolls 2 m to the right then rolls back 1 m to the left.
a. What is the total distance rolled by the cart?

Answers

Explanation:

It is given that,

Distance covered by the cart to the right is 2 m

Distance covered by the cart to the left is 1 m

We need to find the total distance rolled by the cart. Total distance is equal to the sum of the distances covered by an object. It does depend on the direction.

Total distance = 2 m + 1 m

D = 3 m

The cart rolled to a total distance of 3 m.

What is the main difference between analog anddigital technology?a. Digital technology reproduces sound more faithfullythan analog technology.b. Analog technology stores information as soundwaves; digital technology stores it as strings of onesand zeroes.c. Analog technology can be used to record sound andimages; digital technology can only be used to recordsound.d. Analog technology is based on binary code; digitaltechnology is based on electromagnets

Answers

Answer:

Answer b)

Explanation:

The correct answer is that analog technology stores information as sound-waves, while digital technology stores it as strings of ones and zeroes. So pick answer b)

The rainbow of visible colors in the electromagnetic spectrum varies continuously from the longest wavelengths (the reddest colors) to the shortest wavelengths (the deepest violet colors) our eyes can detect. Wavelengths near 655 nm are perceived as red. Those near 515 nm are green and those near 475 nm are blue. Calculate the frequency of light (in Hz) with a wavelength of 655 nm, 515 nm, and 475 nm.

The rainbow of visible colors in the electromagnetic spectrum varies continuously from the longest wavelengths

Answers

The frequency of light with a wavelength of 655 nm is\(4.57 x 10^14 Hz\) and 515 nm is \(5.82 x 10^14\) Hz and  475 nm is\(6.31 x 10^14 Hz\)

The equation that links the speed of light to wavelength and frequency is

c = λν

Where, c = speed of lightλ = wavelengthν = frequency c is a constant of 2.998 x 10^8 m/s.

Calculating the frequency of light with a wavelength of

655 nm:λ = 655 nm = \(6.55 x 10^-7m\)

Using the above equation, we get

c = λνν = c/λ = \((2.998 x 10^8 m/s)/(6.55 x 10^-7m)ν = 4.57 x 10^14 Hz\)

Therefore, the frequency of light with a wavelength of 655 nm is 4.57 x \(10^14 Hz.\)

Calculating the frequency of light with a wavelength of 515 nm:λ = 515 nm = \(5.15 x 10^-7m\)

Using the above equation, we get

c = λνν = c/λ =\((2.998 x 10^8 m/s)/(5.15 x 10^-7m)ν = 5.82 x 10^14 Hz\)

Therefore, the frequency of light with a wavelength of 515 nm is 5.82 x \(10^14 Hz\).

Calculating the frequency of light with a wavelength of 475 nm:λ = 475 nm = \(4.75 x 10^-7\)m Using the above equation, we get

c = λνν = c/λ = \((2.998 x 10^8 m/s)/(4.75 x 10^-7m)ν = 6.31 x 10^14 Hz\)

Therefore, the frequency of light with a wavelength of 475 nm is 6.31 x \(10^14 Hz.\)

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A 3.0 kg block (mass 1) and a 3.8 kg block (mass 2) are connected by a light string as shown; the inclination of the ramp is 40°. Friction is negligible. What is (a) the acceleration of each block and (b) the tension in the string (hint: for part "a", find Wx' for mass 1, using a tilted coordinate system, to get the "leftward" pull, and for the "rightward" pull due to mass 2, use it's full weight; then divide by their total mass)?

Answers

The tension in the string is 32.6 N. Tension is the force transmitted by the rope or cable to the object, supporting it against gravity.

What is Tension?

Tension is a pulling force transmitted through a rope, cable, wire, or similar object when it is pulled tight by forces acting from opposite ends. It is a reactive force and is directed along the length of the wire, rope, or cable.

Since friction is negligible, the only forces acting on the system are the force of gravity and the tension in the string. To solve for the acceleration and tension, we need to apply Newton's second law to each block separately.

(a) Acceleration of each block:

For mass 1:

Since the block is accelerating up the ramp, the net force acting on the block in the x-direction is T - mg sin(40°).

According to Newton's second law, F = ma, we can set up the following equation:

T - mg sin(40°) = ma1

For mass 2:

According to Newton's second law, F = ma, we can set up the following equation:

mg sin(40°) - T = ma2

where a2 is the acceleration of mass 2.

To solve for the accelerations, we can use the fact that the tension in the string is the same for both blocks:

T = ma1 + mg sin(40°)

T = mg sin(40°) - ma2

Setting these two equations equal to each other and solving for a, we get:

ma1 + mg sin(40°) = mg sin(40°) - ma2

ma1 + ma2 = g sin(40°)

a = (g sin(40°)) / (m1 + m2)

a = (9.81 m/\(s^{2}\)) sin(40°) / (3.0 kg + 3.8 kg) = 1.21 m/\(s^{2}\)

Therefore, the acceleration of each block is 1.21 m/\(s^{2}\).

(b) Tension in the string:

To solve for the tension, we can use either of the two equations we derived earlier for the tension in the string. Using the equation for mass 1:

T = ma1 + mg sin(40°)

T = (3.0 kg)(1.21 m/\(s^{2}\)) + (3.0 kg)(9.81 m/\(s^{2}\)) sin(40°)

T = 32.6 N

Therefore, the tension in the string is 32.6 N.

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When does a rubber band, which has been shot at a wall, have the most potential energy?
A When it is lying on the floor.
B When it is flying across the room.
C When it hits the wall.
D When it is stretched ready to shoot at the wall.

Answers

D When it is stretched ready to shoot at the wall

Answer:

C because that requires lots of energy

Suppose a radio signal (light) travels from Earth and through space at a speed of 3 × 10^8/ (this is the speed of light in vacuum). How far (in meters) into space did the signal travel during the first 10 minutes?

Answers

Answer:

Explanation:

we know that

s=vt here v is the speed and s is distance covered by the signals

given data

v=3*10^8

t=10 min we have to convert it into seconds

1 minute=60 seconds

so

10 minutes =10*60/1 =600 seconds

now putting the value of v and t we can find the value of s

s=vt

s=3*10^8*600

s=1.8*10^11m

i hope this will help you

Speed is the rate of distance over time.

The signal will travel \(1.8 \times 10^{11}\) meters in the first 10 minutes

The given parameters are:

\(s = 3 \times 10^8\ ms^{-1}\) ---the speed of light

\(t = 10\ min\) -- the time of travel

The relationship between speed, distance (d) and time is:

\(s = \frac dt\)

Make d the subject

\(d = s \times t\)

Substitute values for t and s

\(d = 3 \times 10^8\ ms^{-1} \times 10\ min\)

Convert minutes to seconds

\(d = 3 \times 10^8\ ms^{-1} \times 10 \times 60s\)

So, we have:

\(d = 3 \times 10^8\ m \times 10 \times 60\)

\(d = 18 \times 10^{10}m\)

Rewrite as:

\(d = 1.8 \times 10^{11}m\)

Hence, the signal will travel \(1.8 \times 10^{11}\) meters in the first 10 minutes

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A sled that has a mass of 8 kg is pulled at a 50 degree angle with a force of 20 N. The force of friction acting on the sled is 2.4 N. The free-body diagram shows the forces acting on the sled. A free body diagram with 4 force vectors. The first vector is pointing downward, labeled F Subscript g Baseline. The second vector is pointing up to the right at an angle of 50 degrees, labeled F Subscript p Baseline. The third vector is pointing upward, labeled F Subscript N Baseline. The fourth vector is pointing left, labeled F Subscript f Baseline. The up and down vectors are the same length. The right vector is longer than the left vector. What is the acceleration of the sled and the normal force acting on it, to the nearest tenth? a = 1.3 m/s2; FN = 63.1 N a = 1.6 m/s2; FN = 65.6 N a = 1.9 m/s2; FN = 93.7 N a = 2.2 m/s2; FN = 78.4 N

Answers

The acceleration of the sled will be 1.30 m/s². Force is defined as the product of mass and acceleration.

What is force?

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Given data;

m(mass of sled)=8 kg

Θ is the inclination of force= 50°

Force of friction,f=2.4 N.

The applied force at the given angle is resolved into the two-component as;

\(\rm F_h=F cos \theta \\\\ F_h= 20 cos 50 ^0 \\\\ F_h= 12.85 \ N\)

\(\rm F_v=F sin \theta \\\\ F_v=20 sin 50^0 \\\\ F_v=15.32 \ N\)

The net vertical force is zero;

\(\rm F_N=mg-Fsin50^0 \\\\ \rm F_N=8 \times 9.81 -15.32 \\\\ F_N=63.1 \ N \\\\\)

From Newton's second law the net force as;

\(\rm \sum F_{net}=ma \\\\ Fcos 60^0-f =ma \\\\ a=\frac{12.855-2.4}{8} \\\\a = 1.30 \ m/s^2\)

Hence, the acceleration of the sled will be 1.30 m/s².

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Answer:

1) a = 1.3 m/s2; FN = 63.1 N

Explanation:

Edg 2022:)

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