The molecular formula mass of this compound is 240 amu. What are the subscripts in the actual molecular formula?.

Answers

Answer 1

To calculate the subscripts in the actual molecular formula, we first have to find out the empirical formula of the given compound. Empirical formula mass is the sum of the atomic masses of all the atoms in a formula unit of the empirical formula of a compound.

To calculate the empirical formula mass, we add up the atomic masses of all the atoms present in a molecule of a compound. Using the molecular formula mass and empirical formula mass, we can calculate the actual molecular formula of the compound. The subscripts in the actual molecular formula are calculated by dividing the molecular formula mass of the compound by the empirical formula mass of the compound. Let's consider an example to understand how to calculate the subscripts in the actual molecular formula.

Example:

The empirical formula of a compound is CH2O, and the molecular formula mass of the compound is 180 amu. The empirical formula mass can be calculated using the formula:

Empirical formula mass = sum of atomic masses of atoms in the empirical formula

= (1 × atomic mass of C) + (2 × atomic mass of H) + (1 × atomic mass of O)

= (1 × 12.01 amu) + (2 × 1.01 amu) + (1 × 16.00 amu)

= 30.03 amu

Molecular formula mass = 180 amu

Now, we can calculate the ratio of the molecular formula mass to the empirical formula mass as:

180 amu ÷ 30.03 amu

= 6

The actual molecular formula will have six times the number of atoms as the empirical formula: C6H12O6. Therefore, the subscripts in the actual molecular formula of the compound are C6H12O6.

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Answer 2
Final answer:

The subscripts of a molecular formula, where its mass is known, can only be determined when the elements in the compound are specified. The subscripts in this case are the ratios of these elements. Without these, one can only give hypothetical answers, like a carbon dioxide compound repeated five times which gives subscripts of 5 (C5O10).

Explanation:

To deteremine the subscripts in the actual molecular formula, one first needs to know the formula of the compound itself. Without knowing the elements in the compound, we cannot ascertain the subscripts from the molecular formula mass. For example, if the compound is carbon dioxide (CO2), and knowing that the molecular mass of carbon (C) is approximately 12 amu and oxygen (O) is 16 amu, we know that two oxygens (16 * 2) with one carbon (12) has a total mass of 44 amu. Repeating this compound 5 times (as 240 is 5 times 44) would imply, in this hypothetical case, subscripts of 5, making the compound C5O10 . However, to get actual subscripts we need specifics about the compound's elements.

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Related Questions


Beryllium is in Group 2.
What does this tell you about the electronic structure of beryllium?

Answers

Answer:

[He] 2s²

Explanation:

How is the process of converting kiwi into plasticware evidence of a chemical reaction?.

Answers

Chemical reaction to biomass, like kiwi, into synthetic materials, like plastic, impact society because kiwi is biodegradable but plastic is not.

The series of chemical reactions used to change natural resources into synthetic products is termed chemical synthesis. Synthetic materials are formed when humans mix substances together for the purpose of creating new materials with desirable properties. Synthetic materials are produced by chemically changing the initial substances to create some material with different characteristics. Some of the best examples of synthetic materials are plastics and medicines. A synthetic substance may or may not be chemically identical to a naturally-occurring substance.

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What is the volume in liters that is needed to create a 0.5 M solution with 4.9 moles of Fe(OH)2? Round your answer to 1 decimal.

Answers

Answer:

\(0.5\: moles\: occupies \: 1 \: litre \\ 4.9 \: moles \: will \: occupy \: ( \frac{4.9}{0.5} ) \: moles \\ = 9.8 \: litres\)

The reusable booster rockets of the U.S. space shuttle employ
a mixture of aluminum and ammonium perchlorate for fuel. A
possible equation for this reaction is
3Al1s2 1 3NH4ClO4 1s2 h

Al2O3 1s2 1 AlCl3 1s2 1 3NO1g2 1 6H2O1g2
What mass of NH4ClO4 should be used in the fuel mixture for
every kilogram of Al?

Answers

The mass of NH₄ClO₄ needed to react for every kilogram of Al is 4.351 Kg

Balanced equation

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

3Al + 3NH₄ClO₄ -> Al₂O₃ + AlCl₃ + 3NO + 6H₂O

Molar mass of Al = 27 g/mol

Mass of Al from the balanced equation = 3 × 27 = 81 g = 81 / 1000 = 0.081 Kg

Molar mass of NH₄ClO₄ = 117.5 g/mol

Mass of NH₄ClO₄ from the balanced equation = 3 × 117.5 = 352.5 g = 352.5 / 1000 = 0.3525 Kg

SUMMARY

From the balanced equation above,

0.081 Kg of Al reacted with 0.3525 Kg of NH₄ClO₄

How to determine the mass of NH₄ClO₄ needed to react with 1 Kg of Al

From the balanced equation above,

0.081 Kg of Al reacted with 0.3525 Kg of NH₄ClO₄

Therefore,

1 Kg of Al will react with = (1 × 0.3525) / 0.081 = 4.351 Kg of NH₄ClO₄

Thus, 4.351 Kg of NH₄ClO₄ is needed for the reaction.

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what is the change in ph when 0.30 liters of 0.020 m koh is added to a 1.0-liter solution containing 0.25 m hf and 0.78 m naf (ka for hf is 7.2 10–4)?

Answers

The change in pH resulting from the addition of 0.30 liters of 0.020 M KOH to the solution containing 0.25 M HF and 0.78 M NaF is approximately -0.614.

First, we need to determine the initial concentrations of HF and F⁻ in the 1.0-liter solution. The concentration of HF is given as 0.25 M, and the concentration of NaF can be used to determine the concentration of F⁻ since NaF is a strong electrolyte and will fully dissociate in solution. Therefore, the concentration of F⁻ is 0.78 M.

Next, we need to consider the reaction between KOH and HF:

KOH + HF ⟶ H2O + KF

The reaction between KOH and HF is a neutralization reaction. For every 1 mole of KOH added, 1 mole of HF will react to form 1 mole of water and 1 mole of KF. Since we know the initial volume of KOH added is 0.30 liters and the concentration of KOH is 0.020 M, we can calculate the number of moles of KOH added:

moles of KOH = volume × concentration = 0.30 L × 0.020 M = 0.006 moles

Therefore, 0.006 moles of HF will react with 0.006 moles of KOH, resulting in the formation of 0.006 moles of water and 0.006 moles of KF.

Now, we can calculate the new concentrations of HF and F⁻. The initial concentration of HF was 0.25 M, and we subtract 0.006 moles from it, which corresponds to the moles of HF that reacted with KOH. The volume of the solution is still 1.0 liter. Thus, the new concentration of HF is:

new concentration of HF = (0.25 moles - 0.006 moles) / 1.0 L = 0.244 M

For F⁻, the initial concentration was 0.78 M, and we add 0.006 moles to it, which corresponds to the moles of F⁻ formed from the reaction. The volume of the solution is still 1.0 liter. Thus, the new concentration of F⁻ is:

new concentration of F⁻ = (0.78 moles + 0.006 moles) / 1.0 L = 0.786 M

To calculate the change in pH, we need to consider the dissociation of HF and the equilibrium expression for the acid dissociation constant (Ka):

HF + H₂O ⇌ H₃O⁺ + F⁻

The Ka expression is given by:

Ka = [H₃O⁺][F⁻] / [HF]

Since HF is a weak acid, we assume that the concentration of [H₃O⁺] is equal to the concentration of [HF]. Therefore, the expression simplifies to:

Ka = [F⁻] / [HF]

Plugging in the values:

Ka = (0.786 M) / (0.244 M)

Solving this expression gives the Ka value. Then, we can use the Ka value to calculate the pH using the equation:

pH = -log[H₃O⁺]

To calculate the numerical values, we need to determine the new concentrations of HF and F⁻ after the reaction with KOH.

Initial concentration of HF: 0.25 M

Moles of HF reacting with KOH: 0.006 moles

New concentration of HF = (0.25 moles - 0.006 moles) / 1.0 L = 0.244 M

Initial concentration of F⁻: 0.78 M

Moles of F- formed from the reaction: 0.006 moles

New concentration of F⁻ = (0.78 moles + 0.006 moles) / 1.0 L = 0.786 M

Now, we can calculate the Ka value using the concentrations of HF and F⁻:

Ka = [F⁻] / [HF] = 0.786 M / 0.244 M = 3.2131

Using the Ka value, we can calculate the pH. Since HF is a weak acid, we assume that the concentration of [H₃O⁺] is equal to the concentration of [HF]:

pH = -log[H₃O⁺] = -log[HF] = -log(0.244) ≈ 0.614

Therefore, the change in pH resulting from the addition of 0.30 liters of 0.020 M KOH to the solution containing 0.25 M HF and 0.78 M NaF is approximately -0.614.

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the inital concentration of ractant in a first-order reaction is 0.27m the concentration aftr 1.5s is 8.8 x 10^-2 m what is the half life for this reaction

Answers

0.753 is the half life for this reaction.

For First order reaction.

K = 2·303 log t the inital concentration of in a first-order reaction is 0.27m the concentration 1.5s is 8.8 x 10^-2 m.

where K → rate constant t → time Ao Initial concentration At Concentration after time t

half life period → when half of the reaction is completed x = 9/2 Representing the time taken

for half life of the reaction to be completed by equation becomes,

T1/2 =  2·303 / K log 2

T1/2 = 0.693 / K log 2

0.92 = 0.693 / K

K=0.753

A_{t} = (0.27m)/3109

Concentration of reactant after 1.5 seconds

At = 0.087mel / L

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Which element is likely to react violently with water?
a) carbon
b) beryllium
c) cesium
d) sulfur

Answers

I think the answer is beryllium.

because it's not sulfur or carbon and probably not cesium

Calculate the pOH of a 7.68x10-7 M HCl solution.


pOH = (round to 3 sig figs)

Answers

Answer:

pOH = 7.89

Explanation:

As HCl is a strong acid, [H⁺] is equal to the original acid concentration. In other words:

[H⁺] = 7.68x10⁻⁷ M

Knowing [H⁺], we calculate the pH of the solution:

pH = -log[H⁺]pH = 6.11

With the pH, we can calculate the pOH of the solution, using the following formula:

pOH = 14 - pHpOH = 7.89

Ethylene glycol (antifreeze) has a density of 1.11 g/cm3. What is the mass in grams of 355 mL of ethylene glycol?

Answers

Density=1.11g/mLVolume=355mL

\(\\ \bull\tt\leadsto Density=\dfrac{Mass}{Volume}\)

\(\\ \bull\tt\leadsto Mass=Density\times Volume\)

\(\\ \bull\leadsto Mass=1.11(355)\)

\(\\ \bull\leadsto Mass=394.05g\)

during the cell cycle, compounds called cyclins increase and decrease in a regular pattern. what is the role of cyclins?

Answers

During the cell cycle, compounds called cyclins increase and decrease in a regular pattern. They regulate the stages of cell division and growth.

Cell cycle development is regulated in element by way of the sequential pastime of various cyclins. The cyclins are regulatory subunits that bind, prompt and provide substrate specificity for their catalytic companion serine-threonine kinases, collectively called cyclin-established kinases.

Cyclins are a family of proteins that don't have any enzymatic interest of their personal however spark off CDKs through binding to them.

S cyclins are involved inside the induction of DNA replication and early stages of mitosis. Their stages upward push at the beginning of S phase and fall in early mitosis.

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why did mendeleev switch the order of some elements in his periodic table

Answers

Answer:

to keep the groups consistent.

Explanation:

* What element has an electron configuration of
1s2 2s2 2p6 3s2 3p6 4s2 and which block is it in? Use the periodic table.

Answers

Answer:

phosphorus

Explanation:

Work done when lifting up the water tank,give the water in the tank________ energy.

Answers

Answer:

Kinetic mechanical energy

Explanation:

The water was used to power a generator, creating electric energy.

Balance the following chemical equation
Mg + O₂ ​ → MgO

Answers

Answer:

2Mg + O₂ ​ → 2MgO

Explanation:

293939388728282992929

Lithium has an atomic number of 3 and an average atomic mass of 6.941. how many protons does lithium have in the nucleus? 3 3 4 4 6 6 10

Answers

Lithium has 3 protons in the nucleus.

Atomic number is the number of protons or the number of electrons in the nucleus of a neutral atom.Mass number is the sum of the protons as well as the neutrons in the nucleus of an atom. ( sum of neutrons and protons = nucleons)

Atomic number =number of protons =number of electrons

According to the question,

we have been given atomic number= 3

So, number of protons will be 3 and number of electrons will also be 3.

We can additionally calculate number of neutrons as follows-

number of neutrons= mass number - number of protons

                                   = 6.941 - 3

                                   ≈ 4

Hence, the number of protons in lithium will be 3.

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The nucleus of Lithium has three protons.

The number of protons or electrons in the nucleus of a neutral atom is known as its Atomic number.

The total mass of an atom's protons and neutrons is known as its mass number. (neutrons and protons added together Equals nucleons)

Atomic mass= Mass number + Neutrons

                                         

Atomic number equals the sum of the protons and electrons

Since, atomic number given is 3

Therefore, protons in the nucleus will be 3.

Additionally, we may determine the neutron number using the formula below.

mass number = number of neutrons + number of protons

⇒ 6.941 = number of neutrons + 3

⇒ number of neutrons will be approximately 4.

Thus, lithium will contain three protons.

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using ethanol as a solvent in today’s synthesis produces an ether as a side product. predict this product and propose a mechanism for its formation.

Answers

A molecule of ethanol takes up the proton to form the product.CH3CH2O−CH2CH3 + H+ → CH3CH2OH + CH3CH2O−Here, R represents an alkyl group, X represents a halogen, and H represents a hydrogen ion.

The product produced when using ethanol as a solvent in the synthesis is an ether. The mechanism proposed for its formation is a nucleophilic substitution reaction.The reaction can be represented as follows: R-OH + CH3CH2OH → R-O-CH2CH3 + H2OThe formation of the ether can be explained through the following steps: Step 1: The ethanol is deprotonated to form a strong nucleophile (ethoxide ion).CH3CH2OH + Na → CH3CH2O−Na+ + ½ H2Step 2: The nucleophilic ethoxide ion attacks the carbon atom of the alkyl halide, R-X, via nucleophilic substitution reaction. The result is the formation of an alkoxide ion (R-O−) and a halogen acid (HX).R−X + CH3CH2O− → R−O−CH2CH3 + X−Step 3: The reaction produces an ether molecule and a proton.

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4 (c) Aluminium is produced by electrolysis of a molten mixture of aluminium oxide and cryolite. This is shown in Figure 3.
Name a gas produced at the positive electrode. Gas forms at the positive electrode Aluminium forms at the negative electrode [1 mark]​

Answers

i’m not that smart in chem but i think it’s oxygen (O2)

When butter is melted, the _____________ of the butter has changed, but the substance is still butter?

Answers

melting of butter is a physical change

Explanation:

What is the name of Br6F10 ?

Answers

Answer:

Bromine fluoride

Which of the following is NOT a part of adenosine diphosphate?

glucose, ribose, adenine, two phosphate groups

Answers

Answer:

a. glucose c. ribose b. adenine d. two phosphate groups user: all organisms need energy to perform different functions. cells are able to ...

Mass is measured against a standard using a

Answers

Answer:

balance

Explanation:

Tin (II) oxide is placed into a bottle of hydrogen gas and a reaction occurs where metallic tin and water form:
Skeleton Equation:

Balanced Equation:

Answers

The skeleton equation of the reaction of Tin oxide and hydrogen:

\(SnO_2 + H_2\longrightarrow Sn + H_2O\)

Balanced equation:

\(SnO_2 + 2H_2\longrightarrow Sn + 2H_2O\)

What happened in the reaction of tin and water?

Tin (Sn) can be defined as an unreactive metal. When tin dioxide and hydrogen gas react with each other, metallic tin and water are formed.

Sn is not very reactive in comparison with the other elements in its own group, it is more reactive than Ge, which lies just above it in the group. It is unaffected by water or air at room temperature. Sn is anti-corrosive and therefore applied as a coating to protect metals.

When tin dioxide (SnO₂) is placed into a bottle of hydrogen gas. The balanced chemical equation for the chemical reaction is as follows:

\(SnO_2 + 2H_2\longrightarrow Sn + 2H_2O\)

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Substance P is soluble in water but insoluble in propanone.

Substance Q is insoluble in water but soluble in propanone.

Substance R is insoluble in both water and propanone.

Describe how to obtain a pure dry sample of each of P, Q, and R from a mixture of P+Q+R.

Answers

Divide:
35x³-25x4y³/5x²y²

How many grams of potassium oxide would be needed to produce 5.00 g of potassium nitrate (​KNO​3)​ ?

Answers

Answer:

Mass = 2.355 g

Explanation:

Given data:

Mass of K₂O needed = ?

Mass of KNO₃ produced = 5.00 g

Solution:

Solution:

K₂O + 2HNO₃     →     2KNO₃ + H₂O

Number of moles of KNO₃:

Number of moles = mass/molar mass

Number of moles = 5.00 g/ 101.1 g/mol

Number of moles = 0.05 mol

now we will compare the moles of KNO₃ and K₂O.

                 KNO₃           :             K₂O

                    2                :               1

                   0.05           :           1/2×0.05 = 0.025 mol

Mass of potassium oxide needed in gram:

Mass =  number of moles × molar mass

Mass = 0.025 mol × 94.2 g/mol

Mass = 2.355 g

difference between symbol and molecular formula​

Answers

A symbol represents an individual element, while a molecular formula represents the composition of a molecule.

A symbol is a shorthand representation of an element. It consists of one or two letters, typically derived from the element's name. Symbols are used to identify and represent individual atoms of elements. For example, "H" represents hydrogen, "C" represents carbon, and "O" represents oxygen. Symbols are often combined to form chemical formulas.

A molecular formula, on the other hand, represents the actual composition of a molecule. It provides the type and number of atoms present in a compound. Molecular formulas are used to describe the ratio of different atoms in a molecule.

They provide information about the number of atoms of each element in a compound. For example, the molecular formula of water is \(H_2O\), which indicates that a water molecule consists of two hydrogen atoms and one oxygen atom.

In summary, symbols represent individual elements, while molecular formulas represent compounds by indicating the types and numbers of atoms present in a molecule. Symbols are used to represent elements in the periodic table, while molecular formulas provide a concise representation of the composition of chemical compounds.

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Solve the problems. Express your answers to the correct number of significant figures.
(Image below)

Solve the problems. Express your answers to the correct number of significant figures.(Image below)

Answers

 Three significant figures in 2.31 and three in 0.790 2.31/0.790 = 2.92

  .  

2.) (2.08 × 10³) × (3.11 × 10²) = 6.468 800 000 × 10⁵  

      Three significant figures in 2.08 and three in 3.11.

Significant figures are the variety of digits in a value, frequently a dimension, that contribute to the degree of accuracy of the value. We begin counting widespread figures at the primary non-0 digit.

If a number expressing the end result of a dimension (e.g., duration, pressure, volume, or mass) has more digits than the quantity of digits allowed by way of the measurement decision, then most effective as many digits as allowed by means of the measurement decision are dependable, and so best those can be massive figures.

5 rules for significant figures include:-

* All non-zero numbers ARE substantial.

* Zeros among two non-0 digits ARE great.

* Leading zeros are not giant.

* Trailing zeros to the proper of the decimal are widespread.

* Trailing zeros in an entire quantity with the decimal proven are enormous.

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A physical change involves a change in the identity o the sample.
O True
O False

Answers

It is true because it changes the identity of a persin or a character

Explain the Law of Definite Proportions

Answers

Answer:

The law of definite proportions states that all pure samples of a particular chemical compound contain similar elements combined in the same proportion by mass.

The second law of chemical combination which is supported by the Atomic theory was proposed by Proust (1755-1826). Known as the Law of Definite Proportions or Constant Composition ,it is based on the fact that when elements combine to form a given compound , they do so in fixed proportions by mass so that all pure samples of that compound are identical in composition by mass.

Consider water for example . Chemical analyses showed that as long as it is pure, its composition is always in the ratio of one mole of oxygen molecules (i.e 32 g) to two moles of hydrogen molecules (i.e 4g) , irrespective of whether the water comes from the river , sea, rain ,wine ,saliva  or any other source .

Explanation:

A balloon containing helium gas has a volume of 2.44 L at room temperature 23 oC. The balloon is heated to a temperature of 78 oC. Assuming no change in pressure, what is the new

Answers

The new volume of the balloon when heated to 78 oC is approximately 2.89 L, assuming no change in pressure.

The volume of a gas is directly proportional to its temperature when pressure remains constant. This relationship is described by Charles's Law.

To find the new volume of the balloon after it is heated to 78 oC, we can use the formula:

(V1 / T1) = (V2 / T2)

where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume, and T2 is the final temperature.

Given:
Initial volume, V1 = 2.44 L
Initial temperature, T1 = 23 oC = 23 + 273.15 K = 296.15 K
Final temperature, T2 = 78 oC = 78 + 273.15 K = 351.15 K

We can plug these values into the formula and solve for V2:

(2.44 L / 296.15 K) = (V2 / 351.15 K)

Cross-multiplying:

(2.44 L) * (351.15 K) = (296.15 K) * (V2)

V2 = (2.44 L) * (351.15 K) / (296.15 K)

Calculating:

V2 ≈ 2.89 L

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The wall of the flask is periodically rinsed with the previously boiled, deionized water from the wash bottle. Does this titrimetric technique result in an increase, a decrease, or have no effect on the reported percent acetic acid in the vinegar

Answers

The titrimetric technique will have no effect on the reported percent acetic acid in vinegar despite periodically rinsing the wall of the flask with previously boiled, deionized water from the wash bottle.

Acetic acid is a common component in vinegar, which can be measured by titration. It is a quantitative chemical analysis method in which a solution of unknown concentration reacts with a standard solution of known concentration, typically until completion. It will cause the volume of the solution to be a slightly larger, and the concentration will be lowered when distilled or deionized water is added to the solution.

However, as long as the vinegar is measured against a known, unchanging standard, such as NaOH, the percent acetic acid reported in the vinegar would not change.

Rinsing the flask's walls with deionized water helps to ensure that the acetic acid reacts with the NaOH in the titration, and it reduces the risk of losing the NaOH and changing the final result. The volume of the vinegar sample used in the titration would be precisely measured, ensuring that the accurate amount of NaOH solution was used.

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