The original pressure of a gas was 2.5 atmospheres. When the pressure was decreased to 1.7 atmospheres, the volume increased to 850 mL. What was the original volume? Make sure that you show your work and use the proper units.

Answers

Answer 1

Taking into account the Boyle's law, the original pressure of a gas was 2.5 atmospheres and the original volume was 578 mL.

Boyle's law

Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant. This is because when the volume decreases, the distance that the particles have to travel is less and therefore more shocks occur in each unit of time, that is, the pressure increases.

Mathematically, if the amount of gas and the temperature remain constant, the product of the pressure and the volume always has the same value:

P×V= k

where:

P is the pressure.V is the volume.k is a constant.

Being an initial state 1 and a final state 2, it is fulfilled:

P₁×V₁= P₂×V₂

Original volume

In this case, you know:

P₁= 2.5 atmV₁= ?P₂= 1.7 atmV₂= 850 mL

Replacing in Boyle's law:

2.5 atm ×V₁= 1.7 atm ×850 mL

Solving:

V₁= (1.7 atm ×850 mL)÷ 2.5 atm

V₁= 578 mL

The original volume was 578 mL.

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Related Questions

Examine the Pythagorean theorem below. In this form you can find the length of the hypotenuse c) of a right triangle if you know the lengths of the two short sides (a &). Solve this equation for the short side b. If you need to indicate a square root in your answer, type it like this: root * (e + f) to mean the square root of the sum (e + f) . For example, the equation below can be typed as c = root (a^ ^ 2+b^ ^ 2)

Examine the Pythagorean theorem below. In this form you can find the length of the hypotenuse c) of a

Answers

Answer:

what is the number

Explanation:

From which type of clouds do hail pelets form

Answers

Answer:

Cumulonimbus

Explanation:

because Ideal conditions for hail formation are very high clouds with intense updrafts, containing a large quantity of supercooled water (liquid water under 0°C) and with dust particles in the atmosphere.

Rainfall from a slow-moving thunderstorm was over 5 inches. This storm led to
the erosion of about 0.2 mm of soil from a field. Express this soil loss in Mg ha-1 (Ton/ha) if the bulk density
of the soil is 1.01 Mg m-3.

Please show your work!
a. 0.202 Mg/ha
b. 2.02 Mg/ha
c. 20.2 Mg/ha

Answers

The soil loss in  \(Mg ha^{-1}\) (Ton/ha) if the bulk density of the soil is 1.01  \(Mg m^{-3}\)  is option a. 0.202 Mg/ha.

For expressing the soil loss in \(Mg ha^{-1}\), need to convert the units appropriately. First, convert the soil loss from millimetres (mm) to meters (m) by dividing it by 1,000 (1 mm = 0.001 m). Thus, the soil loss is 0.0002 m.

Next, calculate the volume of soil lost per unit area (ha). The volume can be obtained by multiplying the soil loss (0.0002 m) by the area (ha). Since the bulk density of the soil is given as 1.01 \(Mg m^{-3}\), can convert the volume to mass by multiplying it by the bulk density.

Using the formula:

Soil loss (Mg ha-1) = Soil loss (m) × Bulk density (\(Mg m^{-3}\)) × Area (ha)

Substituting the values:

Soil loss (\(Mg ha-1\)) = 0.0002 m × 1.01 \(Mg m^{-3}\) × 1 ha

Calculating the result:

Soil loss (\(Mg ha-1\)) = 0.0002 × 1.01 = 0.000202 \(Mg ha-1\)

Therefore, the correct answer is option a. 0.202 Mg/ha.

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the deposits on a properly burning spark plug should be ____.

Answers

The deposits on a properly burning spark plug should be very little or none. A spark plug works as a sensor in an engine and the deposits indicate the overall health of the engine.

Deposits on a spark plug are often black, brown, or greyish in color. When the deposits are more, it may indicate that the engine is not running as efficiently as it should or that it has some problem causing the engine to misfire. If the engine is not running efficiently or is not burning fuel, it can cause the spark plug deposits to build up quickly. Therefore, it is important to keep the spark plugs clean and free from excessive deposits to ensure optimal engine performance.

The deposits on a properly burning spark plug should be very little or none. A spark plug works as a sensor in an engine and the deposits indicate the overall health of the engine.

When the spark plug is functioning properly, it burns off any fuel or oil that comes into contact with it during the combustion process. This results in very little or no deposit buildup on the spark plug. However, if the engine is not running efficiently, such as when it is misfiring or not burning fuel properly, it can cause the spark plug deposits to build up quickly.There are several types of deposits that can accumulate on a spark plug. Carbon deposits are typically black in color and are caused by incomplete combustion of fuel. Oil deposits, on the other hand, are typically brown or greyish in color and are caused by worn piston rings or valve seals, which allow oil to seep into the combustion chamber and burn with the fuel. Deposits can also indicate that the engine is running too hot, which can be caused by a malfunctioning cooling system or a lean air-fuel mixture.

A properly burning spark plug should have very little or no deposits. Excessive deposits can indicate that the engine is not running efficiently and may require maintenance or repair. It is important to keep the spark plugs clean and free from excessive deposits to ensure optimal engine performance.

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WILL GIVE BRAINLIEST & 25 POINTS!!! A container of water with an initial temperature of 90°C is placed in a room where the temperature is 20°C. Which of the following statements describes what happens to the water over the next several hours? Please explain.

Answers

Answer:

Based on the information provided, the following statement describes what happens to the water over the next several hours:

The water in the container gradually cools down toward the temperature of the room.

When a container of water with an initial temperature of 90°C is placed in a room with a lower temperature of 20°C, heat transfer occurs between the water and its surroundings. Heat naturally flows from a higher temperature to a lower temperature until equilibrium is reached.

In this case, since the initial temperature of the water is higher than the room temperature, the water will lose heat to the surroundings. This process is known as conduction, where heat is transferred from the water to the air molecules in the room. As a result, the water's temperature decreases gradually.

The rate of cooling depends on factors such as the volume and surface area of the water, the thermal conductivity of the container, and the temperature difference between the water and the room. Over time, the water's temperature will approach and eventually reach the temperature of the room (20°C) as it continues to lose heat to the surrounding environment.

It's important to note that without additional information about the insulation of the container, the specific properties of the water, or the duration of the process, it is difficult to determine the exact rate of cooling or the specific timeline for the water to reach equilibrium with the room temperature.

Answer:

The water will lose heat to the surroundings and its temperature will decrease.

Explanation:

When a container of water with an initial temperature of 90°C is placed in a room where the temperature is 20°C, the water will lose heat to the surroundings and its temperature will decrease until the water becomes the same, if not, almost the same temperature as its surroundings.

when two or more cars arrive at an intersection at approximately the same time, who goes first?

Answers

When two or more cars arrive at an intersection at approximately the same time, the general rule is that the car on the right has the right of way.

However, if the cars are directly across from each other and there is no clear right or left, then the car that is already in the intersection has the right of way. In situations where there is still confusion, it is always best to proceed with caution and communicate with other drivers to ensure a safe and orderly flow of traffic.
When two or more cars arrive at an intersection at approximately the same time, the question of "who goes first?" depends on several factors.
1. Check for traffic signs or signals: Follow the rules indicated by stop signs, yield signs, or traffic signals to determine the right of way.
2. Right of way at a four-way stop: If it is a four-way stop, the first car to come to a complete stop has the right to proceed. If multiple cars stop at the same time, the car furthest to the right has the right of way.
3. Right of way at a T-intersection: If it is a T-intersection (three-way stop), the car on the through road has priority over the car on the terminating road.
Remember, always prioritize safety and ensure all drivers are aware of their turn before proceeding through the intersection.

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Example 2.3 The moon is observed from
two diametrically opposite points A and B
on Earth. The angle o subtended at the
moon by the two directions of observation
is 1°54'. Given the diameter of the Earth to
be about 1.276 x 107 m, compute the
distance of the moon from the Earth.​

Answers

Explanation:

you can see this example to undersranding the question

Example 2.3 The moon is observed fromtwo diametrically opposite points A and Bon Earth. The angle o subtended

Which of these diagrams is a convex mirror? A vertical rectangular box with a left side that bows out. A vertical rectangular box. A vertical rectangular box with a left side that bows in.

Answers

A vertical rectangular box with a left side that bows out is a convex mirror. A convex mirror reflects light outwards, it cannot be utilized to concentrate light.

What is a convex mirror?

A convex mirror, also known as a curved mirror, has a reflecting surface that bulges toward the light source. A curved mirror's surface can be convex, or bulging outward, or concave, or bulging inward.

A convex mirror is a hollow spherical is divided into pieces, the exterior surface of each cut portion is painted. The image of the plant has real, inverted, and smaller characteristics.

A vertical rectangular box with a left side that bows out is a convex mirror. A convex mirror reflects light outwards, it cannot be utilized to concentrate light.

Hence, option A is correct.

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Answer:

the answer is a

Explanation:

A car has a speed of 20 m/s. If the speed of the car increases to 30 m/s in 5 seconds, what is the car’s acceleration?

Answers

2

Explanation:

2 times 5 is 10/ 20+10=30

Which statement best describes how waves carry energy?
O Energy moves from one place to another through the wave.
O Energy increases as it moves through the wave.
Energy is completely consumed by the beginning of the wave.
Energy builds through the wave and is released at the end.
Ο Ο

Answers

Answer:

Energy moves from one place to another through the wave. answer A

A wave is a disturbance that transmit energy. Thus, the correct statement is energy moves from one place to another through the wave.

What is a wave?

A wave is a disturbance that transfers energy as it moves from one point to another.

Different terminologies are used to characterise a wave as it travels. Some of these include

Wave speed Wave crest Wave Frequency Wave Period Wavelength Wave troughAmplitude etc

Considering the question given above, we see clearly from the definition of wave that the energy is transferred as the wave is moving.

Thus, we can conclude that the correct answer to the question is energy moves from one place to another through the wave

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What is the speed of the sailboat that is traveling 110 meters in 135 seconds?

Answers

Answer:

your answer is 0.814.

Explanation:

you divide the total distance traveled by the time taken

I need help with parts ANB of question number two

I need help with parts ANB of question number two

Answers

Answer:

a.

b.

Explanation:

The change in tire's angular velocity is

\(\Delta\omega=\omega_f-\omega_i\)

Now,

\(\begin{gathered} \omega_f=3.9\text{rad}/s \\ \omega_i=-3.9\text{rad}/s \end{gathered}\)

Therefore,

\(\Delta\omega=3.9-(-3.9)\)

\(\boxed{\Delta\omega=7.8\text{rad}/s\text{.}}\)

Part B.

The average angular acceleration is given by

\(\alpha_{\text{avg}}=\frac{\Delta\omega}{\Delta t}\)

Now,

\(\Delta\omega=7.8\text{rad}/s\)

and

\(\Delta t=1.85s\)

Therefore,

\(\alpha_{\text{avg}}=\frac{\Delta\omega}{\Delta t}=\frac{7.8}{1.85}\)

\(\Rightarrow\boxed{\alpha_{\text{avg}}=4.22\text{rad}/s^2}\)

which is our answer!

AYE I NEED HELP!
Which two things balance and keep a main sequence star in equilibrium?

Answers

Answer:

While self-gravity pulls the star inward and tries to make it collapse, thermal pressure (heat created by fusion) pushes outward. These two forces cancel each other out in a main sequence star, thus making it stable.

Explanation:

oxygen passes from maternal hemoglobin to fetal hemoglobin by a process known as:

Answers

The process by which oxygen passes from maternal hemoglobin to fetal hemoglobin is known as "placental transfer."

During pregnancy, oxygen is transported from the mother's lungs to the placenta via the maternal bloodstream. In the placenta, the exchange of oxygen and other essential nutrients occurs between the maternal blood and the fetal blood. The placenta acts as a vital interface, allowing the exchange of gases, nutrients, and waste products between the mother and the developing fetus. Maternal hemoglobin, which is found in red blood cells circulating in the maternal bloodstream, carries oxygen from the mother's lungs. Fetal hemoglobin, on the other hand, is present in the red blood cells of the developing fetus.

Through a process called "oxygen dissociation," oxygen molecules diffuse across the thin walls of the placental blood vessels. Oxygen moves from an area of higher oxygen concentration in the maternal blood to an area of lower oxygen concentration in the fetal blood, facilitated by the difference in oxygen binding affinities of maternal and fetal hemoglobin. In summary, the transfer of oxygen from maternal hemoglobin to fetal hemoglobin occurs through the placenta via the process of placental transfer.

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What if the frequency is now increased to f = 69 Hz, and we want to keep the impedance unchanged? (A) What new resistance should we use to achieve this goal? R = Ω (B) What is the phase angle (in degrees) between the current and the voltage now? ϕ = ° (C) Find the maximum voltages across each element.

Answers

Complete Question

A series RLC circuit has R = 405 Ω, L = 1.40 H, C = 3 µF. It is connected to an AC source with f = 60.0 Hz and ΔVmax = 150 V. What if the frequency is now increased to f =  69 Hz, and we want to keep the impedance unchanged? (A) What new resistance should we use to achieve this goal? R = Ω (B) What is the phase angle (in degrees) between the current and the voltage now? ϕ = ° (C) Find the maximum voltages across each element.

Answer:

A

   \(R = 513.9 \ \Omega\)

B

   \(\theta = 34.79^o\)

C

  \(V_c =212.96 \ V\) ,  \(V_L = 168.139 \ V\) ,  \(V_R = 142.35 \ V\)

Explanation:

From the question we are told that

   The resistance is  \(R = 405 \ \Omega\)

    The inductance is  L = 1.40 H

    The capacitance is  \(C = 3 \mu F = 3 *10^{-6} \ F\)

    The original  frequency is \(f = 60 \ Hz\)

    The new frequency is  \(f_1 = 69 \ Hz\)

Generally the reactance of the inductor is mathematically represented as

    \(X_L = 2 \pi * f * L\)

=> \(X_L = 2 * 3.142 * 60 * 1.40\)

=> \(X_L = 527.5 \ \Omega\)

Generally the reactance of the capacitor is mathematically represented as

    \(X_c = \frac{1}{2 \pi * f * C}\)

   \(X_c = \frac{1}{2 * 3.142 * 60 * 3*10^{-6}}\)

=> \(X_c = 884.6 \ \Omega\)

Generally the impedance of the circuit is mathematically  represented as

      \(Z = \sqrt{[X_L - X_c ]^2 + R^2}\)

=>    \(Z = \sqrt{[527.5 -884.6 ]^2 + 405^2}\)

=>    \(Z = 540 \ \Omega\)

Generally when the frequency is changed , the reactance of the inductor becomes

        \(X_L' = 2 * 3.142 * 69 * 1.4\)

 =>   \(X_L' = 607 \ \Omega\)

Generally when the frequency is changed , the reactance of the capacitor becomes

   \(X_c' = \frac{1}{2 * 3.142 * 69 * 3*10^{-6}}\)

=> \(X_c ' = 768.8 \ \Omega\)

Generally the new resistance is mathematically represented as

      \(R ^2 = Z^2 - ( X_c' - X_L')^2\)

=>  \(R ^2 = 540^2 - ( 603 - 768.8 )^2\)

=>  \(R = \sqrt{264110.4}\)

=>   \(R = 513.9 \ \Omega\)

Generally the phase angle is mathematically represented as

      \(\theta = tan^{-1}[\frac{[X_L - X_C]}{R} ]\)

=>    \(\theta = tan^{-1}[\frac{[ 884.6 - 527.5]}{513.92} ]\)

=>   \(\theta = 34.79^o\)

Generally the maximum current flowing through the circuit is mathematically represented as

       \(I_{max} = \frac{\Delta V}{ Z}\)

=>    \(I_{max} = \frac{150}{540 }\)

=>    \(I_{max} = 0.2778 \ A\)

Generally  the maximum voltage across the capacitor is

     \(V_c = I_{max} * X_c'\)

     \(V_c = 0.2778* 768.8\)

=>  \(V_c =212.96 \ V\)

Generally  the maximum voltage across the inductor is

     \(V_L = I_{max} * X_L\)

     \(V_L = 0.2778* 607\)

=>  \(V_L = 168.139 \ V\)

Generally  the maximum voltage across the resistor is

     \(V_R = I_{max} * R\)

     \(V_R = 0.2778* 513.9\)

=>  \(V_R = 142.35 \ V\)

. If the electrical force of repulsion between two same amount of charges is 10 N, andthey are 30000 m apart. What is the magnitude of each charge?

Answers

Answer:

Explanation:

Given: q₁ = q₂,

F= 10 N,

distance between two charges, r = 30000 m.

We have, \(F = \frac{q_{1} q_{2} }{4\pi Er^{2} }\)

Hence, \(q_{1} q_{2} =F * 4\pi *E *r^{2}\)

E (epsilon) =\(8.85 * 10^{-12} C^{2} /Nm\)

Substituting the values, we have,

\(q_{1} q_{2} = 1 C\)

Hence \(q_{1} = q_{2} = 0.5 C\)

Newton's 3rd Law of Motion
For every__________ (or force), there is an ____________ and __________ action (or force).

Answers

Answer:

Explanation:

For every action (or force), there is an equal and opposite action (or force).

if two objects, each with a mass of 4.1x10^2 kg, produce a gravitational force between them if 9.2x10^-6 N, what is the distance between them?

Answers

Taking into account the Universal Law of Gravitation, the distance between the objects is 1.10396×10⁻⁶ m².

Universal Law of Gravitation

The Universal Law of Gravitation establishes that bodies, by the simple fact of having mass, experience a force of attraction towards other bodies with mass, called gravitational force.

This law states that the gravitational force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance that separates them, expressed as:

\(F=G\frac{Mm}{d^{2} }\)

where:

G is the universal gravitational constant, with a value of 6.67×10⁻¹¹ \(\frac{Nm^{2} }{kg^{2} }\).M and m are the masses of the bodies that interact.d is the distance that separates them.

Distance between two objects

In this case, you know:

F= 9.2×10⁻⁶ NG= 6.67×10⁻¹¹ \(\frac{Nm^{2} }{kg^{2} }\)M= m= 4.1×10² kgd= ?

Replacing in the Universal Law of Gravitation:

\(9.2x10^{-6} N=6.67x10^{-11}\frac{Nm^{2} }{kg^{2} } \frac{4.1x10^{2} kgx 4.1x10^{2} kg}{d^{2} }\)

Solving:

9.2×10⁻⁶ N÷ 6.67×10⁻¹¹ \(\frac{Nm^{2} }{kg^{2} }\)= \(\frac{4.1x10^{2} kgx 4.1x10^{2} kg}{d^{2} }\)

1.3793×10⁻¹⁷ kg²÷m²= \(\frac{168100 kg^{2} }{d^{2} }\)

1.3793×10⁻¹⁷ kg²÷m²× d²= 168100 kg²

d²= 168100 kg²÷ 1.3793×10⁻¹⁷ kg²÷m²

d²= 1.2187341×10⁻¹² m²

d= √1.2187341×10⁻¹² m²

d= 1.10396×10⁻⁶ m²

Finally, the distance is 1.10396×10⁻⁶ m².

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why is newtons cradle described as an almost ideal close system?Explain in one or two sentences.

Answers

Newton's cradle is described as an almost ideal closed system because it is a system that is nearly isolated from its environment. This means that the system is mostly self-contained and does not exchange matter or energy with its surroundings.

In the case of Newton's cradle, the system consists of a set of metal balls that are suspended from a frame. When one ball is pulled back and released, it strikes the other balls and causes them to swing back and forth. This motion is almost perfectly elastic, which means that the balls do not lose or gain energy during the collision. As a result, the system is nearly closed and does not exchange energy with the surrounding environment.

Overall, Newton's cradle is described as an almost ideal closed system because it is nearly isolated from its environment and does not exchange matter or energy with its surroundings. This allows the system to demonstrate the principles of conservation of momentum and energy in a simple and visual way.

Because it is a system that is almost completely isolated from its surroundings, Newton's cradle is referred to be an almost ideal closed system. This indicates that the system is largely self-contained and does not interact with the environment to exchange matter or energy.

What is Newton's cradle?

The Newton's Cradle is an apparatus that uses spheres in motion to show how momentum and energy are conserved. One of the stationary spheres at the end is lifted and released, striking them and sending a force through them that forces the final sphere higher.

In order to recreate the effect in the other way, the final sphere swings back and collides with the virtually stationary spheres. The instrument was created by French scientist Edme Mariotte and is named after English scientist Sir Isaac Newton who lived in the 17th century.

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An object moves from point A to B to C to D and finally to A
along the circle shown in the figure below.
a) Find the distance covered by the moving object.
b) Find the magnitude of the displacement of the object.

An object moves from point A to B to C to D and finally to Aalong the circle shown in the figure below.a)

Answers

Answer:

a) The distance covered by the moving object is approximately 18.85 km

b) The magnitude of the displacement of the object is 0 (no displacement)

Explanation:

From the drawing, we have;

The sale of the drawing is 1 unit = 1 km

The radius of the circle in the drawing along which the object moves = 3 units

Therefore;

The radius of the circle along which the object moves, r = 1 km/unit × 3 units = 3 km

a) The distance covered by the object that moves from point A to B to C to D and finally to A is equal to the circumference of the circle

Therefore;

The distance covered by the moving object, d = 2·π·r

By pugging the value for r = 3 km

d = 2 × π × 3 km = 6·π km ≈ 18.85 km

The distance covered by the moving object, d ≈ 18.85 km

b) The displacement = The object's change in position

The initial position of the object = Point A

The final position of the object = Point A

Therefore, the displacement of the object, A = No displacement = 0 (No difference between the initial and final location of the object

An emergency vehicle is traveling at 45 m/s approaching a car heading in the same direction at a speed of 24 m/s. The emergency vehicle driver has a siren sounding at 650 Hz. At what frequency does the driver of the car hear

the siren?

Answers

The frequency that the driver of the car hears the siren of an emergency vehicle traveling at 45 m/s and approaching a car heading in the same direction at a speed of 24 m/s is 538 Hz.

Doppler effect refers to a shift in the frequency of sound waves or light waves as they move toward or away from an observer. When the vehicle moves towards us, the sound waves are compressed, and their frequency increases, resulting in a higher pitch.

When the vehicle moves away from us, the sound waves are stretched out, and their frequency decreases, resulting in a lower pitch. This effect is also applicable to light waves.

The formula for calculating the Doppler effect is: f'= f(v±vᵒ)/(v±vᵰ), where,• f' is the frequency of the observed wave,• f is the frequency of the emitted wave,• v is the speed of the wave in the medium,• vᵒ is the speed of the observer relative to the medium,• vᵰ is the speed of the source relative to the medium.

In this case, the driver of the car hears the siren, which is moving towards him, hence the formula is:

f'= f(v+vᵒ)/(v±vᵰ)

Substituting the values of f, v, vᵒ, and

vᵰ,f' = 650(343+24)/(343-45)f'

= 538 Hz

Therefore, the driver of the car hears the siren at a frequency of 538 Hz.

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Why is a 1 solar-mass red giant more luminous than a 1 solar-mass main sequence star?.

Answers

Answer:

No

Explanation:

I dont know please help

Two identical speakers are 3.50 m
and 5.20 m from a listener. What is
the lowest frequency (n = 0) that
would cause destructive
interference there?
(Unit = Hz)

Answers

Answer:

The difference in distance from the speakers is 5.2 - 3.5 = 1.7 m

The listener would be 1/2 wavelength out of phase with the speakers

1/2 y = 1.7 m    where y is the wavelength

y = 3.4 m       the required wavelength

f = v / y = 340 m/s / 3.4 m = 100 / sec     lowest frequency  

Answer:

100.8

Explanation:

Trust :)

A projectile is fired with an initial muzzle speed 370 m/s at an angle 40∘ from a position 4 meters above the ground level. Find the horizontal displacement from the firing position to the point of impact. Use g=9.8 m/s2. meters. Tries 0/8 At what speed does the projectile hit the ground? meters/second. Tries 0/8

Answers

The horizontal displacement from the firing position to the point of impact is approximately 2,425 meters. The projectile hits the ground with a speed of approximately 230.4 meters/second.

To calculate the horizontal displacement of the projectile, we need to find the time of flight and then multiply it by the horizontal component of the initial velocity.

Step 1: Find the time of flight

Using the given initial muzzle speed and launch angle, we can find the time of flight. The vertical component of the initial velocity can be determined by multiplying the initial speed by the sine of the launch angle. Since the projectile is launched from a height of 4 meters, the time it takes for the projectile to reach the ground can be calculated using the equation h = ut + (1/2)gt^2, where h is the height, u is the initial vertical velocity, g is the acceleration due to gravity, and t is the time of flight. Plugging in the known values, we get 4 = (370 * sin(40))t - (1/2)(9.8)t^2. Solving this equation yields t ≈ 7.28 seconds.

Step 2: Calculate the horizontal displacement

The horizontal component of the initial velocity can be found by multiplying the initial speed by the cosine of the launch angle. The horizontal displacement is then given by multiplying the horizontal component of the initial velocity by the time of flight. Therefore, the horizontal displacement is approximately 370 * cos(40) * 7.28 ≈ 2,425 meters.

Step 3: Determine the speed at impact

To find the speed at which the projectile hits the ground, we need to calculate the vertical component of the velocity at the time of impact. The vertical component of the velocity can be determined by multiplying the initial speed by the sine of the launch angle and subtracting the product of the acceleration due to gravity and the time of flight.

Thus, the vertical component of the velocity at impact is given by 370 * sin(40) - 9.8 * 7.28 ≈ -230.4 meters/second. The negative sign indicates that the velocity is directed downwards. Therefore, the speed at which the projectile hits the ground is approximately 230.4 meters/second.

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let there be a cylinrical charg source by radius 2 and length 4 m. the volume charge density in this cylinder is >. calculate the electric flux density inside and outside of this charge source. (your answer should be in terms of variable r).

Answers

According to Gauss law, Inside the cylindrical charge source: D = (ρ * (π * r² * 4)) / (ε₀ * A), Outside the cylindrical charge source: D = 0

To calculate the electric flux density inside and outside of the cylindrical charge source, we need to use Gauss's Law.

Inside the cylindrical charge source:

Since the charge is uniformly distributed within the cylinder, the electric field will be radially symmetric. Thus, the electric flux density (D) will also be radially symmetric.

According to Gauss's Law, the electric flux (Φ) through a closed surface is given by:

Φ = ∮ D · dA

For a cylindrical Gaussian surface placed inside the cylinder, the electric flux passing through the Gaussian surface is equal to the charge enclosed by the surface divided by the permittivity of free space (ε₀).

Since the charge is uniformly distributed within the cylinder, the charge enclosed by the Gaussian surface will be equal to the volume charge density (ρ) multiplied by the volume of the cylinder (V):

Charge enclosed = ρ * V

The volume of the cylinder can be calculated by multiplying the cross-sectional area (π * r²) by the length (4 m):

V = π * r² * 4

Therefore, the charge enclosed is:

Charge enclosed = ρ * (π * r² * 4)

Substituting this back into Gauss's Law, we have:

Φ = (ρ * (π * r² * 4)) / ε₀

Since the electric flux density (D) is related to the electric flux (Φ) by D = Φ / A, where A is the area of the Gaussian surface, we can rewrite the equation as:

D = (ρ * (π * r² * 4)) / (ε₀ * A)

Outside the cylindrical charge source:

Outside the cylinder, there is no charge enclosed by the Gaussian surface, and hence the electric flux density will be zero (D = 0).

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The assumption that there is no energy loss is not accurate. Assuming the spring has a spring constant of 100Nm-1 and has a length change of 2 cm, the track is on a level surface, and that the final velocity of the car is 0.25 ms-1 when it reaches the end of the track, what is the percentage efficiency of the toy? Take the mass of the car to be 150 g

Answers

The toy percentage efficiency is 23%.

Solution:

The kinetic energy is:

KE = \(\frac{1}{2} mv^{2}\)

KE = \(\frac{1}{2} *(150)(0.25)^2\)

KE = 4.6875 J

The elastic potential energy is:

E = 0.5 x 4 x 10 = 20

E = 100 J

The percentage efficiency of the toy is found as:

%n = \(\frac{4.6875*100}{20}\)

%n = 23%

The more the elastic material is stretched the greater the potential for elastic energy storage. The amount of elastic potential energy stored in a stretched spring can be calculated using the formula: Work is done when the spring expands and contracts.

Springs store elastic potential energy. If no inelastic deformation has occurred, the work done is equal to the stored elastic potential energy. As the spring constant increases for a constant applied force, the spring deflection decreases as the spring stiffness increases.

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what does the symbol 'Mg' represent?​

Answers

Answer:

\(the \: symbol \: mg \: represent \: magnesium \\ thank \: you\)

Answer:

Magnesium.

I hope it's helps you

Why does time seem to flow only in one direction?

Answers

Answer:

Time seem to flow in only one direction because it's from entropy. In tiny physics, time is directionally neutral.

Explanation:

Answer:

objects that store memories heat up as the operate(computers and brains). heat(energy) generation increases entropy. entropy is a measure of disorder. entropy is an irreversible process, so the laws of thermodynamics(law 1. energy can't be created or destroyed law 2. the total entropy must increase) require that such objects can only run in one direction: from past to present

why does the rubber rod push the balloon away, and then why does the glass rod pull the balloon towards it after it is rubbed in fur?

Answers

Answer/Explanation:

Rubber is an insulator, meaning it doesn't conduct electricity well. Rubber is a very poor conductor of electricity.

The glass rod, however, is being rubbed with fur which makes the glass rod lose its electrons, leaving it to be only positively charged. The electrons get stripped away and remain on the fur.

Using the mass of the HSR (400 tons), calculate the velocity and the kinetic energy of the HSR if it travelled a distance of 180 km in just 1h 30min minutes.

Answers

Answer:the velocity and the kinetic energy of the HSR if it travelled a distance of 180 km in just 1h 30min minutes.  

 

In your answer, explain how can you know if the HSR has more kinetic energy. How can kinetic energy be transferred or transformed?  

Explanation:suiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii

The kinetic energy of the given mass is 2173 kJ. The energy of an object or body due to its movement is called kinetic energy.

What is kinetic energy?

It is the energy of an object or body due to its movement. It can be calculated by the formula,

\(KE = \dfrac 12 mv^2\)

Where,

\(m\) - mass = 400 tons = 400000 kg

\(v\) - velocity

First, calculate the velocity.

\(v = \rm \dfrac {180 \km}{1.5 \ hours}\\\\v = 12 km/h\\\\v = 3.3 m/s\)

Now, put the values in the formula,

\(KE = {\rm \dfrac 12 400000\ kg \times (3.3 \ m/s)^2}\\\\KE = 2178000 {\rm \ kg .m^2/s^2}\\\\KE = 2173\rm \ kJ\)

Therefore, the kinetic energy of the given mass is 2173 kJ.

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