The following diagram shows a person exerting a
300.-newton force on the handle of a shovel that
makes an angle of 60. with the horizontal ground.
Determine the magnitude of the component of the
force perpendicular to the ground.
Answer:
260 Newtons
Explanation:
Okay, so what you have to do is know what the question is asking. It wants to know the force perpendicular to the ground. We know perpendicular makes a right angle, so we use the diagram to make it into a right triangle with a degree of 60, and hypotunese of 300 newtons. Now, we use basic trigonometry, we place x on the horizontal side since it perpendicular to the ground. We know it´s sin because x is opposite to 300 which is the hyp.
Sin= opp/hyp
x/300
sin(60)= x/300
300*sin(60)= 259.8, which rounds to
260 Newtons
There is your answer :D. Happy to help.
The component of the force which is perpendicular to the ground is → F [y] = 261 a[y].
What are the components of a Vector?A vector V making an angle θ with the x - axis, can be resolved into two two components along the x and y - axes respectively as →
V = Vcosθ a[x] + Vsinθ a[y]
where -
a[x] is the unit vector along the +x axis
a[y] is the unit vector along the +y axis.
Given is a force of magnitude 300 N acting on the handle that makes an angle of 60° with the horizontal ground.
The component normal to the ground will be the component along the y - axis. The component along the y - axis is the sine component. Suppose that vector F represents the force of magnitude (|F|) 300 N. The component perpendicular to the ground will be -
F [y] = |F| sinθ a[y]
F [y] = 300 x sin(60°) a[y]
F [y] = 300 x 0.87
F [y] = 261 a[y]
Therefore, the component of the force which is perpendicular to the ground is → F [y] = 261 a[y].
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What force acts between Earth and the moon?
O gravity
O mass
O motion
Onewtons
Answer:
A. gravity
or gravitational force
Mark as brainliest if this helped
Peace
The attaction between magnets is a chemical property.
True
Or
False
Answer:
false its an attraction property
Answer:
True
The attraction is a chemical property.
An object is thrown downward with an initial velocity of 6 feet
per second. The relationship between the distance s it travels and
time t is given by s=6t+16t2. How long does it take the object to
fal
The object does not fall or it takes no time to fall according to the given information.
To determine how long it takes for the object to fall, we need to find the time at which the distance traveled (s) becomes zero. This represents the point at which the object hits the ground.
Given: s = 6t + 16t^2
To find the time at which s becomes zero, we set the equation equal to zero and solve for t:
0 = 6t + 16t^2
This equation is a quadratic equation in terms of t. To solve it, we can factor out a common factor of t:
0 = t(6 + 16t)
Setting each factor equal to zero, we have:
t = 0 (from the factor t = 0)
or
6 + 16t = 0 (from the factor 6 + 16t = 0)
Solving the second equation for t:
16t = -6
t = -6/16
t = -3/8
We discard the negative solution since time cannot be negative in this context.
Therefore, the object takes t = -3/8 seconds to fall. However, this negative value doesn't make physical sense in this context. Therefore, we can conclude that the object does not fall or it takes no time to fall according to the given information.
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bro my mom just baought em
Answer:
weow hahaha lol!
Explanation:
Answer:
LOLOLOLOLOL LOL
Explanation:
Imagine that we strike two tuning forks, one with a frequency of 340 Hz, and another with frequency 342 Hz. What will we hear? Hint: what quantity does our response depend on in the case of the sound waves, and is that different or not compared to EM waves?
When striking two tuning forks with frequencies of 340 Hz and 342 Hz, we will hear beats, which are periodic variations in sound intensity. The beat frequency can be calculated by taking the absolute difference between the two frequencies, resulting in a beat frequency of 2 Hz.
When two sound waves of slightly different frequencies interfere with each other, they produce beats. Beats occur due to the superposition of waves with similar amplitudes and slightly different frequencies. In the case of sound waves, our response depends on the frequency of the waves.
The beat frequency corresponds to the difference between the frequencies of the two tuning forks.
Beat frequency = |frequency1 - frequency2|
Beat frequency = |340 Hz - 342 Hz|
Beat frequency = 2 Hz
Striking tuning forks with frequencies of 340 Hz and 342 Hz will result in the perception of beats with a frequency of 2 Hz. This phenomenon occurs due to the interference of sound waves with slightly different frequencies. In contrast to electromagnetic waves, where our response depends on factors like amplitude and wavelength, our perception of sound depends primarily on the frequency of the waves.
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with what constant velocity would you have to push or pull the rod in order to make the magnetic force zero
Energy and Power Due to Motional Electromotive Force. Emf may be prompted in primary ways: Due to the movement of a conductor withinside the presence of a magnetic field. Due to the extrude withinside the magnetic flux enclosed via way of means of the circuit.
The length of the voltage may be various through 3 factors: The length of the magnetic discipline. The greater flux strains there are, the greater flux strains there are for the conductor to cut.
The lively period of the conductor. The velocity at which the conductor passes thru the discipline. Moving the bar to the proper decreases the vicinity of the loop, reducing the flux.
The caused modern need to generate a discipline out of the page. This calls for a counter-clockwise modern. The flux thru the loop is converting, so the loop attempts to oppose the alternate. The flux is converting due to the fact the bar is moving, converting the place of the loop. To oppose the alternate the loop makes the bar gradual down.
Thus the velocity (and the brought on emf and current) lower exponentially to zero.
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EXPLAIN: Why must you reduce friction
order to move certain objects?
Friction is one of the forces working against a moving object, it makes it harder to move the more friction is exerted on the object. So, by reducing friction, you are making it easier for you to be able to move objects.
can a chemical change be undone?
Answer:
no
Explanation:
because it will bind together in the molecular level
Two point charges q1 = +2.4 nC and q2 = -6.5 nC are 0.100 m apart. Point A is midway between them; point B is 0.080 m from and 0.060 m from (Fig. E23.19). Take the electric potential to be zero at infinity. Find (a) the potential at point A; (b) the potential at point B; (c) the work done by the electric field on a charge of 2.50 nC that travels from point B to point A.
potential at point A( -776 V)
the potential at point B;( -855 V)
the work done by the electric field on the charge is 198 nJ.
How find the electric field?first, we can use Coulomb's law to find the electric field at points A and B due to the two charges:
Electric field at A:
\(E1 = kq1/r1^2\), where k is Coulomb's constant \((9*10^9 Nm^2/C^2),\) q1 is the charge of q1 (+2.4 nC), and r1 is the distance from q1 to A (0.050 m)
\(E2 = k*q2/r2^2\), where q2 is the charge of q2 (-6.5 nC), and r2 is the distance from q2 to A (0.050 m)
The net electric field at A is the vector sum of these two fields:
E_net = E1 + E2
Electric field at B:
\(E1 = kq1/r1^2\), where r1' is the distance from q1 to B (0.080 m)
\(E2 = k*q2/r2^2\), where r2' is the distance from q2 to B (0.060 m)
The net electric field at B is the vector sum of these two fields:
E_net' = E1' + E2'
(a) The potential at point A can be found using the formula:
V_A = kq1/r1 + kq2/r2
where r1 and r2 are the distances from q1 and q2 to A, respectively.
Substituting the given values:
V_A =\((9*10^{9} Nm^2/C^2) * (2.4*10^{-9} C) / (0.050 m) + (9*10^{9} Nm^2/C^2) * (-6.5*10^{-9} C) / (0.050 m)\)
V_A = -776 V
(b) The potential at point B can be found using the same formula as for point A, but with the distances r1' and r2':
V_B = kq1/r1' + kq2/r2'
Substituting the given values:
V_B =\((9*10^{9} Nm^2/C^2) * (2.4*10^{-9} C) / (0.080 m) + (9*10^{9} Nm^2/C^2) * (-6.5*10^{-9} C) / (0.060 m)\)
V_B = -855 V
(c) The work done by the electric field on a charge of 2.50 nC that travels from point B to point A is equal to the change in potential energy of the charge:
ΔU = q * (ΔV)
where q is the charge (2.50 nC), ΔV is the change in potential (V_A - V_B).
Substituting the given values:
\(ΔU = (2.50*10^{-9} C) * (-776 V - (-855 V))\)
ΔU = 198 nJ
Therefore, the work done by the electric field on the charge is 198 nJ.
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What’s 2.3 miles into kilometers
Answer:
3.70149
Explanation:
A
is the order in which things are arranged.
O plan
sequence
O process
O goal
Answer:
sequence
Explanation:
sequences are the way in which things are ordered, for example: 1, 2, 3, 4 is a sequence:)
now calculate the acceleration between points B and E as follows
time between dots calculation
It should be noted that to calculate the acceleration between points B and E, we need to have information about the initial and final velocities, as well as the time it takes to go from point B to point E.
How to explain the accelerationAssuming we have this information, we can use the following formula to calculate the acceleration:
acceleration = (final velocity - initial velocity) / time
Here's a step-by-step process to calculate the acceleration between points B and E:
Determine the initial velocity at point B. This could be given to you or you may need to calculate it based on other information.
Determine the final velocity at point E. Again, this could be given to you or you may need to calculate it based on other information.
Determine the time it takes to go from point B to point E. This could be given to you or you may need to calculate it based on other information.
Plug the values from steps 1, 2, and 3 into the acceleration formula:
acceleration = (final velocity - initial velocity) / time
Calculate the acceleration using the formula and express the answer in the appropriate units (such as meters per second squared or feet per second squared).
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2. A bar magnet is divided in two pieces . Which of the following statements is true about the force between the broken pieces if they face each other with a small separation ? A. There is an electric repulsive force between the broken pieces B. There is an electric attractive force between the broken pieces C. There is a magnetic repulsive force between the broken pieces D. There is a magnetic attractive force between the broken pieces .
a 25.0 μf capacitor is charged to a potential difference of 850 v . the terminals of the charged capacitor are then connected to those of an uncharged 8.00 μf capacitor.
(A) the original charge of the system is 21,250 μC. (B) the final potential difference across the capacitor is 850 V. (C) The final energy of the system is 11,740,750 μJ.
To compute the original charge of the system, we can use the formula;
Q = C × V
where Q will be the charge, C will be the capacitance, and V will be the potential difference.
For the 25.0 μF capacitor charged to 850 V;
Q₁ = C₁ × V₁
= (25.0 μF) × (850 V)
Q1 = 21,250 μC
Therefore, the original charge of the system is 21,250 μC.
When the charged capacitor is connected in parallel to the uncharged capacitor, the potential difference across both capacitors becomes equal. This means the final potential difference across the capacitors will be the same as the initial potential difference of the charged capacitor, which is 850 V.
Therefore, the final potential difference across the capacitor is 850 V.
The energy stored in a capacitor can be calculated using the formula:
E = 0.5 × C × V₂
where E will be the energy, C will be the capacitance, and V will be the potential difference.
For the 25.0 μF capacitor with a potential difference of 850 V:
E₁ = 0.5 × C1 × V1²
= 0.5 × (25.0 μF) × (850 V)²
E₁ = 9,018,750 μJ
For the 8.00 μF capacitor with a potential difference of 850 V:
E₂ = 0.5 × C₂ × V2²
= 0.5 × (8.00 μF) × (850 V)²
E2 = 2,722,000 μJ
The final energy of the system is the sum of the energies of both capacitors;
E_final = E₁ + E₂
= 9,018,750 μJ + 2,722,000 μJ
E_final = 11,740,750 μJ
Therefore, the final energy of the system is 11,740,750 μJ.
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--The given question is incomplete, the complete question is
"A 25.0 μf capacitor is charged to a potential difference of 850 v . the terminals of the charged capacitor are then connected to those of an uncharged 8.00 μf capacitor. A) compute the original charge of the system B)compute the final potential difference across the capacitor C)compute the final energy of the system."--
Pls help I really need help w this one Tnks
kisses has mass of 57 kg runs up a flight of stairs with a vertical heighy of 28 m. if the trip takes 32 seconds to complete, calculate kisses power?
Kisses' power is approximately 490.13 Watts.
Power (P) is defined as the rate at which work is done. The formula to calculate power is:
P = W / t
P is the power,
W is the work done,
t is the time taken.
The work done (W) can be calculated as the product of force (F) and distance (d):
W = F * d
In this case, the force is the weight of Kisses, which can be calculated using the formula:
F = m * g
m is the mass of Kisses,
g is the acceleration due to gravity (approximately 9.8 m/s^2).
m = 57 kg
d = 28 m
t = 32 seconds
g = 9.8 m/s^2
First, calculate the work done:
W = F * d
W = (m * g) * d
Next, calculate the power:
P = W / t
Substituting the given values:
W = (57 kg * 9.8 m/s^2) * 28 m
W ≈ 15684.24 J
P = 15684.24 J / 32 s
P ≈ 490.13 W
Therefore, Kisses' power is approximately 490.13 Watts.
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Which of the following is a FALSE statement? (A) Heat moves through solids by conduction (B) Molecules move faster in warmer substances (C) Warm water is denser than cold water (D) Heat moves through liquids and gases by convection
Answer:
C.
Explanation:
during a crash a dummy with the mass of 60.0 kg hits a airbag that exerts a constant force in the dummy the acceleration of the dummy is 250 m/2 what force did the airbag exert on the dummy?
Explanation:
F = ma
F = (60.0 kg) (250 m/s²)
F = 15,000 N
During a crash, a dummy with a mass of 60 kg hits an airbag, then the airbag will exert 15,000 N force on the dummy.
What is acceleration?The rate of change in an object's velocity concerning time is known as acceleration in mechanics. The vector quantity of accelerations. The direction of the net force that is acting on an object determines its acceleration.
Since acceleration has both a magnitude and a direction, it is a vector quantity. Velocity is a vector quantity as well. The definition of acceleration is the change in velocity vector over a time interval divided by the time interval.
There are several types of acceleration :
Uniform AccelerationNon-Uniform AccelerationAverage AccelerationAccording to the question, the given values are :
Mass, m = 60 kg
Acceleration, a = 250 m/s²
F = ma
F = (60.0 kg) × (250 m/s²)
F = 15,000 N
Hence, the force exerted by the airbag will be 15,000 N.
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identify a stationary checkpoint, begin counting when the rear of the vehicle in front of you passes the checkpoint, and count until you pass the checkpoint is a way to determine:
1) Time Interval
2) Following Distance
3) Relative Speed
The method you described, where you identify a stationary checkpoint, begin counting when the rear of the vehicle in front of you passes the checkpoint, and count until you pass the checkpoint, is a way to determine the following:
Time Interval: By measuring the time it takes for your vehicle to pass the checkpoint after the vehicle in front of you, you can determine the time interval between the two vehicles.
Following Distance: By knowing the time interval and considering the speed of your vehicle, you can estimate the following distance between your vehicle and the one in front of you. This information can help you maintain a safe distance to prevent collisions.
Relative Speed: If you know the distance between the stationary checkpoint and the speed of the vehicle in front of you, you can calculate the relative speed between the two vehicles.
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An object with a velocity of
1 m s-l accelerates with an
acceleration of 1 m s2.
What is its velocity after
moving 1 m?
A 1.4 ms s-1
B 1.7 m s -1
C) 2.0 m s-
D 3.0 m s-1
-1
Answer:
v = 1.7 m/s
Explanation:
Given that,
Initial velocity of the object, u = 1 m/s
Acceleration of the object, a = 1 m/s²
We need to find the velocity of the object after moving 1 m. Let v be the velocity. Using third equation of kinematics to find it i.e.
\(v^2-u^2=2ad\\\\v^2=2ad+u^2\\\\v^2=2(1)(1)+1^2\\\\v=\sqrt3\\\\v=1.7\ m/s\)
So, the final velocity of the object is 1.7 m/s.
Two charged particles repel each other with a force f. If the charge on only one of the particles is doubled and the distance between them is also doubled, then the force will be.
With a force of f, two charged particles repel one another. The force will be F/2 if only one particle's charge is doubled and the distance in them is likewise doubled.
What does the word "force" mean in science?A force of this magnitude can be described as a push or a pull, which is perfectly fine. A force does not "exist in" or "contain" an object. A force from another can exert pressure on something. The concept of a force makes no distinction across living creatures and inanimate objects.
what is In one words, define force.The definition of force is an external cause that, when applied, modifies or tends to modifies the state of the body. The body comes to rest while it is in motion, and it will go into motion when it is at rest.
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in 1965, two scientists made a surprising discovery. they detected a faint microwave radiation signal coming from all over the universe
what is this microwave radiation?i’ll give brainlist
Answer: someone took down my answer I don’t know why when I took this test and got it right but the answer is C like the other person said.
Explanation:
The microwave radiation referred to in this context is radiation that was released as matter formed in the early universe. Therefore option A is correct.
Microwave radiation, also known as cosmic microwave background radiation (CMB), is a faint radiation that permeates throughout the universe.
It is considered to be the remnants of the thermal radiation released shortly after the Big Bang, during a phase called recombination. At this time, the universe transitioned from a hot, dense plasma to a state where neutral atoms could form, allowing photons to travel freely.
The cosmic microwave background radiation is isotropic, meaning it is uniformly distributed in all directions, and it has a characteristic temperature of approximately 2.7 Kelvin (-270.45 degrees Celsius).
It was first detected in 1965 by Arno Penzias and Robert Wilson, who were awarded the Nobel Prize in Physics for their discovery.
The presence of cosmic microwave background radiation provides strong evidence for the Big Bang theory and helps to support the understanding of the early universe's formation and evolution.
It serves as an important tool for studying cosmology and provides insights into the structure, age, and composition of the universe.
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a 87 kg block is pulled across the table by the horizontal force of 43N with a fictional force of 7.3 opposing the motion calculate the acceleration of the object
Answer:
a = 0.41 [m/s²]
Explanation:
To solve this problem we must use Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.
∑F = m*a
where:
F = force [N]
m = mass = 87 [kg]
a = acceleration [m/s²]
The frictional force will be taken as negative, since it opposes the movement of the block.
\(43-7.3 = 87*a\\35.7 = 87*a\\a=0.41[m/s^{2} ]\)
Acceleration is related to velocity and time by the following expression: a=v^p t^q.
Find the powers p and that make this equation dimensionally consistent Enter your answers numerically separated by a comma
Acceleration is related to velocity and time by the following expression: a=v^p t^q. The powers that make the equation dimensionally consistent are p = 1 and q = -2.
In order for the equation to be dimensionally consistent, the units on both sides of the equation must be the same. Acceleration is measured in meters per second squared (m/s^2), velocity is measured in meters per second (m/s), and time is measured in seconds (s).
When we substitute these units into the given expression, we get:
m/s^2 = (m/s)^p s^q
To make the units on both sides equal, we can equate the powers of meters and seconds:
p = 1 (since the velocity has only one meter)
q = -2 (since time has negative two meters)
Substituting these values back into the original expression gives us the dimensionally consistent equation:
a = v t^-2
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how does a battery work ?
Answer:
I completely agree with the first person's response.
Explanation:
They deserve Brainliest. Have a great summer.
A modified Atwood machine is at rest. The hanging block has a mass of 3kg. The black on wheels has unknown mass M1. When released the block m2 falls at 5.88m/s^2. If frictional forces are considered so small they are negligible, the block M1 must have a mass of _______ kg.
Answer:
From the figure,
The free-body diagrams for and are shown in the figures below. The only forces on the blocks are the upward tension and the downward gravitational forces and . Applying Newton’s second law, we obtain:
which can be solved to yield
Substituting the result back, we have
(a) With and , the acceleration becomes
(b) Similarly, the tension in the cord is
ASAP will do brainiest 22 points PLSS HELP
Sports such as football, baseball, soccer, horseback riding, tennis, volleyball, skateboarding, and surfing (to name a few) are full of examples of Newton’s Three Laws of Motion. To answer this question: 1. Choose any sport. Write down the name of the sport. 2. In your own words, state each of Newton’s 3 Laws of Motion and give a clear, specific example of how each law applies to the sport you have chosen.
Answer:
tenis
Tenis applies to each of Newton's 3 Laws of Motion because with the first law if a tenis ball is at rest it will stay at rest unless acted on by an unbalanced force which would be playing tenis in which it would stay in motion. The second law applies since the acceleration at which it is hit times the mass equals the force it has. The third law applies since when hitting a tenis ball back and forth with racquets the reaction may be equal or opposite
if your oven uses a 220.0 volt line and draws a maximum 8.00 A current what is the resistance of the oven when it is fully heated
Answer:
27.5 ohms
Explanation:
V = IR
V / I = R
220/8 = 27.5 Ohms
Experiments performed with light indicate that light exhibits:________
Answer:
Both particle and wave properties
Explanation:
Light is defined as a particle and a wave, and even as a combination of a particle and a wave. A unit of light is the photon. Higher energy photons behave like particles and low energy photons behave like waves.
Experiments performed with light indicate that light exhibits both particle and wave properties.