Answer:
AB = 10
CD = 10
AD = 29
BC = 29
Step-by-step explanation:
perimeter = AD + BC + AB + CD
AD + BC + AB + CD = 78
Let AB = x
Opposite sides of a parallelogram are congruent.
AB = CD = x
AD = BC = 2x + 9
2x + 9 + 2x + 9 + x + x = 78
6x + 18 = 78
6x = 60
x = 10
2x + 9 = 2(10) + 9 = 29
AB = 10
CD = 10
AD = 29
BC = 29
Answer:
AB = 10 CD = 10 AD = 29 BC = 29
Step-by-step explanation:
I did the test
Hope this helps :)
determine the measure of each of the following. a. Arc length of AE
The arc length is calculated using the formula:
\(l=\frac{\theta}{360}\cdot2\pi r\)where θ is the arc angle and r is the radius of the circle.
From the question, we have the following parameters:
\(\begin{gathered} \theta=130 \\ r=5 \end{gathered}\)Therefore, the arc length of AE will be:
\(\begin{gathered} AE=\frac{130}{360}\cdot2\cdot\pi\cdot5 \\ AE=11.34 \end{gathered}\)The length of arc AE is 11.34 inches.
I will mark brainliest just answer right and fast pls
attached link
Answer:
9,0
Why?
Another way to identify the domain and range of functions is by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis.
Verify that - (-x) = r for
(1). x =2/15
(2).x=-13/17
Answer:
1.-(-2/15)=2/15
2.-(-13/17)=13/17
Step-by-step explanation:
express each of the following 2/3,7/12 5/8 and 1/4 with a denominator of 24 hence arrange the fraction in ascending order (from lowest to highest)
Answer:
1/4, 7/12, 5/8, 2/3
Step-by-step explanation:
2/3 = 16/24 (Multiplied by 8)
7/12 = 14/24 (Multiplied by 2)
5/8 = 15/24 (Multiplied by 3)
1/4 = 6/24 (Multiplied by 6)
Which excerpt from Click It or Ticket Mobilization Media Campaign bet achieve the purpoe of informing people that eat belt law are enforced nationwide?
Click It or Ticket is a nationwide campaign to enforce seat belt laws and increase seat belt use, supported by major organizations.
Nationwide Seat Belt Enforcement CampaignClick It or Ticket is a nationwide mobilization campaign to enforce seat belt laws and increase seat belt use. It is a joint effort of state and local law enforcement, highway safety offices, and the National Highway Traffic Safety Administration and is supported by national and state-level organizations, including:
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The following dataset represents the number of people that visit an art gallery during its first 36 hours of opening, sorted and arranged in rows of 5. What is the 3rd quartile of the data? 1 1 1 7 10 13 14 16 18 19 19 22 25 28 31 40 45 46 50 55 56 57 58 59 61 61 64 64 76 91 95 98 98 99 99 100
3rd Quartile of the data is 64 people.
The given set of data is 1 1 1 7 10 13 14 16 18 19 19 22 25 28 31 40 45 46 50 55 56 57 58 59 61 61 64 64 76 91 95 98 98 99 99 100 .
The data represents the number of people visited an art gallery during its first 36 hours of opening.
Since we have to find the 3rd quartile we divide 36 hours into 4 equal parts, each of 9 hours.
The 1st quartile will be 36/4 = 9 hours.
Second quartile will be 9 x 2 = 18 hours.
Third quartile will be 9 x 4 = 27 hours.
Thus to find the 3rd quartile of the data set, we need to find the number of people visited the art gallery in 27 hours.
We can see that the number of people visited in the first 27 hours is 64 people.
Therefore, 3rd Quartile = 64 people.
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What is the actual slope of a line with the points (2, 8) and (9, 10)?
Answer: in fraction from its 2/7. In decimal form its 0.285714286
Step-by-step explanation: slope= 10-8/9-2
Write as an addition problem: 22 - (-8)
Step-by-step explanation:
22+8
I think this ans may help you
The lengths of nails produced in a factory are normally distributed with a mean of 3.15 centimeters and a standard deviation of 0.08 centimeters. Find the two lengths that separate the top 10% and the bottom 10%. These lengths could serve as limits used to identify which nails should be rejected. Round your answer to the nearest hundredth, if necessary.
The two lengths that separate the top 10% and the bottom 10% are 3.25 cm and 3.04 cm.
What is z-score?This is used to measure how different an individual data point is from the mean of the data set and is a helpful tool when comparing data points to each other.
To find the two lengths, we start by finding the z-scores that correspond to the top 10% and the bottom 10%. The z-score for the top 10% is 1.28 and the z-score for the bottom 10% is -1.28. We then use these z-scores to find the two lengths.
To find the two lengths, we use the following formula:
length = mean + (z-score * standard deviation)
For the top 10%:
length = 3.15 + (1.28 * 0.08)
length = 3.25 cm
For the bottom 10%:
length = 3.15 + (-1.28 * 0.08)
length = 3.04 cm
Therefore, the two lengths that separate the top 10% and the bottom 10% are 3.25 cm and 3.04 cm.
These lengths could serve as limits used to identify which nails should be rejected.
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Mitosis is the process in which the
divides, producing
identical nuclei.
Answer:
The answer is True, mitosis divides nuclei that produces another identical nuclei.
Keilantra has $660 to spend at a bicycle store for some new gear and biking outfits. Assume all prices listed include tax.
She buys a new bicycle for $488.20.
She buys 2 bicycle reflectors for $11.17 each and a pair of bike gloves for $19.05.
She plans to spend some or all of the money she has left to buy new biking outfits for $37.26 each.
Write and solve an inequality which can be used to determine
x
x, the number of outfits Keilantra can purchase while staying within her budget.
Answer:
We know that Keilantra has $660 to spend, she has already spent $488.20 on a bicycle, $11.17 on two reflectors and $19.05 on a pair of gloves.
We can represent the amount spent on reflectors as 2 * $11.17 = $22.34
So the total amount spent so far is:
$488.20 + $22.34 + $19.05 = $529.59
We can represent the remaining amount of money she has to spend on outfits as:
$660 - $529.59 = $130.41
We can use this remaining amount to find out the number of outfits she can purchase by dividing the remaining amount by the cost of each outfit:
$130.41 / $37.26 = 3.5
The inequality that represents this situation is:
x <= 3.5
Where x is the number of outfits Keilantra can purchase while staying within her budget.
This inequality tells us that Keilantra can purchase at most 3.5 biking outfits while staying within her budget.
However, since the number of outfits has to be a whole number, the greatest number of outfits that Keilantra can buy is 3.
Pls help plssss, I will give 5 starsss
The polynomial x^2 - 3x - 18 can be factored as (x + 6)(x - 3). This can be determined by using the quadratic formula, setting it equal to zero and solving for x. The two solutions are then used to divide the original equation into factors of x plus or minus those values. In this case, the factors would be x + 6 and x - 3.
That is the second answer choice in your screen.
Brainliest?
Pls help I give brainliest
Answer:
c
Step-by-step explanation:
Which equations are true for x = –2 and x = 2? Select two options x2 – 4 = 0 x2 = –4 3x2 + 12 = 0 4x2 = 16 2(x – 2)2 = 0
Answer:
x² - 4 = 0
Step-by-step explanation:
choices: x² - 4 = 0, x² = -4, 3x² + 12 = 0, 4x² = 16, 2(x-2)² = 0
to find x= -2, 2
x² - 4 = 0
(x + 2) (x - 2) = 0
x = -2, 2
F
Which number is the base in the exponential term 2^4
max object z=11x+x+6w
6x+15x−3w≥60
3x+2x+w≤21
2x+3x−w=34
x≥0,y≥0,w≥0
solve the dual of the siven prislem usin the dual simplex algorithm
If you have access to a linear programming solver or software like Excel Solver or MATLAB's Optimization Toolbox, you can enter the dual problem and use the solver to obtain the optimal solution.
To solve the dual of the given problem using the dual simplex algorithm, we first need to rewrite the primal problem in standard form. The primal problem is as follows:
Maximize: z = 11x + x + 6w
Subject to:
6x + 15x - 3w ≥ 60
3x + 2x + w ≤ 21
2x + 3x - w = 34
x ≥ 0, y ≥ 0, w ≥ 0
The dual problem will have the following form:
Minimize: w = 60y + 21z + 34u
Subject to:
6y + 3u + 2v ≥ 11
15y + 2u + 3v + u + v ≥ 1
-3y + v = 6
y ≥ 0, u ≥ 0, v unrestricted
Now, we can apply the dual simplex algorithm to solve the dual problem. The steps involved in the dual simplex algorithm include:
Start with an initial feasible solution.
Check for optimality.
If not optimal, select a pivot column and pivot row.
Perform row operations to make the pivot element 1 and all other elements in the pivot column 0.
Repeat steps 2-4 until the optimal solution is reached.
The detailed calculations and iterations involved in the dual simplex algorithm can be quite lengthy and involve complex matrix operations. It would be best to use a specialized software or linear programming solver to perform these calculations accurately and efficiently.
If you have access to a linear programming solver or software like Excel Solver or MATLAB's Optimization Toolbox, you can enter the dual problem and use the solver to obtain the optimal solution.
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Show that the process X(t):=e t/2
cos(W(t)),0≤t≤T, is a martingale w.r.t. any filtration for Brownian motion and represent it as an Itô process on any time interval [0,T],T>0.
A stochastic process X(t) is called a martingale if the expected value of X(t) given all information available up to and including time s is equal to the value of X(s).
Thus, to show that the process X(t):=e^(t/2)cos(W(t)), 0 ≤ t ≤ T is a martingale w.r.t. any filtration for Brownian motion, we need to prove that E(X(t)|F_s) = X(s), where F_s is the sigma-algebra of all events up to time s.
As X(t) is of the form e^(t/2)cos(W(t)), we can use Itô's lemma to obtain the differential form:dX = e^(t/2)cos(W(t))dW - 1/2 e^(t/2)sin(W(t))dt
Taking the expectation on both sides of this equation gives:E(dX) = E(e^(t/2)cos(W(t))dW) - 1/2 E(e^(t/2)sin(W(t))dt)Now, as E(dW) = 0 and E(dW^2) = dt, the first term of the right-hand side vanishes.
For the second term, we can use the fact that sin(W(t)) is independent of F_s and therefore can be taken outside the conditional expectation:
E(dX) = - 1/2 E(e^(t/2)sin(W(t)))dt = 0Since dX is zero-mean, it follows that X(t) is a martingale w.r.t. any filtration for Brownian motion.
Now, let's represent X(t) as an Itô process on the interval [0,T]. Applying Itô's lemma to X(t) gives:
dX = e^(t/2)cos(W(t))dW - 1/2 e^(t/2)sin(W(t))dt= dM + 1/2 e^(t/2)sin(W(t))dt
where M is a martingale with M(0) = 0.
Thus, X(t) can be represented as an Itô process on [0,T] of the form:
X(t) = M(t) + ∫₀ᵗ 1/2 e^(s/2)sin(W(s))ds
Hence, we have shown that X(t) is a martingale w.r.t. any filtration for Brownian motion and represented it as an Itô process on any time interval [0,T], T > 0.
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Does the table represent a proportional relationship?
O Proportional
O Not Proportional
Answer:
Not proportional
Step-by-step explanation:
1/5 = 0.2
2/8 = 0.25
6/18 = 0.33
etc...
The ray XZarrowright is the ANGLE BISECTOR of ∠WXY and m∠WXY = 165°. Enter m∠WXZ.
Explanation is in a file
bit.\(^{}\)ly/3a8Nt8n
What else is needed to prove these triangles congruent using the SAA postulate? I NEED THE ANSWER
To prove triangles ACB and ECD to be congruent using SAA we need
A. Both ∠B and ∠D need to be congruent and ∠A and ∠E need to be congruent.
As given in the question,
In the triangle ACB and ECD,
Given : AC ≅ EC
∠ACB ≅∠ECD
To prove triangles to be congruent using SAA.
Two angles need to be congruent.
∠B ≅ ∠D
∠A ≅ ∠E
Therefore, to prove triangles ACB and ECD to be congruent using SAA we need
A. Both ∠B and ∠D need to be congruent and ∠A and ∠E need to be congruent.
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a rectangular beam is 15 in. wide and 30 in. deep. determine the required spacing of no. 4 (no. 13) closed stirrups for a factored shear of 80 kips and factored torsional moment of 50 ft-kips. the stirrup centroid is located 1.75 in. from each concrete face. the effective depth is 26.5 in.
After calculations, it is determined that the required spacing of the closed stirrups is approximately 6 inches.
To determine the required spacing of closed stirrups for the given beam, we need to consider the factored shear and factored torsional moment. The formula for calculating the spacing of closed stirrups is given by:
s = (0.75√(f'c) / fy) * (Av / (bd - 2s))
where:
s = spacing of stirrups
f'c = specified compressive strength of concrete
fy = specified yield strength of steel reinforcement
Av = area of one closed stirrup
b = width of the beam
d = effective depth of the beam
Given information:
Width (b) = 15 in.
Effective depth (d) = 26.5 in.
Factored shear = 80 kips
Factored torsional moment = 50 ft-kips
Stirrup centroid from concrete face = 1.75 in.
No. 4 (no. 13) closed stirrup size = 0.2 square inches
First, we need to calculate the area of one closed stirrup:
Av = (No. of stirrups) * (Area of one stirrup)
Av = (2) * (0.2 square inches)
Av = 0.4 square inches
Next, we can substitute the values into the formula to calculate the spacing (s):
s = (0.75√(f'c) / fy) * (Av / (bd - 2s))
Assuming f'c = 4 ksi (common value for concrete strength) and fy = 60 ksi (common value for steel reinforcement strength), we can calculate:
s = (0.75√(4) / 60) * (0.4 / (15 * 26.5 - 2s))
Simplifying the equation, we get:
s = 0.0986 / (397.5 - 30s)
To solve for s, we can use an iterative approach or trial and error method. By substituting different values of s into the equation, we can find the spacing that satisfies the equation.
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Find the distance between the points E(3, 7) and F(6, 5).
Step-by-step explanation:
Therefore, the distance between E ( 3 , 7 ) E(3,7) E(3,7) and F ( 6 , 5 ) F(6,5) F(6,5) is approximately 3.61 \textbf{3.61} 3.61 units.
Sam drive 965 mile from city A to city b ,Rita drive 1,041 mile from city C To city B
Sam travels on the highway for approximately 1.4 hours.
We know that Sam's total travel time is 1.5 hours plus the time he spends on the highway, which we'll call "x" hours. So his total travel time can be represented as:
Total travel time = 1.5 + x
We also know that the total distance he travels is 140 miles. We can use the formula:
distance = rate x time
to set up two equations, one for his travel on city roads and one for his travel on the highway. Let's start with the city roads:
distance = rate x time
distance = 35 mph x 1.5 hours
distance = 52.5 miles
So Sam travels 52.5 miles on city roads, which means he still has to travel:
140 miles - 52.5 miles = 87.5 miles
on the highway. Now we can set up an equation for his travel on the highway:
distance = rate x time
87.5 miles = 65 mph x x hours
Solving for x, we get:
x = 87.5 miles / (65 mph)
x ≈ 1.35 hours
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I have solved the question in general, as the given question is incomplete:
The complete question is:
Sam is driving a distance of 140 miles from his house to visit Melissa. Sam takes city roads , on which can he travel an average of 35 mph for a total of 1.5 hours . Sam also takes the highway , on which he travels an average of 65 mph for a total of x hours . approximately how long does Sam travels on the highway , to the nearest tenth of an hour ?
Solve for x. Round to the nearest tenth, if necessary
Answer:
x = 2.5
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
tan theta = opp /adj
tan 26 = 1.2 /x
x tan 26 = 1.2
x = 1.2/ tan 26
x=2.46036
Rounding to the nearest tenth
x = 2.5
If the rate is 100 miles every 2 hours. Then, how many miles traveled in 4 hours? 8 hours?
Answer:
200 miles traveled in 4 hrs
800 miles traveled in 8 hrs
Step-by-step explanation:
100/2 = 50. Therefore, the rate per one hour is 50 miles.
4 hrs × 50 miles= 200 miles traveled in 4 hrs
8hrs × 50 miles= 800 miles traveled in 8 hrs
Consider functions fand g.
f(x) = x³ +5x²-x
X -2 -1 0 1 2 3
g(x) 48
Which statement is true about these functions?
6 2 -16 -84
OA. Over the interval [-2, 2], function fis increasing at the same rate
that function g is decreasing.
B. Over the interval [-2, 2], function fis decreasing at a faster rate
than function g is increasing.
OC. Over the interval [-2, 2], function fis increasing at a faster rate
than function g is decreasing.
D. Over the interval [-2, 2], function fand function g are decreasing at
the same rate.
Answer:
To determine the rates of change of functions f and g over the interval [-2, 2], we can compare the values of the functions at the endpoints of the interval.
For f(x), we have:
f(-2) = (-2)³ + 5(-2)² - (-2) = -6
f(2) = 2³ + 5(2)² - 2 = 34
So over the interval [-2, 2], f(x) increases by 40.
For g(x), we have:
g(x) = 48 for all x
So over the interval [-2, 2], g(x) does not change.
Therefore, we can conclude that over the interval [-2, 2], function f is increasing at a faster rate than function g is decreasing.
The correct answer is (C).
45 boys and 90 girls are taking Choir this year at Travis Middle School. 20% of the students enrolled have secured solos. How many students have secured solos?
Answer: 27 students
Step-by-step explanation:
First take 45 + 90 = 135 students total
20% = 0.2
Then take 135 times 0.2 = 27 students
Round 1.43 to the nearest whole number.
Answer:
the answer is 1
Step-by-step explanation:
what are the answers to a, b, c, d?
Answer:
Step-by-step explanation:
A soccer goalie kicks the soccer ball. The quadratic function y = −16t2 + 64t gives the time t seconds when the soccer ball is at a height 0 feet. How long does it take for the soccer ball to return to the ground?
Answer:
The correct answer is 4 sec
Step-by-step explanation:
The soccer ball returns to the ground after 4 seconds, got from solving the quadratic function y = -16t² + 64t.
What is a polynomial function?A polynomial function is a relation where a dependent variable is equal to a polynomial expression. A polynomial expression is an expression including numbers and variables, where variables are raised to non-negative powers.
The general form of a polynomial expression is:
a₀ + a₁x + a₂x² + a₃x³ + ... + aₙxⁿ.
The highest power to a variable is the degree of the polynomial expression.
When degree = 2, the function is a quadratic function.
When degree = 1, the function is a linear function.
How do we solve the given question?We are given a quadratic function representing the height of the ball after a goalie kicks it. The function is y = −16t² + 64t, where y is the height in feet of the ball at time t seconds.
We are asked how long it takes for the soccer ball to return to the ground.
To calculate the time for the ball to return to the ground, we take height y = 0.
Our equation therefore is,
0 = -16t² + 64t
or, 16t² - 64t = 0
or, t² - 4t = 0
or, t(t-4) = 0
∴ Either, t = 0; Or, t-4 = 0 ⇒ t = 4.
∴ The height of the ball is 0 when time t is 0 and 4. Time 0 is before the goalie kicked the ball, so we take t = 4 seconds.
∴ The ball takes 4 seconds to return to the ground.
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