According to the given statement The asteroid's orbital period is 2.74 years.
Does an asteroid have an orbit?Asteroids are tiny, rocky bodies that revolve around the Sun. Asteroids are far tiny than planets, although orbiting the Sun in a manner comparable to planets. There are many asteroids in our solar system. The major asteroid belt, which lies between Mars' and Uranus orbits, is where the majority of them have been located.
Briefing:T1 = 1 year
r1 = 150 million km
r2 = 440 million km
Let T2 be the asteroid's orbital period.
Use Kepler's third law
T² ∝ r³
So,
(T₂ / T₁)² = (r₂ / r₁)³
(T₂ / 1)² = (295 / 150)³
T2 = 2.74 years
Therefore, the asteroid's orbital period is 2.74 years.
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define 1 pascal pressure
Answer:For example, standard atmospheric pressure (or 1 atm) is defined as 101.325 kPa. The millibar, a unit of air pressure often used in meteorology, is equal to 100 Pa. (For comparison, one pound per square inch equals 6.895 kPa.)
Explanation:A pascal is a pressure of one newton per square metre, or, in SI base units, one kilogram per metre per second squared.
I hope this helps.... I'm sorry if it doesn't
In the SI unit system, time (t) is measured in seconds, distance (d) ismeasured in meters, velocity (v) is measured in meters per second,and acceleration (a) is measured in meters per second squared.Based on This units select the following expressions that could be valid expressions. a= sqr*root inside vd/t^3. V=a/t A=d/t^2 t= cubc* root inside d^2/va. V=at. D=at
Given
List of expression
\(a=\sqrt[\square]{\frac{vd}{t^3}}\)YES
\(v=\frac{a}{t}\)NO
\(a=\frac{d}{t^2}\)YES
\(t=\sqrt[3]{\frac{d^2}{va}}\)YES
\(v=at\)YES
\(d=at\)NO
Is kinetic energy conserved in an elastic collision.
An elastic collision is a collision in which there is no net loss in kinetic energy in the system as a result of the collision. Both momentum and kinetic energy are conserved quantities in elastic collisions. ... They collide, bouncing off each other with no loss in speed.
When can acceleration be observed and what result will it have on an object?
Answer:
Work out the change in velocity for you given time.
Calculate the change in time for the period you are considering.
Divide the change in velocity by the change in time.
can increase the velocity of the object, decrease the velocity of the object, or change the direction of the velocity of the object.
Explanation:
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calculate the magnitude of the centripetal force acting on earth as it orbits the sun
The magnitude of the centripetal force acting on Earth as it orbits the Sun can be calculated using Newton's law of universal gravitation and the principles of circular motion.
According to Newton's law of universal gravitation, the force of gravity between two objects is given by the equation F = G * (m1 * m2) / r^2, where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between their centers of mass.
In the case of Earth orbiting the Sun, Earth's mass (m1) is much smaller than the Sun's mass (m2), so we can consider Earth as the smaller mass. The centripetal force acting on Earth is provided by the gravitational force between Earth and the Sun.
The centripetal force can be expressed as Fc = m1 * (v^2) / r, where m1 is the mass of Earth, v is the velocity of Earth in its orbit, and r is the distance between the centers of Earth and the Sun.
Since the centripetal force is provided by the gravitational force, we can equate the two equations: Fc = F. Therefore, m1 * (v^2) / r = G * (m1 * m2) / r^2.
Simplifying the equation, we find that (v^2) / r = G * m2 / r^2.
The magnitude of the centripetal force can be obtained by rearranging the equation as Fc = m1 * (v^2) / r = (m1 * G * m2) / r^2.
Therefore, the magnitude of the centripetal force acting on Earth as it orbits the Sun is given by (m1 * G * m2) / r^2, where m1 is the mass of Earth, m2 is the mass of the Sun, G is the gravitational constant, and r is the distance between their centers.
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Find the magnitude and direction of
the net force being acted on the
free body diagram below.(look at the picture I provided)
Explanation:
Pick your direction of the perpendicular forces.
Let down be negative and up be positive.
Remember that sum of all the forces is the net force,
So for the vertical forces, we have
\(45 + ( - 45) = 0\)
Next, pick your direction of the parallel forces.
Let right be positive and left be negative so we have
\(15 + ( - 45) = - 30\)
So our net force is 30 N to the left
What is meant by the statement that you don’t “own” the atoms that make up your body?
Answer:
there are as many atoms in a normal breath of air as there are breathfuls of air in the atmosphere of the world
Explanation:
the bose? (The weightidensty of water is 62.4 pounds per outec foct.) 7f−lb [0/1 Points] LARCALCET7 7. 5,027Mi
The weight density of water is 62.4 pounds per cubic foot. This value is used to determine the weight of water based on its volume.
The weight density of a substance is a measure of how much weight it has per unit volume. In the case of water, its weight density is 62.4 pounds per cubic foot. This means that for every cubic foot of water, it will weigh 62.4 pounds.
Weight density is an important concept in various fields, such as engineering, construction, and fluid mechanics. It allows us to calculate the weight of water in different scenarios. For example, if we have a tank with a known volume of water, we can use the weight density to determine the total weight of the water in the tank. Similarly, if we know the weight of water in a container, we can calculate its volume by dividing the weight by the weight density.
Understanding the weight density of water is crucial for various practical applications. It helps in designing structures that involve water, such as dams, reservoirs, and pipes, as it provides insights into the forces exerted by the water. Additionally, it is also relevant in fields like hydrology and environmental science, where accurate measurements of water weight are necessary for calculations and analysis.
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The recommended initial dose of mercaptopurine is 1.5 mg/kg/day p.o. the recommended daily dosage for a child weighing 44 lb is _______________
In conclusion, to calculate the recommended daily dosage of mercaptopurine for a child weighing 44 lb, we need to convert the weight to kilograms and then multiply it by the recommended initial dose. This results in a dosage of approximately 29.7 mg/day.
The recommended initial dose of mercaptopurine is 1.5 mg/kg/day p.o. To calculate the recommended daily dosage for a child weighing 44 lb, we need to convert the weight from pounds to kilograms.
First, we know that 1 lb is equal to approximately 0.45 kg. So, we can calculate the weight of the child in kilograms by multiplying 44 lb by 0.45 kg/lb.
44 lb * 0.45 kg/lb = 19.8 kg (rounded to one decimal place)
Now that we have the weight in kilograms, we can calculate the recommended daily dosage by multiplying the weight by the recommended initial dose of 1.5 mg/kg/day.
19.8 kg * 1.5 mg/kg/day = 29.7 mg/day (rounded to one decimal place)
Therefore, the recommended daily dosage for a child weighing 44 lb is approximately 29.7 mg/day.
In conclusion, to calculate the recommended daily dosage of mercaptopurine for a child weighing 44 lb, we need to convert the weight to kilograms and then multiply it by the recommended initial dose. This results in a dosage of approximately 29.7 mg/day.
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why is it better to hold a musical events or programs in the evening?
Answer:
sound travels faster in the night
Explanation:
2. Amy runs exactly 2 laps around a 400 meter track. What is her distance and displacement?
Amy's distance is 800 meters since she runs 2 laps around the 400 meter track. Her displacement is 0 meters because displacement refers to the change in position from the starting point to the end point, and since she ends up back where she started, the displacement is zero.
Distance refers to the total length covered in a particular path, regardless of direction or position. Amy runs 2 laps, and each lap is 400 meters, so her total distance is 800 meters (400 meters per lap multiplied by 2 laps).
Displacement, on the other hand, refers to the change in position from the starting point to the end point. Since Amy ends up back at the starting point after completing her 2 laps, her displacement is zero. Displacement takes into account direction and position, and in this case, there is no net change in position from the start to the end, resulting in a displacement of zero.
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Two carts with masses of 4.0 kg and 3.3 kg move toward each other on a
frictionless track with speeds of 5.9 m/s and 4.6 m/s, respectively. The carts stick
together after colliding head-on. Find their final speed. Answer in units of m/s.
Crash of two vehicles that are moving directly toward each other
What is the final speed?This is a difficulty with momentum conservation. Each cart has a starting momentum equal to its mass multiplied by its velocity. When they hit and stick together, they become a single unit of combined mass of 4 kg + 5 kg, and their new velocity must account for momentum conservation.
Assume the 4 kilogram cart is coming from the left and the 5 kg cart is coming from the right. This results in a velocity of +12 m/s for the 4 kg cart and a velocity of -9 m/s for the 5 weight cart.
The carts’ early moments are
(4 kg * 12 m/s) = 48 kg * m/s
And
-45 (kg * m)/s = (5 kg * -9 m/s)
This results in a total starting momentum of 48 + (-45) = 3 (kg * m)/s.
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Answer Questions below
Answer:
When several resistors are connected in series, the total resistance equals the sum of the individual resistors. In series combination, the current is same through each resistor.
1) V= 60 volt
Total resistance R = R₁ + R₂
= 20 + 10
= 30 Ω
2) Ohms law states that,
\(\sf I =\dfrac{V}{R}\\\\\\I = \dfrac{60}{30}\\\\I = 2 \ A\)
3) Voltage around 10 Ω resistor,
V₂ = I R₂
= 2 * 10
= 20 volt
___________________________________________________
4) Total current = 1 A
5) Total voltage = 8 volt
6) Voltage around R₁ is V₁
R₁ = 2 Ω ; I = 1 A
V₁ = IR₁
= 1 * 2
= 2 volt
7) Resistance 2:
Total resistance = R
Total voltage = V = 8 volt
Total current = I = 1 A
\(\sf R = \dfrac{V}{I}\\\\\\ R = \dfrac{8}{1}\\\\\)
R = 8 Ω
R₁ + R₂ = 8 Ω
2 + R₂ = 8
R₂ = 8 - 2
R₂ = 6 Ω
8)Voltage around R₂:
\(\sf V_2 = IR_2\\\\V_2 = 1*6\\\\\)
V₂ = 6 volt
9) Total R = 8 Ω
_________________________________________________
10) Total V = 12 volt
11) Total R = 8 + 8
= 16 Ω
12) Total current I,
\(\sf I = \dfrac{V}{R}\\\\I = \dfrac{12}{16}\\\\I = 0.75 \ A\)
13) Voltage at each resistor:
V₁ = I*R₁
= 0.75 * 8
= 6 volt
V₂ = I*R₂
= 0.75 * 8
= 6 volt
_______________________________________________________
14) Total R = 40 + 20
= 60 Ω
15) To find V₁, first find total voltage.
I = 2 A ; R = 60 Ω
V = IR
= 2 * 60
= 120 V
V₁ + V₂ =V
V₁ + 80 = 120
V₁ = 120 - 80
V₁ = 40 volt
Explain why the question "Put these bodies in order of
increasing size (black hole, neutron star, white dwarf):" is a
"bad" question to ask on an exam?
The question "Put these bodies in order of increasing size (black hole, neutron star, white dwarf):" is a "bad" question to ask on an exam because the size of a black hole cannot be measured.
The question provides three celestial bodies and asked to arrange them according to their size. The first problem is with the black hole. The black hole is a celestial body that has infinite density and zero volume, which implies that it does not have a size. Thus, it is impossible to compare the sizes of black holes with other celestial bodies.
The second problem is that the sizes of white dwarfs and neutron stars are hard to measure accurately. It is almost impossible to compare the sizes of celestial bodies in the universe since the universe contains many celestial bodies of various sizes. Thus, the question should have been modified to make it less vague and less difficult. The better way to ask the question might have been "Put these celestial bodies in order of increasing mass."
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with what tension must a rope with length 2.10 m and mass 0.110 kg be stretched for transverse waves of frequency 36.0 hz to have a wavelength of 0.760 m ?
To find the tension in the rope, we can use the equation: v = fλ, where v is the speed of the wave, f is the frequency, and λ is the wavelength.
The speed of a wave on a rope is given by: v = √(T/μ), where T is the tension in the rope and μ is the mass per unit length of the rope.
We can rearrange this equation to solve for T: T = μv^2
Substituting the expression for v from the first equation, we get:
T = μ(fλ)^2
Plugging in the given values, we get:
T = (0.110 kg / 2.10 m)(36.0 Hz)(0.760 m)^2
T = 37.5 N
Therefore, the tension in the rope must be 37.5 N for transverse waves of frequency 36.0 Hz to have a wavelength of 0.760 m.
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why can't you run from momentum?
The greatest number of galaxies belong to the type known as elliptical galaxies.a. Trueb. False
False. The greatest number of galaxies do not belong to the type known as elliptical galaxies. In fact, the most common type of galaxy in the universe is the spiral galaxy.
Spiral galaxies are characterized by their distinctive spiral arms, which contain young stars, gas, and dust. These galaxies have a central bulge and a rotating disk. Examples of spiral galaxies include our own Milky Way galaxy and the Andromeda galaxy.
Elliptical galaxies, on the other hand, have a more rounded or elliptical shape and lack the prominent spiral arms. They are often reddish in color and have older populations of stars. Elliptical galaxies are typically found in galaxy clusters and are thought to have formed through galaxy mergers and interactions.
While elliptical galaxies are still abundant in the universe, they are not the most numerous type. Studies and observations have shown that spiral galaxies outnumber elliptical galaxies by a significant margin. This is supported by surveys and statistical analyses of large samples of galaxies in different regions of the universe.
The distribution and abundance of galaxy types can provide valuable insights into the formation and evolution of galaxies over cosmic time. Understanding the prevalence of different galaxy types helps astronomers piece together the story of how galaxies form, grow, and interact with their environments.
In conclusion, the statement that the greatest number of galaxies belong to the type known as elliptical galaxies is false. The most common type of galaxy in the universe is the spiral galaxy.
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Which electrical component is used for detecting light levels in digital cameras?
The electrical component that is used for detecting light levels in digital cameras is the light meter.
What are light meters?A light meter is a device used to measure the amount of light. In photography industry, a light meter is used to determine the proper exposure for a photograph.
A digital camera is a camera that captures photographs in digital memory.
Most digital cameras can be grouped into four main types which includes:
digital SLR (or DSLR), point-and-shoot, bridge cameras, and camera phones.Each type of these digital cameras has advantages and disadvantages, and some the types are more expensive than their counterparts.
There are two different kinds of light meters which are:
incident and reflective.-An incident light meter measures all the light falling onto a subject. Incident light meters help a camera focus on a subject regardless of how light or dark the surrounding background is.
- Reflective light meters on the other hand do the opposite by measuring the light reflected by or bouncing off a subject.
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Given the densities of five objects: 2.00 grams/cm^3, 3.00 grams/cm^3, 4.00 grams/cm^3, 5.00 grams/cm^3, and 6.00 grams/cm^3. How many of these objects would float in water? A)1 B)2 C)3 D)4 E)0
Givne densities are,
\(\begin{gathered} \rho_1=2\text{ g/}cm^3 \\ \rho_2=3\text{ g/}cm^3 \\ \rho_3=4\text{ g/}cm^3 \\ \rho_4=5\text{ g/}cm^3 \end{gathered}\)The density of water is ρ=1 g/cm³.
Any object will float if the denisty of the object is less than the density of water, if the density of object is greater than the dnesity of water, then the object sink in the water.
In the given case, all the objects have density greater than the density of water. Therefore, all the objects will sink in the water.
Thus, option E is corret, no object will flot on the water.
please answer 11-13. say if i'm right for 10 if you can.
How do you know if a resistor is in series or parallel?
When resistance is linked in series with other resistance, as opposed to parallel, where the same nodes are connected in the same directions.
When two nodes share terminal connections, resistors are said to be in parallel. It makes no difference whether the resistors are drawn horizontally or vertically. All of the parts of a series circuit are attached end to end, creating a single route for current flow. All of the components of a parallel circuit are linked across one another to create precisely two sets of electrically coupled points.
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What can occur when air rises in a low pressure system?
When air rises in a low-pressure system, it can lead to the formation of clouds and precipitation, such as rain or snow. The rising air also cools and condenses, releasing latent heat, which can further contribute to the development of the storm.
What happens in a low-pressure system?A low-pressure system is a weather pattern characterized by a region of lower atmospheric pressure compared to the surrounding areas. It is often associated with unsettled and stormy weather.
How are clouds formed?Clouds are formed when moist air rises and cools, causing water vapour to condense into tiny water droplets or ice crystals. This process occurs when the temperature of the air decreases, either because it is rising, or because it is mixing with cooler air.
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Starting from rest, a car accelerates at a rate of 7.2 m/s2 for 4.5 seconds. what is its velocity at the end of this time?
A car starts from rest and undergoes an acceleration of 7.2 m/s² for a duration of 4.5 seconds. The objective is to determine the velocity of the car at the end of this time.
Velocity of the car at the end of the given time, we can use the equation of motion that relates initial velocity, acceleration, and time:
final velocity = initial velocity + (acceleration × time)
Since the car starts from rest (initial velocity = 0), the equation simplifies to:
final velocity = acceleration × time
Plugging in the given values, we have:
final velocity = 7.2 m/s² × 4.5 s
Calculating the expression, we find:
final velocity = 32.4 m/s
Therefore, the velocity of the car at the end of 4.5 seconds, after accelerating at a rate of 7.2 m/s², is 32.4 m/s.
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To prepare homemade ice cream, a crank must be turned with a torque of 3.95N*m. How much work is required for each complete turn of the crank?
To determine the work required for each complete turn of the crank when preparing homemade ice cream with a torque of 3.95 N*m, you can follow these steps:
1. Identify the given values: torque (τ) = 3.95 N*m.
2. Remember that work (W) is calculated by multiplying the torque (τ) by the angle in radians (θ): W = τ * θ.
3. Since we want the work required for each complete turn of the crank, the angle (θ) should be in radians for a full rotation, which is 2π radians.
4. Plug the values into the equation: W = 3.95 N*m * 2π radians.
Your answer: To prepare homemade ice cream, if a crank must be turned with a torque of 3.95 N*m, the work required for each complete turn of the crank is approximately 24.83 J (joules).
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A 5.00kg firecracker explodes into two parts: one part has a mass of 3.00kg and moves at a velocity of 25.0m/stowards the west. The other part has a mass of 2.00kg. What is the velocity of the second piece as a result of the explosion?
The velocity of the second piece of the firecracker of mass 5.00kg as a result of explosion is 37.5 m/s.
What is velocity?Velocity can be defined as the rate of change of displacement of a body.
To calculate the velocity of the second piece, we use the formula below.
Formula:
MV = mv..............Equation 1Where:
M = Mass of the first part of the firecrackerV = Velocity of the first part of the firecrackerm = Mass of the second part of the firecrackerv = Velocity of the second part of the firecracker.Make v the subeject of the equation
v = MV/m.......... Equation 2From the question,
Given:
M = 3 kgV = 25 m/sm = 2 kgSubstitute these values into equation 2
v = (3×25)/2v = 37.5 m/sHence, the velocity of the second piece is 37.5 m/s.
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A car is sitting still what could cause the car to move
The velocity of a ball about the elbow joint is 30.0rad/s and the ball is 1.30 m from the elbow joint what is he velocity of the ball
Answer:
39.0 meters per second
Explanation:
So the linear speed of the ball then is that distance from the pivot to the ball times by the angular speed. So this is 1.30 meters times 30.0 radians per second which is 39.0 meters per second.
Which statement is true about historical models of the solar system?
1.) The heliocentric model was the first model of the solar system.
2.)Astronomers developed questions from observations that the geocentric model could not answer.
3.)In the heliocentric model every astronomical body travels in perfect circles.
4.)Old explanations about the natural world are always wrong.
how are electromagnets used in communication{plsssssssssssssssss pu!!! deadline na next week !!!!!}
Radio works by transmitting and receiving electromagnetic waves. The radio signal is an electronic current moving back and forth very quickly. A transmitter radiates this field outward via an antenna; a receiver then picks up the field and translates it to the sounds heard through the radio
Answer:
radio work by transmitting and receiving electro magnetic waves.
Em um centro de distribuição uma empilhadeira carrega uma caixa de 1000kg até o caminhão responsável pelo transporte desta carga. Partindo do repouso a empilhadeira precisa percorrer uma certa distância 8,4 m para atingir a sua velocidade máxima de operação 10 k/h. Determine a força média necessária para acelerar essa carga.
Answer:
F = 592238.09 N
Explanation:
To find the mean force you first calculate the acceleration by using the following kinematic equation:
\(v^2=v_o^2+2ax\\\\v_o=0m/s\\\\v=10km/h\\\\x=8.4m\\\\\)
you do "a" the subject of the equation and replace the values of the other parameters:
\(a=\frac{v^2}{2x}=\frac{10000m/s}{2(8.4m)}=595.23\frac{m}{s^2}\)
next, the force, by using the second Newton law is:
\(F=ma=(1000kg)(595.23\frac{m}{s^2})=595238.09\ N\)
hence, the force is 592238.09 N
- - - - - - - - - - - - - - - - - - - - - - - - - - -
TRANSLATION:
Para encontrar a força média, primeiro calcule a aceleração usando a seguinte equação cinemática:
você faz "a" o assunto da equação e substitui os valores dos outros parâmetros:
Em seguida, a força, usando a segunda lei de Newton, é:
portanto, a força é 592238.09 N