The persistence of vision for normal eye is

Answer:

Suppose the micrometeoroid weighed 1 g = .001 kg

Suppose also the spacecraft were moving at 18,000 mph (1.5 hrs per rev)

Usually, the smaller particle would be moving but for simplicity suppose that it were stationary wrt the ground

v = 18000 miles / hr * 1500 m/mile / 3600 sec/hr = 7500 m/s

KE = 1/2 * .001 kg * (7500 m)^2 = 28,125 Joules

One can see that 28000 Joules could be damaging amount of energy

Answer:

option A because in sport pain makes a player strongest.......

Answer: Choice C: You should understand the risks of each sport and listen to your body.

Explanation: The statement that BEST describes the process of playing sports is C. You should understand the risks of each sport and listen to your body. It’s important to be aware of the potential risks associated with each sport and to pay attention to your body’s signals to avoid injury.

Answer:

The pressure difference required between the two ends of the 1.6 km pipe section, with a diameter of 29 cm, to transport the oil at a rate of 650 cm^3/s, is approximately 0.398 Pa.

Explanation:

To calculate the pressure difference between the two ends of a pipe, we can use the Poiseuille's Law equation, which relates flow rate, viscosity, pipe length, diameter, and pressure difference.

The formula is as follows: ΔP = (8 * n * L * Q) / (π * r^4)

Where:

ΔP is the pressure difference,

n is the viscosity of the fluid,

L is the length of the pipe section,

Q is the flow rate,

and r is the radius of the pipe (half of the diameter).

Given:

L = 1.6 km = 1600 m (convert to meters)

Diameter = 29 cm

Radius (r) = 29 cm / 2 = 14.5 cm = 0.145 m (convert to meters)

Q = 650 cm^3/s = 650 * 10^-6 m^3/s (convert to cubic meters per second)

n = 0.20 Pa.s (viscosity)

p = 950 kg/m^3 (density)

ΔP = (8 * 0.20 * 1600 * 650 * 10^-6) / (π * (0.145)^4)

ΔP ≈ 0.398 Pa

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Given

On Saturday, she found 4 times as many shells as she found on Sunday.

Saturday = 4*Sunday

Saturday = 21 + Sunday

Two system equations, now we can solve:

4*Sunday = 21 + Sunday

3*Sunday = 21

Sunday = 7 Shells

Saturday = 28 Shells

Total = 35 Shells

Answer:35 in total

Explanation:

The tension in a transverse wave on a string can be calculated using the equation y = (F/μ) sin(kx-wt), where F is the tension force, μ is the linear density of the string, k is the wave number, x is the position of the particle, w is the angular frequency, and t is time.

Using the given equation y = 0.021 sin (8πt + 2x) and the linear density of the string (16 x 10-2 g/cm), the tension in the string is calculated to be 2.53 N.

To find the tension in the string, the equation for a transverse wave on a string is used: y = (F/μ) sin(kx-wt), where F is the tension force, μ is the linear density of the string, k is the wave number, x is the position of the particle, w is the angular frequency, and t is time.

Rearranging this equation to solve for F, we get F = μwk^2A, where A is the amplitude of the wave.

Using the given equation y = 0.021 sin (8πt + 2x),

we can see that the amplitude of the wave is A = 0.021 m. To find k and w, we can compare this equation to the standard form of a transverse wave: y = A sin(kx-wt). We see that k = 2, and w = 8π.

Finally, substituting these values for k, w, and A into the equation for tension, we get F = (16 x 10-2 g/cm)(8π)^2(2)^2(0.021 m), which simplifies to 2.53 N.

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Answer:

if not mistaken its b

Answer:

t = 2.40 s

Explanation:

It just told me

The error in the estimate of acceleration due to gravity (g) is approximately -0.02π(T√(Lg)).

The formula for the period of a simple pendulum is given by:

T = 2π√(L/g)

Where:

T is the time period of the pendulum

L is the length of the pendulum

g is the acceleration due to gravity

Taking the derivative of the equation with respect to g:

d(T)/d(g) = -πL/(T√(L/g))

Using the concept of error propagation, the relative error in g (Δg/g) can be calculated as:

(Δg/g) = (ΔT/T) / (d(T)/d(g))

Substituting the given values into the equation:

(Δg/g) = (0.02) / (-πL/(T√(L/g)))

(Δg/g) = -0.02π(T/g)(√(L/g))

To obtain the absolute error in g, we can multiply the relative error by the estimated value of g:

Error in g (Δg) = (Δg/g) * g

Error in g (Δg) = (-0.02π(T/g)(√(L/g))) * g

Error in g (Δg) = -0.02π(T√(Lg))

Note that the negative sign indicates a decrease in the estimate of g due to the errors in length and time period.

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The density of SO₃ gas at 25 °C and 715 Torr is 3.08 g/L.

We want to calculate the density of SO₃ gas at 25 °C and 715 Torr.

Density (ρ) is the ratio of the mass to the volume of a substance.

If we assume ideal behavior, we can calculate the density of SO₃ using the following expression.

ρ = P × M / R × T

where,

To apply this formula, we need to convert 25 °C to Kelvin using the following expression.

K = °C + 273.15 = 25 °C + 273.15 = 298 K

The density of SO₃ is:

ρ = P × M / R × T

ρ = 715 Torr × (80.06 g/mol) / (62.4 mmHg.L/mol.K) × 298 K = 3.08 g/L

The density of SO₃ gas at 25 °C and 715 Torr is 3.08 g/L.

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The life expectancy of the given stars are:a) 0.2-solar mass, 0.01-solar luminosity red dwarf: 10 trillion yearsb) 3-solar mass, 30-solar luminosity star: 10 million yearsc) 10-solar mass, 1000-solar luminosity star: 10 million years.

The life expectancy of a star is determined by its mass and luminosity. The more massive and luminous the star is, the shorter its life expectancy is. Hence, using this information, we can estimate the life expectancy of the following stars:a) 0.2-solar mass, 0.01-solar luminosity red dwarfRed dwarfs are known to have the longest life expectancies among all types of stars. They can live for trillions of years.

Hence, a 0.2-solar mass, 0.01-solar luminosity red dwarf is expected to have a much longer life expectancy than the Sun. It could live for up to 10 trillion years or more.b) 3-solar mass, 30-solar luminosity starA 3-solar mass, 30-solar luminosity star is much more massive and luminous than the Sun. As a result, it will have a much shorter life expectancy than the Sun.

Based on its mass and luminosity, it is estimated to have a lifetime of around 10 million years.c) 10-solar mass, 1000-solar luminosity starA 10-solar mass, 1000-solar luminosity star is extremely massive and luminous. It will burn through its fuel much faster than the Sun, resulting in a much shorter life expectancy. Based on its mass and luminosity, it is estimated to have a lifetime of only around 10 million years as well.

Therefore, the life expectancy of the given stars are:a) 0.2-solar mass, 0.01-solar luminosity red dwarf: 10 trillion yearsb) 3-solar mass, 30-solar luminosity star: 10 million yearsc) 10-solar mass, 1000-solar luminosity star: 10 million years.

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If the coefficient of static friction between the tires and the road is doubled, it means that the frictional force keeping the car from sliding will also increase.

Therefore, it is possible that the car will be able to make the turn with less slipping and at a higher speed. It is also possible that the car will require less force to make the turn, as the increased frictional force will provide more grip and stability. However, it is important to note that other factors, such as the weight distribution of the car and the sharpness of the turn, may also affect the car's ability to make the turn safely.

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Answer:

The linear speed of the car is approximately 27.30 m/s

Explanation:

The question parameters are;

The mass of the person on the rollercoaster, m = 57.0 kg

The radius of the rollercoaster track, r = 42.7 m

The normal force felt by the person, F = 995 N

The centripetal force acting on the person keep the circular motion is given by the following equation;

\(Centripetal \, force \ F_c = \dfrac{m \times v^2}{r}\)

Where;

v = The linear velocity of motion = The linear speed of the car

The centrifugal force, F, is the force normal force felt by the person and is equal to the centripetal force, therefore, we have;

\(Centripetal \, force \ F_c = Centrifugal \, force \ F = \dfrac{m \times v^2}{r}\)

From which we have;

\(F = 995 = \dfrac{57 \times v^2}{42.7}\)

\(\therefore v = \sqrt{\dfrac{995 \times 42.7}{57} } \approx 745.38\)

The linear speed of the car = v ≈ 27.30 m/s

The angular speed of the car, ω = v/r ≈ 27.30/42.7 ≈ 0.639 rad/s

Answer: 18.1 m/s

Explanation:

After 0.50 s, the pebble is approximately 5.7 meters beneath the cliff top in the negative direction.(a) The acceleration of the pebble during the downward motion is equal to the acceleration due to gravity, which is approximately -9.8 m/s² (negative because it is in the downward direction). The pebble is accelerating downward due to the gravitational force acting on it. It is not decelerating because the acceleration remains constant throughout its motion.

(b) To find how far beneath the cliff top the pebble is after 0.50 s, we can use the kinematic equation:

d = v₀t + (1/2)at²,

where:

d = displacement (distance beneath the cliff top),

v₀ = initial velocity,

t = time,

a = acceleration.

Plugging in the given values:

v₀ = 9.0 m/s (negative since it is downward),

t = 0.50 s,

a = -9.8 m/s²,

d = (9.0 m/s)(0.50 s) + (1/2)(-9.8 m/s²)(0.50 s)²,

d = -4.5 m - (1/2)(9.8 m/s²)(0.25 s²),

d = -4.5 m - 1.225 m,

d ≈ -5.7 m.

Therefore, after 0.50 s, the pebble is approximately 5.7 meters beneath the cliff top in the negative direction.

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The resulting changes will be:

1. Pressure head: 88 ft (or 26.82 m)

2. Effective stress: No change, assuming no other factors affect it

3. Fluid pressure: No change

4. Total stress: Decreased by the same amount as the effective stress

To calculate the effective stress in the aquifer, we need to subtract the fluid pressure from the total stress.

Given:

Pressure head in the aquifer = 100 ft (or 30.48 m)

The pressure head in the aquifer is directly proportional to the fluid pressure, which can be calculated using the formula:

Fluid pressure (P) = ρ * g * h

Where:

ρ = density of the fluid (water) = approximately 1000 kg/m³

g = acceleration due to gravity = 9.8 m/s²

h = pressure head

Fluid pressure = 1000 kg/m³ * 9.8 m/s² * 30.48 m ≈ 298,440 N/m² (or Pa)

The total stress in the aquifer is the sum of the fluid pressure and the effective stress. Therefore, the effective stress can be calculated by subtracting the fluid pressure from the total stress.

Now, let's consider the changes in the hydraulic head due to pumping:

Change in hydraulic head = -12 ft (or -3.66 m)

The resulting changes in each parameter will be as follows:

1. Pressure head:

The pressure head will be reduced by 12 ft, so the new pressure head will be 100 ft - 12 ft = 88 ft (or 26.82 m).

2. Fluid pressure:

The fluid pressure does not change, as it depends on the density of the fluid and the acceleration due to gravity, which remain constant.

3. Effective stress:

The effective stress can be calculated as the total stress minus the fluid pressure. Since the fluid pressure remains constant, the effective stress will also remain constant unless there are other factors affecting it.

4. Total stress:

The total stress is the sum of the fluid pressure and the effective stress. As mentioned earlier, the fluid pressure remains constant, so the total stress will decrease by the same amount as the effective stress, assuming no other factors affect the total stress.

Therefore, the resulting changes will be:

1. Pressure head: 88 ft (or 26.82 m)

2. Effective stress: No change, assuming no other factors affect it

3. Fluid pressure: No change

4. Total stress: Decreased by the same amount as the effective stress

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Answer:

(b) is correct

object moving towards you - higher frequency heard

object moving away from you - lower frequency heard

Infrared wave basically have shorter wavelengths than X-rays. The correct option is A.

A section of the electromagnetic radiation spectrum with wavelengths ranging from roughly 700 nanometers (nm) to one millimetre is known as infrared radiation (IR), or simply infrared (mm).

While shorter than radio waves, infrared waves are longer than visible light waves.

Infrared radiation has the ability to ease muscle tension and encourage local blood circulation.

Infrared radiation has been used in conventional medicine to treat conditions including autoimmune diseases and issues with wound healing in addition to relieving muscle pain and tension.

Infrared waves are shorter than radio waves but longer than visible light waves.

Thus, the correct option is A.

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Answer:

turbine

Explanation:

Turbine       that turns the generator

Answer: C

Explanation: i hoped that helped!