The populations and land areas of four cities in Texas are shown. Which statements are true? Check all that apply. The population density for City B can be found using the ratio 48,592 : 26. The population density for City D can be found using the ratio 258 : 196,429. City A has the greatest population density of the four cities. The population density of City B is greater than that of City C. City D has the lowest population density of the four cities.

Part a:  What quantity order size would minimize the total annual inventory cost? Total Annual Inventory Cost = Annual Ordering Cost + Annual Carrying Cost At minimum Total Annual Inventory Cost, the formula for the Economic Order Quantity (EOQ) is used. EOQ formula is given below: EOQ = sqrt((2DS)/H)Where, D = Annual DemandS = Ordering cost

The company should place an order for 168 boxes at a time in order to minimize the total annual inventory cost.Part b: Determine the minimum total annual inventory cost.Using the EOQ, the company can calculate the minimum total annual inventory cost. The Total Annual Inventory Cost formula is:Total Annual Inventory Cost = Annual Ordering Cost + Annual Carrying CostAnnual Ordering Cost = (D/EOQ) × S = (16,800/168) × $60 = $6,000Annual Carrying Cost = (EOQ/2) × H = (168/2) × $30 = $2,520Total Annual Inventory Cost = $6,000 + $2,520 = $8,520Therefore, the minimum Total Annual Inventory Cost would be $8,520.Part c: Would you recommend the manager to use your quantity from part (a) rather than 300 boxes? Justify your answer (by determining the total annual inventory cost for 300 boxes)

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Answer:

80v

Step-by-step explanation:

Multiply the numbers: 12 * 4 = 48

=48v + 8 * 4v

Multiply the numbers: 8 * 4 = 32

=48v + 32v

Add similar elements: 48v + 32v = 80v

Answer: 80v

Step-by-step explanation:

If a customer rolls the dice and every Thursday rents a second movie for 30 consecutive weeks. The approximate probability will be 0.14

Value anticipated = 0.47

0.15 is the standard deviation.

Sample size: 30 people

Mean = Expected Value * Sample Size

Mean = 0.47 * 30 = 14.1

The sample's standard deviation is equal to /n.

0.15 = σ/√30

σ = 0.8216

P(x > 15) :

Z is equal to (x-mean)/(standard deviation).

Z = (15 - 14.1) divide by 0.8216 = 1.095

P(Z > 1.095) = 0.1367

P(Z > 1.095) = 0.14

Probability means measuring the probability of an event, dividing the desirable number of outcomes by the total number of possible outcomes using a probability formula.

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56 units are in the sum of the lengths of the three altitudes in a triangle with sides $7,$ $24,$ and $25$

Properties of triangles are:

A triangle has three sides and three angles.

The sum of the angles of a triangle is always 180 degrees.

The exterior angles of a triangle always add up to 360 degrees.

The sum of consecutive interior and exterior angle is supplementary.

Given:

Height: ha = 7

Height: hb = 24

Height: hc = 25

Sum to sides is:

25 +7 + 24 =56 units.

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The fraction is  :

\(\frac{x+3}{3} =\frac{y+2}{2}\) then :\(\frac{x}{3} = \frac{y}{2}\)

The correct option is (c).

Now, According to the question:

The given fraction is :

\(\frac{x+3}{3} =\frac{y+2}{2}\)

To solve the above fraction and find x/3 =?

We can solve this by cross-multiplying.

Since \(\frac{x+3}{3} =\frac{y+2}{2}\) ,we can cross-multiply both sides of the equation to remove the denominators.

Multiple the right side by 2 and the left side by 3 to get 2(x+3)=3(y+2).

Distribute to get the x on one side. 2x+6=3y+6.

The 6s on both sides cancel out so we are left with

2x=3y.

Divide both sides by 2 to get x on one side, so x= 3y/2

The question asks for x/3,

so we can divide both sides of the equation to get:

\(\frac{x}{3} = \frac{3y}{6}\)

Simplify, We get:

\(\frac{x}{3} = \frac{y}{2}\)

Hence, (c) is the correct answer.

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The value of x is 17

The congruent arcs are (b) PQ and SR

The radius is 12 units

The value of PQ is 4

The length YZ is 19 units

In this question, we make use of the property of congruent sides

So, we have

3x - 24 = x + 10

When evaluated, we have

2x = 34

Divide by 2

x = 17

By the definition of congruent arcs, congruent arcs are arcs that have equal measures

In this figure, the congruent arcs are PQ and SR i.e. (b) PQ and SR

The radius of the circle is calculated as

r² = (25 + r)² - 35²

When expanded, we have

r² = 625 + 50r + r² - 1225

So, we have

50r = 600

Divide both sides by 50

r = 12

In this question, we make use of the property of congruent sides

So, we have

PQ = SR

Where

SR = 4

When evaluated, we have

PQ = 4

The length of YZ in the circle is calculated as

YZ² = (9 + 8)² + 8²

So, we have

YZ² = 17² + 8²

When expanded, we have

YZ² = 289 + 64

So, we have

YZ² = 353

Take the square root of both sides

YZ = 19

Hence, the length YZ is 19 units

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The water level is rising at a rate of 0.0075 ft/min when the depth at the deepest point is 5 ft.

Let's call the depth at the deepest point of the pool "y" and the volume of

the water in the pool "V".

We want to find the rate at which the water level is rising, which is the

rate of change of "y" with respect to time.

We know the rate at which the pool is being filled, which is 0.9 ft3/min,

and we can find the rate at which the volume of the water is increasing

using the formula for the volume of a rectangular prism:

V = lwh

where l is the length, w is the width, and h is the height.

Since the pool is not rectangular, we can find the volume of the water as

a function of "y" using similar triangles:

h/y = (9 - 3)/(40 - 20) = 0.3

where h is the height of the pool at the deepest point. Solving for h, we get:

h = 0.3y

Substituting this expression for h into the formula for the volume, we get:

V = lw(3 + 0.6y)

Taking the derivative with respect to time, we get:

dV/dt = lw(0.6 dy/dt)

Now we need to find the values of l and w. The width is given as 20 ft,

and the length is a function of "y":

l = 40 - 2(40 - y) = 2y

Substituting these values into the expression for dV/dt, we get:

dV/dt = 40y(0.6 dy/dt)

Finally, we can find the rate at which the water level is rising when y = 5 ft

by plugging in the values:

0.9 = 40(5)(0.6 dy/dt)

Solving for dy/dt, we get:

dy/dt = 0.9/(4050.6) = 0.0075 ft/min

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The dimensions of the open rectangular box that will result in a box of maximum volume using 12 ft^2 of material are 2 ft x 2 ft x unlimited height.

To find the dimensions of the open rectangular box that will result in a box of maximum volume using 12 ft^2 of material, we need to use optimization techniques.

Let's assume that the box has length L, width W, and height H, where L and W are the dimensions of the base and H is the height of the box. Since we are given that the box is open, we can assume that one of the dimensions, say H, is unlimited.

The surface area of the box is given by:

SA = LW + 2LH + 2WH

Since we are given that the total amount of material used is 12 ft^2, we can write:

SA = 12

Substituting H with an unlimited value, we can write the volume of the box as:

V = LW H

To find the dimensions that will result in a box of maximum volume, we can use the method of Lagrange multipliers. We need to maximize the volume function V subject to the constraint that the surface area SA is constant, which gives us the following function to maximize:

F(L, W, H, λ) = LW H + λ(12 - LW - 2LH - 2WH)

We take the partial derivative of F with respect to L, W, H, and λ, and set each to zero:

∂F/∂L = WH - λ(2H + W) = 0

∂F/∂W = LH - λ(2H + L) = 0

∂F/∂H = LW - λ(2L + 2W) = 0

∂F/∂λ = 12 - LW - 2LH - 2WH = 0

Solving these equations simultaneously, we get:

L = W = 2H

Substituting these values into the equation for surface area, we get:

SA = LW + 2LH + 2WH = 12

Substituting L = W = 2H into this equation, we get:

12H + 4H^2 = 12

Simplifying and solving for H, we get:

H = 1 ft

Substituting this value of H into L = W = 2H, we get:

L = W = 2 ft

Therefore, the dimensions of the open rectangular box that will result in a box of maximum volume using 12 ft^2 of material are 2 ft x 2 ft x unlimited height.

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Answer:

slope of the line is 2

Step-by-step explanation:

formula:

slope=m=(y2-y1)/(x2-x1)

plug the values in:

m=(9-3)/(2-(-1))

simplify:

m=6/3

divide:

m=2

Answer:

Dialation is to make the shape smaller or larger. It stays in the same place, but it changes size.

Answer:

An object usually a circle or "dot" moving. Getting bigger or smaller.

Step-by-step explanation:

So, Lana gave away 26.32% of he Pokemon cards  to her little brother.

To find the percentage of cards Lana gave away, we can use the formula:(Quantity given away / Total quantity) * 100.

In this case, Lana gave away 125 cards out of her total collection of 475 cards.Plugging these values into the formula, we have:

(125 / 475) * 100 = 0.2632 * 100 = 26.32%.

Lana gave away 26.32% of her Pokemon cards to her little brother.

Alternatively, we can calculate the percentage by subtracting the remaining cards from the total and finding the ratio:

Percentage given away

= (Cards given away / Total cards) * 100

= (125 / 475) * 100

= 26.32%.

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A period is the difference in x over which a sine function returns to its equivalent state and the amplitude is A/5.

Amplitude:

The amplitude of a periodic variable is a measure of its change over a period of time, such as a temporal or spatial period. The amplitude of an aperiodic signal is its magnitude compared to a reference value. There are various definitions (see below) of amplitude, which is any function of the magnitude of the difference between the extreme values ​​of a variable. In the previous text, the phase of a periodic function is called the amplitude.

                       X = A sin (ω[ t - K]) + b

A is the amplitude (or peak amplitude),

x is the oscillating variable,

ω  is angular frequency,

t is time,

K and b are arbitrary constants representing time and displacement respectively.

According to the Question:

An equation does not have an amplitude. This "equation" represents the formula of a vibration, and was better written as:

X= A/5* sin(1000.t + 120)

These oscillations have a certain amplitude. X values ​​can vary from minimum to maximum. Normally, the stop position of the oscillation is X=0. In this case, we can see that the maximum occurs when the sine is +1 and the minimum occurs when the sine is -1.

For theses cases X= A/5 respectively -A/5.

Therefore,

The amplitude is A/5.

For formulas of this type, the term in front of the sinus (or cosine) is equal to the amplitude.

Complete question:

Can I find the amplitude of this equation? A/5 *