The position of a point during the interval of time from t=0 to t=3 s is s=12+5t^2−t^3 ft. (a) What is the maximum velocity during this interval of time, and at what time does it occur? (b) What is the acceleration when the velocity is a maximum?

Answers

Answer 1

Main answer:(a) The maximum velocity during the interval of time from t=0 to t=3 s is 30 ft/s at time t=1.5 s.(b) The acceleration when the velocity is a maximum is 20 ft/s².Explanation 1:The position of a point during the interval of time from t=0 to t=3 s is given by the formula,s=12+5t²−t³ ft The velocity of the point is the first derivative of the position with respect to time.The velocity function is given byv=s'=10t−3t² ft/s The acceleration of the point is the second derivative of the position with respect to time.The acceleration function is given bya=v'=10−6t ft/s²To find the maximum velocity, we need to find the time at which the velocity is a maximum.

We can do this by setting the derivative of the velocity function to zero, and then solving for t.v'=0⇒10−6t=0⇒t=5/3 sWe can check that this critical point is indeed a maximum by examining the sign of the second derivative of the velocity function at this time.v''=-6 ft/s²Since the second derivative is negative, the critical point is indeed a maximum. Therefore, the maximum velocity during the interval of time from t=0 to t=3 s isv(t=5/3)=10(5/3)−3(5/3)²=30 ft/sat time t=5/3 s.To find the acceleration when the velocity is a maximum, we need to evaluate the acceleration function at the time t=5/3 s.a(t=5/3)=10−6(5/3)=20 ft/s²Therefore, the acceleration when the velocity is a maximum is 20 ft/s².Explanation 2:To solve the problem, we need to use the formulas for velocity and acceleration. The velocity is given byv = ds/dtThe acceleration is given bya = dv/dtWe are given the position of the point in terms of time,s = 12 + 5t² - t³ ftWe can find the velocity by taking the derivative of the position with respect to timev = ds/dt= 10t - 3t² ft/sWe can find the acceleration by taking the derivative of the velocity with respect to timea = dv/dt= 10 - 6t ft/s²To find the maximum velocity, we need to find the time at which the velocity is maximum.

We can do this by setting the derivative of the velocity function equal to zero and solving for t. This gives us,t = 5/3 sWe can find the maximum velocity by substituting t = 5/3 s into the velocity function. This gives us,v = 10(5/3) - 3(5/3)²= 30 ft/s Therefore, the maximum velocity during the interval of time from t = 0 to t = 3 s is 30 ft/s at time t = 5/3 s.To find the acceleration when the velocity is a maximum, we need to evaluate the acceleration function at t = 5/3 s. This gives us,a = 10 - 6(5/3)= 20 ft/s²Therefore, the acceleration when the velocity is a maximum is 20 ft/s².

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Related Questions

The same type of stress that creates anticlines and syncline in some rocks will create ___ faults in rock exhibiting brittle deformation

Answers

Answer:

reverse and thrust faults

Explanation:

explain why it is not advisable to wear a ring at work shop

Answers

Answer:

Metal conducts heat so it could severely burn your finger.

Rings can create multiple hazards while working with chemicals.

Rings/Jewlery can be a "hiding place" for bacteria.

Amongst many other reasons as to why it's not advisable to wear a ring(s) at a workshop/workplace.

When driving a commercial motor vehicle safely, it is recommended that you leave at
least one second between your vehicle and the vehicle you are following for each
feet of your vehicle's length.

Answers

Answer:

If you are driving below 40 mph, you should leave at least one second for every 10 feet of vehicle length.

by indicial notation, show that the material derivative of the jacobian of the deformation gradient tensor can be determined by d/dt(j(y,t)

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we have shown that the material derivative of the jacobian of the deformation gradient tensor can be determined by d/dt(j(y,t)) through indicial notation.

In order to show that the material derivative of the jacobian of the deformation gradient tensor can be determined by d/dt(j(y,t)) through indicial notation, let us start by first defining some of the notations used in this problem. Definitions:    Jacobian of a deformation gradient tensor: The Jacobian of a deformation gradient tensor is defined as the determinant of the deformation gradient tensor. It is denoted by J(y,t).Material Derivative: The material derivative of a given quantity, represented by f(y,t), is defined as:df(y,t)/dt = (∂f/∂t) + (v·∇)fwhere v is the velocity of the fluid (or in this case, the material)Gradient: The gradient of a given scalar function, represented by f(y,t), is defined as the vector of its partial derivatives with respect to its independent variables. It is denoted by ∇f.Indicial Notation: Indicial Notation is a notational method that is used to represent and manipulate vectors, tensors, and other geometrical objects in a concise and unambiguous manner. It is based on the Einstein summation convention, which states that any repeated index in a term of a tensor expression should be summed over all possible values of that index.Indicial Notation is used in this problem to represent the partial derivatives of the deformation gradient tensor with respect to its independent variables, which are the spatial coordinates of the material point being considered.Now, let us apply these definitions and notations to the problem at hand.To begin with, we have the following given information:Jacobian of the deformation gradient tensor = J(y,t)Material Derivative of the Jacobian of the deformation gradient tensor = d/dt(J(y,t))Our task is to show that the material derivative of the Jacobian of the deformation gradient tensor can be determined by d/dt(j(y,t)) through indicial notation.To do this, we will start by expressing the material derivative of J(y,t) using its definition, as follows:df(y,t)/dt = (∂f/∂t) + (v·∇)fwhere f(y,t) = J(y,t)Therefore,df(y,t)/dt = (∂J(y,t)/∂t) + (v·∇)J(y,t)Now, let us use the indicial notation to express the partial derivatives of the deformation gradient tensor with respect to its independent variables. For convenience, we will denote the deformation gradient tensor by F and its partial derivatives by Fi,j, where i and j represent the spatial coordinates of the material point being considered.Thus, we can write the following expression for J(y,t):J(y,t) = det(F) = F1,1F2,2F3,3 - F1,1F2,3F3,2 - F1,2F2,1F3,3 + F1,2F2,3F3,1 + F1,3F2,1F3,2 - F1,3F2,2F3,1Using this expression, we can now use the chain rule of differentiation to find the partial derivatives of J(y,t) with respect to its independent variables. Specifically, we have:∂J(y,t)/∂t = ∂det(F)/∂t = det(F)·tr(F^-1(dF/dt))where tr denotes the trace of a matrix, and F^-1 denotes the inverse of the deformation gradient tensor.Using the indicial notation, we can write this expression as:∂J(y,t)/∂t = J(y,t)·Fi,i^-1·Fi,j·dFj,i/dtwhere we have used the summation convention to sum over the repeated index i.Now, let us look at the second term in the material derivative of J(y,t), which involves the gradient of J(y,t) with respect to its independent variables. Using the expression we derived earlier for J(y,t), we can write:∇J(y,t) = (partial(J)/partial(x1), partial(J)/partial(x2), partial(J)/partial(x3))where x1, x2, and x3 denote the spatial coordinates of the material point being considered.Using the indicial notation, we can write this expression as:∇J(y,t) = (partial(J)/partial(xi))where i = 1,2,3Therefore, the gradient of J(y,t) with respect to its independent variables can be expressed as:∇J(y,t) = J(y,t)·Fi,i^-1·Fi,j·(partial(Fj,k)/partial(xi))Using the chain rule of differentiation, we can express this as:∇J(y,t) = J(y,t)·Fi,i^-1·Fi,j·(dFj,k/dxk)·(dxk/dxi)where we have used the summation convention to sum over the repeated index k.Now, substituting these expressions back into the material derivative of J(y,t), we get:d/dt(J(y,t)) = (∂J(y,t)/∂t) + (v·∇)J(y,t)= J(y,t)·Fi,i^-1·Fi,j·dFj,i/dt + J(y,t)·Fi,i^-1·Fi,j·(dFj,k/dxk)·(dxk/dxi)·vwhich is the desired result.

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in general, fall protection must be provided to construction workers who are working on surfaces with unprotected sides and edges which are above the lower level

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The threshold when no explicit rule is in effect is six feet, which is the standard rule for the construction industry.

When might fall protection be necessary when working close to an unprotected edge? The threshold when no explicit rule is in effect is six feet, which is the standard rule for the construction industry.Each employee must be prevented from falling by the use of guardrail systems, safety net systems, or personal fall arrest systems when on a walking or working surface (horizontal or vertical) with an unprotected side or edge that is 6 feet (1.8 m) or higher over a lower level.Fall protection is required by OSHA in general industrial workplaces at altitudes of four feet, in shipyards at elevations of five feet, in the construction sector at elevations of six feet, and in long shoring operations at elevations of eight feet.An adequate load must be supported by the anchorage point.For fall restraint or placement, a harness (or body belt) must be worn in accordance with the manufacturer's instructions.

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53. The plan of a building is in the form of a rectangle with
centerline dimension of outer walls as 9.7mx14.7m. The
thickness of the wall in super structure is 0.30m. Then its
plinth area is
a) 150m
b) 145m2
c) 145.5m
d) 135.36m
.​

Answers

Answer: 150m

Explanation:

The following can be depicted from the question:

Dimensions of outer walls = 9.7m × 14.7m.

Thickness of the wall = 0.30 m

Therefore, the plinth area of the building will be:

= (9.7 + 0.30/2 + 0.30/2) × (14.7 × 0.30/2 + 0.30/2)

= 10 × 15

= 150m

The plinth area will be 150m.

Given information

Dimensions of outer walls = 9.7m × 14.7m.

Thickness of the wall = 0.30 m

Plinth area of the building = (9.7 + 0.30/2 + 0.30/2) × (14.7 × 0.30/2 + 0.30/2)

Plinth area of the building = 10 × 15

Plinth area of the building = 150m

Therefore, the Option A is correct.

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Assuming the temperature of the system is 20 C the atmospheric pressure is 0.998 atm, and the total volume collected in the balloon is 0.28 L, calculate the number of moles of H2 collected in the ballot. This is the actual yield. Use the dalton's law of partial pressure to determine the partial pressure of H2 in the balloon. The vapor pressure of water is 20 Cis 17.5 mmHg

Answers

Answer:

The number of moles of H₂ is 0.01135 moles

The partial pressure of H₂ in the balloon is 0.975 atm

Explanation:

From Dalton's law of partial pressure, we have;

Total pressure = Pressure of H₂ + Pressure of the water vapor

The vapor pressure of water at 20°C = 17.5 mmHg = 0.0230225 atm

For equilibrium, pressure of the balloon = Surrounding pressure = Atmospheric pressure

∴ Pressure of H₂ + Pressure of the water vapor = Atmospheric pressure

Partial pressure of H₂ in the balloon, P = 0.998 - 0.0230225 = 0.9749775 ≈ 0.975 atm

0.975 atm  = 98789.595 Pa

Volume of balloon, V = 0.28 L

n = PV/(RT)

Where:

R = Universal gas constant = 0.08205 L·atm/(mol·K)

T = Temperature = 20°C = 293.15 K

∴ n = 0.975 * 0.28/ (0.08205  * 293.15) =  0.01135 moles.

which one of these reduce fraction?

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How is I’m supposed to answer the question

28. Which method or operator can be used to concatenate lists? A. * B. + C. % D. concat

Answers

The operator that can be used to concatenate lists is the + operator. The correct option is B.

List concatenation refers to the merging of two or more lists into a single list.

List concatenation is performed using the + operator, which combines two or more lists and returns a new list.

Consider the example given below:>>> list1 = [1, 2, 3]>>> list2 = [4, 5, 6]>>> concatenated_list = list1 + list2>>> print(concatenated_list)[1, 2, 3, 4, 5, 6]

Explanation:The given code contains two lists, list1 and list2.

The + operator is used to combine these lists into a new list named concatenated_list.

Finally, the concatenated list is printed using the print statement, which returns the output as [1, 2, 3, 4, 5, 6].

Hence, the correct option is B.

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what is the ratio of the induced emf in the loop cdbc to the induced emf in the loop cadc; i.e., what is ecdbc ecadc ?

Answers

The ratio of the induced EMF in the loop CDBC to the induced EMF in the loop CADC can be calculated as follows:

ecdbc/ecadc = -dΦ_cdbc/dt / (-dΦ_cadc/dt) = dΦ_cadc/dt / dΦ_cdbc/dt

Let's dive deeper into the details below

The induced EMF is the voltage generated by a changing magnetic field in a coil of wire. In a loop, the induced EMF is proportional to the rate of change of the magnetic flux that is threading the loop. Therefore, in a loop, the induced EMF can be calculated as:

induced EMF = -dΦ/dt, where Φ is the magnetic flux threading the loop.

We can assume that both loops are parallel to the surface and therefore perpendicular to the magnetic field. This means that the magnetic flux threading each loop is proportional to the area of the loop, as follows:

Φ_cadc = B A_cadc and Φ_cdbc = B A_cdbc

Therefore, the ratio of the induced EMF in the loop CDBC to the induced EMF in the loop CADC can be calculated as follows:

ecdbc/ecadc = dΦ_cadc/dt / dΦ_cdbc/dt = (B A_cadc)/dt / (B A_cdbc)/dt = A_cadc / A_cdbc

The answer is the ratio of the areas of the loops.

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A Ethernets data packet is a ?

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Ethernet packets are sometimes called network frames because they add both a header and a trailer to the packets, thus framing the network data being transmitted. The older Ethernet standards and the newer 802.3 standards are mostly the same.

It is proposed to absorb acetone from air using water as a solvent. Operation is at 10 atm and is isothermal at 20°C. The total flow rate of entering gas is 10 kmol /h. The entering gas is 1.2 mol% acetone. Pure water is used as the solvent. The water flow rate is 15 kmol/h. The desired outlet gas concentration should be 0.1 mol % acetone. For this system, Henry's law holds and Ye = 1.5 X where Ye is the mol fraction of acetone in the vapour in equilibrium with a mol fraction X in the liquid.
KGa = 0.4 kmol*m^-3*s^-1
1. Draw a schematic diagram to represent the process.
2. Determine the mole fraction of acetone in the outlet liquid.

Answers

Answer:

The meole fraction of acetone in the outlet liquid is \(x_1 = 0.0072\)

Explanation:

1.

The schematic diagram to represent this process is shown in the diagram attached below:

2.

the mole fraction of acetone in the outlet liquid is determined as follows:

solute from Basis Gas flow rate \(G_s = 10(1-0.012) =9.88 kmol/hr\)

Let the entering mole be :\(y_1 = 1.2\) % = 0.012

\(y_1 =(\dfrac{y_1}{1-y_1})\)

\(y_1 =(\dfrac{0.012}{1-0.012})\)

\(y_1 =0.012\)

Let the outlet gas concentration be \(y_2\) = 0.1% = 0.001

\(y_2 = 0.001\)

Thus; the mole fraction of acetone in the outlet liquid is:

\(G_s y_1 + L_s x_2 = y_2 L_y + L_s x_1\)

\(9.88(0.012-0.001)=15*x_1\)

\(9.88(0.011) = 15x_1\)

\(x_1 = \dfrac{0.10868}{15}\)

\(x_1 = 0.0072\)

The mole fraction of acetone in the outlet liquid is \(x_1 = 0.0072\)

It is proposed to absorb acetone from air using water as a solvent. Operation is at 10 atm and is isothermal

Most technicians install rebuilt or new power steering pumps rather than overhauling the defective unit in the shop. True or False?

Answers

Answer:

Most technicians install rebuilt or new power steering pumps rather than overhauling the defective unit in the shop.

True

Explanation:

It has been established that most technicians, instead of overhauling the defective power steering pumps, prefer to install rebuilt or revamped pumps or even new pumps when they could have overhauled the unit themselves.  Some are afraid that leakage could occur again.  They are not confident enough to do the overhauling in-house or some claim that they do not have the time and other tools to carry out the overhauling.  Acknowledgedly, overhauling a power steering pump is not a job for the novice.  They require experienced and skilled hands to do the hard work.

An ideal Otto cycle has a compression ratio of 7. At the beginning of the compression process, P1 = 90 kPa, T1 = 27°C, and V1 = 0.004 m3. The maximum cycle temperature is 1127°C. For each repetition of the cycle, calculate the heat rejection and the net work production. Also calculate the thermal efficiency and mean effective pressure for this cycle. Use constant specific heats at room temperature.

Answers

Answer:

i) Heat rejection =  1.0288 KJ

  Network production = 1.212 kJ

ii) Thermal efficiency = 54.08%

   mean effective pressure = 353.5 kPa

Explanation:

Given data :

Compression ratio ( r )  = 7

P1 ( initial pressure ) = 90 kPa,

T1 ( initial temperature ) = 27°C + 273 = 300 K

V1 = 0.004 m^3

Max cycle Temperature = 1127°C for each repetition of the cycle

i) Determine the heat rejection and net work production

considering that process 1-2 is an Isentropic compression

Find ; T2 = T1 ( r )^1.4-1

      T2 = 300 ( 7 )^0.4  = 653.371 K

    P2 = P1( r )^k

          = 90 ( 7 )^1.4  = 1372.081 kPa

considering that process 3-4 is an Isentropic expansion

T4 = T3 / r^k-1

    = 1400 / 7^(1.4 -1 ) = 642.82 K

Next ; Calculate the value of m

m = P1V1 / RT1   = 90(0.004) / 0.287 ( 300 )

                      m = 4.18 * 10^-3 kg

Finally :

amount of heat rejected = mCv ( T4 - T1 )

                                          = 4.18 * 10^-3 ( 0.718 ) ( 642.82 - 300 )

                                    Qout  = 1.0288 KJ

amount of heat added ( Qin ) =  mCv ( T3 - T2 )

                                                = 4.18 * 10^-3 ( 0.718 ) ( 1400 - 653.371 )

                   hence           Qin  = 2.2408 kJ

Network production( Wnet) = Qin - Qout

                                  = 2.2408 - 1.0288 ) KJ

                                  = 1.212 kJ

ii) Determine the thermal efficiency and mean effective pressure of the cycle

Thermal efficiency = 1 - Qout / Qin

                               = 1 - ( 1.0288 / 2.2408 )  = 54.08%

mean effective pressure = Wnet / V1 ( 1 - 1/r )

                                         = 1.212 / 0.004 ( 1 - 1/7 )

                                         = 353.5 kPa

Weight, density, electrical conductivity, and coefficient of thermal expansion are examples of _______ properties.

Answers

Answer:

"Physical" would be the right approach.

Explanation:

Those properties would be that can be established without even any alteration throughout the identification of that same object.  Property (whenever color, compressive strength, vapor pressure) of substance which does not require a biochemical alteration including its representation.  

So the answer here is just the perfect one.

Which of the following reduces friction in an engine A)wear B)drag C)motor oil D)defractionation

Answers

It is motor oil, as oil is used to reduce friction

An electrochemical cell is composed of pure copper and pure cadmium electrodes immersed in solutions of their respective divalent ions. For a 6.5 × 10-2 M concentration of Cd2+, the cadmium electrode is oxidized, yielding a cell potential of 0.775 V. Calculate the concentration of Cu2+ ions if the temperature is 25°C.

Answers

From the calcuation, the concentration of the copper II ion is 0.98 M.

What is an electrochemical cell?

An electrochemical cell is one in which current is produced by means of a chemical reaction. In this cell, the cell reaction is;

Cd(s) + Cu^2+(aq) ----> Cd^2+(aq) + Cu(s)

E°cell = 0.34 V - (-0.40V) = 0.74 V

Using the Nernst equation;

0.775= 0.74 - 0.0592/2 log(6.5 × 10-2)/[Cu^2+]

0.775 - 0.74 =  - 0.0592/2 log(6.5 × 10-2)/[Cu^2+]

0.035 = -0.0296 log(6.5 × 10-2)/[Cu^2+]

0.035 /-0.0296 = log(6.5 × 10-2)/[Cu^2+]

-1.18 =  log(6.5 × 10-2)/[Cu^2+]

Antilog (-1.18) = (6.5 × 10-2)/[Cu^2+]

0.066= (6.5 × 10-2)/[Cu^2+]

[Cu^2+] =  (6.5 × 10-2)/0.066

[Cu^2+] =0.98 M

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An engine is received that hunts and surges at top no-load speed only. To determine whether the carburetor or the governor system is causing the symptom, a specific troubleshooting process can be followed.
Technician A says that to separate the governor system from the carburetion system, place the speed control cable in the slow or idle position and manually snap the throttle linkage from idle to high speed several times quickly. If the engine accelerates well, the governor can be eliminated as the cause of the symptom.
Technician B says that to separate the governor system from the carburetion system, place the speed control cable in the slow or idle position and hold the throttle plate linkage against the idle speed screw with a finger. Slowly increase the engine speed using the idle speed adjustment screw until the engine reaches top no-load speed. If the engine does not hunt and surge, the problem is the governor system.
Who is correct?
A. Technician A
B. Technician B
C. Both Technician A & B
D. Neither Technician A & B

Answers

At its maximum no-load speed, an engine may hunt and surge due to a blocked carburetor bowl vent.

What is an engine ?

An engine or motor is a device designed to convert electrical energy from one or more sources into mechanical energy.

Currently available energy sources include potential energy, heat energy, chemical energy, electric potential, nuclear energy, and energy from the Earth's gravitational field (from nuclear fission or nuclear fusion).

Since many of these processes require heat as an intermediary energy source, heat engines are particularly crucial.

One instance of a natural process that converts environmental heat into motion is atmospheric convection cells (e.g. in the form of rising air currents).

Mechanical energy is essential for transportation in addition to participating in many industrial operations like cutting, grinding, crushing, and mixing.

Mechanical devices transform heat into work.

Hence, At its maximum no-load speed, an engine may hunt and surge due to a blocked carburetor bowl vent.

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27 In the approach, topics that may cause hurt feelings are not discussed. Select one: out of a. Competing or Forcing b. Collaborating, Confronting, or Problem Solving on c. Accommodating or Smoothing d. Avoiding or Withdrawing

Answers

The approach that avoids discussing topics that may cause hurt feelings is option d. Avoiding or Withdrawing.

This approach may be used in situations where it is not necessary or appropriate to confront or collaborate on sensitive topics. Still, it is essential to recognize that avoiding the discussion altogether may not lead to a resolution of the issue at hand. It is essential to balance the need to consider others' feelings with the need to address important issues in a respectful and productive manner. Practicing mindfulness and creating physical distance, can help you let go of hurt feelings. Avoiding might seem like a great way to protect yourself, but this might not always be the case. More often than not, confronting a problem or dealing with a stressor is the only way to effectively reduce the stress it causes.


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what is a gas-fired forced hot air furnace and where is it typically used

Answers

A gas-fired forced hot air furnace is a heating system that utilizes natural gas as its fuel source to generate heat.

It functions by burning the gas in a combustion chamber, which heats up a metal heat exchanger. The furnace's blower then forces air over the heat exchanger, causing the air to become warm. This warm air is subsequently distributed throughout a building via a system of ducts and vents.
Typically, gas-fired forced hot air furnaces are used in residential, commercial, and industrial settings to provide comfortable indoor temperatures during colder months. These systems are popular due to their energy efficiency, cost-effectiveness, and reliability. Additionally, they are often preferred over other heating options because they can provide even, consistent heat distribution throughout a building, ensuring a comfortable environment for occupants.

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A bronze alloy specimen having a diameter of 12. 8 mm and a gage length of 50 mm was tested to fracture. Stress and strain data obtained during the test are shown. Determine the modulus of elasticity.

Answers

The modulus of elasticity of bronze alloy specimen is 750000 MPa.

To calculate the modulus of elasticity, the stress-strain diagram is plotted and the slope of the line is determined.Using the data given in the table and drawing a stress-strain graph, the modulus of elasticity can be calculated as follows.

From the stress-strain diagram, the slope of the curve can be calculated as

: E = (σ2 - σ1) / (ε2 - ε1) = (600 - 240) / (0.0008 - 0.0002) = 750000 MPa

Therefore, the modulus of elasticity of bronze alloy specimen is 750000 MPa.

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Under conditions for which the same room temperature is maintained by a heating or cooling system, it is not uncommon for a person to feel chilled in the winter but comfortable in the summer. Provide a plausible explanation for this situation (with supporting calculations) by considering a room whose air temperature is maintained at 20 ℃ throughout the year, while the walls of the room are nominally at 27 ℃ and 14 ℃ in the summer and winter, respectively. The exposed surface of a person in the room may be assumed to be at a temperature of 32 ℃ throughout the year and to have an emissivity of 0.90. The coefficient associated with heat transfer by natural convection between the person and the room air is approximately 2 W/m2∙K.

Answers

Answer:

  radiative heat loss substantially increases as the wall temperature declines

Explanation:

The body's heat loss due to convection is ...

  (2 W/m^2·K)((32 -20)K) = 24 W/m^2

__

The body's heat loss due to radiation in the summer is ...

  \(\epsilon\sigma(T_b^4-T_w^4)\quad\text{where $T_b$ and $T_w$ are body and wall temperatures ($^\circ$K)}\\\\0.90\cdot 5.6703\cdot 10^{-8}(305.15^4-300.15^4)\,\text{W/m$^2$}\\\\\approx 28.3\,\text{W/m$^2$}\)

The corresponding heat loss in the winter is ...

  \(0.90\cdot 5.6703\cdot 10^{-8}(305.15^4-287.15^4)\,\text{W/m$^2$}\\\\\approx 95.5\,\text{W/m$^2$}\)

Then the total of body heat losses to surroundings from convection and radiation are ...

  summer: 24 +28.3 = 52.3 . . . W/m^2

  winter: 24 +95.5 = 119.5 . . . W/m^2

__

It is reasonable that a person would feel chilled in the winter due to the additional radiative loss to the walls in the winter time. Total heat loss is more than doubled as the wall temperature declines.

Which explanation best summarizes what went wrong during Paul’s cost analysis?


Paul is developing a new automobile. His cost analysis took into consideration the costs of materials, insurance, and labor. Suddenly, unanticipated bills have begun coming in, putting his project far over budget.


He forgot to include direct costs such as advertising, legal fees, and repairs.


He forgot to include circumstances such as employee vacations and faulty materials.


He forgot to include indirect costs such as advertising, legal fees, and repairs.


He forgot to include circumstances such as attrition and failure of delivery of materials

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Answer:

The correct answer is He forgot to include indirect costs such as advertising, legal fees, and repairs.

Explanation:

What do you think are 5 of the most important technological inventions in human history? Why?​

Answers


1. The Printing Press: Invented by Johannes Gutenberg in the 15th century, the printing press revolutionized the way information was disseminated, making knowledge accessible to a wider audience and facilitating the spread of ideas.

2. The Steam Engine: Developed in the 18th century, the steam engine powered the Industrial Revolution and transformed the way goods were produced, leading to significant changes in the economy and society.

3. The Telephone: Invented by Alexander Graham Bell in the 19th century, the telephone revolutionized communication, allowing people to communicate with each other over long distances in real-time.

4. The Internet: Developed in the 20th century, the internet transformed the way people access and share information, leading to significant changes in communication, commerce, and social interaction.

5. The Smartphone: Invented in the 21st century, the smartphone has become an essential tool for communication, entertainment, and productivity, allowing people to access a wide range of services and information from anywhere at any time.

These inventions have had a profound impact on human history, transforming the way people live, work, and interact with each other.

leaks from the ____________ can result in coolant misting out of the vents or coolant dripping from the same drain hole used by the ac evaporator.

Answers

Leaks from the heater core can result in coolant misting out of the vents or coolant dripping from the same drain hole used by the AC evaporator.

The heater core is a component in a vehicle's heating system that helps provide warm air to the interior of the vehicle. It is typically located behind the dashboard and is connected to the engine's cooling system.

When there is a leak in the heater core, coolant (a mixture of antifreeze and water) can escape from the core. This coolant can then find its way into the ventilation system, where it can be forced out of the vents and create a misting effect. This misting of coolant can be noticeable as a fine spray or droplets coming out of the vents when the heating system is turned on.

Additionally, the HVAC (Heating, Ventilation, and Air Conditioning) system in many vehicles shares some components with the AC (Air Conditioning) system, including the drain hole used by the AC evaporator to remove condensation. If there is a heater core leak, coolant can also drip from the same drain hole used by the AC evaporator, leading to coolant dripping onto the ground beneath the vehicle.

These coolant leaks from the heater core can be problematic as they can cause a loss of coolant from the engine cooling system, which can lead to overheating of the engine if not addressed. It is important to have any coolant leaks diagnosed and repaired by a qualified mechanic to ensure the proper functioning of the vehicle's heating and cooling systems and to prevent potential engine damage.

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How do cars moves? and explain Please.

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Answer:

when car vroom it go electric

Explanation:

i think then it goes to some spinny thing that spins and make the electric and the electic spins the spinny thing and the smoke comes outside the back

what materials does a material extrusion machine dispense when building composite parts with high strength-to-weight ratios?

Answers

Thermoplastic building materials, Melt quickly at high temperatures and hold their shape when they cool.

What is the purpose of material extrusion?

Material extrusion is frequently utilized in manufacturing and industrial contexts to create non-functional prototypes or cost-effective rapid prototyping for several iterations of the same thing. When compared to the conventional production system, additive manufacturing technologies are more effective at reducing scrap waste.

What kinds of materials are frequently employed in the extrusion additive manufacturing process?

Although a variety of materials can be used in material extrusion, thermoplastics such acrylonitrile butadiene styrene (ABS), aliphatic polyamides (PA, also known as Nylon), high-impact polystyrene (HIPS), polylactic acid (PLA), and thermoplastic polyurethane are the most popular (TPU).

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Dependence of oxidation on the temperature 10 points total The process temperature is an important parameter for the oxide growth process. To get an estimate for the temperature dependence of the Deal-Groove formula, the following considerations can be used. All processes (transport, diffusion and reaction) that are used in the Deal-Groove model are thermally activated. Thus, the dependence on the growth parameters on the temperature T can be estimated by: X(T) = Xpe Xe{A, B, B/A} (5) Here kB = 8.617 x 10-5 eV/K is the Boltzmann Constant and EX is the activation energy for the parameter. X, is the value for the corresponding parameter at T =0 K. Please note that this is not a 'physical activation energy but rather an average/fit parameter for all the physical and chemical thermally activated processes relevant for the process. In the original publication by Deal and Groove, they gave the following parameter sets for dry oxidation: Oxidation temperature in 'C A in um Bin um²/h 1000 0.165 0.0117 1200 0.040 0.045 a)EXct and X, for A, B and B/A
a) Use the given values for the parameters A and B in the table above, along with equation ?? to derive the activation energies EXd and zero temperature values X(T = 0 K) for all three parameters A, B and B/A. Then use this calculate the corresponding values of A,B, B/A for the following temperatures: 1000°C, 1200°C, 800°C and 900 °C.
b) Plot estimates for other temperatures 2 points Use the obtained values from the previous sub-task along with the full Deal-Groove model equation for Z:(t) to plot the oxide thickness over time (0-100h) using at least 20 data points each for the following temperatures: 1000°C, 1200°C, 800°C and 900 °C. Assume Zo = Om.

Answers

Answer:

mama mia

Explanation:

haha

is it worth replacing compressor on ac unit in car?

Answers

It depends on the age and condition of the car's AC unit, as well as the cost of the compressor replacement. If the car is relatively new and the AC unit is in good condition, replacing the compressor may be a worthwhile investment to extend the life of the unit.

However, if the car is older or the AC unit has other issues, it may be more cost-effective to replace the entire unit instead of just the compressor.

Ultimately, the decision to replace the compressor on an AC unit in a car depends on a variety of factors and should be based on a careful assessment of the costs and benefits. It is recommended to consult with a qualified mechanic or automotive technician to determine the best course of action for your specific situation.

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4. The resumes of two male applicants for a college teaching position in chemistry are placed in the
same file as the resumes of two female applicants. Two positions become available, and the first, at the
rank of assistant professor, is filled by selecting one of the four applicants at random. The second
position, at the rank of instructor, is then filled by selecting at random one of the remaining three
applicants. Using the notation M₂F₁, for example, to denote the simple event that the first position is
filled by the second male applicant and the second position is then filled by the first female applicant,
(a) list the elements of a sample space S;
(b) list the elements of S corresponding to event A that the position of assistant professor is filled by a
male applicant
(c) list the elements of S corresponding to event B that exactly one of the two positions is filled by a
male applicant;
(d) list the elements of S corresponding to event C that neither position is filled by a male applicant;
(e) list the elements of S corresponding to the event A ∩ B;
(f) list the elements of S corresponding to the event A U C;

(g) Construct a Venn diagram to illustrate the intersections and unions of the events A, B, and C.

Answers

The Venn diagram to illustrate the intersections and unions of the events A, B, and C are (a) S = {M1F1, M1F2, M2F1, M2F2},(b) A = {M1F1, M2F1},(c) B = {M1F1, M2F2, M1F2}.

What is the illustrate ?

Illustration is the art of creating visual images to represent a concept, idea, or message. It is often used in books, magazines, advertisements, educational materials, and more to help convey a particular message or thought. Illustrations can be created using a range of mediums, from traditional drawings and paintings to digital media such as photography, vector art, and 3D art. Illustration is an important form of communication because it helps to bring an idea to life in a unique and creative way. It can help to engage readers and viewers and provide a more vivid and memorable experience than words alone.

(d) C = {M2F2, M2F1}

(e) A ∩ B = {M1F1}

(f) A U C = {M1F1, M1F2, M2F1, M2F2}

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