the principle that explains the scattering of shortwave radiation and accounts for earth's blue sky is question 36 options: rayleigh scattering. transmission. mie scattering. refraction.

Answer:

The last option

Explanation:

Answer:

Explanation:

Given:

m = 2.0 kg

Wk = 225 J

__________

H - ?

Wp = m*g*H

Wp = Wk

m*g*H = 225

H = 225 / (m*g) = 225 / (2.0*9.8) ≈ 11,5 m

Most helpful Answer~

There are no options~

Anyway If the ball is of bad quality it will get deflated/ or strike out.

' The must reasonable thing that could happen is that the ball will bounce'

*Smile* :)  

The activity of the source in Becquerel is 333.3Bq

The number of nuclei that disintegrate or decay per unit time is known as Activity.

Given that a sample of radioactive material emits 400000 particles over a period of 20 minutes.

Activity A = dN/dt

A = 400000 / 1200

A = 333.3 particles / s

A = 333.3 Bq

Therefore,

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Therefore, the mass of ball 2 is approximately 24.7 kg.

A collision is an event that occurs when two or more objects come into contact with each other in a way that alters their motion. In physics, collisions are studied in terms of the conservation of momentum and the conservation of kinetic energy. In an elastic collision, the total kinetic energy of the system is conserved, and the objects bounce off each other without any loss of energy. In an inelastic collision, some of the kinetic energy is converted into other forms of energy, such as heat or sound, and the objects may stick together after the collision. Collisions can be categorized into two types: head-on collisions and oblique collisions. In a head-on collision, the objects approach each other directly from opposite directions, while in an oblique collision, the objects approach each other at an angle. Collisions are an important concept in physics and have applications in fields such as engineering, transportation, and sports. Understanding the principles of collisions can help us design safer cars, improve the performance of athletic equipment, and develop new technologies for space exploration.

Here,

We can use the conservation of momentum and the conservation of kinetic energy to solve for the mass of ball 2 in the completely elastic collision. Using the conservation of momentum:

m1v1i + m2v2i = m1v1f + m2v2f

Substituting the known values:

(6.7 kg)(2.0 m/s) + m2(-5.0 m/s) = (6.7 kg)(-6.18 m/s) + m2(0.83 m/s)

Simplifying and solving for m2:

(13.4 - 33.9) kg·m/s = -44.006 kg·m/s + 0.83 m2

-20.5 kg·m/s = 0.83 m2

m2 = (-20.5 kg·m/s) / (0.83 m/s)

m2 ≈ 24.7 kg

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The estimated surface temperature of the star determined using Wien's displacement law is approximately 4,498 Kelvin.

The surface temperature T of a star can be determined using Wien's displacement law, which states that the wavelength of maximum intensity emitted by a blackbody is inversely proportional to its temperature.

The equation is given as λ_max = (b/T), where λ_max is the wavelength of maximum intensity, T is the temperature in Kelvin, and b is Wien's constant.

Given that the maximum intensity wavelength of the star, λ_max, is 645 nm, we can convert it to meters by dividing by 10^9 (since 1 nm = 10^-9 m). Therefore, λ_max = 645 x 10^-9 m.

Substituting the known values into the equation, we have:

645 x 10^-9 m = (b/T)

To solve for T, we rearrange the equation as follows:

T = b / (645 x 10^-9 m)

The value of Wien's constant, b, is approximately 2.898 x 10 m·K. Substituting this value, we can calculate the surface temperature of the star T using the equation:

T = (2.898 x 10 m·K) / (645 x 10m)

By simplifying and performing the division, we find:

T ≈ 4,498 K

Therefore, the estimated surface temperature of the star is approximately 4,498 Kelvin.

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Answer:

Mass and kinetic energy have a positive relationship, which means that as mass increases, kinetic energy increases, if all other factors are held constant.

In this state, Kinetic energy is equal to half of the product mass and velocity. SI unit is joules. So it's if the mass is doubled then the kinetic energy also gets doubled.

The distance covered by the object during the first 3 second, t = 3sis given bys

3 = (1/2) × a × (3)² + 2as3 = (1/2) × 4ms⁻² × (3)² + 2 × 4ms⁻²s3 = 22m

Thus, during the first 3.00 seconds it will move 22m.

Given, the object starts from rest and accelerates uniformly.

Part a

If it moves 2.00 m during the first second

then, during the first 3.00 seconds it will move

The acceleration of the object is constant.

Therefore, the average acceleration of the object is given by the formula,

aavg = Δv/ Δt

Where;

Δv is the change in velocity of the object.

Δt is the change in time.

Now, since the object starts from rest, the initial velocity, u = 0m/s

Thus, the final velocity at time t is given by,

v = u + at

Now, we have v and u.

So, we can write above equation as

v = 0 + atv = at

Thus, the distance covered by the object in time t is given by,

s = ut + (1/2)at²

Where; s is the distance covered by the object

The distance covered by the object during the first 1 second, t = 1 s is given by,

s1 = (1/2)at²

s1 = (1/2) × a × (1)²

s1 = a/2

The distance covered by the object during the first 2 second, t = 2 s is given by,

s2 = (1/2)at² + s1

s2 = (1/2) × a × (2)² + (a/2)

s2 = 2a

The distance covered by the object during the first 3 second, t = 3 s is given by,

s3 = (1/2)at² + s2

s3 = (1/2) × a × (3)² + 2a

As per the question,The distance covered by the object during the first 1 second,

s1 = 2m

Therefore,

2 = (1/2) × a × (1)²a = 4ms⁻²

Thus,The distance covered by the object during the first 3 second, t = 3sis given bys

3 = (1/2) × a × (3)² + 2as3 = (1/2) × 4ms⁻² × (3)² + 2 × 4ms⁻²s3 = 22m

Thus, during the first 3.00 seconds it will move 22m.

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Answer:

All options except fur color of palomino horses and blood type

Answer:

A, B, D, and E

Explanation:

Answer:

9.79

Explanation:

to lazy to explain just go do your homework

The force of friction on the sled is  12.39 N.

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Frictional force allows the ball to stay in the hand while muscular force is employed to stop the motion of the ball during catching. Throughout this activity, the Earth's gravitational pull on the ball is constant.

Frictional force = μmg

Frictional force = (.110)(11.5)(9.8)

Frictional force = 12.39

The force of friction on the sled is  12.39 N.

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The gravitational force of Earth on the satellite, given that the satellite is launched into orbit 30000 km above sea level is 1.63×10³ N

The gravitaional force between two objects can be obtained by using the following formula:

F = GM₁M₂ / r²

Where

The following data were obtained from he question:

The gravitaional force can be obtained as shown below:

F = GM₁M₂ / r²

F = (6.673×10¯¹¹ × 5.4×10³ × 6.0×10²⁴) / (36400000)²

F = 1.63×10³ N

Thus, the gravitational force is 1.63×10³ N

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Answer:

the reflection of the candle in the concave mirror formed upside down real image that is diminished

Answer:

traveling at a constant acceleration

8.9 x 10⁻⁵ J energy this wave carries through the window during a 30.0 s commercial.

Area = 0.7 m²

electric field of wave = 0.0400 V/m

time = t =30 s

The intensity of an electromagnetic wave

I =\(E_{0}^{2}\) /  μ20c

E0 ^2 = 2Erms^2

c is the speed of light

I = 2Erms^2 / 2μ0^2c

I = Erms^2 / μ0^2c

I = (0.04) ^2 / 4

π x 10 ^-7 x 3 x 10 ^8

I = 4.24 x 10⁻⁶ W/m²

the amount of energy required

E = I x A x t

E = 4.24 x 10⁻⁶ x 0.7 x 30

E = 8.9 x 10⁻⁵ J

Electromagnetic radiation includes electromagnetic waves, which are synchronized oscillations of electric and magnetic fields. Electromagnetic radiation or electromagnetic waves are created because of the periodic trade of the electric or magnetic area. relying on how this periodic change occurs and the power generated, one-of-a-kind wavelengths of the electromagnetic spectrum are produced. In a vacuum, electromagnetic waves journey at the rate of light typically denoted c.   

Electromagnetic waves of various frequencies are called with the aid of exclusive names seeing that they've exclusive sources and results on count number. in order of increasing frequency and reducing wavelength these are radio waves, microwaves, infrared radiation, seen mild, ultraviolet radiation, X-rays, and gamma rays.

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Given a binding affinity of 4.73 electron volts, we are interested in learning the highest velocity of electrons that an 80 nanometer photon may eject from a material.

The formula KEe = hf BE, wherein hf is the photon energy and Also be is the energy (or binding energy) of the electron to the specific material, determines the maximal kinetic energy KEe of expelled electrons (photoelectrons). The formula KEe=hv-, where h is the absorption coefficient and v is the workfunction (not binding energy) of a electron to the specific material, yields the maximal kinetic KEe of released electron (photoelectrons). When incoming light with wavelengths of 400 nm & 250 nm strikes a metal surface, the maximal photoelectron ejection velocities are v and 2v, respectively. In terms of the Planck constant (h) and the speed of light (c), the binding energy of the metal is. The photovoltaic formula Ek = hf , wherein Ek is the maximal energy of the expelled electron, was developed by Einstein using the principle of energy conservation.

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For the designing of differential amplifier following were found out :

the small-signal gain is zero.

the transconductance (gm) and output resistance (ro) of the NMOS transistors are  -640 * (W/L) μA/V and 1 / (8 * (W/L)) kΩ respectively.

the transconductance (gm) and output resistance (ro) of the PMOS transistors are -320 * (W/L) μA/V and  respectively.

NMOS transistor: Wn = 0.03 μm, L = 0.2 μm

PMOS transistor: Wp = 0.0075 μm, L = 0.2 μm

Bias current: Itail = 1 mA

Resistance: R = 0.3 kΩ

To design the differential amplifier according to the given specifications, we will follow these steps:

Step 1: Calculate the small-signal gain (Av)

Step 2: Determine the transconductance (gm) and output resistance (ro) of the NMOS transistors

Step 3: Determine the transconductance (gm) and output resistance (ro) of the PMOS transistors

Step 4: Calculate the tail current (Itail) based on the specified Iss

Step 5: Determine the resistance (R) value

Step 6: Calculate the width (Wp) of the PMOS transistor

Step 7: Calculate the width (Wn) of the NMOS transistors

Now let's go through each step in detail.

Step 1: Calculate the small-signal gain (Av)

Given: Av = 10, VOP = VON = 3.5V

Av = (vop - von) / (vip - vin)

10 = (3.5 - 3.5) / (0.1)

10 = 0 / 0.1

Since the numerator is zero, the small-signal gain is zero.

Step 2: Determine the transconductance (gm) and output resistance (ro) of the NMOS transistors

Given: unCox = 400 μA/V², Vtn = 0.8V, n = 0.02 V^(-1), L = 0.2 μm

gm = 2 * unCox * (W/L) * (Vgs - Vtn)

ro = 1 / (lambda * unCox * (W/L))

We need to design the amplifier for DC operation (Vin = Vbias), where the differential voltage (vgs = Vin - Vbias) should be zero to operate the transistors in the saturation region.

For the NMOS transistors:

Vgs = 0 (since Vin = Vbias)

gm = 2 * unCox * (W/L) * (Vgs - Vtn)

  = 2 * 400 μA/V² * (W/L) * (0 - 0.8)

  = -640 * (W/L) μA/V

ro = 1 / (lambda * unCox * (W/L))

  = 1 / (0.02 V^(-1) * 400 μA/V² * (W/L))

  = 1 / (8 * (W/L)) kΩ

Step 3: Determine the transconductance (gm) and output resistance (ro) of the PMOS transistors

Given: upCox = 200 μA/V², Vtp = -0.8V, p = 0.04 V^(-1), L = 0.2 μm

Similarly, for the PMOS transistors, we need to design the amplifier for DC operation (Vin = Vbias), where the differential voltage (vsg = Vbias - Vin) should be zero to operate the transistors in the saturation region.

For the PMOS transistors:

Vsg = 0 (since Vin = Vbias)

gm = 2 * upCox * (W/L) * (Vtp - Vsg)

  = 2 * 200 μA/V² * (W/L) * (-0.8 - 0)

  = -320 * (W/L) μA/V

ro = 1 / (lambda * upCox * (W/L))

  = 1 / (0.04 V^(-1) * 200 μA/V² *

  = 1 / (5 * (W/L)) kΩ

Step 4: Calculate the tail current (Itail) based on the specified Iss

Given: Iss = 2 mA

Itail = Iss / 2

= 2 mA / 2

= 1 mA

Step 5: Determine the resistance (R) value

Given: Vs = 0.3 V, VDD = 5 V

We can calculate the resistance (R) value using Ohm's Law:

Vs = Itail * R

0.3 V = 1 mA * R

R = 0.3 kΩ

Step 6: Calculate the width (Wp) of the PMOS transistor

To calculate Wp, we'll use the equation for the tail current:

Itail = 2 * upCox * (Wp/L) * (VDD - Vtp)^2

1 mA = 2 * 200 μA/V² * (Wp/0.2 μm) * (5 V + 0.8 V)^2

1 mA = 2 * 200 μA/V² * (Wp/0.2 μm) * (5.8 V)^2

Solving for Wp:

Wp = (1 mA * 0.2 μm) / (2 * 200 μA/V² * (5.8 V)^2)

Wp = 0.01 μm / (2 * 200 μA/V² * 33.64 V^2)

Wp ≈ 0.0075 μm

Step 7: Calculate the width (Wn) of the NMOS transistors

Given: Wn = 4 * Wp

Wn = 4 * 0.0075 μm

Wn = 0.03 μm

So, the design parameters for the differential amplifier are as follows:

the small-signal gain is zero.

the transconductance (gm) and output resistance (ro) of the NMOS transistors are  -640 * (W/L) μA/V and 1 / (8 * (W/L)) kΩ respectively.

the transconductance (gm) and output resistance (ro) of the PMOS transistors are -320 * (W/L) μA/V and  respectively.

NMOS transistor: Wn = 0.03 μm, L = 0.2 μm

PMOS transistor: Wp = 0.0075 μm, L = 0.2 μm

Bias current: Itail = 1 mA

Resistance: R = 0.3 kΩ

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Explanation:

list in order with the smallest molecules at the top and largest molecules at the bottom:

1.Oxygen

2.Water

3.Carbon dioxide

4.amino acid

5.Glucose

6. Starch

7. Protein

The molecules can be arranged as follows with the smallest at the top is oxygen, water, carbon dioxide, amino acid, glucose, starch, protein.

The given molecules;

starch, water, glucose, carbon dioxide, protein, amino acid, oxygen

The molecular weight of the given compounds is listed as follows;

water -------- 18 g/mol

glucose -------  180.2 g/mol

starch (2 or more glucose) ------ 360 g/mol

carbon dioxide ------ 44 g/mol

protein -------- 20,000 g/mol

amino acid (glycine) ----- 75 g/mol

oxygen -------- 16 g/mol

Thus, the molecules can be arranged as follows with the smallest at the top;

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Answer: that Christians should not withdraw from the world, but should actively participate in the ... That is perhaps the reason why there is currently such an ... Investigating the root causes and consequences of corruption may contribute to a more.

Explanation:

Answer:

Concave mirror

Explanation:

Because as we move the object far away from the mirror, the image gets inverted.

Answer:

Concave mirror

Explanation:

Answer:

Explanation:

Given

Velocity = 388m/s

Height S = 2.89m

Required

Time

Using the equation of motion

S =ut+1/2gt²

2.89 = 388t+1/2(9.8)t²

2.89 = 388t+4.9t²

Rearrange

4.9t²+388t-2.89 =0

Factorize

t = -388±√388²-4(4.9)(2.89)/2(4.9)

t= -388±√(388²-56.644)/9.8

t = -388±387.93/9.8

t =0.073/9.8

t = 0.00744 seconds

40cm³ is  volume of a metal block measures 10cm×2cm×2cm and 5 blocks have the same total volume.

volume=l×b×h

volume=10cm×2cm×2cm= 40cm³

volume=l×b×h

volume= 2cm×2cm×2cm=8cm³

blocks have the same total volume= 40cm³/8cm³= 5

The space occupied inside an object's borders in three dimensions is referred to as its volume. It is sometimes referred to as the object's capacity. Finding an object's volume can help us calculate the quantity needed to fill it, such as the volume of water needed to fill a bottle, aquarium, or water tank.

A sphere is the most basic and typical form of a three-dimensional shape. We see spheres on a regular basis in the form of balls, globes, ornamental lights, oranges, etc.

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The resultant force is the force that can replace all the acting forces and have a comparable effect on the section or beam when several forces are acting on it.

If the forces acting on a body in a specific direction result in a net sum of zero in that direction, the forces acting on the body are said to be in equilibrium.

The resultant force is the force that can replace all other forces operating on a beam or section while still having the same impact on the section or beam. This force is used when many forces are acting on a beam or section.

The resultant force in the X direction equals 250 and must act for more than five, minus 500 cosign 30 minus 300, which equals 533.41 Newton and the magnitude of the forces in the left direction. The magnitude of the resultant force in the y direction should likewise be the same. S

ome forces that are equal to 500 sign 30 - 150 in the y direction. multiply it by 3/5 so that it equals 100. Newton's are inefficient, thus the force Rf's magnitude should be square root off 533.1 square lost 100 square, equaling 542 Newtons, and the angle Sita if 10 members 100 over 533.41, equal to 10.6 degrees for the location off.

We have 533.1 when we multiply the equal 500 committed by the result on force So instant off the resultant around the. 30 supply point to minus 250 and multiplied by minus 500. city above five, apply.

Subtract 200 50 from 0.5. Divide by 4/5. Loss of three supplies A 300 must submit one. Therefore, using this equation, we can determine T's value, which is 827 millimeters.

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Answer:

True

Explanation:

Answer:

-Radio waves

-Microwaves

-Infrared light (IR)

-Visible light

-Ultraviolet (UV)

-X-ray

-Gamma rays

(this is in order from the longest wavelength to shortest wavelength)

The types of energy that move through the system are as follows: potential energy, kinetic energy, mechanical energy, and electrical energy.The water stored in the dams contains potential energy.

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The car's velocity is 2 m/s.

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer:

mass is the amount of matter in an object, whereas weight is the force exerted on an object by gravity