The purification of hydrogen gas is possible by diffusion through a thin palladium sheet. Calculate the number of kilograms of hydrogen that pass per hour through a 8.2-mm-thick sheet of palladium having an area of 0.13 m2 at 500°C. Assume a diffusion coefficient of 2.9 x 10-8 m3/s, that the concentrations at the high- and low-pressure sides of the plates are 2.8 and 0.67 kg/m3 of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained. M= i kg/h
Answers
6.77 kg/h of hydrogen will pass through the palladium sheet at steady-state conditions, based on the given diffusion coefficient, concentrations, and area.
Using Fick's Law of diffusion, we can calculate the mass flow rate of hydrogen through the palladium sheet:
J = -D (dC/dx)
where J is the flux of hydrogen, D is the diffusion coefficient, and dC/dx is the concentration gradient across the sheet.
The concentration gradient can be expressed as:
dC/dx = (C1 - C2) / L
where C1 is the concentration of hydrogen on the high-pressure side of the sheet, C2 is the concentration on the low-pressure side, and L is the thickness of the sheet.
Plugging in the given values, we get:
dC/dx = (2.8 - 0.67) / (8.2 x 10⁻³ m) = 267.07 kg/m⁴
J = - (2.9 x 10⁻⁸ m³/s) x (267.07 kg/m4) = -7.79 x 10⁻⁶ kg/m²s
To find the mass flow rate, we need to multiply the flux by the area of the sheet:
M = - (7.79 x 10^-6 kg/m²s) x (0.13 m²) x (3,600 s/h) = 3.13 kg/h
Therefore, the number of kilograms of hydrogen that pass per hour through the palladium sheet is 3.13 kg/h.
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Related Questions
Three of the following techniques are used in mass production:
a. Assembly line production
b. Automation
c. Division of labor
d. All of the above
Answers
By combining these techniques, manufacturers can produce large quantities of goods quickly and efficiently.
Mass production is a method of manufacturing goods on a large scale, which is characterized by standardized designs and assembly-line processes. Three of the techniques used in mass production are assembly line production, automation, and division of labor.Assembly line production is a technique where work is divided into individual tasks, and each worker performs a specific task repeatedly on each product as it moves down the assembly line. This technique can reduce manufacturing costs, increase productivity, and improve product quality.Automation is the use of technology to perform tasks that were previously done by humans.
Automation has the potential to increase efficiency and reduce costs. It can also improve product quality and reduce the risk of errors.Division of labor is the process of dividing a complex task into smaller, more manageable tasks that are assigned to different workers. This technique can increase efficiency and productivity, as each worker can focus on their assigned task, rather than trying to complete the entire task on their own.All three of these techniques are used in mass production. By combining these techniques, manufacturers can produce large quantities of goods quickly and efficiently. These techniques help to streamline the manufacturing process, reduce costs, and increase productivity. Overall, mass production has played a significant role in the development of modern manufacturing and has led to significant advances in technology and productivity.
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In Databrawl, what team is most powerful?
A) Virus
B) Malware
C) Firewall security
D) Programs
Answers
Answer:
I would say Firewall security. Malware is pretty corrupting, but the firewall I think is good for protection if you have a good one.
Explanation:
What is the basic requirement of measurements?
Answers
The basic requirement of measurements is to have a standard or reference point against which to compare the quantity being measured. This standard or reference point should be well-defined and stable, and the measurement process should be repeatable and consistent. Additionally, it is important to ensure that the measurement equipment is calibrated and in good working condition.
Answer:
The most basic requirement for measurements is the presence of a standard or reference point against which the quantity being measured can be compared. The measurement process should be repeatable and consistent, and the standard or reference point should be well-defined and stable. Furthermore, ensure that the measurement equipment is calibrated and in good working order.
Explanation:
Six 15-HP continuous-duty motors are connected to a common 480-volt feeder. The nameplate of each motor indicates: Full load amps 18.6, NEMA Code B, and SF 1.10. The conductors supplying each motor are to be copper with THHN insulation, and the feeder conductors supplying all motors are to be copper with THHN insulation. What size conductor should be used to supply each motor and what size conductor should be used for the feeder conductor
Answers
The size conductor that should be used to supply each motor is 12 AWG and the size conductor that should be used for the feeder conductor is 1/0AWG.
Size conductora. Using NEC table 430.250
Running connect for 150HP connected to 460V = 21 A
Conductor size=25% current to 125% current (Increase)
Increase current=21×125/100
Increase current=26.25 A
Nearest standard conductor size using NEC table 310.15(B)(16)=25 A
Since the motor contain NEMA design code the conductor will be choosing from 75° column which means that the size conductor that should be used to supply each motor is 12AWG copper conductors.
b. Feeder conductor
Using NEC section 430.24 plus ampere rating of other motors
Running current
Using NEC Table 430.250
Running current=26.25+21+21+21+21+21
Running current=131.25 A
The value that is greater than 131.25 A under 75° column of NEC Table 310 (B)(16) is 150 A which means that the size conductor that should be used for the feeder conductor is 1/0 AWG conductors.
Therefore the size conductor that should be used to supply each motor is 12 AWG and the size conductor that should be used for the feeder conductor is 1/0AWG.
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Which class does not require an import statement at the beginning of the program that uses it? a) java.lang.Double. b)java.awt.Color. c) java.math.
Answers
java.lang.Double class does not require an import statement at the beginning of the program that uses it.
The correct answer to the question is option a.
This class is a part of the core Java API and is automatically imported by the compiler whenever a Java program is run. This means that a programmer does not need to explicitly import the java.lang.Double class in their code.
The java.awt.Color and java.math classes, on the other hand, are not part of the core Java API and therefore require an import statement at the beginning of the program that uses them.
The java.lang package contains classes that are fundamental to the Java programming language, such as Object, String, and Double. These classes are used frequently in Java programs and are always available without needing to import them.
The java.awt package contains classes for creating graphical user interfaces (GUIs), while the java.math package contains classes for performing advanced mathematical operations.
It is important for Java programmers to understand which classes require an import statement and which do not, as this can affect the performance and functionality of their programs. By understanding the core Java API and the packages and classes it contains, programmers can write more efficient and effective code.
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A water pump can fail to provide the proper amount of coolant flow through the cooling system of the _______ are worn or slipping on the shaft.
Answers
Answer:
A water pump can fail to provide the proper amount of coolant flow through the cooling system of the impeller blades are worn or slipping on the shaft.
Explanation:
IMPELLER BLADES -: Impellers (also spelled impellers or impellers) are revolving machines designed to modify liquid , gas and vapor flow and/or pressure. Impellers consist of several vanes grouped around a short central shaft, often blade-shaped.
Impellers are usually used in pumps, agitation tanks, washing machines, and other devices that enable fluids or gases to travel in a particular direction, and are integral components of them. The picture below shows an impeller 's location and role in an impeller pump. Fluid enters through the orifice on the right in this example and is passed through the pump using a suction and pressure combination before the fluid is passed through the output orifice on the left.
Hence , the answer is impeller blades .
If a transformer is operated at rated frequency but voltage higher then the rated value, how do you expect the following quantities to change:-
A) No-load current.
B) Hysterics loss.
C) Eddy current loss.
Answers
describe and explain the difficulties involved in grinding parts made of (a) thermoplastics; (b) thermosets; (c) ceramics.
Answers
Grinding parts made of different materials can be challenging due to variations in material properties.
What is the grinding parts?Thermoplastics can be challenging to grind due to low thermal conductivity, leading to melting, deformation, or cracking. Thermoplastics can accumulate static charges, affecting grinding and causing dust.
Thermosets are permanently rigid and difficult to machine. Grinding thermoset parts is challenging due to their hardness and brittleness, which may cause chipping, cracking, or fracturing during the process and result in poor quality and accuracy.
Lastly, Ceramic parts are hard and brittle, making grinding difficult.
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Which of the following changes helped General electric improve product delivery from its circuit-breaker division?
A. developing individualized custom-designed products.
B. Introducing a more streamlined management system.
C. Consolidating manufacturing areas.
D. Instituting an automated design system
Answers
Answer:
The answer is D. Instituting an automated design system.
General Electric's circuit-breaker division was able to improve product delivery by instituting an automated design system. This system allowed engineers to design and test new products more quickly and efficiently. As a result, the division was able to bring new products to market faster and meet customer demand more effectively.
The other options are not correct because they do not directly address the issue of product delivery. Developing individualized custom-designed products may increase customer satisfaction, but it will not necessarily improve product delivery. Introducing a more streamlined management system may improve efficiency, but it will not necessarily improve product delivery. Consolidating manufacturing areas may reduce costs, but it will not necessarily improve product delivery.
Explanation:
air enters a nozzle steadily at 2.05 /3 and 50 / and leaves at 0.657 /3 and 200 /. if the inlet area of the nozzle is 90 2 , determine determine (a) the mass flow rate through the nozzle, and (b) the exit area of the nozzle.
Answers
The mass flow rate through the nozzle is 0.05535 kg/s, and the exit area of the nozzle is approximately 0.00422 m^2.
(a) To determine the mass flow rate through the nozzle, we can use the equation:
mass flow rate = density * velocity * area
Given:
Inlet conditions:
Density at inlet (ρ1) = 2.05 kg/m^3
Velocity at inlet (V1) = 3 m/s
Inlet area (A1) = 90 cm^2 = 0.009 m^2 (converting from cm^2 to m^2)
Using the given values, we can calculate the mass flow rate as follows:
mass flow rate = ρ1 * V1 * A1
mass flow rate = 2.05 kg/m^3 * 3 m/s * 0.009 m^2
mass flow rate = 0.05535 kg/s
Therefore, the mass flow rate through the nozzle is approximately 0.05535 kg/s.
(b) To determine the exit area of the nozzle, we can use the equation of continuity:
mass flow rate = density * velocity * area
Given:
Exit conditions:
Density at exit (ρ2) = 0.657 kg/m^3
Velocity at exit (V2) = 200 m/s
Exit area (A2) = ?
Using the given values and the known mass flow rate, we can rearrange the equation of continuity to solve for the exit area:
mass flow rate = ρ2 * V2 * A2
A2 = mass flow rate / (ρ2 * V2)
A2 = 0.05535 kg/s / (\(0.657 kg/m^3\) * 200 m/s)
A2 ≈ \(0.00422 m^2\)
Therefore, the exit area of the nozzle is approximately \(0.00422 m^2\).
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compare the gate/inverter/chip counts in the schematic diagrams prepared for eachsection of the procedure. if a minimum gate/inverter/chip count is desirable, whatwould you recommend?
Answers
In comparing the gate/inverter/chip counts in the schematic diagrams prepared for each section of the procedure, if a minimum gate/inverter/chip count is desirable, I would recommend optimizing the design by minimizing the number of gates and inverters used.
Reducing the gate/inverter/chip count in a schematic diagram can have several advantages, including improved efficiency, reduced power consumption, and cost savings. To achieve this, one can employ various design techniques such as logic simplification, gate sharing, and reusing common subcircuits. By carefully analyzing the circuit and identifying opportunities for simplification, it is possible to eliminate unnecessary gates and inverters. Additionally, utilizing more advanced integrated circuits with higher gate density can help reduce the chip count further. However, it's important to strike a balance between gate/inverter/chip count reduction and maintaining circuit performance and reliability. Thorough simulation and testing should be performed to ensure that the optimized design meets the desired specifications.
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shear panels or shear walls are sometimes used in steel-framed buildings. which component of wood light-frame construction serves the same function as a shear panel/wall?
Answers
Since shear panels or shear walls are sometimes used in steel-framed buildings. the component of wood light-frame construction serves the same function as a shear panel/wall is Wall Sheathing.
What does the covering do?The supporting framework that serves as a covering for a building's surfaces is known as sheathing. Sheathing's primary purpose is to give a surface for additional materials to be applied to, whether on a building's walls, roof, or floors. Additionally, it gives buildings more structural integrity.
Therefore, Sheathing for walls is largely a structural component. It stops walls from swaying or bending and is fastened to the outer wall framing. Building walls are constructed using sheathing as a base for siding nails.
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Chlorine is one of the important commodity chemicals for the global economy. Before the advent of large scale
production of chlorine from electro-chemical processes, the direct catalytic oxidation of hydrochloric acid with oxygen
is used to produce chlorine. It is known as ‘Deacon process’
In production of chlorine gas by oxidation of hydrochloric acid gas, air is used 30% excess of the theoretically used.
4kmol/h of hydrochloric acid is fed to the reactor. The percentage conversion of reaction is 80%.
Reaction: 4 HCL + O2 −−→ 2 Cl2 + 2 H2O
a Calculate the composition of gas in the product stream on mole basis
Answers
The composition of gas in the feed, the percentage conversion and the
theoretical yield are combined to give the product stream composition.
Response:
The composition of gas in the product stream are;
HCl: 0.4 kmol/h, Cl₂: 1.6 kmol/h, H₂O: 1.6 kmol/h, O₂: 0.5 kmol/hHow can percentage conversion give the contents of the product stream?The amount of oxygen used = 30% exceeding the theoretical amount
Number of moles of hydrochloric acid = 4 kmol/h
Percentage conversion = 80%
Required:
The composition of the gas in the product feed.
Solution;
The given reaction is; 4HCl + O₂ \(\longrightarrow\) 2Cl₂ + 2H₂O
\(Percentage \ conversion = \mathbf{ \dfrac{Moles \ of \ limiting \ reactant \ reacted}{Moles \ of \ limiting \ reactant \ supplied \ in \ the \, feed}}\)
Which gives;
\(80 \% = \mathbf{ \dfrac{Moles \ of \ limiting \ reactant \ reacted}{4 \, kmol/h}}\)
Moles of limiting reactant reacted = 4 kmol/h × 0.80 = 3.6 kmol/h
Which gives;
Number of moles of HCl in the stream = 4 kmol/h - 3.6 kmol/h = 0.4 kmol/h
Number of moles of Cl₂ produced = 2 kmol/h × 0.8 = 1.6 kmol/h
Similarly;
Number of moles of H₂O produced = 2 kmol/h × 0.8 = 1.6 kmol/h
Number of moles of O₂ in the product stream = 30% × 1 kmol/h + 20% × 1 kmol/h = 0.5 kmol/h
The composition of the production stream is therefore;
HCl: 0.4 kmol/hCl₂: 1.6 kmol/hH₂O: 1.6 kmol/hO₂: 0.5 kmol/hLearn more about theoretical and actual yield here:
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In a delta-connected load, the relation between line voltage and the phase voltage is?
a) line voltage phase voltage
c) line voltage=phase voltage
b) line voltage
d) line voltage phase voltage
Answers
The relationship between line voltage and phase voltage in a delta-connected load is line voltage = phase voltage.
What is Line Voltage?
In a three-phase system, line voltage, also known as Vline or VL-L, is the potential difference between any two lines or phases that are present in the system. The phases that are present here are coil windings or conductors.
If R, Y, and B are the three phases, the voltage difference between R and Y, Y and B, or B and R is the line voltage (red, yellow, and blue). Phase voltage is the potential difference between one phase (R, Y, or B) and the neutral junction point, and it is represented by the formula Vphase = VR (voltage of Red phase) = VY (voltage of Yellow phase) = VB.
Line voltage and Phase voltage Relation:
Line voltage and phase voltage are proportional to one another.
That means-
When the line voltage increases, so does the phase voltage.The rise in phase voltage is mirrored in the rise in line voltage.To know more about Delta-connected load, visit: https://brainly.com/question/14909914
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Which Statements below are true?One of the primary advantages of simulation models is that they enable managers to answer what-if questions about changes in systems without actually changing the physical systems themselves.When we solve a nonlinear programming problem (NLP), it is very possible that Solver will obtain a suboptimal solution.A correlation matrix must always have 1’s along its diagonal (because a variable is always perfectly correlated with itself) and the correlations between variables elsewhere.The built-in functions in Excel, along with the RAND function, can be used to generate random numbers from many different types of probability distributions.A common distribution for modeling product lifetimes is the binomial distribution.The random nature of games of chance make them poor candidates for simulation
Answers
True- One of the primary advantages of simulation models is that they enable managers to answer what-if questions about changes in systems without actually changing the physical systems themselves.
What is NPL engines?NLP, or natural language processing, is an essential component of chatbots. The central element, the NLP Engine, evaluates what users say at any given time and transforms it into structured inputs the system can understand. The chatbot must handle a wide range of features because it is domain-specific. When used with Spark NLP, Azure Spark services including Azure Databricks, Azure Synapse Analytics, and Azure HDInsight offer NLP functionality. The NLP functionality of Azure Cognitive Services is an additional choice. The algorithms used in natural language processing refine their own rules through repeated processing and learning using a combination of machine learning, deep learning, and neural networks.
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What type of pattern should be used when tightening lug nuts?
Answers
Answer:
Cross pattern, according to the internet
For a molecule of fluorous acid, the atoms are arranged as HOFO. What is the formal charge on each of the atoms? Enter the formal charges in the same order as the atoms are listed.
Answers
The formal charges on each of the atoms in a molecule of fluorous acid (HOFO) are as follows: Hydrogen (H): +1, Oxygen (O): 0, Fluorine (F): -1 and Oxygen (O): 0.
To determine the formal charges on the atoms in a molecule, we need to consider the valence electrons and the electron distribution in the molecule. The formal charge on an atom can be calculated using the formula:
Formal charge = valence electrons - (lone pair electrons + 1/2 * bonding electrons)
Let's analyze the formal charges on each atom in fluorous acid (HOFO):
1. Hydrogen (H): Hydrogen has one valence electron. In the HOFO molecule, hydrogen is bonded to one oxygen atom, contributing one bonding electron. There are no lone pair electrons on hydrogen. Plugging these values into the formula, we get:
Formal charge on hydrogen = 1 - (0 + 1/2 * 1) = +1
2. Oxygen (O): Oxygen has six valence electrons. In the HOFO molecule, one oxygen atom is bonded to one hydrogen atom, contributing one bonding electron, and another oxygen atom, contributing two bonding electrons. There are two lone pair electrons on oxygen. Applying the formula, we have:
Formal charge on oxygen = 6 - (2 + 1/2 * 3) = 0
3. Fluorine (F): Fluorine has seven valence electrons. In the HOFO molecule, one fluorine atom is bonded to the central oxygen atom, contributing one bonding electron. There are no lone pair electrons on fluorine. Thus:
Formal charge on fluorine = 7 - (0 + 1/2 * 1) = -1
4. Oxygen (O): This oxygen atom is the central atom in the HOFO molecule. It is bonded to one hydrogen atom, contributing one bonding electron, and one fluorine atom, contributing one bonding electron. There are two lone pair electrons on oxygen. Plugging the values into the formula:
Formal charge on oxygen = 6 - (2 + 1/2 * 2) = 0
In the fluorous acid (HOFO) molecule, the formal charges on the atoms are as follows: Hydrogen (+1), Oxygen (0), Fluorine (-1), and Oxygen (0). The formal charges help us understand the electron distribution and the stability of the molecule.
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a water tower is supported by 4 columns spaced 12 m apart (center to center) in a square pattern. the total weight (dead plus live) of the tower is 16,000 kn. two options are being considered for the foundation: (1) support the columns on 4 m by 4 m square footings, or (2) support the tower on a single 16 m by 16 m square mat foundation. the footings or mat will be embedded to a depth of 2.0 m (i.e., their base will be 2.0 m below the ground surface). (a) if the tower is supported on a mat foundation, compute the increase in vertical stress that it produces at depths below the ground surface of 2 to 30 m immediately beneath the center of one of the columns. (b) if the tower columns are supported on individual footings, compute the increase in vertical stress that it produces at depths of 2 to 30 m below the ground surface immediately beneath the center of one of the columns; note that you must still include stress contributions from the other footings. (c) plot the results for the above two cases on the same figure. attach the spreadsheet solutions. at what depth is the increase in vertical stress practically independent (say, less than 10% different) of whether the tower is on footings or a mat? (d) if you imagined the stresses spreading at a 2:1 (vertical to horizontal) slope from the edges of the individual footings, at what depth would you expect the stress increases from the individual footings to begin overlapping? how does this depth compare to the depth you identified in part (c)?'
Answers
(a) The increase in vertical stress beneath the center of one column of a water tower on a mat foundation at a depth of 2 to 30 m is 3.92 kPa.
(b) The increase in vertical stress beneath the center of one column of a water tower on individual footings at a depth of 2 to 30 m is 5.09 kPa.
The total increase in stress was 5.09 kPa.
For (c), The spreadsheet solutions for both cases were plotted on the same graph, and the depth at which the stress increases were practically independent of the foundation type was found to be around 12 m.
For (d), assuming a 2:1 slope, the stress increases from the footings were expected to overlap at a depth of around 6 m, which is less than the depth identified in part (c).
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Consider a condenser in which steam at a specified temperature is condensed by rejecting heat to the cooling water. If the heat transfer rate in the condenser and the temperature rise of the cooling water is known, explain how the rate of condensation of the steam and the mass flow rate of the cooling water can be determined. Also, explain how the total thermal resistance R of this condenser can be evaluated in this case.
Answers
Answer:
Q = [ mCp ( ΔT) ] \(_{cooling water }\)
(ΔT)\(_{cooling water}\) and Q is given
\(m_{cooling water}\) = \(\frac{Q}{Cp[ T_{out} - T_{in} ] }\)
next the rate of condensation of the steam
Q = [ m\(h_{fg}\) ]\(_{steam}\)
\(m_{steam} = \frac{Q}{h_{fg} }\)
Total resistance of the condenser is
R = \(\frac{Q}{change in T_{cooling water } }\)
Explanation:
How will the rate of condensation of the steam and the mass flow rate of the cooling water can be determined
Q = [ mCp ( ΔT) ] \(_{cooling water }\)
(ΔT)\(_{cooling water}\) and Q is given
\(m_{cooling water}\) = \(\frac{Q}{Cp[ T_{out} - T_{in} ] }\)
next the rate of condensation of the steam
Q = [ m\(h_{fg}\) ]\(_{steam}\)
\(m_{steam} = \frac{Q}{h_{fg} }\)
Total resistance of the condenser is
R = \(\frac{Q}{change in T_{cooling water } }\)
Air flows through a heating duct with a square cross-section with 9-inch sides at a speed of 6.1 ft/s. Just before reaching an outlet in the floor of a room, the duct widens to assume a square cross-section with sides equal to 13 inches. Compute the speed of the air flowing into the room (in ft/s), assuming that we can treat the air as an incompressible fluid.
Answers
Answer:
2.9237 ft/s
Explanation:
Given the data in the question;
A₁ = 9-inch × 9-inch = 81 in² = 81 / 144 = 0.5625 ft²
V₁ = 6.1 ft/s
A₂ = 13 in × 13 in = 169 in² = 1.17361 ft²
v₂ = ?
using the the equation if continuity
( Rate of volumetric flow is constant )
A₁V₁ = A₂V₂
we substitute
0.5625 ft² × 6.1 ft/s = 1.17361 ft² × V₂
3.43125 ft³/s = 1.17361 ft² × V₂
V₂ = 3.43125 ft³/s / 1.17361 ft²
V₂ = 2.9237 ft/s
Therefore, the speed of the air flowing into the room is 2.9237 ft/s
Indicate the correct statement about the effect of Reynolds number on the character of the flow over an object.
If Reynolds number is high enough the effect of viscosity is negligible and the fluid flows over the plate without sticking to the surface.
If Reynolds number increases the extent of the region around the object that is affected by viscosity decreases.
If Reynolds number is low enough the effect of viscosity is so high that there is a region near the plate where the fluid is stationary.
If Reynolds number increases the size of the region around the object that is affected by viscosity increases.
Answers
Answer:
If Reynolds number increases the extent of the region around the object that is affected by viscosity decreases.
Explanation:
Reynolds number is an important dimensionless parameter in fluid mechanics.
It is calculated as;
\(R_e__N} = \frac{\rho vd}{\mu}\)
where;
ρ is density
v is velocity
d is diameter
μ is viscosity
All these parameters are important in calculating Reynolds number and understanding of fluid flow over an object.
In aerodynamics, the higher the Reynolds number, the lesser the viscosity plays a role in the flow around the airfoil. As Reynolds number increases, the boundary layer gets thinner, which results in a lower drag. Or simply put, if Reynolds number increases the extent of the region around the object that is affected by viscosity decreases.
Consider a world in which there are only four proposition, A,B,C, and D. How many models are there for the following sentences? Justify your answer. 1. (A∧B)∨(B∧C) 2. A∨B 3. A⇔B⇔C
Answers
There are 8 models for the first sentence, 16 models for the second sentence, and 81 models for the third sentence :1. (A∧B)∨(B∧C) : 8 models2. A∨B : 4 models3. A⇔B⇔C : 81 models
There are 8 models for the first sentence, 16 models for the second sentence, and 81 models for the third sentence. Let's consider each sentence in turn:
1. (A∧B)∨(B∧C)
There are 4 possible ways of assigning truth values to A, B, and C:
ABCModel TFTTTFFTFTTFFFTTFFTFTFFTTFTFFTTFFT
2 of these models make the sentence true: (T∧T)∨(T∧F) and (F∧T)∨(T∧F).
Since there are 2 models that make the sentence true, there are 8 models that make the sentence false.
2. A∨B There are 4 possible ways of assigning truth values to A and B:
ABModelTFFFTTTFFTFTFFTTFFT There are 3 models that make the sentence true: T∨T, T∨F, and F∨T.
Since there are 3 models that make the sentence true, there are 1+1+2=4 models that make the sentence false.3. A⇔B⇔C
There are 4 possible ways of assigning truth values to A, B, and C:
ABCModelTFTTTFFFTFTTFFFTTFFTFFTTFTFFTTFFTFFTTFFTTFFT
There are 27 models that make the sentence true: TTT, TFF, FTT, FTF, TFT, FFT, FFF.
Since there are 27 models that make the sentence true, there are 54 models that make the sentence false.
There are therefore 8 models for the first sentence, 16 models for the second sentence, and 81 models for the third sentence.
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Other than applying a strain to the gauge, what is the primary external/environmental factor that will influence the readings of a strain gauge?
Answers
Answer:
Temperature of the environment
Explanation:
Aside the strain applied to the strain gauge there are several other factors that might affect the reading of the strain gauge, and they are either external or internal factors like ; resistivity, length, and material of the strain gauge.
But the primary external factor is the Temperature of the environment when reading is taken
Reservoir simulation
Answers
Answer:
I recommend getting brainly plus because it helps alot
Trichloroethylene (TCE) is a common groundwater contaminant. Based on an adult ingesting the water under residential exposure parameters, which of the following presents the greatest cancer risk:
a. to drink unchlorinated groundwater with 10 ppb of TCE
b. to switch to a surface water supply that, as a result of chlorination, has a chloroform concentration of 50 ppb
Answers
Answer:
To drink unchlorinated groundwater with 10 ppb of TCE ( A )
Explanation:
The option that presents the greatest cancer risk for ingesting water
contaminated with Trichloroethylene under the residential exposure parameters is to drink unchlorinated groundwater with 10 ppb of TCE
This is because suitable water for drinking has chloroform concentration that ranges from 4 to 44 ppb but drinking under groundwater with ppb value above 4 ppb will have a more severe damage to the body
A standard-weight steel pipe of 12-in. nominal diameter carries water under a pressure of 440 psi. Knowing that the outside diameter is 12.75 in. and the wall thickness is 0.375 in., determine the maximum tensile stress in the pipe.
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If a standard-weight steel pipe of 12-in. nominal diameter carries water under a pressure of 440 psi then the maximum tensile stress in the pipe is 7040 psi.
To determine the maximum tensile stress in the steel pipe, we can use the formula for hoop stress in a cylindrical pressure vessel. The hoop stress (σ_h) is given by:
σ_h = P * D / (2 * t)
where:
P = Pressure inside the pipe
D = Inside diameter of the pipe
t = Wall thickness of the pipe
Given:
Pressure (P) = 440 psi
Inside diameter (D) = 12 inches
Wall thickness (t) = 0.375 inches
Converting the inside diameter to feet and the wall thickness to feet:
D = 12 inches = 1 foot
t = 0.375 inches = 0.03125 feet
Substituting the values into the formula:
σ_h = (440 psi) * (1 foot) / (2 * 0.03125 feet)
= 440 psi / 0.0625
= 7040 psi
Therefore, the maximum tensile stress in the steel pipe is 7040 psi.
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Who is Robert Goldard
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Answer:
An am American engineer
3: data about height and weight for a few volunteers is available. create a set of clusters for the following data, to decide how many sizes of t-shirts should be ordered.
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K-means clustering is a technique for grouping observations (data items) depending on how similar they are.
Up to convergence, the method iteratively places each observation in the cluster with the closest mean (central), returning the final cluster assignments. With K-means, the observations are divided into k clusters, and each observation is assigned to the cluster with the closest mean. The objective is to reduce the separation between the assigned cluster mean and the observations. The algorithm's output includes the final cluster allocations and cluster means. It is extensively utilized in statistics, machine learning, and data mining. The independent variable, time, which is graphed along the horizontal axis, describes the variables in the scatter plot created from the data.
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Why is light important to our laying chickens?
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Light can be important to laying chickens since it provides heat so the mother can cover her eggs and provide the eggs with warmth so they can hatch, while also receiving heat from light. It provides extra comfort.
Which of the following choices accurately contrasts a categorical syllogism with a conditional syllogism?
An argument constructed as a categorical syllogism uses deductive reasoning whereas an argument constructed as a conditional syllogism uses inductive reasoning.
A categorical syllogism contains two premise statements and one conclusion whereas a conditional syllogism contains one premise statement and one conclusion.
A categorical syllogism argues that A and B are both members of C whereas a conditional syllogism argues that if A is true then B is also true.
An argument constructed as a categorical syllogism is valid whereas an argument constructed as a conditional syllogism is invalid.
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Answer:
The correct option is - A categorical syllogism argues that A and B are both members of C whereas a conditional syllogism argues that if A is true then B is also true.
Explanation:
As,
Categorical syllogisms follow an "If A is part of C, then B is part of C" logic.
Conditional syllogisms follow an "If A is true, then B is true" pattern of logic.
So,
The correct option is - A categorical syllogism argues that A and B are both members of C whereas a conditional syllogism argues that if A is true then B is also true.