the rate constant for this zero‑order reaction is 0.0170 m·s−1 at 300 ∘c. a⟶products how long (in seconds) would it take for the concentration of a to decrease from 0.780 m to 0.280 m?

The air is too "rich" to burn above the upper limit, but the situation might soon deteriorate into danger: For instance, increasing the air in a space can quickly reduce the product's vapor percentage to levels that are within its flammability range, which could have explosive effects.

Flammable liquids and gases need to be handled and stored carefully since they have low flash points. Never assume that these items won't catch fire. You must continually keep in mind the safety precautions for handling and storing combustible products if you want to keep both you and your company safe.

To prevent them from getting engaged and stoking a fire, combustible objects including cardboard, paper towels, sawdust, and waste must be kept away from flammable storage spaces. All flammable liquid containers must be kept closed while not in use to further help avoid fires.

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Answer:

Students communicate results in laboratory reports, and professional scientists communicate results in scientific journals.

Explanation:

This is the answer i just did it.

I hope this helps.

Answer:

Students communicate results in laboratory reports, and professional scientists communicate results in scientific journals.

Explanation:

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Answer:What happens to the temperature of a substance during a phase change? Why does this happen?

Explanation:During a phase change the temperature remains constant. This is because the heat supplied to change the state of matter is used in breaking the intermolecular forces and other attractive forces. Therefore, the temperature remains constant as no heat is absorbed or released.

Answer:

Mixture

Explanation:

A mixture has two or more substances that are together in the same place but are not chemically combined .

HOPE THIS HELPS YOU;)

To calculate the concentration of the iron sample by using a spectrophotometric method, it is necessary to dilute the sample. The volume to which the sample should be diluted is a crucial question in achieving the most accurate result.

The process involves diluting the sample, and the concentration must be calculated to determine the precise result of the dilution. This question can be answered by calculating the uncertainty and identifying the value of the uncertainty. The value with the lowest uncertainty will be the best value to choose. The volume with the lowest uncertainty will be the ideal volume to dilute the 5 ml aliquot of the iron sample to achieve a result with the minimum level of uncertainty.
To determine the optimal volume for dilution, the uncertainty should be calculated.
This can be done by using the equation for propagation of uncertainty, which states that the uncertainty of the result is equal to the square root of the sum of the squares of the uncertainties of the individual components. When calculating the uncertainty of the diluted sample, the uncertainty of the initial sample and the uncertainty of the diluent must be considered. The uncertainty of the initial sample can be calculated using the calibration curve. As the expected iron content is 40-60%, the concentration of the sample is expected to be 8-12 ppm. The uncertainty of the calibration curve is given by the standard deviation of the calibration standards.
The diluent has a negligible uncertainty. The uncertainty of the diluted sample will be lower if a larger volume is used for dilution because the relative contribution of the uncertainty of the initial sample will decrease. However, the uncertainty of the measurement will increase if the sample is diluted too much because the concentration of the analyte will be too low to be detected accurately. A 100 mL volume is a good choice because it balances the need for sufficient dilution to reduce the uncertainty of the initial sample with the need for sufficient concentration to allow for accurate detection of the analyte.

The volume of the sample that should be diluted is 5 ml. The minimum level of uncertainty is obtained at a dilution of 100 ml. When the volume of the diluent is greater than 100 ml, the uncertainty of the measurement increases, and when the volume of the diluent is less than 100 ml, the uncertainty of the measurement also increases. Thus, a 100 ml volume of diluent is the ideal volume to minimize the uncertainty in the analysis of iron.

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Answer: Energy of a shear wave relates to the direction of a particle motion is downwards.

Explanation:

Answer:

Describe how the energy of a shear wave relates to the direction of particle motion.

Explanation:

Answer:

It is called "periodic" because elements are lined up in cycles or periods. From left to right elements are lined up in rows based on their atomic number (the number of protons in their nucleus). ... Each horizontal row in the table is a period. There are seven (or eight) total periods.

Explanation:

Measuring tool would you use to measure the area of a football field is used a tender wheel

If you need to measure much longer lengths for example the length of a football pitch then you could use a trundle wheel then you use it by pushing the wheel along the ground and it clicks every time it measures one meter and to measure the football field area then

Area = length×breadth

Area = 90m×45m

Area = 4.05m²

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0.0170 g of precipitate is formed from the reaction.

The balanced equation for the reaction between calcium chloride and ammonium sulfate is:

\(CaCl_{2}\)(aq) + \((NH_{4} )_{2} SO_{4}\)(aq) → \(CaSO_{4}\)(s) +2 \(NH_{4} Cl\)(aq).

The reaction is a double displacement reaction since the cations in both the reactants exchange places.

Moles of \(CaCl_{2}\) = (volume in litres x molarity) ,

Volume of \(CaCl_{2}\) used = 15 ml = 15/1000 L = 0.015 L.

Moles of \(CaCl_{2}\) = 0.015 x 0.01 = 0.00015 mol.

Moles of \((NH_{4} )_2 SO_{4}\)= (volume in litres x molarity)

Volume of \((NH_{4} )_2 SO_{4}\) used = 25 ml = 25/1000 L = 0.025 L

Moles of \((NH_{4} )_2 SO_{4}\) = 0.025 x 0.005 = 0.000125 mol

The limiting reagent Calcium chloride (\(CaCl_{2}\)) is present in excess while ammonium sulfate (\((NH_{4} )_2 SO_{4}\)) is the limiting reagent.

Since the balanced equation shows that one mole of \(CaSO_{4}\) is formed for every mole of ammonium sulfate used, the moles of precipitate formed is equal to the moles of ammonium sulfate used.

Moles of \(CaSO_{4}\) = 0.000125 mol

Mass of \(CaSO_{4}\)= Moles of \(CaSO_{4}\) x Molar mass of \(CaSO_{4}\)

Mass of \(CaSO_{4}\) = 0.000125 x 136.14 = 0.0170185 g (rounded to four significant figures).

Therefore, 0.0170 g of precipitate is formed when 15 ml of 0.01 m calcium chloride (110.98 g/mol) are reacted with 25 ml of 0.005 m ammonium sulfate (132.14 g/mol).

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Answer:

190

Explanation:

Gold has atomic number of 79, which is the number of protons.

Mass number = #protons + #neutrons = 79 + 111 = 190

The errors in the approximations to y(0.2), y(0.6), and y(1) are 0.573, 0.004, and 0.031, respectively.

Using Euler's method with time step h=0.2, we have:

k tk yk

0 0 3

1 0.2 y₁ = y₀ + h f(t₀, y₀) = 3 - 0.2(3e⁻³) = 2.416

2 0.4 y₂ = y₁ + h f(t₁, y₁) = 2.416 -   \(0.2[0.2e^{-2.416)}\)] = 2.073

3 0.6 y₃ = y₂ + h f(t₂, y₂) = 2.073 -  \(0.2[0.6e^{-2.073}\)] = 1.805

4 0.8 y₄ = y₃ + h f(t₃, y₃) = 1.805 - \(0.2[0.8e^{-1.805}\)] = 1.596

5 1.0 y₅ = y₄ + h f(t₄, y₄) = 1.596 - \(0.2[1e^{-1.596}\)]  = 1.433

Therefore, the approximations of y(0.2), y(0.4), y(0.6), y(0.8), and y(1.0) using Euler's method with time step h=0.2 are 2.416, 2.073, 1.805, 1.596, and 1.433, respectively.

The differential equation y˙=3te−y is separable, so we can write it as:

dy / dt = 3t\(e^{-y}\)

Separating variables as well as integrating both sides, we get:

∫ dy / \(e^{-y}\) = ∫ 3t dt

-ln|\(e^{-y}\)| = \(3t^{2/2+C}\)

\(e^{-y}\) = \(Ce^{-3t^{2/2} }\)    

y(t) =-ln\([Ce^{-3t^{2/2]} }\)]          

Using initial condition y(0) = 3,

3 = -ln(Ce⁰)

C = -e⁻³

Therefore, the exact solution to differential equation is:

y(t) = -ln[\(e^{3^{e-3t^{2/2} } }\)] = 3 - (3/2)t²

The errors in the approximations can be computed as follows:

|y(0.2) - y₁| = |2.989 - 2.416| = 0.573

|y(0.6) - y₃| = |1.809 - 1.805| = 0.004

|y(1) - y₅| = |1.464 - 1.433| = 0.031

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--The given question is incomplete, the complete question is

"Let y(t) be the solution to y˙=3te−y satisfying y(0)=3 . (a) Use Euler's Method with time step h=0.2 to approximate y(0.2),y(0.4),...,y(1.0) . k tk yk 0 0 3 1 0.2 equation editor Equation Editor 2 0.4 equation editor Equation Editor 3 0.6 equation editor Equation Editor 4 0.8 equation editor Equation Editor 5 1.0 equation editor Equation Editor (b) Use separation of variables to find y(t) exactly. y(t) = equation editor Equation Editor (c) Compute the error in the approximations to y(0.2),y(0.6) , and y(1). |y(0.2)−y1|="--

One method of obtaining these nutrients from the shrub is through the branches of the Dodder plant penetrating the tissues of the shrub. This is an illustration of a partnership in which only one creature benefits.

Tissue is a collection of cells with a common structure and function that work as a single unit. The brain give it shape and help it retain heat and energy. ibrocartilage, epithelial tissue, muscle tissue, and nervous tissue are the four different types of tissues.

Your organism is made up of cells, and tissues are created when groupings of cells carry out similar tasks. Your body consists mostly of four different tissue types: connective, epithelial, muscular, and nervous tissue. Organs are cushioned and joined together by connective tissue. The skin's outer layer is made up of epithelial tissue.

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Plants produce glucose and oxygen in an endothermic reaction called photosynthesis. The mass of glucose, C6H12O6, made when 1.0g of water reacts with carbon dioxide is 60gm.

Photosynthesis is a process used by plants and other organisms to change light energy into chemical energy that, through cellular respiration, can later be passed to fuel the organism's activities.

6H₂O + 6CO₂ CH12O6 + 602

We must convert the water to moles. We know that the molar mass of

Water 18

= 1 / 18

= 0.055

Now we look at our chemical equation's mole ratios. We can see that

6 moles of water produce 1 mole of glucose.

therefore, we will have 1/3 mol of glucose

The molar mass of glucose is 180

= 60gm of glucose will produce.

Thus, the mass of glucose, C6H12O6, made when 1.0g of water reacts with carbon dioxide is 60gm.

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Both Technician A and Technician B are correct in their statements about octane ratings and the use of regular and high octane gasoline.

Technician A is correct because most modern engines are designed to use regular grade gasoline, which has an octane rating of 87. This is the most commonly used gasoline and it is suitable for most engines.

Technician B is also correct because high octane gasoline, which has an octane rating of 91 or higher, should only be used when an engine was designed to use it. High octane gasoline is more expensive and is not necessary for most engines. However, some high-performance engines require high octane gasoline to prevent engine knocking and to achieve optimal performance.

Therefore, both Technician A and Technician B are correct in their statements about octane ratings and the use of regular and high octane gasoline.

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Answer:

Because after increasing of temperature kinetic energy of molecules increases and reaction speed increases in forward or reverse direction.

Explanation:

To make a more informed statement about how green your extraction of curcumin from turmeric was, you would need to consider the entire life cycle of the process. This includes the sourcing and cultivation of the turmeric, the extraction process itself, and any waste or byproducts generated.

Specifically, you would need to gather information about the environmental impact of the turmeric cultivation, including water usage, land use, and potential impacts on biodiversity. You would also need to evaluate the energy and solvent usage in the extraction process, as well as the potential for any waste or byproducts to harm the environment.

Comparing your extraction method to other methods, such as synthetic solvent extraction, would also be valuable in determining the greenness of your process. By taking a holistic approach and considering all aspects of the process, you can make a more informed statement about the sustainability and environmental impact of your curcumin extraction from turmeric.

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Answer:

see explanations

Explanation:

1. pH = -log [H+]

so [H+] = 10^(-pH) = 10^(-3.57) = 2.7 x 10^(-4) M

2. neutralize implies mol acid = mol base

so [HNO3] = (1 M) * (0.080 L) / (0.250 L) = 0.32 M HNO3

3. mol HNO3 = molarity of HNO3 * volume of HNO3

= 0.32 M HNO3 * 0.250 L HNO3 = 0.080 mol HNO3

Answer:

To find the number of grams of iron chloride produced when 4.3 moles of iron react with excess chlorine, you can use the following equation: 4.3 moles of iron x (2 moles of iron chloride/3 moles of chlorine) = 2.86 moles of iron chloride. Then, you can use the molar mass of iron chloride (162.195 g/mol) to calculate the number of grams of iron chloride produced: 2.86 moles of iron chloride x 162.195 g/mol = 464.14 g of iron chloride.

Explanation:

Answer:

Boiling

Explanation:

It's a phase transition from the liquid to gas once at or above the boiling temperature. Boiling is the rapid vaporization of a liquid once heated to its boiling point.

Answer:

the answer is aluminum

Answer:

hope it helps you a little

Displacement is defined as the distance, in any direction, of an object relative to the position of another object. Physicists use the concept of a position vector as a graphical tool to visualize displacements. A position vector expresses the positionof an object from the origin of a coordinate system

Answer:

Pick a reference point on the line to be the zero position. Determine the direction and measure the distance from zero in standard units.

Explanation:

The amount of water that should be added to 28 ml of 15​% alcohol solution to reduce the concentration to ​14% is: 2 ml

To solve this problem, the formula and the procedure that we have to use is:

c1 * v1 = c2 * v2

Where:

Information about the problem:

Applying the dissolution of concentrations formula and clearing the volume of the diluted solution (v2) we get:

c1 * v1 = c2 * v2

v2 = (c1 * v1)/ c2

v2 = (15% * 28 ml)/ 14%

v2= 30 ml

In order to know how much water should be added we have to subtract 28 ml from the volume of the diluted solution:

amount of water should be added = v2 - v1

amount of water should be added = 30 ml - 28 ml

amount of water should be added = 2 ml

In chemistry a solution is known as a homogeneous mixture of two or more components called:

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Edible mushrooms: Consuming edible mushrooms is safe and provides health advantages like fiber, vitamins, and minerals.

Non-Edible mushrooms: Mushrooms that cannot be eaten could be harmful or have unappealing flavors and textures that could be harmful if consumed.

The activation energy for a reaction can be calculated using the Arrhenius equation.

The given rate constant k1 = 6.20 × 10-4 min-1 and

half-life t1/2 = 29.0 min are both known at a temperature of

T1 = 760 K.

The activation energy (Ea) can be calculated as follows:Ea = (ln k2/k1) × (RT1T2/T1 - T2)

Where:k1 = 6.20 × 10-4 min-1

T1 = 760 Kt1/2

= 29.0 minR

= 8.314 J mol-1 K-1k2 is the rate constant at a higher temperature of T2 = 700 K and needs to be calculated using the half-life at this temperature.

The half-life at 700 K is given by the following equation:

t1/2 = (ln 2)/(k2)Rearranging the equation,

we get:k2 = (ln 2)/t1/2

Substituting the values:k2 = (ln 2)/29 minEa

= (ln [(ln 2)/29 min × 6.20 × 10-4 min-1])/((8.314 J mol-1 K-1) × (760 K - 700 K)/((760 K × 700 K))

= 114.69 kJ mol-1

Therefore, the activation energy for the isomerization of cyclopropane is 114.69 kJ mol-1.

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Answer: 11.25 moles of \(O_2\) will be required to completely react with 2.25 moles of \(C_3H_8\).

Explanation:

The balanced chemical equation is:

\(C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)\)  

According to stoichiometry :

1 mole of \(C_3H_8\) require = 5 moles of \(O_2\)

Thus 2.25 moles of \(C_3H_8\) will require=\(\frac{5}{1}\times 2.25=11.25moles\)  of \(O_2\)  

Thus 11.25 moles of \(O_2\) will be required to completely react with 2.25 moles of \(C_3H_8\).

The volume of H₂ gas required with an excess of nitrogen at STP to prepare 45.0 g of ammonia is 88.7 L.

45 gm ammonia is to be prepared.

The reaction to produce NH₃ is as below-

N₂ ₊ 3H₂ → 2NH₃

First let us calculate the number of moles

number of moles= mass/ molecular mass

number of moles= 45g/ 17 g/mol

number of moles= 2.6 mol

Since 2 moles of NH₃ is produced from 3 moles of H₂.

So, 1 mole of NH₃ will be produced from 1.5 moles of H₂

Hence, 2.6 moles of NH₃ will be produced from 1.5 x 2.6 moles of H₂

So NH₃ produced will be 3.9

Volume = number of moles x 22.4L

Volume= 3.9 x 22.4 L

Volume= 88.7 L

Hence, the volume of H₂ required is 88.7 L.

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To prevent the time temperature  when transporting the food, the practice should be followed is the correct option is D. Transport potentially  haza-r-dous ( TCS) hot food in an ins-ul-ated food container at the 135  or the higher.

The average body of the temperature is 98.6  that is 37 °C. The average body temperature, is will be as the high as 99  that is 37.2 °C or will be low as the 97  that is 36.1 °C. The temperature may be varies that is based on the time of the day .

Thus, Transport cold potentially haza-r-dous (TCS) that  is hot food in the ins-ul-ated food container at the 135  or the higher.

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