the ratio c:g is 2:3 and the ratio g:t is 5:4. workout the ratio c:g:t in its simplest form

The selection of a month and selecting a day of the month for vacation are independent events.

Probability of selecting specific month is unaffected by the probability of selecting a specific day of the month. The outcome of selecting a month does not influence the outcome of selecting a day.

The selection of a month and the selection of a day are separate and do not impact each other. The probability of selecting a particular month does not change based on the day chosen or vice versa.

Full question:

You select a month to go on vacation and then select the day of the month to begin the vacation. Classify as either Independent and Dependent Events.

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Answer: 126 milligrams

Step-by-step Easy to answer but all your doing is converting your mg's and 35% into decimals. and you will get your answer

As per the question, in context of mathematics the relation between 2 and 2 is equality relationship.

n mathematics, an equality relationship is a relationship between two quantities or expressions that are equal to each other. This relationship is represented using the equals sign (=).

Relations are important in mathematics because they allow us to describe and analyze the relationships between different quantities or values. Relations can be used to describe how two quantities are related to each other, such as whether they are equal, greater than, or less than each other.

The relationship between 2 and 2 is that they are both equal to each other. In mathematics, two is a number that is equal to the sum of one plus one. It is a cardinal number, which means it is used to count the number of objects in a set. Two is also an even number, which means it is divisible by 2 without a remainder.

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Answer:

-9?????????????????????????

Step-by-step explanation:

Answer:

71

Step-by-step explanation:

Answer: y = 5x + 26

Step-by-step explanation:

To find the equation of a line that is perpendicular to the given line y = -1/5x + 1 and passes through the point (-5, 1), we need to determine the slope of the perpendicular line. The given line has a slope of -1/5. Perpendicular lines have slopes that are negative reciprocals of each other. So, the slope of the perpendicular line will be the negative reciprocal of -1/5, which is 5/1 or simply 5. Now, we have the slope (m = 5) and a point (-5, 1) that the perpendicular line passes through.

We can use the point-slope form of a linear equation to find the equation of the line:

y - y1 = m(x - x1)

Substituting the values, we get:

y - 1 = 5(x - (-5))

Simplifying further:

y - 1 = 5(x + 5)

Expanding the brackets:

y - 1 = 5x + 25

Rearranging the equation to the slope-intercept form (y = mx + b):

y = 5x + 26

Therefore, the equation of the perpendicular line that passes through the point (-5, 1) is y = 5x + 26.

Answer: $6085.15

Step-by-step explanation:

Substituting into the exponential decay formula yields \(9250(1-0.051)^8 \approx \$6085.15\).

interest is approximately $29,138.27. To calculate the amount accumulated in thirty years with monthly savings and quarterly compounding interest, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:

A is the final amount accumulated

P is the monthly savings ($35)

r is the annual interest rate (5% or 0.05)

n is the number of compounding periods per year (quarterly, so 4)

t is the number of years (30)

Substituting the values into the formula:

A = 35(1 + 0.05/4)^(4*30)

A = 35(1 + 0.0125)^(120)

A = 35(1.0125)^(120)

A ≈ $29,138.27

Therefore, the amount you will accumulate in thirty years with monthly savings and quarterly compounding interest is approximately $29,138.27. Thus, the correct option is $29,138.27.

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Answer:  65536a^4 b^2

Step-by-step explanation:

\(\Large\boxed{\tt Answer:~x=\frac{5}{7} }\)

\(\tt Step-by-step~explanation:\)

Remember: PEMDAS - Parentheses, exponents, multiply/divide, add/subtract

Distribute: 9(1+x) = 9+9x

19 - 5x = 9 + 9x

Add 5x to both sides of the equation and subtract 9 from both sides.

19 - 5x + (5x) = 9 + 9x + (5x)

19 - (9) = 9 - (9) + 14x

10 = 14x

Divide both sides by 14 to get the variable on its own.

10/14 = 14x/14

10/14=x

5/7 = x

Answer:

The answer is (-4x² + x + 2)

Step-by-step explanation:

(2x² - 4x + 3) + (5x - 6x² - 1)

open the brackets

2x² - 4x + 3 + 5x - 6x² - 1

rearrange the priority order

2x² - 6x² - 4x + 5x + 3 - 1

combine like terms

-4x² + x + 2

Thus, The answer is (-4x² + x + 2)

Answer:

D is correct option.

Step-by-step explanation:

g(x) =-3 root x-1.

Answer:

65⁰ because the opposite angles of parallelogram are equal...

H0: p=0.24 is the null hypothesis, whereas H1: p>0.24 is the alternative hypothesis.

To find out whether two proportions are different, compare them. The proportion of graduates with jobs is 281 ÷ 1120, or 0.25. It was 0.24 last year.

The null hypothesis states that 0.25 equals 0.24.

The alternate hypothesis states that 0.25 is not the same as 0.24.

The Chi-square test might potentially be employed in this situation. It would be possible to acquire a Pearson chi² value with one freedom degree and a probability. If the probability is smaller than the cutoff, such as less than 0.05, the null hypothesis is rejected.

However, the criteria are not just a percentage of the previous year's statistics. If the prior year's figures are insufficient, the chi-square analysis is inapplicable.

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The question is -

In a survey of 1120 new college graduates, 281 had a professional job on graduation day. One year ago the proportion of graduates with a professional job on graduation day was 24%. The setup of the null and alternative hypotheses to test whether there is sufficient evidence to conclude that the proportion of graduates with a professional job is higher now than it was one year ago is:

a) H0: p=.24  vs.  H1: p<.24

b) H0: p=.24   vs.  H1: p≠.24

c) H0: p=.24   vs.  H1: p>.24

d) H0: p=.25    vs.  H1: p<.25

e) H0: p=.25    vs.  H1: p>.24

Answer:

the perimeter of the rectangle is 70 cm

Step-by-step explanation:

The computation of the perimeter of the rectangle is given below:

first we determine the side of each tile i.e.  

l² = A

l² = 49cm²

l = √49cm²

l = 7cm

now we calculate the perimeter i.e.  

P = 2 (3 (7cm) + 2 (7cm))

= 2 (21cm + 14cm)

= 2 (35cm)

= 70cm

Hence, the perimeter of the rectangle is 70 cm

Therefore , the solution of the given problem of unitary method comes out to be a 2-liter soda costs $4.98 and a platter of nachos costs $11.99.

The measurements taken from this femtosecond section must be multiplied by two in order to complete the task using the unitary variable technique. In essence, the characterised by a group and the hue groups are both removed from the unit approach when a desired object is present. For example, 40 pens with a expression price will indeed cost Inr ($1.01). It's possible that one country will have total influence over the approach taken to accomplish this. Almost every living creature has a distinctive quality.

Here,

Let's use "N" for the price of a platter of nachos and "S" for the price of a 2-liter soda.

The first aspect of the issue reveals that:

=> 5N + 2S = 67.87

The second component of the issue reveals the following to us:

=>2N + S = 27.94

=> S = 27.94 - 2N

When we use this expression in place of S in the first equation, we obtain:

=> 5N + 2(27.94 - 2N) = 67.87

When we simplify and account for N, we obtain:

=> 5N + 55.88 - 4N = 67.87\sN = 11.99

We can determine S by substituting this number for N in the second equation:

=> 2(11.99) + S = 27.94\sS = 4.98

As a result, a 2-liter soda costs $4.98 and a platter of nachos costs $11.99.

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False. The statement is not entirely accurate. While significantly different sample variances can impact the assumptions of a t-test, it does not necessarily mean that a t-test cannot be conducted.

In traditional t-tests, there is an assumption of equal variances between the compared groups or populations. This assumption is known as the assumption of homogeneity of variances. If the sample variances are significantly different, it violates this assumption.

However, there are alternative versions of the t-test that can be used when the variances are not equal, such as the Welch's t-test or the modified t-test. These tests do not assume equal variances and can be applied when the variances are significantly different.

Therefore, it is possible to conduct a t-test even when the sample variances are significantly different, using appropriate modifications to the test. However, it is essential to consider the validity and appropriateness of the chosen test based on the specific circumstances and assumptions of the data.

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Answer:

Your answer, many solutions is correct!

Step-by-step explanation:

The answer one solution is incorrect because there is more than one solution to this equation.

The answer no solution is incorrect because there is a solution to this equation so clearly, this one is incorrect.

The answer many solutions is correct because there are two solutions to this equation, \(y=-3,\:x=\frac{9}{2}\).

hope this helps!!!

(Try using Symbolab, I use it all the time it gives the correct answer and it gives good explanations.)

Answer:

yeah correct

Step-by-step explanation:

The probability that the average bacteria count for one day is between 2350 and 2650 bacteria per milliliter is 0.3485.

Given that the bacteria count in milk follows a normal distribution with a mean of 2500 bacteria per milliliter and a standard deviation of 200 bacteria per milliliter.

The question requires finding the probability that the average bacteria count for one day is between 2350 and 2650 bacteria per milliliter.

Therefore, we can use the standard normal distribution to find the probability. To convert the normal distribution to the standard normal distribution, we use the formula:z = (x - µ) / σz = (2350 - 2500) / 200z = -0.75z = (2650 - 2500) / 200z = 0.75

Therefore, the probability of the average bacteria count for one day being between 2350 and 2650 bacteria per milliliter is:

P(-0.75 < z < 0.75)

The area under the standard normal distribution curve between -0.75 and 0.75 is equal to 0.3485.

Thus, the probability that the average bacteria count for one day is between 2350 and 2650 bacteria per milliliter is 0.3485.

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The position value, r(t) is equals to the (t³/6)k + 2j and velocity value, v(t) is equals to ( t²/2 )k + 4i , for a(t) = tk, v(0) = 4i, r(0) = 2j.

Acceleration is defined as the rate of change of the velocity of an object with respect to time. Accelerations are vector quanty.

a = dv/dt

We have the following informations are available,

Initial velocity, v(0) = 4i

Initial position, r(0) = 2j

Acceleration at any time "t",

a(t) = tk

we have to determine the value of v(t) and r(t).

As we know, a(t) = dv(t)/dt = tk

integrating the above equation ,

v(t) = ∫tk dt = ( t²/2 )k + c

at t = 0 , v(0) = 0 + c = 4i ( since, v(0) = 4i

=> c = 4i

So, v(t) = ( t²/2 )k + 4i

Also, velocity is calculated by derivative of postion (r) with respect to time.

=> v(t) = dr(t) /dt

=> r(t) = ∫ v(t) dt

=> r(t) = ∫ ( t²/2 )k dt

integrating value of the right hand side,

r(t) = ( t³/2×3 )k +d

= (t³/6)k + d

At t = 0, r(0) = (0/6)k + d

=> r(0) = d = 2j

so, r(t) = (t³/6)k + 2j

Hence, the required position and velocity are

(t³/6)k + 2j and ( t²/2 )k + 4i.

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The slope of the line that passes through the coordinates is -6/5.

The slope of the line is given by;

m = (y₂ - y₁)/(x₂ - x₁)

Where, the coordinates are given.

(x₁ ,y₁) = (2, 8)

(x₂, y₂) = (-3, 14)

Put the value in the slope;

m = (14 - 8)/(-3 - 2)

m = 6/-5

m = -6/5

Therefore, the slope of line passing from the points is -6/5

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The dimensions 36 x 27 inches are too small to allow a 48-inch piece of glass to fit through it.

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Answer:

a line segment

Step-by-step explanation:

because a line segment is made my points at end of the line so a----b make a line segment

The population mean is 8. Now, putting the values in the formula = (9+10+13+1+4+5)/(6-1) = 42/5. Therefore, the population variance is 4.9167.

Given,Population consists of the four members 5, 8, 9, 10.Total number of possible samples of size two which can be drawn without replacement from this population = 6.The possible samples are {5,8}, {5,9}, {5,10}, {8,9}, {8,10}, {9,10}.The sum of the values in each of the sample is as follows:{5,8} → 13{5,9} → 14{5,10} → 15{8,9} → 17{8,10} → 18{9,10} → 19Now, calculating the mean of all the possible samples of size two we get:Mean = (13+14+15+17+18+19)/6=96/6=16Therefore, the population mean is 16/2 = 8.2.

To find the population mean of a population, we use the formula;μ = ΣX/N Where,X is the value of each observation N is the total number of observations μ is the population mean .Given,Population consists of the four members 5, 8, 9, 10.Total number of observations = 4The sum of all observations = ΣX = 5+8+9+10 = 32Now, putting the values in the formula we get;μ = 32/4 = 8Therefore, the population mean is 8.To find the population variance of samples of size two, we use the  Where,N is the total number of possible samplesσ² is the population varianceS² is the sample variance of all possible samples of size two To calculate the sample variance of all possible samples of size two, we use the formula Where,X is the value of each sample  is the mean of the populationn is the size of the sampleGiven,Population consists of the four members 5, 8, 9, 10.Total number of possible samples of size two which can be drawn without replacement from this population = 6.The possible samples are {5,8}, {5,9}, {5,10}, {8,9}, {8,10}, {9,10}.First, we calculate the sample mean of all possible samples of size two using the formula Where,X is the value of each samplen is the size of the sample.

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Answer:6.66

Step-by-step explanation:

Answer:

144

Step-by-step explanation:

bc 6 tennis courts x 24 equals 144 sorry if it's wrong

Answer:

1.  3 and -5

2.  7

Step-by-step explanation:

The zeros of functions are the x-values when y = 0, i.e the point(s) at which the line crosses the x-axis.

To find the zeros of the given functions, set the function to zero and solve for x.

Given function:

\(y=5(x-3)(x+5)\)

Set the function to zero:

\(\implies 5(x-3)(x+5)=0\)

\(\implies \dfrac{5(x-3)(x+5)}{5}=\dfrac{0}{5}\\\)

\(\implies (x-3)(x+5)=0\)

Using the Zero Product Property, set each factor equal to zero and solve for x:

\(\implies (x-3)=0 \implies x=3\)

\(\implies (x+5)=0 \implies x=-5\)

Therefore, the zeros of the function are 3 and -5.

Given function:

\(y=(x-7)^2\)

Set the function to zero and solve for x

\(\implies (x-7)^2=0\)

\(\implies \sqrt{(x-7)^2}=\sqrt{0}\)

\(\implies x-7=0\)

\(\implies x=7\)

Therefore, the zero of the function is 7 (with multiplicity 2).

The average hourly wage each year is $0.77 per year

From the question, we have the following parameters that can be used in our computation:

Years (since 2015) 0 1 2 3 4 5 6 7

Hourly Wage (in dollars) 8.50 9 10 10.50 11 12 13 14

Next, we enter the table of values in a graphing calculator

From the graphing calculator, we have the following summary:

The average (b) is calculated as

b = SP/SSX

So, we have

b = 32.5/42

Evaluate

b = 0.77381

Approximate

b = 0.77

Hence, the average is 0.77

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