The reaction of 15 moles carbon with 30 moles O2 will
result in a theoretical yield of moles CO2.

Answer:

1.674 x 10^-23 grams

Explanation:

Hydrogen-1 is called Protium

wikipedia

atomic mass of Protium is 1.00794 amu

sciencedirectcom

atomic mass of 10 Protiums is 10.0794 amu

10.0794 amu in grams is

1.6737236x10^-23 grams

The frequency of gamma radiation is calculated to be = 1.11 *10^20 Hz.

A gamma radiation is also known as gamma ray. It is a penetrating form of electromagnetic radiation arising from radioactive decay of atomic nuclei. It consists of shortest wavelength electromagnetic waves, even shorter than X-rays.

Gamma rays can pass through the human body completely and as they pass through, they cause ionizations that damage tissue and DNA.

As we know that E= hf

Hence, f= E/h

Given E=  6.96 x 10-14 J

And, Planck's constant, h = 6.626 *10^-34 m² kg/s

f = 6.96 * 10^-14J  +/6.626 *10^-34

f = 1.11 *10^20 Hz

Hence, frequency of gamma radiation = 1.11 *10^20 Hz.

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The true statements are;

The reaction is endothermic

Heat is a reactant

ΔHrxn is 89 kJ/mol

Enthalpy is a thermodynamic property that represents the total energy of a system, including both its internal energy (the energy of its constituent particles) and the energy it has due to its temperature and pressure. It is commonly used in energy analysis and heat transfer calculations and is expressed in units of joules (J) or calories (cal).

We know that the enthalpy of the reaction can obtained from;

Enthalpy of the products - Enthalpy of the reactants

ΔH reaction = 2(-391.4) - 2(-435.9)

(-782.8) - (-871.8)

= 89 kJ/mol

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The mass (in grams) of sodium carbonate, Na₂CO₃ required to produce 85 grams of barium carbonate, BaCO₃ is 45.7 grams

First, we shall observe the balanced equation to obtain useful information. This is shown below:

Na₂CO₃ + BaSO₄ -> BaCO₃ + Na₂SO₄

From the balanced equation above,

197 g of BaCO₃ were obtained from 106 g of Na₂CO₃

With the above information, we can obtain the mass of sodium carbonate, Na₂CO₃ required to produce 85 grams of barium carbonate, BaCO₃. This is illustrated below:

From the balanced equation above,

197 g of BaCO₃ were obtained from 106 g of Na₂CO₃

Therefore,

85 g of BaCO₃ will be obtain from = (85 × 106) / 197 = 45.7 g of Na₂CO₃

Thus, we can conclude from the above calculation that the mass of sodium carbonate, Na₂CO₃ required is 45.7 grams

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Approximately 70.57 mL of 1.00 M NaOH should be added to 250 mL of 0.50 M CH3CO₂H to produce a buffer with a pH of 4.50.

To determine the volume of 1.00 M NaOH required to produce a buffer with a pH of 4.50 when added to 250 mL of 0.50 M CH3CO₂H, we need to consider the Henderson-Hasselbalch equation and the stoichiometry of the reaction.

The Henderson-Hasselbalch equation for a buffer solution is given as:

pH = pKa + log([A-]/[HA])

In this case, CH3CO₂H (acetic acid) acts as the weak acid (HA) and CH3COO- (acetate ion) acts as its conjugate base (A-). We are given that the desired pH is 4.50, and we can determine the pKa value for acetic acid from reference sources, which is approximately 4.75.

Using the Henderson-Hasselbalch equation, we can rearrange it to solve for the ratio [A-]/[HA]:

[A-]/[HA] = 10^(pH - pKa)

[A-]/[HA] = 10^(4.50 - 4.75) = 10^(-0.25) = 0.5623

This means that the ratio of the acetate ion to acetic acid in the buffer solution should be approximately 0.5623.

To calculate the required volume of NaOH, we need to consider the stoichiometry of the reaction. Acetic acid reacts with hydroxide ions (OH-) to form acetate ions and water:

CH3CO₂H + OH- → CH3COO- + H2O

The stoichiometric ratio between acetic acid and hydroxide ions is 1:1. Therefore, the volume of 1.00 M NaOH needed can be calculated using the equation:

Volume (NaOH) × 1.00 M = Volume (CH3CO₂H) × 0.50 M × 0.5623

Volume (NaOH) = (Volume (CH3CO₂H) × 0.50 M × 0.5623) / 1.00 M

Volume (NaOH) = (250 mL × 0.50 M × 0.5623) / 1.00 M

Volume (NaOH) ≈ 70.57 mL

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The enthalpy change of the reaction C(diamond) → C(graphite) is -2.9 kJ.

The given information is ΔHrxn for the reaction C(diamond) → C(graphite) can be calculated with the given equations:Equations:  C(diamond) + O2(g) → CO2(g) ΔH = −395.4 kJ  2 CO2(g) → 2 CO(g) + O2(g) ΔH = 566.0 kJ  C(graphite) + O2(g) → CO2(g) ΔH = −393.5 kJ  2 CO(g) → C(graphite) + CO2(g) ΔH = −172.5 kJThe required reaction can be obtained by adding the equations (1) and (4), as follows:C(diamond) + O2(g) + 2CO(g) → C(graphite) + 3CO2(g)Addition of the two equations (1) and (4) results in a reaction whose products are C(graphite) and CO2.

To get the final equation that involves only the required reactants and products, the equation (2) should be added, which consumes CO2 and produces O2, as shown below:C(diamond) + O2(g) → CO2(g)  ΔH = −395.4 kJ [eq. (1)]  2 CO(g) → C(graphite) + CO2(g)  ΔH = −172.5 kJ [eq. (4)]  2 CO2(g) → 2 CO(g) + O2(g)  ΔH = 566.0 kJ [eq. (2)]  C(diamond) + O2(g) + 2CO(g) → C(graphite) + 3CO2(g)  ΔHrxn=ΣΔHf(products)−ΣΔHf(reactants)  ΔHrxn=[(3 mol CO2)(-393.5 kJ/mol) + (1 mol C(graphite))(0 kJ/mol)] − [(1 mol C(diamond))(0 kJ/mol) + (1 mol O2)(0 kJ/mol) + (2 mol CO(g))(−172.5 kJ/mol)] − [(2 mol CO2)(566.0 kJ/mol)]  ΔHrxn=−2.9 kJ.

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Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat, and ΔT is the change in temperature (T₂-T₁). The specific heat of water is 4.184 J/g °C. We are given the mass of water (m = 18.3 g), the final temperature (T₂ = 49.32 °C), and the initial temperature (T₁ = 11.88 °C). The change in temperature, ΔT, equals 49.32 °C - 11.88 °C = 37.44 °C. With all these values at hand, we can solve for the amount of energy needed, Q:

Q = (18.3 g)(4.184 J/g °C)(37.44 °C) = 2866.7 J ≈ 2870 J (three sig figs).

15 moles of NaCl would have been used up in the reaction as a result.

The number of moles is obtained by taking each mass and dividing it by the molar mass. The molar mass of Ca₃(PO₄)₂ is 310.18 grammes/mole. The result is 0.016 moles of Ca₃(PO₄)₂ when five is divided by 310.18.

The balanced chemical equation for the reaction of sodium chloride (NaCl) and calcium phosphate (Ca₃(PO₄)₂) is:

3Ca₃(PO₄)₂ + 6NaCl → 6NaPO₄ + CaCl₂ + 2Ca₃(PO₄)₂

calculate the amount of NaCl consumed using the following proportion:

2 mol Ca₃(PO₄)₂ / 6 mol Sodium Chloride = 5 mol Ca₃(PO₄)₂ / x

Solving for x, we get:

x = (6 mol NaCl × 5 mol Ca₃(PO₄)₂) / 2 mol Ca₃(PO₄)₂

x = 15 mol NaCl

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Answer:  A

Explanation:

Answer:

1.44 g

Explanation:

1. get number of nitrogen atoms in 9.79 grams of nitrogen

1 mole of Nitrogen is 6.022 x 10^23 atoms N which is = 14.01g N

2.

if 6.022 x 10^23 atoms of Nitrogen is 14

then x atoms  of Nitrogen is 9.79

3.

6.022 x 10^23/ x = 14/9.79 ->

x = 8.431 x 10^24 / 9.79 =

8.61799714478 x 10^23

4.

8.61799714478 x 10^23 atoms of N

6.022 x 1023 atoms of H have a mass of 1.008g, so

8.61799714478 x 10^23 atoms of H have a mass of (1.008/6.022 x 1023) x 8.61799714478 x 10^23) = 1.44250051072175g

1.44 g

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Answer: Refract

Explanation:

The student paid an interest of $3,000 over the next five years.

HOW TO CALCULATE INTEREST:

The interest on a borrowed amount of money can be calculated by subtracting the principal from the amount paid over time. That is;

Interest = principal - amount

According to this question, a student borrows $10,000 from a bank but ends up paying $13,000. This means that the principal is $10,000 while the amount is $13,000. The interest is calculated thus;

Interest = $13,000 - $10,000

Interest = $3,000

Therefore, the student paid an interest of $3,000 over the next five years.

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Mixing calcium carbonate and HCl

Heating copper sulfate pentahydrate

Mixing potassium iodide and lead nitrate

Combining magnesium and HCl

Burning the candle.

The crushing of limestone is a bodily trade it no longer alters the chemical composition of the limestone. The heating of limestone is a chemical trade the limestone decomposes into two other materials, lime and carbon dioxide. both ended in gas formation. both ended in shade change.

Rust is not anything however Iron Oxide is a brand new substance shaped out of the response. The color of the floor of the iron additionally modifications. hence, rusting of iron is a chemical trade. Rusting is an instance of chemical exchange. A chemical property describes the ability of a substance to go through a particular chemical alternate. The chemical belonging of iron is that it is miles capable of combining with oxygen to form iron oxide, the chemical call of rust. like several steel carbonates, calcium carbonate reacts with acidic solutions to supply carbon dioxide gas.

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Sodium chloride is more likely to dissolve in water because it is polar and is attracted to the polar molecules of water. On the other hand, butane is nonpolar and is not attracted to the polar molecules of water, so it is less likely to dissolve.

Sodium chloride, also known as table salt, has ionic bonds, meaning it is composed of positive and negative ions. The positive sodium ion and negative chloride ion are attracted to the polar water molecules, which have a positive charge at one end and a negative charge at the other. This attraction between the ions of salt and the polar water molecules leads to the dissolution of salt in water.

Butane, on the other hand, is a nonpolar substance. It is composed of nonpolar carbon and hydrogen atoms arranged in a linear structure. These nonpolar atoms are not attracted to the polar water molecules, so they do not dissolve well in water. In fact, butane is a hydrocarbon and is one of the components of natural gas. It is a fuel that is used for heating and cooking, and it is not soluble in water.

In conclusion, the solubility of a substance in water depends on its molecular structure and the type of bonds it contains. Polar substances tend to dissolve well in water because they are attracted to the polar water molecules, while nonpolar substances are less likely to dissolve because they are not attracted to the polar water molecules.

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Answer:

\(189kJ\)

Explanation:

Hello!

In this case, since one mole of ethanol release 8,842 J per 1 mole of ethanol, we can write:

\(\frac{8,842J}{1molC_2H_6H}\)

Thus, since we need the energy released by 982.6 g of ethanol, we compute the moles in such mass of fuel:

\(n=982.6g\frac{1mol}{46.08g} =21.3mol\)

Therefore, the result is:

\(\frac{8,842J}{1mol}*21.3mol=188,545J\)

Which in kJ is:

\(189kJ\)

Best regards!

Yes, hydrogen found in a natural abundance, hydrogen is easily the most abundant element in the universe.

Hydrogen the most abundant in nature because hydrogen is the simplest element in the universe, with only one proton and one electron ,it is the only element without a neutron.

The element hydrogen is by far the most abundant in the universe. It can be found in the sun and most stars, and the planet Jupiter is mostly made up of hydrogen. Water is the most abundant form of hydrogen on Earth.

Thus, hydrogen found in a natural abundance.

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Answer:

Filter it

Explanation:

Answer:

oficialismo hemostasia Jalisco

Answer:

K

Explanation:

Potassium is atomic no 19 and it is k because is from kalium, the Meldiaeval Latin for potash, which may have derived from an arabic word quality, meaning alkali.

Atomic mass, 39.098amu

Oxidation status, +1

Year discovered, 1807

Melting point, 63.28 degrees Celsius(145.90degrees Fahrenheit )

Boiling point, 760 degrees Celsius (1400 degrees Fahrenheit )

Based on the given reaction, the acid-base pairs in this reaction are:

An acid-base pair refers to a set of two chemical species that are related through the transfer of a proton (H+ ion) during a chemical reaction.

One species acts as an acid by donating a proton, while the other acts as a base by accepting that proton.

In the given reaction:

HCO₃⁻ (aq) + NH₃ (aq) → NH₄⁺ + CO₃²⁻

An acid-base pair can be identified as follows:

HCO₃⁻ (bicarbonate ion) can act as an acid by donating a proton (H⁺), becoming CO₃⁻.

NH₃ (ammonia) can act as a base by accepting a proton (H⁺), becoming NH₄⁺ (ammonium ion).

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The calculated formula masses to 133.5 amu, we find that the substance with a formula mass closest to 133.5 amu is (d) AlCl3. Therefore, the answer is option D.

To identify the substance with a formula mass of 133.5 amu, we need to calculate the formula mass of each given substance and compare it to 133.5 amu.

(a) MgCl2:

The formula mass of MgCl2 can be calculated by adding the atomic masses of magnesium (Mg) and chlorine (Cl).

Mg: atomic mass = 24.31 amu

Cl: atomic mass = 35.45 amu

Formula mass of MgCl2 = (24.31 amu) + 2(35.45 amu) = 95.21 amu

(b) SCl:

The formula mass of SCl can be calculated by adding the atomic masses of sulfur (S) and chlorine (Cl).

S: atomic mass = 32.07 amu

Cl: atomic mass = 35.45 amu

Formula mass of SCl = 32.07 amu + 35.45 amu = 67.52 amu

(c) BCl:

The formula mass of BCl can be calculated by adding the atomic mass of boron (B) and chlorine (Cl).

B: atomic mass = 10.81 amu

Cl: atomic mass = 35.45 amu

Formula mass of BCl = 10.81 amu + 35.45 amu = 46.26 amu

(d) AlCl3:

The formula mass of AlCl3 can be calculated by adding the atomic mass of aluminum (Al) and 3 times the atomic mass of chlorine (Cl).

Al: atomic mass = 26.98 amu

Cl: atomic mass = 35.45 amu

Formula mass of AlCl3 = 26.98 amu + 3(35.45 amu) = 133.78 amu. Option D

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Answer:

A. simple

Explanation:

Answer:

complexation

Explanation:

KSCN + FeCl 3 → K + + [FeSCN] 2+ + 3 Cl. This is a complexation reaction: [FeSCN] 2+ is the formed complex.

Answer:

I think It's the 2nd "There are two compounds present"

Answer: 0.27 moles of CO2 and 11.88 grams of CO2

Explanation: Use the Ideal Gas Law, PV = nRT, substitute the values given and solve.

I can't seem to upload procedure but:

P = 1.5atm

V = 4.5L

n = moles

R = 0.0821gr/mol (when using atm, kPa is 8.31)

T = 300K

Isolate what you don't have, in this case n. Change PV = nRT to PV/RT = n. Substitute the values to get moles. Once you have this, multiply the value by the molar mass of CO2 (44gr/mol) to get the mass of CO2 in grams.

Explanation:

1.17×10^24 molecules of co2

The necessary volume of H₂ gas to obtain 5.0 g of propane (C₃H₈) is approximately 12.60 liters.

To determine the necessary volume of H₂ gas to obtain 5.0 g of propane (C₃H₈), we need to use the molar ratio between H₂ and C₃H₈, as well as the density of H₂ gas.

First, let's calculate the molar mass of propane (C₃H₈):

C: 12.01 g/mol

H: 1.01 g/mol

Molar mass of C₃H₈ = (3 * C) + (8 * H) = (3 * 12.01) + (8 * 1.01) = 44.11 g/mol

Next, we can determine the number of moles of propane (C₃H₈) using its mass:

Number of moles = Mass / Molar mass

Number of moles of C₃H₈ = 5.0 g / 44.11 g/mol ≈ 0.1134 mol

Now, we can establish the molar ratio between H₂ and C₃H₈ from the balanced chemical equation:

C₃H₈ + 5H₂ → 3CH₄

According to the balanced equation, 5 moles of H₂ are required to produce 1 mole of C₃H₈.

Therefore, the number of moles of H₂ required can be calculated as:

Number of moles of H₂ = 5 * Number of moles of C₃H₈ = 5 * 0.1134 mol = 0.567 mol

Finally, we can determine the necessary volume of H₂ gas using the ideal gas law equation:

Volume = (Number of moles * Gas constant * Temperature) / Pressure

Given that the density of H₂ is 0.09 g/L, we can convert it to moles per liter:

Density = Mass / Volume

0.09 g/L = 2 g/mol / Volume (since the molar mass of H₂ is 2 g/mol)

Solving for Volume:

Volume = 2 g/mol / 0.09 g/L ≈ 22.22 L/mol

Now, we can calculate the necessary volume of H₂ gas:

Volume of H₂ = Number of moles of H₂ * Volume per mole

Volume of H₂ = 0.567 mol * 22.22 L/mol ≈ 12.60 L

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Meiosis cause siblings to have similar physical characteristics, while not being identical to each other because meiosis creates new combinations of genetics material in each of the four daughter cell

During meiosis homologous chromosomes pair along their length and the chromosomes cross over at point called chiasma at each chiasma the chromosomes break and rejoin and trading some of their genes and this recombination result in genetics variation

meiosis creates new combination of genetic material in each of the four doughtier cell and this new combination result from the exchange of DNA between paired chromosome and such exchange means that the gametes produced through meiosis exhibit an amazing range of genetic variation

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To calculate the moles of H+ and OH-, you need to know the concentration of the solution in terms of its pH or pOH value.

When you get the pH of the solution, you can use this formula to calculate the concentration of H+ ions: [H+] = 10^(-pH)

Also, if you know the pOH of the solution, you can use this formula to calculate the concentration of OH- ions: [OH-] = 10^(-pOH)

Having determined the concentration of H+ and OH- ions, the molarity formula can be used to calculate the number of moles of each ion as follows: moles = concentration (in mol/L) x volume (in L)

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