The reduction of 3-pentanone with hydrogen in the presence of a nickel catalyst will yield.

Answer:

It has 53

Explanation:

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Answer: 72

Explanation:

There are 72 neutrons that iodine have.

Answer:

Second-degree burns, or partial thickness burns, are more severe than first-degree burns. They affect the outer layer of skin, called the epidermis, and part of the second layer of skin, called the dermis. Second-degree burns can be very painful and often take several weeks to heal.

Explanation:

In the synthesis of Friedel-Crafts products, hydrochloric acid is used as a catalyst to generate the reactive electrophilic species, which attacks the aromatic ring and leads to the formation of the desired product.

The HCl reacts with the Lewis acid catalyst (such as AlCl3) to generate a complex that can activate the electrophile and facilitate the reaction. Additionally, HCl is used to quench the reaction at the end by protonating the intermediates and generating the final product. Overall, the function of hydrochloric acid in Friedel-Crafts reactions is to enhance the reactivity of the system and promote the formation of the desired product.

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Answer:

definite volume

Explanation:

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Answer:

Mountains

Explanation:

Mountains are colder than the lower elevations.  When humid air enters a cooler region, the saturated air begins to cool  and this reduces the ability of the air to maintain the evaporated water is the gas state.  Molecules of water have reduced enerfy at the cooler temperatures.  They will slow down and coalesce with other water molecules to form small droplets of water.  The atmoshere cannot hold these heaevier droplets and they begin to fall  (i.e., rain).

One migh ask why does the air temperature drop at higher altitudes?  Heat rises, so why shouldn't it be warmer on top a mountain, compared to the valley.  The reason is that the atmosphere becomes less dense the further from Earth's center on gets.  This less dense air has a lower water saturation point, so it rains.

The main answer to the question is: The test statistic is 51.20 and the critical values are 9.591 and 34.170.

To explain the main answer, we are conducting a hypothesis test to determine if the population standard deviation of the pH of rain is indeed 0.5, as suggested by the theory. The null hypothesis (H0) is that the population standard deviation is 0.5, while the alternative hypothesis (H1) is that the population standard deviation is not 0.5.

In this case, we are given a random sample of 21 rainy days, and the sample standard deviation is 0.8. To test the hypothesis, we need to calculate the test statistic, which is given by the formula: test statistic = [(sample standard deviation) - (hypothesized standard deviation)] / (sample standard deviation / sqrt(sample size)).

Plugging in the values, we get: test statistic = [(0.8 - 0.5) / (0.8 / sqrt(21))] = 51.20.

To determine the critical values, we need to look at the critical region associated with the given significance level (alpha) of 0.05. Since this is a two-tailed test, we divide the significance level by 2, resulting in an alpha of 0.025 for each tail. Using the degrees of freedom (n-1), which is 20 in this case, we can consult the t-distribution table or use a statistical software to find the critical t-values. For an alpha of 0.025 and 20 degrees of freedom, the critical t-values are approximately ±2.093.

Converting the t-values to critical values using the formula: critical value = (hypothesized standard deviation) + (t-value * (sample standard deviation / sqrt(sample size))), we get: critical values = 0.5 + (2.093 * (0.8 / sqrt(21))) = 9.591 and 0.5 - (2.093 * (0.8 / sqrt(21))) = 34.170.

Therefore, the correct answer is: The test statistic is 51.20 and the critical values are 9.591 and 34.170.

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1. mercury - metal, liquid at temperature

2. oxygen - does not have a definite volume

3.Bromine - non-metal, liquid at room temperature

4.mercuric oxide - compound

5. silver -malleable and ductile

6. chemical change - decomposition of compound

The only common metal that is liquid at room temperature is mercury, a chemical element. It is a thick, silvery-white liquid metal that is frequently referred to as quicksilver. Mercury is a metal in transition.

Since mercury is a chemical element, it cannot be made or destroyed. Since the creation of the earth, the same quantity has been present on the planet. However, both natural and human activity can cycle mercury in the environment. Additionally, there have been numerous new uses for mercury metal in electrochemistry and electrical equipment. Mercury metal has a significant vapour pressure at normal temperature and is a volatile liquid.

At 20°C, mercury has a density of 13.6 g.cm-3.

Mercury is a metallic element that is liquid and has a wide range of uses. Additionally, it has dangerous qualities.

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Answer:

Showers

Drinking Water

Waching your hands

Explanation:

Answer:

Drinking Water

Showering

Washing dishes

Washing your hands

Watering the plants

Cooking (to boil pasta and/or noodles and things such as that)

Answer: The correct answer is 4.956 * 10^7.

Explanation:

For Electrostatic force,

Given qA =1.2 × 10∧-6 C (Since 1 micron = 10∧-6)

qB=0.92 ×10∧-6 C Since 1 micron = 10∧-6)

r = 4.8m

Electrostatic force = (K×qA×qB)÷r∧2 where K is Coulomb's constant or electrostatic constant =8.98755×10∧9

Therefore Electrostatic energy =(8.98755×10∧9×1.2×0.92×10∧-12)÷4.8∧2

                                                   =0.00043065 N ················ eq1

Now for Gravitational force,

mA=2Kg ,mB=1.5Kg ,r=4.8m,G is Gravitational constant =6.67408 × 10-11 N m2 kg-2

Gravitational force=(G×mA×mB)÷r∧-2

                               =(6.67408 × 10-11 ×2×1.5)÷4.8∧-2

                                 =0.869021875 ×10∧-11 N...............eq2

Ratio of electric and gravitational force between ‘A’ and ‘B’ = eq1÷eq2

                                                                                 =49555714.5785

Electrostatic force occurs due to interaction either between like charges that is either between positive-positive or negative negative charges or between unlike charges like positive-negative. Its strength  depends on the charges and the distance between the charges which decreases as the distance increases.

Gravitational  force occurs due to the fact every particle attracts each and every other particle in the universe. Its strength  depends on the mass  and the distance between the particles which decreases as the distance increases.

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Answer: Sodium is the metal reacts vigorously with oxygen and water.

Explanation:

sodium

Answer:

C

Explanation:

Brainliest

I tried my best

Answer:

What's the problem???

3.51023 at. I moles. 6.80 x 1024 fux. 1 www. Count the atoms in the system.

Dermatologists advise monthly skin checks for their patients. often benign moles Consult a dermatologist to have your mole examined if you detect changes in its color or appearance. Moles should also be examined if they bleed, leak, itch, look scaly, change in size, or become uncomfortable or painful.

It's possible for the pigment to penetrate the nearby skin. unbalanced color: There could be various tones of tan, brown, and black. Areas of red, pink, blue, gray, or white may also appear.

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Hey there mate ;)

Question: Write ionic equation

. HCl(aq) + KOH(aq) → KCl(aq) + H2O(l)

Answer:-

The ionic equation is-

K+ + OH- + H+ + Cl- = H2O + K+ + Cl-

Answer: a. 65.37 mL
b. 5.3 cm
c. 2.08 km (plus) or 1.64 km (minus)
d. 18°C (plus) or 16°C (minus)

Explanation:

The way significant figures work when you're adding or subtracting, is you go to the answer with the least amount of decimal places. Take a. for example; you have 65.316 (3 places after the decimal) and 0.05 (2 places after the decimal place). Based off of this, you would round your answer to two places after the decimal. And when you have a whole number, like in d. you round to the nearest whole number, since there aren't any decimal places to round your answer to.

To determine the enthalpy change in a coffee cup calorimetry experiment, the following data or information is needed: initial and final temperatures (T1, T2), heat capacity of the calorimeter (Cp), and mass of the reaction mixture (m), and the equation used is ΔH = Cp * (T2 - T1) * m.

In a coffee cup calorimetry experiment, the following data or information is needed to determine the enthalpy change for a reaction:

The initial temperature of the reaction mixture (T1) and the final temperature after reaction (T2).

The heat capacity of the calorimeter, usually represented by "Cp".

The mass of the reaction mixture.

The equation used to calculate the enthalpy change (ΔH) in a coffee cup calorimetry experiment is given by:

ΔH = q = Cp * (T2 - T1) * m

where q is the heat gained or lost by the reaction mixture, m is the mass of the reaction mixture, Cp is the heat capacity of the calorimeter, T2 is the final temperature of the reaction mixture, and T1 is the initial temperature of the reaction mixture.

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The substance in the image above would be classified as a mixture of elements (option E).

A compound is a substance formed by chemical bonding of two or more elements in definite proportions by weight.

On the other hand, a mixture is made when two or more substances are combined, but they are not combined chemically.

According to this question, an image is shown with two different substances or elements as distinguished by coloration (white and purple). These elements are combined but not chemically bonded, hence, is a mixture.

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The hydroxide ion (−OH) is a strong base and can deprotonate compounds that have an acidic hydrogen atom.

When the −OH ion reacts with an acidic compound, it accepts a proton (H+) to form a water molecule, thereby neutralizing the acidic compound. The pKa value of water is 15.7, which means that compounds with a pKa value below 15.7 can be deprotonated by −OH.

Some examples of compounds that can be deprotonated by −OH include:

Carboxylic acids: These compounds have a carboxyl group (-COOH) that can be deprotonated by −OH to form a carboxylate ion (-COO−). Examples include acetic acid (pKa = 4.75) and benzoic acid (pKa = 4.2).

Phenols: These compounds have a hydroxyl group (-OH) attached to an aromatic ring that can be deprotonated by −OH to form a phenoxide ion (-O−). Examples include phenol (pKa = 9.95) and 4-nitrophenol (pKa = 7.15).

Amides: These compounds have a nitrogen atom attached to a carbonyl group (-CONH2) that can be deprotonated by −OH to form an amide anion (-CONH−). Examples include acetamide (pKa = 16.5) and formamide (pKa = 15.5).

Overall, any compound that has an acidic hydrogen atom with a pKa value below 15.7 can be deprotonated by −OH, resulting in the formation of a conjugate base and water.

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875.38 g are equal to 3.46 moles of iodine.

The mole is the SI basic unit of substance quantity, with the sign mol. The amount of substance in an object or sample is defined as the number of elementary entities of that substance.

It is given that n = 3.46, molar mass of iodine = 253 g/mol.

Moles can be expressed as:

Moles = mass /molar mass

3.46 mol= mass / 253 g/mol.

mass = 253 g/mol ×3.46 mol

mass = 875.38 g.

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The aqueous solution that has the lower freezing point is 0.60 m glucose.

Freezing point depression is the reduction in the temperature at which a liquid freezes caused by dissolved particles. The freezing point depression (ΔTf) of a solution is proportional to the molality (m) of the solute, which is the number of moles of solute per kilogram of solvent.

Freezing point depression is a colligative property, which means it depends only on the number of solute particles in the solution, not on their nature. The van't Hoff factor (i) is used to account for the dissociation of solutes in the solution. The van't Hoff factor of glucose is 1, whereas the van't Hoff factor of CaCl2 is 3.

To calculate the freezing point depression, we use the formula:

ΔTf = i * Kf * m

To calculate the freezing point depression, we use the formula:

ΔTf = i * Kf * m

The freezing point depression constant of water is 1.86 °C/m.

Thus, for the given molality of the solutions, the freezing point depression is

:ΔTfcacl2 = 3 * 1.86 °C/m * 0.60 m = 3.348 °CΔTfglucose = 1 * 1.86 °C/m * 0.60 m = 1.116 °C

Therefore, 0.60 m glucose has a lower freezing point depression than 0.60 m CaCl2.

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Answer:

not fission, the answer is fussion

The test that reacts with blood stains and turns pink if blood is present is called the Kastle-Meyer test, also known as the phenolphthalein test.

The Kastle-Meyer test is based on the principle of catalytic activity of the enzyme peroxidase, which is found in blood. Peroxidase is an enzyme that catalyzes the breakdown of hydrogen peroxide into water and oxygen. The reaction involves the oxidation of phenolphthalin in the presence of hydrogen peroxide, leading to the formation of a pink-colored compound.

When the phenolphthalin reagent is applied to a suspected blood stain, it reacts with any peroxidase present in the blood. The peroxidase enzyme accelerates the breakdown of hydrogen peroxide, which in turn causes the oxidation of phenolphthalin. This oxidation reaction results in the formation of a pink color.

The pink color change is a positive indication of the presence of blood. The intensity of the pink color can vary depending on factors such as the age of the blood stain and the amount of blood present. It is important to note that the test is sensitive to the presence of heme, an iron-containing compound found in hemoglobin, the oxygen-carrying protein in red blood cells.

The Kastle-Meyer test is a widely used presumptive test for blood, it is not specific to blood and can yield false positive results with certain substances that contain peroxidase like activity, such as certain plant materials. Therefore, confirmatory tests, such as DNA analysis, are essential for conclusive identification of blood stains in forensic investigations.

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A dipole is indeed a polar molecule featuring two electrically charged areas from either end.

Both negative and positive charge areas are present in polar compounds. An illustration of a polar substance is water. Given its form and type of bonds, the molecule has a net positive charge for one end (the gas end) and a gradually decreasing charge on the other side (the oxygen end).

All covalent bonds that are polar and hydrophilic should be depicted by sending arrows towards an more charged object in order to identify whether the molecule stands polar or non-polar. The relative polarity can be depicted by altering the arrows' lengths.

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Answer:

m = 1.5 gram

Explanation:

Given that,

Density of protein gelatin, d = 3 g/L

The volume of protein gelatin, V = 0.5 L

We need to find the mass of the protein gelatin. The density of an object is given by :

d = m/V

Where

m is mass

\(m=d\times V\\\\m=3\ g/L\times 0.5\ L\\\\m=1.5\ g\)

So, the required mass is 1.5 gram.

Answer:

benefits: can help reduce waste in land fills, and promotes reusability (turned into different products)

drawbacks: can be much more expensive to salvage than to just throw it in a landfill, and most of the time products cannot be recycled effectively due to its material.

The least polar yet still considered polar covalent bond among the options given would be (D) Si-O

In a polar covalent bond, there is an unequal sharing of electrons between the atoms involved, resulting in a partial positive charge on one atom and a partial negative charge on the other. The electronegativity difference between the atoms determines the degree of polarity in the bond. The larger the electronegativity difference, the more polar the bond.

Among the given options, silicon (Si) and oxygen (O) have a relatively small electronegativity difference compared to the other elements. This means that the Si-O bond is less polar than the other options, yet it still exhibits some degree of polarity due to the electronegativity difference between silicon and oxygen.

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Answer:

a closed circuit is needed because the power has to have a full path to go through if the circuit is open it can not complete there for the power will not work in an open circuit because electricity will not completely make it through to the device.

To balance a chemical equation, you can only adjust the coefficients; you cannot change the subscripts. The ratios of the atoms in the molecule and the resulting chemical characteristics are altered by changing subscripts.

Changing the coefficients solely affects the quantity of molecules in that specific chemical. However, modifying the subscripts will change the substance itself, rendering your chemical equation incorrect.

You can determine the substance from the subscript. You can find out how much of each element is present in the molecule. The substance itself would change if it were altered. In contrast, simply altering the coefficient results in a change in the number of molecules.

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